If the arc length of a circle with a radius of 5 cm is 18.5 cm, what is the area of the sector, to the nearest hundredth



i need it quick please

2x - 3 would be 92 - 3 = 89 inches, which is the length of the table

The table needs to be 2 times longer than it is wide, so its length is 2 times its width, or 2x.

The table also needs to be 3 inches shorter than it is wide, so its width is x + 3 inches.

The area of the table is 4,608 square inches, so we can set up an equation:

2x(x + 3) = 4,608

Simplifying this equation:

2x²+ 6x = 4,608

Dividing both sides by 2:

x²+ 3x - 2,304 = 0

We can solve for x using the quadratic formula:

x = (-b ±  √(b² - 4ac)) / 2a

In this case, a = 1, b = 3, and c = -2,304. Substituting these values:

x = (-3 ±  √(3² - 4(1)(-2,304))) / 2(1)

Simplifying:

x = (-3 ±  √(9 + 9,216)) / 2

x = (-3 ±  √(9,225)) / 2

x = (-3 ± 95) / 2

x = 46 or x = -49

Since the width of the table cannot be negative, we can ignore the negative solution. Therefore, x needs to be 46 inches to fit the given requirements.

The length of the table is 2x, or 2(46) = 92 inches, and the width is x + 3, or 46 + 3 = 49 inches. The area is 92 * 49 = 4,508 square inches, which matches the given area requirement.

So, 2x - 3 would be 92 - 3 = 89 inches, which is the length of the table.

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The number of different menu combinations Mr. Carlos' family can choose is 60.

To find the total menu combinations, you need to use the multiplication principle. Since there are 3 choices of appetizers, 5 choices of entrees, and 4 choices of cake, you simply multiply these numbers together. Here's the step-by-step explanation:

1. Multiply the number of appetizer choices (3) by the number of entree choices (5): 3 x 5 = 15
2. Multiply the result (15) by the number of cake choices (4): 15 x 4 = 60

So, there are 60 different menu combinations possible for Mr. Carlos' family to choose for their reception.

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Answer:

  C = (-1, -2)

  D = (2, 0)

Step-by-step explanation:

You want the coordinates of points C and D in parallelogram ABCD such that point E(0, 2) is the intersection of the diagonals. Given points are A(1, 6) and B(-2, 4).

The diagonals of a parallelogram bisect each other. This means the point of intersection of the diagonals is the midpoint of each:

  E = (A +C)/2 . . . . . . . . . . . . . . . E is the midpoint of AC

  C = 2E -A = 2(0, 2) -(1, 6)

  C = (-1, -2)

and

  D = 2E -B = 2(0, 2) -(-2, 4) . . . . . using the same pattern

  D = (2, 0)

The value of x is 5/3.

A fraction is a part of a whole. In arithmetic, the number is expressed as a quotient, in which the numerator is divided by the denominator.

We have equation in fraction are:

[tex]\frac{3x-2}{3x+1} = \frac{1}{2}[/tex]

To solve the value of x

In the above equation, Solve by cross multiplication:

2(3x - 2) = 3x + 1

Open the bracket and multiply by 2 :

6x - 4 = 3x +1

Combine the like terms:

6x - 3x = 1 + 4

Add and subtract the terms:

3x = 5

x = 5/3

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The rate at which the cost of production is changing is 1000 hundred dollars per day or $100,000 per day.

To find the rate at which the cost of production is changing, we'll use the given cost function C = 50x + 1000, and the information that production is growing at a rate of 20 cases per day when x = 50 cases.

First, differentiate the cost function with respect to x to get the rate of change of the cost with respect to the number of cases produced (dC/dx):

dC/dx = 50

The derivative, 50, tells us that the cost increases by 50 hundred dollars for each additional case produced.

Now, we're given that dx/dt = 20 cases per day when x = 50 cases. To find dC/dt, the rate at which the cost of production is changing, multiply the rate of change of the cost with respect to the number of cases (dC/dx) by the rate of change of the number of cases with respect to time (dx/dt):

[tex]dC/dt = (dC/dx) × (dx/dt) = 50 × 20[/tex]

dC/dt = 1000

So, the rate at which the cost of production is changing is 1000 hundred dollars per day or $100,000 per day.

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The area under the curve at the given points is 3.758 sq.units.

The area under the curve at the given points is calculated as follows;

y = -3/x ; (-7, -2)

To find the area under the curve y = -3/x between x = -7 and x = -2, we need to integrate the function from x = -7 to x = -2.

