Answer:
Wilma will pay $23.44 total.
Step-by-step explanation:
Cost of sweater = (+) $24.49
Discount = (-) $5
Shipping cost = (+) $3.95
Solve:
24.49 - 5 = 19.49
19.49 + 3.95 = 23.44
Wilma will pay $23.44 total.
which expresion shows 7+21 written as a product of two factors
As we used the distributive property of multiplication to rewrite 7+21 as a product of 7 x (1+3) or 7 x 4.
However, you are asked to express this sum as a product of two factors. A factor is a number that is multiplied by another number to produce a product. Therefore, to express 7+21 as a product of two factors, we need to find two numbers that, when multiplied together, give us the sum of 7+21.
One way to approach this problem is to use the distributive property of multiplication, which states that a(b+c) = ab + ac. We can apply this property by rewriting 7+21 as 7+3*7, since 21 is equal to 3 times 7. Then, we can factor out the common factor of 7 from the expression to get:
7+37 = 7(1+3)
Now, we have expressed 7+21 as a product of two factors: 7 and (1+3), or simply 7 and 4. Therefore, the expression that shows 7+21 written as a product of two factors is:
7 x (1+3) or 7 x 4
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what is 45 x 6 i need help
Answer:
270
Step-by-step explanation:
I am showing my mental math, hope this helps you:
45 x 6 is the same as 4 x 6 = 10s place value and 5 x 6 = 1s place value:
4 x 6 = 24
5 x 6 = 30
Therefore, the answer is:
2 (4 + 3) 0
270
The value of the expression 45 x 6 is 270.
We have,
To calculate the product of 45 multiplied by 6, you can follow these steps:
- Start by multiplying the units digits of the two numbers: 5 x 6 = 30.
- Write down the units digit of the result, which is 0, and carry over the tens digit, which is 3.
- Multiply the tens digit of the first number by the second number: 4 x 6 = 24.
- Add the carried-over value from step 2 to this result: 24 + 3 = 27.
- Write down the tens digit of the result, which is 7, and carry over the hundreds digit, which is 2.
- Multiply the hundred digit of the first number by the second number: 4 x 6 = 24.
- Add the carried-over value from step 5 to this result: 24 + 2 = 26.
- Write down the hundred digit of the result, which is 6.
- Combine the hundreds, tens, and units digits together: 6, 7, 0.
- The final product of 45 multiplied by 6 is 270.
So, 45 x 6 = 270.
Thus,
The value of the expression 45 x 6 is 270.
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Jordan is tracking a recent online purchase. The shipping costs state that the item will be shipped in a 24-inch long box with a volume of 2,880 cubic inches. The width of the box is seven inches less than the height.
The volume of a rectangular prism is found using the formula V = lwh, where l is the length, w is the width, and h is the height.
Complete the equation that models the volume of the box in terms of its height, x, in inches.
Is it possible for the height of the box to be 15 inches?
also the question has 3 boxes
Answer:
Sure, I can help you with that.
Given:
* The box is 24 inches long.
* The width of the box is seven inches less than the height.
* The volume of the box is 2,880 cubic inches.
To solve:
* Complete the equation that models the box's volume in terms of its height, x, in inches.
* Determine if the height of the box can be 15 inches.
Solution:
Let's define the following variables:
* $h$ = the height of the box (in inches)
* $w$ = the width of the box (in inches)
* $l$ = the length of the box (in inches)
We are given that l=24 and w=h−7. We can use these values to find the volume of the box:
[tex]V = lwh = 24(h - 7)h[/tex]
We can simplify this expression to get the following equation:
[tex]V = 24h^2 - 168h[/tex]
To determine if the height of the box can be 15 inches, we can substitute 15 for $h$ in the equation and see if we get a positive value for the volume.
[tex]V = 24(15)^2 - 168(15) = 2160 - 2490 = -330[/tex]
Since the volume is negative, the height of the box can't be 15 inches.
Therefore, the equation that models the box's volume in terms of its height, x, in inches is [tex]$V = 24x^2 - 168x$[/tex]. Consequently, the size of the box can't be 15 inches.
Answer:
Yes
Step-by-step explanation:
The only answer is height = 15 because the -8 will be rejected
Un elevador de taller mecánico tiene pistones de entrada y salida de 5 cm y de 60 cm de radio respectivamente. Con este dispositivo se mantiene levantado un auto de 2000 kg. ¿Cuál es la fuerza aplicada al pistón de entrada?
