Answer:
B
Explanation:
Fermium is a synthetic element with the symbol Fm and atomic number 100. It is an actinide and the heaviest element that can be formed by neutron bombardment of lighter elements, and hence the last element that can be prepared in macroscopic quantities, although pure fermium metal has not yet been prepared.[3] A total of 19 isotopes are known, with 257Fm being the longest-lived with a half-life of 100.5 days.
It was discovered in the debris of the first hydrogen bomb explosion in 1952, and named after Enrico Fermi, one of the pioneers of nuclear physics. Its chemistry is typical for the late actinides, with a preponderance of the +3 oxidation state but also an accessible +2 oxidation state. Owing to the small amounts of produced fermium and all of its isotopes having relatively short half-lives, there are currently no uses for it outside basic scientific research.
A bowling ball results in ______ friction compared to a sliding bowling ball.
A bowling ball results in kinetic friction compared to a sliding bowling ball.
What is the Conservation of momentum?According to Conservation of momentum, if a bowling ball hits some pins, the momentum that lost by the bowling ball is known to be equal to the momentum obtained by the pins.
The friction that is used in bowling is kinetic friction because the more oil that is placed down, the lower the friction that is found between the ball and that of the lane surface. The little friction, the stronger it is for the bowler to be able to send the ball in a curved path and thus the formula to find the kinetic friction is know to be : µk=F k/mg.
Therefore, A bowling ball results in kinetic friction compared to a sliding bowling ball.
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A futuristic train rushes past you at an incredible, relativistic speed such that it appears to only be 80% as long as you know it to be. At what speed is that train traveling from the point of view of your reference frame
Answer:
v = 0.6c = 1.8 x 10⁸ m/s
Explanation:
From Einstein's theory of relativity, we know that the length of an object contracts while traveling at a speed relative to speed of light. The contraction is according to following equation:
[tex]L = L_{0}\sqrt{1 - \frac{v^2}{c^2}}[/tex]
where,
L = Relative Length
L₀ = Rest Length
According to given:
L = 0.8 L₀
c = speed of light = 3 x 10⁸ m/s
v = relative speed of train = ?
Therefore,
[tex]0.8L_{0} = L_{0}\sqrt{1 - \frac{v^2}{c^2} } \\\\0.8 = \sqrt{1 - \frac{v^2}{c^2} }[/tex]
squaring on both sides:
[tex]0.64 = 1-\frac{v^2}{c^2}\\\\\frac{v^2}{c^2} = 1-0.64 \\v^2= 0.36c^2\\[/tex]
taking square root on both sides:
v = 0.6c = 1.8 x 10⁸ m/s
Discuss the relationship between size and wieght of an object and the amount
g the space in between two glass sheets has a volume of 0.025 m3. If the temperature of the gas is 290 K, what is the rms speed of the gas atoms
Complete Question
Argon gas (a monatomic gas) is sometimes used to insulate a double-pane window for purposes of insulation. In a particular window, the space in between two glass sheets has a volume of [tex]0.025 \ m^3[/tex]. If the temperature of the gas is 290 K. what is the rms speed of the gas atoms? The atomic mass of Argon is 39.9 u.(l u= 1.66x10-27 kg) Enter your answer in m/s
Answer:
The value is [tex]V_{rms} = 425.75 \ m/s[/tex]
Explanation:
From the question we are told that
The volume of the space in between the two glass sheet is [tex]a = 0.025 \ m^3[/tex]
The temperature of the gas is [tex]T = 290 \ K[/tex]
The atomic mass of Argon is [tex]m = 39.9 \ u = 39.9 * 1.66 *10^{-27} = 6.623 *10^{-26} \ kg[/tex]
Generally the root mean square velocity is mathematically represented as
[tex]V_{rms} = \sqrt{\frac{3 K T}{ m } }[/tex]
Here K is the Boltzmann constant with value [tex]k = 1.38 *10^{-23} \ m^3 \cdot kg \cdot s^{-2} \cdot K^{-1}[/tex]
So
[tex]V_{rms} = \sqrt{\frac{3 * 1.38 *10^{-23} * 290 }{ 6.6234*10^{-26} } }[/tex]
=> [tex]V_{rms} = 425.75 \ m/s[/tex]
A woman starts at the origin and walks 7m along the x-axis. She then turns 90° and walks parallel to the y-axis for 6m. How far is she from the origin? Express your answer in m to the nearest tenth.
