Answer:
833.9kg that's the answer
A baseball player hits a pop fly ball. If the ball leaves the bat at 45 m/s at an angle of 68° above the horizontal, what is the maximum height above the point of contact with the bat that the ball will reach? Ignore air resistance.
The maximum height above the point of contact with the bat that the ball would reach would be 88.72 meters
What is a projectile motion?It is the movement of any item or body when it is launched from the the earth's surface and follows any curving course while being affected by the gravitational pull of the planet.
The maximum height of the projectile motion is given by,
Maximum height = v² sin²θ / 2 g
=45² sin² 68/ 2 *9.81
=88.72 meters
Thus, the maximum height the ball would reach would be 88.72 meters
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A person kicks a soccer ball off of a 20 meter hill and it lands 17 meters away. What
would be the final horizontal velocity of the soccer ball?
the final horizontal velocity of the soccer ball is 16.53 (m/s)
Typically, horizontal velocity is defined as horizontal displacement divided by time, expressed in units like meters per second or miles per hour. Simply put, displacement is the separation of a thing from its origin. V stands for the needed soccer ball's initial horizontal velocity (in m/s). T stands for the soccer ball's time of flight, expressed in seconds. The kinematic relations that result from the data given are as follows:
22 = 0 + (1/2) *g*T^2 [g = acceleration due to gravity]
or T^2 = 44/g
or T = √(44/g)
35 = V*T
or V = 35/T
or V = 35*√(g/44)
or V = 35*√ (9.81/44) (Assumed) g = 9.81 m/s2
V = 16.53 (m/s)
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1. A UEFA BAll is vertically Thrown up with an 'ni-
tial velocity of 25mls. Calculate;
i maximum height
Answer:
maximum height,h=31.25m
Explanation:
when an object is thrown vertically upward, v=0.
using the formula, v²= u²+2gh.
since the object is thrown upwards, g= -10m/s
v²=u²-2gh
0²=25²- 2×10×h
0=625-20h
20h = 625
h=31.25m
At the mail racing championship in England, the winner moved at an average velocity of 2.4 mm/s [ford] for 140 s. Determine the winning snail's displacement during this time interval.
The displacement of the victorious snail will be 336.0mm .
The term displacement refers to a change in an object's position. It is a vector quantity and has a direction and magnitude .
We are given here,
Average velocity of snail = Δv = 2.4 mm/s
Time interval taken by snail = Δt = 140 s
The average velocity can be define as, the rate of change in displacement in the particular time interval of the object. The formula can be given as,
Δv = Δx / Δt
Where, Δv is the average velocity, Δx is the change in displacement, Δt is the time interval of an object. Unit can be written as meter/second.
Therefore, the displacement of snail during the race can be calculated by the relation i.e.
Δx = Δv × Δt
Thus , putting the values in above equation we get,
Δx = 2.4mm/s × 140s
Δx = 336.0 mm
Hence, the snail would move 336.0 mm in 140s.
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An 80.8 kg man is standing on a frictionless ice surface when he throws a 2.3 kg book at 11.8 m/s. With what velocity does the man
move across the ice?
VM= ? m/s in the opposite direction as the book
The amount of velocity does the man who standing on a frictionless ice surface move across the ice(V)= 1 m/s in the opposite direction as the book.
What is Velocity?Velocity of a particle is its speed and the direction in which it is moving.
It can also be described as the instantaneous rate of change of the particle's distance traveled.
How can we calculate the values of the velocity does the man move across the ice?To calculate the velocity we would be using the formula,
M₁U₁ + M₂U₂ = M₁V₁+ M₂V₂
Here we are given that,
Apply the law of linear momentum
Before the throw:
M₁=Man initial mass= 80kg,
U₁=Man's initial velocity = 0,
M₂=Book initial mass = 4kg,
U₂=Book's initial velocity = 0.
After the throw:
M₁=Man final mass = 80kg,
V₁=Man's final velocity = V.
M₂=Book final mass = 4kg,
V₂=Book final velocity = 20.
