if your guitar pick is producing a harsh sound, you should use your fingernail instead relax your wrist, arm, and shoulder make sure your wrist and arm are at a ninety degree angle press the pick more firmly onto the strings

Answers

Answer 1

If your guitar pick is producing a harsh sound, you should make sure your wrist and arm are at a ninety degree angle.

Making of harsh sounds due to the pick from a guitar is seen often during guitar practices from beginners. There are numerous reasons for this. One of the reasons that can be considered as the most often mistake is the way a guitarist holds the pick. In order to avoid the sound produced by the pick, make sure that your wrist and arm are in a ninety degree angle.

This will provide a comfortable position to use the picks. You should not hold the pick firmly either. Try to hold the pick gently. Remember lesser the pick gets in contact with the string, lesser the sound produced. Also try to use a proper pick for guitar.

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Related Questions

Computer-enhanced x-rays are called __________ scans. a. tms b. pet c. ct d. mri please select the best answer from the choices provided a b c d

Answers

Computer-enhanced x-rays are called CT scans.

A CT scan is a computer-based technology and refers to the inside image of the body generated by using X-rays and advanced scientific technology.

The image shows detailed information about various body parts including bones, organs, blood vessels, veins, fat, and muscles.

CT scans are more advanced, innovative, and detailed technology compared to standard X-ray techniques.

Experts performing CT scans are known as radiology technologists or radiographers.

It differs from CAT which is the reduced form of Computer Axial Tomography.

The major difference between CT scan and MRI is that CT scan uses X-rays while MRI uses magnetic fields.

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Two carts connected by a 0.25 m spring hit a wall, compressing the spring to 0.1 m. The spring constant k is 100 N m . What is the elastic potential energy stored from the spring's compression?

Answers

Given that,

Initial position of the spring, x₁ = 0.25 m

Final position of the spring, x₂ = 0.1 m

The spring constant of the spring, k = 100 N/m

To find,

The elastic potential energy stored from the spring's compression.

Solution,

The work done in moving a spring from on position to another is stored in the form of elastic potential energy. It can be given as follows :

[tex]E=\dfrac{1}{2}k(x_2^2-x_1^2)\\\\=\dfrac{1}{2}\times 100\times (0.1^2-0.25^2)\\\\=2.62\ J[/tex]

So, the required energy is 2.62 J.

Answer:

1.125 J

Explanation:

The correct answer is 1.125 J

c) The infra-red detectors are made from thermocouples soldered to blackened metal plates. These are connected to galvanometers. In the space below, draw
a labelled diagram of a thermocouple. [2] [Total 6]

Answers

The infra-red detectors are made from thermocouples soldered to blackened metal plates. These are connected to galvanometers.

What is galvanometers?

A galvanometer measures electric current electromechanically. Early galvanometers were not calibrated, but later models, called ammeters, were, and could measure current flow more precisely.

A galvanometer functions by deflecting a pointer in response to an electric current running through a coil in a steady magnetic field. Galvanometers can be viewed as a particular type of actuator.

The discovery that a magnetic compass needle deflects when near an electric current-carrying wire led to the invention of galvanometers, which was made by Hans Christian rsted in 1820. They were the first tools used to find and gauge minute currents. The apparatus was given the name Luigi Galvani by André-Marie Ampère after the Italian electricity researcher who, in 1791, discovered it.

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A nonconducting ring of radius R is uniformly charged with a total positive charge q. The ring rotates at a constant angular speed \omega about an axis through its center, perpendicular to the plane of the ring. What is the magnitude of the magnetic field on the axis of the ring a distance 1/2 R from its center?

Answers

The magnitude of the magnetic field on the axis of the ring (1/2)R from its center is [tex]\frac{\mu_{0} \omega qR^{2}}{2.5(\sqrt{5} )\pi R }[/tex].

The magnetic influence on moving electric currents, electric charges, and magnetic materials is described by a magnetic field, which is a vector field. A force acting on a charge while it travels through a magnetic field is perpendicular to both the charge's motion and the magnetic field.

The radius of the nonconducting ring is R.

The ring is uniformly charged q.

The ring rotates at a speed of ω.

The distance between the ring and its center is x = (1/2)R.

