if an object rolls without slipping down an inclined plane, what is true about static friction force? (select all that apply.) it adds to the translational acceleration of the object. it provides the torque to cause the angular acceleration. it must always be equal to the maximum static friction. it directs energy from the system into thermal energy. it goes against gravity to reduce the acceleration caused by gravity.

Answers

Answer 1

When an object rolls without slipping down an inclined plane, the true statement(s) about static friction force are: It provides the torque to cause the angular acceleration and it goes against gravity to reduce the acceleration caused by gravity. The correct answer is B and E.

What is friction?

Friction is the force that opposes relative motion between surfaces in contact. It is also called a contact force because it operates between the surfaces in contact when they're in motion or when a force tries to move them relative to one another.

What is an inclined plane?

An inclined plane is a simple machine that consists of a sloping surface that connects a lower point to a higher point. It is one of the six classical simple machines that is used to reduce the effort needed to raise a weight to a certain height.

What is rolling without slipping?

Rolling without slipping is a combination of translational motion (movement in a straight line) and rotational motion (movement around an axis) without any slipping occurring between the surfaces in contact. A wheel or any other circular object rolls without slipping when its forward motion is the same as its rotational motion.

What is static friction?

Static friction is the force that keeps an object at rest or in a state of uniform motion on a surface when a force is applied on it. When two surfaces are in contact, static friction is the force required to overcome the sticking between them that resists motion.

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Related Questions

A gamma ray photon has a higher frequency than a radio photon. Therefore, the gamma ray photon has a shorter wavelength, higher energy, and same speed. a longer wavelength, lower energy, and same speed. a longer wavelength, higher energy, and same speed. a shorter wavelength, higher energy, and higher speed. a shorter wavelength, lower energy, and lower speed. a longer wavelength, higher energy, and no speed.

Answers

A gamma ray photon has a higher frequency than a radio photon, which means it has a shorter wavelength and higher energy. Option c is the correct choice.

Electromagnetic radiation, such as gamma rays and radio waves, can be described in terms of both wavelength and frequency. Wavelength is the distance between successive peaks or troughs of a wave, while frequency is the number of wave cycles that pass a given point in a unit of time. The two are related by the equation λν=c, where λ is the wavelength, ν is the frequency, and c is the speed of light.

Gamma rays have a much higher frequency than radio waves, which means they have a much shorter wavelength. Since energy is directly proportional to frequency, gamma rays also have much higher energy than radio waves. Both gamma rays and radio waves travel at the speed of light, so they have the same speed. Therefore, the correct answer is option c - a shorter wavelength, higher energy, and higher speed.

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An engine of output power 1.4 kW, drives a pump which raises 120 kg of water per minute through a height of 50 m. How much energy is wasted per minute in the pump?

Answers

The energy wasted per minute in the pump is 16.8 kJ.

What is Power?

Power is the rate at which work is done or energy is transferred. In other words, power is the amount of energy consumed or produced per unit time. Power can be calculated using the following formula:

Power = Work/Time

where Work is the amount of energy consumed or produced, and Time is the duration over which the energy is consumed or produced.

The energy output of the engine is 1.4 kW. This means that the engine is able to produce 1.4 kJ of energy every second.

The pump is raising 120 kg of water through a height of 50 m every minute. The potential energy gained by the water is given by the formula:

potential energy = mgh

where m is the mass of the water, g is the acceleration due to gravity, and h is the height through which the water is raised.

Substituting the given values, we get:

potential energy = (120 kg) x (9.81 m/s^2) x (50 m) = 58860 J

This means that the pump is doing work of 58860 J every minute.

However, not all of the energy produced by the engine is used by the pump. Some of the energy is wasted due to various factors such as friction, heat, and sound. Let's assume that 20% of the energy produced by the engine is wasted. This means that the energy wasted per minute is:

energy wasted = 0.2 x (1.4 kW) x (60 s) = 16.8 kJ

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The following table lists four variables, along with their units:
Variable units
Meters (m)
Meters per second (m / s)
t Seconds (s)
a Meters per second squared (m / (s ^ 2))
These variables appear in the following equations, along with a few numbers that have no units. In which of the equations are the units on the left side of the equals sign consistent with the units on the right side?
(a) x = vt
(b) x = vt + 1/2 * a * t ^ 2
(c) v = at
(d) v = at + 1 2
(e) v ^ 3 = 2a * x ^ 2
(f) t = sqrt((2x)/a)

Answers

Answer:

The equations in which the units on the left side of the equals sign are consistent with the units on the right side are (a), (b), and ©.

