What is the relationship between the distance traveled and time for an object that travels at a constant speed ?
If a bat hits a ball with 85 N of force, how much force does the ball exert on the bat?
If a bat hits a ball with 85 N of force the bat will also exert the same force
85N.
You are probably already aware of the force the ball applies to the wall when it is thrown against it. Similar to how the wall exerts a force on the ball, the ball bounces off the wall. Similar to how the earth drags you down with gravity. You might not be aware of it, but you are also pushing the planet with the same amount of power. The third law of Newton is a result of this amazing event.
Newton's Third Law states that if object A exerts a force on object B, then object B must apply a force on object A that is equal in magnitude and directed in the opposite direction.
An object interacts with another object when a push or pull is applied to it. A product of interaction is force. Frictional force, for example, falls into the category of contact force. Non-contact force, on the other hand, includes gravitational force. Newton's third rule of motion explains that when two bodies contact, they exert force on one another. This force is referred to as an action and reaction pair.
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convert these into proper Vector notation Westward velocity of 42 km/h
Postion 6.5 measured in m that is North of the refrence point.
Downward acceleration measured in m/s2 that has a magnitude of 1.9.
Proper vector notations are V = 42i km/hr, r = 6.5j m, and a = -1.9j m/s².
In physics, a vector is a quantity with both magnitude and direction. It is typically represented by an arrow whose length is proportional to the magnitude of the quantity and whose direction is the same as that of the quantity.
A) Let us assume that the west direction is the positive X-axis.
In vector notation, the X-axis is denoted by "i". So, the westward velocity of 42 km/hr will be written as
V = 42i km/hr
B) Let us assume that the North direction is the positive Y- axis.
In vector notation, the Y-axis is denoted by "j". Also, the position vector is represented by the letter 'r'. So position 6.5 measured in m, that is North of the reference point will be written as
r = 6.5j m
C) Let us assmue thaat the downward direction is negative Y-axis.
In vector notation, the Y- axis is denoted by "j". so, the downward acceleration measured in m/s2 that has a magnitude of 1.9 will be written as
a = 1.9 × (-j) m/s²
a = -1.9j m/s²
So, proper vector notations are V = 42i km/hr, r = 6.5j m, and a = -1.9j m/s².
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Girl runs 40m due south in 40 seconds,he then return to North,20m in 10 seconds,, calculate
1. average speed
2.average velocity
3.change in velocity
4.acceleration
A test car carrying a crash test dummy accelerates from 0 to 30 m/s and then crashes into a brick wall. Describe the direction of the initial acceleration vector and compare the initial acceleration vector's magnitude with respect to the crash acceleration magnitude.
Question 8 options:
The direction of the initial acceleration vector will point towards the wall, and its magnitude will be less than the acceleration vector of the crash.
The direction of the initial acceleration vector will point away from the wall, and its magnitude will be more than the acceleration vector of the crash.
The direction of the initial acceleration vector will point away from the wall, and its magnitude will be less than the vector of the crash.
The direction of the initial acceleration vector will point towards the wall, and its magnitude will be more than the acceleration vector of the crash.
The direction of the initial acceleration vector will point towards the wall, and its magnitude will be less than the acceleration vector of the crash, therefore the correct answer is option A.
What is acceleration?The rate of change of the velocity with respect to time is known as the acceleration of the object.
As given in the problem, a test car carrying a crash test dummy accelerates from 0 to 30 m/s and then crashes into a brick wall. Describe the direction of the initial acceleration vector and compare the initial acceleration vector's magnitude with respect to the crash acceleration magnitude.
Thus, the initial acceleration vector will point in the direction of the wall and be smaller than the crash's acceleration vector, therefore the correct answer is option A.
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The electric force on one of the masses is 0.6 N.
The acceleration of the mass is 0.35 m/s².
Electric force between the masses
The electric force between the masses is calculated as follows;
F = kq²/r²
where;
K is Coulomb's constantr is the distance between the chargesq is the chargeF = (9 x 10⁹ x (9.8 x 10⁻⁶)²)/(1.2²)
F = 0.6 N
Acceleration of the massThe acceleration of the mass is calculated as follows;
F = ma
a = F/m
a = (0.6 N) / (1.7 kg)
a = 0.35 m/s²
Thus, the electric force on one of the masses is 0.6 N.
The acceleration of the mass is 0.35 m/s².
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I 'm driving down the street at 15 m/s, it takes me 20 minutes to get to my destination. What was the distance to my destination?
The distance to the destination is 18,000 meters or 18 kilometers. the formula for calculating the distance is speed × Time.
