To calculate the wavelength of the 'C' note from Problem 2 in this guitar string, we also need to know its frequency. Assuming you're referring to the 'C' note with a frequency of 261.63 Hz (C4), we need to use the formula,
Using the formula, wavelength = speed / frequency, we can calculate the wavelength as follows:
Wavelength = Speed of Sound / Frequency
wavelength = 220 m/s / 261.63 Hz
wavelength = 0.8415 meters.
wavelength = 84.15 cm.
Therefore, the wavelength of the 'C' note on this guitar string is approximately 0.8415 meters or 84.15 cm.
therefore the correct answer is : his guitar string is approximately 0.8415 meters or 84.15 cm.
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a car pull a truck with a force of 1500N The truck move a distance of 10m in 15s, what is the work and the power
The amount of work done is 15,000 J if an automobile pulls a truck with a force of 1500 N and the truck travels 10 meters in 15 seconds. One kW or 1,000 W is the power.
How do you determine the amount of work done in this scenario?A force's work is indicated by:
Fdcosθ = W
d is the distance moved in the direction of the force, F is the force's magnitude, and is the angle between the force and the displacement.
W = 1500 N x 10 m x cos(0°), which equals 15,000 J.
The amount of work is 15,000 J.
How would you determine power in this scenario?P = W/t
P = 15,000 J / 15 s = 1,000 W
One kW or 1,000 W is the power.
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if vector A and B has equal magnitude and A+B is 3 times larger than A-B what is the angle of A and B Search instead for if vector A and B has equal magnitude and A+B is three times larger than A-B what must be the angle of A and B
Answer:
Let's represent the magnitude of both vectors A and B using the variable "m".
According to the problem statement, we have:
|A| = |B| = m
|A+B| = 3|A-B|
Squaring both sides, we get:
|A+B|^2 = 9|A-B|^2
Expanding the left-hand side using the dot product formula, we have:
(A+B)·(A+B) = A·A + 2A·B + B·B
Similarly, expanding the right-hand side, we have:
9(A-B)·(A-B) = 9A·A - 18A·B + 9B·B
Substituting the given magnitudes, we have:
(A+B)·(A+B) = 2m^2 + 2(A·B)
9(A-B)·(A-B) = 18m^2 - 18(A·B)
Substituting these expressions back into the original equation, we get:
2m^2 + 2(A·B) = 9(18m^2 - 18(A·B))
Simplifying and rearranging, we get:
20(A·B) = 323m^2
Dividing by |A|·|B| = m^2, we have:
20(cosθ) = 323
where θ is the angle between vectors A and B. Solving for θ, we get:
θ = cos⁻¹(323/20)/π * 180
θ ≈ 83.4 degrees
Use the law of the conservation of energy and the formulas for one-dimensional projectile motion, gravitational potential energy. and kinetic energy to solve the problems below. Neglect friction. air resistance, and other dissipative forces in all problems.
Use g = 9.8 m/s.
1. A metal ball bearing with mass 5.0 g falls out of a factory machine and drops to the concrete floor 3.0 m below. It bounces back up to its starting point. Find the changes in the bearing's potential and kinetic energies as it a) travels from the machine down to the floor, and b) travels up from the floor back to its starting point.
Answer:
First, let’s convert the mass of the ball bearing from grams to kilograms: 5.0 g = 0.005 kg.
a)
As the ball bearing falls from the machine to the floor, its gravitational potential energy is converted into kinetic energy. The change in potential energy can be calculated using the formula for gravitational potential energy: PE = mgh, where m is the mass of the object, g is the acceleration due to gravity, and h is the height of the object above some reference point.
In this case, the change in potential energy is ΔPE = mgh = (0.005 kg)(9.8 m/s²)(3.0 m) = 0.147 J.
Since energy is conserved, this means that the change in kinetic energy is equal to the change in potential energy: ΔKE = ΔPE = 0.147 J.
b)
As the ball bearing bounces back up from the floor to its starting point, its kinetic energy is converted back into potential energy. Since energy is conserved and there are no dissipative forces, the changes in potential and kinetic energies are the same as in part a): ΔPE = 0.147 J and ΔKE = 0.147 J
Can someone help me
Answer:
online medical
Explanation:
like COVID dieases technicians do online training
when the pressure of a fixed of gas is increase to 10 atmosphere, the temperature increases from o.c to 73.c ? what is the ratio of the initial pressure to the final pressure
The initial pressure to final pressure ratio is 0.789.