Now we put the values in the formula, we get,
M₁U₁ + M₂U₂ = M₁V₁+ M₂V₂
Or, (80x0) + (4x0) = (80V) + (4x20)
Or, 0=80V + 80
Or, 80V = -80
Or, V = -80/80
Or, V= -1m/s.
From the above calculation we can conclude that,
The amount of velocity does the man move across the ice(V)= 1 m/s in the opposite direction as the book
[Note: The (-)Ve sign shows that the opposite direction]
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A pebble of mass 0.05kg is thrown vertically upwards. Give the direction and
magnitude of the net force on the pebble.
(a) During its upward motion.
(b) At the highest point where it is momentarily at rest.
In each case, 0.5N of force in a downward direction
No matter which way an object is moving, gravity's acceleration always works downward. In all three scenarios, the stone is just subject to the gravitational pull. According to Newton's second rule of motion, its magnitude is as follows:
Force=ma
Where, m is a mass of the pebble and a is acceleration due to gravity
F = Net force.
M = 0.05 kg of pebble mass
a=g=10m/s^2 F=0.05 × 10=0.5N
In all three scenarios, there is a downward-moving net force of 0.5N acting on the stone.
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The speed of sound is measured to be 340 m/s on a certain day.
What is this in Kilometers per hour?? s/km/h=
Please help and explain how to do these types of problems in very confused!!!
what is the general formula for measuring [tex] \vec{B} [/tex] , i.e. , magnetic field intensity ?
tysm ;-;
Explanation:
[tex]{ \rm{ \vec{B}} = \frac{ \mu_{0}N}{l} } \\ [/tex]
N is number of turns
l is conductor length
mu_0 is permeability
[tex]{ \boxed{ \tt{ \mu_{0} = 4\pi \times {10}^{ - 7} }}}[/tex]
#include <stdio.h>
int main()
{
const int LENGTH = 10;
const int WIDTH = 5;
const char NEWLINE = '\n';
int area;
area = LENGTH * WIDTH;
printf("value of area : %d", area);
printf("%c", NEWLINE);
return 0;
}
Consider two vectors a and B and their resultant A+ B the magnitude of the vector a and b respectively 16.2 and 6 and they act at 140 each other
The magnitude of resultant vector R = A + B is 12.23 if the act at 140° to each other.
We know that,
A + B = √ ( A² + B² + 2AB cos θ )
Given that,
A = 16.2
B = 6
θ = 140°
A + B = √ ( 16.2² + 6² + ( 2 * 16.2 * 6 * cos 140° ) )
R = √ ( 262.44 + 36 - 148.91 )
R = √ 149.52
R = 12.23
The magnitude of a vector is the numeric value of a vector. It gives the individual values vectors along x, y and z axis.
Therefore, the magnitude of resultant vector is 12.23
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Imagine that a car is traveling from your left to your right at a constant velocity. Which two actions could the driver take that may be represented as (a) a velocity vector and an acceleration vector both pointing to the right and then (b) changing so the velocity vector points to the right and the acceleration vector points to the left?
Question 13 options:
(a) Push down on the brakes and then (b) push down on the accelerator.
(a) Push down on the brakes and then (b) push down on the brakes a second time.
(a) Push down on the accelerator and then (b) push down again on the accelerator a second time.
(a) Push down on the accelerator and then (b) push down on the brakes.
The two actions that the driver could take would be to (a) Push down on the accelerator and then (b) push down on the brakes, therefore the correct answer is option D.
What is Velocity?The total displacement covered by any object per unit of time is known as velocity.
When the driver pushes down on the accelerator the velocity and the acceleration would be in the same direction.
When he pushes down on the brakes the acceleration vector would point in the opposite that of velocity, therefore the correct answer is option D.
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HELP ASAP!!!!!!
If a car goes along a straight road heading east and speeds up from 45 ft/s to 60 ft/s in 5 s, calculate the acceleration.
fus 2
a=
Note: If the speed were given in miles per hour, and the time were given in minutes, you could change the minutes to a
fraction of an hour and do the problem. The answer would be in miles/h².
Answer:
3ft/s²
Explanation:
[tex]a = \frac{60 - 45}{5} = 3ft \div {s}^{2} [/tex]
A 0.15 kg arrow is shot at +44 m/s. It hits an apple (m = 0.49 kg), and goes through the apple, leaving with a velocity of +28 m/s.
