if f(x)=4x-7 and g(x)=2x+4 evalvate f(x)+g(x) for x=-3

Answer:

x = -1.47, 1.14

Step-by-step explanation:

Quadratic Formula: [tex]x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}[/tex]

We are given a = 3, b = 1, and c = -5. Simply plug it into the Quadratic Formula:

Step 1: Plug in variables

[tex]x=\frac{-1+/-\sqrt{1^2-4(3)(-5)} }{2(3)}[/tex]

Step 2: Solve

[tex]x=\frac{-1+/-\sqrt{1+60} }{6}[/tex]

[tex]x=\frac{-1+/-\sqrt{61} }{6}[/tex]

Step 3: Plug into calculator to evaluate into decimals

You should get x = -1.46837 and 1.13504

Answer:

1.13 and -1.46

Step-by-step explanation:

Our quadratic equation is:  3x²+x-5=0

The method we will use is te dicriminant method

let Δ be the discriminant:

Δ = b²-4*a*c

61 is a positive number so we have solutions x and x':

so the two solutions are :

-1.46 and 1.13

Answer:

x = 1/3 , y = 10/3

Step-by-step explanation:

Solve the following system:

{y = x + 3 | (equation 1)

y = 7 x + 1 | (equation 2)

Express the system in standard form:

{-x + y = 3 | (equation 1)

-(7 x) + y = 1 | (equation 2)

Swap equation 1 with equation 2:

{-(7 x) + y = 1 | (equation 1)

-x + y = 3 | (equation 2)

Subtract 1/7 × (equation 1) from equation 2:

{-(7 x) + y = 1 | (equation 1)

0 x+(6 y)/7 = 20/7 | (equation 2)

Multiply equation 2 by 7/2:

{-(7 x) + y = 1 | (equation 1)

0 x+3 y = 10 | (equation 2)

Divide equation 2 by 3:

{-(7 x) + y = 1 | (equation 1)

0 x+y = 10/3 | (equation 2)

Subtract equation 2 from equation 1:

{-(7 x)+0 y = -7/3 | (equation 1)

0 x+y = 10/3 | (equation 2)

Divide equation 1 by -7:

{x+0 y = 1/3 | (equation 1)

0 x+y = 10/3 | (equation 2)

Collect results:

Answer: {x = 1/3 , y = 10/3

Answer:

[tex]\boxed{x=\frac{1}{3} }[/tex]

[tex]\boxed{y=\frac{10}{3} }[/tex]

Step-by-step explanation:

[tex]y=x+3\\y=7x+1[/tex]

Plug y as x+3 in the second equation.

[tex]x+3=7x+1\\7x-x=3-1\\6x=2\\x=\frac{1}{3}[/tex]

Plug x as 1/3 in the second equation.

[tex]y=7(\frac{1}{3} )+1\\y=\frac{7}{3}+1\\y=\frac{10}{3}[/tex]

Answer: [tex]x=0\text{ and }x=e^4[/tex]

Step-by-step explanation:

Given function: [tex]f(x) = \ln(4 - \ln(x))[/tex]

Since, [tex]\ln 0=\infty[/tex]

Here, if

[tex]f(x)\to \infty\\\Rightarrow\ 4-\ln x=0\Rightarrow\ln x=4\Rightarrow\ x=e^4\\\text{OR}\ln x=\infty\Rightarrow\ x=0[/tex]

Hence, the vertical asymptotes of f(x) are:

[tex]x=0\text{ and }x=e^4[/tex].

Using it's concept, it is found that the vertical asymptotes of the function are: [tex]\mathbf{x = 0, x = e^4}[/tex]

A vertical asymptote of a function f(x) are the values of x for which the function is outside it's domain.

For the ln function, that is, [tex]\ln{g(x)}[/tex], they are the values of x for which:

[tex]g(x) = 0[/tex]

In this problem, the function is:

[tex]f(x) = \ln{(4 - \ln{(x)})}[/tex]

For the inner function, x = 0 is a vertical asymptote, as [tex]\ln{0}[/tex] is outside the domain.