Using the formula:
Distance = Speed × Time
Speed = 15 m/s (meters per second)
Time = 20 minutes
First, we need to convert the time from minutes to seconds, as the speed is given in meters per second.
1 minute = 60 seconds
Time in seconds = 20 minutes × 60 seconds/minute = 1200 seconds
Now, we can calculate the distance:
Distance = 15 m/s × 1200 seconds
Distance = 18,000 meters
So, the distance to the destination is 18,000 meters, or 18 kilometers (since 1 kilometer = 1000 meters).
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Someone pls tell me what the answer is
The distance of the ball that would land which was launched horizontally at a speed (s) of 3.4 m/s from a table that is 7.8 m tall (d) will land is 4.29m
Consider the ball moving horizontally off the table. When it moves, gravitational force acts on it pulling the ball downwards. In addition to that objects that are falling down would accelerate quickly i.e., let’s take an object falling at the speed of x, after time t it would travel at 2x, after 2t it would be 4x.
We need to find time to calculate distance by using speed equation.
For calculating time, let’s use the freefall formula,
d = 1/2 gt²
t = √(2d) / g
t = √2 (7.8)/ 9.8
t = 1.262 s
To calculate distance, we could use speed equation as we have both Time and Velocity
s = d / t
d = s t
d = 1.262 * 3.4
d = 4.29 m
Thus, the distance of the ball that would land is 4.29 m
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An electric stove is rated 1200,
240v-calculate?
(a) The current drawn is 5A.
(b) The resistance of the filament is 48Ω.
(a) The formula for power is:
P = VI
therefore, current drawn is;
[tex]I = \frac{P}{V}[/tex]
[tex]I = \frac{1200}{240}[/tex]
I = 5A
Therefore, the current drawn is 5A.
(b) Using, ohm's law:
V = IR
therefore, resistance of the filament is:
[tex]R = \frac{V}{I}[/tex]
[tex]R = \frac{240}{5}[/tex]
R = 48Ω
Therefore, the resistance of the filament is 48Ω.
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100 Points!
A projectile is fired in the earth's gravitational field with a horizontal velocity of v=9.00 m/s. How far does it go in the horizontal direction in 0.550s? Show your work.
B) How far does the projectile go in the vertical direction in 0.550s. Show your work
Answer:
A) 4.95 m
B) 1.48225 m
Explanation:
Constant Acceleration Equations (SUVAT)
[tex]\boxed{\begin{array}{c}\begin{aligned}v&=u+at\\\\s&=ut+\dfrac{1}{2}at^2\\\\ s&=\left(\dfrac{u+v}{2}\right)t\\\\v^2&=u^2+2as\\\\s&=vt-\dfrac{1}{2}at^2\end{aligned}\end{array}} \quad \boxed{\begin{minipage}{4.6 cm}$s$ = displacement in m\\\\$u$ = initial velocity in ms$^{-1}$\\\\$v$ = final velocity in ms$^{-1}$\\\\$a$ = acceleration in ms$^{-2}$\\\\$t$ = time in s (seconds)\end{minipage}}[/tex]
When using SUVAT, assume the object is modeled as a particle and that acceleration is constant.
Consider the horizontal and vertical motion of the projectile separately.
Part AThe horizontal component of velocity is constant, as there is no acceleration horizontally.
Resolving horizontally, taking → as positive:
[tex]u=9.00\quad v=9.00 \quad a=0\quad t=0.550[/tex]
[tex]\begin{aligned}\textsf{Using} \quad s & = \left(\dfrac{u+v}{2}\right)t:\\\\s&= \left(\dfrac{9+9}{2}\right)(0.550)\\s&= (9)(0.550)\\ \implies s&= 4.95\:\sf m\\\end{aligned}[/tex]
Part BAs the projectile is fired horizontally, the vertical component of its initial velocity is zero.
Acceleration due to gravity = 9.8 ms⁻²
Resolving vertically, taking ↓ as positive:
[tex]u=0\quad a=9.8\quad t=0.550[/tex]
[tex]\begin{aligned}\textsf{Using} \quad s & = ut+\dfrac{1}{2}at^2:\\\\s&= (0)(0.550)+\dfrac{1}{2}(9.8)(0.550)^2\\s&= 0+(4.9)(0.3025)\\\implies s&= 1.48225\:\sf m\\\end{aligned}[/tex]
Calculate the frequency of this radiation.
The frequency of a radiation that has a wavelength of 9.17 × 10-⁷m is 3.27 × 10¹⁴ Hz.
