If a wave of wavelength 1m and another wave of wavelength 3m are both transmitted at a velocity of 120m/s, what is the frequency difference between these signals?

Answers

Answer 1
The velocity of a wave is given by the product of its wavelength and frequency:

velocity = wavelength x frequency

Rearranging this equation, we can solve for frequency:

frequency = velocity / wavelength

For the wave with a wavelength of 1 m:

frequency1 = 120 m/s / 1 m = 120 Hz

For the wave with a wavelength of 3 m:

frequency2 = 120 m/s / 3 m = 40 Hz

The frequency difference between these two signals is the absolute value of the difference between their frequencies:

|frequency1 - frequency2| = |120 Hz - 40 Hz| = 80 Hz

Therefore, the frequency difference between these signals is 80 Hz.

Related Questions

This piece of rock had broken off a much larger rock. Maria thinks that the density of the larger rock will be the same as the density of her piece. Is she correct? Circle your answer. yes no Explain your answer.

Answers

No, she is not correct. The density of the larger rock may be different than the density of her piece, depending on the composition of the rock and how it was formed.

What is density?

Density is the measure of the mass of a substance per unit of volume. It is a physical property of a substance that can be used to identify the material. Density is calculated by dividing the mass of an object by its volume. Density is an intensive property, meaning it is independent of the size of the sample. The SI unit of density is kilograms per meter cubed (kg/m^3). Different materials have different densities, which can be compared to each other. For example, the density of water is 1 g/cm^3, while the density of lead is 11.3 g/cm^3. Density is an important physical property that is used in many scientific fields, such as physics and chemistry.

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A 5.3-cm -thick layer of oil (n=1.46) is sandwiched between a 1.5-cm -thick sheet of glass and a 2.3-cm -thick sheet of polystyrene plastic (n=1.59). How long (in ns ) does it take light incident perpendicular to the glass to pass through this 9.1- cm -thick sandwich?

Answers

Time taken to incident light perpendicular to glass to pass through this 9.1 cm thick sandwich is 0.399 ns.

How long it took to calculate:

Being aware of

Layer thickness / light speed equals the amount of time required.

Also,

V is equal to the product of the sound speed and the refractive index.

Now

T1 = 0.05*1.46/3*10^8 = 2.43*10^-10 s

t2 = 0.01*1.5/3*10^8 = 5*10^-11 s

t3 = 0.02*1.59/3*10^8 = 1.06*10^-10 s

So,

Total time is equal to 2.43*10-10, 5*10-11, and 1.06*10-10 s, or 0.399*10-9 s.

= 0.399 ns

Light Speed:

When a light beam passes through a certain media, its speed in that medium may be determined using the light speed in vacuum and the medium's refractive index. With the use of the medium's light speed, the value of the amount of time needed to travel a particular distance can be determined.

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NEED HELP ASAP
what is the maximum height achieved by a track star who goes into a long jump at 12m/s at an angle of 20.0 about the horizontal? (hint 12m/s is not the horizontal component of the velocity vector.)

Answers

11.76m is the maximum height achieved by a track star who goes into a long jump at 12m/s at an angle of 20.0 about the horizontal

Define projectile motion.

An object or particle that is projected into a gravitational field, such as from the surface of the Earth, and moves along a curved route only under the influence of gravity is said to be experiencing projectile motion.

Most calculations make the assumption that the effects of air resistance are passive and insignificant in the specific instance of Earth projectile motion. Galileo demonstrated that the curved path of objects in projectile motion is a parabola; however, in the unique situation where an object is hurled directly upwards, it may also be a straight line. Such a trajectory is a ballistic trajectory, which is the study of such movements.

v = u + at

a = g = 9.8m/s2

v = 0

u = 12 sin 20

t = 12 sin 20 /9.8 = 0.42 s

s = ut +1/2 at2

s = 12sin20 + 1/2 *9.8*0.42*0.42

s = 10.9 +.864 = 11.76m

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an electric kettle takes 2kw at 240v. Calculate the current and the resistance of the heating element

Answers

The power output is given 2000 watt and voltage is 240 v. Then the current through the heating element is 8.3 A and the resistance is 29 ohms.

What is power ?