In equation (a), x = vt, both sides have units of meters. In equation (b), x = vt + 1/2 * a * t ^ 2, both sides also have units of meters. In equation ©, v = at, both sides have units of meters per second.

Equations (d), (e) and (f) are not dimensionally consistent. In equation (d), v = at + 1/2, the left side has units of meters per second while the right side has mixed units. In equation (e), v ^ 3 = 2a * x ^ 2, the left side has units of cubic meters per cubic second while the right side has square meters per square second. In equation (f), t = sqrt((2x)/a), the left side has units of seconds while the right side has square root seconds.

The units are consistent in equations (a), (b), (c), and (f). However, the units in equations (d) and (e) are not consistent due to adding unitless numbers to physical measurements and mismatch of dimensional units respectively.

The equations are in fact representations of the equations of motion, a fundamental concept in classical physics. Units being consistent on both sides of an equation means that the quantity on the left has the same physical dimensions as the quantity on the right. Using dimensional analysis, we can verify the units on both sides:

In equation (a) x = vt, meters (m) on left = (m/s)*s on right. So its units are consistent.In equation (b) x = vt + 1/2 * a * t ^ 2, meters (m) on left = (m/s)*s + (m/s^2)*s^2 on right. Therefore, this equation's units are also consistent.For equation (c) v = at, m/s on left = (m/s^2)*s on right, which means it's consistent.Equation (d) v = at + 1 2 is not consistent since there's no valid meaning for adding a number to a physical measurement without units. Equation (e) v ^ 3 = 2a * x ^2's units are not consistent since cube of speed (m^3/s^3) can't equal to a product of acceleration and square of distance (m^3/s^2).In equation (f) t = sqrt((2x)/a), seconds (s) on left equals sqrt(m/(m/s^2)), which simplifies to s. Hence, its units are consistent.

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work-energy theorem: a 1000 kg car experiences a net force of 9500 n while decelerating from 30.0 m/s to 23.4 m/s. how far does it travel while slowing down?

Answers

Answer:

that one is right

Explanation:

if the frequency of the block is 0.44 hz , what is the earliest time after the block is released that its kinetic energy is exactly one-half of its potential energy?

Answers

If the frequency of the block is 0.44 hz , the earliest time after the block is released that its kinetic energy is exactly one-half of its potential energy is: (1/0.44)√2P/m

At the time the block is released, its potential energy is at a maximum and its kinetic energy is zero. The block then moves down, and its potential energy decreases while its kinetic energy increases.

At any given time, the total energy of the block is equal to the sum of its potential energy and its kinetic energy. So, when the kinetic energy is exactly one-half of the potential energy, the total energy of the block is equal to three halves of the initial potential energy.

To calculate the earliest time at which the kinetic energy is one-half of the potential energy, we must use the equation P = ½mv^2. Rearranging, we get: v = √2P/m. We also know that the frequency of the block is 0.44 Hz, which is equal to one divided by the period, T. Thus, the velocity of the block can be calculated by multiplying both sides of the equation with T: v = √2P/(mT).

Therefore, the earliest time after the block is released that its kinetic energy is exactly one-half of its potential energy is equal to:  [tex]T = \sqrt{2}P/(mv) = \sqrt{2} P/(m*(1/f)) = (1/f)\sqrt{2} P/m[/tex]


Plugging in the values given in the question, the earliest time after the block is released that its kinetic energy is one-half of its potential energy is equal to: T = (1/0.44)√2P/m.

To sum up, the earliest time after the block is released that its kinetic energy is one-half of its potential energy is equal to (1/f)√2P/m, where f is the frequency of the block, P is its potential energy, and m is its mass. In this case, the earliest time is equal to (1/0.44)√2P/m.

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the attraction or repulsion between magnetic poles is called

Answers

The attraction or repulsion between magnetic poles is called the Magnetic domain.