∫[-7,-2] (-3/x) dx

= [-3 ln|x|]_(-7)^(-2)

= [-3 ln|-2| - (-3 ln|-7|)]

= [-3 ln(2) + 3 ln(7)]

= 3 ln(7/2)

= 3.758 sq.units

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1. Write out the given equation: 8/10 + unknown fraction = 97/100

2. Subtract 8/10 from both sides of the equation to isolate the unknown fraction:

  8/10 + unknown fraction - 8/10 = 97/100 - 8/10

  Simplifying the left side: unknown fraction = 97/100 - 8/10

3. Convert both fractions to have a common denominator of 100:

  97/100 - 8/10 = 97/100 - 80/100

  Simplifying the right side: unknown fraction = 17/100

4. Therefore, the unknown fraction is 17/100.

So, the correct answer is "seventeen hundredths".

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The cost of a plumber's one-hour visit is $51, determined by the linear equation C = 51d, where C is the cost and d is the duration of the visit in hours.

If a plumber's visit lasts for a certain duration, the cost can be determined using the equation

                           C = 51d

where C is the cost and d is the duration of the visit in hours.

In this case, the duration of the plumber's visit is given as 1 hour. Substituting d = 1 in the equation, we get

                             C = 51(1) = $51

as the cost of the plumber's visit.

Therefore, if the plumber's visit lasts for one hour, it would cost $51 according to the given equation.

This cost may vary if the duration of the visit changes, as it is directly proportional to the duration of the visit.

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U(1,1), Q(4,4), and A(6,2) form a right triangle with UQ and QA being the legs and UA being the hypotenuse.

To determine whether U(1,1), Q(4,4), and A(6,2) form a right triangle, we will follow the given guide:

Find the slopes of sides UQ, QA, and UA:

Determine which segments are perpendicular and how we know they are perpendicular:

To determine if two lines are perpendicular, we need to check if their slopes are negative reciprocals of each other.

Find the lengths of each side:

Use the Pythagorean Theorem to show that it is a right triangle:

Since we have determined that UQ and QA are perpendicular, we can use the Pythagorean Theorem to show that it is a right triangle.

Since (Length of UA)² + (Length of QA)² = (Length of UQ)², we know that the triangle is a right triangle.

U(1,1), Q(4,4), and A(6,2) form a right triangle with UQ and QA being the legs and UA being the hypotenuse.

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The cost of a small cup of coffee is $2.97, and the cost of a piece of banana bread is $5.13.

Let x represent the cost of a small coffee and y represent the cost of a piece of banana bread. We know:

Cost of muffin: $3.51

y = x + $2.16

5(x + $3.51) + 2(x + y) = $48.60

Substitute y with x + $2.16:

5(x + $3.51) + 2(x + (x + $2.16)) = $48.60

Solve for x:

9x + $21.87 = $48.60

9x = $26.73

x = $2.97

Find y:

y = x + $2.16

y = $2.97 + $2.16

y = $5.13

A slice of banana bread costs $5.13, while a small coffee costs $2.97.

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Part a: f(x) = (x-3)^2 + 5

Part b: f(x) = (x+10)^2 + 5

Part a: To shift the function f(x) = x^2 + 5 right 3 units, we need to subtract 3 from the x-coordinate of the vertex. The vertex form of a quadratic function is given by f(x) = a(x-h)^2 + k, where (h,k) is the vertex. Thus, the function in vertex form that shifts f(x) right 3 units is:

f(x) = (x-3)^2 + 5

Part b: To shift the function f(x) = x^2 + 5 left 10 units, we need to add 10 to the x-coordinate of the vertex. Using the same vertex form as before, the function in vertex form that shifts f(x) left 10 units is:

f(x) = (x+10)^2 + 5

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The surface area of the given regular pyramid is 84 cm^2.

To find the surface area of a regular pyramid, we need to calculate the area of each face and add them together. A regular pyramid has a base that is a regular polygon, and its lateral faces are triangles that meet at a common vertex. We can use the Pythagorean theorem to find the slant height of the pyramid, which is the height of each lateral face.

Let's assume that the base of the regular pyramid is a square with side length 6 cm, and the slant height is 4 cm.

First, we need to find the area of the base of the pyramid:

Area of the base = (side length)^2

                = 6 cm x 6 cm

                = 36 cm^2

Next, we need to find the area of each triangular lateral face. Since the pyramid is a regular pyramid, all the triangular faces are congruent.

We can find the area of each triangular face using the formula:

Area of a triangle = (1/2) x base x height

The base of each triangular face is equal to the side length of the square base, which is 6 cm. The height of each triangular face is equal to the slant height, which is 4 cm.

