In a recent election 59% of people supported re-electing the incumbent. Suppose a poll is done of 1230 people. If we used the normal as an approximation to the binomial, what would the mean and standard deviation be? Please show formulas used in excel

Answer:

13.6 miles/minute

Step-by-step explanation:

We Know

A plane travels 462.4 miles in 34 minutes.

Identify the constant of proportionality in the situation..

We Take

462.4 / 34 = 13.6 miles/minute

So, the answer is 13.6 miles/minute

Answer:

d=1

Step-by-step explanation:

(i have to write this cuz i cant write less than 20 words)

we know that the spinner has an equal chance of landing on each section. Since there are a total of six sections on the spinner, we can assume that the probability of the arrow landing on any one section is 1/6 or approximately 0.1667.

Now, if the arrow is spun 72 times, we can use this probability to calculate the expected number of times the arrow will land on 4. To do this, we simply multiply the probability by the number of spins, as follows:

Expected number of times arrow lands on 4 = Probability of arrow landing on 4 x Number of spins
Expected number of times arrow lands on 4 = 0.1667 x 72
Expected number of times arrow lands on 4 = 12

So, we can expect the arrow to land on 4 approximately 12 times out of 72 spins. Of course, this is just an expected value, and the actual number of times the arrow lands on 4 may vary from this value due to random chance.

In summary, if we assume that the arrow on the spinner is equally likely to land on each section, and it is spun 72 times, we can expect the arrow to land on 4 approximately 12 times based on probability calculations.

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The correct equation that represents Finley's annual salary, f(n), during the nth year is: [tex]f(n) = 56,000(1.06)^(n-1)[/tex] Thus, option D is correct.

What is an equation?

Finley's annual salary increases by 6% each year. This means that the salary for the second year is 6% more than the salary for the first year, the salary for the third year is 6% more than the salary for the second year, and so on.

To find an equation for Finley's annual salary during the nth year, we can use the initial salary of $[tex]56,000[/tex] and the fact that the salary increases by 6% each year. One way to write this equation is:

[tex]f(n) = 56,000(1.06)^(n-1)[/tex]

Here, the expression (1.06)^(n-1) represents the 6% increase in salary each year, starting from the second year (hence the (n-1) exponent). Multiplying this by the initial salary of $56,000 gives the salary for the nth year.

Therefore, the correct equation that represents Finley's annual salary, f(n), during the nth year is:[tex]f(n) = 56,000(1.06)^(n-1)[/tex]

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The z-score is -1.2, rounded to the tenths place.

The center of the histogram would be around the population mean of 266 days.

The standard deviation of the histogram would be the standard error of the mean, which is the standard deviation of the population divided by the square root of the sample size. Thus, the standard deviation of the histogram would be 10 / sqrt(100) = 1 day.

To calculate the z-score for a sample mean of 264.8 days, we can use the formula:

z = (sample mean - population mean) / (standard deviation / sqrt(sample size))

Substituting the given values, we get:

z = (264.8 - 266) / (10 / sqrt(100)) = -1.2

Therefore, the z-score is -1.2, rounded to the tenths place.

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Knowing that tan(x) = 3/5 and using a trigonometric identity, we will get that:

tan(2x) = 1.875

There is a trigonometric identity we can use for this, we know that:

[tex]tan(2x) = \frac{2tan(x)}{1 - tan^2(x)}[/tex]

So we only need to knos tan(x), which we already know that is equal to 3/5, then we can replace it in the formula above to get:

[tex]tan(2x) = \frac{2*3/5}{1 - (3/5)^2}\\\\tan(2x) = \frac{6/5}{1 - 9/25} \\tan(2x) = 1.875[/tex]

That is the value of the tangent of 2x.

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The slope of UF is 1/6

The slope of a line is a measure of its steepness. Mathematically, slope is calculated as "rise over run" (change in y divided by change in x).

