Answer:
The value is [tex]F = 1.568 *10^{-9} \ N[/tex]
Explanation:
From the question we are told that
The mass of the first lead sphere is [tex]m = 1.60 \ kg[/tex]
The mass of the second lead sphere is [tex]M = 16 \ g = 0.016 \ kg[/tex]
The separation between masses is [tex]r = 3.30 \ cm = 0.033 \ m[/tex]
Generally the gravitational force between each sphere is mathematically represented as
[tex]F = \frac{G * m * M }{r^2 }[/tex]
Here G is the gravitational constant with value [tex]G = 6.67 *10^{-11 } \ m^3 \cdot kg^{-1} \cdot s^{-2}[/tex]
[tex]F = \frac{6.67 *10^{-11 } * 1.60 * 0.016 }{0.033^2 }[/tex]
=> [tex]F = 1.568 *10^{-9} \ N[/tex]
Jared is driving around a traffic circle. If he is traveling at a speed of 7.1 m/s, and it takes his 5.8 s to complete an entire loop around the traffic circle, what is the radius of the traffic circle?
A. 7.1 m
B. 6.6 m
C. 9.4 m
D. 5.6 m
Answer:
B. 6.6 m
Explanation:
Given;
speed of Jared , v = 7.1 m/s
time taken, T = 5.8 s
let the radius of the traffic circle = r
The speed of Jared is calculated as;
[tex]v = \frac{2\pi r}{T}[/tex]
Where;
v is speed of Jared
T is period of the motion
r is radius of the traffic circle
[tex]r = \frac{vT}{2\pi} \\\\r = \frac{7.1 \ \times \ 5.8}{2\pi} \\\\r = 6.55 \ m\\\\r = 6.6 \ m[/tex]
Therefore, the radius of the traffic circle is 6.6 m.
A roller coaster travels around a vertical 8-m radius loop. Determine the speed at the top of the loop if the normal force exerted by the seats on the passengers is equal to ¼ of their weight.
Answer:
[tex]v=10m/sec[/tex]
Explanation:
From the question we are told that
Radius of vertical r= 8m
Force exerted by passengers is 1/4 of weight
Generally the net force acting on top of the roller coaster is give to be
[tex]F_N+Fg[/tex]
where
[tex]F_N =forceof the normal[/tex]
[tex]Fg= force due to gravity[/tex]
Generally the net force is given to be [tex]FC(force towards center)[/tex]
[tex]F_C =F_N + Fg[/tex]
[tex]F_N =F_C -Fg[/tex]
[tex]F_N=F_C-F_g[/tex]
[tex]F_N=\frac{mv^2}{R} -mg[/tex]
Mathematical we can now derive V
[tex]m_g + \frac{8m}{4}= \frac{mv^2}{8}[/tex]
[tex]\frac{5mg}{4} =\frac{mv^2}{8}[/tex]
[tex]v^2 =\frac{40*10}{4}[/tex]
[tex]v=10m/sec[/tex]
Therefore the speed of the roller coaster is given ton be [tex]v=10m/sec[/tex]
[tex]v=10m/s[/tex]
Given:
Radius of vertical r= 8m
To find:
Force exerted by passengers is 1/4 of weight
Generally the net force acting on top of the roller coaster is give to be
[tex]F_N+F_g[/tex]
where
[tex]F_N=\text{Force of Normal}[/tex] and [tex]F_g=\text{Force due to gravity}[/tex]
Generally the net force is given to be [tex]FC- \text{Force towards centre}[/tex]
[tex]F_C=F_N+F_g\\\\F_N=F_C+F_g\\\\F_N=\frac{mv^2}{r} -mg[/tex]
Mathematically we can now derive V
[tex]mg-\frac{8m}{4} =\frac{mv^2}{8}\\\\\frac{5mg}{4}=\frac{mv^2}{8}\\\\v^2=\frac{40*10}{4} \\\\v=10m/s[/tex]
Therefore, the speed of the roller coaster is given to be 10m/s.
Learn more:
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Problem 4: For a conservative force,esvoedca2beee49af123450c68a7237065a45ad885a4229cb932c3697d0b27c6328eaeovse 0N86-C1-52-40-A837-22820 If you push a wooden crate across rough ground with a force F over a distance d, what is the potential energy stored in the system due to this force
Answer:
PE = Fd
Explanation:
Potential energy is the energy possessed by a body by virtue of its position. It is expressed mathematically as:
PE = mgd
m is the mass
g is the acceleration due to gravity
d is the distance
Since Force F is expressed as the product of mass and acceleration due to gravity then, F = mg
Substitute into the formula above:
Recall that: PE = mgd
Since F = mg
PE = Fd
Hence the required expression is PE = Fd
The is the sac-like structure that holds the testes.