The power used by an object is the rate of its work done or energy. It is the energy divided by time. The power output in a circuit is the product of the potential difference V and current I.

P = I V

Given,

P = 2 kw = 2000 W

v = 240 V.

Then I = P/v

I = 2000 w/240 v = 8.3 A.

According to Ohm's law, voltage v is the product of the current and resistance through the material.

hence,

V = I R

then, R = V/I

R = 240 V/8.33 A

  = 29 Ω.

Therefore, the current and resistance through the heating element are 8.3 A and 29 ohms respectively.

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Baliz help meh

The level of education that a state’s population attains directly impacts the economy. Identify which economic consequence matches which level of education.
well-paying jobs

Answers

The economic consequence matches which level of education are :

Well paying jobs - High School diploma or higher Higher tax revenues - High School diploma or higher Increased purchasing power - High School diploma or higher Failure of local businesses  - High School dropout or lower More social assistance programs - High School dropout or lower Less tax collected - High School dropout or lower

What are the economic consequences of education ?

Studies have shown that individuals with a high school diploma or higher tend to have higher incomes and greater access to well-paying jobs, which can lead to increased purchasing power and higher tax revenues for their local communities.

In contrast, individuals who have not completed high school may be more likely to struggle with unemployment or low-paying jobs, which can lead to a greater need for social assistance programs and less tax collected by local governments.

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Find the total equivalent resistance for the circuit. Req = [?] 2 9.0 V 30 Ω www 40 Ω www 50 Ω Enter 20Ω 10Ω​

Answers

The total equivalent resistance for the circuit is 35.89 Ω

How do i determine the total equivalent resistance?

First, we shall determine the equivalence resistance between 30 Ω and 40 Ω. Details below:

Resistor 1 (R₁) = 30 Ω Resistor 2 (R₂) = 40 ΩEquivalent (R) = ?

R = (R₁ × R₂) / (R₁ + R₂)

R = (30 × 40) / (30 + 40)

R = 17.14 Ω

Next, we shall determine the equivalence resistance between 20 Ω and 10 Ω. Details below:

Resistor 1 (R₁) = 20 Ω Resistor 2 (R₂) = 10 ΩEquivalent (R) = ?

R = R₁ + R₂

R = 20 + 10

R = 30 Ω

Next, we shall determine the equivalence resistance between 50 Ω and the equivalence of 20 Ω and 10 Ω (i.e 30 Ω). Details below:

Resistor 1 (R₁) = 50 Ω Resistor 2 (R₂) = 30 ΩEquivalent (R) = ?

R = (R₁ × R₂) / (R₁ + R₂)

R = (50 × 30) / (50 + 30)

R = 18.75 Ω

Finally, we shall determine the total equivalent resistance for the circuit. Details below:

Equivalence resistance between 30 Ω and 40 Ω = 17.14 ΩEquivalence resistance between 50 Ω and the equivalence of 20 Ω and 10 Ω = 18.75 ΩTotal equivalent resistance =?

Total equivalent resistance = 17.14 + 18.75

Total equivalent resistance = 35.89 Ω

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What’s the right answer for 2

Answers

The little number you see to the right of the symbol for an element is called a subscript. That number indicates the number of atoms of that element present in the compound.

To lift a box 5m in 10s, 250W of power are produced. How much force was applied?

Answers

quiero una resolución para acer esto mandame un foto

refer to the attachment and answer the question;-;​

Answers

The electric current is of two types, direct current and alternating current. Direct current do not change its direction and amperage with time whereas alternating current change with time.

What are direct current and alternating current?

Direct current (DC) is an electric current which is uni-directional, and so the flow of charge is always in the same direction. As opposed to the alternating current, the direction and amperage of direct currents do not change with time. Direct current is used in many household electronics and in all the devices which use batteries.

Alternating current is an electric current which periodically reverses its direction and change its magnitude continuously with the time in contrast to direct current, which flows only in one direction. The current produced by the generators or turbines is the AC current, as it is the current which is obtained from our home power sockets.

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Observing a set of pith balls with positive charges, how does the distance between the pith balls affect the electric electrical charge?