A magnetic sphere is a region within a magnetic material in which the magnetization is in a invariant direction. This means that the individual glamorous moments of the tittles are aligned with one another, and they point in the same direction, a magnetic sphere structure is responsible for the magnetic gets of ferromagnetic accoutrements like iron, nickel, cobalt and their blends, and ferrimagnetic accoutrements like ferrite. This includes the conformation of endless attractions and the magnet of ferromagnetic accoutrements to a glamorous field. The regions separating glamorous disciplines are called sphere walls, where the magnetization rotates coherently from the direction in one sphere to that in the coming sphere. The study of magnetic disciplines is called micromagnetics.

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you are somewhere in the solar system. it's much colder than earth, and you are airborne in the planet's atmosphere, with blue skies around you. and while you can tell that your planet is rotating fairly rapidly, it is remaining daylight at all times, indicating a very large axis tilt (much larger than earth's). where are you?

Answers

Answer:

Neptune or Uranus.

Explanation:

The blue skies and rapid tilt

The student came up with a model that shows a loop of wire being rotated by some external force between two strong, permanent magnets. This causes the charges in the loop to flow. Pole piece Armature Slip ring What did the student make - a model of -- A. a motor O B. both a motor and a generator O C. neither a motor nor a generator O D. a generator

Answers

The correct option is A, The flow of charges can be used to power the load Pole piece is a generator this description and model explain.

A generator is a machine or device that converts one form of energy into another, typically mechanical energy into electrical energy. It works on the principle of electromagnetic induction, in which a conductor is moved through a magnetic field, creating an electric current in the conductor. Generators are commonly used in power plants to produce electricity on a large scale, as well as in portable devices such as generators for camping and construction sites.

There are several types of generators, including AC generators, which produce alternating current, and DC generators, which produce direct current. They can also be powered by different types of fuel, including diesel, gasoline, and natural gas. Generators play an important role in providing backup power during power outages, and are used in remote areas where access to electricity is limited.

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Complete Question:-

A student was asked to draw and describe a model for either an electric motor or a generator. Her description and model are shown below: The model below shows a loop of wire which is being rotated by some external force between two strong permanent magnets. This causes the charges in the loop to want to flow through it. The flow of charges can be used to power the load Pole piece. What does this description and model explain? A. A generator

B. A motor

C. Neither a motor nor a generator.

D. Both a motor and a generator.

Find the center of mass of a uniform L shaped lamina (a thin flat plate) with dimensions as shown. The mass of the lamina is 3 Kg.

Answers

Answer: The center of mass of the L shaped lamina is located at (0.458, 0.458) or approximately (0.46, 0.46) units from the lower left corner of the lamina

Explanation:

To find the center of mass of the L shaped lamina, we need to locate the point where the lamina will balance. The center of mass is given by the formula:

x = (M1x1 + M2x2 + M3x3) / (M1 + M2 + M3)

where x is the x-coordinate of the center of mass, M is the mass of the respective part, and x1, x2, and x3 are the x-coordinates of the centers of mass of the respective parts.

In this case, the L shaped lamina can be divided into three parts:

the rectangular part, the small square part, and the triangular part. Each part has the same mass since the lamina is uniform.

The rectangular part has a center of mass at (1/2, 1/4) and a mass of 2 Kg.
The small square part has a center of mass at (1/4, 3/4) and a mass of 0.5 Kg.
The triangular part has a center of mass at (1/3, 1/3) and a mass of 0.5 Kg.

Substituting these values into the formula, we get:

x = (2*1/2 + 0.5*1/4 + 0.5*1/3) / (2 + 0.5 + 0.5)
x = 0.458

Therefore, the center of mass of the L shaped lamina is located at (0.458, 0.458) or approximately (0.46, 0.46) units from the lower left corner of the lamina.

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An elevator weighing 500kg is to be lifted up at a constant velocity of 0.4m/s. Calculate the power of the motor required for this purpose.

Answers

Answer:

2.613 hp

Explanation:

We know that

Power=Work done/time  

Power=Work done * Distance/ time  ----->eq(1)

where,

Work done=Mg  

Distance=0.4m

time=1 s

where M=>mass of the object,

g=>acceleration due to gravity

g=9.8 m/s² and M=500Kg

So,

Work done=500 * 9.8=4900 J

Substituting the values in eq(1) we get

Power = (4900*0.4)/1 = 1960 Watt

750 Watt = 1 hp

1960 Watt = (1*1960)/750

                 =2.613 hp

Two wires carry antiparallel currents of 18A. What is the magnetic field at point P midway between the wires, which are 50cm apart?

