I'm having a really hard time trying to solve this
A block with mass mb = 1.3 kg is connected by a rope across a 50-cm-diameter, 2.0 kg pulley, as shown in (Figure 1). There is no friction in the axle, but there is friction between the rope and the pulley; the rope doesn't slip and the pulley can be modeled as a solid cylinder. The weight is accelerating upward at 1.2 m/s^2.
What is the tension in the rope on the right side of the pulley?
Answers
Answer:
Approximately [tex]15.5\; {\rm N}[/tex], assuming that [tex]g = 9.81\; {\rm N \cdot kg^{-1}}[/tex].
Explanation:
To find the tension in the rope on the right side of the pulley, apply the following steps:
Find the tension that the rope exerts on the block, which is equal to the tension [tex]T_{\text{left}}[/tex] on the left side of the pulley.Find the torque [tex]\tau_{\text{left}}[/tex] resulting from the tension [tex]T_{\text{left}}[/tex] on the left side of the pulley.Find the moment of inertia [tex]I[/tex] of the pulley and the net torque [tex]\tau_{\text{net}}[/tex].Add the torque on the left [tex]\tau_{\text{left}}[/tex] to the net torque [tex]\tau_{\text{net}}[/tex] to find [tex]\tau_{\text{right}}[/tex], the torque on the right side of the pulley. Divide [tex]\tau_{\text{right}}[/tex] by radius of the pulley [tex]r[/tex] to find the tension on the right side, [tex]T_{\text{right}}[/tex].
The net force on the block is:
[tex]F_{\text{net}} = m_{\text{b}} \, a[/tex], where
[tex]m_{\text{b}} = 1.3\; {\rm kg}[/tex] is the mass of the block, and[tex]a = 1.2\; {\rm m\cdot s^{-2}}[/tex] is the linear acceleration of the block.At the same time, the net force on the block can also be expressed as:
[tex]\begin{aligned}F_{\text{net}} &= T_{\text{left}} - (\text{weight}) \\ &= T_{\text{left}} - m_{\text{b}}\, g \end{aligned}[/tex], where
[tex]g = 9.81\; {\rm N\cdot kg^{-1}}[/tex] by assumption, and[tex]T_{\text{left}}[/tex] is the tension the rope exerted on the block. This tension is equal to the tension on the left side of the pulley.Rearrange and solve for [tex]T_{\text{left}}[/tex]:
[tex]T_{\text{left}} - m_{\text{b}}\, g = F_{\text{net}} = m_{\text{b}}\, a[/tex].
[tex]\begin{aligned}T_{\text{left}} &= m_{\text{b}}\, a + m_{\text{b}}\, g \\ &= m_{\text{b}}\, (a + g) \\ &= 1.3\, (1.2 + 9.81)\; {\rm N} \\ &= 14.313\; {\rm N}\end{aligned}[/tex].
Let [tex]r[/tex] denote the radius of the pulley. It is given that the diameter of the pulley is [tex]50\; {\rm cm}[/tex]. In standard units, the radius of the pulley would be [tex]r = 25\; {\rm cm} = 0.25\; {\rm m}[/tex].
On the left side of the pulley, tension in the rope exerts a torque of [tex]\tau_{\text{left}} = T_{\text{left}}\, r[/tex] on the pulley:
[tex]\begin{aligned}\tau_{\text{left}} &= T_{\text{left}}\, r \\ &= (14.313)\, (0.25)\; {\rm N\cdot m} \\ &= 3.57825\; {\rm N\cdot m} \end{aligned}[/tex].
Under the assumptions, the moment of inertia [tex]I[/tex] of this cylindrical pulley would be:
[tex]\begin{aligned} I &= \frac{1}{2}\, m\, r^{2} \end{aligned}[/tex], where
[tex]m = 2.0\; {\rm kg}[/tex] is the mass of the pulley, and[tex]r = 0.25\; {\rm m}[/tex] is the radius of the pulley.[tex]\begin{aligned} I &= \frac{1}{2}\, m\, r^{2} \\ &= \frac{1}{2}\, (2.0)\, (0.25)^{2}\; {\rm kg \cdot m^{2}} \\ &= 0.0625\; {\rm kg\cdot m^{2}} \end{aligned}[/tex].
Since the rope doesn't slip on the pulley, linear acceleration of the pulley would be equal to that of the rope, [tex]a = 1.2\; {\rm m\cdot s^{-2}}[/tex]. Divide this linear acceleration by the radius of the pulley to find the angular acceleration [tex]\alpha[/tex] of the pulley:
[tex]\begin{aligned}\alpha &= \frac{a}{r} \\ &= \frac{1.2}{0.25}\; {\rm s^{-2}} \\ &= 4.8\; {\rm s^{-2}}\end{aligned}[/tex].
Multiply angular acceleration by the moment of inertia to find the net torque [tex]\tau_{\text{net}}[/tex] on the pulley cylinder:
[tex]\begin{aligned}\tau_{\text{net}} &= I\, \alpha \\ &= (0.0625)\, (4.8)\; {\rm kg \cdot m^{2}\cdot s^{-2}}\\ &= 0.3\; {\rm kg \cdot m^{2} \cdot s^{-2}} \end{aligned}[/tex].