Answer:
9.2m
Explanation:
Think of the woman's path as a triangle. She walks 7m horizontally and 6m vertically. These are the two legs of a triangle. In order to find her distance from the origin, we can use pythagorean theorem to find the hypotenuse of the triangle. The hypotenuse will give us the direct measurement from the origin (0,0) to her current point (7,6).
a²+b²=c²
(7)²+(6)²=c²
49+36=c²
85=c²
Find the square roots of both sides to get c=9.21954...
Round your answer to the nearest 10th:
c=9.2m
The woman is approximately 9.2m from the origin.
How much force is required to accelerate a 5 kg mass at 20 m/s^2
Hello!
[tex]\large\boxed{F = 100N}[/tex]
Use the equation F = m · a (Newton's Second Law) to solve. Substitute in the given values:
F = 5 · 20
F = 100N
The half-life for radioactive decay (a first-order process) is 24,000 years. How many years does it take for one mole of this radioactive material to decay so that just one atom remains?
Answer: it will take 1.9 × 10⁶ yrs for one mole of the radioactive material to decay so that just one atom remains
Explanation:
Given that;
Half life t_1/2 = 24,000 years
initial amount of radio active element = 1 mole
now one mole of a substance has Avagadro number of atoms which is initially 6.023 × 10²³ which are present and finally only 1 atom is left
using the formula
t_1/2 = 0.693/k
In[ N₀/N_t] = kt
N₀ is the initial amount, N_t is the amount left after t time, t is the time, k is the rate constant.
now we substitute
t_1/2 = 0.693/k
k = 0.693/ t_1/2
k = 0.693 / 24,000 years
k = 0.000028875 yr⁻¹
so
In[ N₀/N_t] = kt
t = 1/0.000028875 yr⁻¹ In [ 6.023 × 10²³ / 1 ]
= 34632.0346 In[6.023 × 10²³]
= 34632.0346 × 54.7550
= 1896277.0545 yrs ≈ 1.9 × 10⁶ yrs
Therefore it will take 1.9 × 10⁶ yrs for one mole of the radioactive material to decay so that just one atom remains
A stretched string is 1.95 m long and has a mass of 19.1 g. When the string oscillates at 440 Hz, which is the frequency of the standard A pitch, transverse waves with a wavelength of 16.7 cm travel along the string. Calculate the tension T in the string.
T= ________ N
Answer:
The tension in the string is 52.89 N.
Explanation:
Given;
mass of the string, m = 19.1 g = 0.0191 kg
length of the string, L = 1.95 m
⇒mass per unit length, μ = 0.0191 / 1.95 = 0.009795 kg/m
Also Given;
frequency of the string, F = 440 Hz
wavelength of the sound wave, λ = 16.7 cm = 0.167 m
⇒the speed of the wave, v = Fλ = 440 x 0.167 = 73.48 m/s
The tension T in the string is calculated as;
[tex]v = \sqrt{\frac{T}{\mu} } \\\\v^2 = \frac{T}{\mu}\\\\T = v^2 \mu\\\\T = (73.48)^2 (0.009795)\\\\T = 52.89 \ N[/tex]
Therefore, the tension in the string is 52.89 N.
Comparing infrared and ultraviolet, we can say that __________. Comparing infrared and ultraviolet, we can say that __________.
Answer:
The appropriate response will be "Infrared has a longer wavelength and lower photon energy".
Explanation:
This same Infrared emission falls between some of the observable but rather microwave components of the electric spectrum. Infrared rays have quite a wavelength longer than ultraviolet light. And indeed the frequency of radiation remains smaller, unlike UV rays. Even before we recognize that the energy (photon) of the visible region has always been equal to the total of waves. Infrared thus has smaller photon intensity versus ultraviolet.a waterwheel built in Hamah, Syria, has a radius of 20 m . If the tangential velocity at the wheels edge is 7.85 m/s , what is the centripetal acceleration of the wheel?
Answer:
3.08m/s²
Explanation:
Given parameters:
Radius = 20m
Tangential velocity = 7.85m/s
Unknown:
Centripetal acceleration = ?
Solution:
Centripetal acceleration is the acceleration of a body along a circular path.
it is mathematically given as;
a = [tex]\frac{v^{2} }{r}[/tex]
v is the tangential velocity
r is the radius
a = [tex]\frac{7.85^{2} }{20}[/tex] = 3.08m/s²
calculate the load placed 10m from the fulcrum that can be balanced by an effort of 5 N applied at a distance of 4 m from the fulcrum in a lever
Answer:
A = 2 m from fulcrum
Explanation:
Product of anti clockwise = Product of clockwise moment
5 × 4 = 10 × A
20 = 10 x A
A = 20 / 10
A = 2 m from fulcrum
Is electricity matter?
