If an area has high air pressure and low humidity, what type of weather will it most likely have?

Answer:

Petroleum

Explanation:

Because Petroleum reservoirs can be depleted but something like wind energy wind will always be there

Answer: Petroleum

Explanation: Have a Good day!!

Answer:

1. result

2.strengths

3. power

4. target heartbeat

5. visualize it

6. mindfulness

7. effort and practice

tried my best not sure if #3 #5 and #7 is correct but I tried. How is it?

Answer:

i think its....A

Explanation:

Answer:

mgh = GPE

Explanation:

2.3×3.25

7.475J

Answer:

a is correct

The particles will move up and down over large areas.

Answer:

B. The particles will move up and down over small areas.

Explanation:

I just took the quiz and got 100% :)

Answer:

  about 4.74 seconds

Explanation:

The time to fall distance d from height h is given by ...

  t = √(2d/g)

  t = √(2·110 m/(9.8 m/s^2)) ≈ 4.74 s

It will take the car about 4.74 seconds to fall 110 meters to the river.

__

We assume the car's speed is horizontal, so does not add or subtract anything to/from the time to fall from the height.

Answer:

E∝A²

Energy varies as square of change in amplitude

If amplitude of 1 has energy of 2

Amplitude of 2 (double of 1) = (2x2)=4x2=8  4 times the energy at amplitude of 1.

For 8 units of amplitude change

8x8=64x2= 128  or C:

Explanation:

When the amplitude of the wave is 8 units, the corresponding energy of the wave is 128 units.

The given parameters;

The energy of a string at  a given amplitude is calculated as follows;

[tex]E = \frac{1}{2} kA^2\\\\\frac{E}{A^2} = \frac{E_1}{A_1^2}[/tex]

When the amplitude is 8, the energy of the wave is calculated as follows;

[tex]\frac{2}{1^2} = \frac{E_2}{8^2} \\\\E_2 = 2(8^2)\\\\E_2 = 2(64)\\\\E_2 = 128 \ units[/tex]

Thus, when the amplitude of the wave is 8 units, the corresponding energy of the wave is 128 units.

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Answer:

Toward the normal line

Explanation:

I had the same question on a quiz

Answer:

True

Explanation:

I just know.

Analyzing two-dimensional projectile motion is done by breaking it into two motions: along the horizontal and vertical axes.

hope it helps!!

Answer:

up and down

Explanation:

this is because they do have the correct flagellum to move to the left and to the right

Answer:

The correct option is;

Still constant

Explanation:

The relative refractive index ₁n₂ between the two medium can be as follows;

[tex]_1n_2 = \dfrac{The \ speed \ of \ light \ in \ medium \ 1}{The \ speed \ of \ light \ in \ medium \ 2} = \dfrac{c_1}{c_2}[/tex]

Therefore, given that the speed of light in medium 1 is constant and the speed of light on medium 2 is also constant, the relative refractive index ₁n₂ = c₁/c₂ is always constant.

Answer:

follow me for the answer

Answer:

18 m

Explanation:

G = Gravitational constant

m = Mass of planet = [tex]\rho V[/tex]

[tex]\rho[/tex] = Density of planet

V = Volume of planet assuming it is a sphere = [tex]\dfrac{4}{3}\pi r^3[/tex]

r = Radius of planet

Acceleration due to gravity on a planet is given by

[tex]g=\dfrac{Gm}{r^2}\\\Rightarrow g=\dfrac{G\rho V}{r^2}\\\Rightarrow g=\dfrac{G\rho \dfrac{4}{3}\pi r^3}{r^2}\\\Rightarrow g=\dfrac{4G\rho\pi r}{3}[/tex]

So,

[tex]g\propto \rho r[/tex]

Density of other planet = [tex]\rho_p=\dfrac{1}{4}\rho_e[/tex]

Radius of other planet = [tex]r_p=\dfrac{1}{3}r_e[/tex]

[tex]\dfrac{g_e}{g_p}=\dfrac{\rho_e r_e}{\rho_p r_p}\\\Rightarrow \dfrac{g_e}{g_p}=\dfrac{\rho_e r_e}{\dfrac{1}{4}\rho_e\times \dfrac{1}{3}r_e}\\\Rightarrow \dfrac{g_e}{g_p}=12\\\Rightarrow g_p=\dfrac{g_e}{12}\\\Rightarrow g_p=\dfrac{9.8}{12}[/tex]

Since the person is jumping up the acceleration due to gravity will be negative.

