20 - 10 = 10 pupils are more probability to be wearing shirts other than blue or white.
What purposes does probability serve?Probability gives information about the likelihood that something will occur. For instance, weather patterns are used by meteorologists to predict the possibility of rain. Probability theory is utilised in epidemiology to comprehend the connection between exposures and the risk of health outcomes.
What is the probability fundamental rule?A AND B = P(B)P(A|B) if A and B are two events defined on a sample space. (The likelihood of A given B is equal to the likelihood of A and B divided by the likelihood of B.) P(A|B) = P if A and B are independent (A).
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pls help me out with this
answer is adjacent angles
Answer:
complementary and
adjacent
Step-by-step explanation:
Complementary means the angles add up to 90°, that is, they make a right angle.
Adjacent means they are next to each other.
Both of these are the correct answer.
(since the question has boxes on the answers, you can mark more than one correct answer)
How do you find the verticle asymtote of y = x-4/x-2
Answer: VA: x = 2
Step-by-step explanation: In order to find the verticle asymtote you have to substitute values for x in order to get zero. Look in the denominator and see which value minus or plus the value next to it will equal zero. In this case, 2-2 is 0 so your verticle asymtote is 2. Keep in mind you want 0 in the denominator because that would mean the value on a graph is undefined, showing your asymtote.
Answer: 2
Step-by-step explanation:
In Exercises 51-56, find all solutions to the equation in the interval \( [0,2 \pi) \). You do not need a calculator. 51. \( 2 \cos x \sin x-\cos x=0 \) 52. \( \sqrt{2} \tan x \cos x-\tan x=0 \) 53. \
Solutions to Exercises 51-56:
The equation can be rewritten as: \( \cos x (2 \sin x-1)=0 \). The solutions are: \( \cos x=0 \) or \( \sin x=\frac{1}{2} \). The solutions in the interval \( [0,2 \pi) \) are: \( x=\frac{\pi}{2}, \frac{3 \pi}{2}, \frac{\pi}{6}, \frac{5 \pi}{6} \).
The equation can be rewritten as: \( \tan x (\sqrt{2} \cos x-1)=0 \). The solutions are: \( \tan x=0 \) or \( \cos x=\frac{1}{\sqrt{2}} \). The solutions in the interval \( [0,2 \pi) \) are: \( x=0, \pi, \frac{\pi}{4}, \frac{3 \pi}{4}, \frac{5 \pi}{4}, \frac{7 \pi}{4} \).
The equation can be rewritten as: \( \sin x (1-\cos x)=0 \). The solutions are: \( \sin x=0 \) or \( \cos x=1 \). The solutions in the interval \( [0,2 \pi) \) are: \( x=0, \pi, 2 \pi \).
Overall, the solutions to these exercises can be found by factoring the equations and finding the solutions to each factor in the given interval.
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The solutions in the interval \( [0,2 \pi) \) are x = 0, π, and 2π.
In Exercises 51-56, find all solutions to the equation in the interval \( [0,2 \pi) \). You do not need a calculator.
51. \( 2 \cos x \sin x-\cos x=0 \): The solutions in the interval \( [0,2 \pi) \) are x = 0, π, and 2π.
52. \( \sqrt{2} \tan x \cos x-\tan x=0 \): The solutions in the interval \( [0,2 \pi) \) are x = π/4, 3π/4, 5π/4, and 7π/4.
53. \( 2 \cos^2 x-\sin^2 x=1 \): The solutions in the interval \( [0,2 \pi) \) are x = 0, π, and 2π.
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A soccer ball kicked off the ground has a height modeled by the function h= -t2 + 6t,
where t is the number of seconds since the ball was kicked and h is the height in meters.
What is the maximum height reached by the ball?
3 meters
6 meters
9 meters
27 meters
The maximum height reached by the baII is 9 meters.
What is a functiοn?In mathematics, a functiοn is a relatiοn between twο sets, typically called the dοmain and range, that assigns tο each element οf the dοmain a unique element οf the range. In οther wοrds, a functiοn is a rule οr a set οf rules that assοciates each input value with exactly οne οutput value.
Tο find the maximum height reached by the ball, we need to find the vertex of the parabolic functiοn [tex]h = -t^2 + 6t[/tex]. The vertex of a parabola in the form[tex]y = ax^2 + bx + c[/tex] is located at the point [tex](-b/2a, c - b^2/4a)[/tex].