Answer:
Scrotum
Explanation:
Answer: Scrotum
Explanation: edge
For the following types of electromagnetic radiation, how do the wavelength, frequency, and photon energy change as one goes from the top of the list to the bottom?
a. radio waves
b. infared radiation
c. visible light
d. ultraviolet radiation
e. gamma radiation
Answer:
Wavelength, frequency and the photon energy changes as the one goes across the ranges of the electro-magnetic radiations.
Explanation:
Electro-magnetic radiations may be defined as the form of energy that is radiated or given by the electro-magnetic radiations. The visible light that we can see is the one of the electro-magnetic radiations. Other forms are the radio waves, gamma waves, UV rays, infrared radiations, etc.
The wavelength of the radiations decreases as we go from a. radio waves -- b. infrared radiation -- c. visible light -- d. ultraviolet radiation -- e. gamma radiation.
The frequency of the radiations increases when we move from a. radio waves -- b. infrared radiation -- c. visible light -- d. ultraviolet radiation -- e. gamma radiation.
The photon energy of the radiations increases when we move from a. radio waves -- b. infrared radiation -- c. visible light -- d. ultraviolet radiation -- e. gamma radiation.
(a) What is lightning?
A hydrogen atom that has lost its electron is moving east in aregion where the magnetic field is directed from south to north. Itwill be deflected:_____________
a. up
b. down
c. not at all
Answer:
a. up
Explanation:
As per the rule of Fleming left hand, the three fingers should be places in a perpendicular manner i.e. mutually also.
The fore finger depicts the field direction
The middle finger depicts the velocity
And, the thumb finger depicts the force direction that experienced on that particle i.e. charged
So the electrons would be deflects to up
Hence, the correct option is a.
An object is moving with constant speed in a
circular path. The object's centripetal
acceleration remains constant in
(1) magnitude, only
(2) direction, only
(3) both magnitude and direction
(4) neither magnitude nor direction
Answer:
both magnitude and direction
Explanation:
When an object moves in a circular path, its motion is called uniform circular motion. In this motion, the force acting on it is centripetal force and it is moving under centripetal acceleration. This type of force acts towards the centre of the circle.
In this type of motion, the speed remains constant while the velocity keeps on changing. The object's centripetal acceleration remains constant in magnitude as well as direction.
Hence, the correct option is (3).
If an object is moving with constant speed in the circular path the object's centripetal acceleration remains constant in both magnitude and direction
The formula for calculating the centripetal acceleration of an object is expressed as:
[tex]a =\frac{v^2}{r}[/tex]
v is the speed of the objectr is the radius of the circular pathIf the speed of the object is constant, the acceleration is of the body is also constant.Hence if an object is moving with constant speed in the circular path the object's centripetal acceleration remains constant in both magnitude and direction
Learn more on centripetal acceleration here: https://brainly.com/question/79801
1. A series circuit has three resistors, each on different paths and connected to a 120 V battery. Resistor 1 has a resistance of 5.0 Ω, Resistor 2 has a resistance of 7.5 Ω, and Resistor 3 has a resistance of 9.5 Ω. Create the circuit using the PhET simulator, and then draw a picture of the circuit you made. Then, fill in the table below for this circuit. Show your work completed. Measurements and the corresponding units Resistor 1 Resistor 2 Resistor 3 Total V (volts) 120 V I (A – amperes) R (Ω – ohms) 5.0 Ω 7.5 Ω 9.5 Ω P (W – work) Show your work: I=Vtotal/Rtotal. This gives you the total, I, which then allows you to calculate Ohm’s law for the other individual resistors. The total voltage spread across the three resistors should equal the total number of voltage periods. The power is determined by P 5 I 3 V.
Answer:
Measurements/cor. units Resistor 1 Resistor 2 Resistor 3 Total
V (volts) 24V 16V 12.63V 120 V
I (A – amperes) 4.8A 2.13A 1.34A 5.45A
R (Ω – ohms) 5.0 Ω 7.5 Ω 9.5 Ω 22Ω
P (W – work) 115.2W 34.08W 16.92W 2,640W
Which of the following is an instantaneous speed?
A: All of the above
B: 80 ft/s
C. 80 yds./min
D. 80 km/hr
Answer:
A: All of the above
Explanation:
The instantaneous speed of an object is simply the current seed of the object at any given time. The SI unit is m/S and it is a vector quantity.
Therefore, according to the given options, they all have SI units that are consistent with distance and time which makes them all an example of instantaneous speed.