The force applied to the input piston is 136.25 N.
How to find the force applied to the intake piston?This problem can be solved using the principle of hydraulic systems, which states that pressure in a confined fluid is transmitted equally in all directions.
Thus, we can equate the pressure on the input piston to the pressure on the output piston, and solve for the force on the input piston. That is:
P₁ = P₂
F₁/A₁ = F₂/A₂ (Pressure = Force/Area)
F₂ = 2000 * 9.81 = 19620 N (F = mg)
A₁ = π * r₁² = π * 5² = 25π cm²
A₂ = π * r₂ ² = π * 60² = 3600π cm²
F₁ = F₂/A₂ * A₁
F₁ = (19620/3600π) * 25π
F₁ = 136.25 N
Therefore, the force applied to the input piston is 136.25 N.
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Question in English
A machine shop lift has input and output pistons of 5 cm and 60 cm radius respectively. With this device, a 2000 kg car is kept lifted. What is the force applied to the intake piston?
If 86
is added to a number, the result is 44
less than three times the number. Find the number.
Answer:
x = 65
Step-by-step explanation:
let the number be 'x'.
If 86 is added to a number, the result is 44 less than three times the number. Therefore the equation will be,
=> 86 + x = 3x - 44
Rearranging,
=> x - 3x = -44 - 86
=> -2x = -130
=> x = 130/2
=> x = 65
Find the midpoint of the segment formed by the points D(8, 6) and E(4, 10). A. (2, –2) B. (6, 8) C. (9, 5) D. (12, 16)
Answer:
B
Step-by-step explanation:
let the mid-point of DE be ( x , y )
x = (8+4)/2 = 6
y = (6+10)/2 = 8
the mid- point of DE is ( 6 , 8 )
If tanθ=-5/2 and sinθ>0, find the exact values of sinθ,cosθ,secθ,cscθ,cotθ.
The exact values are;
sinθ = -5/√29
cosθ = 2/√29
secθ =√29/2
cscθ = -√29/5
cotθ = -2/5
We are given that
tanθ=-5/2 and sinθ>0
First quadrant: I, 0°<θ<90°
We can find the first quadrant between 0° and 90° , the values from 0 to the positive numbers for the x-axis and the y-axis, the functions sine, cosine and tangent will always have positive values.
sinθ = -5/√29
cosθ = 2/√29
secθ =√29/2
cscθ = -√29/5
cotθ = -2/5
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I’ve had trouble on these even on my test and I still can’t figure it out. Can someone explain how to solve:
3x = y - 2
6x = 4 - 2y
Answer: Sure, here's how to solve the system of equations:
1. Start with the first equation: 3x = y - 2
Solve for y by adding 2 to both sides: y = 3x + 2
2. Substitute the value of y from the first equation into the second equation:
6x = 4 - 2y
6x = 4 - 2(3x + 2) (substitute y = 3x + 2)
6x = 4 - 6x - 4
12x = 0
3. Solve for x by dividing both sides by 12: x = 0
4. Substitute the value of x from step 3 into either equation to solve for y:
y = 3x + 2
y = 3(0) + 2
y = 2
Therefore, the solution to the system of equations is (x, y) = (0, 2).
hope this helpsss :D
Step-by-step explanation:
a 7 cm times 5 cm rectangle sits inside a circle with a radius of 6 cm
The shaded area of the portion as shown in the diagram is 78.04 cm².
What is area?Area is the region bounded by a plane shape.
To calculate the shaded area of the portion, we use the formula below
Formula:
A = πr²-lw.................. Equation 1Where:
A = Area of the shaded portionr = Radius of the circlel = Length of the rectanglew = Width of the rectangleFrom the question,
Given:
r = 6 cml = 7 cmw = 5 cmSubstitute these values into equation 1
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Complete question: A 7 cm times 5 cm rectangle sits inside a circle with a radius of 6 cm. Calculate the area of the shaded portion.
On a computer screen, lengths and widths are measured not in inches or millimeters but
in pixels. A pixel is the smallest visual element that a computer is capable of processing. A
common size for a large computer screen is 1024 × 768 pixels. (Widths rather than heights are
conventionally listed first.) For the following, assume you’re working on a 1024 × 768 screen.
1. You have a photo measuring 640 × 300 pixels and you
want to enlarge it proportionally so that it is as wide as the
computer screen. Find the measurements of the photo after it
has been scaled up. Explain how you found the answer.