What happens if an ideal gas's pressure is 10% higher at constant temperature?An ideal gas's volume must fall by if its pressure is raised by 10% at constant temperature. If an ideal gas's pressure is raised at constant temperature. At constant temperature, when a gas's pressure is increased by 5%.
P1V1/T1 = P2V2/T2
Since the volume of the gas is fixed in this problem, we can simplify the equation to:
P1/T1 = P2/T2
We are given that P1 = 1 atmosphere and T1 = 0°C = 273.15 K, and we need to find the ratio P1/P2. We can rearrange the equation to solve for P2:
P2 = P1 × T2 / T1
We are also given that T2 = 73°C = 346.15 K and P2 = 10 atmospheres, so we can substitute these values into the equation and solve for P1/P2:
P1/P2 = T1/T2 × P2/P1
P1/P2 = 273.15 K / 346.15 K × 10 atm / 1 atm
P1/P2 = 0.789
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Help! Please Show Your Work!!!
V = I R or I = V / R
I = 25 / 45 amps = .56 amps
How much charge is passing through a
circuit providing electricity for a 120 V light
bulb if it uses 300 J of energy?
6.25 coulombs of charge is passing through a circuit providing electricity for a 120 V light bulb if it uses 300 J of energy.
What is charge ?
When placed in an electromagnetic field, the physical property of matter known as electric charge causes matter to feel a force. A positive or negative electric charge can exist. (commonly carried by protons and electrons respectively, by convention). Like charges repel one another, while unlike charges draw one another. A neutral substance is one that does not have any net charge. Classical electrodynamics refers to early understanding of how charged substances interact, and it is still accurate for problems that do not require consideration of quantum effects.
Electric charge is a conserved characteristic; the net charge of an isolated system, which is the sum of positive and negative charges, cannot change. Subatomic particles carry electric energy. Negative charge in ordinary substance.
Calculate the amount of time that the energy is used.
[tex]\frac{300 J}{120 V}[/tex]= 2.5 seconds
Calculate the current running through the circuit.
Current = Power / Voltage = [tex]\frac{300W}{120V}[/tex]= 2.5 Amps.
Calculate the charge passing through the circuit.
Charge = Current x Time
= 2.5 Amps x 2.5 seconds
= 6.25 Coulombs of charge.
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Please help! Its due date is in 10 minutes!!
Answer:
the circle on left shows the needle to the right (north pole). the circle on the right shows the needle to the right again.
Explanation:
the needle always goes to north
jpopwgtxfp give atleast 2 situations,in which you would store the data on cloud storage
Disaster recovery and cooperation are both benefited by cloud storage. It makes file sharing simple and guarantees that data is backed up and retrievable in the event of loss or damage.
What are the two benefits of keeping all of your data in the cloud?Your documents and data are kept in a safe data centre off-site by a cloud provider. You are no longer required to update software, maintain the servers, or make sure the hardware is working properly.
What kinds of information can be stored in the cloud?To store data, including files, business data, videos, or photographs, cloud storage uses remote servers. Users use an internet connection to upload data to servers, where it is stored on a virtual machine on a physical server.
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4.
In a TV picture tube, an electron in the beam is
accelerated by a potential difference of 20,000V.
Then it passes
through a region of transverse
magnetic field where it moves in a circular arc
with radius 12cm. What is the magnitude of the
field?
The magnitude of the magnetic field is 1.50 x 10^-3 T.
Magnitude of field calculation.
The force on a charged particle moving through a magnetic field is given by the equation:
F = qvB sin(theta)
where F is the force, q is the charge on the particle, v is the velocity of the particle, B is the magnetic field strength, and theta is the angle between the velocity vector and the magnetic field vector.
