in spherical coordinated the cone 9z^2=x^2+y^2 has the equation phi = c. find c

The radius of the circle is 7.25

The radius of the circle is determined using Pythagoras' theorem as `follows:

The length of the chord, XY = 10

The bisector of XY = 5

Let the radius be r

The length of the third side of the right-angles triangle = r - 2

Using Pythagoras' theorem:

r² = (r - 2)² + 5²

r² = r² - 4r + 4 + 25

r² - r² = - 4r + 29

-4r = -29

r = 29/4

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Based on the statistical analysis, there is insufficient evidence to support the hypothesis that men spend more time at the gym each week than women who exercise regularly at a gym.

Based on the given summary statistics, the college student conducted a two-sample t-test to test the hypothesis that on average, men spend more time at the gym each week than women who exercise regularly at a gym. The output of the hypothesis test includes the t-statistic, degrees of freedom, p-value, and confidence interval. The t-statistic value is 0.94, and the degrees of freedom are 141. The p-value is 0.348, which is greater than the 5% significance level. Therefore, we fail to reject the null hypothesis that there is no significant difference in the average time spent at the gym each week between men and women who exercise regularly at a gym.

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We need a minimum sample size of 336 to estimate the population proportion of U.S. adults who eat fast food four to six times per week with a 90% confidence level.

A) When there is no preliminary estimate available, we can use the worst-case scenario, which is p = 0.5 (since this gives the maximum possible variability). The margin of error is given as 3% or 0.03. The formula to calculate the minimum sample size needed is:

n = [Z² x p x (1 - p)] / E²

where Z is the z-value for the desired confidence level, p is the population proportion, and E is the margin of error.

At 90% confidence, the z-value is 1.645. Plugging in the values, we get:

n = [(1.645)² x 0.5 x (1 - 0.5)] / (0.03)²

n ≈ 1217.75

We need a minimum sample size of 1218 to estimate the population proportion of U.S. adults who eat fast food four to six times per week with a 90% confidence level and an accuracy of 3%.

B) If a proper study found that 11% of U.S. adults eat fast food four to six times per week, we can use this as a preliminary estimate and calculate the minimum sample size needed with the formula:

n = [Z² x p x (1 - p)] / E²

where p is the preliminary estimate of the population proportion (0.11), and the other variables are the same as before.

At 90% confidence, the z-value is 1.645. Plugging in the values, we get:

n = [(1.645)² x 0.11 x (1 - 0.11)] / (0.03)²

n ≈ 335.77

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All the expressions which are equivalent to 1/10,000 are,

⇒ (10,000)⁻¹

⇒ (10)⁻⁴

⇒ (100)⁻²

We have to given that;

Expression is,

⇒ 1/10,000

Now, We can simplify as;

⇒ 1/10,000

⇒ (10,000)⁻¹

⇒ (10)⁻⁴

⇒ (100)⁻²

Thus, All the expressions which are equivalent to 1/10,000 are,

⇒ (10,000)⁻¹

⇒ (10)⁻⁴

⇒ (100)⁻²

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The equation of the perpendicular line passing through the point (-3,3) in "slope-intercept" form is y = (-1/3)x + 2.

In the graph, We observe that, the given line passes through the point (1,2) and (-1,-4);

First we find the slope of the given line that passes through (1,2) and (-1,-4),

⇒ Slope = (-4 -2)/(-1-1) = -6/-2 = 3,

⇒ slope of given line is 3,

we want to find the equation of a line which is perpendicular to this line, and we know that the slope of the new line will be the negative reciprocal of 3,

So, slope of perpendicular line = -1/3,

Now we use point-slope form of equation of a line to find equation of the new line.

The equation in "point-slope" form is denoted as : y - y₁ = m(x - x₁),

where m = slope and (x₁, y₁) is = point on line.

Substituting the values of "slope = -1/3" and point (-3, 3),

We get,

⇒ y - 3 = (-1/3)(x - (-3)),

⇒ y - 3 = (-1/3)x - 1

⇒ y = (-1/3)x + 2

Therefore, the required equation of the perpendicular line in slope-intercept form is y = (-1/3)x + 2.

