If two people lift identical stacks of books the same distance and one person does the job twice as fast, which of the following has doubled?


-power

-work output

-work input

-efficiency








​

Answer: 0.064 m/s²

Explanation:

Initial velocity = 22m/s

Final velocity = 44m/s

Time taken = 345 seconds

Acceleration = (Final velocity - Initial velocity) / Time taken

= (44 - 22) / 345

= 22/345

= 0.0637681

= 0.064 m/s²

Therefore, the acceleration is 0.064 m/s².

The object fall just during the 2nd second is 14.7m.

As we know the equation of motion

equation off motion are equation that describe the behavior of physical system in terms of its motion as a function of time.

using 2nd equation of motion

S = ut +gt²/2

S= distance covered

u = initial velocity

g = acceleration due to gravity

t = time taken (t= 1 sec)

a = g = 9.8 m/s²

u = 0 m/s

At time t=1 sec

S₁ = 0 + 9.8 (1)²/2  = 4.9m

S₁  = 4.9m

S1 is the distance covered in ist second.

At t = time (t= 2 sec)

S₂ = 0 + 9.8 (2)²/2  = 19.6m

S₂ = 19.6m

S2 is the distance covered after 2nd second.

The object fall just during the 2nd second is

S = S₂ - S₁

S = 19.6 - 4.9  = 14.7m

The object fall just during the 2nd second is 14.7m.

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Answer:

the last option is correct

Explanation:

Newton's third law of motion , the ground will exact the equal opposite force the rubber ball

Answer:

0.729

Explanation: by using ohms laws

The distance between Dina and Owen with respect to Ed is 1.44 × 10¹² m.

A frame of reference is a set of reference points—geometric points whose positions are known mathematically and physically—that define the origin, orientation, and scale of an abstract coordinate system.

If a body does not continuously adjust its position in relation to its environment throughout the course of time, it is said to be at rest.

In the frame S', Dina and Owen are at rest.

The speed of the ball with respect to Owen, u =0.800c

The speed of the frame S' with respect to frame S,  v = 0.600c

Distance between Dina and Owen, L(p) = 1.8 × 10¹² m

Speed of light, c = 3 × 10⁸ m/s

Therefore, the distance between Dina and Owen with respect to Ed is:

L = L(p) √[1-(v²/c²)]

L = (1.8 × 10¹² m)√[1-(0.6c)²/c²)]

L = (1.8 × 10¹² m)(0.8)

L = 1.44 × 10¹² m

The distance is 1.44 × 10¹² m.

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Answer:

Explanation:

Kinetic force is the force caused kinetic energy. Kinetic energy is energy this is in movement such as a moving car or a falling rock.

Answer:

Explanation:

The solution along with the diagram can be found in the attachment. Feel free to raise doubts.

Centripetal force is defined as the force that allows the object to follow a curvature path.

The velocity will be 19.80 m/s.

Given:

Normal Force = 1.2 x weight

Normal Force = 1.2 Mg

Mass = Mass of car + occupants

Centripetal Acceleration = [tex]\text a_c[/tex]

Now, applying the equilibrium equation:

[tex]\begin{aligned} \sum \text F&= \text m \times \text a_c\\\\\text F_n - \text{mg} &= m \times \text a_c\\\\1.2 \text{Mg} - \text{Mg} &= m \times \text a_c\\\\\text a_c &=0.2 \;\text g\\\end[/tex]

Now, substituting the value in the formula:

[tex]\begin {aligned} \text a_c &=\dfrac{\text v^2}{\text r}\\\\0.2 \text g &= \dfrac {\text v ^2}{\text r}\\\\\text v &= \sqrt{0.2 \times 9.8 \times 200}\\\\\text v &= 19.80 \;\text {m/s}\end[/tex]

Thus, the velocity will be 19.80 m/s.

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Answer:

Speed is 0 m/s.

Distance is 200 meters.

Explanation:

In this scenario, we can treat speed as the absolute value of velocity and distance as absolute value of displacement since we are dealing with one-dimensional motion.

There’ll only exist one component of vector, by applying magnitude formula, it’ll return value as shown below:

Suppose we have a one-dimensional vector, [tex]\displaystyle{\vec v = 5\hat i}[/tex], this represents a vector with magnitude of [tex]\displaystyle{|\vec v | = \sqrt{5^2} = 5}[/tex].