In this case, the electron is moving in a circular arc, which means that the force on the electron is directed inward toward the center of the circle, and is equal to the centripetal force:
F = mv^2 / r
where m is the mass of the electron, v is the velocity of the electron, and r is the radius of the circular arc.
We can equate these two forces and solve for the magnetic field strength:
mv^2 / r = qvB sin(theta)
Simplifying and rearranging:
B = mv / (qr) * 1/sin(theta)
To find the velocity of the electron, we can use the equation for the kinetic energy of a charged particle:
KE = 1/2 mv^2 = qV
where KE is the kinetic energy of the electron, q is the charge on the electron, and V is the potential difference that the electron was accelerated through.
Solving for v:
v = sqrt(2qV/m)
Plugging in the given values:
V = 20,000 V
m = 9.11 x 10^-31 kg
q = -1.6 x 10^-19 C
v = sqrt(2(-1.6 x 10^-19 C)(20,000 V) / 9.11 x 10^-31 kg) = 2.43 x 10^7 m/s
Now we can plug in the values for m, q, v, r, and theta (which is 90 degrees since the velocity vector is perpendicular to the magnetic field vector) to find the magnetic field strength:
B = (9.11 x 10^-31 kg)(2.43 x 10^7 m/s) / ((-1.6 x 10^-19 C)(0.12 m)) * 1/sin(90 degrees) = 1.50 x 10^-3 T
Therefore, the magnitude of the magnetic field is 1.50 x 10^-3 T.
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At the initial height of 40cm and temperature of 25°C, what change in temperature (AT) is needed for the liquid to rise to a height of 49cm?
Answer:
The answer to your problem is, The change in temperature required is ΔT = ΔV/Vγ
Explanation:
ΔT = ΔV/Vγ
ΔV = 49 - 40 = 9cm
V = 40 cm
γ is unknown since it cannot be calculated due to error in values.
Thus the answer to your problem is, The change in temperature required is ΔT = ΔV/Vγ
A lizard accelerates from 2 m/s to 10 m/s in 4 seconds. What is the lizard’s average acceleration?
Hello and regards emmateddyafton94.
Answer:The acceleration of the lizard that has speeds between 2 m/s and 10 m/s, in a time of 4 seconds, is 2 m/s².
Explanation:It is an exercise in rectilinear motion uniformly accelerated (MRUA) is a type of movement in a straight line in which an object moves with a constant acceleration. This type of movement is common in everyday life, such as when an object falls due to the force of gravity or when a car moves in a straight line and accelerates at a constant speed.
In the MRUA, the speed of the object changes at a constant rate in each unit of time. This means that acceleration is the amount of change in velocity that occurs in each second, and it is constant throughout the motion. Acceleration is measured in units of length per unit of time squared (for example, meters per second squared).
The fundamental formula of the MRUA is:
d = v₀ × t + 1/2 a × t²Where:
d is the distance traveled by the object.V₀ is the initial velocity of the object (i.e. its velocity at the time it started moving).a is the acceleration of the object (constant)t is the time elapsed since the start of the movement.We now know that the data is:
Vf = Final speed = 10 m/sVo = initial velocity = 2 m/st = time = 4 sBut since they are asking us to calculate the acceleration, we clear the formula:
a = (Vf - V₀) / tWhere:
a is the acceleration of the object (constant)Vf is the final velocity of the objectV₀ is the initial velocity of the objectt is the time elapsed since the start of the movement.This formula shows that the acceleration is equal to the difference between the final velocity and the initial velocity of the object, all divided by the elapsed time. It is important to note that final velocity and initial velocity must be in the same units (for example, meters per second) and that time must be in units of time (for example, seconds).
We substitute data in the formula, and calculate the acceleration:
a = (Vf - V₀)/t
a = (10 m/s - 2 m/s)/(4 s)
a = 2 m/s²
The acceleration of the lizard that has speeds between 2 m/s and 10 m/s, in a time of 4 seconds, is 2 m/s².
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Answer:
The lizard's average acceleration is 2 m/s².