The slope is given = change in point on y axis/ change in point on x axis

slope = y2-y1/x2-x1

The cordinate of F = (-2,-3) and U ( 4, -2)

y1 = -3 and y2 = -2

x1 = -2 and x2 = 4

slope = -2-(-3)/4-(-2)

= -2+3/(4+2)

= 1/6

therefore the slope of UF is 1/6

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Answer:

Set your calculator to degree mode.

Using the Law of Sines:

7/sin(40°) = x/sin(81°)

x = 7sin(81°)/sin(40°) = 10.8

Answer:

10.8=x

Step-by-step explanation:

Using the Law of Sines, we can put together the fact that

[tex]\frac{sin A}{a} =\frac{sinB}{b}[/tex]

Substitute our given values from the triangle:

[tex]\frac{sin 81}{x} =\frac{sin40}{7}[/tex]

Turn the sines into a decimal:

[tex]\frac{0.9876}{x} =\frac{0.6427}{7}\\[/tex]

cross multiply using butterfly method

0.988·7=0.643x

solve for x

6.916=0.643x

divide both sides by 0.643

10.8=x (round to nearest tenth)

Hope this helps! :)

Answer:

Begin by simplifying the phrases within the brackets, beginning with the innermost brackets:

(2 x 3)^-1 = 1/6 (because 2 x 3 = 6, and the negative exponent flips the fraction)

1/2^3 = 1/8 (because 2^3 = 8)

So, (2x3)^-1x1/2^3 = 1/6 x 1/8 = 1/48

Next, simplify the expression outside the parentheses:

(3x2^2)^-2 = 1/(3x2^2)^2 = 1/(3^2 x 2^4) = 1/36 x 1/16 = 1/576

Now, substitute the simplified terms back into the original expression and simplify:

3x(1/48)x(1/576) = 1/768

So the final answer is 1/768.

Answer: The answer is 5.

Step-by-step explanation:

You first set up the equation

10 + 7x = 45

You must put x because you don't know the number of hours he stays

You then subtract 10 from both sides of the numbers 10 and 45

That'll get you 7x = 35

To find out what x is you divide both sides by 7

7x divided by 7 is x

35 divided by 7 is 5

X = 5

The mZDPC is approximately 15 degrees.

We know that the length of an arc of a circle is given by the formula:

length of arc = (central angle / 360°) × 2πr

where r is the radius of the circle.

In this case, the length of arc DC is 9.77 inches and the radius of the circle is 8 inches. Let's use the above formula to find the central angle mZDPC:

9.77 = (mZDPC / 360°) × 2π(8)

Simplifying this equation, we get:

mZDPC = (9.77 / (2π(8) / 360°))

mZDPC = (9.77 / 0.670206) degrees

mZDPC ≈ 14.58 degrees

Rounding to the nearest degree, we get:

mZDPC ≈ 15 degrees

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A family camping in a national forest used a 4-foot pole and a tarp to build a temporary shelter. One corner of the tarp was staked 5 feet from the bottom of the pole. The slope of the tarp from that corner to the top of the pole is 0.8 or 4/5.

We can draw a right triangle with the pole being the height, the distance from the pole to the stake being the base, and the slope of the tarp being the hypotenuse. The hypotenuse is the longest side of the triangle and is opposite to the right angle.

Using the Pythagorean theorem, we can find the length of the hypotenuse

hypotenuse² = height² + base²

hypotenuse² = 4² + 5²

hypotenuse² = 41

hypotenuse = √(41)

Therefore, the slope of the tarp is the ratio of the height to the base, which is

slope = height / base = 4 / 5 = 0.8

So the slope of the tarp from that corner to the top of the pole is 0.8 or 4/5.

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The solution of the quadratic equation is y = (x + 3)(x - 3).

The solution of the quadratic equation is calculated by applying difference of two squares as shown below;

y = x² - 9

y = x² - 3²

the difference of two square of x² - 3² = (x + 3)(x - 3)

The solution of the quadratic equation is calculated as;

y = (x + 3)(x - 3)

Thus, solution of the quadratic equation has been determined using  square root method.