Area of each triangular face = (1/2) x 6 cm x 4 cm

                            = 12 cm^2

Since the pyramid has 4 triangular faces, we need to multiply the area of one triangular face by 4 to get the total area of all the triangular faces:

Total area of the triangular faces = 4 x 12 cm^2

                                 = 48 cm^2

Finally, we can find the total surface area of the pyramid by adding the area of the base and the area of the triangular faces:

Total surface area = Area of the base + Total area of the triangular faces

                  = 36 cm^2 + 48 cm^2

                  = 84 cm^2

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Using the Pythagorean theorem, the value of x, rounded to the nearest tenth, is 11.5 units.

In the given right triangle ABC with right angle B, you are given the lengths of sides BC (8 units) and AC (14 units). You are asked to find the length of side AB (x units). To do this, you can use the Pythagorean theorem, which states that the square of the hypotenuse (AC) is equal to the sum of the squares of the other two sides (AB and BC).

So, the equation for this triangle is:

AC² = AB² + BC²

Plug in the given values:

14² = x² + 8²

196 = x² + 64

Subtract 64 from both sides:

132 = x²

Now, find the square root of 132:

x ≈ 11.5

So, the value of x, rounded to the nearest tenth, is 11.5 units.

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p(x) = x + 5, and k = 2. The expression x^2 + 7x + 12 / (x + 2) can be written in the form p(x) + k / (x + 2) as:

x + 5 + 2 / (x + 2)

To express the given expression x^2 + 7x + 12 / (x + 2) in the form p(x) + k / (x + 2), we will perform polynomial division.

1. Divide the numerator (x^2 + 7x + 12) by the denominator (x + 2):

(x^2 + 7x + 12) ÷ (x + 2)

2. Perform long division:

       x + 5
       ________________
x + 2 | x^2 + 7x + 12
       - (x^2 + 2x)
       ________________
             5x + 12
             - (5x + 10)
       ________________
                 2

3. Write the result:

p(x) + k / (x + 2) = x + 5 + 2 / (x + 2)

So, p(x) = x + 5, and k = 2. The expression x^2 + 7x + 12 / (x + 2) can be written in the form p(x) + k / (x + 2) as:

x + 5 + 2 / (x + 2)

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The backpack forms an angle of approximately 15 degrees with the ground.

What is Pythagorean theorem?

The Pythagorean theorem is a fundamental concept in mathematics that relates to the lengths of the sides of a right triangle.

To find the angle that Luis's backpack forms with the ground, we can use the inverse tangent function.

The height of the backpack when the handle is extended is 3.5 feet, and the distance from the ground to Luis's hand is 3 feet. So the opposite side of the triangle is 3.5 - 3 = 0.5 feet, and the adjacent side is the distance from Luis's hand to the backpack, which we can call x.

Using the tangent function, we have:

tan(theta) = opposite/adjacent

tan(theta) = 0.5/x

To solve for x, we can use the Pythagorean theorem:

x² + 3² = (3.5)²

x² = 3.5² - 3²

x² = 3.25

x = sqrt(3.25)

x ≈ 1.8 feet

Now we can substitute x into our tangent equation and solve for theta:

tan(theta) = 0.5/1.8

theta = arctan(0.5/1.8)

theta ≈ 15 degrees

Therefore, the backpack forms an angle of approximately 15 degrees with the ground.

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The height of the trapezoidal tabletop is approximately 59.5 centimeters.

To calculate the height of a trapezoid with the given measurements, we need to use the formula for the area of a trapezoid: A = (b1 + b2)h / 2, where A is the area, b1 and b2 are the lengths of the two bases, and h is the height.

In this problem, the area (A) is 7,021 square centimeters, the longer base (b1) is 131 centimeters, and the shorter base (b2) is 105 centimeters. Our task is to find the height (h).

First, let's plug the given values into the formula:

7,021 = (131 + 105)h / 2

Now, simplify the equation:

7,021 = 236h / 2

To solve for h, multiply both sides of the equation by 2:

14,042 = 236h

Finally, divide both sides by 236:

h ≈ 59.5

Thus, the height is approximately 59.5 centimeters.

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Note that Dawson's annual premium will be $2,462.40.

Dawson's annual premium will be $2,462.40.

This can be derived by going across from "Male 40-44" over to "20-year coverage" which is $13.68. Since $13.68 is per $1000 of coverage, you would multiply it by 180 to get $2,462.40.

An insurance premium is the amount of money paid by a person, firm, or enterprise to obtain an insurance coverage. The amount of the insurance premium is governed by a variety of factors and varies from one payee to the next.

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Full Question:

Although part of your question is missing, you might be referring to this full question:

Answer:

Step-by-step explanation:

The total number of students who were surveyed is 575

The graph likely displays a horizontal axis and a vertical axis.