What is the velocity of the apple after the arrow leaves it?
A bicycle with 26-inch diameter wheels is traveling at 20 mi/h. Find the angular speed of the wheels in rad/min.
______radians per minute.
How many revolutions per minute do the wheels make?
___revolutions per minute
A bicycle with 26-inch diameter wheels is traveling at 20 mi/h. Find the angular speed of the wheels in rad/min.
______radians per minute
___revolutions per minuteω = 1320 rad/min, Revolution per minutes = 210.084
Diameter = 24 in
Radius r = 24/2 in = 12 in = 12 × 2.54 cm = 30.48 cm = 0.3048 m
Linear Speed v= 15 mi/hr = 15 * 1609.34 / 3600 m/s = 6.7056 m/s
Angular Speed ω = v / r = (6.7056 m/s) / (0.3048 m) = 21.999945
ω = 22 rad/s = 22× 60 rad/min = 1320 rad/min
∴ 1 revolution = 2π rad
⇒1 rad = 1 / 2π rev
so 1320 rad/min = 1320 / 2π rev/min = 210.0845 rev/min
Revolution per minutes = 210.0845
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i have no question d d d d
Answer:
okay
Explanation:
why don't you have any question in this app?
Find the direction of vector A -> = ( 21m)x^ + ( -15m)y^ (in degrees)
Find the magnitude of vector A -> = (21m)x^ + (-15m)y^ (in meters)
Find the direction of vector B -> = (4.5m)x^ + (20m)y^ (in degrees)
Find the magnitude of vector B -> = (4.5m)x^ + (20m)y^ (in meters)
Find the direction of vector A-> + B -> (in degrees)
Find the magnitude of vector A-> + B -> (in meters)
Answer: ill do deeper reaseach because thats hard
Explanation:
I throw a ball straight up, It takes 4 secs to reach the highest point. How high did the ball travel?
The height reached by the ball is 78.4 m.
What is Height?Height can be defined as the vertical distance between two points.
To calculate the height reached by the ball, we use the formula below.
Formula:
H = ut+gt²/2............ Equation 1Where:
H = Height reached by the ballt = Time taken to reach the heightu = Initial velocityg = acceleration due to gravityFrom the question,
Given:
t = 4 sg = 9.8 m/s²u = 0 m/sSubstitute these values into equation 1
H = (0×4)+(9.8×4²)/2H = 9.8×8H = 78.4 mHence, the height reached by the ball is 78.4 m.
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WILL GIVE BRAINLIEST!!!!
How many revolutions around the Sun does Uranus complete by the time Jupiter finishes its orbit?
Answer:
0
Explanation:
it takes 84 years for Uranus to orbit the Sun. It only takes 12 years for Jupiter to orbit the Sun. So technically by the time that Jupiter finishes it's one, Uranus will not be able to even finish half of its orbit.
What is electronegativity and how does it relate to the bonding of atoms? Define the terms valence electron, covalent bond, ionic bond, and metallic bond in your answer.
The tendency of an atom to attract electrons (or electron density) to itself is measured by its electronegativity. It determines the distribution of the shared electrons between the two atoms in a bond. The stronger an atom's electronegativity, the more strongly it would attract electrons to its bonds.
A single electron, or one of two or more, in an atom's outer shell is known a valence electron and is responsible for the chemical characteristics of the atom.When two or more nonmetal atoms bond together via sharing valence electrons, a covalent molecule is formed i.e. Covalent bonds are formed when two nonmetal atoms share valence electrons. When two atoms start sharing electrons, covalent bonds are formed. The positively charged atomic nuclei of the atoms attract the electrons to it.The complete transfer of valence pair of electrons) between atoms is referred to as an ionic bond. It is a kind of chemical bond that produces two ions with opposite charges. In ionic bonding, the nonmetal takes the lost electrons to form a negatively charged anion while the metal loses them to become a positively charged cations.In a metallic bond, which is a specific type of chemical bond formed between positively charged atoms, a lattice of cations shares the free electrons. Ionic and covalent bonds, On the other side, develop between two distinct atoms. The main kind of chemical bond that develops between metal atoms is known as metallic bonding.To know more about electronegativity
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what is visual merchandising
Answer:Visual Merchandising is the practice in the retail industry of optimizing the presentation of product and services to better highlight their features and benefits. The purpose of such visual merchandising is to attract, engage, and motivate the customer towards making a purchase
Explanation:
u welcome
A football player has a mass of 100 kg and can accelerate at 4 m/s². How much
force does this football player apply?