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This linear equation is invalid, the left and right sides are not equal, therefore there is no solution.

What in mathematics is a linear equation?

An algebraic equation with simply a constant and a first-order (linear) component, such as y=mx+b, where m is the slope and b is the y-intercept, is known as a linear equation.

                         Sometimes, the aforementioned is referred to as a "linear equation of two variables," where x and y are the variables. Equations with variables of power 1 are referred to be linear equations. axe+b = 0 is a one-variable example in which a and b are real numbers and x is the variable.

2x + -7 = -1(3 + -2x)

Reorder the terms:

-7 + 2x = -1(3 + -2x)

-7 + 2x = (3 * -1 + -2x * -1)

-7 + 2x = (-3 + 2x)

Add '-2x' to each side of the equation.

-7 + 2x + -2x = -3 + 2x + -2x

Combine like terms: 2x + -2x = 0

-7 + 0 = -3 + 2x + -2x

-7 = -3 + 2x + -2x

Combine like terms: 2x + -2x = 0

-7 = -3 + 0

-7 = -3

Solving

-7 = -3

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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The population of bacteria in the culture after 13 hours is approximately 1,656,320.

An equation is a statement that two expressions, which include variables and/or numbers, are equal. In essence, equations are questions, and efforts to systematically find solutions to these questions have been the driving forces behind the creation of mathematics.

We have the initial population, Po = 65000, and the doubling time, d = 2 hours. To find the population after 13 hours, we need to use the formula:

[tex]Pt = Po * 2^{(t/d)[/tex]

where Pt is the population after t hours, Po is the initial population, t is the time in hours, and d is the doubling time.

Substituting the given values, we get:

Pt = 65000 x [tex]2^{(13/2)[/tex]

Pt ≈ 1,656,320

Rounding this to the nearest whole number, we get:

The population of bacteria in the culture after 13 hours is approximately 1,656,320.

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The figure after changing the scale of the grid is added as an attachment

From the question, we have the following parameters that can be used in our computation:

Old scale: 1 unit = 4 ft

New scale: 1 unit = 8 ft

Using the above as a guide, we have the following:

Scale = Old scale/New Scale

Substitute the known values in the above equation, so, we have the following representation

Scale: (1 unit = 4 ft)/(1 unit = 8 ft)

Evaluate

Scale: 1/2

This means that the figure on the new grid will be half the side lengths of the old grid

Next, we draw the figure

See attachment for the new figure

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The project completion time is output of the simulations, option A, the EXCEL function used is (c) 1+4*RAND() and the standard deviation is

(b) 1.47.

1) In this simulation, we enter commands based on the way that activity durations are distributed (here uniformly with predetermined intervals). We determine the project completion time as an output based on the command we used and our calculations. This value will fluctuate (slightly) when the simulation is run, hence it is not fixed.

Hence, the "project completion time" is an (a) Output of the simulation.

2) Here, it is given that time required to complete activity A is uniformly distributed in an interval [1, 5].

So, we require random numbers starting from 1 with an interval of length 5-1=4.

We know, during simulation using usual Excel function RAND() we obtain random numbers in an interval [0, 1].

Thus if we multiply usual Excel function RAND() by 4 and thus use 4*RAND(), then we obtain random numbers in an interval [0*4, 1*4] i.e

[0, 4].

Adding 1 to this Excel function i.e. using Excel function 1+4*RAND() we obtain random numbers in an interval [0+1, 4+1] i.e [1, 5].

Hence, the Excel function to be used to generate random numbers for the duration of activity A is (c) 1+4*RAND().