Explanation:
The average acceleration of the lizard can be calculated using the formula:
[tex]\sf\qquad\dashrightarrow a = \dfrac{(V_f - V_o)}{t}[/tex]
where:
a is the accelerationVf is the final velocityVo is the initial velocityt is the timePlugging in the given values, we get:
[tex]\sf\qquad\dashrightarrow a = \dfrac{(10\: m/s - 2\: m/s)}{4\: sec}[/tex]
[tex]\sf\qquad\dashrightarrow a = \boxed{\bold{\:\:2\: m/s^2\:\:}}[/tex]
Therefore, the lizard's average acceleration is 2 m/s².
The image above shows a magnetized object.
True
False
Indeed, a magnetised object with a north and south pole can be seen in the above photograph.
What is something that has magnetic north and south poles?Any object that creates a magnetic field of its own and interacts with other magnetic fields is a magnet. A magnet has two poles, the north pole and the south pole. Field lines that begin at the north pole and end at the south pole of a magnet are used to show the magnetic field.
What do the magnet's north and south poles represent?When hanging in the magnetic field of the Earth, a bar magnet automatically points northward and southward. A north magnetic pole is any pole that seeks the north, such as the north-seeking pole of this type of magnet.
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Question 1
Given an object's momentum and velocity, which equation can be used to
calculate the object's mass?
V
○ A. m-p
B. m=
vp
1
C. m-P
D. m-pv
Answer:
Explanation:
m=p/v
where m is mass, p is momentum and v is velocity
A man has to push his boat on the shore across the mud to get to the water. The coefficient of friction between the boat and the mud is given by μ = 0.500. If the boat has a mass of 50 kg, calculate the magnitude of the force of friction acting on the boat
The magnitude of the force of friction acting on the boat is 245.25 N.
How do you determine the amount of friction energy being applied to?F = mg sin - kmg cos is the formula for the component of the total force down the slope.
The following algorithm can be used to determine the amount of friction the boat is experiencing:
F friction = friction coefficient * normal force
normal force=weight of the boat
=m *g
where m is the mass of the boat and g is the acceleration due to gravity (9.81 m/s²).
Therefore, the force of friction on the boat is:
F friction = μ * m * g
Substituting the given values, we get:
F friction = 0.500 * 50 kg * 9.81 m/s² = 245.25 N
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Someone who fears their actions or behaviors Will support negative ideas about a group to which they belong is experiencing.
A) cognitive dissonance
B) group polarization
C) misperception
D) stereotypes threat
Suppose the input piston of a hydraulic jack has a diameter of 3 cm and the load piston a diameter of 24 cm. The jack is being used to lift a car with a mass of 1700 kg.
(a) What is the area of the input and load piston in square centimeter? (A = πr^2)
(b) What is the ratio of the area of the load to the area of the input piston?
(c) What is the weight of the car in newtons? (W = mg)
(d) What force must be applied to the input piston to support the car?
The area of the input and load piston is [tex]7.07 cm^2[/tex] and [tex]452.16 cm^2[/tex], the ratio of the area of the load to the input piston is 63.95, the weight of the car is 16,660N, the force must be applied to the input is 260.15N.
Given the diameter of hydraulic jack (d1) = 3cm
The diameter of load piston of jack (d2) = 24cm
The mass of jack that is being used to lift a car (m) = 1700 kg.
We know that pressure is calculated as force per unit area such that: P = F/A where F is force applied and A is area
(a)Let The area of the input piston is = A1
Then [tex]A1 = \pi r1^2 = \pi * (d1/2 cm)^2 = \pi * (1.5)^2 = 7.07 cm^2.[/tex]
Let The area of the load piston is = A2
Then [tex]A2 = \pi r2^2 = \pi * (d2/2)^2 = \pi * (12 cm)^2 = 452.16 cm^2.[/tex]
(b) The ratio of the area of the load to the area of the input piston = A2/A1
ratio = 452.16 / 7.07 = 63.95
(c) The weight of the car in newtons is W = mg
[tex]W = 1700 kg * 9.81 m/s^2 = 16,660N.[/tex]
(d) The force must be applied to the input piston to support the car = F1
The force applied at the load piston = F2 = W
We know that pressure exerted at both ends of piston is same, so P1 = P2 such that P1 = F1/A1 and P2 = F2/A2
F1 = F2 * A1/A2 = 16,660/63.95 = 260.15N
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A body of mass 3.0kg moves with a velocity 10m/s calculate the moment of the body
In this case, the body has a mass of [tex]3.0[/tex] kg and is moving with a velocity of [tex]10 m/s[/tex]. the moment of the body is [tex]30 kg m/s.[/tex]
What is the momentum?The moment of a body (also known as its momentum) is defined as the product of the body's mass and velocity.
