Answer:
i think it would round to 4031.08
Step-by-step explanation:
3200.00 * 1.08^3
=4032.0784
If 10 candy cost $35. How much candy can I buy with $20
Answer:
6 candies
Step-by-step explanation:
(find unit rate, cost / quantity)
35/10 = 3.5
20/3.5 = = 5.7142857142857
candies cannot be in decimal so you must round to the nearest whole
On Monday, Elsbeth’s bank account balance was -$16.75. On Tuesday, she deposited a check for $5.72. On Thursday, she deposited $16.75. What is her new balance?
-16.75 + (5.72 + 16.75)
Use the commutative property to get:
-16.75 + (16.75 + 5.72)
Use the associative property to get:
(-16.75 + 16.75) + 5.72
Answer:
5.72
Step-by-step explanation:
(-16.75 + 16.75) = 0
0 + 5.72= 5.72
Therefore, the answer is 5.72
How can you multiply fractions and mixed numbers?
Step-by-step explanation:
To multiply fractions:
Multiply numerator to numerator and multiply denominator to denominator. Simplify the answer.
To multiply mixed numbers:
Change mixed numbers into improper fraction. Then multiply numerator and denominator just like how you multiply the fractions. Simplify.
help me pls help me
Answer:
Well I’m not sure what Answers do you want
Step-by-step explanation:
I’m confused on this question
Answer:
[tex]\lim_{x \to 5}f(x)=-5\\\lim_{x \to 1^-} f(x)=3\\\lim_{x \to 1^+} f(x)=3\\\lim_{x \to 1} f(x)=4\\[/tex]
Step-by-step explanation:
[tex]\lim_{x \to 5}f(x)[/tex]
This means "the limit of f(x) as x approaches 5"
In this case, f(x) is a basic linear function while x > 1, so a limit is not necessary but it can still be used as it is here. For this one, you can just calculate f(5), and that is:
[tex]f(x)=5-2x[/tex]
[tex]f(5)=5-2(5)=5-10=-5[/tex]
[tex]\lim_{x \to 5}f(x)=-5[/tex]
===================
[tex]\lim_{x \to 1^-} f(x)[/tex]
This one is a little different. It means "the limit of f(x) as x approaches 1 from the negative (left) direction"
The negative direction of course means x will be less than 1, so we'll use this function:
[tex]f(x)=4-x[/tex]
It's easier if you graph it, but you can also do it like this:
[tex]f(0)=4+0=4\\f(0.5)=4-0.5=3.5\\f(0.75)=4-0.75=3.25\\f(0.9)=4-0.9=3.1\\f(0.99)=4-0.99=3.01[/tex]
There's a clear pattern there. You can see that f(1) should be 3, but this function only applies while x is less than 1 so it can never reach 3. It will get infinitely close, and that can be shown with the limit:
[tex]\lim_{x \to 1^-} f(x)=3[/tex]
===================
[tex]\lim_{x \to 1^+} f(x)[/tex]
This one works the same way, but from the positive (right) direction.
[tex]f(2)=5-4=1\\f(1.5)=5-3=2\\f(1.25)=5-2.5=2.5\\f(1.1)=5-2.2=2.8\\f(1.01)=5-2.02=2.98\\f(1.001)=5-2.002=2.998[/tex]
It will also get infinitely close to 3 when x = 1, but won't ever reach it because this function only applies when x is greater than 1.
[tex]\lim_{x \to 1^+} f(x)=3[/tex]
===================
[tex]\lim_{x \to 1} f(x)[/tex]
Here, the function for x=1 is just:
[tex]f(x)=4[/tex]
It's given already, so the limit is just:
[tex]\lim_{x \to 1} f(x)=4[/tex]
The product of two positive odd consecutive integers is 1599. What is the larger integer?
Answer:
800
Step-by-step explanation:
800+799=1599
Shawn has $20.00 to spend. He wants to save $5.00. He buys two ice creams for $1.65 each, what is the maximum number of packets of chocolate can he buy at a cost of $3.45 for each packet and still have at least $5.00 left over
(solve as an inequality)
Answer:
3
Step-by-step explanation:
3.45x+2*1.65+5>=20
3.45x+8.3>=20
3.45x>=11.7
after rounding
x>=3
What is the first step needed to solve (2/5)x - 6 = -16
Answer:
Add 6 to both sides
Step-by-step explanation:
The (usual) first thing to do when solving any equation is to simplify both sides of the equation. However, since we have nothing to simplify, we move onto the next step that'll be the first step: isolating the variable, x. To do so, we must do the inverse of subtracting 6 (which is adding 6).
at does the point (2, 1.5) represent in this context?
In what context? Do you mean calculus If you are talking about graphing on a graph plane it would be the two accelerates on the x axis so (left or right) and then the 1.5 accelerates on the y axis so 1.5 on the y axis would be one and halfway to the 2 mark on the y axis so in the middle of 1 to 2 on the y axis the y axis goes (up and down)
Can someone help with question #4 please
Answer:
4,0 is the right ok I am a professor
This table shows data collected by a runner.