2. a. Explain why you can’t enlarge the photo proportionally so
that it is as tall as the computer screen.
b. Why can’t you correct the difficulty in (a) by scaling the
width of the photo by a factor of 1024 ÷ 640 and the
height by a factor of 768 ÷ 300
To enlarge the photo proportionally so that it is as wide as the computer screen, we need to find the scaling factor. The scaling factor is the ratio of the width of the computer screen to the width of the photo:
Scaling factor = 1024 ÷ 640 = 1.6
We can then use this scaling factor to find the new dimensions of the photo:
New width = 640 × 1.6 = 1024 pixels
New height = 300 × 1.6 = 480 pixels
Therefore, the new dimensions of the photo are 1024 × 480 pixels.
2a. We cannot enlarge the photo proportionally so that it is as tall as the computer screen because the aspect ratio of the photo is different from the aspect ratio of the computer screen. The aspect ratio of the photo is 640 ÷ 300 ≈ 2.13, while the aspect ratio of the computer screen is 1024 ÷ 768 ≈ 1.33. This means that if we enlarge the height of the photo to match the height of the computer screen, the width of the photo will be too wide to fit on the screen.
b. We cannot correct the difficulty in (a) by scaling the width of the photo by a factor of 1024 ÷ 640 and the height by a factor of 768 ÷ 300 because this would change the aspect ratio of the photo. The aspect ratio of the photo would become 1024 ÷ (640 × 1024 ÷ 640) ≈ 1.6, which is the same as the aspect ratio of the computer screen. However, the height of the photo would be scaled by a factor of 768 ÷ 300 ≈ 2.56, which would make the photo too tall to fit on the screen.
To enlarge the photo proportionally, we need to scale it up by the same factor in both dimensions. Since we want to scale it so that its width matches the width of the screen, we can find the scaling factor by dividing the screen width by the photo width:
scaling factor = screen width / photo width = 1024 / 640 = 1.6
Now we can use this scaling factor to find the new height of the photo:
new height = photo height x scaling factor = 300 x 1.6 = 480 pixels
Therefore, after the photo is scaled up proportionally, its measurements are 1024 x 480 pixels.
2a. We can't enlarge the photo proportionally so that it is as tall as the computer screen because its aspect ratio (the ratio of its width to its height) is different from the aspect ratio of the screen. The photo's aspect ratio is 640/300 = 2.13, while the screen's aspect ratio is 1024/768 = 1.33. Enlarging the photo so that its height matches the screen's height would require stretching the photo vertically, which would distort the image.
2b. Scaling the width of the photo by a factor of 1024/640 and the height by a factor of 768/300 would not correct the difficulty in part (a) because it would not change the aspect ratio of the photo. The aspect ratio of the photo would still be 2.13, which is different from the aspect ratio of the screen. The photo would still need to be stretched vertically to match the screen's height, which would distort the image.
find the measure of angle PRT
measure of Angle PRT = 90 degrees
Step-by-step explanation:A circle with center T exists -- Given
Point R is on the the circle. -- THIS IS AN ASSUMPTION BASED ON THE PICTURE (if you have more information that makes this not true, the rest of this logic fails).
Line segment TR is the radius of the circle. -- Definition of radius
Line PR is tangent to the circle. -- PR touches at exactly one point: R
Angle PRT has a vertex as point R. -- definition of angle PRT
Since PR is tangent to the circle, TR is perpendicular to PR -- consequence of lines perpendicular to circles
Perpendicular lines form right angles. -- Consequence of two congruent angles that form a straight angle pair.
The measure of a right angle is 90 degrees. -- definition of right angle
Therefore, the measure of angle PRT is 90 degrees.
does a number being squared with x and being negative make it so it has to be multiplied by 2 like the first number in the third part of the question? I'm unsure where it came from
Squaring a number implies increasing it by itself. In case the number being squared is negative, the result will continuously be positive. Increasing a number by 2 implies multiplying it, which is not linked to squaring a number.
What is the number about?To square a number, one must raise it to the power of two, that is different from carrying out its multiplication with itself. One way of squaring a value is shown by taking the number 3 and raising it to the power of 2.
3² = 3 x 3 = 9
By the same way , if we raise -2 to the power of 2, the result will be a positive value of four.
