Which units are used to express sound intensity?
Answer: decibels
Explanation:
if you lift weights faster than normal you have increased what?
A work
B force
C power
D distance
A hiker is traveling through the woods. He first travels east 125 m and then turns and travels 36 m north . What his his resultant displacement. Make sure you include magnitude , direction , and angle.
Answer:
can you put it in a sentence
calculate the gravitational force between earth and sun
Answer:
Given that the mass of the earth = 6 x 1024 kg, mass of the sun = 2 x 1030 kg, average distance between the two is 1.5 x 10-11 m and G = 6.67 x 10-11 Nm2kg-2
Explanation:
Please help me will mark u brainiest
Answer:
Answer: B. 12 N
Explanation:
Static Equilibrium
Static equilibrium occurs when an object is at rest, i.e., neither rotating nor translating.
In the static rotational equilibrium, the total torque is zero with respect to any rotational axis.
The torque applied by a force F perpendicular to a displacement X with respect to a reference rotating point is:
T = F*X
Considering the pivot as the rotating point, there are 3 forces producing torque. Let's consider counterclockwise torques as positive, thus:
30N * 40 cm - 60 N * 30 cm + F (30 cm + 20 cm) = 0
Operating:
1200 N.cm - 1800 N.cm + F(50 cm) = 0
- 600 N.cm + F(50 cm) = 0
Solving for F:
F = 600/50
F = 12 N
Answer: B. 12 N
when two resistors are wired in series with a 12 v battery, the current through the battery is 0.31 a. when they are wired in parallel with the same battery, the current is 1.60 a.
R₁ = 28. 535 v and R₂ 10.125 Ω are the resistance are wired in series with a battery.
Let R₁ and R₂ be the two Resistance
resistance - which resists the flow of current.
R₁ - Resistance of 1st resistor
R₂ - Resistance of 2nd resistor
V = Voltage = 12V
I = O.31A ( in series)
I = 1.6 A ( in parallel)
when two resistance connected in series then
Rs = R₁ + R₂
V = IRs = 12 /0.31 V
R₁+R₂ = 38.700Ω (equation1.)
When two resistance connected in parallel then the value of R is.
[tex]R_{p} =\frac { R_{1} R_{2}}{R_{1} + R_{2} }[/tex]
V = I Rp
V= I (R₂ R₁ /R₁ +R₂)
R₁ R₂ = 290.25 Ω
As we know
(R₁ - R₂ ) ² = (R₁ + R₂ ) ² - 4R1R2
Using above values we get,
(R₁ - R₂ ) ² = (38.70) ² - 4x 290.25
(R₁ - R₂ ) ² = 336.69 Ω
R₁ - R₂ = 18.34 (equation 2 )
Using equation 1 and 2 we get
R₁+ R₂ = 38.70 52
R₁ - R₂ = 18.34
R₁ = 28.535 Ω
Using the value of R₁ in equation 1 we get
R₂ = 38·700 - 28.535
R₂ = 10.125 Ω
R₁ = 28. 535 v and R₂ 10.125 Ω are the resistors are wired in series with a battery.
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What’s our “blind spot”?
Answer:
inside of our brain and the above the nose
you know the mass of an object and the force applied to it. which equation will tell you the acceleration of the object?
Answer:
This equation for acceleration can be used to calculate the acceleration of an object when its mass and the net force acting on it are known.
so it wa The equation for the acceleration can be rewritten as to calculate the nets force acting on an object when its mass and acceleration
Answer: F=ma
Explanation:
What happens when plate subducts and reaches the mantle
Answer:
burns
Explanation:
Conclusion When there is a constant unbalanced force applied in the same direction as the motion, speed will ___________________ and acceleration will _____________________________. When there is an increasing unbalanced force applied in the same direction as the motion, speed will ___________________ and acceleration will ________________________. When there is a constant unbalanced force applied in the opposite direction as the motion, speed will ___________________ and acceleration will ________________________. When there is an increasing unbalanced force applied in the opposite direction as the motion, speed will ___________________ and acceleration will ________________________.
Explanation:
When there is a constant unbalanced force applied in the same direction as the motion, speed will increase and acceleration will remain constant. When there is an increasing unbalanced force applied in the same direction as the motion, speed will increase and acceleration will increase.