From kinematic equations we have

[tex]v^2-u^2=2g_es\\\Rightarrow u^2=v^2-2g_es\\\Rightarrow u^2=0-2\times -9.8\times 1.5\\\Rightarrow u^2=2\times 9.8\times 1.5[/tex]

On the other planet

[tex]v^2-u^2=2g_ps\\\Rightarrow s=\dfrac{v^2-u^2}{2g_p}\\\Rightarrow s=\dfrac{0-(2\times 9.8\times 1.5)}{2\times -\dfrac{9.8}{12}}\\\Rightarrow s=18\ \text{m}[/tex]

The man can jump a height of 18 m on the other planet.

Answer:

1.318m

Explanation:

The set up is a right angled triangle

Horizontal distance is the distance covered by the hurdler = 0.535m =adjacent

Angle of elevation = 67.9°

Height of the hurdler = opposite

Using the SOH CAH TOA identity

Using the TOA identity

Tan67.9° = opp/adj

Tan67.9 = opp/0.535

Opp = 0.535tan67.9°

Opp = 1.318m

Hence the required height is 1.318m

Answer:

The two types of biogenous sediments are calcareous ooze and siliceous ooze

Explanation:

Answer:

v = 98.1 m/s

Explanation:

We will apply the law of conservation of energy here, between peak A and peak B.

Total Energy of Ball at A = Total Energy of Ball at B

[tex]K.E_{A}+P.E_{A}=K.E_{B}+P.E_{B}\\where,\\K.E_{A} = Kinetic\ Energy\ of\ ball\ at\ Peak\ A = \frac{1}{2}mv^{2} \\K.E_{B} = Kinetic\ Energy\ of\ ball\ at\ Peak\ B = \frac{1}{2}m(0)^{2} = 0\ J (since, ball\ stops\ at\ last) \\[/tex]

[tex]P.E_{A} = Potential\ Energy\ of\ ball\ at\ Peak\ A = mgh_{A}\\P.E_{B} = Potential\ Energy\ of\ ball\ at\ Peak\ B = mgh_{B}[/tex]

[tex]\frac{1}{2}mv^{2} + mgh_{A} = 0\ J + mgh_{B}\\m(\frac{1}{2}v^{2} + gh_{A}) = mgh_{B}\\v = \sqrt{2g(h_{B}-h_{A})}\\where,\\h_{A} = height\ pf\ peak\ A = 5\ m\\h_{B} = height\ pf\ peak\ B = 10\ m\\v = \sqrt{2(9.81\ m/s^{2})(10\ m-5\ m)}\\[/tex]

v = 98.1 m/s

Ultraviolet (UV) "light" is a type of electromagnetic radiation. UV light has a shorter wavelength than visible light. ... The wavelength of violet light is around 400 nanometers (or 4,000 Å). Ultraviolet radiation oscillates at rates between about 800 terahertz (THz or 1012 hertz) and 30,000 THz.

If you're starting at the lowest frequency that our eyes can see, you're at RED light.  

Then, as you hike through higher and higher frequencies, you travel through orange light, yellow light, green light, blue light, violet light.

Suddenly, as you keep going to higher frequency, you can't see the light any more. You've crossed the line from violet to ULTRAviolet. Now your eyes don't know it's there.  The frequency is too high. (Wavelength is too short.)

Answer:

2.66secs

Explanation:

To get the time it will take to reach the ground, we will use the equation of motion;

S = ut + 1/2at²

S is the distance

u is the initial velocity

g is the acceleration due to gravity

Given

S = 30m

u = 0m/s

Let's get the acceleration

According to newton's second law;

[tex]\F_x = ma_x\\F_m - F_f = ma_x\\mgsin \theta - 0 = ma_x\\gsin\theta = a_x\\a_x = 9.8sin 60\\a_x = 9.8(0.8660)\\a_x = 8.49m/s^2[/tex]

Get the required time:

Recall that: S = ut + 1/2at²

Substitute the given parameters and find t

30 = 0(t) + 1/2(8.49)t²

30 = 4.24t²

t² = 30/4.24

t² = 7.08

t = √7.08

t = 2.66secs

Hence it take the box 2.66seconds to reach the ground

Answer:

58.8m

Explanation:

Answer:

By putting something like a sheet of glass in the water.

Explanation:

Putting a sheet of glass in the water will make the ripples move slower because the speed of a wave depends on the depth of water.