The picture shows a basic diagram of an electric motor. At top left a piece of magnet labeled N and at top right a piece labeled S. Between these a square coil of wire X sits attached to a metal rod, which runs between the 2 pieces of magnet. 2 semicircular pieces Z of metal surround the rod at its opposite end from the pieces of magnet. Wires connect to each semicircular piece at terminals Y to one pole of a battery. Blue arrows superimposed on the end of the coil away from the magnets point toward S and away from N. Which labels best complete the diagram? X: Brush Y: Armature Z: Commutator X: Commutator Y: Brush Z: Armature X: Armature Y: Commutator Z: Brush X: Armature Y: Brush Z: Commutator Mark this and return
Answer:
I know this isn't much help but its not B
Explanation:
Answer:
D
Explanation:
Calculate the translational speed of a cylinder when it reaches the foot of an incline 7.05 mm high. Assume it starts from rest and rolls without slipping.
Height is 7.05 m and not 7.05 mm
Answer:
9.603 m/s
Explanation:
We are dealing with rotation, so velocity of centre of mass is given by;
v_cm = Rω
Since we are working with a solid cylinder, moment of inertia of the cylinder is; I = ½mR²
Since it is rolled from the top to the bottom, at the top it will have potential energy(mgh) while at the bottom it will have kinetic energy (rotational plus translational kinetic energy).
Using conservation of energy, we have:
P.E = K.E_t + K.E_r
Formula for rotational and kinetic energy here are;
K.E_t = ½mv²
K.E_r = ½Iω²
mgh = ½mv² + ½Iω²
Since we want to find translational speed(v), let's get rid of ω.
Earlier, we saw that v_cm = Rω
Thus; ω = v/R
Also, we know that I = ½mR².
Thus;
mgh = ½mv² + ½(½mR²)(v/R)²
This gives;
mgh = ½mv² + ¼mv²
Divide through by m to get;
gh = v²(½ + ¼)
gh = ¾v²
Making v the subject gives;
v = √(4gh/3)
v = √((4 × 9.81 × 7.05)/3)
v = 9.603 m/s
Based on the three-cell model of global circulation, surface winds diverge in the vicinity of:________.
a. the polar front
b. subpolar lows
c. the equator
d. the north and south poles
Answer:
a. the polar front
Explanation:
When the surface winds move towards the pole at angles that range from 30 to 60 degrees, they usually collide with cold air moving towards the equator. Since these two winds do not mix with ease, the polar front helps to separate them.
The three-cell model assumes that the earth is entirely filled with water thus removing any interactions with the land. It also assumes that there are no seasons nor Coriolis force.
a slingshot is used to shoot a small ball upward into the air; when the pouch is released, the sling propels the ball upward. assuming no air resistance, as the ball is propelled upward, what kind of energy transformation is taking place
kinetic to gravitational potential
gravitational potential to kinetic
gravitational potential to chemical
chemical to kinetic
Explanation:
kinetic to gravitational
In a perfectly inelastic one-dimensional collision between two objects, what initial condition alone is necessary so that all of the original kinetic energy of the system is gone after the collision
Answer:
The objects must have moments with the same magnitude but opposite directions.
Explanation:
The condition alone that is necessary in order to make the final kinetic energy of the system to be zero after the collision is that the objects must have moments that are the same in magnitude but have opposite directions.
If an electric iron of 1200W is used for 30minutes every day, find electric energy consumed in the month of November. Also calculate bill amount if the rate of 1 unit = Rs 2
Answer:
Electric energy produced in the month of April is 18 kWh
Explanation:
Given
P = 1200 W = 1.2 kW
Use time per day = 30 minutes = 1 / 2 hrs
We know,
No. of days in April = 30 days
Total time iron being used
T = 1 / 2 * 30 = 15 hrs
We know,
Energy consumed = Pt
Substituting the value of P and T
= 1.2 kW * 15 hr
= 18 kWh
Hence,
Electric energy produced in the month of April is 18 kWh
From the gravitational law calculate the weight W (gravitational force with respect to the earth) of a 89-kg man in a spacecraft traveling in a circular orbit 261 km above the earth's surface. Express W in both (a) newtons and (b) pounds.
