Answer:
it is reduced to half of that strength
___ is the pull that all objects exert on each other.
A.Resistance
B.Inertia
C.Gravity
D. Force
Answer:
B
Explanation: Inertia is where it exerts.
What is the displacement of the object?
Answer:
Displacement is a vector quantity that refers to "how far out of place an object is"; it is the object's overall change in position.
A sprinter begins from rest and accelerates at the rate of 2 m/s^2 for 200 m.
a. What is the sprinters velocity at the end of the 200 m?
b. How long does it take him to cover it?
c. What is his average velocity?
Answer:
a. 28.28
B.14.4
C.14.4
Explanation:
A. v^2=u^ + 2as
v^2=0^2 + 2*2*200
B. v=u+at
t=v-u/a
C. V+u/2
The sprinter velocity at the end of the 200 m would be 28.28 m/s.
What are the three equations of motion?There are three equations of motion given by Newton
The first equation is given as follows
v = u + at
the second equation is given as follows
S = ut + 1/2×a×t²
the third equation is given as follows
v² - u² = 2×a×s
As given in the problem a sprinter begins from rest and accelerates at the rate of 2 m/s^2 for 200 m.
By using the third equation of the motion,
v² - u² = 2×a×s
v² - 0² = 2×2×200
v² = 800
v =28.28 m/s
The sprinter velocity at the end of the 200 m would be 28.28 m/s
By using the second equation of motion
S = ut + 1/2*a*t²
u= 0 m/s , a= m/s² s = 200 m
200 = 0 + 0.5*2*t²
t² = 200
t = √200
t = 14.14 seconds
It would take him 14.14 seconds to cover.
average velocity = initial velocity + final velocity /2
= 0+ 28.28/2 m/s
= 14.14 m/s
Thus, The sprinter velocity at the end of the 200 m would be 28.28 m/s.
Learn more about equations of motion from here
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