For the outer function:

[tex]4 - \ln{(x)} = 0[/tex]

[tex]\ln{(x)} = 4[/tex]

[tex]e^{\ln{(x)}} = e^4[/tex]

[tex]x = e^4[/tex]

A similar problem is given at https://brainly.com/question/23535769

Answer:

Step-by-step explanation:

m : n = 2 : 1

R (-3, 3 )  ;  x1 = -3 & y1 = 3

S(6 , -3)   ; x2 = 6 & y2 = -3

Formula for the point that divides a line m:n = [tex](\frac{mx_{2}+nx_{1}}{m+n} , \frac{my_{2}+ny_{1}}{m+n})[/tex]

[tex]Q(\frac{2*6+1*(-3)}{2+1}, \frac{2*-3 + 1*3}{2+1})\\\\\\Q(\frac{12-3}{3} , \frac{-6+3}{2+1})\\\\\\Q(\frac{9}{3} , \frac{-3}{3})\\\\[/tex]

=Q(3, -1)

Answer:

D.) (3,-1)

Step-by-step explanation:

I got it correct on founders edtell

Answer: y = 3(x - 5)² + 4

Step-by-step explanation:

Use the Vertex form:  y = a(x - h)² + k to find the a-value

Given: (x, y) =(0, 79) and (h, k) = (5, 4)

79 = a(0 - 5)² + 4

79 = 25a + 4

75 = 25a

3 = a

Input a = 3 and (h, k) = (5, 4) into the Vertex form:

y = 3(x - 5)² + 4

Sara works 46 hours per week

9 hours are overtime and 37 hours are regular time

pay rate at time and a half: 10.20∗1.5=15.30

regular hours plus overtime pay

37∗10.20=377.40

9∗15.30=137.70

Income due to tips

Total hours worked∗60per hour∗20%

46∗60∗.20=552

Weekly Income=Hourly income + tips

Weekly Income=377.40+137.70+552.00

Weekly Income=1067.10

Annual income=Weekly income∗52

Annual income=55489.20

Answer:

[tex]x=-1[/tex]

Step-by-step explanation:

[tex]2x-3x-1=0\\(2x-3x)+(-1)=0\\-x-1=0\\-x-1+1=0+1\\-x=1\\\frac{-x}{1}=\frac{1}{-1}\\ x=-1[/tex]

Complete question:

[tex] F(x) = -6x^5 + 4x^3 [/tex]

Which characteristic is correct for the function

a) odd

b) neither even nor odd

c) both even and odd

d) even

Answer:

a) odd

Step-by-step explanation:

Given the equation:

[tex] F(x) = -6x^5 + 4x^3 [/tex]

To test for even or odd let's perform the following:

F

Replace "x" with "-x"

Thus,

[tex] F(x) = -6x^5 + 4x^3 [/tex]

[tex] = -6(-x)^5 + 4(-x)^3 [/tex]

[tex] = 6x^5 + -4x^3 [/tex]

Since [tex] -6x^5 + 4x^3 [/tex] ≠ [tex]-6(-x)^5 + 4(-x)^3[/tex] the equation is not even.

Also,  the signs changed, the equation is considered to be odd.

I.e f(x) = -f(x)

Correct answer is option (a) odd

Answer:

odd

explanation:

Large-size shirts should be brought more of which is more likely to be sold.

An expression is a way of writing a statement with more than two variables or numbers with operations such as addition, subtraction, multiplication, and division.

Example: 2 + 3x + 4y = 7 is an expression.

We have,

                  Sales       Sold

Small            180          126

Medium        220          270

Large            284           315

x-large           95            135

Now,

The percentage of small size sold.

= 126/180 x 100

= 70%

The percentage of medium size sold.

= 220/270 x 100

= 81.5%

The percentage of large size sold.

= 284/315 x 100

= 90%

The percentage of x-large size sold.

= 95/135 x 100

= 70%

Thus,

Large-size shirts are sold more.