A three column table with 7 rows. The first column, Time in minutes, has the entries, 1, 2, 3, 4, 5, 6. The second column, Distance in miles, has the entries, 0.19, 0.38, 0.57, 0.76, 0.95, 1.14. The third column, Elevation in meters, has the entries, 12, 28, 67, 98, 124, 145.
Which statement about the scenario represented in the table is true? Assume time is the independent variable.
The distance run is a nonlinear function because it does not have a constant rate of change.
The elevation is a nonlinear function because it does not have a constant rate of change.
Both the distance run and the elevation are nonlinear functions because they do not have constant rates of change.
Both the distance run and the elevation are linear functions because they have a constant rate of change.
Answer:
a
Step-by-step explanation:
Answer:
The correct answer is B, The elevation is a nonlinear function because it does not have a constant rate of change.
Step-by-step explanation:
¿Qué fuerza media se requiere para que un objeto de 2 Kg aumente su velocidad de 5 m/s a 12 m/s en una distancia de 8 m?
Answer:
14.87
Step-by-step explanation:
Para conocer cual es la fuerza que necesita el cuerpo para aumentar su velocidad de 5 m/s a 12 m/s en 8 m
Necesitamos conocer la aceleración y para conocer la aceleración debemos saber cuanto tiempo tarda en recorrer los 8m
Vf = Vo +a(t)
12 = 5 +a(t) -------> Vamos a despejar el tiempo.
t = 7/a
X= Vo(t) +1/2a(t²)
X= 5(7/a)+1/2a( 7/a )²
8 = 35/a+49/2a
a = 7.43 m/s²
Ahora que conocemos la aceleración podemos calcular la fuerza como:
F = m*a
F = 7.43 * 2 kg.
F = 14.87
Steven walked 3 miles and drove 24 miles. Maureen walked 3 miles and drove
18 miles. Who has the greater ratio of miles walked/miles driven?
If 11% of a number equals 4, find 66% of that number.
Answer:
363/20,000
.................................................................................
Answer:
24
Step-by-step explanation:
Let the number be " x ".
11 % of x = 4
( 11 / 100 ) * x = 4
x = 4 * ( 100 / 11 )
x = 400 / 11
66 % of that number
= 66 % of x.
= 66 % of 400 / 11
= ( 66 / 100 ) x ( 400 / 11 )
= ( 66 x 400 ) / ( 100 x 11 )
= 6 x 4
= 24
what is the HCF of 2x and x
HCF (2x, x) = x.
Factors of 2x = 2 × x × 1
Factors of x = x × 1
Common factors = x, 1
HCF = x × 1 = x
See the attachment too.
________
Hope it helps ⚜
Line /1 and line /2 are parallel line
Step-by-step explanation:
1=56⁰
2=56⁰
3=68⁰
4=68⁰
5=56⁰
6=112⁰
7=180-124 Ans=56⁰
8=68+56 Ans=124⁰
9=68⁰
10=112⁰
11=124⁰
12=56⁰
IT TOOK 15MINS mark me BRAINLIEST pls!PLEASE ANSWER ASAP (no links please)
Solve for the indicated variable
g/h = e - 10 for g
Answer:
g = he - 10h
Step-by-step explanation:
is 1/4 to the 0 power bigger then 1
Answer:
1/4 to the 0 power is equal to 1. Therefore, it is not bigger than 1
Please please help !
Answer:
Unsure but it might be -8/3
Step-by-step explanation:
Find the value of x.
(8x + 2)°
60°
Y
70°
Z
Here according to angle sum property all angles sum u up 180°
So,
[tex]8x + 2 + 60 + 70 = 180 \\ 8x + 132 = 180 \\ 8x = 180 - 132 \\ 8x = 48 \\ x = \frac{48}{8} \\ x = 6[/tex]
- BRAINLIEST answerer
Billie bikes 9 miles in 45 minutes. At this rate, how many miles can he bike in 90 minutes?
Answer:
18 miles
Step-by-step explanation:
9 miles : 45 minutes
? miles : 90 minutes
45 x 2 = 90 minutes
9 x 2 = 18 miles
Suppose a population is of size N is 1,000,000. Compute the correction factor for the SE of the sample mean, when the sample size, n, is equal to 1,000; 10,000; and 100,000.
Answer:
90081???
Step-by-step explanation:
Write the equation of the line that passes through (-2, 4) and is perpendicular to x = 3.
Check the picture below.
Abby has $32 to spend on party supplies. After buying 9 packs of noisemakers, she has $20 left.
How much did each pack of noisemakers cost?