Note that the net torque of the pulley [tex]\tau_{\text{net}}[/tex] is in the same direction as [tex]\tau_{\text{right}}[/tex], but the opposite of [tex]\tau_{\text{left}}[/tex]. Hence:
[tex]\begin{aligned}\tau_{\text{right}} &= \tau_{\text{net}} + \tau_{\text{left}} \\ &= 0.3\; {\rm N\cdot m} + 3.57825\; {\rm N\cdot m} \\ &= 3.87825\; {\rm N\cdot m}\end{aligned}[/tex].
Divide the torque on the right [tex]\tau_{\text{right}}[/tex] by radius [tex]r[/tex] to find the tension in the string on the right [tex]T_{\text{right}}[/tex]:
[tex]\begin{aligned}T_{\text{right}} &= \frac{\tau_{\text{right}}}{r} \\ &= \frac{3.87825}{0.25}\; {\rm N} \\ &= 15.513\; {\rm N}\end{aligned}[/tex].
Related Questions
if two different wires having identical cross-sectional areas carry the same current, will the drift velocity be higher or lower in the better conductor? explain in terms of the equation vd
Answers
When two different wires with identical cross-sectional areas carry the same current, the drift velocity will be lower in the better conductor.
To understand this, let's look at the drift velocity equation:
vd = I / (nAe)
In this equation, vd represents the drift velocity,
I is the current,
n is the number density of free electrons,
A is the cross-sectional area, and e is the charge of an electron.
Since the wires have the same cross-sectional areas (A)
and carry the same current (I),
we can focus on the number density of free electrons (n).
A better conductor has a higher number density of free electrons, meaning there are more free electrons available to carry the charge.
This is one of the main factors contributing to the increased conductivity of the better conductor.
Now, let's examine the equation again.
If n is higher in the better conductor, then the value of the fraction I / (nAe) will be smaller.
This means that the drift velocity (vd) will be lower in the better conductor.
In summary, the drift velocity is lower in the better conductor due to its higher number density of free electrons, which allows for more efficient charge transfer without the need for high drift velocities.
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if the ammeter has the following reading when set on the 0.05 a scale, what is the current it is measuring? a) 2 A. b) 0.2 A. c) 0.002 A. d) 0.02 A. e) 10 A.
Answers
The ammeter is measuring 0.02 A (0.02 Amps). To find this value, you need to multiply the reading on the scale (0.05 A) by the multiplier (40). The multiplier is the number of divisions on the scale multiplied by the least count of the scale.
In this case, the multiplier is 40 (4 divisions x 0.01 A least count). Therefore, the current measured is 0.02 A (0.05 A x 40 = 0.02 A). This is significantly less than the other values listed (2 A, 0.2 A, 0.002 A, and 10 A), so it is unlikely that the ammeter is measuring any of them.
An ammeter is an instrument used to measure electrical current. It is connected in series with the circuit, meaning that the current flows through the ammeter.
The reading is usually displayed on a scale, with each division having a particular least count. This least count is then multiplied by the number of divisions on the scale to get the multiplier. This multiplier is then multiplied by the reading on the scale to determine the current being measured.
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(LOOK AT PHOTO) Fill in the table with the distance and the displacement for each scenario
Answers
Answer: Below are the answers
Explanation:
Distance : 3 3+5+3 = 11 3+5+3+5 = 16
Displacement: 3 5 0
2. Distance : 4 4+3 = 7 4+3+5 = 12
Displacement : 4 5 0
tarzan steps off a branch and swings down on a vine that has an initial angle of 60 degrees relative to vertical. when the vine makes an angle of 30 degrees with the vertical, what fraction of his maximum kinetic energy will he have at that moment?
Answers
To determine the fraction of Tarzan's maximum kinetic energy when the vine makes an angle of 30 degrees with the vertical, we need to use the conservation of energy.
Tarzan's initial potential energy is converted into kinetic energy as he swings down on the vine. When the vine makes an angle of 30 degrees with the vertical, Tarzan's potential energy has decreased by half, so his kinetic energy must have increased by the same amount. Therefore, at this point, Tarzan has half of his maximum kinetic energy. We can express this as a fraction by dividing the current kinetic energy (half the maximum) by the maximum kinetic energy, giving a fraction of 1/2.
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if the force on a particle at some point in space is zero, must its potential energy also be zero at that point? match the words in the left column to the appropriate blanks in the sentences on the right.
Answers
If the net force on a particle at some point in space is zero, its potential energy need not be zero at that point.
According to the law of energy conservation, a particle's mechanical energy is conserved, i.e., it is constant when there is no external force. So, the net force on a particle is zero when the potential energy is maximum or minimum at that point. This statement means that the particle's mechanical energy is the sum of its potential energy and kinetic energy, and it is constant.