In this case, the functiοn is[tex]h = -t^2 + 6t[/tex]t, which has a=-1, b=6, and c=0. Therefοre, the vertex οf the parabοla is located at:
t = -b/2a = -6/(-2) = 3
Tο find the maximum height, we substitute t = 3 into the functiοn:
[tex]h = -t^2 + 6t = -3^2 + 6(3) = 9 meters[/tex]
Therefοre, the maximum height reached by the baIl is 9 meters.
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HELP!! ASAP!! 50 POINTS!!
The quadratic equations are solved and the value of x are 1 and -7 respectively
What is Quadratic Equation?A quadratic equation is a second-order polynomial equation in a single variable x , ax² + bx + c=0. with a ≠ 0. Because it is a second-order polynomial equation, the fundamental theorem of algebra guarantees that it has at least one solution. The solution may be real or complex.
The roots of the quadratic equations are
x = [ -b ± √ ( b² - 4ac ) ] / ( 2a )
where ( b² - 4ac ) is the discriminant
when ( b² - 4ac ) is positive, we get two real solutions
when discriminant is zero we get just one real solution (both answers are the same)
when discriminant is negative we get a pair of complex solutions
Given data ,
Let the quadratic equation be represented as A
Now , the value of A is
a)
x² + 6x = 7
Adding 9 on both sides of the equation , we get
x² + 6x + 9 = 16
On simplifying the equation , we get
( x + 3 )² = ( 4 )²
Taking square roots on both sides , we get
x + 3 = ±4
Subtracting 3 on both sides , we get
x = 1 and x = -7
Therefore , the value of x are 1 and -7 respectively
Hence , the quadratic equations is solved
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Recursive a_(n)=a_(n-1)+100 a_(1)=-12 Common Difference: First Term: Explicit Form: a_(n)= + n
a_(n) = -12 + 100n.
The recursive formula for the sequence is a_(n) = a_(n-1) + 100. The first term of the sequence is a_(1) = -12 and the common difference is 100. The explicit form for this sequence is a_(n) = -12 + 100n.
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HELP ASAP
Find the value of y
Answer:
y = 129°
Step-by-step explanation:
the figure has opposite sides congruent and is therefore a parallelogram.
• consecutive angles are supplementary , that is
y + 51° = 180° ( subtract 51° from both sides )
y = 129°
13. The scale on a map is 1 : 20 000.
The area of a lake on the map is 1.6 square centimeters.
Calculate the actual area of the lake. Give your answer in square meters.
The actual area of the lake 64000 square meters.
What is ratio?When two numbers are compared, the ratio between them shows how often the first number contains the second. As an illustration, the ratio of oranges to lemons in a dish of fruit is 8:6 if there are 8 oranges and 6 lemons present.
In this given question, we are first of all going to use the given ratio of the on map measurements to the actual measurements, that is 1:20000 to calculate the actual measurements as follows:
[tex]1.6cm^2=1\times 1.6cm^2[/tex]------->1
Using the ratio 1:20000 in 1.1, we get,
[tex]1.6\times1 cm^2= 1.6\times (20000)^2 cm^2 = 1.6\times 400000000 cm^2 = 640000000cm^2[/tex]-----> 2
As the actual measurement of the area of the lake.
So, 1m = 100 cm
=> [tex](1m)^2=(100cm)^2[/tex]
=> [tex]1m^2 = 10000cm^2[/tex]-------> 3
So, using equation 3 in the value obtained 2, we get,
=> [tex]640000000cm^2 = \frac{640000000}{10000} = 64000m^2[/tex]
Hence the actual area of the lake is 64000 square meters.
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The function g is related to one of the parent functions g(x) = x^(2) + 6 The parent function f is: f(x)= x^(2) Use function notation to write g in terms of f.
We can find g(x) for any value of x by using the function notation g(x) = f(x) + 6.
The function g is related to the parent function f by a vertical shift of 6 units. In function notation, we can write g in terms of f as:
g(x) = f(x) + 6
This means that for any value of x, we can find the corresponding value of g by first finding the value of f at that x value, and then adding 6.
For example, if x = 2, we can find g(2) by first finding f(2) and then adding 6:
f(2) = 2^(2) = 4
g(2) = f(2) + 6 = 4 + 6 = 10
So g(2) = 10.