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Raymond would be charged a prepayment fee of approximately $772.44 for paying off his loan 5 years early.

To calculate the prepayment fee, we first need to determine the remaining balance on the loan after 20 years of payments. We can use the formula for the present value of an annuity to calculate this:

P = (A / r) * [1 - (1 + r)⁻ⁿ]

where P is the present value, A is the monthly payment, r is the monthly interest rate, and n is the total number of payments.

We can first calculate the monthly interest rate as 3.6% / 12 = 0.003, and the total number of payments as 25 years * 12 months/year = 300 months. Then, we can calculate the monthly payment using the formula for the present value of an annuity:

A = P * (r / (1 - (1 + r)⁻ⁿ))

where P is the principal, r is the monthly interest rate, and n is the total number of payments.

Plugging in the values, we get:

A = 135,000 * (0.003 / (1 - (1 + 0.003)⁻³⁰⁰))

A ≈ $636.93

After 20 years of payments, the remaining balance on the loan would be the present value of the remaining payments, which we can calculate using the same formula:

P = (636.93 / 0.003) * [1 - (1 + 0.003)⁻²⁴⁰]

P ≈ $80,486.94

The prepayment fee would be 6 months' interest on 80% of the remaining balance:

Fee = 0.5 * 6 * (0.003 * 0.8 * $80,486.94)

Fee ≈ $772.44

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r is reflexive, symmetric, and transitive, we can conclude that r is an equivalence relation.

To prove that r is an equivalence relation, we need to show that it is reflexive, symmetric, and transitive.

1. Reflexive: A relation is reflexive if x r x for all x in Z.
Let x ∈ Z. We need to show that x r x, i.e., x 3x is even.
Since 3x is always even (because 3x = 2 * (3/2 * x) and 2 is a factor of 3x), x 3x is even, which means x r x. Therefore, r is reflexive.

2. Symmetric: A relation is symmetric if x r y implies y r x for all x, y in Z.
Let x, y ∈ Z such that x r y, i.e., x 3y is even.
We need to show that y r x, i.e., y 3x is even.
Since x 3y is even, there exists an integer k such that x 3y = 2k.
Then, y 3x = 3y - x = -(x - 3y) = -2k.
As -2k is also an even number, y 3x is even, which means y r x. Therefore, r is symmetric.

3. Transitive: A relation is transitive if x r y and y r z imply x r z for all x, y, z in Z.
Let x, y, z ∈ Z such that x r y and y r z, i.e., x 3y is even and y 3z is even.
We need to show that x r z, i.e., x 3z is even.
Since x 3y and y 3z are even, there exist integers k and m such that x 3y = 2k and y 3z = 2m.
Adding these two equations, we get x 3y + y 3z = 2k + 2m.
Therefore, x 3z = 2(k + m).
As 2(k + m) is even, x 3z is even, which means x r z. Hence, r is transitive.

Since r is reflexive, symmetric, and transitive, we can conclude that r is an equivalence relation.

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Answer:

p = 131.25

Step-by-step explanation:

The mean number of travel days per year for salespeople employed by three hardware distributors needs to be estimated with a 0.95 degree of confidence. The correct option to this number is 1,219.

To calculate the sample size needed for a desired level of confidence, we can use the formula:
n = (Z^2 * σ^2 * N) / ((B^2 * (N-1)) + (σ^2))
where:
n = required sample size
Z = Z-score (for a 0.95 degree of confidence, Z = 1.96)
σ = standard deviation (18 days)
N = population size (unknown, but not needed for large populations)
B = margin of error (2 days)
n = (1.96^2 * 18^2) / (2^2)
n = (3.8416 * 324) / 4
n = 1241.7984
Since we cannot have a fraction of a salesperson, we round up to the nearest whole number. Thus, the required sample size is approximately 1,242 salespeople. However, this option is not among the multiple choices provided. The closest option to this number is 1,219.

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On the map​ (right), the length of each​ east-west block is 1/8 mile and the length of each​ north-south block is 1/10 mile, the straight-line distance between the two locations is approximately 1.41 miles.