To understand it better, let us consider an example of a block of mass m, which is sliding down a frictionless hill. Here, the particle has the highest potential energy at the top of the hill and zero potential energy at the bottom of the hill. According to the law of conservation of energy, the total mechanical energy of the block at the top of the hill is equal to the total mechanical energy of the block at the bottom of the hill.
So, if the net force on a particle at some point in space is zero, its potential energy need not be zero at that point. The potential energy can be either maximum or minimum, and the particle's mechanical energy is constant.
Note: The question is incomplete. The complete question probably is: If the net force on a particle at some point in space is zero, must its potential energy also be zero at that point? Explain.
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what is the maximum value of the electric field in an electromagnetic wave whose average intensity is 7.55 w/m2 ?
Answers
The maximum value of the electric field in an electromagnetic wave whose average intensity is 7.55 W/m² is 30.5 V/m.
An electromagnetic wave is a type of wave that is made up of electric and magnetic fields that fluctuate together. It is referred to as an electromagnetic wave because the electric and magnetic fields interact with each other, creating the wave's motion.
The equation for the average intensity of an electromagnetic wave is given by
I = 1/2εcE²
where I is the average intensity, ε is the permittivity of free space, c is the speed of light, and E is the maximum value of the electric field.
Equating the given value of average intensity to the equation,
7.55 W/m² = 1/2 × 8.85 × [tex]10^{-12}[/tex] F/m × (3 × [tex]10^{8}[/tex] m/s) × E²
simplifying and solving for E,
E = 30.5 V/m
Thus, the maximum value of the electric field in an electromagnetic wave whose average intensity is 7.55 W/m² is 30.5 V/m.
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Suppose a wheel is initially rotating at 10.0 rad/s while undergoing constant angular acceleration reaching a speed of 30.0 rad/s after 20.0 seconds have elapsed. How long after the initial time has the wheel undergone half of the angular displacement that it will have gone through during the entire 20.0 second interval?
a. 10.0 s
b. 12.4 s
c. 14.2 s
d. 15.0 s
The answer is B, according to the textbook but I don't know why
Answers
To solve this problem, you can use the equations of motion for rotational motion under constant acceleration:
ωf = ωi + αt --(1)
θ = ωit + 0.5αt^2 --(2)
where ωi is the initial angular velocity, ωf is the final angular velocity, α is the angular acceleration, t is the time elapsed, and θ is the angular displacement.
Using equation (1), we can find the angular acceleration of the wheel:
α = (ωf - ωi)/t
= (30.0 rad/s - 10.0 rad/s)/20.0 s
= 1.0 rad/s^2
Using equation (2), we can find the total angular displacement of the wheel during the 20.0 seconds:
θ = ωit + 0.5αt^2
= 10.0 rad/s × 20.0 s + 0.5 × 1.0 rad/s^2 × (20.0 s)^2
= 400.0 rad
To find the time at which the wheel has undergone half of this angular displacement, we can use equation (2) again:
θ/2 = ωit + 0.5αt^2
Rearranging and solving for t, we get:
t = [(-ωi) ± sqrt(ωi^2 + 2αθ)]/α
Since we are looking for a positive time, we take the positive root:
t = [(-10.0 rad/s) ± sqrt((10.0 rad/s)^2 + 2 × 1.0 rad/s^2 × 400.0 rad)]/1.0 rad/s^2
≈ 12.4 s
Therefore, the answer is B, 12.4 s.
as light travels from one medium to another, which of its properties change? (select all that apply.)
Answers
When light travels from one medium to another, its speed, direction, and wavelength can change, while its frequency remains constant. These changes are due to differences in the refractive indices of the two media.
As light travels from one medium to another, several of its properties change, including its speed, direction, and wavelength. The speed of light changes because the refractive index of each medium is different, which alters the velocity of the wave. The direction of the light may also change, a phenomenon known as refraction, as it enters a medium with a different refractive index. The amount of refraction depends on the angle of incidence, the angle between the incoming light and the normal line to the surface of the medium. Finally, the wavelength of the light may also change due to the refractive index of the medium, a phenomenon known as dispersion. This results in the separation of white light into its component colors when it passes through a prism or other refracting medium.
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a series rl circuit with a resistor of 50ohm and inductor of 10mh is connected to a 100v (peak), voltage source. what is the power factor of this circuit? ( the frequency of the input is 250hz)
Answers
In this case, the series RL circuit is fairly efficient, as the power factor is close to 1.
The given series RL circuit contains a resistor of 50 Ω and an inductor of 10 mH. It is connected to a 100 V (peak) voltage source. The frequency of the input is 250 Hz. We need to find the power factor of this circuit.
The first step is to find the impedance (Z) of the circuit. The impedance of a series RL circuit is given by:
Z = √(R² + Xl²)
Where R is the resistance and Xl is the inductive reactance.
The formula for inductive reactance is:
Xl = 2πfL
Where f is the frequency and L is the inductance.