According to newton's 2nd law
F = ma
F ∝ a
meaning when F increases , a increases and vice versa
A force of 75N accelerates a box at 5 m/s2. What is the mass of the box?
Answer:
15 kg
Explanation:
mass=force÷acceleration
force: 75N
acceleration: 5 m/s^2
mass = 75 / 5
= 15 kg
If the answer made sense, please give me brainliest :)
Density of water is 1000kg/meter cube. what will be the volume of 35000kg water
Answer:
i think 35 cubic meters of water
Explanation:
pls solve this numerical.
Answer:
[tex]{ \rm{A .B = |A| |B| \sin( \theta) }} \\ { \rm{A.B = 5 \times 7 \times \sin(45) }} \\ { \rm{A.B = 35 \times \frac{1}{ \sqrt{2} } }} \\ \\ { \rm{A.B = \frac{35}{ \sqrt{2} } }}[/tex]
rationalise the denominator;
[tex]{ \rm{A.B = \frac{35}{ \sqrt{2} } \times \frac{ \sqrt{2} }{ \sqrt{2} } }} \\ \\ { \rm{A.B = \frac{35 \sqrt{2} }{2} }}[/tex]
A. Group of cross country runners decided to go on an hour and a half run. During the first hour, they ran a total of 13 kilometers. Then, they ran 5.0 kilometers during the next half an hour. What was the group's average speed for the entire run?
Answer:
The average speed for the entire run is 12 km/h.
Explanation:
The average speed is given by the following equation:
[tex] \overline{v} = \frac{d_{T}}{t_{T}} [/tex]
Where:
[tex]d_{T}[/tex]: is the total distance
[tex]t_{T}[/tex]: is the total time
If during the first hour, they ran a total of 13 kilometers and then, they ran 5.0 kilometers during the next half an hour we have:
[tex] d_{T} = 13 km + 5 km = 18 km [/tex]
[tex] t_{T} = 1 h + \frac{1}{2} h = 1.5 h [/tex]
Hence, the average speed is:
[tex] \overline{v} = \frac{d_{T}}{t_{T}} = \frac{18 km}{1.5 h} = 12 km/h [/tex]
Therefore, the average speed for the entire run is 12 km/h.
I hope it helps you!
Which event causes the formation of trenches in Earth’s crust?
magma rising
mantle emerging
volcanoes erupting
lithosphere colliding
A car starts from rest and accelerates to a speed of 30 m/s in 20 seconds, what is its acceleration
The acceleration of a car that starts from rest and accelerates to a speed of 30 m/s in 20 seconds is 1.5 m/s².
What is the acceleration of the car?Acceleration is defined as the change in velocity of a body or an object with time.
Mathematically;
Acceleration = change in velocity/time takenThe acceleration of the car is calculated using the equation of motion as follows:
v = u + a * t
where;
v is the final velocity
u is the initial velocity
t is the time taken
a is the acceleration
From the dat provided: v = 30 m/s, t = 20 s, u = O m/s
a = v - u/t
a = 30 - 0/20
a = 1.5 m/s²
Therefore, the acceleration of the car that starts from rest and accelerates to a speed of 30 m/s in 20 seconds, is 1.5 m/s².
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help me
1. A girl drops her new I-phone in the parking garage at First Colony Mall off a 22m ledge.
How fast is her phone moving just before racking into pieces?
2. An AHS football player throws a soccer ball straight up at 4m/s. How long does it take
for it to come back to their hand?