In this instance, the body weighs 3.0 kilogrammes and is travelling at a speed of 10 m/s.
The formula to calculate the moment of the body is:
momentum = mass x velocity
Plugging in the given values, we get:
momentum [tex]= 3.0 kg \times 10 m/s[/tex]
Solving the above expression, we get:
momentum = [tex]30 kg m/s[/tex]
Therefore, the moment of the body is [tex]30[/tex] kg m/s.
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a standing wave is formed by waves of frequency 256hz.the speed of the wave is 128m/s.what is the distance between the nodes
Answer:
V = f * λ Velocity = frequency * wavelength
λ = V / f = 128 m/s / 256 / s= .5 m is the wavelength
There will be nodes at o, λ/2, λ, 3λ/2 or at intervals of λ/2
The distance between nodes is ".25 m"
Find the y-component of this
vector:
12.1 m
48.4°
The y-component of the vector is approximately 9.029 m.
How to find the y-component?In order to determine the y-component of this vector, we must first acknowledge that the information provided is a polar form of the vector, with 12.1 m representing its magnitude and 48.4° representing its angle with the positive x-axis.
The formula for this vector's y-component is as follows:
y = r sin θ
where r is the magnitude of the vector and θ is the angle that the vector makes with the positive x-axis.
In this case, r = 12.1 m and θ = 48.4°, so we have:
y = 12.1 m * sin(48.4°)
y ≈ 9.029 m
Therefore, the y-component of the vector is approximately 9.029 m.
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A billiard ball of mass 0.28 kg hits a second, identical ball at a speed of 8.6 m/s
and comes to rest as the second ball flies off. The collision takes 250 μs.
What is the average force on the first ball?
What is the average force on the second ball?
The average force on the first ball = - 272.8 N.
The average force on the second ball is 9,568 N, and it acts in the direction of its motion.
What is the principle of conservation?the principle of conservation of momentum, which states that the total momentum of a closed system remains constant if no external forces act on it. In this case, the two billiard balls can be considered as a closed system.
Let's define some variables:
m = (mass of each ball)
v1 = (initial velocity of the first ball)
v2 = (final velocity of the second ball)
t = 250 μs = 0.00025 s (duration of the collision)
According to the conservation of momentum, the total momentum before the collision is equal to the total momentum after the collision:
m * v1 = m * v2
Solving for v2, we get:
v2 = v1 * (m/m) = v1
This indicates that the second ball departs in the opposite direction of the first ball but with the same velocity. As a result, the system's total momentum is preserved.
The impulse-momentum theorem states that the impulse (change in momentum) is equal to the average force multiplied by the duration of the collision. We can use this to determine the average force on the first ball:
F1 * t = m * (v2 - v1)
Substituting the values we know, we get:
F1 * 0.00025 = 0.28 * (-8.6)
Solving for F1, we get:
F1 = - 272.8 N
The first ball's force is acting in the opposite direction of its initial velocity when the sign is negative.
To find the typical power on the subsequent ball, we can utilize a similar recipe:
F2 * t = m * (v2 - v1)
Substituting the values we know, we get:
F2 * 0.00025 = 0.28 * (v2 - 0)
Since we know that v2 = 8.6 m/s, we can solve for F2:
F2 = (0.28 * 8.6) / 0.00025
F2 = 9,568 N
Therefore, the average force on the second ball is 9,568 N, and it acts in the direction of its motion.
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In some ways, the Hubble Space Telescope could be considered what type of science fiction device?
O
a freeze-ray gun
a time travel machine
a matter transporter
a replicator
Answer:
Time Travel Machine
Explanation:
The Hubble Space Telescope can look at galaxies that are many light years away. If it captured an image of a star that was 5 light years away, then that means it took light 5 years to reach the lens of the telescope. So, the image we see is what that star looked like 5 years ago. In other words, it is a glimpse of the past.