In this graph, the horizontal axis may indicate two categories, such as "juniors" and "seniors," and the vertical axis shows the number of students in each category who responded "yes," "no," or "not sure."

To find the total number of students surveyed, we need to look for the bar that represents the entire group of juniors and seniors. Typically, this bar will be labeled as "total," "all," or something similar. Once we locate this bar, we can add up the number of students represented by the bar. The value will be displayed on the vertical axis, and it should correspond to the sum of the bars for juniors and seniors separately.

=> 100 + 200 + 125 + 150 = 575

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To solve this equation, we first simplify both sides of the equation by using the distributive property to expand the right-hand side:

4x + 5 = 6(x + 3) - 20 - 2x

4x + 5 = 6x + 18 - 20 - 2x

Next, we can combine like terms on the right-hand side:

4x + 5 = 4x - 2

Now, we can subtract 4x from both sides to isolate the variable on one side of the equation:

4x - 4x + 5 = 4x - 4x - 2

5 = -2

This is a contradiction since 5 cannot be equal to -2. Therefore, there is no solution to this equation.

In other words, the equation is inconsistent and there is no value of x that can make it true.

The value of the expression 11C7 is 330. This can be calculated using the formula for combinations, which is nCr = n!/r!(n-r)!, where n is the total number of objects and r is the number of objects being selected. So, the correct answer is A).

To calculate the value of the expression 11C7, we need to use the formula for combinations or binomial coefficients, which is

nCr = n! / (r! * (n-r)!)

where n is the total number of items, r is the number of items to be chosen, and ! denotes the factorial operation (the product of all positive integers up to n).

In this case, we have

n = 11 and r = 7

So, we can substitute these values into the formula

11C7 = 11! / (7! * (11-7)!)

= 11! / (7! * 4!)

= (11 * 10 * 9 * 8 * 7 * 6 * 5) / (4 * 3 * 2 * 1)

= 330

Therefore, the value of the expression 11C7 is 330. So, the correct answer is A).

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--The given question is incomplete, the complete question is given

"Pls respond quick | what is the value of the expression? ₁₁C₇

a)330

b)1,663,200

c)5040

d)7920"--

The area of the circles are 1384.74 cm², 20601.54 cm² and 1589.625 cm²

From the question, we have the following parameters that can be used in our computation:

Radii = 21 cm, 81 ft, 45/2 cm

The area of a circle is calculated as

Area = πr²

substitute the known values in the above equation, so, we have the following representation

Area = 3.14 * 21² = 1384.74

Area = 3.14 * 81² = 20601.54

Area = 3.14 * (45/2)² = 1589.625

Hence, the area of the circles are 1384.74 cm², 20601.54 cm² and 1589.625 cm²

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Proportionately, if 8 cm represents​ 10%, the length of a line segment that is​ 100% is 80 cm.

Proportion is the ratio of two quantities equated to each other.

Proportion also represents the portion or part of a whole.

Proportions can be represented using decimals, fractions, or percentages, like ratios.

The percentage of 8 cm length = 10%

The whole length = 100%

Proportionately, 100% = 80 cm (8 ÷ 10%) or (8 x 100 ÷ 10)

Thus, we can conclude that 100% of the line segment will be 80 cm if 8 cm is 10%.

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If 8 cm represents​ 10%, what is the length of a line segment that is​ 100%? Explain.

The function represents exponential decay with a percentage rate of decrease of 9.8%.

The given exponential function y = 660(0.902) represents decay because the base of the exponent is less than one.

This means that the output value of the function will decrease as the input value increases.

To determine the percentage rate of decrease, we need to find the value of the base of the exponent subtracted from one and then multiply it by 100.

The base of the exponent is 0.902, so we subtract it from one to get 0.098.

Multiplying by 100 gives us a percentage rate of decrease of 9.8%.

This means that for every unit increase in the input value, the output value of the function will decrease by approximately 9.8%.

For example, if the input value increases from 1 to 2, the output value will decrease by 9.8%, and if the input value increases from 2 to 3, the output value will again decrease by 9.8%.

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The percentage of body weight the dog lost is 9.2%. Mary would weigh 52.664 kg after losing the same percentage of body weight as her dog.

A) To find the percentage of body weight the dog lost, first, calculate the actual weight loss: 25 kg - 2.3 kg = 22.7 kg. Then, divide the weight loss (2.3 kg) by the original weight (25 kg) and multiply by 100 to get the percentage: (2.3 kg / 25 kg) * 100 = 9.2%.