Answers

The electrical force between two charged objects decreases as the distance between them increases. This means that as the distance between two positively charged pith balls increases, the electrical force between them decreases. Therefore, the electrical charge on each pith ball is not affected by the distance between them. The charge on each pith ball will remain the same regardless of the distance between them. However, the electrical force between the pith balls will be weaker at greater distances, and stronger at smaller distances.

Answer:

i'm pretty sure what the other guy means is:

The greater the distance between the pith balls, the lesser the amount of electric charge that exists between them.

Explanation:

"This means that as the distance between two positively charged pith balls increases, the electrical force between them decreases"

A 75.0 kg ladder that is 3.00 m long is placed against a wall at an angle theta. The center of gravity of the ladder is at a point 1.20 m from the base of the ladder. The coefficient of static friction at the base of the ladder is 0.800. There is no friction between the wall and the ladder. What is the vertical force of the ground on the ladder?

Answers

The vertical force is given as 735.75 N

How to solve for the vertical force

Given that there is no friction existing between the wall and the ladder, we would have

w - n = 0

w is the weight of thios ladder

while N is the vertical force that acts on it

n = w

the formula for n = mg

this is mass of ladder * the gravitational constant

= 75.0 kg ladder * 9.81

= 735.75 N

written as substituting the weight of the ladder, W = 75.0 kg * 9.81 m/s^2 = 735.75 N

Therefore the vertical force is givem as 735.75 N

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A cyclist starts from rest and coasts down a 4.5 degree hill. The mass of the cyclist plus bicycle is 80 kg. The cyclist has traveled 260 m.

a) What was the net work done by gravity on the cyclist? (in J)
Express your answer using two significant figures.

b) How fast is the cyclist going? Ignore air resistance. (m/s)
Express your answer using two significant figures.

Answers

a) The net work done by gravity on the cyclist is equal to the change in the kinetic energy of the cyclist-bicycle system. Since the cyclist starts from rest, the initial kinetic energy is zero. The final kinetic energy can be calculated using the equation:

KE = (1/2)mv^2

where m is the mass of the cyclist-bicycle system and v is the final velocity of the cyclist.

The work-energy principle states that the net work done on an object is equal to its change in kinetic energy:

W_net = KE_final - KE_initial

Since the initial kinetic energy is zero, the net work done by gravity on the cyclist is equal to the final kinetic energy:

W_net = (1/2)mv^2

To calculate the final velocity, we can use the conservation of energy principle, which states that the total mechanical energy of a system is conserved:

E_i = E_f

where E_i is the initial mechanical energy and E_f is the final mechanical energy. Since the cyclist starts from rest, the initial mechanical energy is equal to the gravitational potential energy:

E_i = mgh

where h is the vertical distance the cyclist travels down the hill. We can use trigonometry to calculate the vertical distance:

h = d*sin(theta)

where d is the distance the cyclist travels and theta is the angle of the hill in radians.

Plugging in the given values:

h = 260sin(4.5pi/180) = 20.05 m

Therefore, the initial mechanical energy is:

E_i = (80 kg)(9.81 m/s^2)(20.05 m) = 15742 J

Since there is no non-conservative work done on the system, the final mechanical energy is equal to the initial mechanical energy:

E_f = E_i = 15742 J

The final mechanical energy can also be expressed as the sum of the final kinetic and potential energies:

E_f = (1/2)mv^2 + mgh

Plugging in the known values and solving for v:

(1/2)(80 kg)v^2 = 15742 J - (80 kg)(9.81 m/s^2)(20.05 m)

v = sqrt[(2(15742 J - 15686 J))/80 kg] = 7.0 m/s

Therefore, the net work done by gravity on the cyclist is:

W_net = (1/2)(80 kg)(7.0 m/s)^2 = 1960 J (to two significant figures)

b) The final velocity of the cyclist is 7.0 m/s, as calculated in part a).

How is the water cycle connected to the average temperature of the Earth's
atmosphere and the average temperature of the Earth's oceans? (This
should be in addition to what you just wrote about the Sun)
ITI

Answers

Answer:

Through the water cycle, heat is exchanged and temperatures fluctuate. As water evaporates, for example, it absorbs energy and cools the local environment. As water condenses, it releases energy and warms the local environment. The water cycle also influences the physical geography of the Earth.

Name 3 different ways of reducing the effect of sound waves.