3) For [tex]\tiny X\sim Unif\left ( a,b \right )[/tex], variance is given by

[tex]\tiny Var\left ( X \right )=\frac{\left ( b-a \right )^2}{12}[/tex]

Variance for activity A is given by

[tex]\tiny \frac{\left ( 5-1 \right )^2}{12}=\frac{4^2}{12}=1.333333[/tex]

Variance for activity B is given by

[tex]\tiny \frac{\left ( 3-2 \right )^2}{12}=\frac{1^2}{12}=0.083333[/tex]

Variance for activity C is given by

[tex]\tiny \frac{\left ( 6-3 \right )^2}{12}=\frac{3^2}{12}=0.75[/tex]

Variance of project completion time in the project is \tiny [tex]1.333333+0.083333+0.75= 2.166666[/tex]

So, standard deviation of project completion time in the project is [tex]\tiny \sqrt {2.166666}=1.47196\approx 1.47[/tex]

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Complete question:

A project has three activities A, B, and C that must be carried out sequentially. The probability distributions of the times required to complete each of the activities A, B, and C are uniformly distributed in intervals (1,5), (2,3) and (3,6) respectively. Find the total project completion time and run 1000 simulation trials in Excel. 7. The "project completion time" is a(n)... a. Output of the simulation b. Input of the simulation c. Decision variable in the simulation d. A fixed value in the simulation 8. Which of the following Excel functions would properly generate a random number for the duration of activity A in the project described above? a. 5* RANDO b. 1+5 * RANDO c. 1+4* RANDO d. NORM.INV(RAND(),1,5) e. NORM.INV(RAND(0,5,1) 9. The standard deviation of the project completion time in the project described above is cl a 2.83 b. 1.47 c. 1.15 d. 1.82 e. 1.63

Answer:

(a) G(t) = (1.68 × 10^-4) × (1/3) t^3 - (0.02/2) t^2 - 0.10t - 2445.84

(b) A(t) = G(t) - G(1900) = (1.68 × 10^-4) × (1/3) (t^3 - 1900^3) - (0.02/2) (t^2 -     1900^2) - 0.10(t - 1900)

Step-by-step explanation:

(a) The antiderivative of g(t) can be found by integrating each term of the function with respect to t:

∫g(t) dt = ∫(1.68 × 10^-4)t^2 dt - ∫0.02t dt - ∫0.10 dt

= (1.68 × 10^-4) × (1/3) t^3 - (0.02/2) t^2 - 0.10t + C

where C is the constant of integration.

To find the specific antiderivative G(t) that passes through the point (1970, 94.8), we can use this point to solve for C:

94.8 = (1.68 × 10^-4) × (1/3) (1970)^3 - (0.02/2) (1970)^2 - 0.10(1970) + C

C = 94.8 + (1.68 × 10^-4) × (1/3) (1970)^3 - (0.02/2) (1970)^2 - 0.10(1970)

C ≈ -2445.84

Therefore, the specific antiderivative that gives the gender ratio is:

G(t) = (1.68 × 10^-4) × (1/3) t^3 - (0.02/2) t^2 - 0.10t - 2445.84

(b) The accumulation function of g is the integral of g with respect to t, or:

A(t) = ∫g(t) dt = G(t) + C

where C is the constant of integration. We can find the value of C using the initial condition given in the problem:

A(1900) = ∫g(t) dt ∣t=1900 = G(1900) + C = 0

Therefore, C = -G(1900), and the accumulation function of g is:

A(t) = G(t) - G(1900) = (1.68 × 10^-4) × (1/3) (t^3 - 1900^3) - (0.02/2) (t^2 - 1900^2) - 0.10(t - 1900)

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y < four-fifthsx - one-fifth

y < 2x + 6

The given system of inequalities can be represented in slope-intercept form as follows:

y < (4/5)x - 1/5

y < 2x + 6

To convert the given inequalities into slope-intercept form, we rearrange each equation to solve for y

In the first inequality, we add 5y to both sides and then divide by 4 to isolate y. This gives us:

4x - 5y < 1

-5y < -4x + 1

y > (4/5)x - 1/5

In the second inequality, we add x to both sides and then divide by -1/2 to isolate y. This gives us:

1/2y - x < 3

1/2y < x + 3

y > 2x + 6

Therefore, the given inequalities in slope-intercept form are:

y < (4/5)x - 1/5

y > 2x + 6

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The two letters in which the new point lie include the following: C. between G and H.

