if the sum of three consecutive integer is 75 ..then what is the greatest possible value of smallest one

Answers

Answer 1

Answer:

If sum were 75 the integers would be 24, 25 and 26, so the next lowest/smallest sum would be 23 + 24 + 25 is 72. The answer is 23.

Answer 2

Answer:

smallest value=24

Step-by-step explanation:

steps are in picture.

Note:If you have any confusion you can ask me.

If The Sum Of Three Consecutive Integer Is 75 ..then What Is The Greatest Possible Value Of Smallest

Related Questions

Anyone’s knows how do this and the answer?

Answers

Answer:

12 -16. 19

4. 8. 22

3. -9. -4

Step-by-step explanation:

13-1 = 12

-10-6= -16

12 - -7 = 12+7=19

6-2 = 4

Keep subtracting

State the transformations of the following function in order: = − 3|6 − 2| + 1

Answers

Answer:

6

Step-by-step explanation:

-3 | 6 - 2| + 1

-3 + 6 + 2 + 1

-3 + 9 = 6

Solve using substitution.


6x + y = 7

8x + 9y = 17

(_,_)


Please help me I really need it

Answers

You take the first equation and make a value for y. So 6x + y =7 change it to :
y = -6x + 7
Now in the second equation replace the “y” with -6x +7 this is what it means to use substitution method . Your combined equation will now be :
8x + 9(-6x + 7) =17
Now do distributive property and you get :
8x + -54x +63 =17
Now combine like terms ;
-46x +63 =17
-46x =-46
x = 1
Now replace 1 for X value and we can get the value of Y .
Y=1
X=1

Need answers in 2 minutes ASAP

Answers

Step-by-step explanation:

f(10)=10

f(-2)=-2

f(a)=a

f(a+b)=a+b

g(10)=5×10-12=3

g(-2)=5×(-2)-12=-10-12=-22

g(a)=5×a-12=5a-12

g(a+b)=5×(a+b)-12=5a+5b-12

h(10)=(10)^2 +4(10)-7=100+40-7=133

h(-2)=(-2)^2 +4(-2)-7=4-8-7=-11

h(a)=a^2 +4a -7

h(a+b)=(a+b)^2 +4a+4b-7=a^2+2ab+b^2+4b-7

[tex]\lim_{n \to \0}(x/(tan⁡(x))^(cot⁡(x)^2 )[/tex]

Answers

It looks like the limit you want to compute is

[tex]\displaystyle L = \lim_{x\to0}\left(\frac x{\tan(x)}\right)^{\cot^2(x)}[/tex]

Rewrite the limand with an exponential and logarithm:

[tex]\left(\dfrac{x}{\tan(x)}\right)^{\cot^2(x)} = \exp\left(\cot^2(x) \ln\left(\dfrac{x}{\tan(x)}\right)\right) = \exp\left(\dfrac{\ln\left(\dfrac{x}{\tan(x)}\right)}{\tan^2(x)}\right)[/tex]

Now, since the exponential function is continuous at 0, we can write

[tex]\displaystyle L = \lim_{x\to0} \exp\left(\dfrac{\ln\left(\dfrac{x}{\tan(x)}\right)}{\tan^2(x)}\right) = \exp\left(\lim_{x\to0}\dfrac{\ln\left(\dfrac{x}{\tan(x)}\right)}{\tan^2(x)}\right)[/tex]

Let M denote the remaining limit.

We have [tex]\dfrac x{\tan(x)}\to1[/tex] as [tex]x\to0[/tex], so [tex]\ln\left(\dfrac x{\tan(x)}\right)\to0[/tex] and [tex]\tan^2(x)\to0[/tex]. Apply L'Hopital's rule:

[tex]\displaystyle M = \lim_{x\to0}\dfrac{\ln\left(\dfrac{x}{\tan(x)}\right)}{\tan^2(x)} \\\\ M = \lim_{x\to0}\dfrac{\dfrac{\tan(x)-x\sec^2(x)}{\tan^2(x)}\times\dfrac{\tan(x)}{x}}{2\tan(x)\sec^2(x)}[/tex]

Simplify and rewrite this in terms of sin and cos :

[tex]\displaystyle M = \lim_{x\to0} \dfrac{\dfrac{\tan(x)-x\sec^2(x)}{\tan^2(x)}\times\dfrac{\tan(x)}{x}}{2\tan(x)\sec^2(x)} \\\\ M= \lim_{x\to0}\dfrac{\sin(x)\cos^3(x) - x\cos^2(x)}{2x\sin^2(x)}[/tex]

As [tex]x\to0[/tex], we get another 0/0 indeterminate form. Apply L'Hopital's rule again:

