Answer:
$15540 is 2.1% of 740,000 which is the same percent as the 920,000 which was 2.1 percent so your answer is $15540
Step-by-step explanation:
Write the ratio as a fraction: 630kilometers in 5hours. Simplify your answer.
___ km/hour
Answer:
126/1=126
Step-by-step explanation:
630:5 as a fraction would be 630/5.
630/5 simplified would be 126/1.
Hope this helps :)
Answer:
630:5 would be 126:1
Step-by-step explanation:
To solve this we would divide 630 by five giving us 126, and divide 5 by 5 giving us one
Now we have 126:1, or 126 km/hour
50 points! Help (Vectors)
[tex]2v - 3u\\\\=2<3,7> - 3<-5,4>\\\\=<6,14>-<-15,12>\\\\=<6+15, 14-12>\\\\=<21,2>[/tex]
Answer:
Step-by-step explanation:
Raju has to grow 26 cm more to reach 3 m height. What is Raju's height in metres
Answer:
2.74 m
Step-by-step explanation:
3 m to cm is 300.
Then, 300 cm - 26 cm = 274 cm.
You asked "What is Raju's height in METRES"
So, 274 cm to m is 2.74.
Hope you understand ^^
Answer:
2.74 m
Step-by-step explanation:
Converting centimeter to meter: 26 cm = 0.26 m
3 - 0.26 = 2.74 m
plz help i only need this question who ever get its right will get 77 point
Answer:
Ok, so I think it's x= 2.5 and y= 306.1 plz forgive me if I'm wrong.
Look at the two equations:
-3x + 6 = 21
-3x + 6 < 21
Which statement best describes the process used to solve the equations?
O In both cases, subtract 6 from both sides, but reverse the inequality sign when doing that for the inequality
O In both cases, divide by -3 on both sides, but reverse the inequality sign when doing that for the inequality.
O The process is exactly the same for solving the equation and solving the inequality
O The process for solving the equation is entirely different from solving the inequality.
Are the following two lines parallel, perpendicular, neither, or the same line?
3x+4y = 2
4x+3y = 2
what are they?
Answer:
Neither.
Step-by-step explanation:
Manipulate the formulas into slope-intercept form which is [tex]y=mx+b[/tex].
In order for them to be parallel, m needs to be the same. Perpendicular, m for one needs to be the negative reciprocal of the other [tex]m=-\frac{1}{m}[/tex].
Let's see what we get.
(1)
[tex]3x+4y=2\\4y=-3x+2\\y=-\frac{3}{4}x+1/2[/tex]
(2)
[tex]4x+3y=2\\3y=-4x+2\\y=-\frac{4}{3}x+2/3[/tex]
They are reciprocals, but they are both negative. So, they are not the same line, perpendicular, nor parallel.
Also, you can graph these equations on desmos and see easily that they have none of these relationships.
Sam says that the length of diagonal SQ is two times the length of diagonal OM.
Is Sam correct? Justify your answer and show all your work. Your work should state the theorem you used to find the lengths of the diagonals.
Answer:
Sam is NOT correctStep-by-step explanation:
Let's find the diagonal measures using Pythagorean and compare:
[tex]SQ=\sqrt{12^2+6^2} =\sqrt{4*6^2+6^2} =\sqrt{5*6^2} =6\sqrt{5}[/tex]and
[tex]OM=\sqrt{6^2+6^2} =\sqrt{2*6^2} =6\sqrt{2}[/tex]Find the ratio of diagonals:
SQ / OM = √5 / √2 ≠ 2Plz help!! Given: DE is a midsegment of ABC. Show all work.
Find the value of x and y.
And What is the length of AC? !Please show all work!
Incase photo is blurry
AE-y+6
EC-x-3
DE-x+2
BC-24
Answer:
AC=14
X=10
Y=1
Hoped this helped!
Step-by-step explanation:
DE is half of BC, therefore x=10. AE and EC have to be the same length, which is 7. SO, y=1 and x is 10.
Please help me answer this question!!!
Answer:
B
Step-by-step explanation:
<STR = <SRT Given the markings of the triangle
<STR + <STU = 180 Supplementary angles
(2x - 9) + 7x = 180 Remove the brackets
2x - 9 + 7x = 180 Combine
9x - 9 = 180 Add 9 to both sides
9x = 180 + 9 Combine
9x = 189 Divide by 9
9x/9 = 189/9
x = 21
Brian has half of his investments in stock paying a 5% dividend and the other half in a stock paying 9% interest. If his total annual interest is $420, how much does he have invested?
The amount invested in each stock, the stock interest rate and the
duration of the investment, determines the interest.