Learn more about expressions here:

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Answer:

Step-by-step explanation:

[tex] \frac{7x + 19}{(x + 1)(x + 5)} [/tex]

Multiply each term in the first parentheses by each term in second parentheses ( FOIL)

[tex] \frac{7x + 19}{x(x + 5) + 1(x + 5)} [/tex]

Calculate the product

[tex] \frac{7x + 19}{ {x}^{2} + 5x + x + 5} [/tex]

Collect like terms

[tex] \frac{7x + 9}{ {x}^{2} + 6x + 5 } [/tex]

Hope this helps...

Best regards!!

Answer:

B: X less than or equal to 12

x≤12

Step-by-step explanation:

Corey owns a 50acre vineyard

Corey wants rainfall amounts to be at most 12 inches per year

Let rainfall=x

Corey wants amount of rainfall (x) to be at most 12 inches per year

x is at most 12 inches per year

In inequality, the appropriate symbol representing “at most” is the “less than or equal to”

(≤) symbol

So, substituting the symbol

We have,

x≤12

B: X less than or equal to 12

Answer:

1

Step-by-step explanation:

identify two points on the graph:

1. (0, 4)

2. (-2, 2)

use slope formula: (y² - y¹) / (x² - x¹)

1. (2 - 4) / (-2 - 0) = -2 / -2 = 1

slope = 1

Answer:

c

Step-by-step explanation:

Answer:

B. x < -8

Step-by-step explanation:

Well first we need to get x by itself.

To do that we do 4 / -1/2 = -8

And since a negative was divided the > changes to a <.

So x<-8.

If x is less than -8 the line starts at -8 and goes to the left.

Thus,

the answer is choice b.

Hope this helps :)

Answer:

Length of hypotenuse of given triangle

= sqrt(356)   (exact value)

= 18.87 (to 2 decimal places)

Step-by-step explanation:

Using the pythagorean Theorem,

The hypotenuse

c = sqrt(a^2+b^2)

= sqrt(16^2+10^2)

= sqrt(356)   (exact value)

= 18.87 (to 2 decimal places)

The length of the hypotenuse of the right triangle is approximately

18.9 cm.

Pythagorean theorem states that for a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

We can apply this theorem only in a right triangle.

Example:

The hypotenuse side of a triangle with the two sides as 4 cm and 3 cm.

Hypotenuse side = √(4² + 3²) = √(16 + 9) = √25 = 5 cm

We have,

The length of the hypotenuse of a right triangle can be found using the Pythagorean theorem:

c² = a² + b²

where c is the length of the hypotenuse, and a and b are the lengths of the other two sides (the base and the height in this case).

Plugging in the given values, we get:

c² = 16² + 10²

c² = 256 + 100

c² = 356

c ≈ 18.9

Rounding the answer to the nearest tenth of a centimeter, we get:

c ≈ 18.9 cm

Therefore,

The length of the hypotenuse of the right triangle is approximately

18.9 cm.

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Answer:

34x - 107.

Step-by-step explanation:

5 + 2{x - 4[3x + 7(2 - x)]}

= 5 + 2[x - 4(3x + 14 - 7x)]

= 5 + 2[x - 4(-4x + 14)]

= 5 + 2(x + 16x - 56)

= 5 + 2(17x - 56)

= 5 + 34x - 112

= 34x - 107

Hope this helps!

Answer

34x - 107

Let me know if it was correct please.

Answer:

(500,0) , (300,0), (200,200) and (300,200)

Step-by-step explanation:

The region of the graph we are concerned with is that small portion which is shaded.

We need the coordinates that bounds this portion of the graph.

These coordinates are four in number and they are as identified by noticing the four points that surround the portion then making tracings from these points to the x and y axes respectively.

We proceed as follows;

The four points we are looking at in no particular order are;

(500,0) , (300,0), (200,200) and (300,200)

The points having coordinates that have y = 0 are those that are domiciled on the x-axis

We have two of these points which are on the x-axis.

Answer:

99,290

Step-by-step explanation:

99,200 + 10(18/2)

= 99,200 + 10(9)

= 99,200 + 90

= 99,290

Answer:

Height of stone face is : 56.7 ft

Step-by-step explanation:

Kindly refer to the attached image for the diagram of the given conditions and values.