Answers

Answer:

There are several basic ways to reduce sound: increasing the distance between source and receiver, decoupling, using noise barriers to reflect or absorb the energy of the sound waves, using damping structures such as sound baffles for absorption, or using active antinoise sound generators.

PLEASE HELP ME THIS IS FOR GYM! YOU WILL MAKE MY DAY FOR WHOEVER DOES THIS.

In a three (3) page, double spaced, typed paper, discuss why cardiovascular fitness and flexibility are important factors in maintaining a healthy lifestyle. In this assignment, define cardiovascular fitness and flexibility. Research two (2) cardiovascular fitness activities and explain why these activities are important in maintaining good health. Finally, discuss in detail several flexibility exercises a person should complete before engaging in physical activity.

Answers

Cardiovascular fitness and flexibility are both important factors in maintaining a healthy lifestyle because they contribute to overall physical health and well-being.

Why are  cardiovascular fitness and flexibility important factors in maintaining a healthy lifestyle?

Cardiovascular fitness refers to the ability of the heart, lungs, and circulatory system to deliver oxygen-rich blood to the body's tissues during physical activity. Regular cardiovascular exercise, such as running, swimming, or cycling, can improve heart health, lower blood pressure, reduce the risk of heart disease, and improve overall fitness and endurance.

In combination, cardiovascular fitness and flexibility can provide a foundation for good physical health, allowing individuals to engage in a wide range of physical activities and enjoy an active lifestyle. Regular exercise that includes both cardiovascular fitness and flexibility can also help improve mental health and reduce the risk of chronic diseases, such as obesity, type 2 diabetes, and some forms of cancer. Overall, maintaining good cardiovascular fitness and flexibility is an important part of a healthy lifestyle.

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Rank the four cases below according to the magnitude of the net electric force on the + q charge. Explain how you determined your ranking.

Answers

The order of net coulombic measurement of the amount is (4) > (3) > (1) > (2) .

What kinds of electrostatic charge exist?

The Many Kinds of Electric Forces Electromagnetic forces can be divided into two categories: attractive electromagnetic forces and repellent electrical forces. Related crimes repel each other whereas opposite charges attract one another.

(1)   Net charge density force on charge q: magnitude  = kQq / R2  +  2 kQq cos(theta) / R2

                                                                   = k Q q ( 1 + 2 cos(theta) ) / R2

(2)   Net charge density force on charge q: magnitude = kQq / R2  +  2 kQq cos(theta) / (R/cos(theta))^2

                                                                = k Q q ( 1 + 2 cos3(theta) ) / R2

(3) Net charge density force on charge q: magnitude =  3 kQq / R2

(4)Net charge density force on charge q: magnitude=  kQq / (R/2)^2  = 4 kQq / R2

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20 points!!! Emergency help required.
Florence is spinning a 770 g weight tied to a string over her head. The string is 0.94 m long, and the weight is moving with a speed of 4.24 m/s. What is the centripetal force pulling the weight inward?

14.7 N

20.6 N

11.0 N

19.7 N

Answers

The centripetal force pulling the weight inward is 19.7 N. The closest option to this value is option (D), 19.7 N.

What is Centripetal Force?

Centripetal force is a force that acts on an object moving in a circular path, directing it toward the center of the circle. In other words, it is the force required to keep an object moving in a circular path, rather than flying off in a straight line. The word "centripetal" comes from the Latin words "centrum", which means "center", and "petere", which means "to seek or aim for".

The centripetal force, which is the force acting on an object moving in a circular path, is given by the formula:

F = m * v^2 / r

where F is the centripetal force, m is the mass of the object, v is its velocity, and r is the radius of the circular path.

In this case, the mass of the weight is 770 g, or 0.77 kg, the velocity is 4.24 m/s, and the radius is 0.94 m.

F = (0.77 kg) * (4.24 m/s)^2 / 0.94 m

F = 19.7 N

Therefore, the centripetal force pulling the weight inward is 19.7 N. The closest option to this value is option (D), 19.7 N.V

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Which weighs more, a liter of ice or a liter of water?

Answers

Answer:

Water is denser so a liter of water weighs more than a liter of ice

Infrared observations of a star show that the star is most intense at a wavelength of 800 nm. What is the temperature of the star's surface in K?