Answer: F=400 N
Explanation:
F=ma ==> F=force, m=mass, a=acceleration
F=100*4
F=400 N
Select the correct answer.
In the periodic table of elements, what do all of the elements in group 2 have in
common?
4. A wave is described by the following equation: = 10i(40 − 2).
a) Identify the wavenumber and angular frequency and calculate the frequency, period, wavelength, and the speed of the wave. b) Draw the wave for t = 0.
The calculated answer is 320 cm/s.
The wave diagram is attached below.
The quantity of waves that pass a set location in a predetermined period of time is known as frequency. Therefore, if a wave passes through in half a second, the frequency is 2 per second. The frequency is 100 times per hour if it takes 1/100 of an hour. Even though the concept of frequency as it is commonly understood is based on events per second, other units of time, like minutes or hours, may also be employed.
For a wave with the equation y=Acos(kx)t,
k= 2 = 40cm² =0.157rad/cm,
v=28=50.3rad/s,
T= 1/ = 1/8Hz
=0.125s.
Wave speed = k = 0.157*50.3
= 320 cm/s
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Pleaseee help me with this question!!!!!!!
A ball is dropped vertically from 15.3 meter height. If the acceleration due to gravity is given by 9.8 ms^-2, find the time it will take for the ball to hit the ground.
The time taken for the ball to hit the ground is 1.77 s
Data obtained from the questionFrom the questionn give above, the following data were obtained:
Height (h) = 15.3 mAcceleration due to gravity (g) = 9.8 m/s²Time (t) =? How to determine the time taken to fall to the groundThe time taken for the ball to fall to the ground can be obtained as follow:
h = ½gt²
15.3 = ½ × 9.8 × t²
15.3 = 4.9 × t²
Divide both side by 4.9
t² = 15.3 / 4.9
Take the square root of both side
t = √(15.3 / 4.9)
t = 1.77 s
Thus, we can conclude that: it will take the ball 1.77 s to fall to the ground.
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Two batteries of 7 V and 13 V with the internal resistances 1 ohm and 2 ohm respectively are connected in parallel with a resistance of 12 22. Find the current through each branch of the circuit and the potential difference across 12 ohm resistance.
the current through each branch of the circuit and the potential difference across 12-ohm resistance is 0.711A
The flow of charge is the current. A component is used to measure current. Potential difference is measured between two points on either side of a component because it represents the energy transferred between two points in a circuit.
-12(I1+I2) -1I1+7=0
12(I1+I2) +1I1=7
For the loop
-12(I1+I2) -2I=13
From 1&2
2I -I1=13-7=6
I1=2I2-6
The crucial distinction between current and voltage. Current in the circuit flows due to voltage, which is the potential difference between two locations in an electric field. The term "current" refers to the rate at which electrons are moving.
I2=85/38=2.237A
I1=2I 2-6
I1=2 x 85/38-6=-1.526A
I=I1+I2=-1.526+2.237=0.711A
Potential difference across 12-ohm resistance
V=0.711 x 12=8.53 v
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Can anyone help me solve this?
A free-falling item is one that is falling solely as a result of gravity, as was discovered in the previous section of this course. A free-falling object experiences a downward acceleration of 9.8 m/s/s (on Earth).
Its acceleration due to gravity is the acceleration that an object experiences as a result of gravitational force. M/s2 is its SI unit. Gravitational acceleration is a vector, meaning it has a magnitude and a direction. The universal gravitational constant, G, is unaffected by the type of particle, the medium separating the particles, or the passage of time. Because its value is consistent throughout the cosmos, it is referred to as "universal."