How to calculate frequency?The frequency of a radiation can be calculated by dividing the velocity of the radiation by the wavelength. That is;
f = v/(λ)
According to this question, some radiation detected by a thermal imaging camera during a training exercise has a wavelength of 9.17 × 10-⁷m. The frequency can be calculated as follows:
f = 3 × 10⁸m/s ÷ 9.17 × 10-⁷m
f = 3.27 × 10¹⁴ Hz
Therefore, the frequency of a radiation that has a wavelength of 9.17 × 10-⁷m is 3.27 × 10¹⁴ Hz.
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A 5.1 kg textbook is raised a distance of 21.2 cm as a student prepares to leave for school. How much work did the student do on the book ?
Work done on the book is 10.595 Joules .
Work done on the book would be equal to the Potential Energy
Work Done = Potential Energy
W = m g h
where , ' m ' represents mass of the book
' g ' stands for Acceleration due to gravity
' h ' represents the height to which the book is raised
So, according to the given question ,
m = 5.1 kg
g = 9.8 m / s ²
h = 21.2 cm
= 0.212 m
W = m g h
= 5.1 kg x 9.8 m / s ² x 0.212 m
= 10 . 595 Joules
Hence, Work done on the book is 10.595 Joules .
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At the beginning of a 3.0-h plane trip, you are traveling due north at 192 km/h. At the end, you are traveling 250 km/h in the northwest direction (45° west of north).
Find the magnitude of the change in velocity.
Find the change in direction of your velocity. Enter the angle in degrees where negative indicates north of west and positive indicates south of west.
What is the magnitude of your average acceleration during the trip?
EDIT: ANSWERED
Magnitude of the change in velocity: 177.4 km/h
Change in direction of velocity: 4.9°
Magnitude of average acceleration during trip: 59.1 km/h2
The magnitude of the change in velocity is determined as 408.94 km/h.
The change in direction of the velocity is 64.4⁰ north of west.
The magnitude of the average acceleration during the trip is 0.0105 m/s².
Magnitude of change in velocityThe magnitude of change in velocity is the resultant velocity of the plane.
v² = a² + b² - 2ab cosθ
where;
θ is the angle between the two velocities = 45 + 90 = 135v² = (192²) + (250²) - 2(192 x 250) cos(135)
v² = 167,236
v = √167,236
v = 408.94 km/h
Vertical component of the velocityvyi = 192 km/h
vy2 = 250 x sin(45) = 176.77 km/h
vy(total) = 192 km/h + 176.77 km/h = 368.77 km/h
Horizontal component of the velocityvxi = 0
vx2 = - 250 km/h x cos(45) = -176.77 km/h
Change in direction of the velocityθ = arc tan (Vy/Vx)
θ = arc tan(368.77 / -176.77)
θ = -64.4 ⁰
θ = 64.4⁰ north of west.
Acceleration of the tripa = v/t
v = 408.94 km/h = 113.6 m/s
h = 3 h = 10,800 seconds
a = (113.6 m/s) / ( 10,800 s)
a = 0.0105 m/s²
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HELP! Along the line through the centers of the Moon and the Earth, there is a point where the gravitational forces exerted by the Moon and the Earth, respectively, are equal. We consider an elementary mass located at this point. How can this state be rated? Stable equilibrium, unstable equilibrium, total mechanical energy minimum, total mechanical energy maximum or minimum
We consider an elementary mass located at this point to be in a stable equilibrium.
What is stable equilibrium?An equilibrium is said to be stable if small, externally induced displacements from that state produce forces that tend to oppose the displacement and return the body or particle to the equilibrium state.
Also a body is said to be in a stable equilibrium, if the opposing forces acting on a body are equal.
Examples of a stable equilibriuma weight suspended by a springa brick lying on a level surfacea cone resting on its baseThus, along the line through the centers of the Moon and the Earth, there is a point where the gravitational forces exerted by the Moon and the Earth, respectively, are equal. We consider an elementary mass located at this point to be in a stable equilibrium.
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Estimate the car's velocity at 4.0 s . Express your answer to two significant figures and include the appropriate units.
The most commonly used conductor in the laboratory is?
Answer:
A battery
Explanation:
A battery is the biggest conductor. I think.
physics help needed
Answer: 1 > 3 > 2
Explanation: The range will increase with the velocity. If they are all launched at the same time the ones that are launched the hardest or with the most velocity will go the furthest horizontally. But because they are all launched from the same height and the force of gravity on all three projectiles is constant (the same for all three) they will all hit the ground at the same time but different distances from the starting point.
pls pls help !!! <33
Answer: Vx is changing and Vx is greatest near the beginning of the launch.