Substituting the given values, we get:
Xl = 2π × 250 × [tex]10^{-3}[/tex] = 1.57 ΩZ = √(50² + 1.57²) = 50.18 Ω
Now,
The power factor (PF) of a circuit is given by:
PF = cosφ
Where φ is the phase angle between the voltage and current.
Since this is a series RL circuit, the current lags the voltage by an angle φ, which is given by:
tanφ = Xl/Rφ = [tex]tan^{-1}[/tex](Xl/R)φ = [tex]tan^{-1}[/tex](1.57/50) = 1.79°
The power factor is:
PF = cos(1.79°) = 0.9985 (approx)
Therefore, the power factor of the given series RL circuit is approximately 0.9985.
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What is initial velocity of a ball (m/s) which is thrown upwards and takes 15.0s to return to its starting position?
A. 73.6 m/s
B. 73.6 m/s^2
C. 25 m/s^2
D. 25 m/s
Show the work for determining the velocity of the ball...show symbolic solution then numerical solution.
Answers
Answer:
Approximately [tex]73.6\; {\rm m\cdot s^{-1}}[/tex].
([tex]v = (1/2)\, g\, t[/tex], assuming that [tex]g = 9.81\; {\rm m\cdot s^{-2}}[/tex].)
Explanation:
Assume that the air resistance on the ball is negligible. Let [tex]v[/tex] denote the initial velocity of the ball.
The kinetic energy of the ball will be conserved. Hence, when the ball returns to the starting position, the ball will be travelling at the same speed but in the opposite direction (downwards.) The velocity will become [tex](-v)[/tex].
The change in the velocity of the ball would be [tex]\Delta v = ((-v) - v) = (-2\, v)[/tex].
Change in velocity is also equal to [tex]a\, t[/tex], where [tex]a[/tex] is acceleration and [tex]t[/tex] is the time required to achieve such change. Under the assumptions, acceleration of the ball will be constantly [tex]a = (-g)[/tex]. Hence:
[tex]\Delta v = a\, t = (-g)\, t[/tex].
Since [tex]\Delta v = ((-v) - v) = (-2\, v)[/tex]:
[tex](-2\, v) = \Delta v = (-g)\, t[/tex].
[tex]\begin{aligned}v &= \frac{(-g)\, t}{(-2)} = \frac{g\, t}{2}\end{aligned}[/tex].
Substitute in [tex]g = 9.81\; {\rm m\cdot s^{-2}}[/tex] and [tex]t = 15.0\; {\rm s}[/tex] to obtain:
[tex]\begin{aligned}v &= \frac{g\, t}{2} \\ &= \frac{(9.81)\, (15.0)}{2}\; {\rm m\cdot s^{-1}} \\ &\approx 73.6\; {\rm m\cdot s^{-1}}\end{aligned}[/tex].
why do people live in areas affected by a natural strikes
Answers
Answer:
People tend to live in these areas because they believe that the benefits of the location outweigh the risks. Most volcanoes and seismic zones are safe for long periods between eruptions or seismic events. Often, tectonic events can be adjusted and residents perceive these events as predictable.
What is meant by differential partitioning between stationary and mobile phase? What is the recommended procedure for cleaning a TLC spotting capillary? Arrange the folewing in order of increasing Rf on thin-layer chrooaphy: octanoic acid,
Answers
Differential partitioning between stationary and mobile phase refers to the separation of components in a mixture based on their differing affinities for a stationary phase (usually a solid or a liquid on a solid support) and a mobile phase (usually a liquid or a gas).
The components with higher affinity for the stationary phase move slower, while those with a higher affinity for the mobile phase move faster.
To clean a TLC spotting capillary, follow these steps:
1. Rinse the capillary with an appropriate solvent (e.g., acetone or methanol) several times.
2. After rinsing, blow air through the capillary to remove any remaining solvent.
3. Allow the capillary to air dry before using it again for spotting.
Regarding the order of increasing Rf values on thin-layer chromatography for octanoic acid, the original list of compounds was not provided in the student question.
However, Rf values are affected by factors like polarity, size, and solubility.
Generally, compounds with lower polarity and smaller size will have higher Rf values, as they have a greater affinity for the mobile phase and will move faster on the TLC plate.
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why did we calculate the difference between segments rather than simply reporting the point-to-twitch velocities?
Answers
The reason why we calculate the difference between segments rather than simply reporting the point-to-twitch velocities is that the point-to-twitch velocities change from one segment to the next due to the effect of inertial forces.
A segment is part of a trajectory between two key points of interest. Point-to-twitch is a measure of the speed of movement between successive key positions. Velocity is the rate at which an object changes its position. It is a vector quantity that has a magnitude (speed) and a direction. It is also known as the rate of change of displacement. We need to calculate the difference between segments because the movement speed is not constant during a movement. The point-to-twitch velocities change from one segment to the next because of the impact of inertial forces. The inertial forces play a crucial role in influencing the velocity of the system. Inertial forces act in a direction opposite to the acceleration of the system.
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a 2-kg object moving with a velocity of 7 m/s in the positive x direction strikes and sticks to a 5-kg object moving with a speed of 3 m/s in the same direction. how much kinetic energy is lost in this collision?