Answer:
[tex]W=\frac{773}{4.45}=173.76 l b f[/tex]
Explanation:
[tex]W=\frac{G \cdot m_{e} \cdot m}{(R+h)^{2}}[/tex]
The law of gravitation
[tex]G=6.673\left(10^{-11}\right) m^{3} /\left(k g \cdot s^{2}\right)[/tex]
Universal gravitational constant [S.I. units]
[tex]m_{e}=5.976\left(10^{24}\right) k g[/tex]
Mass of Earth [S.I. units]
[tex]m=89 kg[/tex]
Mass of a man in a spacecraft [S.I. units]
[tex]R=6371 \mathrm{~km}[/tex]
Earth radius [km]
Distance between man and the earth's surface
[tex]h=261 \mathrm{~km} \quad[\mathrm{~km}][/tex]
ESULT [tex]W=\frac{6.673\left(10^{-11}\right) \cdot 5.976\left(10^{24}\right) \cdot 89}{\left(6371 \cdot 10^{3}+261 \cdot 10^{3}\right)^{2}}=773.22 \mathrm{~N}[/tex]
[tex]W=\frac{773}{4.45}=173.76 l b f[/tex]
A hockey puck sliding on smooth ice at 4 m/s comes to a 1-m-high hill. Will it make it to the top of the hill?
Answer:
No it will not make to the top of the hill
Explanation:
From the question we are told that
The velocity is [tex]v = 4 \ m/s[/tex]
The height of the hill is [tex]h = 1 \ m[/tex]
Generally from the law of energy conservation we have that
The kinetic energy of the pluck at the level position = The potential energy of the pluck at the maximum height the pluck can get to
So
[tex]\frac{1}{2} * m * v^2 = m * g * h_{max}[/tex]
=> [tex]\frac{1}{2} * v^2 = g * h_{max}[/tex]
=> [tex]h_{max} = \frac{0.5 * v^2}{g}[/tex]
=> [tex]h_{max} = 0.8163 \ m[/tex]
Given that the maximum height which the pluck can get to at this speed given in the question is less than the height of the hill then conclusion will be that the pluck will not make it to the top of the hill
SOMEBODY ONCE TOLD ME THE WORLD WAS GONNA ROLL ME
I AIN'T THE SHARPEST TOOL IN THE SHED~
SHE WAS LOOKING KINDA DUM WITH HER FINGER AND HER THUMB
IN THE SHAPE OF AN "L" ON HER FOREHEAD~
WELL THE YEARS START COMING AND THEY DON'T STOP COMING
FED TO THE RULES AND I HIT THE GROUND RUNNING
DIDN'T MAKE SENSE NOT TO LIVE FOR FUN
YOUR BRAIN GETS SMART BUT YOUR HEAD GETS DUM
SO MUCH TO DO, SO MUCH TO SEE--
SO WHATS WRONG WITH TAKING THE BACKSTREETS?
YOU'LL NEVER KNOW IF YOU DON'T GO
YOU'LL NEVER SHINE IF YOU DON'T GLOW.
Answer:
shrek
Explanation:
allstar
Compare and contrast Infra-red, visible light and UV.
Answer:
The EM radiation most immediately lower-frequency than visible light is called infrared, and the EM radiation most immediately higher-frequency is called ultraviolet.
Which of the following terms refers to the gas that escapes a comet?
O Adust tail
OAplasma tail
O An asteroid
O Ameteorite
Answer:
The correct option is "a plasma tail"
Explanation:
Gases escaping from a comet are ionized by ultraviolent rays from the sun. These ionized gases are then carried away from the sun by the solar wind to form the plasma tail. While the plasma tail is made up of gases, the dust tail is made up of tiny solid particles (dust) that escapes from the comet and are also pushed away from the sun.
why is heat called a form of energy?
Answer:
Because heat can be converted from one form to another.
Heat is also does work, for example it sets water molecules into motion when boiling ( convection currency ).
since energy is the ability to do work, heat does work.
What us the difference in the ways objects move at a speed of a car and an object mkvinf close to the speed of light?
Answer:
The difference is in who or what is observing the speed.
Explanation:
Giving that speed is relative between the objects and the reference point from which it is being observed.
It is concluded that speed alone has no direct effect on a moving object, hence it is just a determining unit for the difference in distance between two objects.
Therefore, in this case, the difference is in who or what is observing the speed.
I’m confused help me
Answer:
you select what ever feels right to you if you think what it tells you is true then you would say strongly agree and if you don't agree then it would be any of the other options
A solenoid 30 cm long is wound with 250 turns of wire. The cross-sectional area of the coil is 3.5 cm^2. What is the self-inductance of the solenoid?