EXPLAIN.
Answer:
Yes it is matter
Explanation:
In physics, usually the word "electricity" isn't really used. "Electric current" is more common, and is defined as the flow of charges, where the charges are held by particles (electrons). Electrons have mass, so they are definitely matter.
Solenoid 2 has twice the radius and six times the number of turns per unit length as solenoid 1. The ratio of the magnetic field in the interior of 2 to that in the interior of 1 is: 1/3 1 2 4 6
Answer:
6
Explanation:
The magnetic field inside a solenoid is given by the following formula:
[tex]B = \mu_{0}nI[/tex]
where,
B = Magnetic Field Inside Solenoid
μ₀ = permittivity of free space
n = No. of turns per unit length
I = Current Passing through Solenoid
For Solenoid 1:
[tex]B_{1} = \mu_{0}n_{1}I ------------------- equation 1[/tex]
For Solenoid 2:
n₂ = 6n₁
Therefore,
[tex]B_{1} = \mu_{0}n_{2}I\\B_{1} = 6\mu_{0}n_{1}I ----------------- equation 2[/tex]
Diving equation 1 and equation 2:
[tex]\frac{B_{2}}{B_{1}} = \frac{6\mu_{0}nI}{\mu_{0}nI}\\\\\frac{B_{2}}{B_{1}} = 6[/tex]
Hence, the correct option is:
6
The ratio of the magnetic fields in interior 2 to interior 1 will be
[tex]\dfrac{B_2}{B_1} =\dfrac{6}{1}[/tex]
What will be the ratio of the magnetic fields?The formula for the magnetic fields inside the solenoid will be given:
[tex]B=\mu_onI[/tex]
here,
B = Magnetic Field Inside Solenoid
μ₀ = permittivity of free space
n = No. of turns per unit length
I = Current Passing through Solenoid
For the first Solenoid
[tex]B_1=\mu_on_1I[/tex]..................(1)
For the second solenoid
[tex]n_2=6n_1[/tex]
Now
[tex]B_2=\mu_on_2I[/tex]
[tex]B_2=\mu_o(6n_1)I[/tex]..................(2)
Diving equation 1 and equation 2:
[tex]\dfrac{B_2}{B_1} =\dfrac{\mu_o(6n_1)I}{\mu_on_2I}[/tex]
[tex]\dfrac{B_2}{B_1} =6[/tex]
Thus the ratio of the magnetic fields in interior 2 to interior 1 will be
[tex]\dfrac{B_2}{B_1} =\dfrac{6}{1}[/tex]
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A force of 16 N is applied to a 5 kg block that is at rest on a smooth, horizontal surface. What is the velocity of the
block at time t = 5 seconds?
Answer:
16m/s
Explanation:
Given the following data;
Force, F = 16N
Mass, m = 5kg
Time, t = 5 seconds.
First of all, we would find the acceleration of the object.
Force is given by the multiplication of mass and acceleration.
Mathematically, Force is given by the formula;
[tex] F = ma[/tex]
Where;
F represents force.m represents the mass of an object.a represents acceleration.Making acceleration (a) the subject, we have;
[tex]Acceleration, a = \frac{F}{m}[/tex]
Substituting into the equation;
[tex]Acceleration, a = \frac{16}{5}[/tex]
Acceleration, a = 3.2 m/s²
Now, to find velocity;
We would use the first equation of motion given by the formula;
[tex] V = U + at[/tex]
Where;
V is the final velocity. U is the initial velocity. a is the acceleration. t is the time measured in seconds.We know that acceleration due to gravity is 9.8m/s² and initial velocity (U) is 0 since the object is at rest.
Substituting into the equation, we have;
[tex] V = 0 + 3.2*5[/tex]
[tex] V = 0 + 16[/tex]
Velocity, V = 16m/s.
An object undergoing simple harmonic motion completes one cycle of motion in 1.7 seconds. Determine the angular frequency (rad/s) of the motion.
Answer:
3.69 rad/s
Explanation:
From the question given above, the following data were obtained:
Period (T) = 1.7 s
Angular frequency (ω) =?
Thus, we can obtain the angular frequency (ω) by applying the following formula:
ω = 2π/T
Period (T) = 1.7 s
Pi (π) = 3.14
Angular frequency (ω) =?