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the sum of the two numbers is 90. The larger the number is 14 more than 3 times the smaller the number. Find the numbers
x+y=_; x=_+_y
Answer:
Smaller number = 19
Larger number = 71
x + y = 90
x = 14 + 3y
Step-by-step explanation:
Let y represent the smaller number, and then represent the larger number as x, in terms of y:
Smaller number = y
Larger number = x = 3y + 14
Since the sum of the two numbers is 90, form an equation by adding them together in this notation:
y + 3y + 14 = 90
Simplify the equation:
4y + 14 = 90
4y = 76
y = 19
Therefore the smaller number is 19. Now substitute into the expression for the larger number to find its value:
x = 3(19) + 14 = 71
Now verify the two values sum to 90 like we expect:
19 + 71 = 90
Now we can use what we know to complete the equations, if x = 71:
x + y = 90 (we know they sum to 90)
x = 14 + 3y (as respresented above - multiplying by 3 and adding 14)
Find an equation for the plane through A(-2, 0, -3) and B(1, -2, 1) that lies parallel to the line through C(-2, -13/5, 26/5) and D(16/5, -13/5, 0).
2x+7y+2z+10=0 is the equation of the plane passing through A(-2, 0, -3) and B(1, -2, 1) that lies parallel to the line through C(-2, -13/5, 26/5) and D(16/5, -13/5, 0).
The equation of the plane passing through a point (a,b,c) can be written as A(x-a) + B(y-b) + C(z-c) = 0, where A, B and C are the coefficients of the normal vector to the plane.
So, the equation of the plane passing through a point (-2,0,-3) can be written as A(x+2) + B(y) + C(z+3) = 0,...i)
Now the plane also passes through the point (1,-2,1) so A(1+2) + B(-2) + C(1+3) = 0,
So, 3A-2B+4C=0.........ii)
Now, the direction cosines of CD is
l= 16/5 +2= 26/5
m= -13/5+13/5 = 0
n= 0-26/5 = -26/5
For a plane and line to be perpendicular Dot product of the direction cosines must be zero
or A*26/5 + B*0 + C*-26/5=0
or, A=C.....iii)
Putting this in i) 7A-2B=0 or, A=2B/7....iv)
putting iii) and iv)
A(x+2) + B(y) + C(z+3) = 0
or, A(x+2) + B(y) + A(z+3) = 0
or, 2*B*(x+2)/7 + B(y) + 2*B*(z+3) /7= 0
or 2*(x+2)/7 + y + 2*(z+3) /7= 0
or 2x+7y+2z+10=0
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Kuro has a stack of 15 coins on a table with a volume of 8 cubic centimeters. He has stacked them perfectly straight creating a cylindrical shape. He accidentally bumps the table, causing the coins to shift to a leaning position; but are still stacked. What would be the best estimate of the volume of the stack once it has been bumped/shifted?
The best estimate of the volume of the stack once it has been bumped/shifted is 4πt³ cubic centimeters.
Describe Volume of cylinder?A cylinder is a three-dimensional geometric shape that consists of two parallel circular bases connected by a curved surface. The volume of a cylinder is the amount of space occupied by the shape and is given by the formula:
Volume = πr²h
where π (pi) is a mathematical constant approximately equal to 3.14, r is the radius of the circular base, and h is the height of the cylinder.
Assuming that the coins have the same dimensions and are perfectly circular, the original stack of 15 coins formed a cylinder with a height of 15 times the thickness of a single coin, and a radius equal to the radius of a single coin.
The volume of this cylinder can be calculated using the formula V = πr²h, where r is the radius and h is the height.
Since the volume of the original stack is 8 cubic centimeters, we can set up the equation:
8 = πr²(15t)
where t is the thickness of a single coin.
Solving for r, we get:
r = √(8/15πt)
When the stack is bumped and shifts to a leaning position, the new shape will still be a cylinder, but the height will be shorter than before. Let's say that the new height is h2. We can calculate the new volume using the same formula:
V2 = πr²h2
To estimate the new height, we can use the fact that the coins are now leaning against each other, so the new height will be less than 15t. Let's say that the new height is approximately 12t.
Substituting in the values, we get:
V2 = π(√(8/15πt))²(12t)
Simplifying, we get:
V2 = 4πt³
Therefore, the best estimate of the volume of the stack once it has been bumped/shifted is 4π³ cubic centimeters.