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Stone Bonner throws a football pass horizontally to his teammate. How could he
increase the range the ball covers during the throw?
There is nothing he could do to increase the range because gravity is constant.
He could throw the ball from a lower height.
He could choose a a football with less mass.
He could throw the ball with a greater horizontal velocity
He can increase the range of the ball covers during the throw by throwing the ball with a greater horizontal velocity
Assuming a projectile is launched from the ground level, the range is defined as the distance between the launch point and the point where the projectile hits the ground.
Range = [tex]u^{2}[/tex] sin (2 (theta )) / g
u = initial horizontal velocity
g= acceleration due to gravity
theta = angle of velocity vector with the ground
since , initial horizontal velocity is directly proportional to the range
hence , if we increase horizontal velocity range of the projectile will also increase .
hence , correct option is d) He could throw the ball with a greater horizontal velocity
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How much tension must a cable withstand if it is used to accelerate a 1000-kg car vertically upward at 0.60 m/s2 ?
Answer:
Approximately [tex]10410\; {\rm N}[/tex] (assuming that [tex]g = 9.81\; {\rm m \cdot s^{-2}}[/tex].)
Explanation:
There are two forces on this car:
Upward tension force from the cable, andDownward weight of the car (gravitational pull.)The net force on this car would be:
[tex](\text{net force}) = (\text{tension}) - (\text{weight})[/tex].
Rearrange to obtain:
[tex](\text{tension}) &= (\text{net force}) + (\text{weight})[/tex].
Let the mass of this car be [tex]m[/tex]. The weight of the car would be [tex]m\, g[/tex].
If the acceleration of the car is [tex]a[/tex], the net force on this car would be [tex]m\, a[/tex].
Thus:
[tex]\begin{aligned}(\text{tension}) &= (\text{net force}) + (\text{weight}) \\ &= m\, a + m\, g \\ &= (m)\, (a + g) \\ &= (1000\; {\rm kg}) \, (0.60\; {\rm m \cdot s^{-2}} + 9.81\; {\rm m\cdot s^{-2}}) \\ &\approx 10410\; {\rm N}\end{aligned}[/tex].
What is the most common number of neutrons in an atom of argon?
Carbon14 has half life of 5,730 years. If an archaeological sample has only one-fourth of the radioactivity of a similar sample from today how old is the archaeological sample
The age of the sample will be 11460 years.
The half-life of C-14 = 5730 years.
The half- life time is the time taken by the object to attain its position till the half of its initial value.
i.e after 5730 years only half of the C-14 carbon will exists.
To retain one-fourth of the sample, another cycle of 5730 years is required.
This means 2 half-lives should have passed to retain one-fourth of the sample.
so to calculate it's age
[tex]\frac{t}{\frac{t}{\frac{1}{2} } }[/tex] = 2
where t = the age of the sample
with t(1/2) = the half-life time of the sample = 5470 years
2 = the number of half- lives passed
therefore
[tex]\frac{t}{5730}[/tex] = 2
t = 2*5730 = 11460 years
When only one-fourth of the sample will remain, the age of the sample will be 11460 years
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(c)
Another four students did the same experiment.
The measurements taken and the calculated values for power are given in the table.
Student
A
(ii)
B
C
D
Weight in
newtons
285
360
600
725
Time taken in Power in watts
seconds
3.8
2.4
3.4
4.0
240
480
560
580
(i)
To make a fair comparison of their powers the students kept one variable in the
experiment constant.
What variable did the students keep constant?
From the data in the table a student wrote the following conclusion.
'The greater the weight of the student the greater the power developed.'
Suggest why this conclusion may not be true for a larger group of students.
The early phases of undertaking an epidemiological, clinical, or lab study include calculating the sample size. There are ethical and methodological guidelines that should be followed when creating a scientific publication.
When it comes to making clinical judgments, two studies that used the same approach and produced equal results but had different sample sizes could provide the researcher with different information. Therefore, contrary to popular belief, samples should not be too tiny or too large in the perfect world. The primary effects of the sample size on study interpretation will be covered in this paper using clinical terminology. Although it can appear at first glance that methodological difficulties are the most important thing, particularly to clinicians.
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