Answers
The kinetic energy lost in this collision is 1.07 J. The negative sign indicates that the kinetic energy is lost during the collision.
Mass of 1st object = 2 kg, Velocity of 1st object = 7 m/s. Mass of 2nd object = 5 kg, Velocity of 2nd object = 3 m/s. We need to calculate the kinetic energy lost in this collision. As both the objects are moving in the same direction, we can apply the conservation of momentum equation for this type of collisions. Let us apply the equation for conservation of momentum before and after the collision:
Initial momentum = m1v1 + m2v2= (2 kg) (7 m/s) + (5 kg) (3 m/s)= 14 kg m/s + 15 kg m/s= 29 kg m/s. Final momentum = (m1 + m2) vf= (2 kg + 5 kg) vf= 7 kg vf. According to the conservation of momentum equation, Initial momentum = Final momentum29 kg m/s = 7 kg vfvf = 4.143 m/s. Now, we can apply the equation for kinetic energy to find out how much kinetic energy is lost in this collision.
Initial kinetic energy of the system = (1/2) m1v12 + (1/2) m2v22= (1/2) (2 kg) (7 m/s)2 + (1/2) (5 kg) (3 m/s)2= 49 J + 22.5 J= 71.5 J. Final kinetic energy of the system = (1/2) (m1 + m2) vf2= (1/2) (7 kg) (4.143 m/s)2= 72.57 J. Therefore, the kinetic energy lost in this collision is: Kinetic energy lost = Initial kinetic energy - Final kinetic energy= 71.5 J - 72.57 J= -1.07 J
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two long straight wires are parallel and 8.0 cm apart. they are to carry equal currents such that the magnetic field at a point halfway between them has magnitude 300 ,ut. (a) should the currents be in the same or opposite directions? (b) how much current is
Answers
a) The currents should be in the same direction to produce a magnetic field of magnitude 300 uT.
b) To produce a magnetic field of magnitude 300 uT, the two wires must carry an equal current of [tex]I = \sqrt{(300*10^{-6} / (2*(4*\pi*10^{-7}))}[/tex] = 0.220 A.
The magnetic field is created by the combination of the two parallel wires and can be found using Ampere's Law: B = (μ0 * I) / (2π * d), where μ0 is the permeability of free space, I is the current, and d is the distance between the two wires.
When two long straight wires are parallel and 8.0 cm apart, and they are to carry equal currents such that the magnetic field at a point halfway between them has magnitude 300 μT, the currents should be in opposite directions. Let's find out how much current is required. Given:Magnetic field, B = 300 μT. Distance between two wires, d = 8 cm = 0.08 mWe need to find out the current required. Formula: Magnetic field due to the wire, B = µ₀I/(2πd) where µ₀ is the permeability of free space and I is the current. Substituting the given values in the above formula, we get:300 × 10⁻⁶ = (4π × 10⁻⁷) × I/(2π × 0.08)I = (300 × 2 × 0.08)/4π × 10⁻⁷I = 1.2 × 10⁴ A.
Therefore, the current required is 1.2 × 10⁴ A.(a) The currents should be in opposite directions.(b) The required current is 1.2 × 10⁴ A.
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Kinetic energy of a gas molecule depends on:
A. PressureB. VolumeC. TemperatureD. All the above
Answers
Kinetic energy of a gas molecule depends on temperature. The correct answer is option C.
The kinetic energy of a molecule is the energy that it possesses due to its motion. This kinetic energy depends on temperature. Hence, the correct option is C: Temperature.
When we raise the temperature of a gas, we increase the kinetic energy of the gas molecules. When the temperature of a gas increases, the gas molecules start moving with more speed. As a result, the average kinetic energy of the gas molecules increases.
What is Kinetic Energy?Kinetic energy is the energy that is associated with the motion of an object. Kinetic energy is a scalar quantity, and it depends on the mass and speed of the object. The formula for kinetic energy is given by
K = 1/2mv²
Where
K represents the kinetic energy of the object,
m represents the mass of the object,
v represents the speed of the object.
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50 points!
A. The object in the diagram above is called a(n)? _____
B. Given only the materials in the diagram, how can the strength of the magnetic field be increased? _____
Answers
Answer:
A. it is Electromagnet
B. there are 2 ways to increase the magnetic field in this situation.
by increasing the number of turns of wire in coilsecond, by increasing the current flowing. ( this step can not be achieved as the supply that is battery here, would not increase or decrease its current flow).
hence only by doing first way ( increase number of turns) magnetic field can be increased.
When ultraviolet light with a wavelength of 400.0 nm falls on a certain metal surface, the maximum kinetic energy of the emitted photoelectrons is measured to be 1.10 eV. What is the maximum kinetic energy of the photoelectrons when light of wavelength 300.0 nm falls on the same surface?
Answers
The maximum kinetic energy of the photoelectrons when light of wavelength 300.0 nm falls on the same surface is 1.83 eV.