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help plssssssssssssssssssss
Answer:
Step-by-step explanation:
The llsab have to be divided by the number quotient and then once your sllab get hot then you answer.
READ THIS BACKWARDS
3. John wants an average bowling score of 215. If he scored 159, 182, 225, 240, 198,
200 and 230 on his first seven games, what must he score on his 8th game to achieve
this average?
John must score 286 on his 8th game to achieve an average score of 215.
What is an Average?
Average, also known as the mean, is a mathematical concept that represents the central value of a set of numbers. It is found by dividing the sum of the numbers by the total count of the numbers.
To find out what John must score on his 8th game to achieve an average score of 215, we need to use the formula for calculating the average or mean:
Average = (Sum of Scores) / (Number of Scores)
We can use this formula to solve for the unknown score:
215 = (159 + 182 + 225 + 240 + 198 + 200 + 230 + x) / 8
Multiplying both sides by 8, we get:
1720 = 159 + 182 + 225 + 240 + 198 + 200 + 230 + x
Simplifying, we get:
1720 = 1434 + x
Subtracting 1434 from both sides, we get:
x = 286
Therefore, John must score 286 on his 8th game to achieve an average score of 215.
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BRAINLIEST. Can someone please answer all the question in the picture below. BRAINLIEST.
Answer:
P'(1,2) S'(2,5)
Step-by-step explanation:
P(3,-2) S(4,-5) glode translation (x-2,y)
-2 -2
P(1,-2) S(2,-5) reflect over x-axis
P'(1,2) S'(2,5) ----> answer
hope this helpzzz
PLEASE HELP ME! IT WAS DUE YESTERDAY
Answer:
Step-by-step explanation:
2b + 3d = 13.25
2b + 2d = 11.50
2b + 3d = 13.25
-2b - 2d = -11.50
d = $1.75 for one drink
2b + 3.50 = 11.50
2b = 8
b = $4 for one Big Mac
QUESTION 4 4.1 Calculate the difference between the interest of the following two investmen A and B. A. R5 500 Simple interest 8% for 4 years Grade 9 B. R5 500 Compound interest 7,5% for 3 years
The difference in interest earned between the twο investments is R5 118.08.
Describe Interest?There are twο main types οf interest: simple interest and cοmpοund interest. Simple interest is calculated οnly οn the principal amοunt, while cοmpοund interest is calculated οn bοth the principal amοunt and any accumulated interest frοm previοus periοds.
Interest rates can be fixed οr variable. A fixed interest rate remains the same thrοughοut the lοan οr investment periοd, while a variable interest rate can change οver time depending οn market cοnditiοns.
Interest is an impοrtant cοncept in finance and ecοnοmics, and it plays a key rοle in bοrrοwing and lending, investments, and savings.
Investment A:
Simple interest = P × r × t
Where P = R5 500, r = 8% = 0.08 and t = 4 years
Simple interest = 5500 × 0.08 × 4
Simple interest = 1760
Investment B:
Cοmpοund interest = [tex]$A = P(1 + \frac{r}{n})^{nt}[/tex]
Where P = R5 500, r = 7.5% = 0.075, n = 1 (as it is cοmpοunded annually) and t = 3 years
Cοmpοund interest = [tex]$5500 \times (1 + \frac{0.075}{1} )^{(1 \times 3)} - 5500[/tex]
Cοmpοund interest = 1332.63
The difference between the interest earned οn the twο investments is:
Difference = Investment A - Investment B
Difference = 1760 - 1332.63
Difference = 427.37
Therefοre, the difference in interest earned between the twο investments is R5 118.08.
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I’ll give brainlyyyyy
Answer:
CD = 22
Step-by-step explanation:
You would double the side lengths given since this is a rectangle and set them equal to 80 cause that is the perimeter. So the equation would be 6z + 6 + 8z + 4 = 80. You would use the PEDMAS rule and subtract 6 from both sides which gives you:
6z + 8z +4 = 74
Subtract 4 from both sides
6z + 8z = 70
Add 6z + 8z
14z = 70
Divide 70 and 14z
z = 5.
AB and CD is equal in length so all you have to do is plug in 5 to z in the AB equation.