[tex]\displaystyle M = \lim_{x\to0} \frac{\sin(x)\cos^3(x) - x\cos^2(x)}{2x\sin^2(x)} \\\\ M = \lim_{x\to0} \frac{\cos^4(x) - 3\sin^2(x)\cos^2(x) - \cos^2(x) + 2x\cos(x)\sin(x)}{2\sin^2(x)+4x\sin(x)\cos(x)}[/tex]

Recall the double angle identity for sin:

sin(2x) = 2 sin(x) cos(x)

Also, in the numerator we have

cos⁴(x) - cos²(x) = cos²(x) (cos²(x) - 1) = - cos²(x) sin²(x) = -1/4 sin²(2x)

So we can simplify M as

[tex]\displaystyle M = \lim_{x\to0} \frac{x\sin(2x) - \sin^2(2x)}{2\sin^2(x)+2x\sin(2x)}[/tex]

This again yields 0/0. Apply L'Hopital's rule again:

[tex]\displaystyle M = \lim_{x\to0} \frac{\sin(2x)+2x\cos(2x)-4\sin(2x)\cos(2x)}{2\sin(2x)+4x\cos(2x)+4\sin(x)\cos(x)} \\\\ M = \lim_{x\to0} \frac{\sin(2x) + 2x\cos(2x) - 2\sin(4x)}{4\sin(2x)+4x\cos(2x)}[/tex]

Once again, this gives 0/0. Apply L'Hopital's rule one last time:

[tex]\displaystyle M = \lim_{x\to0}\frac{2\cos(2x)+2\cos(2x)-4x\sin(2x)-8\cos(4x)}{8\cos(2x)+4\cos(2x)-8x\sin(2x)} \\\\ M = \lim_{x\to0} \frac{4\cos(2x)-4x\sin(2x)-8\cos(4x)}{12\cos(2x)-8x\sin(2x)}[/tex]

Now as [tex]x\to0[/tex], the terms containing x and sin(nx) all go to 0, and we're left with

[tex]M = \dfrac{4-8}{12} = -\dfrac13[/tex]

Then the original limit is

[tex]L = \exp(M) = e^{-1/3} = \boxed{\dfrac1{\sqrt[3]{e}}}[/tex]

The length of a rectangle is 22 meters. This is 8 more than twice of the width. Find the width of the rectangle

Answers

Answer:

w = 7

Step-by-step explanation:

L = 22

L =  2*w + 8

Since the Ls are the same thing, you can equate them

2w + 8 = 22                 Subtract 8 from both sides

2w = 22 - 8                  Combine

2w = 14                         divide by 2

w = 14/2

w = 7

GIVING BRAINLIEST PLS HELP

Answers

Hope it helpsssss !!!!! Don’t mind about “so x=8 and smt” dad

if image of a point (4,6) under enlargement with centre (0,0) and scale factor 'k' is (2,3) find value of k ​

Answers

Answer:

k = 2

Step-by-step explanation:

2 x 2 = 4

3 x 2 = 6

so (2,3) multiplied by 2 will be (4,6)

Select the correct answer.
Based on these segment lengths, which group of segments cannot form a triangle?
OA 12,7,8
OB. 8, 7, 13
OC. 1,2,3
OD. 80,140, 70
Reset
Next
2021 EdimentumAll rights

Answers

Answer:

C

Step-by-step explanation:

If you add up the length of two sides, the sum must be greater than the third side of the triangle.

If you add 1 and 2, it equals 3

But that means it will be equal to the length of the third side, 3

It will be impossible to make a triangle with those lengths of sides no matter how the sides or angles are set.

It's sort of difficult to explain this without any visual

You can look up "triangle inequality" to find out more about this

On solving equation 3*1/5b+5=50, the value of b will be?

Answers

Answer:

Step-by-step explanation:

14 1⁄16

27 devided by 1234 chunking method

Answers

Answer:

45

Step-by-step explanation:

Which statement describes the graph?

Answers

Answer:

the graph crosses the y-axis at -5 and x-axis at -6

Determine the quotient of 1 and 2 over 3 divided by 4 over 5.

A 1 and 1 over 3
B 1 and 8 over 15
C 2 and 1 over 12
D 2 and 5 over 6

Answers

Answer:

D

Step-by-step explanation:

1 2/3÷4/5

=5/3×5/4

=25/12

2 and 1 over 12

Given that f(x) = 2x³-7x²+7ax+ 16 is divisible by x-a, find
(i) the value of the constant a
(ii) the remainder when f(x) is divided by 2x+1.