Let C be the base of mountain.

D be the point from where two sightings are taken.

AB be the stone face.

Angle of elevations:

[tex]\angle BDC =35^\circ\\\angle ADC =38^\circ[/tex]

To find:

Height of stone face = ?

AB = ?

Solution:

We can use trigonometric function of tangent here in two triangles [tex]\triangle BCD\ and\ \triangle ACD[/tex]:

[tex]In\ \triangle BCD :[/tex]

[tex]tan(\angle BDC) = \dfrac{Perpendicular}{Base} = \dfrac{BC}{CD}\\\Rightarrow BC = 700 \times tan35 ..... (1)[/tex]

[tex]In\ \triangle ACD :[/tex]

[tex]tan(\angle ADC) = \dfrac{Perpendicular}{Base} = \dfrac{AC}{CD}\\\Rightarrow AC = 700 \times tan38\\\Rightarrow AB +BC = 700 \times tan38\\\\\text{Using equation (1):}\\\Rightarrow AB + 700 \times tan 35 = 700 \times tan 38\\\Rightarrow AB = 700 \times tan 38-700 \times tan35\\\Rightarrow AB = 700 \times (tan 38-tan35)\\\Rightarrow AB = 700 \times 0.081\\\Rightarrow AB = \bold{56.7}\ ft[/tex]

So, Height of stone face is : 56.7 ft

Container + cement = 78.1

Container + sand = 25.5

Difference( cement - sand) = 78.1 -25.5 = 52.6

4 x Sand = 52.6

Sand = 52.6/4 = 13.15

Container = 25.5 - 13.15 = 12.35 kg

Answer:

Step-by-step explanation:

If BD║CE then ΔADB and ΔAEC a similar triangles

so:

     [tex]\frac{AE}{AD}=\frac{AC}{AB}\\\\\frac{AE}{7}=\frac{6}{4}\\\\AE=\frac32\cdot7\\\\AE=\frac{21}2\\\\AE=10.5[/tex]

Answer:

see below

Step-by-step explanation:

Angle C is equal to the 1/2 the difference of the two arcs

C = 1/2 ( large DC - small DC)

Large DC = ( 360 - 5x - 2)   sum of a circle is 360 degrees

Small DC = 5x-2  the central angle is equal to the intercepted arc

C = 1/2 ( 360 - 5x-2 - ( 5x -2))  Angle Formed by Two Intersecting Chords

C = 1/2 ( 360 - 2 ( 5x-2))

Distributing the 1/2

C = 180 - (5x-2)

Replacing the C with 2x+7

2x+7 = 180 - (5x-2)

Add 5x-2 to each side

2x+7  +5x-2  = 180

Antonio is correct

Combine like terms

7x +5 = 180

7x = 175

Divide by 7

x =25

Then solve for A = 5x-2

A = 5*25-2

   = 125-2

   = 123

Answer:

1. Always translate the question stem, set up equations (limit the number of variables) and breakdown the question stem of possible

2. Never overlook the constraints the question provides.

Now the question stem tells us that on the

1st day Joe earned = x

2nd day = 2x

3rd day = 4x

4th day = 8x

Question stem: Did Joe earn less than $35 on the 4th day -----> 8x < 35 ----> x < 4.375

Since x is an integer, the question becomes 'Is x <= 4

Statement 1 : Joe earned more than $120 in total for the first five days he worked in December.

x + 2x + 4x + 8x + 16x > 120

31x > 120 ---> x > 3.9....

This gives us both a YES and a NO since x can be 4 or any integer greater than 4

Statement 2: Joe earned less than $148 on the 6th day he worked in December

32x < 148 ----> x < 4.625

Since x is an integer, x <=4. Sufficient.

hope this helps

-lvr

Answer:

here,

money spent in 1st year =$250

money spent in 2nd year=$295

total inflated amount=$295- $250

=$45

Then,

inflation rate= ($45/ $250)×100%

=18%

Answer:

(3, 1/2)

Step-by-step explanation:

set the equation up

x+2y=4

2x-2y=5

then solve

The correct option is B.[tex](3,\frac{1}{2})[/tex]

Given equations,

[tex]x+2y=4.....(1)\\2x-2y=5.....(2)[/tex]

The standard form for linear equations in two variables is [tex]Ax+By=C[/tex].