3. Batman throws a Batarang 31 m/s into the air. How high does it go?
4. A rock falls off a cliff for 0.004 hours, how high was the cliff?
5. An object is thrown into the air going 11 m/s. How fast is it going 2 seconds later?
1. The phone is moving with a velocity of 20.77 m/s before racking into pieces
2. The time taken for the ball to come back to their hand is 0.82 s
3. The maximum height reached by the batarang is 49.03 m
4. The cliff is 1016.06 m high
5. The object is moving with a velocity of –8.6 m/s after 2 s
1. How to determine the velocityInitial velocity (u) = 0 m/sAcceleration due to gravity (g) = 9.8 m/s²Maximum height (h) = 22 mFinal velocity (v) = ?v² = u² + 2gh
v² = 0² + (2 × 9.8 × 22)
v² = 431.2
Take the square root of both side
v = √431.2
v = 20.77 m/s
2. How to determine the time taken for the ball to come backWe'll begin obtaining the time taken to reach the maximum height. This is illustrated below:
Initial velocity (u) = 4 m/sFinal velocity (v) = 0 m/s (at maximum height) Acceleration due to gravity (g) = 9.8 m/s²Time to reach maximum height (t) =?v = u – gt (since the ball is going against gravity)
0 = 4 – (9.8 × t)
0 = 4 – 9.8t
Collect like terms
0 – 4 = –9.8t
–4 = –9.8t
Divide both side by –9.8
t = –4 / –9.8
t = 0.41 s
Finally, we shall determine the time for the entire trip
Time to reach maximum height (t) = 0.41 sTime for the entire trip (T) =?T = 2t
T = 2 × 0.41
T = 0.82 s
3. How to determine the maximum height Initial velocity (u) = 31 m/sFinal velocity (v) = 0 m/s (at maximum height) Acceleration due to gravity (g) = 9.8 m/s²Maximum height (h) =?v² = u² – 2gh (since the ball is going against gravity)
0² = 31² – (2 × 9.8 × h)
0 = 961 – 19.6h
Collect like terms
0 – 961 = –19.6h
–961 = –19.6h
Divide both side by –19.6
h = –961 / –19.6
h = 49.03 m
4. How to determine the height of the cliffAcceleration due to gravity (g) = 9.8 m/s²Time (t) = 0.004 h = 0.004 × 60 × 60 = 14.4 s Height (h) =?h = ½gt²
h = ½ × 9.8 × 14.4²
h = 4.9 × 207.36
h = 1016.06 m
5. How to determine the velocityInitial velocity (u) = 11 m/sAcceleration due to gravity (g) = 9.8 m/s²Time (t) = 2 sFinal velocity (v) = ?v = u – gt (since the ball is going against gravity)
v = 11 – (9.8 × 2)
v = 11 – 19.6
v = –8.6 m/s
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a copper wire that is 1 mm thick and 30 cm long is connected to a 1 v battery. (the resistivity of copper is 1.69 x 10-8 ω⋅m.)
A copper wire that is 1 mm thick and 30 cm long is connected to a 1 v battery. (the resistivity of copper is 1.69 x 10-8 ω⋅m). The power is 154.82 W.
As we know the formula of Power:
P = V²/R ......(i)
Where,
P = power dissipated, V = voltage R = resistance
Now,
R = Lρ/A .....(ii)
Where,
L = length of the wire, A = cross-sectional area, ρ = resistivity of the wire.
From eq (i) and eq(ii),
P = V²/(Lρ/A)
P = AV²/Lρ........ (iiI)
Here,
A = πd²/4, Where d = 1 mm
A = (3.14×0.001²/4) = 7.85×10⁻⁷ m²
Putting the value of A and the given values from the question in equation (iii).
P = (7.85×10⁻⁷×1²)/(0.3×1.69 x 10⁻⁸)
P = 154.82 W
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An object moving due west collides with a second object that is initially at rest. Just after the collision the first object is moving toward the southeast. Just after the collision the second object must be moving toward the
Answer: Northwest.
Explanation:
After the collision the second object which was at rest would change its direction and move towards the Northwest. The object in motion was coming from the east and traveling towards the west, where it deflects against a stationery object which changes its direction to southeast. And the object which was at rest moves toward the northwest.
1) A person slides a box down a ramp. The box starts from rest 2m above the lowest
point. The ramp is frictionless, Once the box reaches the bottom there is friction
For every 1m the box travels on the flat part Eint increases by 100). Where does the
box stop? The box has mass of 5 kg.
Answer:
.98m
Explanation:
A soccer ball is kicked 7 meters west and then 3 meters east.
What is the DISTANCE?
What is the DISPLACEMENT?
Answer:
4 meters............
.
.
.
.
.
A rock is thrown from the top of the Empire State Building. What is the overall acceleration it will experience?
Answer:
acceleration due to gravity is constant anywhere on the earth .its value is 9.8m/s²
Can you please answer theese two qeastion
Answer:
C.
Explanation:
kase anjan na yung sagot ohh
Review. A metal rod of mass m carrying a current I glides on two horizontal rails a distance d apart. If the coefficient of kinetic friction between the rod and rails isμ , what vertical magnetic field is required to keep the rod moving at a constant speed?
The vertical magnetic field required to keep the rod moving at a constant speed is IBd=[tex](u_{k} )[/tex]mg.