To find the shortest walking distance, we can use the Pythagorean theorem, which states that for a right triangle, the square of the length of the hypotenuse (the longest side) is equal to the sum of the squares of the lengths of the other two sides.

Let's label the distance that Victoria walks east as x and the distance she walks north as y.

Then, from the map, we can see that the length of each east-west block is 1/8 mile and the length of each north-south block is 1/10 mile. So, we have:

x = (5/8) + (3/8) = 1 mile

y = (3/10) + (1/10) + (1/10) = 1/2 mile

Now, we can use the Pythagorean theorem:

distance = sqrt(x^2 + y^2)

distance = sqrt(1^2 + (1/2)^2)

distance ≈ 1.12 miles

Therefore, the shortest walking distance is approximately 1.12 miles.

To find the straight-line distance between the two locations, we can simply use the distance formula:

distance = sqrt((1 - 0)^2 + (1.5 - 0.5)^2)

distance = sqrt(1 + 1^2)

distance ≈ 1.41 miles

Therefore, the straight-line distance between the two locations is approximately 1.41 miles.

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The probability of default over the two-year period is approximately 19.04%.The probability of default over a two-year period for a corporate bond with a 92% repayment probability in year 1 and an 88% repayment probability in year 2 can be calculated using the complementary rule in probability theory.

First, we need to find the probability of successful repayment in both years. To do this, we multiply the probabilities of repayment for each year:

P(Repayment in Year 1 and Year 2) = P(Repayment in Year 1) × P(Repayment in Year 2 | Repayment in Year 1) = 0.92 × 0.88 ≈ 0.8096

Now, we use the complementary rule to find the probability of default over the two-year period. The complementary rule states that the probability of an event not happening is equal to 1 minus the probability of the event happening:

P(Default over the two-year period) = 1 - P(Repayment in Year 1 and Year 2) = 1 - 0.8096 ≈ 0.1904

To express the probability as a percentage, we multiply by 100:

0.1904 × 100 ≈ 19.04%

Therefore, the probability of default over the two-year period is approximately 19.04%.

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The equation (1), which is equivalent to p'(x) = -3p(x), has exactly three distinct real solutions.

Let p(x) = (x - a)(x - b)(x - c)(x - d). Then p(x) = 0 has exactly four distinct real solutions, namely a, b, c, and d.

Taking the logarithmic derivative of p(x), we get:

p'(x)/p(x) = 1/(x - a) + 1/(x - b) + 1/(x - c) + 1/(x - d)

Multiplying both sides by p(x), we obtain:

p'(x) = p(x) / (x - a) + p(x) / (x - b) + p(x) / (x - c) + p(x) / (x - d)

Simplifying, we get:

p'(x) = (x - b)(x - c)(x - d) + (x - a)(x - c)(x - d) + (x - a)(x - b)(x - d) + (x - a)(x - b)(x - c)

Therefore, the equation (1) can be written as p'(x) = -3p(x).

By Rolle's theorem, between any two distinct real roots of p(x) (i.e., a, b, c, and d), there must be at least one real root of p'(x). Since p(x) has four distinct real roots, p'(x) must have at least three distinct real roots.

Moreover, since p(x) has degree 4, it can have at most four distinct real roots. Therefore, p'(x) = 0 can have at most four distinct real roots. Since we know that p'(x) has at least three distinct real roots, it follows that p'(x) = 0 has exactly three distinct real roots.

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For the Jerome and Mark lives 8 miles and 15 miles directly south of the school respectively, the shortest distance between Mark's house and Jerome's house is equals to the 17 miles.

The distance between Jerome'home from school = 8 miles south

The distance between Mark'home from school = 15 miles west

We have to determine the the shortest distance between Mark's house and Jerome's house. Now, we draw all Scenario on graph to understand it geometrically. See the above figure, the point S represents the position of school, point J and m represents the home location of Jerome and Mark respectively. As we see there is formed a right angled triangle MJS.

So, using the payathagaros theorem, the shortest distance between Mark's house and Jerome's house, [tex]MJ = \sqrt{ MS² + SJ²}[/tex]

[tex]= \sqrt{8² + 15²}[/tex]

[tex] = \sqrt{289}[/tex]

= 17

Hence, the required distance is 17 miles.