The magnetic field on a current loop's axis is given as follows:

[tex]B = \frac{\mu_{0} IR^{2}}{4 \pi (x^{2}+R^{2})^{\frac{3}{2}} }[/tex]

Now, [tex]I=\frac{q}{2 \pi /\omega}[/tex]

The magnetic field's strength at x = R/2 is:

[tex]B = \frac{\mu_{0} IR^{2}}{4 \pi (x^{2}+R^{2})^{\frac{3}{2}} }[/tex]

[tex]B = \frac{\mu_{0} IR^{2}}{4 \pi ((\frac{R}{2} )^{2}+R^{2})^{\frac{3}{2}} }[/tex]

[tex]B = \frac{\mu_{0} IR^{2}}{4 \pi ((\frac{5}{4} )R^{2})^{\frac{3}{2}} }[/tex]

[tex]B = \frac{\mu_{0} \omega qR^{2}}{2.5(\sqrt{5} )\pi R}[/tex]

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please help me will mark u brainiest

Answers

Answer:

Answer is A :)))))))))

Newton's first law of motion: Objects in motion will stay in motion and objects at rest will stay at rest, unless acted on by
a. friction
b. acceleration
c. unbalanced force
d. contact force​

Answers

Newton's first law states that every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force. This is normally taken as the definition of inertia

Scientists study how the continents move. Why might scientists use a model
to show this movement?
O A. It is too slow to observe directly.
O B. It is too fast to observe directly.
O C. It is too dangerous to observe directly.
O D. It is too complex to observe directly.

Answers

Answer: A

Explanation: continents move very slowly, about one inch per year

Answer:

A

Explanation:

it takes thousands of years to see the continents progress in it's movement. by the time we see progress of how they are moving you'd have been dead for 50000 years XD

Help please, need awsnser ASAP!

Answers

Mars has a thin atmosphere.

The effect of gravity on a falling object can be modeled by a ball dropped
from different heights. What is a limitation of this model?
O A. Not all objects bounce, even though balls do.
B. Friction with air also affects the fall of the object.
C. Some balls float in water, while others sink.
O
D. The ball can be dropped from varying heights.

Answers

Answer:

B. Friction with air also affects the fall of the object.

Explanation:

The limitation of this experimental design is that friction with air also affects the fall of the object.

Therefore, it is difficult to measure effect of gravity on falling objects. Air resistance cause friction in the movement of an object falling. Frictional force resists the motion of an object subject to free fall.

Therefore, the experiment will be biased due to the influence of the frictional force.

What is a physical change ?
A. Burning wood
B. Rusting metal
C. Cooking a egg
D. Freezing water
Answer : Freezing water !

Answers

The answer is D but Ig you already knew that

A ball is thrown upward at 25 m/s from the ground. What is the maximum height of the ball?​

Answers

Answer:

31.25 meters in a time of 2.5 seconds.

Explanation:

Because your question gives a number that is a multiple of 5, that is just begging for us to set a = -g = -10 m/s^2. This is acceleration due to gravity. Then, we have an equation vf = v0 + at where v0 = 25 m/s. Plugging in the earlier known values and letting vf = 0 (when final velocity is zero there is maximum height), we get t = 2.5 s. Then, Delta y = vot - 1/2 gt^2. This gives 62.5 - 31.25 = 31.25 m.

Thus, our answer is 31.25 meters in a time of 2.5 seconds.

*Note: g is more precisely 9.806 m/s^2, but that would lead to more annoying sig figs in our answer so I chose to round to 10 m/s^2 which is common.

I will ask again. PLEASE HELP ME! I'M BEGGING! PLEASE HELP! Using what you have learned about energy conversions, describe the energy transfer or transformation for each of the following items:
a. Clapping your hands

b. Turning on a light

Answers

Answer:

A) Mechanical energy is converted into sound and thermal energy when the hands make contact

B) Mechanical Energy used to flip the switch sets off the lever which converts into Electrical Energy. Once the light is turned on, the Electrical Energy is converted into thermal energy, light energy, and a little bit of sound energy.

How much momentum does a stationary 5500 kg mass have?