ω = 2π/T
ω = 2 × 3.14 / 1.7
ω = 6.28 / 1.7
ω = 3.69 rad/s
Thus, the angular frequency of the motion is 3.69 rad/s
A car is traveling at a constant speed of 14. It tires have a diameter of 0.91
30.76/s is the angular speed of the car traveling at a constant speed of 14m/s and having a tire of diameter of 0.91m
The rate of change of angular displacement is known as Angular velocity . The unit of angular velocity is radians/second. The same formula describes both angular velocity and angular velocity. Angular velocity is a vector quantity that expresses both direction and magnitude, but angular velocity expresses only magnitude. Angular velocity (ω) is a scalar measure of rotational speed. The angular distance traveled in one full rotation is 2π and the time is duration (T).
here from the given data that is a constant speed of 14. It tires have a diameter of 0.91
ω=θ/t
V=2πr/t
=14m/s
ω=v/r
=14/0.45
=30.76
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the question you provided was incomplete and I have added the incomplete part that is to find the angular speed of the given data.
Which statement is NOT part of the Cell theory? All cells come from other cells. All cells come from other cells., All organisms are composed of cells. All organisms are composed of cells., Cells are the basic living units of organization in all organisms. Cells are the basic living units of organization in all organisms., EndFragment, All the cells in an organism have exactly the same function
Answer:
All the cells in an organism have exactly the same function
a car is initially at rest. ten seconds later it is moving 30 m/s. what is the car's acceleration
Answer:
The car's acceleration is [tex]3\ m/s^2[/tex]
Explanation:
Constant Acceleration Motion
It's a type of motion in which the velocity of an object changes uniformly over time.
The final speed is given by:
[tex]v_f=v_o+at[/tex]
Where a the constant acceleration, vo the initial speed, vf the final speed, and t the time, the following relation applies:
Using the equation above we can solve for a:
[tex]\displaystyle a=\frac{v_f-v_o}{t}[/tex]
The car is initially at rest (vo=0) and t=10 seconds later it's moving at vf=30 m/s, thus its acceleration is:
[tex]\displaystyle a=\frac{30-0}{10}[/tex]
[tex]\displaystyle a=\frac{30}{10}=3[/tex]
[tex]a = 3\ m/s^2[/tex]
The car's acceleration is [tex]3\ m/s^2[/tex]
Plz help
Fill in the blank with the correct observation from the simulation.
As the days go on, the distance that the moon is from the sun in the night sky
A. Stays the same
B. Decreases
C. Increases
Starting at New Moon, The visual distance increases for about 2 weeks, then decreases for about the next 2weeks, until the next New Moon.
On the average, it changes by about 12° per day.
A penny is dropped from the top of the
Chrysler Building (320 m high). How fast
is it moving when it hits the ground?
Answer:
-79
Explanation:
because I know because that's what the answer is because it is -79 when it hits the ground
Does Light Transmission in oxygen ?
Some students are jumping rope which travels at a speed of 2 m/s. The distance from the top of the swing to the bottom is 2 m. What is the frequency l of the rope
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1. An electrical current is flowing through a circuit at a rate of 25 m/s and then decelerates
when it passes through the resistor and reaches a velocity of 13 m/s within 5 seconds.
What is the electrical current's acceleration?
The acceleration of the electrical current is -2.4 m/s².
What is acceleration?Acceleration can be defined as the rate of change of velocity.
To calculate the acceleration of the electric current, we use the formula below.
Formula:
a = (v-u)/t........... Equation 1Where:
a = Acceleration of the currentv = Fianl velocityu = Initial velocityt = TimeFrom the question,
Given:
v = 13 m/su = 25 m/st = 5 secondsSubstitute these values into equation 1
a = (13-25)/5a = -12/5a = -2.4 m/s²Hence, the acceleration of the electrical current is -2.4 m/s².
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As fuel is burned in an electrical generator, the chemical energy of the fuel is converted into thermal energy that is used to boil water. after the steam from the boiling water moves through the pipe, what sequence of energy transformation best describes what happens?
Answer choices:
A:mechanical ----> electrical ---> light
B: light ----> electrical----> mechanical
C: Electrical---> Mechanical----> light
D: Mechanical----> light ----> electrical
Answer: A
Explanation:
The density formula is d =
m
V
.
A cylinder of lead has a
diameter of 3 cm and a height of 8 cm. The density of lead is
3
11.4 g/cm³. What is the mass of the cylinder?