Answers

The star's surface has a temperature of about 3622.5 K.

What wavelength does a 6000 K star emit the majority of its radiation?

In comparison to the same thing at a cooler temperature, hotter objects produce more energy at all wavelengths. Even though the peaks of the 4,000 K object are closer to this wavelength, the 6,000 K object produces more energy at this wavelength than the 4,000 K one.

The Wien's displacement law can be used to calculate the star's surface temperature.

λ_max = b/T

Before applying Wien's law, we must convert the supplied wavelength of 800 nm to metres.

800 nm = 800 × 10⁻⁹ m

When the values are added to the formula, we obtain:

λ_max = b/T

800 × 10⁻⁹ m = (2.898 × 10⁻³ m·K) / T

Solving for T, we get:

T = (2.898 × 10⁻³ m·K) / 800 × 10⁻⁹ m

T = 3622.5 K

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a professional football player kicks a football eith an initial velociry v= (6.0 m/s) x + (20.0 m/s) y determine how long the football stays in yhe air as well as the horizontal displacement

Answers

The horizontal displacement is given by the product of the horizontal component of the initial velocity and the time of flight, so it is 6 m/s x 0.828 s = 4.968 m.

What is initial velocity?

Initial velocity is the speed of an object at the start of its motion. It is usually represented by the letter u in equations. Initial velocity is important in determining the final velocity, displacement, and acceleration of an object after a certain amount of time.

The horizontal displacement is simply the product of the horizontal component of the initial velocity, 6 m/s, and the time the ball is in the air. To determine the time the ball stays in the air, we can use the formula for the time of flight of an object under the influence of gravity:
t = 2v sin θ / g
Where t is the time of flight, v is the initial velocity, θ is the angle of the initial velocity vector with respect to the horizontal, and g is the acceleration due to gravity (9.8 m/s2).
In this case, the initial velocity vector is (6.0 m/s) x + (20.0 m/s) y, so the angle is given by the inverse tangent of the ratio of the y-component to the x-component, which is inverse tangent (20.0/6.0) = 77.4°.
Substituting the values into the equation, we get:
t = 2 (6.0 m/s) sin 77.4° / 9.8 m/s2 = 0.828 s
The horizontal displacement is given by the product of the horizontal component of the initial velocity and the time of flight, so it is 6 m/s x 0.828 s = 4.968 m.

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if five violins sound the same note of 1000Hz, each at the same sound pressure level of 60 dB, what is their total intensity in decibels, compared with the violin alone?

Answers

The total sound pressure level of the five violins is 47 dB, which is 13 dB less than the sound pressure level of a single violin at 60 dB.

What is the total intensity?

The total intensity of the five violins can be found by summing their individual intensities. The intensity of a sound wave is proportional to the square of the sound pressure level, so we can use the following equation:

I = I0 * 10^(L/10)

where;

I0 is the reference intensity (for sound at the threshold of hearing, I0 = 1e-12 W/m^2), L is the sound pressure level in decibels, and I is the intensity in W/m^2.

Since each violin has a sound pressure level of 60 dB, the intensity of each violin can be calculated as follows:

I_violin = I0 * 10^(60/10) = 1e-12 * 1000 = 1e-9 W/m^2

The total intensity of the five violins can then be found by adding the individual intensities:

I_total = 5 * I_violin = 5 * 1e-9 = 5e-9 W/m^2

To find the sound pressure level corresponding to this total intensity, we can use the inverse of the equation above:

L = 10 * log10(I/I0)

L_total = 10 * log10(I_total/I0)

= 10 * log10(5e-9/1e-12)

= 10 * log10(5e3)

= 47 dB

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The displacement of two interfering light waves are y1=4sinwt and y2=3sin(wt+π/2)The amplitude of the resultant wave is a. 5 b. 7 c. 1 d. 0

Answers

Answer:

Explanation:

Amplitude of first wave a1=4

Amplitude of second wave a2=3

Angle between two waves =Π/2

Resultant amplitude=[tex]\sqrt{a_{1} ^{2}+a_{2} ^{2} +2a_{1} a_{2} cos\alpha }[/tex]

=[tex]\sqrt{4^{2}+3^{2} +2*4*3*cos90 }[/tex]

=5

Answer is a

45.0J of work is done on a 1.50kg ball at rest. What is the velocity of the ball?
30.0m/s
5.48m/s
60.0m/s
7.75m/s

Answers

Answer:

7.75 m/s.