Answers

Answer:0

Explanation:

All stationary objects have no momentum they do not have any motion to have momentum you need mass and motion

Two Forces 20N and 50N act at a point and at an angle of 120 to each. Draw a force diagram for the system​

Answers

the resultant force is F=F1-F2.

F1 = 20 N, and F2 = 50 N

In this instance, two different resultant forces are feasible.

when the two are at an angle of A with one another.

See the outcome in case 1 of the image if both are facing the same way. if they are both facing the opposite directions. when both are at a zero-degree angle from one another If they are parallel to one another and moving in the same direction, the resultant force is F=F1+F2. If they are parallel but moving in the opposite direction, the resultant force is F=F1-F2.

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A sound wave has a velocity of 350 meters/second and a frequency of 430 hertz. what is its wavelength? a. 0.01 meters b. 0.60 meters c. 0.81 meters d. 0.08 meters

Answers

The wavelength of a sound wave with a velocity of 350 meters/second and a frequency of 430 Hz is 0.81 meters.

The relation between velocity(v), frequency(f) and wavelength(lambda) of a sound wave is given by the following formula,

V = (f)(λ)                                                 equation1

We are given that , v = 350 meters/second

f = 430 hertz

By putting the above values in the equation1 , we will get

350 = 430 x (λ)

350/430 = λ

λ = 0.81 meters

Thus, the wavelength of a sound wave with a velocity of 350 meters/second and a frequency of 430 Hz is 0.81 meters.

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if the angular diameter of an object is 15 arc seconds and it is 1.4 billion kilometers away, how big is its physical size?

Answers

the actual diameter of the object is 1.017×10⁵km

actual diameter, d = any line segment that passes through the center of the circle

angular diameter, θ = the angle that an actual diameter of an object makes.

distance, D= the actual path travel

distance of the object ,D= 1.4 billion = 1.4×10⁹km

angular diameter of an object,θ = 15arc

                            θ  = 15 ×π/ (60×60×180) rad

                                                 [ ∵ 1 revolution = 2π = 360°×60×60]

   Using the relation,

     θ = d/D   {angular diameter = actual diameter/ distance}

     d =  θD

      d =  1.4×10⁹×[15×3.14/(60×60×180) ] km

         =  1.017×10⁵km

This shows the actual diameter of the object is  1.017×10⁵km

It is the physical size of object.

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An airfoil is deflected upward as the airflow is deflected downward. Which of Newton's laws does this example best illustrate?

Answers

Newton’s third law of motion states that, for every action, there is an equal and opposite reaction. Based on this law, wings are forced upwards because they are tilted, pushing air downwards so the wings get pushed upwards. This is the angle of attack or the angle at which the wing meets the airflow.

So, this will be (Newton’s third Law)
Have a good day!

If a bicycle has an average acceleration of -0.44 m/s^2, and its initial forward velocity is 8.2 m/s, how long will it take the cyclist to bring the bicycle to a complete stop

Answers

Answer:

The value is  [tex]t = 18.6 s[/tex]

Explanation:

From the question we are told that

     The average acceleration of the bicycle is [tex]v = -0.44 \ m/s^2[/tex]

      The initial forward velocity is  [tex]u = 8.2 \ m/s[/tex]

Generally from kinematic equations we have that

      [tex]v = u + at[/tex]

Here v is the final velocity of the bicycle and the value is v = 0 m/s

So

      [tex]0 = 8.2 + (-0.44)t[/tex]

=>    t = 18.6 s

Which statement correctly compares radio waves and microwaves?
A. Radio waves have shorter wavelengths and lower frequencies than microwaves.
B. Radio waves have longer wavelengths and higher frequencies than microwaves.
C. Radio waves have longer wavelengths and lower frequencies than microwaves.
D. Radio waves have shorter wavelengths and higher frequencies than microwaves.

Answers

Answer:

C. Radio waves have longer wavelengths and lower frequencies than microwaves.

Explanation:

Radio waves and microwaves are both electromagnetic waves. They do not require a medium for their propagation.

These waves are produced as result of the vibration between electric and magnetic fields perpendicular to one another.

On the electromagnetic spectrum, the waves are listed from left to rightAlong the spectrum, wavelength increases as frequency decreases. Energy also decreases to the right on the spectrum. Since microwaves comes before radio waves, they have shorter wavelength and higher frequency than micro waves.