Raising numbers to the power of two is a frequent mathematical procedure use in numerous academic fields such as algebra, geometry, physics, and statistics.
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Match the situation with its probability.
The given probabilities are as follows:
Spinner landing on at least one A = 7/16Spinner landing on C and D in any order = 1/8Spinner landing on two Bs = 1/16Spinner landing on C on the second spin = 1/4What are the probabilities?The probabilities are determined using the formula below:
Probability = number of expected outcome / number of total outcomesSpinner landing on at least one A:
number of at least one A = 7
Spinner landing on at least one A = 7/16
Spinner landing on C and D in any order:
number of landing on C and D in any order = 2
Spinner landing on C and D in any order = 2/16
Spinner landing on C and D in any order = 1/8
Spinner landing on two Bs:
number of landing on two Bs = 1
Spinner landing on two Bs = 1/16
Spinner landing on C on the second spin:
Number of landing on C on the second spin = 4
Spinner landing on C on the second spin = 1/4
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need help with this geometry problem
The shaded area of the circle is around 65.44 square meters in size.
How to find area?To find the area of the shaded region, subtract the area of sector FGH from the area of sector FEGH.
The area of sector FEGH is:
A1 = (1/2) r² θ₁
where r = radius of the larger circle and θ₁ = angle subtended by the arc EH.
Since EH = 30 m and the radius of the larger circle = 18 m (half of 10 + 8):
θ₁ = (EH arc length) / r = 30/18π radians
So,
A₁ = (1/2) (18)² (30/18π) = 270/π m²
The area of sector FGH is:
A₂ = (1/2) r² θ₂
where θ₂ = angle subtended by the arc GH.
Since GH is 8 m and the radius of the larger circle is 18 m:
θ2 = (GH arc length) / r = 8/18π radians
So,
A₂ = (1/2) (18)² (8/18π) = 64/π m²
Therefore, the area of the shaded region is:
A = A₁ - A₂ = (270/π) - (64/π) = 206/π ≈ 65.44 m²
Hence, the area of the shaded region is approximately 65.44 square meters.
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Please help! Daniel incorrectly solved the equations shown. Explain what he did wrong in each solution and then solve both equations correctly.
25x^2-16=9
√(25x^2 )-√16=√9
5x-4=±3
5x=±7
x=±7/5
z^3-2=6
z^3=8
∛(z^3 )=∛8
z=±2
Daniel incorrectly applied the square root to both terms on the left side of the equation and he forgot to take into account the possibility of multiple roots when solving for the cube root of z³.
Let's first look at the first equation that Daniel solved incorrectly:
25x²-16=9
Daniel's solution:
√(25x² )-√16=√9
5x-4=±3
5x=±7
x=±7/5
What Daniel did wrong here is that he incorrectly applied the square root to both terms on the left side of the equation.
Instead, he should have simplified the left side first, using the fact that √(a²) = |a|, before applying the square root. So the correct solution is:
25x²-16=9
25x²=25
x²=1
x=±1
Now let's look at the second equation that Daniel solved incorrectly:
z³-2=6
Daniel's solution:
z³=8
∛(z^3 )=∛8
z=±2
What Daniel did wrong here is that he forgot to take into account the possibility of multiple roots when solving for the cube root of z³.
In fact, z³ = 8 has three roots: z = 2, z = -1 + i√3, and z = -1 - i√3. So the correct solution is:
z³-2=6
z³=8
z=2
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14 A national standardized test is given in May that generates a mean score of 350 with a standard
deviation of 18. What is the probability that a randomly selected test score will fall in the
interval 360 to 380?
(1) 0.56
(2) 0.013
(3) 0.24
(4) 0.76
The probability that a randomly selected test score will fall in the interval 360 to 380 is the option (3), 0.24.
How to solveTo calculate the probability that a test score falls between 360 and 380, we need to standardize these values by subtracting the mean and dividing by the standard deviation.
This gives us:
z(360) = (360-350)/18 = 0.56
z(380) = (380-350)/18 = 1.67
We can then use a standard normal distribution table or a calculator to find the area under the curve between these two z-scores.
The probability is approximately 0.24.
Therefore, the answer is option (3), 0.24.
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Consider the letters in the word SAMPLE. In how many ways can you arrange 5 of the letters?