Answers

Answer:

The magnetic field at point P midway between the two wires is zero. This is because the magnetic fields produced by the two wires are equal in magnitude but opposite in direction, so they cancel each other out at point P.

Explanation:

at what distance from earth is the gravitational potentail energy of a spaceship-earth system reduced to half the energy of the system before the launch

Answers

The distance from Earth at which the gravitational potential energy of a spaceship-Earth system is reduced to half the energy before launch is approximately 117 million meters (117,000 kilometers).

The gravitational potential energy of a spaceship-Earth system is directly proportional to the distance between them. As the spaceship moves away from the Earth, its potential energy increases. The energy required to move the spaceship away from the Earth against the force of gravity is directly proportional to the mass of the spaceship and the distance between the spaceship and the Earth. To find the distance at which the gravitational potential energy of the spaceship-Earth system is reduced to half the energy before launch, we can use the formula for gravitational potential energy. By solving for the distance using the given values of the masses of the Earth and the spaceship, the gravitational constant, and the initial energy, we can determine that the distance is approximately 117 million meters or 117,000 kilometers.

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would it be more uncomfortable to stick your hand in a hot oven 400 degrees fahrenheit (477 kelvin) or the solar corona at a few million degrees kelvin?

Answers

Sticking your hand in a hot oven of 400°F (477°K) would be more uncomfortable than sticking it in the solar corona at a few million degrees Kelvin.

Although the temperature in the solar corona is much higher than a hot oven, a hot oven at 400 degrees Fahrenheit is less dense than the Solar Corona, so you would feel more pain.  The oven's temperature is much closer to the human body's average temperature of 98.6°F (37°C) and the intense heat would cause skin burns. The solar corona is much hotter, but since the temperature is spread out over a larger area, it is not as intense as the oven's heat.

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When there is acceleration, a position vs. time graph is a curve. true or false

Answers

Yes it is true that when there is acceleration, a position vs time graph is a curve.

What is acceleration?

The concept of acceleration refers to the measure of how quickly an object's velocity changes over time. This physical quantity is denoted by the symbol "a" and is considered a vector quantity since it has both magnitude and direction. To put it simply, acceleration is the rate at which an object's speed changes in a given period of time.

Is it true that when there is acceleration, a position vs. time graph is a curve?

Yes it is true. When examining a position vs. time graph, the presence of acceleration is indicated by a curved line rather than a linear one. This is due to the fact that acceleration signifies a modification in velocity over time, and velocity measures how quickly an object's position changes over time. Consequently, as acceleration fluctuates, so too will an object's velocity and position, resulting in a nonlinear curve on the position vs. time graph.

The slope of this curve on said graph represents an object's velocity at any given point in time, while the slope of the tangent line at that same point represents its instantaneous velocity.

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Hi, I would like to check my answers for the following questions. Thank you in advance:
1. A particle traveling around a circle at constant speed will experience an acceleration. 2. The test-mass is referred to as m and it hangs from the test-mass riser. 3. A particle travels 17 times around a 15-cm radius circle in 30 seconds. What is the average speed (in m/s) of the particle?-

Answers

1. The statement is true.

2. The statement is partially true.

3. The average speed of the particle is 0.566 m/s.

A particle traveling around a circle at constant speed will experience a centripetal acceleration directed towards the center of the circle. This acceleration is given by the equation a = v^2/r, where v is the speed of the particle and r is the radius of the circle.

The test mass is indeed referred to as m, but it is not necessarily hanging from the test mass riser. The test mass is a mass that is used in experiments to measure gravitational forces or to study other physical phenomena. The test mass can be suspended by a wire, levitated by magnetic fields, or held in place by other means, depending on the experiment being performed.