The maximum kinetic energy of the photoelectrons when light of wavelength 300.0 nm falls on the same surface is 1.83 eV.Step-by-step explanation:
Given, The wavelength of light, λ₁ = 400.0 nm.
The maximum kinetic energy of the emitted photoelectrons, K₁ = 1.10 eV. We need to find the maximum kinetic energy of the photoelectrons when light of wavelength 300.0 nm falls on the same surface.
We know that the maximum kinetic energy of the photoelectrons is given byK.E = (hc/λ) - Φwherehc = 4.14 x 10⁻¹⁵ eV s.
Planck's constant = 6.63 x 10⁻³⁴ JsΦ = work function of the metal surface.
The work function of the metal surface is the energy required to remove an electron from the metal surface. It is the minimum energy required to emit an electron from the surface of the metal.
For metals, it lies between 2 eV and 6 eV. We can write K. E₁ = (hc/λ₁) - ΦK.E₂ = (hc/λ₂) - ΦDividing equation (1) by equation (2), we getK.E₁/K.E₂ = λ₂/λ₁.
Substituting the given values, we get
1.10 eV/K.E₂ = 300.0 nm/400.0 nmK.E₂ = (1.10 eV)(400.0 nm)/(300.0 nm)K.E₂ = 1.83 eV
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The charge on A is +6,4
The charge on B is 24,6
Express each charge in Coulombs using scientific notation
Answers
The charge on A is +10.24x10-19 Coulombs and the charge on B is 39.36x10-19 Coulombs.
Describe Coulomb's Law. Coulomb's law states that the force of attraction or repulsion between two charged bodies is inversely proportional to the square of the distance between them and directly proportional to the product of their charges.
Charge of an electron is =0.00000000000000000016
=10000000000000000000016
=102016
=10201.6×10
=10191.6
=1.6×10−19
so the charge on A is +6.4x 1.6x10-19 , 10.24x10-19Coulombs
similarly,
The charge on B is 24,6x1.6x10-19 , 39.36x10-19 Coulombs
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a parallel-plate capacitor is charged by a 12.0 v battery, then the battery is removed. a. what is the potential difference between the plates after the battery is disconnected? b. what is the potential difference between the plates after a sheet of teflon is inserted between them?
Answers
The potential difference between the plates after the battery is disconnected is equivalent to the potential difference produced by the charge separated by the capacitor.
This is given by the formula; V = Q/C
Where V is the potential difference, Q is the charge stored by the capacitor, and C is the capacitance of the capacitor. Since the battery is removed after charging, the capacitor would still retain its charge, which is calculated using the capacitance and potential difference given in the question.
IQ = VCQ = (12.0 V) (4.50 x 10-7 F)Q = 5.40 x 10-6 C
Substituting the value of charge in the formula, the potential difference between the plates after the battery is disconnected is given by;
V = Q/CV = 5.40 x 10-6 C / 4.50 x 10-7 FV = 12.0 Vb.
Potential Difference After Sheet of Teflon is Inserted: If a sheet of Teflon is inserted between the plates of the capacitor, the capacitance of the capacitor would change. This is because the dielectric constant of Teflon is greater than that of air or vacuum, which increases the capacitance.
The formula for calculating capacitance with a dielectric inserted is; C = ε0A/
where C is the capacitance, ε0 is the permittivity of free space, A is the area of the capacitor plates, and d is the distance between the plates.
With Teflon inserted, the new capacitance of the capacitor is given by; CT = Kε0A/where K is the dielectric constant of Teflon, which is given as 2.10 for Teflon. The new capacitance is therefore; CT = (2.10) (8.85 x 10-12 F/m) (0.400 m2) / 1.00 x 10-3 mCT = 7.46 x 10-11 F
The potential difference after the sheet of Teflon is inserted is given by the formula;V = Q/CT
Where V is the potential difference, Q is the charge stored by the capacitor, and CT is the new capacitance of the capacitor with Teflon inserted.
The charge stored in the capacitor would remain constant, which is 5.40 x 10-6 C from part a of the question. Substituting the values in the formula gives;
V = 5.40 x 10-6 C / 7.46 x 10-11 FV = 7245.56
The potential difference between the plates after the sheet of Teflon is inserted is 7245.56 V.
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when an object is placed 29.5 cm in front of a convex spherical mirror, a virtual image forms 12.0 cm behind the mirror. determine the mirror's focal length in cm and the magnification.
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The focal length of the convex spherical mirror is 18.4 cm. The magnification is approximately equal to -0.41.
The distance of the object is 29.5 cm from the convex mirror and the image distance is 12.0 cm from the mirror.
The given mirror is a convex spherical mirror which means that the radius of the curvature of the mirror is positive. Therefore, we can use the mirror formula to calculate the focal length of the mirror.
The mirror formula is given by the equation:
1/f = 1/u + 1/v
Here,
f is the focal length of the mirror
u is the distance of the object from the mirror
v is the distance of the image from the mirror
The magnification of the mirror is given by the equation:
magnification, m = v/u
Now,
substituting the values given in the question in the above equations,
we get;
1/f = 1/29.5 + 1/12
Simplifying this equation gives, f ≈ 18.4 cm
Therefore, the focal length of the convex spherical mirror is 18.4 cm.