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The maximum value of f(x, y) is 1, and the minimum value is -1 on the given ellipse.

To find the maximum and minimum values of the function f(x, y) = xy on the ellipse 8x² + y² = 9, we'll use the method of Lagrange multipliers. This method involves finding the critical points of a function subject to a constraint (the ellipse equation in this case).

Let g(x, y) = 8x² + y² - 9 be the constraint function. We'll look for points where the gradients of f and g are proportional, i.e., ∇f = λ∇g, where λ is a constant called the Lagrange multiplier. We also have the constraint g(x, y) = 0.

Computing the gradients, we get:
∇f = (y, x) and ∇g = (16x, 2y)

Equating the gradients and applying the constraint, we obtain the following system of equations:

1) y = 16λx
2) x = 2λy
3) 8x² + y² = 9

Substituting (2) into (1), we get y = 32λ²y. If y ≠ 0, we have 1 = 32λ², which implies λ = ±1/4. Similarly, substituting (1) into (2), we get x = 32λ²x, and if x ≠ 0, λ = ±1/4.

For λ = 1/4, from (1) and (2), we have x = y/4 and y = 4x. Solving these simultaneously gives x = ±1/√2 and y = ±2/√2. For λ = -1/4, we get x = ±1/√2 and y = ∓2/√2. Thus, we have four critical points: (±1/√2, ±2/√2).

Evaluating f(x, y) at these critical points, we obtain the maximum and minimum values:
Maximum value: f(1/√2, 2/√2) = 1
Minimum value: f(1/√2, -2/√2) = -1

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Complete question:

Find The Maximum And Minimum Values Of F(X, Y) = Xy On The Ellipse 8x² + Y² = 9.

Maximum Value =

Minimum Value =

The series ∑(e¹/ⁿ/n√n) is absolutely convergent, determined using the Ratio Test.

To determine whether the series ∑(e¹/ⁿ/n√n) is absolutely convergent, conditionally convergent, or divergent, we can use the Ratio Test.

1. Take the absolute value of the series: |e¹/ⁿ/n√n|.
2. Compute the ratio of consecutive terms: |(e¹/ⁿ⁺¹)/((n+1)√(n+1)))/(e¹/ⁿ/(n√n))|.
3. Simplify the ratio: (n√n)/(e¹/ⁿ/(n+1))(n+1)√(n+1)).
4. Take the limit as n approaches infinity: lim(n->∞) (n√n)/(e¹/ⁿ/(n+1))(n+1)√(n+1)).
5. Observe that the limit is 0, which is less than 1.

Since the limit is less than 1, the series is absolutely convergent according to the Ratio Test.

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Without any specific data about the student's GPA or the school's average, it is impossible to provide a numerical answer to this question.

However, in general, to calculate the number of standard deviations a student's GPA is away from the school's average, we would need to find the difference between the student's GPA and the school's average, and then divide that difference by the standard deviation of the GPA distribution for the entire school population. The resulting number would tell us how many standard deviations the student's GPA is away from the mean.

For example, if the school's average GPA is 3.0 and the standard deviation is 0.5, and a student has a GPA of 3.5, then the student is one standard deviation above the mean (since (3.5 - 3.0) / 0.5 = 1). On the other hand, if the same student had a GPA of 2.5, then they would be one standard deviation below the mean (since (2.5 - 3.0) / 0.5 = -1).

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The mass of the solid cylinder is 260π using the triple integral.

To find the mass of the solid cylinder with density p(r,0,z) = 1 + 5^2, we need to integrate the density over the entire volume of the cylinder. Since we are dealing with a cylinder, cylindrical coordinates are the most efficient choice.