The mass of the cylinder made of lead is 644.33 kg.
What is mass?Mass can be defiend as the quantity of matter a contained in a body. The S.I unit of mass is kilogram (kg).
To calculate the mass of the cylindrical lead, we use the formula below.
Formula:
m = πr²hd........... Equation 1Where:
m = Mass of the cylindrical leadh = Height of the cylindrical leadd = Density of the leadr = Radius of the cylindrical leadπ = PieFrom the question,
Given:
r = 3/2 = 1.5 cmd = 11.4 g/cm³h = 8 cm π = 3.14Substitute the values above into equation 1
m = 11.4×3.14×1.5²×8m = 644.33 kgHence, the mass of the cylinder made of lead is 644.33 kg.
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A small plane starts from rest and accelerates uniformly to the east to a takeoff velocity of 70 m/s in 5 seconds. What is the plane’s acceleration?
Please help!
The acceleration of the plane after 5 seconds will be 14 m/s².
What is acceleration?The rate of change of velocity with respect to time is called acceleration. Mathematically -
a = Δv/Δt
Given is a small plane that starts from rest and accelerates uniformly to the east to a takeoff velocity of 70 m/s in 5 seconds.
The acceleration of the body can be calculated as follows -
a = Δv/Δt
a = (70 - 0)/(5 - 0)
a = 70/5
a = 14 m/s²
Therefore, the acceleration of the plane after 5 seconds will be 14 m/s².
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en the current in one coil changes at a rate of 3.2 A/s, an emf of 5.7 is induced in a second, nearby coil. What is the magnitude of the mutual inductance of the two coils
Given that,
The rate of change of current = 3.2 A/s
Emf induced in the coil = 5.7 V
To find,
The magnitude of the mutual inductance of the two coils.
Solution,
The mutual inductance between the coils is given by the formula as follows :
[tex]\epsilon=M\dfrac{dI}{dt}\\\\M=\dfrac{\epsilon}{\dfrac{dI}{dt}}\\\\M=\dfrac{5.7}{3.2}\\\\=1.78\ H[/tex]
So, the mutual inductance of the two coils is 1.78 H.
when a horse pulls a cart, the horse move forward due to?
Answer:
The horse moves due to kinetic energy and is walking balanced because of the gravitational energy
Explanation:
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a half meter ruler is pivoted at its midpoint and balances whaen a weight of 20N is placed at the 10 cm mark and a weight W is placed at the 45 cm mark on the ruleer. Calculate the weight W
The weight W palced at a distance of 45 cm on a half meter ruler pivote at its midpoint is 15 N.
To calculate the weight W, we use the principle of moment.
Principle of moment?It states that, if a body is at equilibrium, the sum of clockwise moment is equal to the sum of anticlockwise moment.
From the question,
Clockwise moment (F×d ) = Anticlockwise moment (W×D).......... Equation1
Make W the subject of the equation
W = Fd/D............. Equation 2Given:
F = 20 Nd = (25-10) = 15 cm = 0.15 mD = (45-25) = 20 cm = 0.2 mSubstitute these values into equation 2
W = 20×0.15/0.2W = 15 NHence, the weight W is 15 N
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Which statements describe processes involved in the accretion of planetesimals and protoplanets
The statements that describe the processes involved in the accretion of planetesimals and protoplanets are :
II. Both processes involve nebular materials becoming solid particles.
IV. In both cases, masses of stuff are clumped together and gases are trapped.
Accretion basically involves the accumulation of particles into a massive object by gravitationally attracting more matter, mainly the gaseous matter, in an accretion disk.
A protoplanet is basically a large planetary embryo that has originated within a protoplanetary disc and which also has undergone internal melting to produce a differentiated interior.
Planetesimals are known to be small rock-type objects which are
formed by collisions with other objects present in the solar system.
Hence, the statements that describe the processes involved in the accretion of planetesimals and protoplanets are :
Both processes involve nebular materials becoming solid particles.In both cases, masses of stuff are clumped together and gases are trapped.Learn more about Planetesimals and Protoplanets here:
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The complete question is mentioned below:
Which statements describe processes involved in the accretion of planetesimals and protoplanets?
( I ) Both involve the melting of solid materials in the nebula.
( II ) Both involve the formation of solid particles from nebular materials.
( III ) Both involve the work of the gravitational push on nebular materials.
( IV ) Both involve the trapping of gases and the clumping of masses of matter.
( V ) Both involve the growing of gas grains with the addition of atoms and molecules.