Explanation:

We can use the work-energy principle to solve this problem. The principle states that the work done on an object is equal to the change in its kinetic energy:

W = ΔK

where W is the work done, ΔK is the change in kinetic energy.

In this case, the work done on the ball is 45.0 J. Since the ball is initially at rest, its initial kinetic energy is zero. Therefore, the change in kinetic energy is:

ΔK = Kf - Ki = 1/2 mv^2 - 0

where Kf is the final kinetic energy, Ki is the initial kinetic energy, m is the mass of the ball, and v is its velocity.

Substituting the given values, we get:

45.0 J = 1/2 (1.50 kg) v^2

Solving for v, we get:

v^2 = (2 x 45.0 J) / (1.50 kg)

v^2 = 60.0

v = √60.0

v ≈ 7.75 m/s

Therefore, the velocity of the ball is approximately 7.75 m/s.

Fill in the appropriate values for each blank as it refers to ATOM 1. The atomic number of this atom is​

the mass of this atom is

Answers

The atomic number of the atoms is 3

The mass number of the atom is 6.

What is the atomic number of the atom?

The atomic number of an atom is the number of protons in the nucleus of the atom. In a neutral atom, the atomic number also corresponds to the number of electrons orbiting around the nucleus.

The atomic number determines the identity of the element, since each element has a unique number of protons in its nucleus.

The atomic number is typically represented by the symbol Z in chemical equations and atomic models.

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A 0.140 kg baseball is pitched toward home plate at 30.0 m/s. The batter hits the ball back (opposite direction) to the pitcher at 44.0 m/s. Assume that towards home plate is positive. If the ball was in contact with the bat for 0.002 seconds, what is the average force the bat exerts on the ball?

−9700 N

−1000 N

−4700 N

−5200 N

Answers

The average force the bat exerts on the ball is -5200 N. This can be calculated using the equation F = Δp/Δt, where F is the average force, Δp is the change in momentum (pf-pi), and Δt is the time interval. In this case, Δp = m * (vf - vi) = 0.14 kg * (44 m/s - 30 m/s) = 5.4 kgm/s, and Δt = 0.002 s. Thus, F = 5.4 kgm/s / 0.002 s = -5200 N.

Calculate the time required for a 6000-newton net force to stop a 1200-kilogram car initially traveling at 10 meters per second. [Show all work, including the equation and substitution with units.]

Answers

Answer:

To solve this problem, we will use the equation for the net force on an object, which is:

net force = mass x acceleration

We can rearrange this equation to solve for acceleration:

acceleration = net force / mass

Once we have the acceleration, we can use the equation for the motion of an object under constant acceleration:

final velocity^2 = initial velocity^2 + 2 x acceleration x distance

We can rearrange this equation to solve for the distance required to stop the car:

distance = initial velocity^2 / (2 x acceleration)

Finally, we can use the equation for average velocity to calculate the time required to travel this distance:

time = distance / average velocity

Substituting the given values into the equations:

net force = 6000 N

mass = 1200 kg

initial velocity = 10 m/s

Using the first equation:

acceleration = net force / mass

acceleration = 6000 N / 1200 kg

acceleration = 5 m/s^2

Using the second equation:

distance = initial velocity^2 / (2 x acceleration)

distance = 10 m/s^2 / (2 x 5 m/s^2)

distance = 10 m

Using the third equation:

average velocity = (initial velocity + final velocity) / 2

final velocity = 0 (since the car is coming to a stop)

average velocity = 10 m/s / 2

average velocity = 5 m/s

Using the fourth equation:

time = distance / average velocity

time = 10 m / 5 m/s

time = 2 seconds

Therefore, the time required for a 6000-newton net force to stop a 1200-kilogram car initially traveling at 10 meters per second is 2 seconds.

A screw of a certain press has a pitch of 0.20 cm. The diameter of the wheel to which a tangential turning force F is applied is 55 cm. If the efficiency is 40 %, how large must F be to produce a force of 12 kN in the press?