Explanation: Think of Vx as a bullet fired from a gun. As soon as it is fired it starts to slow down so Vx is changing and at the beginning Vx has its greatest velocity because it can only go slower from there.
answers are B and C. horizontal velocity never changes so A cannot be the answer. that makes B one of the answers. I would also say that the horizontal velocity is greatest near the beginning of the launch as it just starts, since it stays at a constant pace after, so D is not an answer. hope this helps ^_^
The magnitude of the impulse on a ball bouncing off a wall is equal?
The impulse is equal to the rate of change of momentum.
What is impulse?The term impulse refers to the product of force and time. Let us recall that from Newton's law, impulse is proportional to the change in the momentum of the ball.
We can write from Newtons law;
F. t = Mv - Mu
F = force
t = time
M = mass
v = final velocity
u = initial velocity
Thus, the impulse is equal to the rate of change of momentum.
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During camp, a simple way to estimate the height of a cliff is to drop a stone from the top and hear the splash when it hits the water below. The stone takes 3.6 seconds to drop. Assume sound speed is infinite. The height of the cliff is ___ meters.
The heigth of the cliff is 63.504 m.
What is height?
Height is the vertical distance between two points.
To calculate the height of the cliff, we use the formula below.
Formula:
S = ut+gt²/2........... Equation 1Where:
S = Height of the clifft = Timeu = Initial velocityg = Accceleration.From the question,
Given:
u = 0 m/st = 3.6 sg = 9.8 m/s²Substitute these values into equation 1
S = 0×3.6+9.8×3.6²/2S = 63.504 mHence, the heigth of the cliff is 63.504 m.
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Select the correct answer.
Which physical property causes you to lean to one side when the bus you are traveling in takes a sharp turn?
A.
inertia
B.
mass
C.
speed
D.
velocity
Answer: I believe that the answer to your question is "Inertia", or A
Explanation:
ANSWER NOW PLEASE
When you are standing still on the Earth, your speed relative to the sun is approximately how many km/s.
If you were standing still on the equator of Earth you would move at nearly 1,000 miles/hour which is approximately 1,600 km/hr.
What is speed?
Speed is measured as the ratio of distance to the time in which the distance was covered.
The Earth is round and spins once every 24 hours. This spinning of the earth causes the daily motion which we feel here. If you were standing still on the equator of Earth you would move at nearly 1,600 km/hr.
Speed is a scalar quantity as it has only direction and no magnitude.
Speed is defined mathematically as distance/ time.
speed = distance/time expressed in m/s.
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Alexus was resting on the couch but then decided she needed some food. She ran at up to 15m/s, accelerating
at 3m/s² the whole time, until she got to the fridge. How far away is the fridge from the couch?
Alexus was resting on the couch but then decided she needed some food. She ran at up to 15m/s, accelerating at 3m/s² the whole time, until she got to the fridge . The fridge will be 37.5 m far away from the couch
The branch of physics that defines motion with respect to space and time, ignoring the cause of that motion, is known as kinematics. Equation of kinematics are a set of equations that can derive an unknown aspect of a body’s motion if the other aspects are provided.
given
final velocity = 15m/s
initial velocity = 0
a = 3m/s²
s = ?
a = acceleration = final - initial / time
3 = 15 - 0 / time
time = 15 /3 = 5 seconds
[tex]v^{2}[/tex] - [tex]u^{2}[/tex] = 2as
[tex]15^{2}[/tex] - 0 = 2 * 3 * s
s = 225 /6
= 37.5 m
The fridge will be 37.5 m away from the couch
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In camping, you drop a stone from the 1st spot to the lake. The splash is heard 4 seconds later. After walking, you drop a stone again at 2nd spot at the same lake. This time the splash is heard 12 seconds later. The height of the 2nd spot is ___ times the 1st spot.
A-3
B-12
C-6
D-9
The height of the 2nd spot is 3 times the height of the 1st spot (Option A)
How to determine the height of the first spotWe'll begin by obtaining the height of the first spot. This can be obtained as follow:
Time (t) = 4 seconds Velocity of sound (v) = 343 m/sHeight of first spot (x) =?v = 2x / t
343 = 2x / 4
Cross multiply
2x = 343 × 4
2x = 1372
Divide by 2
x = 1372 / 2
Height of first spot = 686 m
How to determine the height of the second spotTime (t) = 12 seconds Velocity of sound (v) = 343 m/sHeight of second spot (x) =?v = 2x / t
343 = 2x / 12
Cross multiply
2x = 343 × 12
2x = 4116
Divide by 2
x = 4116 / 2
Height of second spot = 2058 m
How to compare 2nd height with 1st height Height of 1st spot = 686 mHeight of 2nd spot = 2058 mComparison =?