3. A 0.060 kg tennis ball traveling at 12 m/s is[returned by Venus. It leaves her racket with a velocity of
35 m/s in the opposite direction from which it came.
a) what is the change in momentum of the tennis ball?
b) if the 0.060 kg ball is in contact with the racket for 0.02 s, what force was applied to the ball?
The initial momentum of the ball is p₁ = m₁v₁ = (0.060 kg)(12 m/s) = 0.72 kg•m/s, and the final momentum of the ball is p₂ = m₂v₂ = (0.060 kg)(-35 m/s) = -2.1 kg•m/s. Therefore, the change in momentum is Δp = p₂ - p₁ = -2.1 kg•m/s - 0.72 kg•m/s = -2.82 kg•m/s.
What is the law of conservation of momentum and how is it related to this problem?The law of conservation of momentum states that the total momentum of a closed system is conserved if there are no external forces acting on the system.
In this problem, the system consists of the tennis ball and Venus' racket, and since there are no external forces acting on the system, the initial momentum of the ball must be equal to the final momentum of the ball and racket system.
Why is the force calculated in part b negative?The force calculated in part b is negative because it is in the opposite direction to the motion of the ball. The negative sign indicates that the force is acting in the direction opposite to the motion of the ball.
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The momentum of a 2.5 kg hammer with a speed of 6 m/s has a downward momentum moving towards a nail. The hammer hits the nail and bounces off at 2.0 m/s and the nail is in contact with the nail for 0.002 seconds. What is the average force the nail exerts on the hammer? How could you use force vs. time to solve this problem?
The average force is equal to the area under the curve of force versus time divided by the time of contact between the hammer and the nail.
The equation can be used to determine the average force the nail applies to the hammer.
[tex]F = \frac{mv}{t}[/tex], where m is the hammer's mass, v is its speed, and t is the time at which it made impact with the nail. The average force in this situation is given by:
[tex]F = \frac{(2.5 kg)(6 m/s - 2.0 m/s)}{(0.002 s)}\\ F= 4500 N.[/tex]
To solve this problem using force vs. time, you would need to plot a graph of force versus time, with the time of contact between the hammer and the nail representing the x-axis and the force exerted on the hammer by the nail representing the y-axis. The force exerted on the hammer increases from 0 to 4500 N as the hammer moves from rest to its maximum velocity. The average force is equal to the area under the curve of force versus time divided by the time of contact between the hammer and the nail.
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1. Determine the temperature change that occurs when 2750 J of heat is
applied to 85.45 g of iron.
When 2750 J of heat are delivered to 85.45 g of iron, the resultant temperature change is 17.6 °C.
Which natural law and the first law of thermodynamics are the same?first rule. The law of conservation of energy has been thermodynamically modified to form the first law of thermodynamics. The conservation law states that energy can only be transformed from one form to another, not created or destroyed, which keeps the total energy of an isolated system constant.
q = mcΔT
where T is the temperature change, q is the heat energy, m is the mass, c is the specific heat capacity.
0.45 J/g°C is the specific heat capacity of iron. We can plug in the values given in the problem to find the temperature change:
q = mcΔT
2750 J = (85.45 g)(0.45 J/(g·°C))(ΔT)
ΔT = 17.6 °C
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define dispersion light
Answer:
Explanation:"The phenomenon of splitting of visible light into its component colours is called dispersion". Dispersion of light is caused by the change of speed of light.
Example 1
What is the power delivered to a light bulb when the circuit has a voltage drop of
120 V and produces a current of 3.0 ampere?
Answer:
360 watts
Explanation:
P =V × I
= 120×3.0
= 360
Assume Lake Erie contains 4.80 ✕ 1011 m3 of water, and assume the water's density is that of water at 20°C and 1 atm.
(a)
How much energy (in J) is required to raise the temperature of that volume of water from 11.2°C to 21.6°C?
(b)
How many years would it take to supply this amount of energy by using a power of 1,400 MW generated by an electric power plant?