Answers

To produce a force of 12 kN in the press, a tangential turning force of 1187500 N (1187.5 kN) must be applied to the wheel.

What is force?

Force is an influence that causes a change in the motion, shape, or both of an object. It is the result of an interaction between two objects, and is described through Newton's three laws of motion. These laws explain the relationship between force, mass, and acceleration.

The pitch of the screw is the distance between two adjacent threads on the screw, and is 0.20 cm in this case. The wheel diameter is 55 cm.

To calculate the force needed to produce a force of 12 kN in the press, we use the following equation: F = (12000 N * 55 cm) / (0.20 cm * 0.4).

This equation takes into account the pitch of the screw, the wheel diameter, and the efficiency of the press.

Plugging in the numbers, we get: F = (12000 N * 55 cm) / (0.20 cm * 0.4) = 1187500 N.

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Calculate the speed (in m/s) a spherical raindrop would achieve falling from 2.70 km with air drag. Take the size across of the drop to be 3 mm, the density to be 1.00 ✕ 10^3 kg/m3, and the surface area to be r^2. (Assume the density of air is 1.21 kg/m^3.)

Please, solve as soon as possible.

Answers

A spherical raindrop would fall from a height of 2.70 km at a speed of 26.22 m/s due to air resistance.

Calculation-

(a) Height from which the raindrop falls, h = 2.70 km = 2700 m

Now,

suppose, m = mass of raindrop

v = speed of raindrop at the ground.

Apply conservation of energy -

1/2 m v^2 = m g h

v = (2 g h)^1/2

  = (2 * 9.8 * 2700)^1/2 = 230.0 m/s (Answer)

(b) In the presence of air drag -

Dynamics

m x" = m g - k x'^2

limit speed is

v = (m g / k)^1/2

where

k = 1/2 ρ A C

ρ = air density = 1.21 kg/m^3

A = area = π r^2 = 3.141 * 0.0015^2 = 7.07 x 10^-6 m^2

C = coefficient of hydraulic resistance [0.47 for a sphere]

m = ρ' V = 1.0 x 10^3 x (4/3)*pi*0.0015^3 = 1.41 x 10^-5 kg

k = 1/2*1.21*7.07x10^-6*0.47

  = 2.01 x 10^-7 kg/m

Therefore,

v = [(1.41 x 10^-5 x 9.8) / (2.01 x 10^-7)]^1/2

  = 26.22 m/s

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Please help (50 points and Brainly)

Answers

The speed of the basketball is 14.4 m/s if its kinetic energy is 109 J.

What is kinetic energy?

Kinetic energy is the energy possessed by an object due to its motion. It is defined as the energy that an object has because of its velocity, and it depends on the mass of the object and its speed. The formula for kinetic energy is [tex]K = 1/2 mv^2,[/tex]  where K is kinetic energy, m is the mass of the object, and v is its velocity.

The greater the mass and velocity of an object, the more kinetic energy it has. Kinetic energy is a scalar quantity, meaning that it only has magnitude and no direction. It is an important concept in physics and has many practical applications, such as in sports, transportation, and industrial machinery.

The kinetic energy (K) of an object with mass m and speed v is given by:

[tex]K = 1/2 * m * v^2[/tex]

Rearranging this equation, we can solve for v:

[tex]v = sqrt(2K/m)[/tex]

Plugging in the values given in the problem, we get:

[tex]v = sqrt(2*109 J / 0.145 kg) = 14.4 m/s[/tex]

Therefore, the speed of the basketball is 14.4 m/s if its kinetic energy is 109 J.

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Explain why it is so difficult to ride a bicycle in soft sand.

Answers

Soft sand makes it challenging to ride a bicycle since the tires can't generate enough friction. The bicycle struggles to move ahead as a result, and its tires sink.

The danger of ridding a bicycle in soft sand

Riding a bicycle on soft sand poses a risk of the vehicle being stuck and challenging to move. Injuries might result if the rider loses balance and falls off the bicycle. The frame, tires, and other parts of the bicycle could also be harmed by the sand.

Furthermore, sand, dirt, wood chips, deep pea gravel, soft grass, and snow all drastically alter your speed. Sand, however, can be the most challenging of all of them because you typically enter the area quickly from grass or another hard surface.

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