Answer: 720
Step-by-step explanation: There are 6 choices for the first letter, 5 for the second, 4 for the third and so on. 6*5*4*3*2=720
Step-by-step explanation:
according to the law of combination
⁵C6 note 6 is a base numberCombining formula: 6!/(6-1)! 6!solving 6!/5! 6! :120waysBree is replacing the wire on her farm paddock fences. She has measured a couple of the sides and drawn a sketch of the paddock shape. (pic below)
a. Find the two missing sides and calculate the perimeter of the paddocks
Perimeter?
b. The cost of fencing wire is $5 per meter. How much will the wire cost
Cost?
a. The perimeter of the paddock is 120 meters
b. The cost of the wire will be $600
a. To find the missing sides and calculate the perimeter of the paddock, let's analyze the given sketch.
The length of the missing side on the left can be determined by subtracting the known length of 10m from the total height of 20m. Therefore, the left side has a length:
20m - 10m = 10m.
The missing side on the right is equal in length to the known side of 40m.
Now we can calculate the perimeter by adding up all the side lengths:
Perimeter = 10m + 40m + 20m + 10m + 40m
= 120m.
b. To calculate the cost of the wire, we need to multiply the perimeter of the paddock by the cost per meter of fencing wire, which is $5/m.
Wire Cost = Perimeter × Cost per meter
= 120m × $5/m
= $600.
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Which of the following is a biconditional statement?
A) If x2 = 25, then x = 5 or x = –5
B) x = 5 if x2 = 25
C) x = 5 if and only if x + 5 = 10
D) If x ≠ 5 then x2 ≠ 25
Answer:
C) x = 5 if and only if x + 5 = 10
Step-by-step explanation:
You want to identify the biconditional statement among those that are given.
ConditionalA conditional statement is of the form ...
If P, then Q.
ConverseThe converse of the above conditional statement is ...
If Q, then P.
BiconditionalWhen both the statement and its converse are intended, the statement can be written as the biconditional ...
If and only if P then Q.
The given example of a biconditional statement is ...
x = 5 if and only if x +5 = 10.
__
Additional comment
This can be abbreviated ...
Iff P then Q
meaning "if P then Q, and if Q then P", or "if and only if P, then Q."
A supermarket sells fruit snacks by the box. AEach box holds x pachages of strawberry snacks and y packages of cherry snacks. Nina bought 6 boxes.
Write two expressions for home many more strawberry packages than cherry packages nina bought. Then write what the few expressions being equivalent mean in terms of the situation
The two equivalent expressions are 6(x − y) and 6x − 6y.
What are the equivalent expressions?These expressions look different but their simplified forms are same expressions are called equivalent expressions.
The 1st expression shows subtracting the number of packages of cherry snacks from the number of packages of strawberry snacks in each box.
When we multiplying the difference by the number of boxes then, it will be: 6(x-y)
Now, total number of cherry snacks and subtracting it from the total number of strawberry snacks will be 6x - 6y. So, equivalent expressions means in terms of situation are 6(x − y) and 6x − 6y.
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what is the slope of the line below?
Answer:
B. Y= 5x - 2
Step-by-step explanation:
The Y is negative, you can see the number -5 below the point, if you go to the top, that is, to 0 and count down, the lines are two and the X is positive 5, you can see where the number 5 is and the point is above.
Write an equation in standard form
The equation of the quadratic with a directrix of x = 2 and vertex of (0 , 0) is: y² = -8x
The equation of the quadratic with a directrix of y = 4 and vertex of (1, 3) is: (x - 1)² = -4 (y - 3)
How to write the equation of parabola with directrix of x = 2 and vertex of (0, 0)Quadratic equation when the directrix is at x direction is of the form:
(y - k)² = 4P (x - h)
OR
standard vertex form, x = a(y - k)² + h where a = 1/4p
The vertex
v (h, k) = (0, 0)
P in this problem, is the distance between the vertex and the directrix
P = 0 - 2 = -2
substitution of the values into the equation gives
(y - k)² = 4P (x - h)
(y - 0)² = 4 x -2 (x - 0)
y² = -8x
Quadratic equation when the directrix is at y direction is of the form:
(x - h)² = 4P (y - k)
OR
standard vertex form, y = a(x - h)² + k where a = 1/4p
The vertex
v (h, k) = (1, 3)
P in this problem, is the distance between the vertex and the directrix
P = 3 - 4 = -1
substitution of the values into the equation gives
(x - h)² = 4P (y - k)
(x - 1)² = 4 * -1 (y - 3)
(x - 1)² = -4 (y - 3)
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what’s the numbers that correspond to the corret number of solutions
The number of solutions for the given system of linear equations is: Infinitely many solutions.