On comparing equation 1 and equation 2 with the standard form we get,

[tex]a_{1}=1, b_{1}=2, c_{1}=4\\a_{2}=2, b_{2}=-2,c_{2}=5[/tex]

Here,

[tex]\frac{a_{1} }{a_{2} } =\frac{1}{2} \\[/tex] and [tex]\frac{b_{1} }{b_{2} } =\frac{2}{-2} =-1[/tex]

Since [tex]\frac{a_{1} }{a_{2} } \neq \frac{b_{1} }{b_{2} }[/tex], So the given system of equation has a unique solution.

Now Adding equation 1 and 2 we get,

[tex]3x=9\\x=3[/tex]

putting the value of x in equation 1 we get,

[tex]3+2y=4\\2y=1\\y=\frac{1}{2}[/tex].

Hence the required solution of equation is [tex](3,\frac{1}{2})[/tex]. the correct option is B.[tex](3,\frac{1}{2})[/tex]

For more details follow the link:

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Answer:

720 seating arrangments

Step-by-step explanation:

There are eight people but driver is always the same so we only have to deal with combinations of the other 7 seats.

the combination of the five seats has 5! times 2 combinations for each of the 3 passengers willing to ride in the two boat seats thus the total number of different seating arrangements is 5! times 3! or 720

hope this helps :)

Using the Fundamental Counting Theorem, it is found that there are 5760 possible seating arrangements.

It is a theorem that states that if there are n things, each with [tex]n_1, n_2, \cdots, n_n[/tex] ways to be done, each thing independent of the other, the number of ways they can be done is:

[tex]N = n_1 \times n_2 \times \cdots \times n_n[/tex]

In this problem:

Hence:

[tex]N = 8 \times 6 \times 5! = 5760[/tex]

There are 5760 possible seating arrangements.

More can be learned about the Fundamental Counting Theorem at https://brainly.com/question/24314866

Answer:

b. 5 + 17i

Step-by-step explanation:

Answer:

its a! sorry im so late

Step-by-step explanation:

Answer:

[tex]\frac{5x - 8}{3}[/tex]

Step-by-step explanation:

Find the LCM of the denominators and then solve:

[tex]\frac{4x - 5}{2} - \frac{2x - 1}{6} \\\\[/tex]

[tex]\frac{4x - 5}{2} - \frac{2x - 1}{6} \\\\\frac{3(4x - 5) - 2x - 1}{6} \\\\\frac{12x - 15 - 2x - 1}{6}\\\\\frac{10x - 16}{6}\\\\ \frac{2(5x - 8)}{2 * 3} \\\\ \frac{5x - 8}{3}[/tex]

12/31/2020: During 2020, $10,000 in accounts receivable were written off. At the end of the second year of operations, Yolandi Company had $1,000,000 in sales and accounts receivable of $400,000. XYZ's management has estimated that $17,000 in accounts receivable would be uncollectible.

For the end of 2020, after the adjusting entry for bad debts was journalized, what is the balance in the following accounts:

Bad debt expense: Allowance for doubtful accounts:

For the end of 2020, what is the company's net realizable value?

Answer:

Bad debt expense  = $17000

Allowance for doubtful accounts = $17000

Company's net realizable value of accounts receivable at end of 2020 is

= $383,000

Step-by-step explanation:

From the information given :

Accounts written off in 2020 = $10,000

Accounts receivable expected to be uncollectible = $17,000

The Bad debt expense and Allowance for doubtful accounts can be computed as follows:

12/31/2020

Adjustment entry :

                                                           Debit                              Credit

Bad debt expense                             $17000

Allowance for doubtful accounts                                             $17000

Company's net realizable value of accounts receivable at end of 2020 = Closing accounts receivables - Allowance for Doubtful accounts =

Company's net realizable value of accounts receivable at end of 2020 is:

= $400,000 - $17,000

= $383,000