Answer:

Maximum height = 1.27 m

Explanation:

Given:

θ = 30°

Speed = 10 m/s

Find:

Maximum  height

Computation:

Maximum height = v²(sinθ)² / 2g

Maximum height = 10²(sin30)² / (2x9.81)

Maximum height = 1.27 m

Answer:

Hi... Your answer is impulse

Answer:

2/3.or 0,67

Explanation:

acceleration = Result or sum of force / the mass

a = F/m

a = (35-25)/15

a = 10/15 = 2/3 m/s²

a = 0,67 m/s²

Answer:

0.5 N

Explanation:

(0.6 kg)(9.8 m/s^2) = 5.88 N

(0.6 kg)(5 m/s^2) = 3 N

4 N - 3 N = 1 N

1 N/5.88 N = 0.17

(0.17)(3 N) = 0.51 N which rounds to 0.5 N

When a 4 N force pulls on the cart, the cart accelerates at 5 m/s². The frictional force resisting the pull is 0.5 N.

Friction is defined as the force preventing sliding solid surfaces, fluid layers, and material components from moving relative to one another. When two bodies in contact move in relation to one another, friction, a resistive force, arises. friction factors Between-body surface adhesion: When two materials are in close proximity to one another, a molecular force called adhesion is created.

(0.6 kg) (9.8 m/s²2) = 5.88 N

(0.6 kg) (5 m/s²2) = 3 N

4 N - 3 N = 1 N

1 N/5.88 N = 0.17

(0.17) (3 N) = 0.51 N ≅ 0.5 N

Thus, when a 4 N force pulls on the cart, the cart accelerates at 5 m/s². The frictional force resisting the pull is 0.5 N.

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Answer:

1 mole = 767.882 g

1 gram = 0.001 mole

Explanation:

The molar mass of CeAl₁₂O₁₉ is 770.686grams. The molar mass of a substance is the amount of substance which is present in one mole of the compound.

Molar mass of a substance is the mass in grams of one mole of the compound or chemical substance. In a chemical substance, the amount of entities which are present such as atoms, molecules, ions, is defined as a mole. A mole of any substance has 6.022 × 1023 molecules in it.

The molar mass of CeAl₁₂O₁₉  can be calculated as it is made up of three atoms which are Ce (Cerium), twelve atoms of Aluminium (Al), and nineteen atoms of O (Oxygen).

Atomic mass of Cerium = 140.116u

Atomic mass of Aluminium = 26.981539 u

The mass of 12 Aluminium atoms = 12 × 26.98 u

The mass of 12 Aluminium atoms = 323.76 u

Atomic mass of Oxygen =  15.999 u

The mass of 19 atoms of Oxygen = 303.81 u

Therefore, the mass of CeAl₁₂O₁₉ = 140.116 u + 323.76 u + 303.81 u

The molar mass of CeAl₁₂O₁₉ is 770.686 grams.

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Answer:

No not at all

Explanation:

Answer:

Hard-boiled eggs don't react well (or, depending on the perspective, react extremely well) to microwaves. Heat one up in a microwave and — assuming it doesn't burst

so yeah it does not explode

Answer:

Average speed of the car = 16.53 m.s

Explanation:

For first 5 seconds:

As the car starts from rest, so the initial speed of the car, u=0

Acceleration, a= 4 m/s^2

So, the final speed (speed at time, t=5 second)

v=u+at

v=0 + 4 x 5 = 20 m/s

Distance covered,

[tex]s=ut+\frac 1 2 a t^2 \\\\s=0+\frac 1 2 \times 4 \times 5^2[/tex]

s=50 m

As the car maintained the constant speed of 20 m/s for the next 10 seconds.

Distance traveled in 10 seconds, d=20 x 10 =200 m

For the last 4 seconds:

The car slows down at the rate of 2.0 m / s ^ 2 from the speed of 20 m/s.

As the car slows down, so the acceleration will be negative, i.e a=-2 m/s^2

[tex]s=ut+\frac 12 at^2 \\\\s=20\times 4 +\frac 12 (-2)4^2[/tex]

s=80-16=64 m.

Considering all three cases, the total distance covered=

=50+200+64=314 m

Total time= 5+10+4=19 s

So, the averate peed= Totat distance covered / total time taken

=314/19=16.53 m/s

Answer:

v=68[m/s]

Explanation:

To solve this problem we have to use the law of energy conservation, which tells us that potential energy is converted into kinetic energy.

[tex]E_{pot}=E_{kin}[/tex]

[tex]E_{pot}=m*g*h[/tex]

[tex]E_{kin}=0.5*m*v^{2}[/tex]

where:

m = mass [kg]

g = gravity acceleration = 9.81 [m/s²]

h = elevation = 236 [m]

v = velocity [m/s]

[tex]m*9.81*236=0.5*m*v^{2}\\2315.16 = 0.5*v^{2}\\v=\sqrt{4630.32} \\v=68[m/s][/tex]