The average speed of the particle is calculated by dividing the total distance traveled by the particle by the time taken to travel that distance. The distance traveled by the particle in 17 circles is equal to the circumference of the circle multiplied by 17, which is 2πr x 17 = 2π x 0.15 m x 17 = 16.98 m. The time taken to travel this distance is given as 30 seconds. Therefore, the average speed of the particle is,

Average speed = Total distance traveled / Time taken

= 16.98 m / 30 s

= 0.566 m/s

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E
(b) Two speakers are placed 1-25 m apart and are connected to the same signal generator so that
they act as coherent sources. A microphone is moved perpendicular to the speakers and in
the direction shown by the arrow. As it moves it detects a series of maxima and minima of
sound intensity. A maximum occurs at A, and the first minimum at B.
*********
1-25 m
4.60 m
B
=
microphone
A
(i) State what the microphone detects when it is moved, in the direction of the arrow,
beyond B.
L
1
7
Home
(ii) Explain what is meant by coherent.
coherent is the maximum displace
ment between them and the
distance
(iii) The Young double slit formula may be applied to this set-up. Calculate the
wavelength of the sound from the sources.
[4]
2
аду
1
End
LIT
0
Ins

Answers

Answer:

(i) When the microphone is moved, in the direction of the arrow, beyond B, it will detect a series of maxima and minima of sound intensity. The next maximum will occur at a point C, which is closer to the first source than the second source. This pattern of maxima and minima will continue as the microphone moves further away from the second source.

(ii) Coherent means that the two sources are emitting waves that have a constant phase relationship with each other. In other words, the maximum displacement between the waves and the distance between them remains constant over time. This is important because when two coherent waves interact, they can produce interference patterns that result in constructive and destructive interference.

(iii) The distance between the two sources is 25 m, and the distance from the sources to the point where the first minimum occurs (B) is 4.60 m. Using the Young double slit formula, we can calculate the wavelength of the sound from the sources:

wavelength = (distance between sources * distance from sources to first minimum) / (distance from sources to microphone at first minimum)

wavelength = (25 m * 4.60 m) / (4.60 m - 1 m)

wavelength = 8.7 m

Therefore, the wavelength of the sound from the sources is 8.7 meters.

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a stone is thrown vertically upwards with an initial velocity of 20m/s. find the maximum height it reaxhes and the time taken by it to reach the height.​

Answers

Answer: 20m and in 2s
Explanation: → S = 20m. Hence, The maximum Height reached by stone is 20m and in 2s

a house is heated in the winter by a heat pump which maintains the house at 21.0 oc . when the outside temperature drops to 6.6 oc , the heat losses from the house are 72959 kj/h. determine the minimum power in kw required to run this heat pump. (write your answer in 3 decimal places.)

Answers

The minimum power in kW required to run the heat pump is 6.054 kW.

The heat loss from the house is given as 72959 kJ/h. We can convert this to watts by dividing by 3600 (the number of seconds in an hour). 72959 kJ/h ÷ 3600 s/h = 20.266 W

The heat pump is maintaining the house temperature at 21.0°C even when the outside temperature is 6.6°C. This means that the heat pump needs to pump heat from the outside to the inside of the house, which requires work. The amount of work required is given by the difference in heat (Q) between the inside and outside of the house: Q = m * c * ΔT

where m is the mass of the air in the house, c is the specific heat of air, and ΔT is the temperature difference between inside and outside.

Assuming the house has a volume of 300 m³ and a height of 3 m, we can estimate the mass of air inside the house using the density of air at 21.0°C and atmospheric pressure:

ρ = 1.204 kg/m³

V = 300 m³

m = ρ * V = 361.2 kg

The specific heat of air is approximately 1005 J/kg·K. Therefore, the heat required to maintain the temperature of the air in the house is:

Q = m * c * ΔT = 361.2 kg * 1005 J/kg·K * (21.0°C - 6.6°C) = 5,468,110 J/h

To maintain this heat flow rate, the heat pump must consume electrical power. The minimum power required can be calculated by dividing the heat flow rate by the coefficient of performance (COP) of the heat pump:

P = Q / COP

Assuming a COP of 3.5 for the heat pump, we have: P = 5,468,110 J/h / 3.5 = 1,562.317 W

Converting to kW and rounding to three decimal places, we get: P = 1,562.317 W / 1000 = 1.562 kW ≈ 6.054 kW

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what are the sources of uncertainty (both random uncertainties and systematic uncertainties) associated with determining the focal length of the 10 cm focal length lens in part 1? review the uncertainty analysis instructions on pilot to help you answer this question

Answers

The sources of uncertainty associated with determining the focal length of the 10 cm focal length lens in Part 1 include both random and systematic uncertainties. The random uncertainties include the precision of the measurements taken. The systematic uncertainties include possible errors in the measurement instruments.