Answers

Answer:

a = - 2, remainder = 21

Step-by-step explanation:

The Remainder theorem states that if f(x) is divided by (x - a) the remainder is f(a)

Since f(x) is divisible by (x - a) then remainder is zero , then

f(a) = 2a³ - 7a² + 7a² + 16 = 0 , that is

2a³ + 16 = 0 ( subtract 16 from both sides )

2a³ = - 16 ( divide both sides by 2 )

a³ = - 8 ( take the cube root of both sides )

a = [tex]\sqrt[3]{-8}[/tex] = - 2

Then

f(x) = 2x³ - 7x² - 14x + 16

Evaluate f(- [tex]\frac{1}{2}[/tex] ) for remainder on division by (2x + 1)

f(- [tex]\frac{1}{2}[/tex] ) = 2(- [tex]\frac{1}{2}[/tex] )³ - 7(- [tex]\frac{1}{2}[/tex] )² - 14(- [tex]\frac{1}{2}[/tex] ) + 16

        = 2(- [tex]\frac{1}{8}[/tex] ) - 7([tex]\frac{1}{4}[/tex] ) + 7 + 16

        = - [tex]\frac{1}{4}[/tex] - [tex]\frac{7}{4}[/tex] + 23

        = - [tex]\frac{8}{4}[/tex] + 23

       = - 2 + 23

       = 21

Determine the sum by suitable re arrangement .
a) 6254 + 1297 + 446 + 103 Ans:
b) 1983 + 647 + 217 + 353 2.​

Answers

Answer:

a.8100

b.3200

Step-by-step explanation:

hope you're okay

Name the two input device​

Answers

Answer:

keyboard and mouse are two examples of input device

Answer:

keyboard and mouse

Step-by-step explanation:

If you like my answer than please mark me brainliest

What is the fraction or mixed number and write in its simplest form.
3.8416

3.8416=—- (type an integer,proper fraction, or mixed number.)

Answers

Answer:

38416/10000

plss mark me brainliestt

Step-by-step explanation:

3.8416=38416/10000

A bag contains 3 red balls and 5 green balls. What is the probability of picking a red ball from the bag AND getting heads upon flipping a fair coin

Answers

Answer:

the probability would be 3/8

Step-by-step explanation:

Since there are 3 red and 5 green, there is a total of 8 balls in the bag making it a chance of 3/8 to get a red ball. You're Welcome :) <3

Probability of picking a red ball is  [tex]\frac{3}{8}[/tex]

Probability of getting head coin is  [tex]\frac{1}{2}[/tex]

What is probability?

"Probability is the possibility or chance of an event to occur." Ratio of number of favorable outcomes and total number of favorable outcomes is called probability.

We have,

Red balls = 3

Green balls =5

Formula for probability

 [tex]\frac{Number of Favorable Outcomes}{Total Number of Favorable Outcomes}[/tex]

Total number of outcomes n(S) = 8

Number of favorable outcomes for getting a red ball n(E) = 3

Probability of picking a red ball

= [tex]\frac{Number of Favorable Outcomes}{Total number of Favorable Outcomes}[/tex]

= [tex]\frac{3}{8}[/tex]

We have a fair coin,

Total number of outcomes n(S) = 2

Number of favorable outcomes for getting head n(E) = 1

Probability of getting head coin

= [tex]\frac{Number of Favorable Outcomes}{Total Number of Favorable Outcomes}[/tex]

= [tex]\frac{1}{2}[/tex]

Hence, Probability of picking a red ball is  [tex]\frac{3}{8}[/tex]

Probability of getting head coin is  [tex]\frac{1}{2}[/tex].

Learn more about probability here

https://brainly.com/question/15052059

#SPJ2

Do you guys know this because I was trying to submit but it don’t let me I put 7/6 but it say I need different Way

Answers

Answer:

is 5

Step-by-step explanation:

Hope it is helful...

Answer:

5

Step-by-step explanation:

So first when dividing fractions you need to invert and multiply. Thus the fraction becomes:

1/4 * 20/1.

When simplified it becomes 20/4 which is 5.

HOPE THIS HELPED

Calculate 20% of 3 3/4 years in months.​

Answers

Answer:

It is 9 months

Step-by-step explanation:

[tex] = 20\% \times 3 \frac{3}{4} \\ \\ = \frac{20}{100} \times \frac{15}{4} \\ \\ = \frac{300}{400} \\ \\ = \frac{3}{4} \: \: { \sf{years}}[/tex]

convert them to months by multiplying by 12:

[tex]{ \sf{ = \frac{3}{4} \times 12}} \\ \\ = { \sf{9 \: months}}[/tex]

which graph represents the following system of inequalities?
a
b
c
d

Answers

Answer:

A

Step-by-step explanation:

Mark me brainliest.

Both graphs need dashed lines, since they’re < and > and not ≤ or ≥.

You need to shade above y > -x - 4 and you need to shade below y < 2x - 3.

You want to only include the purple section on the right.