What is magnetic field?
When describing the distribution of the magnetic force in the area surrounding and inside of a magnetic object, we use the metaphor of a magnetic field.
The most of us are somewhat familiar with common magnetic items and are aware that there may be forces present between them. We know that magnets have two poles, and that two magnets can be attracted (opposite poles) or repellent depending on how they are oriented (similar poles). We understand that this occurs in some area that surrounds a magnet. Described by the magnetic field, this area.
Mathematics uses a vector field to represent the magnetic field. An array of several vectors drawn on a grid can be used to directly plot this vector field.
Explanation:
Given mass of rod ,m
current carrying= I
Separation between rails =d
The kinetic friction coefficient, uk
The force of magnetic field (F) is perp. to the magnetic field.
Let required magnetic field be B.
Now balancing forces in y-direction,
N=mg
And. in x-direction,
F=f
IBd= [tex]u_{k}[/tex]N
IBd=[tex](u_{k} )[/tex]mg
B=[tex]\frac{u_{k} mg}{Id}[/tex]
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label each statement 1 2 or 3 for the law of motion it illudtrates
Answer:
2
1
2
1
3
1
Explanation:
I'm pretty sure these are right. you might want to go back and check the first and third, but the other 4 are right
The greater mass will have greater acceleration is a fact from second law of motion. Thus, first situation is an example of second law. Spilling of water from the glass indicates the first law , that is law of inertia.
What are laws of motion ?Newton' s first law of motion states that, every body tends to continue on the state of motion or rest until an external force acts upon it. This law is called law of inertia.
Second law states that the force applied on a body is directly proportional to the mass and acceleration.
Newton's third law states that, for every action there is an equal and opposite reaction. The first statement indicates the second law of motion and water spilling indicates the law of inertia.
As the mass increases, more force to be applied and acceleration decreases with mass. Thus third situation indicates second law. The magician pulling the cloth from stationary, hence it is first law.
A rocket launches by a force applied on the space and an opposing force from the fuel make it move indicating the third law. The last situation indicates the first law. Hence, the labeling is as 2,1,2,1,3,1.
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On a 80 km track, a train travels 40 km with a uniform speed of 30 km h¹. How fast must the train travel the next 40 km so as to have average speed 40 km h-¹ for the entire trip?
[tex]{ \qquad\qquad\huge\underline{{\sf Answer}}} [/tex]
Here we go ~
In first 40 km, it travels with speed of 30 kmph
So, time taken in this span is :
[tex]\qquad \sf \dashrightarrow \: \dfrac{40}{30} [/tex]
[tex]\qquad \sf \dashrightarrow \: \dfrac{4}{3} \: \:hours[/tex]
And let's assume that it travels with uniform speed of x kmph during next 40 km
Now, time taken in this span of time is :
[tex]\qquad \sf \dashrightarrow \: \dfrac{40}{x} \: \: kmph [/tex]
Now, we know the formula to find average velocity ~
[tex]\qquad \sf \dashrightarrow \: v_{avg} = \dfrac{total \: \: distance \: \: covered}{total \: \: time \: \: taken} [/tex]
[tex]\qquad \sf \dashrightarrow \: 40 = \dfrac{80}{ \frac{40}{30} + \frac{40}{x} } [/tex]
[tex]\qquad \sf \dashrightarrow \: \dfrac{40}{30} + \dfrac{4 0}{x} = \dfrac{80}{40} [/tex]
[tex]\qquad \sf \dashrightarrow \: 40 \bigg( \dfrac{1}{30} + \dfrac{1}{ {x}^{} } \bigg) = \dfrac{80}{40} [/tex]
[tex]\qquad \sf \dashrightarrow \: \dfrac{1}{30} + \dfrac{1}{ {x}^{} } = \dfrac{2}{40} [/tex]
[tex]\qquad \sf \dashrightarrow \: \dfrac{1}{x} = \dfrac{1}{20} - \dfrac{1}{30} [/tex]
[tex]\qquad \sf \dashrightarrow \: \dfrac{1}{x} = \dfrac{3 - 2}{60} [/tex]
[tex]\qquad \sf \dashrightarrow \: \dfrac{1}{x} = \dfrac{1}{60} [/tex]
[tex]\qquad \sf \dashrightarrow \: x = 60 \: \: kmph[/tex]
So, for next 40 km, he need to maintain average speed of 60 kmph, in order to keep an average of 40 kmph for the whole trip ~
The accompanying table shows measurements of the Hall voltage and corresponding magnetic field for a probe used to measure magnetic fields. (a) Plot these data and deduce a relationship between the two variables.