Comparison = Height of 2nd spot / Height of 1st spot
Height of 2nd spot / Height of 1st spot = 2058 / 686
Height of 2nd spot / Height of 1st spot = 3
Cross multiply
Height of 2nd spot = 3 × Height of 1st spot
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The gravitational force between two objects is 3600 N.
What will be the gravitational
force between the objects the
mass of each object is reduced to one-third of its original mass?
O 400 N
O 1200 N
O 10,800 N
O 32,400 N
The gravitational force between the two objects whose mass is reduced to one-third of its original mass is 400 N
We know that,
F = G[tex]m_{1}[/tex][tex]m_{2}[/tex] / r²
F = Gravitational force
G = Gravitational constant
[tex]m_{1}[/tex], [tex]m_{2}[/tex] = Mass of two objects
r = Distance between two objects
G = 3600 N
[tex]m_{1}'[/tex] = [tex]m_{1}[/tex] / 3
[tex]m_{2}'[/tex] = [tex]m_{2}[/tex] / 3
F' = G [tex]m_{1}'[/tex] [tex]m_{2}'[/tex] / r² = G[tex]m_{1}[/tex][tex]m_{2}[/tex] / 9 r²
F' = F / 9
F' = 3600 / 9
F' = 400 N
Gravitational force is the force of attraction between two objects due to the presence of gravity.
Therefore, the gravitational force between the two objects whose mass is reduced to one-third of its original mass is 400 N
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The power in a lightbulb is given by the equation P=I^2 R, where I is the current flowing through the lightbulb and R is the resistance of the lightbulb. What is the current in a circuit that has a resistance of 25.0 Ω and a power of 30.0 W? A 0.830 A B 1,20 A C 0.910 A D 1.09 A
Answer:
Explanation:
The correct option will be the option (d) that is 1.09 A.
According to the equation given in the question:
That is; P=i^2R where I= current, R= resistance
P=30 W
R=25 ohm
30=i^2*25
I^2=30/25
I^2=1.2
I=1.09A
So, the correct answer of the given question will be 1.09A
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A kayaker needs to paddle north across a
100-m-wide harbor. The tide is going out, creating
a tidal current that flows to the east at 2.0 m/s
The kayaker can paddle with a speed of 3.0 m/s
Answer:
100
Explanation:
3-2=1
100/1=100
Ann is driving down a street at 56 km/h. Suddenly a child runs into the street. If it takes Ann 0.749 s to react and apply the brakes, how far will she have moved before she begins to slow down? Answer in units of m.
The distance travelled by Ann before she begins to slow down is 11.65 m
How do I determine the distance travelled by Ann?First, we shall enlighten ourselves on what speed is. This is given below.
Speed is the distance an object travelled per unit time. It can be expressed as:
Speed = distance / time
Finally, we can obtain the distance Ann travelled as illustrated below.
From the question given above, the following data were obtained:
Speed = 56 Km/h = 56 / 3.6 = 15.56 m/sTime = 0.749 sDistance =?Speed = distance / time
15.56 = distance / 0.749
Cross multiply
Distance = 15.56 × 0.749
Distance = 11.65 m
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A baseball player throws a ball horizontally.
Which statement best describes the ball's
motion after it is thrown? [Neglect the effect of
friction.]
The vertical speed of the ball increases and its horizontal speed remains constant as usual because air friction is being neglected.
By definition, air resistance refers to the forces that work against an object's relative motion as it travels through the atmosphere. These drag forces cause the object to move more slowly by acting in opposition to the speed of the incoming flow. Since drag is the part of the net aerodynamic force operating in the opposite direction to the direction of the movement, it differs from other resistance forces in that it directly depends on velocity.
Fluid friction includes friction in the air. These friction forces differ from the conventional model of surface friction in that they rely on velocity. Only rare examples can be dealt with analytically since the velocity dependence may be extremely intricate. Air resistance is roughly proportional to velocity and can be represented in the form of very low speeds for microscopic particles.
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An object dropped from the window of a tall building hits the ground in 12.0 s. If its acceleration is 9.80 m/s2, the height of the window above the ground is
Answer:
58.8 metres
Explanation:
using the formula
h=ut+½gt
U=0
g=9.8m/s²
t=12.0a
Hence, h= 0.5 × 9.8 × 144
h = 58.8 metres