Brian invested $3,000 in the stock that pays 5% dividend and $3,000 in the stock that pays 9% to make a total investment of $6,000.Reasons:
Let X represent the sum of the amount Brian invested, we have;
Amount invested in stock paying 5% dividend = [tex]\dfrac{X}{2}[/tex]
Amount invested in stock paying 9% dividend = [tex]\dfrac{X}{2}[/tex]
Total annual interest = $420
Required:
The amount invested in the stocks
Solution:
The amount invested is found as follows;
[tex]\dfrac{X}{2} \times 5\% + \dfrac{X}{2} \times 9\% = 420[/tex]
0.025·X + 0.045·X = 420
0.07·X = 420
[tex]\displaystyle \mathrm{The \ amount \ invested , \, X} = \frac{420}{0.07} = \mathbf{ 6,000}[/tex]
The amount he invested = $6,000 ($3,000 in each stock)
Learn more here:
https://brainly.com/question/20612739
Simplify (-9k+12k+9)-(10k+3k+4K-8)
Answer:
-14k+17
Step-by-step explanation:
There were 96 iPads at Fun Elementary. A company donated some iPads and the school purchased 300 more iPads. Now there are 865 iPads. How many iPads were donated to Fun Elementary?
Answer:
469 iPads were donated.
Step-by-step explanation:
The school purchased 396 iPads in total: 300+96
Now, you subtract how many the school purchased from the total amount of iPads to see how many iPads were donated: 865-396 = 469
Is (2, 1) a solution to the equation y = 2x - 1?
Answer:
No
Step-by-step explanation:
Substitute the values for their respective variable and evaluate.
[tex]1=2(2)-1\\1=4-1\\1\neq 3[/tex]
Therefore, (2, 1) is not a solution to the equation y = 2x - 1.
(2, 1) is in the form of (x, y).
Then,
☆ x = 2
☆ y = 1
Equation =》y = 2x - 1
Now, substitute the values.....
=》y = 2x - 1
=》(1) = 2(2) - 1
=》1 = 4 - 1
=》 1 ≠ 3
So, (2, 1) is NOT a solution to the equation y = 2x - 1.
______
Hope it helps ⚜
Evaluate the line integral, where C is the given curve. z2 dx x2 dy y2 dz, C C is the line segment from (1, 0, 0) to (5, 1, 2)
I assume the integral is supposed to be
[tex]\displaystyle \int_C z^2\,dx + x^2\,dy + y^2\,dz[/tex]
Parameterize C by
[tex](x(t),y(t),z(t)) = (1-t)(1,0,0) + t(5,1,2) = (1+4t, t, 2t)[/tex]
with 0 ≤ t ≤ 1, and dx = 4 dt, dy = dt, and dz = 2 dt. Then the line integral is
[tex]\displaystyle \int_C z^2\,dx + x^2\,dy + y^2\,dz = \int_0^1 (2t)^2(4\,dt) + (1+4t)^2\,dt + t^2(2\,dt)[/tex]
[tex]\displaystyle \int_C z^2\,dx + x^2\,dy + y^2\,dz = \int_0^1(1+8t+34t^2)\,dt[/tex]
[tex]\displaystyle \int_C z^2\,dx + x^2\,dy + y^2\,dz = 1+4+\frac{34}3 = \boxed{\frac{49}3}[/tex]
2 paisa per 2 rupees per month
Answer:
2 paisa per rupees per month
So rate= 2%
7 Harper ordered 22 shirts for her soccer team. Seventy-five percent of these shirts were saa samall. How many
seal shirts did Harper order?
Answer:
16.5 shirts were small.
Step-by-step explanation:
0.75 x 22 = 16.5
Please any math experts help thanks you
Answer:
[tex]\frac{p^2-25}{p^2-10p+25}[/tex]
We can factorise the numerator with the difference of squares formula:[tex]x^2-y^2=(x+y)(x-y)[/tex]
-----------------------------
[tex]\frac{p^2-5^2}{p^2-10p+25} =\frac{(p+5)(p-5)}{p^2-10p+25}[/tex]
Now we can factorise the denominator:
[tex]\frac{(p+5)(p-5)}{p^2-10p+25} =\frac{(p+5)(p-5)}{(p-5)^2}[/tex]
[tex]\frac{(p+5)(p-5)}{(p-5)^2} =\frac{(p+5)(p-5)}{(p-5)(p-5)}[/tex]
Cancel out the common factor of (p-5):
[tex]\frac{(p+5)(p-5)}{(p-5)(p-5)} =\frac{(p+5)}{(p-5)}[/tex]
can someone PLEASE construct these 2 for me!
dear and kind community I have a question that urges me which is the following, let's imagine that there are 73 million coins that can be fractioned to a hexadecimal value of a minimum unit of 0.00000001 and would need 0.99999998 to reach a full unit of the coin 1, my question is what would happen if instead of this minimum hexadecimal number of coin 0.00000001 was a hundred 100=1? how many coins would exist if before it was 73 million with hexadecimals (0,00000001) now with a hundred it would be equivalent to one unit (1=100) how many coin units would there be? if now each unit would only be divided in hundreds and not in hexadecimals? thanks in advance to the one who responds.