Answer:
The value is [tex]L = 9.164 *10^{-5} \ H[/tex]
Explanation:
From the question we are told that
The length of the solenoid is [tex]l = 30 \ cm = 0.3 \ m[/tex]
The number of turns is [tex]N = 250 \ turns[/tex]
The cross-sectional area is [tex]A = 3.5 \ cm^2 = 3.5 *10^{-4} \ m^2[/tex]
Generally the self inductance of the solenoid is
[tex]L = \frac{\mu_o * N^2 * A }{ l }[/tex]
Here [tex]\mu_o[/tex] is the permeability of free space with value [tex]\mu_o = 4\pi *10^{-7} \ T \cdot m/A[/tex]
So
[tex]L = \frac{ 4 \pi*0^{-7} * 250^2 * 3.5 *10^{-4} }{ 0.3 }[/tex]
=> [tex]L = 9.164 *10^{-5} \ H[/tex]
A ball is thrown horizontally from the top of a building 100m high. The ball strikes the ground at a point 120 m horizontally away from and below the point of release. What is the magnitude of its velocity just before it strikes the ground?
Answer:
44.3 m/s
Explanation:
Given that a ball is thrown horizontally from the top of a building 100m high. The ball strikes the ground at a point 120 m horizontally away from and below the point of release.
What is the magnitude of its velocity just before it strikes the ground ?
The parameters given are:
Height H = 100m
Since the ball is thrown from a top of a building, initial velocity U = 0
Let g = 9.8m/s^2
Using third equation of motion
V^2 = U^2 + 2gH
Substitute all the parameters into the formula
V^2 = 2 × 9.8 × 100
V^2 = 200 × 9.8
V^2 = 1960
V = 44.27 m/s
Therefore, the magnitude of its velocity just before it strikes the ground is 44.3 m/s approximately
An object has an average acceleration of + 6.24 m/s ^ 2 for 0.300 s . At the end of this time the object's velocity is + 9.31 m/s . What was the object's initial velocity?
Answer:
initial velocity = 7.44 m/s (3 s.f.)
Explanation:
a = 6.24 m/s² t = 0.300 s v = 9.31 m/s u = ?
v = u + at
9.31 = u + (6.24 x 0.300)
9.31 = u + 1.872
u = 7.438
= 7.44 m/s (3 s.f.)
Hope this helps!
A wheel rolling on a horizontal surface with an angular speed of 2.5 rad/s gets on a ramp and rolls down the ramp with a constant angular acceleration of 2.0 rad/s2. If it takes 11.5 us to reach the bottom of the ramp, what is the final angular speed of the wheel at the bottom
Answer:
the final angular speed of the wheel at the bottom is 25.5 rad/s
Explanation:
The computation of the final angular speed of the wheel at the bottom is as follows:
As we know that
[tex]W_f = W_{in} + \alpha t\\\\= 2.5 + (2 \times 11.5)\\\\= 2.5 + 23\\\\= 25.5 rad/s[/tex]
Hence, the final angular speed of the wheel at the bottom is 25.5 rad/s
We simply applied the above formula so that the final angular speed could come
A cylindrical tank of radius R, filled to the top with a liquid, has a small hole in the side, of radius r, at distance d below the surface. Find an expression for the volume flow rate Q through the hole. Do not leave in terms of velocities, only leave in terms of r, R and d.
Answer:
Explanation:
v₁ , v₂ be velocity of flow of water at the surface and hole , h₁ and h₂ be height of surface and hole , P₁ and P₂ be pressure at surface and hole .
Using Bernoulli's formula for flow of liquid in tank
1/2 ρ v₁² + ρgh₁ + P₁ = 1/2 ρ v₂² + ρgh₂ + P₂
P₁ = P₂
1/2 ρ v₁² + ρgh₁ = 1/2 ρ v₂² + ρgh₂
1/2 ( v₁² - v₂² ) = g(h₂ -h₁ )
v₁² - v₂² = - 2gd
a₁ v₁ = a₂ v₂
π R² v₁ = π r² v₂
v₁ = r² v₂ / R²
v₁² - v₂² = -2gd
r⁴ v₂² / R⁴ - v₂² = -2gd
v₂² ( R⁴ - r⁴ ) = 2gd R⁴
v₂² = 2gd R⁴ / ( R⁴ - r⁴ )
v₂ = √ [ 2gd R⁴ / ( R⁴ - r⁴ ) ]
How does heat from the sun affect Earth's spheres?
Answer:
1)The heat from the sun is one of the causes of rainfall.
2) It also causes thermal equilibrium on the earth's surface.
Explanation:
1) Heat from the sun heard of the water bodies, covers some to vapor which is taking up too form rains and snow.
2) Without the heat of the sun the only source of heart for the earth would be the geothermal heat (ie. the heat from within the earth). This type of heart wouldn't be enough to keep us warm because of the presence of the glaziers