Calculating the number of solutionsTo determine the number of solutions for the given system of linear equations:
3x - y = 4
6x - 2y = 8
We can use the algebraic method of solving the system of equations by substitution or elimination.
Let's use the algebraic method to determine the number of solutions:
3x - y = 4 (1)
6x - 2y = 8 (2)
We can simplify equation (2) by dividing both sides by 2:
3x - y = 4 (1)
3x - y = 4 (2')
Equations (1) and (2') are equivalent, which means that they represent the same line.
Therefore, the two equations represent the same line, and we have infinitely many solutions.
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Complete question
What’s the numbers that correspond to the corret number of solutions
0 solution, 1 solution, Many solutions
3x - y = 4
6x - 2y = 8
Julie was testing how far two new electric cars—model A and model B—could drive on a full charge. She obtained a sample of 5 55 new cars of each model, charged them fully, and drove them as far as she could along a controlled route. Here is a summary of the distances: Distance Model A Model B Mean 168 km 168 km168, start text, space, k, m, end text 172 km 172 km172, start text, space, k, m, end text Standard deviation 5.4 km 5.4 km5, point, 4, start text, space, k, m, end text 7.5 km 7.5 km7, point, 5, start text, space, k, m, end text Number of cars 5 55 5 55 Julie wants to use these results to test H 0 : μ A − μ B = 0 H 0 : μ A −μ B =0start text, H, end text, start subscript, 0, end subscript, start text, colon, space, end text, mu, start subscript, start text, A, end text, end subscript, minus, mu, start subscript, start text, B, end text, end subscript, equals, 0 versus H a : μ A − μ B ≠ 0 H a : μ A −μ B =0start text, H, end text, start subscript, start text, a, end text, end subscript, start text, colon, space, end text, mu, start subscript, start text, A, end text, end subscript, minus, mu, start subscript, start text, B, end text, end subscript, does not equal, 0. Assume that these are representative samples and all other conditions have been met. What is the P-value associated with these sample results? Choose 1 answer: Choose 1 answer: (Choice A) P -value < 0.01 P-value<0.01P, start text, negative, v, a, l, u, e, end text, is less than, 0, point, 01 A P -value < 0.01 P-value<0.01P, start text, negative, v, a, l, u, e, end text, is less than, 0, point, 01 (Choice B) 0.01 ≤ P -value < 0.05 0.01≤P-value<0.050, point, 01, is less than or equal to, P, start text, negative, v, a, l, u, e, end text, is less than, 0, point, 05 B 0.01 ≤ P -value < 0.05 0.01≤P-value<0.050, point, 01, is less than or equal to, P, start text, negative, v, a, l, u, e, end text, is less than, 0, point, 05 (Choice C) 0.05 ≤ P -value < 0.10 0.05≤P-value<0.100, point, 05, is le
The p value based on the information will be E. P - value ≥ 0.20
How to compute the valueOpen Minitab 17. Select 'Stat' -> 'Basic Statistics' -> '2 - Sample t... Select 'Summarized data' from the dropdown menu.
Enter 5 in both Sample size of sample 1 and sample 2, 168 and 172 in Sample mean of Sample 1 and Sample 2. 5.4 and 7.5 in Standard deviation of Sample 1 and Sample 2.
Click on 'Options' and Enter 'Confidence level' 95.0(or the given Cofidence level) , 'Hypothesized difference' 0.0 , 'Alternative hypothesis' 'Difference \\neq Hypothesized difference'. Also the box 'Assume equal variance' can be ticked as requirement.
Click on 'Ok' -> 'Ok'.
Output: -
P - value = 0.361 i.e., P - value ≥ 0.20
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Someone please help!! (20 POINTS!)
Answer: C
Step-by-step explanation: Rise/run so 1/1=1 but it's going down so it negative. -1
A motorist travelled from Town A to Town B. After travelling for 1 1/2 hours , he passed
a cyclist travelling at an average speed of 45 Km/h in the opposite direction.
when the motorist reached Town B 2 h later, the cyclist was 30 km away from Town A.
a) Find the average speed of the motorist.
b) Find the distance between Town A and Town B.
Answer:
the formula: Speed = Distance / Time.
Let's break down the problem into two parts:
a) Find the average speed of the motorist.