Answer:
that have no answer so sorry
Can someone help me please I will mark u brilliant
Answer:
6.333... is greater
Step-by-step explanation:
6.3 is larger than 6.2
Answer:
6.33333
Step-by-step explanation:
6.29
6.33333
The 3 is greater than the 2.
Hope this helps :)
b. 2x^2 + 15 _<13x solve polynomial inequality by factoring.
Answer:
x<5 or x<3/2
Step-by-step explanation:
2[tex]x^{2}[/tex]-13x+15<0
2[tex]x^{2}[/tex]-10x-3x+15<0
2x(x-5)-3(x-5)<0
(x-5)(2x-3)<0
x-5<0 or 2x-3<0
x<5 or x<3/2
Evaluate (32 – 1)when z = 6
Answer:
17
Step-by-step explanation:
(3z - 1) when z = 6
Let's plug in 6 into the equation (3(6)-1)
Now we multiply the parenthesis (18-1)
Now we subtract (17)
So the answer is 17!
Please show how you solved the problem.
4a - 14 = 7a - 8
4a - 14 = 7a - 8
4a - 7a = 14 -8
-3a = 6
a = 2
ok done. Thank to me :>
Answer:
a= -2
Step-by-step explanation:
4a -14 = 7a -8
Subtract 7a from both sides
-3a -14= -8
Add 14 to both sides of equation
-3a = -8 +14
Add -8 and 14
-3a = 6
Divide each term by -3
a = -2
1) f(x) = x² + 2x + 1
2) g(x) = x² + 6x + 5
3) h(x) = x² - 12x + 36
4) g(x) = 9x² + 6x + 2
5) g(x) = x² + 6x + 4
Answer:
(X+1)(X+1) (X+5)(X+1)3. (X-6)(X-6)
Fireworks are fired from the roof of a 100-foot building and travel 84 feet per second. The equation h = -16t 2 + 84t + 100 models the height h of the fireworks at any given time t seconds.
The firework reaches the ground after 6.25 seconds.
A projectile is the curved motion of an object thrown into space under the influence of gravity.
Given that the firework experiences a projectile motion given by the equation:
h = -16t² + 84t + 100
where h is the height after t seconds.
The firework reaches the ground when h = 0, hence:
0 = -16t² + 84t + 100
t = 6.25 seconds.
Therefore the firework reaches the ground after 6.25 seconds.
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picture of complex number system.....
Answer:
is this ok 4 uh?
hope it helps
In 1950, the group spent 23% of their budget on food. This has decreased
at an average rate of approximately 0.27% per year since then. Find a
linear function in slope-intercept form that models the percentage of total
spending, p(x), by the group x years after 1950.
The linear function that can be used to model this relationship is:
y = -0.27x + 23
A linear function is in the form:
y = mx + b
where y, x are variables, m is the rate of change and b is the initial value of y.
Let P(x) represent the percentage of total spending x years after 1950.
Since In 1950, the group spent 23% of their budget on food, hence b = 23.
Also, this has been decreasing at 0.27% per year. Hence m = -0.27.
The linear function that can be used to model this relationship is:
y = -0.27x + 23
Find out more at: https://brainly.com/question/13911928
If x^2 - (3x-a) (bx-1) = c, where a, b, and c are constants, what id the value of c?
A. 9
B. 7
C. 13
D. 2
What is the next number in the series shown?
132, 123, 115, 108, 102
158) -.- A) P-3 in B) P-86 C) P-92 in D) P96 4
Answer:
P = 83 in
Step-by-step explanation:
For this one, all we need to do is substitute 7 for x and 4 for y:
3x + y = ?
3(7) + 4 =?
21 +4 = ?
21 + 4 = 25 in.
Now for the next one:
4y = ?
4(4) = ?
4(4) = 16
Now we solve the final side:
6x = ?
6(7) = ?
6(7) = 42
Now to find P, we must add them all together:
25 + 16 + 42 = 83
Therefore P = 83
Answer:
A) P = 83
Step-by-step explanation:
-=======================-
3x + y
3(7) + 4 =
21 + 4 =
25
-=======================-
6x
6(7)
42
-=======================-
4y
4(4)
16
-=======================-
25 + 16 + 42 = 83
Hope this helps.