Theorem I - Magnitude of One-Dimensional Vector

Suppose we have a vector [tex]\displaystyle{\vec v = a\hat i}[/tex] then the magnitude is [tex]\displaystyle{|\vec v| = \sqrt {a^2} = |a|}[/tex].

Speed and distance both are scalar quantity which means they only have magnitude but lack the direction. In one-dimensional motion, speed is defined to be the absolute value of velocity and direction is defined to be the absolute value of displacement, the reason is shown above regarding one-dimensional vector.

An example would be, consider a car moves at velocity of -4 m/s, this means that a car just moves to negative direction or opposite direction of positive at 4 m/s. The negative and positive sign refer to the direction that an object moves, to know how fast they are moving, we consider its magnitude which is speed.

This can also be said same to displacement and distance, but be aware that this can only be applied to straight horizontal or vertical line movement or else the motion will become two-dimensional.

From the problem, there’s no specific distance or displacement’s graph so we will assume that the car is moving in straight horizontal line. The car is moving at speed of 40 m/s and decelerates at 4 m/s².

This means that our acceleration is -4 m/s² since it’s decelerating and is moving at 40 m/s from start. Therefore, we can apply a general physic formula which is:

[tex]\displaystyle{v = u+at}[/tex]

Where v is final velocity, u is initial velocity, a is acceleration and t is time. As said, we can treat speed = positive velocity in this scenario so substitute u = 40 m/s and a = -4 m/s² in the formula.

[tex]\displaystyle{v=40-4t}[/tex]

Now substitute t = 10 in the formula:

[tex]\displaystyle{v = 40-4(10)}\\\\\displaystyle{v=40-40}\\\\\displaystyle{v=0 \ \sf{m/s}}[/tex]

Therefore, the speed of car at 10 seconds is 0 m/s, it’s not moving at this moment.

Next, we find distance which we can use the following formula:

[tex]\displaystyle{s = ut + \dfrac{1}{2}at^2}[/tex]

Substitute u = 40, t = 10 and a = -4 in:

[tex]\displaystyle{s=40(10)+\dfrac{1}{2}(-4)(10)^2}\\\\\displaystyle{s = 400-2(100)}\\\\\displaystyle{s=400-200}\\\\\displaystyle{s=200 \ \sf{m}}[/tex]

Therefore, in 10 seconds, it’ll be able to travel 200 meters.

Answer: What is the force acting down the plane?

• Opp= hyp (sinq)= 450(sin30)= 225 N

• What is the force acting perpendicular to the plane?

• adj= hyp (cosq)= 450(cos30)= 390 N

Explanation:

Answer:

representative and liberal democracy

Explanation:

a representative democracy is an indirect democracy where sovereignty is held by the people's representatives. a liberal democracy is a representative democracy with protection for individual liberty and property by rule of law

Explanation:

The weight is 40 * 6.2 = 248N.

Answer:

248 N

Explanation:

Weight= Gravity*mass

W= 6.2*40

W= 248N

Thank you

Answer:

N

Explanation:

Plato

Answer:

Explanation:

The force required can be found by using the formula

[tex]f = \frac{w}{d} \\ [/tex]

w is the workdone

d is the distance

From the question we have

[tex]f = \frac{25}{0.5} \\ [/tex]

We have the final answer as

Hope this helps you

Answer:

[10 section] is gonna be your answer.

The speed of the car when you hit the police car is 26.154 m/s.

The speed of the car's v = 110km/h = 30.56 m/s

The total time travel will also include the reaction time:

t = 2 + 0.4 = 2.4 s

For police,

The acceleration, a = - 5 m/s²

The distance traveled is:

[tex]S(p) = vt + (\frac{1}{2} ) \times at^{2}[/tex]

[tex]S(p) = 30.56 \times 2.4 + \frac{1}{2} \times (-5) \times (-2.4)^{2}[/tex]

S(p) = 58.93 m

Now, the original gap between the car was 25 m.

Therefore, the final gap = (25 − 73.33 + 58.93) m = 10.6 m

As a result, let's say that at time t₀, the distance between the cars is 10.6 meters.

The speed of the police car at t₀ will be:

v(p) = (30.56 − 5 × 2.4) = 18.56m/s.

Now, the collision occurs at a time t when S = S(p)

We pick your position's coordinates to be S = 0 and the police car's position to be S(p) = 10.6m at time t₀ .