4(5) + 2
= 22
Evaluate each expression. See Example 4. 45. \( \sin ^{2} 120^{\circ}+\cos ^{2} 120^{\circ} \) 46. \( \sin ^{2} 225^{\circ}+\cos ^{2} 225^{\circ} \) 47. \( 2 \tan ^{2} 120^{\circ}+3 \sin ^{2} 150^{\ci
The final answers are:
Example 4. 45: 1
46: 1
47: \( \frac{17}{12} \)
To evaluate each expression, we can use the identities for sine and cosine, and then simplify.
For example 4. 45, we have:
\( \sin ^{2} 120^{\circ}+\cos ^{2} 120^{\circ} \)
= \( (\frac{\sqrt{3}}{2})^{2}+(-\frac{1}{2})^{2} \)
= \( \frac{3}{4}+\frac{1}{4} \)
= 1
For 46. \( \sin ^{2} 225^{\circ}+\cos ^{2} 225^{\circ} \), we have:
= \( (-\frac{\sqrt{2}}{2})^{2}+(-\frac{\sqrt{2}}{2})^{2} \)
= \( \frac{2}{4}+\frac{2}{4} \)
= 1
For 47. \( 2 \tan ^{2} 120^{\circ}+3 \sin ^{2} 150^{\circ} \), we have:
= \( 2(\frac{\sqrt{3}}{3})^{2}+3(\frac{1}{2})^{2} \)
= \( 2(\frac{1}{3})+3(\frac{1}{4}) \)
= \( \frac{2}{3}+\frac{3}{4} \)
= \( \frac{8}{12}+\frac{9}{12} \)
= \( \frac{17}{12} \)
So the final answers are:
Example 4. 45: 1
46: 1
47: \( \frac{17}{12} \)
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PLEASE HELPPPP I need it
0.8 divided by 72.4 : ]
Answer:
0.011
Step-by-step explanation:
Answer:9.05
Step-by-step explanation: uh why? its easy
A certain sum of money lent out at simple interest amount RS.690 in 3 years and RS.750 at the end of the second year on the sum of amount. Which has to be lent
The principal amount lent out at simple interest is RS.690 in 3 years and RS.750 at the end of the second year RS.738.
To calculate the amount of money that needs to be lent out, use the following formula:
Amount = Principal * (1 + (Rate * Time))
Where:
Principal = 690
Rate = 0.05 (5% simple interest rate)
Time = 2 years
Therefore, the amount to be lent out is:
Amount = 690 * (1 + (0.05 * 2)) = 738
Therefore, the amount to be lent out is RS.738.
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1. A plane flies due east for 500 km and then on a heading of 120" for 150 km. What are its distance and bearing from its starting point?
2. A ship leaves port and sails due west for 120 km, then due south for 40 km. What are the distance and bearing of the port from the ship?
(1) The distance from the starting point to the final point is 589.5 km and the bearing from the starting point to the final point is 16.7° north of east
(2) The distance from the ship to the port is 126.49 km and the bearing of the port from the ship is 18.4° south of west.
What is the distance and bearing of the plane?
To solve this problem, we can use the law of cosines to find the distance from the starting point to the final point. We can also use trigonometry to find the bearing (angle) between the starting point and final point.
See the diagram attached:
We want to find the distance and bearing from the starting point (x) to the final point.
Using the law of cosines, we have:
c² = a² + b² - 2abcos(C)
c² = 500² + 150² - 2x500x150xcos(120°)
c² = 250,000 + 22,500 + 75,000
c² = 347,500
c = √347,500
c = 589.5 km
To find the bearing, we can use trigonometry. Let θ be the angle between the line from the starting point to the final point and due east.
tan(θ) = (150 km) / (500 km)
θ = tan⁻¹(0.3)
θ = 16.7°
2. To solve this problem, we can use the Pythagorean theorem to find the distance from the ship to the port. We can also use trigonometry to find the bearing (angle) between the ship and the port.
We want to find the distance and bearing of the port (P) from the ship (S).
Using the Pythagorean theorem, we have:
d² = 120² + 40²
d² = 14400 + 1600
d² = 16000
d = √(16000)
d = 126.49 km
To find the bearing, we can use trigonometry. Let θ be the angle between the line from the ship to the port and due west.
tan(θ) = (40 km) / (120 km)
θ = tan⁻¹ (1/3)
θ = 18.4°
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Find the scale factor.
35
35
11 61035 dit
42
42
پر
42 M
The scale factor is 11.