A block sits on a frictionless sheet of ice. When it is pushed by a force of 15 N, the block will accelerate at a rate of 6.4 m/s^2. The block is then moved to the moon, where the acceleration of gravity is 1.62m/s^2. The coefficient of kinetic friction between the block and the moon's surface is 0.35. If the block is now pushed with the same force, what will be its acceleration?

Answers

Answer:

[tex]a_{moon}=5.84m/s^{2}[/tex]

Explanation:

In order to solve this problem, we will need to draw a free body diagram of both situations (see attached picture).

So first, we need to find what the mass of the object is. We can do so by analyzing the horizontal movement of the first situation, so we get:

[tex]\sum F_{x}=ma[/tex]

F=ma

[tex]m=\frac{F}{a}[/tex]

so

[tex]m=\frac{15N}{6.4m\s^{2}}[/tex]

m=2.34kg

next, we can analyze the second situation, we will start by analizing the vertical movement so we can determine the Normal force, so we get:

[tex]\sum F_{y}=0[/tex]

[tex]N-W=0[/tex]

N=W

N=mg

[tex]N=2.34kg(1.62 m/s^{2}[/tex]

N=3.79N

so now we can analyze the horizontal movement of the block, so we get:

[tex]\sum F_{x}=ma[/tex]

[tex]F-N\mu _{k}=ma[/tex]

[tex]a=\frac{F-N\mu_{k}}{m}[/tex]

[tex]a=\frac{15N-(3.79N)(0.35)}{2.34kg}[/tex]

[tex]a=5.84 m/s^{2}[/tex]

the density of aluminum is 2.70 g/cm3. express this value in units of kilogram per cubic meter and pounds per cubic foot.

Answers

The density of aluminum in units of kilogram per cubic meter is 2700kg/m³

The density of aluminum in units of pounds per cubic foot is 1.686lb/ft³

unit conversion - conversion of one unit to another unit of measurement of same quantity by using multiplication/division.

the density of aluminum is 2.70 g/cm3.(given)

1 kg = 1000g

1m = 100cm

density of aluminum in kg/m³ is :

2.7×10⁻³kg/10⁻⁶m³

2700kg/m³

density of aluminum in  lb/ft³ (ponds per cubic foot) is :

1g = 0.2204lb

1cm = 0.328ft

= 2.7×0.02204/(0.328)³

1.686lb/ft³

The density of aluminum in units of kilogram per cubic meter is 2700kg/m³

The density of aluminum in units of pounds per cubic foot is 1.686lb/ft³

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A hammer strikes a nail with a 8 N force for 0.018 seconds. Calculate the impulse of the hammer.

Answers

Answer:

0.144

Explanation:

Impulse is defined as force multiplied by time

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Ou
A truck starts from rest and accelerates uniformly over a time of 5.5 seconds for a
distance of 130 m. Determine the acceleration (in m/s^2) of the truck.
Please submit your answer with 2 decimal places!

Answers

Answer:

8.6m/s²

Explanation:

Given parameters:

Initial velocity  = 0m/s

Time  = 5.5s

Distance  = 130m

Unknown:

Acceleration  = ?

Solution:

To solve this problem, we use one of the appropriate motion equations:

       S  = Ut  + [tex]\frac{1}{2}[/tex] at²

S is the distance

U is the initial velocity

t is the time taken

a  is the unknown acceleration

t is time taken

    Since U = 0m/s

      S  =  [tex]\frac{1}{2}[/tex] at²

     130 =  [tex]\frac{1}{2}[/tex]  x a x 5.5²  

     130  = 15.13a

         a  = 8.6m/s²

What is white noise?

Answers

Answer:

white noise is a random signal having equal intensity at different frequencies, giving it a constant power spectral density

Answer:

White noise refers to sounds that mask other sounds that might occur naturally in an environment. If you live in a city, for example, white noise could help block out noises associated with traffic. Specific sounds might be used to help encourage sleep regardless of environmental noises.

which statement correctly line graph
a. the x-axis is on the left side of the graph
b. the responding variable is on the y-axis
c. the line graph has 3 axes
d. the manipulated variable is not shown

Answers

Answer:

A.