Therefore,

[tex]S(p) - 10.6 = 18.56(t - t_{0}) - \frac{1}{2} \times (5) \times (t - t_{0})^{2}[/tex]

S(p) = 10.6 + 18.56t − 2.5t²

​And,

[tex]S = 30.56 (t - t_{0}) - \frac{1}{2} \times (5) \times (t - t_{0})^{2}[/tex]

When the distances are equal.

S = S(p)

30.56 (t - t₀) - (1/2)(5)(t - t₀)² = 10.6 + 18.56t − 2.5t²

t =  0.883 sec

So, the speed of your car during the collision will be:

v = 30.56 - 5(0.883) = 26.154 m/s

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The complete is mentioned below:

You are arguing over a cell phone while trailing an unmarked police car by 25m; both your car and the police car are traveling at 110km/h. Your argument diverts your attention from the police car for 2.0s (long enough for you to look at the phone and yell, “I won’t do that!”). At the beginning of that 2.0s, the police officer begins braking suddenly at 5.0m/s². What is the separation between the two cars when your attention finally returns? Suppose that you take another 0.40s to realize your danger and begin braking. If you too brake at 5.0m/s², what is your speed when you hit the police car?

The degree of disorder in the universe tends to increase due to entropy.

ie. the second law of thermodynamic

First law of thermodynamics is the conservation of energy. Energy can change from one form to another form it neither created nor destroyed.

dQ = dU + dW

where

dQ is the heat transferred.

dW is the work done

dU is change in internal energy.

2nd law states entropy of an isolated system always increases.

S > 0

where s is the change in entropy in the universe.

the degree of disorder in the universe tends to increase due to entropy.

ie. the second law of thermodynamic.

The given question is incomplete

the first law of thermodynamics states that the degree of disorder in the universe tends to increase

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Answer:

"the maximum extent of a vibration or oscillation, measured from the position of equilibrium."

hope this helps

Answer:

amplitude and physics the maximum displacement or distance moved by point on a vibrating body or wave measured from its equilibrium position it is equal to 1/2 of the length of the vibration path

Hi there!

[tex]\large\boxed{ -6.36m/s}[/tex]

Use the equation:

[tex]v_{2} = -\frac{m_{1}}{m_{2}} v_{1}[/tex]

Where m2 and v2 deal with the larger object, and m1 and v1 with the smaller object. Plug in the given values:

v2 = ?

m1 = 0.048 kg (converted)

m2 = 2.95

v1 = 391

[tex]v_{2} = -\frac{0.048}{2.95} *391[/tex]

[tex]v_{2} = -6.36m/s[/tex]

The final velocity of the rock before hitting the ground is 34.42m/s

Velocity of an object can be said as, the rate of change of displacement with respect to time of an object . Its unit is m/s and it is a vector quantity.

V = Δx/Δt

In here , V is velocity ,  Δx is change in displacement and Δt is change in time of an object.

We are given that,

The rock thrown downward with initial velocity = (-u) = -20m/s

The height of the building before and after hitting the ground = -Δy = -40 m

Therefore , to get the value of the final velocity (v) of the rock before hitting the ground , then the equation of motion cab be written as,

v² = u² + 2a(Δy )

Here , (a) is the acceleration due to gravity and taken negative (-9.81m/s²) due downward direction of the building then putting all the values in above equation of motion ,

v² = (-20m/s)² + 2(-9.81m/s²) (-40m)

v² = 1184.42m/s

v = 34.42m/s

Hence, the final velocity of the rock before hitting the ground would be 34.42m/s .

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Answer: -3x+13

Explanation:

The slope of the line that passes through the point (3,4) is 1/3. Then , the intercept of the perpendicular line is 3 . Then, the equation of the line is y = 1/3x + 3.

Coordinates are numbers which describes the position of a shape, curve or line. The coordinates are written in terms of x and y axis values. A line or curve passing through certain points can be represented by an equation.

For a straight line the equation is y = mx + c

where m is the slope of the line and c be the intercept on y- axis.

For two perpendicular lines, the slope will be opposite inverse of each other.

The slope of the line y = -3x + 1 is -3. Then, the slope of the line which is perpendicular to this line is - (1/-3) = 1/3.

Then the equation of the line is y = 1/3 x + c.

given the line passes through the point (3,4).

Then,

4 = 1/3×3 + c

c = 3.

Therefore, the equation of the second line is y = 1/3 x + 3.

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Answer:

f=ma

f=280N

m=40kg

a=?

280=40a

a=280/40

a=70N/kg

Answer:it’s a

Explanation:

Static electricity refers to the buildup or imbalance of electric charges on the surface of objects. The correct answer is B. An insulator prevents electric charge from moving through it.