The solid cylinder is defined by 0 ≤ r ≤ 5, 0 ≤ θ ≤ 2π, and 0 ≤ z ≤ 6. So we can set up the triple integral as follows:

∫∫∫ p(r,0,z) r dz dr dθ, with limits of integration:

0 ≤ θ ≤ 2π (full revolution around the z-axis)
0 ≤ r ≤ 5 (radius of the cylinder)
0 ≤ z ≤ 6 (height of the cylinder)

Since the density is constant with respect to θ, we can integrate with respect to θ first:

∫0^2π ∫0^5 ∫0^6 (1 + 5^2) r dz dr dθ

Integrating with respect to z next:

∫0^2π ∫0^5 (1 + 5^2) r(6) dr dθ

Simplifying:

∫0^2π 3(1 + 5^2) r^2 dr dθ

Integrating with respect to r:

∫0^2π 3(1 + 5^2) [(5^3)/3] dθ

Simplifying:

10π(26)

The mass of the solid cylinder is 260π.

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The probability of selecting a sample of 40 adults and finding the mean of this sample to be between 95 and 105 is approximately 0.932 or 93.2%.

We can use the central limit theorem and assume that the sample mean follows a normal distribution with a mean of 100 and a standard deviation of 15/sqrt(40) = 2.37.
To find the probability of selecting a sample with a mean between 95 and 105, we can standardize the values using the formula:
z = (x - μ) / (σ / sqrt(n))
where x is the sample mean (which is between 95 and 105), μ is the population mean (which is 100), σ is the population standard deviation (which is 15), and n is the sample size (which is 40).
For a sample mean of 95:
z = (95 - 100) / (15 / sqrt(40)) = -1.77
For a sample mean of 105:
z = (105 - 100) / (15 / sqrt(40)) = 1.77
Using a standard normal distribution table (or a calculator), we can find the probability that z is between -1.77 and 1.77, which is approximately 0.932.
Therefore, the probability of selecting a sample of 40 adults and finding the mean of this sample to be between 95 and 105 is approximately 0.932 or 93.2%.

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Jada can take the piece with the crust, and Andre can take the piece without the crust. This way, they will each have an equal portion of the pizza slice, and Andre won't have to eat any crust.

To divide the pizza slice into two equal pieces so that Andre doesn't have to eat any crust, Jada and Andre can follow the following steps;

Firstly, find the area of the pizza slice

The area of the sector of a circle is given by the formula A = (1/2) × r² × θ, where r is radius of the circle and θ is the central angle in radians. In this case, the radius of the pizza slice is 20 cm and the central angle is π/3 radians. Plugging in these values, we can calculate the area of the pizza slice.

A = (1/2) × (20 cm)² × (π/3)

A = (1/2) × 400 cm² × (π/3)

A = 200/3 × π cm²

Now, find half of the area of the pizza slice.

To divide the pizza slice into two equal pieces, Jada and Andre need to find half of the total area of the pizza slice.

Half of the area of the pizza slice = (1/2) × (200/3 × π cm²)

Half of the area of the pizza slice = 100/3 × π cm²

However,  Cut along the radius.

Jada and Andre can cut along the radius of the pizza slice, starting from the center of the circle (where the crust is) and extending to the outer edge of the pizza. This will result in two equal pieces, with one piece containing the crust and the other piece not containing any crust.

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The value of AC is,

⇒ AC = 37.57

We have to given that;

The circle E with diameter CD and radius EA.

AB is tangent to E at A.

Here, AD = 16 and EA = 17

Hence, We get;

CD = 17 + 17

CD = 34

By using Pythagoras theorem;

AC² = AD² + CD²

AC² = 16² + 34²

AC² = 256 + 1156

AC² = 1412

AC = √1412

AC = 37.57

Thus, The value of AC is,

⇒ AC = 37.57

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The requreid total decrease in Quect Company's stock was 8 6/25 points.

To find the total decrease in Quect Company's stock, we need to add the decrease by Wednesday to the decrease by Friday.

The decrease by Wednesday was 4 11/50 points. We can write this as a mixed number:

4 11/50 = 4 + 11/50

The decrease by Friday was 4 1/50 points, which can also be written as:

4 1/50 = 4 + 1/50

Adding these two values together, we get:

(4 + 11/50) + (4 + 1/50) = 8 + 12/50 = 8 + 6/25

Therefore, the total decrease in Quect Company's stock was 8 6/25 points.

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Answer: First, we need to convert 0.4 mile to feet by multiplying it by 5,280:

0.4 mile * 5,280 feet/mile = 2,112 feet

Next, we can use the formula for the circumference of a circle, C = 2πr, where C is the circumference and r is the radius.