Now, the magnification of the mirror is given by the equation,
m = v/u = -12/29.5
Thus, the magnification is approximately equal to -0.41.
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Helppp plsssssssssssssssssssssssss
Answers
Answer:
if it is -1^02
your answer is 1
rock that has formed from lithification of any type of sediment, including clastic or chemical sediments, or organic remains.is called?
Answers
Sedimentary rock refers to any rock that has formed as a result of the lithification of sediment, including clastic, chemical, or organic remnants.
Three groups make up the classification of sedimentary rocks. These three types of sedimentary rocks are clastic, chemical, and organic. Rocks that are clastic in natureRock fragments that were already there that have been eroded, moved, and deposited by wind, water, or ice make up clastic sedimentary rocks. Sandstone, conglomerate, and shale are a few examples of clastic rocks.Chemical sedimentary rocks As dissolved minerals precipitate out of water, chemical sedimentary rocks are created. The chemical rocks limestone and gypsum are two examples.Rocks with organic sediments Sedimentary rocks that contain organic material were previously living organisms like plants and animals. The rocks coal and chalk are examples of organic rocks.To know more about rock
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suppose that the current in an lc circuit (a circuit having only an inductor and capacitor in series) oscillates with a certain frequency. if the inductance is increased by a factor of 9.72 and the capacitance is increased by a factor of 6.12 by what factor is the frequency of oscillation multiplied?
Answers
The frequency of oscillation is multiplied by the square root of the product of the factors of inductance and capacitance. In this case, the frequency is multiplied by the square root of 9.72 multiplied by 6.12, which is equal to 11.3.
Suppose that the current in an LC circuit oscillates with a certain frequency. If the inductance is increased by a factor of 9.72 and the capacitance is increased by a factor of 6.12, the factor by which the frequency of oscillation is multiplied is calculated as follows:
Let L be the initial inductance and C be the initial capacitance of the LC circuit. The angular frequency of oscillation of the LC circuit is given by the expression [tex]\omega= 1/\sqrt{LC}[/tex] where ω is the angular frequency, L is the inductance, and C is the capacitance.
The new angular frequency of the LC circuit is ω′ = 1/√(L′C′)where L′ and C′ are the new inductance and capacitance, respectively. Let L′ = 9.72L and C′ = 6.12C. Substituting these values into the equation above gives ω′ = 1/√(9.72LC × 6.12C)ω′ = 1/√(59.4384LC)ω′ = (1/√59.4384) × (1/√(LC))ω′ = (0.161)ω.
Therefore, the factor by which the frequency of oscillation is multiplied is 0.161. Therefore, the frequency of oscillation is decreased by a factor of 6.192.
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Photovoltaic cells use _______ to produce electricity.
a. water stored by a dam
b. heat energy of coal or petroleum
c. wind energy d. solar energy
Answers
Photovoltaic cells use solar energy to produce electricity. The correct option is D.
Photovoltaic cells convert sunlight into electrical energy by converting the energy of photons, which are particles of light. The photovoltaic cell works by separating electric charges in a solid state using the photoelectric effect.
The electric field inside the cell causes the separated charges to flow through the circuit, providing electrical power to the load. Silicon is the most widely utilized material for solar cells.
The photovoltaic effect was initially observed by Edmond Becquerel in 1839, and it was first exploited in the 1950s when photovoltaic silicon was made into semiconductors, which was a technology that had already been in use in the semiconductor industry for over a decade.
In conclusion, solar energy is a renewable and clean source of energy that is produced by photovoltaic cells that convert sunlight into electrical energy using the photovoltaic effect.
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at a location in europe, it is necessary to supply 300 kw of 60-hz power. the only powersource available operate at 50-hz. it is decided to generate the power by means of motor-generator set consisting of synchronous motor driving a synchronous generator. how manypoles should each of the two machines have in order to convert 50-hz to 60-hz power?
Answers
The synchronous motor should have 24 poles and the synchronous generator should have 20 poles in order to convert 50 Hz to 60 Hz power
Given that the location in Europe requires 300 kW of 60 Hz power and the only power source available operates at 50 Hz, it is decided to generate the power by means of a motor-generator set consisting of a synchronous motor driving a synchronous generator. It is required to find how many poles each of the two machines should have in order to convert 50 Hz to 60 Hz power.
Let the synchronous motor have ns number of poles and synchronous generator have ng number of poles.In a synchronous machine, the number of poles is directly proportional to the synchronous speed of the machine.
Hence, synchronous speed (n) is given by; n = 120f/p
where f is the frequency of the supply in Hz and p is the number of poles.