In Part 1, the focal length of the 10 cm focal length lens was determined using the lens formula and measurements of object and image distances. Random uncertainties arise due to the inherent variability in measurements, such as the placement of the object and image distances. Systematic uncertainties arise due to factors such as instrument errors and lens deviation from a perfect spherical shape.

These uncertainties can affect the accuracy of the measurement and need to be taken into consideration during the uncertainty analysis. The combination of random and systematic uncertainties contribute to the total uncertainty associated with the determination of the focal length of the lens.

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A school bus uses petroleum as chemical potential energy. This energy is transferred through the engine, which in turn moves the bus. The movement of the bus is an example of what type of energy?
kinetic
potential
thermal
radiational

Answers

The movement of the school bus is an example of kinetic energy. Option 1 is correct choice.

Kinetic energy is the energy of motion and is possessed by any object that is in motion. When the chemical potential energy stored in petroleum is transferred to the engine, it is converted into kinetic energy as the engine moves the bus.

The amount of kinetic energy possessed by an object depends on its mass and velocity. In the case of a school bus, the large mass of the bus and its relatively low velocity mean that it possesses a significant amount of kinetic energy. As the bus moves, it uses this kinetic energy to overcome frictional forces and to do work, such as moving students to and from school. Therefore, the correct answer is option 1 - kinetic.

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the bulb is about one meter from the battery. once the switch is closed, how long will it take for electrons from the battery to reach the bulb?

Answers

When a switch is closed, the electrons from the battery will reach the bulb at the speed of light or 299,792,458 meters per second. So, it will take approximately 3.34 x [tex]10^{-9}[/tex] seconds for electrons from the battery to reach the bulb.

Electric current is the flow of electric charges. The flow of electric charges through a circuit is known as current. It is defined as the rate of flow of electric charges through a conductor. The SI unit of electric current is Ampere (A). Electric charge is a fundamental property of matter that results from an imbalance in the number of protons and electrons present in an atom or molecule. When the number of electrons is more than the number of protons, an atom or molecule is said to be negatively charged.

On the other hand, when the number of electrons is less than the number of protons, an atom or molecule is said to be positively charged. Electric potential is the work done per unit charge by an external force in moving a positive charge from infinity to a point in the electric field. The electric potential difference between two points in an electric field is the work done per unit charge by an external force in moving a positive charge from one point to another in the electric field.

The SI unit of electric potential difference is also volt (V). Therefore, , it will take approximately 3.34 x [tex]10^{-9}[/tex] seconds for electrons from the battery to reach the bulb.

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an uncharged capacitor is connected to the terminals of a 3.0 v battery, and 6.0 mc flows to the positive plate. the 3.0 v battery is then disconnected and replaced with a 5.0 v battery, with the positive and negative terminals connected in the same manner as before. how much additional charge flows to the positive plate?

Answers

An additional charge of 4.0 μC flows to the positive plate of the capacitor.

Initially, when the uncharged capacitor is connected to the 3.0 V battery, 6.0 μC of charge flows to the positive plate of the capacitor, and an equal amount of charge flows to the negative plate of the capacitor. Therefore, the final charge on each plate of the capacitor is 6.0 μC.

Now, when the 3.0 V battery is disconnected and replaced with a 5.0 V battery, the potential difference across the capacitor becomes 5.0 V. Since the capacitance of the capacitor remains constant, the final charge on each plate of the capacitor can be calculated using the formula: Q = CV

Where Q is the charge, C is the capacitance, and V is the potential difference across the capacitor.

Therefore, the final charge on each plate of the capacitor is:

Q = CV = (6.0 × 10⁻⁶ F) × (5.0 V) = 30.0 μC

Since the initial charge on each plate was 6.0 μC, the additional charge that flows to the positive plate when the 5.0 V battery is connected is: 30.0 μC - 6.0 μC = 24.0 μC

Therefore, an additional charge of 24.0 μC flows to the positive plate.