Let's assume the average speed of the motorist is "v" km/h.
The distance the motorist traveled in 1 1/2 hours is given by: Distance = Speed × Time = v × (3/2) km.
The distance the cyclist traveled in 1 1/2 hours (opposite direction) is given by: Distance = Speed × Time = 45 × (3/2) km.
Since they passed each other, the sum of their distances should be equal to the distance between Town A and Town B.
So, we can set up the equation: v × (3/2) + 45 × (3/2) = Distance between Town A and Town B.
b) Find the distance between Town A and Town B.
When the motorist reached Town B 2 hours later, the cyclist was 30 km away from Town A.
We can set up the equation: Distance between Town A and Town B = v × 2 + 30.
Now, let's solve the equations:
v × (3/2) + 45 × (3/2) = v × 2 + 30.
Simplifying the equation, we have: (3v + 135)/2 = 2v + 30.
Multiplying both sides of the equation by 2 to eliminate the fraction, we get: 3v + 135 = 4v + 60.
Subtracting 3v from both sides of the equation, we have: v = 75.
Therefore, the average speed of the motorist is 75 km/h.
To find the distance between Town A and Town B, we substitute the value of v into the equation:
Distance between Town A and Town B = v × 2 + 30 = 75 × 2 + 30 = 150 + 30 = 180 km.
Therefore, the distance between Town A and Town B is 180 km.
Solve the equation for x -4X+3=11
Answer:
x = -2
Step-by-step explanation:
-4x + 3 = 11
Subtract 3 from both sides:
-4x = 8
Divide both sides by -4:
x = -2
A net of a rectangular prism is shown.
A net of a rectangular prism with dimensions 7 centimeters by 3 and three-fifths centimeters by 2 and two-fifths centimeters.
What is the surface area of the prism?
Answer:
The surface area of a rectangular prism is calculated by adding the areas of all six faces. The formula for the surface area of a rectangular prism is 2lw + 2lh + 2wh, where l is the length, w is the width and h is the height.
In this case, the length is 7 cm, the width is 3 and three-fifths cm (or 3.6 cm), and the height is 2 and two-fifths cm (or 2.4 cm). Plugging these values into the formula gives us a surface area of 2(7) (3.6) + 2(7) (2.4) + 2(3.6) (2.4), which simplifies to 50.4 + 33.6 + 17.28, or 101.28 square centimeters.
So, the surface area of this rectangular prism is 101.28 square centimeters.
Received message. The surface area of a rectangular prism is calculated by adding the areas of all six faces. The formula for the surface area of a rectangular prism is `2lw + 2lh + 2wh`, where `l` is the length, `w` is the width and `h` is the height. In this case, the length is 7 cm, the width is 3 and three-fifths cm (or 3.6 cm), and the height is 2 and two-fifths cm (or 2.4 cm). Plugging these values into the formula gives us a surface area of `2(7)(3.6) + 2(7)(2.4) + 2(3.6)(2.4)`, which simplifies to `50.4 + 33.6 + 17.28`, or **101.28 square centimeters**. So, the surface area of this rectangular prism is **101.28 square centimeters**.
Step-by-step explanation:
Where will X be after a rotation 90° clockwise about (-5,-1)?
Click on the grid to place the point.
The image point of the coordinate X after the rotation is (-1, 5).
Calculating the image point of the coordinate XWhen a point is rotated 90° clockwise around the origin, the new point will be formed by switching the x and y-coordinates and then negating the new x-coordinate.
So for point X (-5, -1), the new x-coordinate will be -1, and the new y-coordinate will be -(-5) = 5, giving the new point (-1, 5).
Therefore, after a rotation of 90° clockwise, point X (-5, -1) will be at the new location (-1, 5).
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You are trying to determine if a router you’re thinking of purchasing will give off a strong enough wifi signal to cover the area in your house. The router you have selected will cover an area of 850 ft^2.
According to the information, the router cannot cover the kitchen area.
Does the router cover the kitchen area?To calculate if the router covers the kitchen area, we must identify the area that the router can cover. In this case, the router covers an area of 850 square feet. However, we must take into account that this area is counted around the router. So, we have to calculate the square root of 850 ft^2.
[tex]\sqrt{850}[/tex] = 29.129.1 / 2 = 14.5From the above, we can infer that the router has signal coverage of 14 meters around it, so it would only cover the living room area.
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