What is scale factor?Scale factor is a numerical value used to proportionally enlarge or reduce a size of an object or image. It is also used to compare two similar shapes or objects. When the scale factor is greater than 1, it indicates an increase in size and when the scale factor is less than 1, it indicates a decrease in size. Scale factors are usually expressed as a ratio, such as 1:2, which means that the object has been doubled in size.
To calculate it, divide the first number by the second number and multiply by the third number: (35/42) x 11 = 10.714. Therefore, the scale factor is 11.
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O FRACTIONS Addition or subtraction of fractions with the sam Add. Write your answer as a fraction in simplest form. (1)/(8)+(5)/(8)
Fraction in simplest form is (3)/(4).
To add or subtract fractions with the same denominator, you simply add or subtract the numerators and keep the same denominator. Then, simplify the fraction if possible.
In this case, the fractions have the same denominator of 8, so we can simply add the numerators:
(1)/(8) + (5)/(8) = (1 + 5)/(8) = (6)/(8)
Now, we need to simplify the fraction by finding the greatest common factor (GCF) of the numerator and denominator. The GCF of 6 and 8 is 2, so we can divide both the numerator and denominator by 2 to get:
(6)/(8) = (6/2)/(8/2) = (3)/(4)
So the final answer is (3)/(4).
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(1 point) Express the following sum in closed form. n Σ (3k – 3) = ____
k=1 Note: Your answer should be in terms of n.
This is our final answer in terms of n.
The given sum is n Σ (3k – 3) = ____ , where k=1. To express this sum in closed form, we can use the formula for the sum of an arithmetic series. The formula is:
S = n/2 (a1 + an)
where S is the sum, n is the number of terms, a1 is the first term, and an is the last term.
In this case, the first term is 3(1) - 3 = 0 and the last term is 3(n) - 3 = 3n - 3. Plugging these values into the formula, we get:
S = n/2 (0 + 3n - 3)
Simplifying the equation gives us:
S = n/2 (3n - 3)
S = (3n^2 - 3n)/2
S = (3n^2)/2 - (3n)/2
S = (3/2)n^2 - (3/2)n
Therefore, the sum in closed form is:
n Σ (3k – 3) = (3/2)n^2 - (3/2)n
This is our final answer in terms of n.
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Please help
Solve the equation.
3x + 2 = 3x + 2
Select the correct choice below and, if necessary, fill in the answer box to complete your choice
A. X =
B. The solution is all real numbers.
C. There is no solution.
Crash cost per week for activity two?
Activity Normal Time Crash Time Normal Cost Crash Cost Total Allowable Crash Time Crash cost per week
1 12 6 3,000 4,200
2 18 12 1,000 4,600
A. Activity 2 can not be crashed
B. $600 per week
C. $800 per week
D. $3600 per week
$600
B. $600 per week
For Activity 2, the Normal Cost is $1,000 and the Crash Cost is $4,600, so the Crash cost per week is $60.
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Solving system of equations using Elin Instructions: Show your work for all qu Solve each system by elimination. 6x+3y=3 2x+7y=7
The solution to the system of equations is (0,1).
To solve the system of equations using elimination, we need to eliminate one of the variables. In this case, we will eliminate x by multiplying the first equation by -2 and the second equation by 6.
First equation: 6x+3y=3
Second equation: 2x+7y=7
Multiply the first equation by -2: -12x-6y=-6
Multiply the second equation by 6: 12x+42y=42
Now we can add the two equations together to eliminate x:
-12x-6y=-6
+12x+42y=42
_______________
0x+36y=36
Now we can solve for y:
36y=36
y=1
Now we can plug y back into one of the original equations to solve for x:
6x+3(1)=3
6x+3=3
6x=0
x=0
So the solution to the system of equations is (0,1).
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A warehouse contains 3,500 boxes of office supplies. Boxes are added to the warehouse at a rate of 7 boxes per day. Which function can be used to find b, the total number of boxes in the warehouse after d days?
The following function can be used to find b:
b= 7d
What is an equation?
An equation is a mathematical statement that proves two mathematical expressions are equal in algebra, and this is how it is most commonly used. In the equation 3x + 5 = 14, for instance, the two expressions 3x + 5 and 14 are separated.
7 boxes per day
=> For d days , the number boxes will be 7d
total number of boxes
b= 7d
when b= 3,500 ,
3500= 7d
=> d= 3500/7 = 500 days
The following function can be used to find b:
b= 7d
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