I'm honestly confused right now, please help me.

Answer:

Small populations tend to lose genetic diversity more quickly than large populations due to stochastic sampling error (i.e., genetic drift). This is because some versions of a gene can be lost due to random chance, and this is more likely to occur when populations are small.

Explanation:

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Answer:

reduce impact on the environment

The main function of environmental policy is to reduce human impact on the environment. So the correct answer is B.

environmental policy is any action taken by a government, business, or other public or private organization to address the impacts of human activity on the environment, particularly those that aim to mitigate or prevent negative effects on ecosystems.

It is our approach to look for consistent improvement all through our business tasks to reduce our effect on the neighborhood and worldwide climate by saving energy, water and other normal assets; reducing the production of waste; repurposing and; minimizing our use of hazardous materials.

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Answer:

i say that the answer is c

Explanation:

Answer:

Carbon dioxide

A fatty acid with no carbon-carbon double bonds; usually from animal sources and solid at room temperature is a saturated fatty acid.

A saturated fatty acid is a special type of fatty acid composed of a  carbon chain that does not exhibit any double bonds, which is well known to reduce fluidity.

In conclusion, a fatty acid with no carbon-carbon double bonds; usually from animal sources and solid at room temperature is a saturated fatty acid.

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Answer:

all of them duh even trees do and flowers and many more all plants even humans do it and animals

Answer:

i think it is a

Explanation:

Answer:

The correct answer is D, "there are approximately 83 cells in interphase. Disruption of interphase will result in the cell being unable to synthesize proteins and organelles required to divide, which will result in the cell not passing key checkpoints and ceasing to divide."

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Herbicides are a broad category of pesticides that are used to get rid of undesirable plants like weeds and grasses that hinder the development and productivity of desired agricultural crops. Both 2,4-D and 2,4,5T are also known as 2,4-Dichlorophenoxyacetic acid and

Thus, by promoting cell division, these compounds act as herbicides.

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A pulmonary (lung) artery obstruction is referred to as an acute pulmonary embolism or embolus.

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In this experiment the dependent variable is the number of mosquito bites, the independent variable is the type of repellent the control group is the population that is not sprayed.

The dependent variable is those that changes in the experiment, while the independent variable is not modified along the experimental procedure. Moreover, the control group is the sample in which the treatment isn't applied.

In conclusion, in this experiment the dependent variable is the number of mosquito bites, the independent variable is the type of repellent the control group is the population that is not sprayed.

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Answer:

benedicts solutuin(c)

Organism represents an individual form of life such as an animal, plant, or single-celled life form. A prokaryote or a eukaryote can be a unicellular organism.  Eukaryotic organisms have a membrane-bound cell nucleus as well as extra membrane-bound compartments known as organelles (such as mitochondria in animals and plants and plastids in plants and algae, all generally considered to be derived from endosymbiotic bacteria)

Fungi, mammals, and plants are examples of eukaryotic organism kingdoms. Organisms are classified as producers, consumers, herbivores, carnivores, omnivores, scavengers, parasites, predators, and decomposers. Everything you need to know about the 39 trillion microbes that live in our bodies, according to the human microbiome.

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Answer: Lipids

Explanation:

Answer:

c) deletion is the type of mutation in the following

cocoon is the correct answer

Answer:

cocoonExplanation:

Answer:

First box: Carbohydrates

monomer is monosaccarides single sugar molecules

Elements: C, H, O

examples are glucose and cellulos

Box two: Proteins

Monomer: amino acid

Elements: C, H, O, N, P, S

function: a lot of differnt functions but examples include:

– Enzymes that control the rate of biochemical reactions

– Hormones that regulate cell processes (Ex. Insulin)

– Structurally make up bones and muscles (Ex. Collagen)

– Transport substances in and out of cell (Ex. Hemoglobin)

– Antibodies help immune system fight diseases

– Movement (Ex. Contractile proteins)

– Receptors aid in cell signaling

– Energy source in the food we eat (Ex. Casein)

Examples: meats, nuts, and dairy products, but many are made by your body

Box three: Nucleic Acid

Monomer: Nucleotides

Elements: C, H, O, N, P

function: informational molecules that store, transmit, and express our genetic information; contain the instructions for making proteins

example: DNA and RNA

Box Four: Lipids

Monomer: fatty acids

Elements: C, H, O

Function: Long term energy storage

Examples: fats, oils, phospholipids (in the cell membrane), steroids

Explanation:

Answer: E. Magnesium

Explanation:

Trust me bro

The correct answer is Ribosomes is the single molecule that could do both cellular work and replicate itself.

Ribosomes have two primary functions: message decoding and peptide bond formation. The ribosomal subunits are made up of two large ribonucleoprotein particles (RNPs) of unequal size. Each subunit is composed of one or more ribosomal RNAs (rRNAs) and a large number of ribosomal proteins (r-proteins). The ribosome is an ancient molecular fossil that can be used to peer into the origins of life. In all living systems, the ribosome, which is composed of RNA and protein, converts mRNA to coded protein. Translation is infused with universality, economy, centrality, and antiquity. Because the ribosome is so important to all aspects of life and reproduction in an organism, rapid change is unlikely to survive. The ribosome components are an excellent resource for studying the evolution of all organisms because all cellular organism have ribosomes .