Explanation:

The X-Axis is always on the left side.

If the radius of an atom is 60 pm and the radius of the Earth is 6000 km, by how many orders of
magnitude is the radius of the Earth larger than an atom?

Answers

Answer:

1 x 10¹⁷

               

Explanation:

Given data:

        Radius of the earth  = 6000km

        Radius of an atom  = 60pm

Now, how many orders is the radius of the earth larger than an atom

Solution:

To solve this problem, let us express both quantity as the same unit;

         1000m  = 1km

    6000km  = 6000 x 10³m   =  6 x 10⁶m

    60pm;

            1 x 10⁻¹²m  = 1pm

    60pm  = 60 x  1 x 10⁻¹²m  = 6 x 10⁻¹¹m

Now;

The order:   [tex]\frac{6 x 10^{6} }{6 x 10^{-11} }[/tex]   = 1 x 10¹⁷

               

1. What coefficients would balance the following equation?
_Al + _02 →_Al2O3
2A1 + 302 +1A1,03
2A1+ 302 → 2A1203
3A1 + 302 + 2A1003
4A1 + 302 → 2A1203

Answers

Answer:

D. 4Al + 3O2 → 2Al2O3

Explanation:

Chemical reactions involves the chemical combination of two or more substances called REACTANTS to yield other substances called PRODUCTS. However, in accordance with the LAW OF CONSERVATION OF MASS, the amount of reactants must be equal to that of the products.

To accomplish this, the reaction must be BALANCED. A balanced equation is an equation in which the number of atoms of each element in the reactant side equals the number of atoms in the product side. In this reaction involving Aluminum and Oxygen to give Aluminum oxide as follows:

Al + 02 → Al2O3

A coefficient is used to balance the number of atoms on both sides of the equation as follows:

4Al + 3O2 → 2Al2O3

Answer:

here for points

3u3784y297y4ui3t7

Explanation:

An escalator is 17.4 m long. If a person stands on the escalator, it takes 47.6 s to ride from the bottom to the top. If a person walks up the moving escalator with a speed of 0.541 m/s relative to the escalator, how long does it take the person to get to the top?

Answers

Answer:

19.1 secs

Explanation:

The first step is to calculate the velocity

= 17.4/47.6

= 0.37 m/s

Therefore the time taken for the person to reach the top can be calculated as follows

= 17.4/(0.37+0.541)

= 17.4 / 0.911

= 19.1 secs

Hence the time taken is 19.1 secs

M A 40.0- cm-diameter circular loop is rotated in a uniform electric field until the position of maximum electric flux is found. The flux in this position is measured to be 5.20 × 10⁵N . m²/C. What is the magnitude of the electric field?

Answers

By electric flux, the electric field is 41.36 x 10⁵ N/C

We need to know about electric flux to solve this problem. Electric flux is the measure of the electric field through a given surface, although an electric field in itself cannot flow. It can be determined as

Φ = E . S = E . Scosθ

where Φ is electric flux, E is electric field, θ is angle of surface and S is surface area.

From the question above, we know that

Φ = 5.20 × 10⁵ N.m²/C

d = 0.4 m²

r = 0.2 m²

because of maximum flux, hence (cosθ = 1)

By substituting the following parameter, we get

Φ = E . Scosθ

5.20 × 10⁵ =E  . π.r²

5.20 × 10⁵ =E . π.0.2²

E = 41.36 x 10⁵ N/C

Hence, the electric field is 41.36 x 10⁵ N/C

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If a car has a mass of 200 kilograms and produces a force of 500 N, how fast will the car accelerate?

Answers

Answer:

2.5m/s²

Explanation:

Given parameters:

Mass of car  = 200kg

Force on car  = 500N

Unknown:

Acceleration of the car  = ?

Solution:

According to Newton's second law of motion:

      Force  = mass x acceleration

Insert the given parameters and find the acceleration;

         500  = 200 x acceleration

           acceleration = 2.5m/s²

Explanation:

F = ma

500N = 200 × a

200a. = 500N

a. =. 2.5m/s²

PLEASE GIVE BRAINLIEST.

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