La chispa de un relámpago artificial de 10.0 MV libera una energia de 0.125 MW .s ¿Cuántos coulombs de
carga fluyen?

Answers

Answer:

nzbzbzZnzbznzbzbzhzhsbsjs

Draw an equilateral triangle PQR with sides of length 6 cm.​

Answers

Answer:

the answer is attached herewith

ps.hv a great day ahead! :)

Equilateral triangle means all 3 sides are equal. So, in this case, you just have to draw 3 equal sides with 6cm each.

Will mark brainless for first response!!!
Instructions
Consider the polynomials numbered 1 through 4, and the binomials A through F. For each
polynomial, find a binomial that can be used as a denominator to create an expression
without a remainder, and find a binomial that can be used as a denominator to create an
expression with a remainder. Feel free to use the same binomials multiple times. Show your
work.
1. 2x2 – 13x - 7
2. 3x2 - x - 10
3. 3x3 + 8x2 – 31x - 60
4. 6x3 + 37x2 + 57x + 20
A.X-2
B. X-3
C. x - 7
D. x + 4
E. 2x + 1
F. 3x + 5

Answers

1. (2x + 1)(x - 7)
2. -x - 4
3. -31x -35
4. 57x + 112
5. (-x) (-x)

The sum of a rational number and an irrational number is always rational,

A.True
B.False

Answers

Answer:

True

Step-by-step explanation:

The sum of any rational number and any irrational number will always be an irrational number

derivative : y=[(1+x^2)arctgx-x]/2

Answers

Answer:

s,-8*2-`±_'682-¥´owhsi

1. Can the numbers 12, 6, 6 be used to form the sides of a triangle? Why or why not?

Answers

Answer: No, a triangle is not possible in this case

Why not? Because the two sides 6 and 6 add to 6+6 = 12, which does not exceed the remaining side.

Refer to the triangle inequality theorem. This theorem says that for a triangle to be possible, we need these three facts to be true

a+b > cb+c > aa+c > b

where a,b,c are the three sides of the triangle. In short: adding any two sides must be larger than the third side.

I recommend cutting out slips of paper to try making a triangle with sides 12,6, and 6. You'll find its not possible. The two smaller sides combine to perfectly line up with the larger side. The three sides form a line and not a triangle.

F(x) =∛2x g(x)=3x+1 Find (f/g) (x) Include any restrictions on the domain

Answers

Answer:

x ≠ -1/3

Step-by-step explanation:

(f/g)(x) = f(x)/g(x) = ∛2x/(3x+1)

since division by zero is undefined,

Answer:

Step-by-step explanation:

x = - 1/2

Perform the operation and reduce the answer fully. Make sure to express your answer as a simplified fraction. 4/3 divided 7/4

Answers

Answer:

so we have 4/3 divided by 7/4

= 4/3 * 4/7

= 4*4/3*7

= 16/21

Step-by-step explanation:

answer from gauth math

16/21 is the answer to the question

express 3x-x^2 as m-(x-n)^2. Ill give brainliest to correct answer!
(Also please see the picture since you might mistake x having a square as a 2x)

Answers

This is simply done by Method of Completing the Square.

3x - x²

Add and subtract half the coefficient of x and square it.

( This is done so there'd be no alterations to the quadractic Expression)

So To start

We'd like x² to be positive...(So factor out a negative).

( - 3x )

Now In this case

You see there's a Negative Outside the the bracket

Instead of adding and Subtracting squared values of half the coefficient of X... We'd Add Twice and do not subtract.

Reason: If you add outside the bracket and subtract the other inside the bracket... This will be wrong because there's a negative patiently waiting outside the bracket to Interact with the negative you subtracted to make it Positive.

See what I mean.

Let's say you added 2² and subtracted 2² in this problem

( - 3x - 2²)

If you decide to open the bracket

You'll have

+ 3x + 2²

NOW THIS IS WRONG BECAUSE WE ALTERED THIS EXPRESSION. WHERE'D 2² + 2² COME FROM?

THIS IS WHY YOU'LL ADD THE SQUARED COEFFICIENT OF X TWICE IN CASES LIKE THESE.

SO GOING BACK TO THE ORIGINAL QUESTION.

(x² - 3x )

Adding the half the coefficient of x twice and squaring them...

Coefficient of x = 3

Half of 3 = 3/2

Squaring it gives (3/2)²

NOW PROCEEDING

(3/2)² [ - 3x + (3/2)²]

If you open this bracket... (3/2)² will cancel out with (3/2)²

Meaning that we haven't altered the expression in any way

Moving On...

Applying basic factorizing principle

9/4 ( x - 3/2)².

Answer = 9/4 ( x - 3/2)² Which is in the Form m ( x - n )²

Therefore m = 9/4 and n = 3/2.

Hope This Helps

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