An insulator prevents electric charge from moving through it. This statement describes an example of static electricity because insulators, such as rubber or plastic, do not allow electric charges to flow freely. When an insulator is rubbed or comes into contact with another object, it can cause the transfer of electrons between the two surfaces, leading to a buildup of static charge.

The charges remain stationary on the surfaces of the objects, resulting in an electrical imbalance without the flow of charges through the insulator.

Therefore, the correct answer is B. An insulator prevents electric charge from moving through it.

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Answer:

C. 1.3 x 10-11 F

I took the test and got this correct, hope this helps

Explanation:

Answer: Regarding the image posted, a unicellular paramecium relies on mitosis for reproduction.

I hope this helps!

Based on the graph, the correct option is that Marty is right because the change in concentration increases with time; option C.

Decomposition reactions are reactions in which a large molecule splits or breaks down into two or more smaller molecules.

The general equation of a decomposition reaction is given below;

The decomposition of hydrogen peroxide to give water and oxygen occurs when it is exposed to air.

The given graph of the decomposition of hydrogen peroxide shows that the concentration of hydrogen peroxide decreases with time.

In conclusion, the decomposition of hydrogen peroxide in the presence of air gives oxygen and water.

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Answer:

Look at the image please

Explanation:

The electric field strength of the electron is 212143.75 N/C

To calculate the electric field strength,we use the formula below,

Formula

•E=ma/q............. equation 1

where,

E=electric field strength of the electron

m=mass of the electron

q=charge of an electron

first we need to calculate the acceleration of electron

•

[tex]v {}^{2} = u {}^{2} + 2as..........equation \: 2[/tex]

from the question,

given:

[tex]v = 3.9 \times 10 {}^{7} \frac{m}{s} [/tex]

[tex]u = 2.5 \times 10 {}^{7} \frac{m}{s} [/tex]

[tex]s = 1.6 cm = 1.2 \times 10 {}^{ - 2} [/tex]

substitute the values into equation 2

[tex](3.9 \times 10 {}^{7} ) {}^{2} = (2.5 \times 10 {}^{7} ) {}^{2} + 2(1.2 \times 10 {}^{ - 2} )a[/tex]

solve for a

[tex]1.521 \times 10 {}^{15} = 6.25 \times 10 {}^{14} + 0.024a[/tex]

[tex]a = 1.521 \times 10 {}^{15} - 6.25 \times 10 {}^{14} \div 0.024[/tex]

[tex]a = 8.96 \times 10 {}^{14} \div 0.024[/tex]

[tex]a = 3.73 \times 10 {}^{16} \frac{m}{s {}^{2} } [/tex]

Also given the following constant

[tex]m = 9.1 \times 10 {}^{ - 31} kg[/tex]

[tex]q = 1.6 \times 10 {}^{ - 19} c[/tex]

substitute these values in equation 1

[tex]e = \frac{(9.1 \times 10 {}^{ - 31})(3.73 \times 10 {}^{16} )}{1.6 \times 10 {}^{? - 19} } [/tex]

[tex] = 212143n \div c[/tex]

Hence,the electric field strength of the electron is 212143n/c

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Answer: Absorption is the transformation of radiant power to another type of energy, usually heat, by interaction with matter. The transmittance t of a medium is defined by the ratio of transmitted radiant power to incident radiant power.

Explanation:

Absorption, in wave motion, the transfer of the energy of a wave to matter as the wave passes through it. ... If there is only a small fractional absorption of energy, the medium is said to be transparent to that particular radiation, but, if all the energy is lost, the medium is said to be opaque.

Answer:

a. 1/1000 sec

Explanation:

Shutter speed is the length of time that the film you’re photographing is being exposed to the scene in film photography. However, in digital photography, shutter speed is the length of time that the image sensor sees the scene the photographer is trying to capture.

For shutter speeds, the greater the denominator the higher the speed and the lower the denominator, the lower the speed.

Thus, the fastest one is option A.

The fastest shutter speed is represented as : ( D )  1/2000 sec

To determine the fastest shutter speed we have to the consider the numerator and denominator values of the given expression representing the relationship between the shutter speed and length of time. The greater the denominator the faster the shutter speed.

Therefore from the options listed the fastest shutter speed would be 1/2000 sec

Hence we can conclude that the fastest shutter speed is represented as 1/2000 sec.

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