Since the generator is required to deliver power at 60 Hz, the synchronous speed of the generator should be 3600 RPM.∴ 3600 = 120 × 60 / ng
Solving this, we get;
[tex]n_g = 20[/tex]
Also, since the motor is supplied with a 50 Hz power supply, its synchronous speed should be 3000 RPM.∴ 3000 = 120 × 50 / [tex]n_s[/tex]
Solving this, we get; [tex]n_s[/tex] = 24
Therefore, the synchronous motor should have 24 poles and the synchronous generator should have 20 poles in order to convert 50 Hz to 60 Hz power.
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I want a molecule consist of 200 out of and one option in Health together by
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The dsDNA molecule with 200 nucleotides and 20% guanine would have a total of 240 hydrogen bonds.
Calculating the number of hydrogen bonds in the moleculeIn a double-stranded DNA molecule, the number of hydrogen bonds between complementary base pairs determines the stability of the molecule.
Guanine (G) pairs with cytosine (C), and adenine (A) pairs with thymine (T), with each base pair forming a specific number of hydrogen bonds.
The number of hydrogen bonds in a G-C base pair is three, while the number of hydrogen bonds in an A-T base pair is two.
Therefore, to determine the number of hydrogen bonds in a dsDNA molecule with 20% guanine, we first need to calculate the number of guanine-cytosine base pairs.
If 20% of the nucleotides are guanine, then 20% of the nucleotides will be cytosine as well (since G always pairs with C). The remaining 60% will be made up of adenine and thymine in equal amounts.So out of the 200 nucleotides, 20% will be guanine and 20% will be cytosine, which means there will be 40% G-C base pairs.
The number of G-C base pairs can be calculated by multiplying the total number of base pairs (200/2 = 100, since each nucleotide pairs with one other nucleotide) by the percentage of G-C base pairs (40% or 0.4):
Number of G-C base pairs = 100 x 0.4 = 40
Therefore, the total number of hydrogen bonds in the dsDNA molecule would be:
Number of hydrogen bonds = (number of G-C base pairs x 3) + (number of A-T base pairs x 2)
= (40 x 3) + (60 x 2)
= 120 + 120
= 240
So the total number of hydrogen bonds in the dsDNA molecule is 240
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Complete question
A dsDNA molecule consists of 200 nucleotides with 20% guanine.
What is the number of hydrogen bonds in that molecule ? 1) 360 2) 260 3) 180 4) 240
IS
Find the components to write this
vector in unit vector notation:
BR
12.0
45.0⁰
B = [? ]î+ [? ]
Answers
The vector BR in unit vector notation is:
BR = 8.485 î + 8.485 j
What is Vector?
Vectors can be added together to find the result, which is known as the vector sum. The vector sum can be found using the head-to-tail method, where the tail of one vector is placed at the head of the other vector. The vector sum is the vector that goes from the tail of the first vector to the head of the second vector.
To write the vector BR in unit vector notation, we need to find its components in the i and j directions.
Given that the magnitude of the vector is 12.0 and it makes an angle of 45 degrees with the positive x-axis, we can use trigonometry to find the components.
The x-component (i-direction) of the vector is given by:
Bx = B cos θ = 12.0 cos 45° = 8.485
The y-component (j-direction) of the vector is given by:
By = B sin θ = 12.0 sin 45° = 8.485
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The wave in which medium particles move perpendicular to the direction of wave is_________.Longitudinal waveTransverse waveBoth 1 and 2Neither 1 nor 2
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The wave in which medium particles move perpendicular to the direction of wave is transverse wave. Option b is correct.
The wave in which medium particles move perpendicular to the direction of wave is a transverse wave. In a transverse wave, the motion of the particles in the medium is perpendicular to the direction of propagation of the wave. This means that when a transverse wave passes through a medium, the particles in the medium move up and down or side to side, perpendicular to the direction of the wave. Examples of transverse waves include light waves, electromagnetic waves, and waves on a string.
In contrast, in a longitudinal wave, the motion of the particles in the medium is parallel to the direction of propagation of the wave. Hence option b is correct choice.
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Which of these stars has the greatest surface temperature?
a. a main-sequence B star b. a supergiant A star
c. a giant K star
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The main-sequence option B star has the greatest surface temperature out of the given stars.
What is a main-sequence star?A main-sequence star is a star that emits energy by nuclear fusion, particularly helium into carbon. These stars are distinguished by the fact that they are burning hydrogen in their cores. Their temperature, luminosity, and lifetime are all directly related to their mass.
According to the Hertzsprung-Russell diagram, a B-star refers to a hot, bright, and blue star that falls on the main sequence of the chart. The surface temperature of a main-sequence B star is about 10,000 Kelvin. Giant K stars and supergiant A stars have much lower surface temperatures than main-sequence B stars.
What is a giant K star?A giant K star is a type of star with a radius between 10 and 100 times that of the Sun. They are often orange, reddish-orange, or reddish-yellow in color. Giant K stars are a type of cool star, with temperatures ranging from 3,900 K to 5,200 K.
What is a supergiant A star?A supergiant A star is a type of star with a mass of more than 10 times that of the Sun. They are bigger and more luminous than normal stars. Their surface temperature is between 7,500 and 9,000 Kelvin, and they have a life expectancy of around 10 million years.
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