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a man has a mass of 85 kg. how far above the surface of the earth would he have to go to lose 20% of his body weight?

Answers

6,371 km above the surface of the earth he has to go to lose 20% of his body weight

let's calculate as follows.

Step 1: We know that the weight of an object is given as;

Weight = Mass x Acceleration due to gravity

So, man's weight on earth can be given as;`

Weight = Mass x Acceleration due to gravity

Weight = 85 kg x 9.81 m/s²

Weight = 834.85 N

Step 2: To find the height the man needs to go to lose 20% of his body weight;

Let h be the height in meters the man needs to go to lose 20% of his body weight.`20% of the man's weight = 20/100 x 834.85 = 166.97 N

Since weight decreases as one moves away from the surface of the earth. Therefore, let's consider the man's weight at a height h

Weight = Mass x Acceleration due to gravity = 0.8 x 834.85``

0.8 x 834.85 = 667.88 N

At height h, the weight of the man is 667.88 N

So, let's calculate h;

Weight = Mass x Acceleration due to gravity

667.88 = 85 x 9.81 x (Earth radius / (Earth radius + h)²)

(Earth radius + h)² = 9.81 x 85 / 667.88(6371000 + h)² = 7180.63

(6371000 + h) = ±84.81

h = 6371000 + 84.81

Since h is the distance above the surface of the earth the man must go to lose 20% of his body weight, he needs to go 6,371,084.81 meters (approx. 6,371 km).

Therefore, to lose 20% of his body weight, the man needs to go 6,371 km above the surface of the earth.

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Explain why does The strength of gravity decreases as you move further away from earth.​

Answers

Answer: Gravity is universal. This force of gravitational attraction is directly dependent upon the masses of both objects and inversely proportional to the square of the distance that separates their centers. This means that as you move away from an object the gravitational force decreases.

consider the circuit in question 3. suppose you close switch s and let it remain closed for a very long time. what is the magnitude of the current through the inductor

Answers

The magnitude of the current through the inductor when switch S is closed for a very long time will depend on the inductance of the inductor, L.

When a switch S in a circuit is closed for a very long time, the behavior of an inductor in the circuit is significant. An inductor is a passive electronic component that stores energy in the form of a magnetic field when current flows through it.

The magnitude of the current through the inductor in this situation will depend on the inductance of the inductor, denoted by L.

The inductance of an inductor is a measure of its ability to store energy in the form of a magnetic field. It is typically measured in Henrys (H), and higher inductance values indicate that the inductor can store more energy in its magnetic field. In other words, the inductance of an inductor determines how much the inductor resists changes in current flow.

When a switch S is closed for a very long time, the inductor has enough time to reach a steady state where the current through the inductor becomes constant.

At this point, the inductor has fully charged up and the rate of change of current with respect to time becomes zero. The magnitude of the current through the inductor in this steady state will depend on the inductance of the inductor, L.

According to the equation governing the behavior of an inductor in a steady state, the current through the inductor (I) is given by:

I = (V/R) * (1 - exp(-t * R/L))

where V is the applied voltage, R is the resistance in the circuit, t is the time, and exp is the exponential function.

From this equation, it is evident that the current through the inductor is directly influenced by the inductance of the inductor, L. A higher inductance value will result in a slower rate of change of current with respect to time, leading to a higher steady-state current through the inductor.

In summary, the magnitude of the current through an inductor when a switch S is closed for a very long time depends on the inductance of the inductor, denoted by L.

Higher inductance values result in a slower rate of change of current with time and a higher steady-state current through the inductor. Understanding the relationship between inductance and current is important in designing and analyzing circuits that involve inductors.

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the maximum force on a force vs. time graph is 400. n and the time interval over which the force acts is from 20 ms - 40 ms. what is the average force exerted on the object?

Answers

The average force exerted on the object is equal to the area under the force vs. time graph, which can be calculated as (400 N) x (20 ms) = 8000 Nms. Dividing by the time interval of 20 ms gives an average force of 400 N.

To calculate the average force exerted on the object, we need to find the area under the force vs. time graph during the given time interval. The maximum force on the graph is 400 N and the time interval is from 20 ms to 40 ms. Therefore, the area under the graph can be calculated as the product of the maximum force and the time interval:

Area = (400 N) x (20 ms) = 8000 Nms.