Based on a number of considerations, it is hypothesized that at some time in the evolution of life, there must have been a single molecule that could do both cellular work and replicate itself. A possible molecule that has been suggested is a catalytic RNA molecule, now called a ?

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Answer:

They will most likely be immune to the treatment.

Explanation:

This is the same as a viruse evolving to survive the vaccine for it.

Answer: wave B has a higher pitch

Explanation:

I mean its obvious...

Answer:

A. Wave B has a higher pitch.

Explanation:

I took the quiz apix

Answer:

A

Explanation:

Answer:

full

Explanation:

Answer: biomarker: A substance used as an indicator of a biological state, most commonly disease.

trace fossil: A type of fossil reflecting the reworking of sediments and hard substrates by organisms including structures like burrows, trails, and impressions.

fossil record: All discovered and undiscovered fossils and their placement in rock formations and sedimentary layers.

strata: Layers of sedimentary rock.

fossiliferous: Containing fossils.

Explanation: hope this is what you mean if not ill try again

If I am understanding correctly, the first thing they are asking you to do is match nitrogen bases.

Adenine (A) always pairs with thymine (T), and guanine (G) always pairs with cytosine (C).

Then, whichever are the double strands, cut them out and put them into you notebook. (I am not sure where the notebook is, but I am assuming you know)

Then in the speech bubble next to the picture of Chargaff- talk about his rule.

What does the rule mean?

What does the rule explain?

How is the rule demonstrated?

Lastly, finding percents. What percent of the pairs has Adenine in them?

For example:

If I look at this pairing below

A →T

T→ A

G →C

C→ G

50% of the pairs include Adenine.

Hope I helped! Comment if you have questions about my answer :)

Answer:

If the sequence of nitrogenous bases of a DNA strand is ATCTAGGCCG, the complementary strand would be TAGATCCGGC, with a percentage of guanine 30%, cytosine 30%, adenine 20% and thymine 20%, according to Chargaff's rule.

Explanation:

DNA is made up of sequences of nitrogenous bases, which are adenine (A), guanine (G), thymine (T) and cytosine (C).  The bases of one strand are matched with the bases of another, according to the complementarity of nitrogenous bases, where:

The image shows a DNA chain whose chain is complementary:

DNA Strand given      Complementary Strand

    Adenine                                Thymine

    Thymine                                Adenine

    Cytosine                                Guanine

    Thymine                                Adenine

    Adenine                                Thymine

    Guanine                                 Cytosine

    Guanine                                 Cytosine

    Cytosine                                Guanine

    Cytosine                                Guanine

    Guanine                                 Cytosine

Therefore, in a DNA molecule there is as much adenine as thymine, and an equal amount of cytosine and guanine. In this example there are 4 molecules of adenine, 4 molecules of thymine, 6 guanines and 6 cytosines.

The proportion or percentages of nitrogenous bases can be calculated according to Chargaff's rule.

Chargaff was able to establish that in a DNA molecule the ratio of purine:pyrimidine of 1:1, so there must be the same amount of thymine as adenine and a similar amount of guanine for the cytosine, according to the complementarity of bases.

Taking into account the law of the base pair, if in a DNA chain there is 30% of Adenine, in the molecule there is:

Guanine 30%

Cytosine 30%

Adenine 20%

Thymine 20%

Total ..... 100%

Answer:

D

Explanation:

Hope it helps

Monosaccharide profiling of glycoproteins by capillary electrophoresis with contactless conductivity detection is saccharides.

Saccharides form one of the major constituents of the biological macromolecules in living organisms. Many biological processes including the protein folding, stability, immune response and receptor activation are regulated by glycosylation.

In this work, we optimized a capillary electrophoresis method with the capacitively coupled contactless conductivity detection for separation of eight monosaccharides commonly found in glycoproteins, namely D-glucose, D-galactose, D-mannose, N-acetyl-D-glucosamine, N-acetyl-D-galactosamine, D-fucose, N-acetylneuraminic acid, and D-xylose. A highly alkaline solution of 50 mM sodium hydroxide, 22.5 mM disodium phosphate, and 0.2 mM CTAB (pH 12.4) was used as background electrolyte in a 10 µm id capillary. To achieve baseline separation of all the analytes, a counter-directional pressure of –270 kPa was applied during the separation. The limits of the detection of our method were below 7 µg/ml (i.e., 1.5 pg or 1 mg/g protein) and the limits of quantification were below 22 µg/ml (i.e., 5 pg or 3 mg/g protein). As a proof of the concept of our methodology, we performed an analysis of monosaccharides released from fetuin glycoprotein by acid hydrolysis. The results show that, when combined with an appropriate pre-concentration technique, developed method can be used as a monosaccharide profiling tool in glyco-proteomics and complement the routinely used LC-MS/MS analysis.

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