In Geometry, a number line simply refers to a type of graph that is composed of a graduated straight line, which typically comprises both negative and positive numerical values (numbers) that are located at equal intervals along its length.

This ultimately implies that, all number lines would primarily increase in numerical value (number) towards the right from zero (0) and decrease in numerical value (number) towards the left from zero (0).

From the number line shown in the image attached below, we can logically deduce the following point:

|J - E| = 45% of x

|J - E| = 0.45x

|J - E| = GH

In conclusion, 45% is almost half way or 50% between E and J, which makes the distance between the two letters G and H, the new point.

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Missing information:

The question is incomplete and the complete question is shown in the attached picture.

The area of the region enclosed by one loop of the curve r = 4cos(θ) is 4 square units. The slope of the tangent line to the polar curve r=1 - 2sin(θ) at θ = π/4 is  2 + √2.

Area of region enclosed by one loop of the curve r = 4cos(2θ)

The curve r = 4cos(2θ) has two loops, and we need to find the area of one loop, which is from θ = 0 to θ = π/4.

To find the area, we use the formula for the area enclosed by a polar curve

A = (1/2) ∫[a,b] r^2 dθ

where r is the polar function, and a and b are the angles of the region we want to find the area for.

So, the area of one loop is

A = (1/2) ∫[0,π/4] (4cos(2θ))^2 dθ

= 8 ∫[0,π/4] cos^2(2θ) dθ

Using the identity cos(2θ) = (cos^2θ - sin^2θ), we can rewrite the integrand as

cos^2(2θ) = (cos^2θ - sin^2θ)^2

= cos^4θ - 2cos^2θsin^2θ + sin^4θ

= (1/2) (1 + cos(4θ)) - (1/2) sin^2(2θ)

So, the integral becomes

A = 8 ∫[0,π/4] [(1/2) (1 + cos(4θ)) - (1/2) sin^2(2θ)] dθ

= 4 [θ/2 + (1/8)sin(4θ) - (1/4)θ - (1/8)sin(2θ)]|[0,π/4]

= 1 + (2/π)

Therefore, the area of one loop of the curve r = 4cos(2θ) is 1 + (2/π).

Slope of tangent line to the polar curve r = 1-2sinθ at θ = π/4

To find the slope of the tangent line, we need to take the derivative of the polar function with respect to θ:

dr/dθ = -2cosθ

Then, we can use the formula for the slope of the tangent line in polar coordinates

dy/dx = (dy/dθ) / (dx/dθ) = (r sinθ) / (r cosθ) = tanθ + r dθ/dθ

At the point specified by θ = π/4, we have

r = 1 - 2sin(π/4) = 1 - √2/2 = (2 - √2)/2

dθ/dθ = 1

So, the slope of the tangent line is

dy/dx = tan(π/4) + r dθ/dθ

= 1 + (2 - √2)/2

= (4 + 2√2)/2

= 2 + √2

Therefore, the slope of the tangent line to the polar curve r = 1-2sinθ at θ = π/4 is 2 + √2.

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Therefore , the solution of the given problem of triangle comes out to be the jewellery's circumference is 12 mm.

If a polygon contains at least one more segment, it is a hexagon. It is a simple rectangle in shape. Anything like this can only be distinguished from a standard triangle form by edges A and B. Even if the edges are perfectly collinear, Euclidean geometry only creates a portion of the cube. A triangle is made up of a quadrilateral and three angles.

Here,

The lengths of all three sides must be added up in order to determine the jewellery's perimeter.

=> c²= a² + b²

where a and b are the lengths of the other two sides, and c is the length of the hypotenuse.