We know that the distance around the circular track is 2,112 feet, so we can set up the equation:

2πr = 2,112

Simplifying the equation, we can divide both sides by 2π:

r = 2,112 / (2π)

Using π = 3.14 and rounding to the nearest hundredth, we get:

r ≈ 336.31 feet

Therefore, the radius of the track is approximately 336.31 feet.

Answer: 336.31 feet

First, let's understand what L'Hospital's Rule is. It is a rule used in calculus to evaluate limits of functions. It states that if the limit of a function is of an indeterminate form, such as 0/0 or infinity/infinity, then you can take the derivative of the numerator and denominator and evaluate the limit again. This process can be repeated until the limit can be evaluated without an indeterminate form.

However, there are times when L'Hospital's Rule cannot be used or is not the most efficient method. Here are some steps to solving a limit problem without using L'Hospital's Rule:

1. Simplify the function as much as possible by factoring, canceling out terms, or applying algebraic properties.

2. Look for patterns or special cases that may help simplify the problem. For example, if you have a trigonometric function with an angle that approaches 0, you can use the limit definition of sine or cosine to evaluate the limit.

3. Use basic limit rules, such as the limit of a sum or difference, the limit of a product, or the limit of a quotient. These rules can help you evaluate the limit without using L'Hospital's Rule.

4. Use trigonometric identities or logarithmic or exponential properties to rewrite the function in a simpler form.

5. If all else fails, try to graph the function or use a table of values to estimate the limit.

By following these steps, you can find a solution to a limit problem without relying on L'Hospital's Rule.

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The new circumference appears 4 times larger than the original circumference.

The diameter of Earth is the distance across the widest part of its circular shape. The circumference of Earth is the distance around its circular shape. When a photograph of Earth is enlarged, the diameter appears 4 times larger. This means that the new diameter is 4 times the original diameter. Mathematically, if the original diameter of Earth is represented by "d", then the new diameter after enlargement would be 4d.

Now, we need to find out how much larger the circumference of Earth appears after the enlargement. The formula for the circumference of a circle is C = πd, where "C" represents the circumference and "d" represents the diameter. Since the diameter has become 4d, the new circumference would be:

C = π(4d)

C = 4πd

This means that if the original circumference of Earth is represented by "c", then the new circumference after enlargement would be 4c.

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The statement that describes the expression 5 × 3 − (2 × 4) + 5 is: "Subtract the product of 2 and 4 from the product of 5 and 3, then add 5."

The expression given is 5 × 3 − (2 × 4) + 5.

First, we need to perform the multiplication and division, working from left to right.

In this case, the only multiplication is 5 × 3, which equals 15.

Next, we need to perform addition and subtraction, also working from left to right.

Here, we have two operations: (2 × 4) and 5.

Therefore, the statement that describes the expression 5 × 3 − (2 × 4) + 5 is option 3: Subtract the product of 2 and 4 from the product of 5 and 3, then add 5.

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The complete question is as follows:

What is the statement that describes this expression: 5 × 3 − (2 × 4) + 5.

1. 5 more than 3 subtract the product of 2 and 4 plus 5

2. 5 times the product of 2 and 4 times 3, then add 5

3. Subtract the product of 2 and 4 from the product of 5 and 3, then add 5

4. 5 more than the product of 5 and 3 plus the 2 times 4

The volume of the solid in the first octant is bounded by the coordinate planes, the cylinder x2 y2 = 4, and the plane z y = 3 is 6 - 6 ln 2 cubic units.