B) If Mary lost the same percentage of her body weight as the dog did, she would lose 9.2% of her weight. To calculate this, multiply her original weight (58 kg) by the percentage (9.2%): 58 kg * 0.092 = 5.336 kg. Now, subtract this weight loss from her original weight to find her new weight: 58 kg - 5.336 kg = 52.664 kg. So, Mary would weigh 52.664 kg after losing the same percentage of body weight as her dog.

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The second wedge has a greater volume by 4.125 cubic inches. Therefore, the correct option is 4.

To determine which cheese wedge has a greater volume, you need to calculate the volume of each triangular prism using the given dimensions.

For the first wedge:

1. Calculate the area of the base (isosceles triangle):

(base x height) / 2 = (2.5 in x 4.5 in) / 2 = 5.625 square inches

2. Calculate the volume of the prism:

base area x thickness = 5.625 sq in x 3 in = 16.875 cubic inches

For the second wedge:

1. Calculate the area of the base (isosceles triangle):

(base x height) / 2 = (3 in x 4 in) / 2 = 6 square inches

2. Calculate the volume of the prism:

base area x thickness = 6 sq in x 3.5 in = 21 cubic inches

To find which wedge has a greater volume and by how much, subtract the smaller volume from the larger volume:

21 cu in - 16.875 cu in = 4.125 cu in.

Therefore, the correct answer is option 4: The second wedge has a greater volume by 4.125 cubic inches.

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Amount that will be in the account after 2 years with daily compounding is $28,484.03.

Amount that will be in the account after 2 years with continuous compounding is $28,498.84.

The appropriate compound interest formula is:

[tex]A = P(1 + r/n)^{nt[/tex]

A is the amount.

P is the principal.

r is the annual interest rate.

n is the number of times the interest is compounded all year.

t is the number of years.

(a) For daily compounding (n = 365), we have:

A = 26000(1 + 0.0365/365)³⁶⁵*²
A = 26000(1 + 0.0001)⁷³⁰
A = 26000(1.0001)⁷³⁰
A = 28,484.03

Therefore, the amount that will be in the account after 2 years with daily compounding is $28,484.03.

(b) For continuous compounding, we have:

A = P[tex]e^{rt[/tex]

e is the mathematical constant almost equal to 2.71828.

A = 26000[tex]e^{0.0365*2[/tex]
A = 26000[tex]e^{0.073[/tex]
A = 28,498.84

Therefore, the amount that will be in the account after 2 years with continuous compounding is $28,498.84.

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Answer:

The equation to represent Fernando's job offer is:

y = 15 + x

Where y is the hourly wage and x is the number of months worked.

The equation to represent Amelia's job offer is:

y = 8(1 + 0.1)^x

Where y is the hourly wage and x is the number of months worked.

To determine the time period for which Fernando's offer is better, we need to find the point where his hourly wage is greater than Amelia's. We can set the two equations equal to each other and solve for x:

15 + x = 8(1 + 0.1)^x

15 + x = 8(1.1)^x

x ≈ 20.44

Therefore, Fernando's offer is better for any time period greater than 20.44 months.

To determine the time period for which Amelia's offer is better, we need to find the point where her hourly wage is greater than Fernando's. We can set the two equations equal to each other and solve for x:

8(1 + 0.1)^x = 15 + x

8(1.1)^x = 15 + x

x ≈ 14.45

Therefore, Amelia's offer is better for any time period less than 14.45 months.

For the long run, we need to determine which offer has a higher hourly wage after a certain number of months. We can compare the two equations by finding their limits as x approaches infinity:

lim (y = 15 + x) as x → ∞ = ∞

lim (y = 8(1 + 0.1)^x) as x → ∞ = ∞

Therefore, both offers have the same long-term hourly wage of infinity. However, Fernando's offer has a faster rate of increase, so it may be more beneficial in the long run.

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OD. M = log(I/10,000)

How can the magnitude of an earthquake be calculated when its intensity is 10,000 times that of the reference earthquake?

The correct equation that calculates the magnitude, M, of an earthquake with an intensity 10,000 times that of the reference earthquake is option B: M = log(10,000/Io).

In the given equation M = log(I/IO), I represents the intensity of the earthquake being measured, and IO represents the intensity of the reference earthquake. Since the intensity of the earthquake in question is 10,000 times that of the reference earthquake, we substitute I with 10,000 times IO.

Therefore, the equation becomes M = log(10,000/Io), which is option B. This equation allows us to calculate the magnitude of the earthquake based on the relative intensity compared to the reference earthquake.

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Answer:

x=180-90-54, y=180-x,z=90

Step-by-step explanation:

the sum of the degree of a triangle will equal 180. the sum of the degree of a line will equal 180.