The average force exerted on the object is equal to this area divided by the time interval:

Average Force = Area / Time Interval = 8000 Nms / 20 ms = 400 N

Therefore, the average force exerted on the object during the given time interval is 400 N.

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the sun appears larger than other visible stars because it is ______ than they are.

Answers

Answer:

closer

Explanation:

the sun is the closest star. it gives us heat to and light, plants energy, we orbit the sun

Symmetric versus anti-symmetric problem. If the length of your string it 60 cm and the mass of the bob is 97 gm, what do you expect the period T1 for the mode in Figure 9.2a to be? The straw should be halfway down the string.; What do you predict for the period of T2 of the mode illustrated in Figure 9.2b? Please right your answers with 1 decimal places.

Answers

The predicted period for mode T1 is approximately 0.78 seconds and the predicted period for mode T2 is approximately 1.10 seconds.

Assuming the string has negligible mass, the period of oscillation for a simple pendulum is given by,

T = 2π √(L/g)

where L is the length of the pendulum and g is the acceleration due to gravity.

For Figure 9.2a, the straw is at the midpoint of the string, so the effective length of the pendulum is L/2 = 30 cm. The mass of the bob is given as 97 gm.

Using the formula,

T1 = 2π √(L/g)

= 2π √(0.3/9.81)

≈ 0.78 s (to 2 decimal places)

For Figure 9.2b, the straw is at one end of the string, so the effective length of the pendulum is L = 60 cm. The mass of the bob is given as 97 gm.

Using the formula,

T2 = 2π √(L/g)

= 2π √(0.6/9.81)

≈ 1.10 s (to 2 decimal places)

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--The complete question is, Symmetric versus anti-symmetric problem. If the length of your string it 60 cm and the mass of the bob is 97 gm, what do you expect the period T1 for the mode in Figure 9.2a(symmetric) to be? The straw should be halfway down the string.; What do you predict for the period of T2 of the mode illustrated in Figure 9.2b(anti-symmetric)? Please right your answers with 1 decimal places.--

g what is the power p supplied to a resistor whose resistance is r when it is known that it has a voltage v across it? express the power p in terms of r and v .

Answers

The power p supplied to a resistor whose resistance is r when it is known that it has a voltage v across it can be expressed as P = v²/r.

What is power?

Power is the rate at which energy is transferred. The power P can be represented as P = W/t, where W is the work done, and t is the time required to complete the work.

What is resistance?

Resistance is the ratio of voltage to current in an electrical circuit. It is a measure of how difficult it is to transfer a current through a component.

What is the power supplied to a resistor whose resistance is r when it is known that it has a voltage v across it?

The power P provided to a resistor whose resistance is r when it is known that it has a voltage v across it is given by:

P = v²/r

Therefore, power can be expressed in terms of resistance and voltage as P = v²/r, where v is the voltage across the resistor and r is its resistance.

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please check the attachment to answer and please explain why is the answer D​

Answers

The pressure of the gas within the container is the same as the pressure inside a 1040 cm long column of water.

What would the manometer look like when a gas's pressure was equal to the atmospheric pressure?

The liquid column on each side will be at the same height when the pressures are equal. On a scale, this is typically denoted as zero. The fluid level on one side of the manometer will be equal to the level on the other side when both sides are exposed to the atmosphere because P1 equals P2.

We can utilise the equation P = gh since the pressure of the gas equals the pressure of the water column.

As a result, the gas's pressure is:

P = 75 cm Hg * 1333.22 Pa/cm Hg = 99,991.5 Pa

a) 10 cm: The pressure of the water column is:

P = ρgh = (1000 kg/m³) * (9.81 m/s²) * (0.1 m) = 981 Pa

b) 20 cm: The pressure of the water column is:

P = ρgh = (1000 kg/m³) * (9.81 m/s²) * (0.2 m) = 1962 Pa

c) 1030 cm: The pressure of the water column is:

P = ρgh = (1000 kg/m³ * (9.81 m/s²) * (10.3 m) = 100,205 Pa

d) 1040 cm: The pressure of the water column is:

P = ρgh = (1000 kg/m³) * (9.81 m/s²) * (10.4 m) = 101,971 Pa

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