.
For Part A, we can use the formula Q = mc(T'f - Ti) to calculate the energy required to raise the temperature of the water. Here, Q is the energy required, m is the mass of the water, c is the specific heat capacity of water at 20°C and 1 atm (4.184 J/g°C), T'f is the final temperature (21.6°C), and Ti is the initial temperature (11.2°C).
First, we need to find the mass of the water. Since density = mass/volume, we can rearrange the formula to get mass = density * volume. Plugging in the given values, we get:
mass = (998 kg/m^3) * (4.80 x 10^11 m^3) = 4.79 x 10^14 kg
Now, we can plug in the values into the formula above:
Q = (4.79 x 10^14 kg) (4.184 J/g°C) (21.6°C - 11.2°C) = 2.02 x 10^19 J
Therefore, it would require 2.02 x 10^19 J of energy to raise the temperature of Lake Erie from 11.2°C to 21.6°C.
For Part B, we can use the formula P = E/t to calculate the time required to supply the energy using a power of 1,400 MW. Here, P is the power in watts, E is the energy required in joules (which we found in Part A), and t is the time in seconds. Since we want the time in years, we can convert from seconds to years at the end by dividing by the number of seconds in a year (31,536,000 s).
First, we need to convert the power from MW to W:
P = 1,400 MW * (10^6 W/MW) = 1.4 x 10^9 W
Now, we can rearrange the formula to solve for t:
t = E / P = (2.02 x 10^19 J) / (1.4 x 10^9 W) = 1.44 x 10^10 s
Converting from seconds to years, we get:
t = 1.44 x 10^10 s / 31,536,000 s/year = 456.7 years (rounded to three significant figures)
Therefore, it would take approximately 457 years to supply the energy needed by using a power of 1,400 MW generated by an electric power plant.
Some zinc (density = 7100kgm³) is mixed with twice its volume of copper(density= 8900kgm³) to make brass. What is the density of brass?
The density of brass is approximately 8300 kg/m³.
What is density ?
To find the density of brass, we need to first determine the total mass and volume of the mixture.
Let's assume that we have 1 cubic meter of zinc (since the exact volume is not given, we can use any convenient value as long as we are consistent with units).
The mass of this zinc would be:
mass_zinc = density_zinc * volume_zinc = 7100 kg/m³ * 1 m³ = 7100 kg
Since we are adding twice the volume of copper, we have 2 cubic meters of copper.
The mass of this copper would be:
mass_copper = density_copper * volume_copper = 8900 kg/m³ * 2 m³ = 17800 kg
The total mass of the mixture would be:
mass_total = mass_zinc + mass_copper = 7100 kg + 17800 kg = 24900 kg
The total volume of the mixture would be:
volume_total = volume_zinc + volume_copper = 1 m³ + 2 m³ = 3 m³
Finally, we can calculate the density of brass:
density_brass = mass_total / volume_total = 24900 kg / 3 m³ ≈ 8300 kg/m³
Therefore, the density of brass is approximately 8300 kg/m³.
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if vector A and B has equal magnitude and A+B is three times larger than A-B what is the angle of A and B Search instead for if vector A and B has equal magnitude and A+B is 3 times larger than A-B what is the angle of A and B
The vectors are defined as an object containing both magnitude and direction. Vector describes the movement of an object from one point to another.the angle of A and B is θ = cos⁻¹ ((n²- 1)/(n²+ 1) ).
A vector's magnitude is defined as the length of a segment of a directed line, and the vector's direction is indicated by the angle at which the vector is inclined. A vector has a "Tail" (the point from which it begins) and a "Head" (the point from which it ends).A mathematical structure is known as a vector. In the fields of physics and geometry, it has numerous applications. We are aware that an ordered pair, like (x, y). In the process of simplifying three-dimensional geometry, the vector is a very helpful tool.
∣A+B∣=n∣A−B∣
⟹(A² + B² +2AB cos θ)=n2 (A² + B² - 2AB cos θ )
It is given that A+B
Hence cos θ= (n²- 1)/(n²+ 1)
θ = cos⁻¹ ((n²- 1)/(n²+ 1) )
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