A
$0.75
B
$1.15
C
$1.33
D
$12.00
Answer:
$1.33
Step-by-step explanation:
32-20 = 12
12/9 = $1.33
Please help with this
==========================================
Explanation:
A) This is true because there are 4 cups of green and 2 cups of white. Each box represents 1 cup.
B) This is false. The ratio 4:2 reduces to 2:1 when describing the ratio of green to white. We have twice as many green compared to white. Choice B describes the other way around. The order is important.
C) This is true. We have 2 cups of white and 4 cups of green.
D) False. There are 6 cups total, but only 2 white (not 4).
E) True. This is a verbal way of describing the ratio 4:2, of green to white.
F) False. The ratio is the other way around. See choice E.
G) False. There are 4 cups of green, not 6. There are 6 cups total, not 4. The ratio of green to total is 4:6.
H) True. We have 2 cups of white and 2+4 = 6 cups total.
7. Add [-6-2 2] + [-3 2 1].
A. [-9-3-5]
B. [-3 0 3]
C. [-6 0 3]
D. [-9 0 3]
Given log_73≈0.5646 and log_716≈1.4248, evaluate the expressions. Please show work using given values.
Answer:
(a) [tex]\log_72 \approx 0.3562[/tex]
(b) [tex]\log_7(\frac{147}{16} ) = 2[/tex]
Step-by-step explanation:
For the point a:
For this problem we use the information of [tex]\log_716 \approx 1.4248[/tex]
16 can be re-write as [tex]2^4[/tex]. Then you have:
[tex]\log_72^4[/tex]
Using the power property of the logarithm we have:
[tex]\log_ba^c = c\log_ba[/tex]
[tex]\log_72^4 = 4\log_72[/tex]
And this expression is equal to:
[tex]4\log_72 \approx 1.4248\\\log_72\approx \frac{1.4248}{4} \approx 0.3562\\[/tex]
For the point b:
For this problem we use the information of [tex]\log_716 \approx 1.4248[/tex] and [tex]\log_73 \approx 0.5646[/tex]
The first is use the quotient property in the given log.
[tex]\log_c\frac{a}{b} = \log_ca-\log_cb[/tex]
[tex]\log_7\frac{147}{16} = \log_7147 -\log_716[/tex]
We already know the value of [tex]\log_716[/tex] then we have to calculate the value of [tex]\log_7147[/tex].
So we factorize the number 147 in [tex]3 \cdot 7 \cdot 7[/tex] (for factorize the number start with the smaller prime and check if the remainder is 0, it is then is a primer factor of the number).
Now re-write [tex]\log_7147[/tex] as [tex]\log_73 \cdot 7^2[/tex] and by the product property get:
[tex]\log_bmn = \log_b m +\log_b n\\\log_73 \cdot 49 = \log_7 3 +\log_7 49 = 0.5646 + 2 = 2.5646[/tex]
Know replace each value in the subtraction and get the result:
[tex]\log_7147 -\log_716 = 2.5646 - 0.5646 = 2[/tex]
Your cell phone bill in August was $61.43, which was $21.75 more than your bill in July. Your cell phone bill in July was $13.62 less than
in June. What was your cell phone bill in June?
Answer:
$53.30
Step-by-step explanation:
61.43-21.75=39.68 is the cell phone bill in July.
39.68+13.62= 53.30 is the phone bill in June.
Answer:
53.30
Step-by-step explanation:
August= 61.43
July= (61.43-21.75) or 39.68
June= (39.68+13.62) or 53.30
Hope this helps! :)
The owner of Get-A-Away Travel has recently surveyed a random sample of 496 customers to test the mean age of the agency's customers is over 24 . The appropriate hypotheses are H0: μ ⤠24, Ha: μ > 24 If he concludes the mean age is over 24 when it is not over 24, he makes a _error.
Using error concepts for hypothesis tests, it is found that there is a Type I error.
A Type I error happens when a true null hypothesis is rejected.
A Type II error happens when a false null hypothesis is not-rejected.
In this problem, the null hypothesis is:
[tex]H_0: \mu = 24[/tex]
The alternative hypothesis is:
[tex]H_1: \mu > 24[/tex]
He concludes that the mean age is over 24 when it is not, that is, a true null hypothesis is rejected, hence there is a Type I error.
A similar problem is given at https://brainly.com/question/25225353
At a particular time, a tree casts a shadow 17 m long on horizontal ground. At the same time, a vertical pole 3 m high casts a shadow 4 m long. Calculate the height of the tree to the nearest tenth of a meter.
Using a system of equations, the height of the tree would be 12.80 meters.
Equating the height and shadows of the tree and pole :
Height of pole / shadow of pole = height of tree / shadow of tree
Representing the equation thus :
Let the height of the tree = h
3/4 = h/17
Cross multiply
4h = 17 × 3
4h = 51
Divide both sides by 4
h = 51/4
h = 12.75.
Hence, the height of the tree to the nearest tenth of a meter is 12.80 meters.
Learn more : https://brainly.com/question/25562438