The value of [tex]V_{H}[/tex] is[tex](1.00\times10^{-4} V/T)B[/tex].
What is a magnetic field?
The magnetic influence on moving electric charges, electric currents, and magnetic materials is described by a magnetic field, which is a vector field. A force perpendicular to the magnetic field and its own velocity acts on a moving charge in a magnetic field. The magnetic field of a permanent magnet pulls on ferromagnetic substances like iron and attracts or repels other magnets. A magnetic field that varies with location will also exert a force on a variety of non-magnetic materials by changing the velocity of those particles' outer electrons. Electric currents, like those utilized in electromagnets, and electric fields that change in time produce magnetic fields that surround magnetized things. Since a magnetic field's position can affect both its strength and its direction.
By using the trend line option in excel, we get
[tex]\Delta V_{H} (in\mu V) = 100B[/tex]
[tex]\Delta V_{H} (V)= (\frac{100} {10^{-6} } V/T)B[/tex]
=[tex](1.00\times10^{-4} V/T)B[/tex]
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Suppose you fill two rubber balloons with air, suspend both of them from the same point, and let them hang down on strings of equal length. You then rub each with wool or on your hair so that the balloons hang apart with a noticeable separation between them. Make order-of-magnitude estimates of (d) the total flux of electric field created by each balloon. In your solution, state the quantities you take as data and the values you measure or estimate for them.
The total flux of electric field created by each balloon is 1.7×10^4N/C.
Consider two balloons of diameter 0.200m each with mass 1.00g hanging apart with 0.0500m separation on the ends of string making angles of 10.0° with the vertical.
The electric flux created by each balloon is:
[tex]\phi_{e} = \frac{q}{\epsilon_{0} } = \frac{1.2 \times10^{4}C }{8.85\times10^{-12}C^{2}/N \cdot m^{2}} = 1.4 \times 10^{4} N\cdot m^{2}/C\\[/tex]
Gauss Law states that the total electric flux out of a closed surface is equal to the charge enclosed divided by the permittivity. The electric flux in an area is defined as the electric field multiplied by the area of the surface projected in a plane and perpendicular to the field.
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A ball released from rest on an elevated ramp uniformly accelerates at a rate of 3.52 m/s2 for 23.3m. what is the final speed of the ball?
The final speed of the ball when it accelerate uniformly at a rate of 3.52 m/s² for 23.3 m is 12.81 m/s.
What is speed?Speed can be defined as the ratio of distance to time.
The S.I unit of speed is m/s.
To calculate the final speed of the ball, we use the formula below.
Formula:
v² = u²+2as........... Equation 1Where:
v = Final speedu = Initial speeda = accelerations = distance.From the question,
Given:
u = 0 m/s from resta = 3.52 m/s²s = 23.3 mSubstitute these values into equation 1
v² = 0²+2×3.52×23.3v² = 164.032v = √(164.032)v = 12.81 m/s.Hence, the final speed of the ball is 12.81 m/s.
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Question 25 of 25 What is a limitation of modeling the effect of gravity on a falling object by using a ball dropped from different heights? A. Air slows down the fall of any object, including the ball. B. The weight of the ball can vary. C. Gravity varies slightly at different heights. D. The height that a ball bounces is affected by the height from which it was dropped.
Answer:
Air slows down The fall of any object including a ball.
A limitation of modeling the effect of gravity on a falling object by using a ball dropped from different heights is: gravity varies slightly at different heights. Hence, option (C) is correct.
What is gravity?Gravity is a fundamental interaction in physics that causes all objects with mass or energy to attract one another. The electromagnetic force is 10³⁶ times stronger than gravity the weak interaction is 10²⁹ times weaker than gravity, and gravity is by far the weakest of the four fundamental interactions.
As a result, it has no appreciable impact on subatomic particle level phenomena. However, at the macroscopic level, gravity is the most important interaction between things and governs the motion of planets, stars, galaxies, and even light.
As gravity is inversely proportional to the square of distance, it varies slightly at different heights. Hence, option (C) is correct.
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