=> A = 3mm, and B = 4mm.

Therefore, we can determine the length of the hypotenuse using the Pythagorean theorem:

=> c² = a²+ b²

=> c² = 3² + 4²

=> c² = 9 + 16

=> c² = 25

=> c = √25)

=> c = 5 mm

As a result, the hypotenuse is 5 mm long.

We total the lengths of all three sides to determine the jewellery's perimeter:

=> perimeter = 4mm, 3mm, and 5mm.

=> 12 mm is the diameter.

Therefore, the jewellery's circumference is 12 mm.

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a = 5

b = 4

c= 0

Therefore, the equation for graph C is Y = a ^b + c

Y = 5 ^4 + 0

A graph is described as a diagram showing the relation between variable quantities, typically of two variables, each measured along one of a pair of axes at right angles.

Graphs are a popular tool for graphically illuminating data relationships.

A graph serves the purpose of presenting data that are either too numerous or complex to be properly described in the text while taking up less room.

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The number of horizontal rails for 10 sections is

The rule for the post is to multiply the number of section by 3

The rule for the rail is to multiply the post by 2

The rules is calculated using the unit value and comparing with other values

the rule for the number of post

1 section requires 3 posts hence multiplication by 3, comparing shows that multiplying by 3 gives the number of post

the rule for the number of rails

1 section requires 6 rails hence multiplication by 6, comparing shows that multiplying each section by 6 gives the correponding number of rails

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Answer:

Step-by-step explanation:

The value of 2s in 43,290 is 2,000, while the value of 2s in 32,865 is 20.

B. 200 is 1/20 the value of 2,000.

This statement is correct, as 200 is 1/10 of 2,000, and there are two 0s in the value of 2s in 43,290 compared to one 0 in the value of 2s in 32,865.

The probability of rolling a number larger than 2 and drawing an Ace or 4 is 2/39. There are 4 numbers larger than 2 and 2 Aces and 1 4 in a deck of 52 cards and a total of 6 outcomes that meet the criteria.

The probability of rolling a number larger than 2 is 4/6, which simplifies to 2/3. The probability of drawing an Ace or 4 is 4/52, which simplifies to 1/13. To find the probability of both events happening, you multiply the probabilities

P(rolling a number larger than 2 and drawing an Ace or 4) = P(rolling a number larger than 2) x P(drawing an Ace or 4)

= (2/3) x (1/13)

= 2/39

Therefore, the probability of number larger than 2 and drawing an Ace or 4 is 2/39.

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Based on the hypothesis test, with a significance level of 0.05, there is no evidence to suggest that the die is loaded, as the p-value is greater than the significance level. The null hypothesis that the die is fair is failed to rejected.

To determine if the die is loaded, we need to perform a hypothesis test.

Null Hypothesis (H0) The die is fair; all outcomes are equally likely.

Alternative Hypothesis (Ha) The die is loaded, and not all outcomes are equally likely.

We will use a significance level of 0.05.

To test the hypothesis, we can use a chi-square goodness-of-fit test.

First, we need to calculate the expected frequencies for each outcome, assuming that the die is fair. Since there are six possible outcomes, each with an expected frequency of 200/6 = 33.33.

Number Observed Frequency (O) Expected Frequency (E) (O - E)² / E

1 45 33.33 3.48

2 39 33.33 0.87

3 35 33.33 0.07

4 25 33.33 1.83

5 27 33.33 0.99

6 29 33.33 0.44

The test statistic is the sum of (O-E)² / E, which is 7.68.

The degrees of freedom for this test are (number of categories - 1) = 5.

Using a chi-square distribution table or calculator, we find that the p-value associated with a test statistic of 7.68 and 5 degrees of freedom is approximately 0.177.

Since the p-value is greater than our significance level of 0.05, we fail to reject the null hypothesis. We cannot conclude that the die is loaded based on this data alone.

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