To find the volume of the solid in the first octant bounded by the coordinate planes, the cylinder x2 y2 = 4, and the plane z y = 3, we can use triple integration. We'll integrate with respect to x, then y, then z.
First, we need to determine the limits of integration. The solid is bounded by the coordinate planes, so we know that 0 ≤ x ≤ 2 and 0 ≤ y ≤ 2. We can also see from the equation of the cylinder that x2 y2 = 4, which can be rearranged to y = ±2/ x. Since we're only interested in the solid in the first octant, we'll use the positive root: y = 2/ x. Finally, the plane z y = 3 can be rearranged to z = 3/ y.
So, our limits of integration are:
0 ≤ x ≤ 2
0 ≤ y ≤ 2/ x
0 ≤ z ≤ 3/ y
Now we can set up the triple integral:
∭V dV = ∫0^2 ∫0^(2/x) ∫0^(3/y) dz dy dx
Evaluating this integral, we get:
∭V dV = ∫0^2 ∫0^(2/x) (3/y) dy dx
= ∫0^2 3 ln(2/x) dx
= 3 [x ln(2/x) - 2] from 0 to 2
= 6 - 6 ln 2
So the volume of the solid in the first octant bounded by the coordinate planes, the cylinder x2 y2 = 4, and the plane z y = 3 is 6 - 6 ln 2 cubic units.

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The data provide sufficient evidence to support the claim that the mean salary for family practitioners in Los Angeles is greater than the national average.

The populace imply earnings for household practitioners in Los Angeles is equal to the country wide average.

Alternative hypothesis: The populace imply revenue for household practitioners in Los Angeles is higher than the country wide average.

We can use the stage of magnitude (alpha) of 0.05 and a one-tailed test, as we are solely fascinated in whether or not the imply earnings in Los Angeles is larger than the countrywide average.

Substituting the given values, we get:

t = ( $210,000 - $175,000 ) / ( $40,000 / √40 )

t = 3.18

Where,

The country wide common is $175,000, as mentioned in the question.

The income for household practitioners in Los Angeles is appreciably higher than the country wide common at the 0.05 degree of significance.

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The function f(t) is increasing on the interval (0, ∞).  f is increasing on the interval (0, ∞). To find all intervals on which f(t) is increasing, we first need to find the derivative of the given function f(t) = ∫(85(t^2 - 17t + 72)e^(t^2)).

Step 1: Differentiate the function with respect to t.
f'(t) = 85(2t - 17)e^(t^2) + 85(t^2 - 17t + 72)(2t)e^(t^2)
Step 2: Simplify the expression.
f'(t) = 170t(e^(t^2)) - 85(17)e^(t^2) + 170t(t^2 - 17t + 72)e^(t^2)
Step 3: Find the critical points by setting f'(t) to zero.
170t(e^(t^2)) - 85(17)e^(t^2) + 170t(t^2 - 17t + 72)e^(t^2) = 0
Step 4: Solve for t.
t(170 - 85(17) + 170(t^2 - 17t + 72)) = 0
t = 0 is a critical point.
Step 5: Analyze the intervals around the critical point.
f'(t) is increasing when:
- For t < 0: f'(t) < 0
- For t > 0: f'(t) > 0
Hence, the function f(t) is increasing on the interval (0, ∞). Your answer: f is increasing on the interval (0, ∞).

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To find the slope of the tangent to the curve r = 4 + 7cosθ at θ = π/2, we first need to convert the polar equation to Cartesian coordinates using x = rcosθ and y = rsinθ.

Substitute r = 4 + 7cosθ into x and y equations:
x = (4 + 7cosθ)cosθ
y = (4 + 7cosθ)sinθ

Now, differentiate x and y with respect to θ:
dx/dθ = -7cos²θ - 7sinθsinθ
dy/dθ = 7cosθsinθ - 4cosθ

To find the slope of the tangent (dy/dx), divide dy/dθ by dx/dθ:
(dy/dx) = (7cosθsinθ - 4cosθ) / (-7cos²θ - 7sinθsinθ)

Next, plug in the value θ = π/2:
(dy/dx) = (7cos(π/2)sin(π/2) - 4cos(π/2)) / (-7cos²(π/2) - 7sin(π/2)sin(π/2))

At θ = π/2, cos(π/2) = 0 and sin(π/2) = 1, so:
(dy/dx) = (7(0)(1) - 4(0)) / (-7(0)² - 7(1)(1))

(dy/dx) = 0 / (-7)

Thus, the slope of the tangent to the curve at θ = π/2 is 0.

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Answer:

see below

Step-by-step explanation:

7. adjacent

8.vertical

9.vertical

10.neither

11.adjacent

12.neither

Hope this helps :)