If a supernova remnant core has a mass greater than 2.8 solar masses, then what force will be able to stop gravity from collapsing the core

Answers

Answer 1

If a supernova remnant core has a mass greater than 2.8 solar masses, then NO force will be able to stop gravity from collapsing the core. (Option C)

What is a Supernova Remnant Core?

A supernova Remnant Core is an astronomic structure that is remaining after the explosion of a star in a supernova has occurred.

A supernova is simply the explosion of a star. When the mass of the sun is used as a unit of mass, it is called solar mass. This unit is given as:

1.989 × 1030 kg.

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Related Questions

HELP ME PLEASE!!!!

Do some research on digital vs. analog recording, and decide which you think gives the most accurate and best quality sound. State the advantages and disadvantages of each in a paragraph. Be sure to back up your opinions with facts, and state your sources.

Answers

Answer:

The question of analog vs. digital audio is one of the more hotly debated questions in the world of music, film, and media today. Does digital sound better? Does analog sound better? Is there even a noticeable difference?

It’s impossible to understand the difference completely without understanding what distinguishes analog audio from digital audio. A full discussion of these terms is best left to your curriculum and discussions with your mentor in the studio. For now, though, here’s a brief explanation of what these two words mean, and the differences between them.

Explanation:

⚠️PLEASE HELP!!⚠️ Which two statements describe how convection currents transfer thermal energy in earths oceans?

Answers

Answer:

The answer is D & B

Answer: B and D

Explanation:

Why do stars more massive than the sun have a higher surface temperature than the sun?.

Answers

Answer:

Stars that are more than 40 times more massive than our Sun, cannot expand into a red supergiant. This is because they burn too quickly and lose their outer layers fast. They will reach the blue supergiant stage, or perhaps yellow hypergiant, before returning to become hotter stars.

Explanation:

Answer:

Cause there bigger so they have a more hotter surface.

Who ran faster? The turtle or the rabbit?
(A) The rabbit
(B) The turtle

Answers

Answer:

the turtle was finished faster but the rabbit was faster

Explanation:

Daily Task $18.3: Homework/Classwork 1. 1.1 The speed of sound in air is about 330 m-s'. A lightning bolt strikes a tree that is 1,5 km away from you. Calculate the time from the moment that you see the lightning flash until you hear the thunder that accompanies it. ​

Answers

Answer:

sup cuh, the answer is, 15 5/8 mm3

Explanation: i did the math.

Carbon -14 is used to date a palm fossil that originally contained 0.24 grams of carbon -14. The half life is 5700 years. If the fossil is found to be 17,100 years old, how much carbon -14 does it contain now?

Please make sure to show all of your work/process so I can learn how to do it on my own!! thank you ​

Answers

Answer:

Exactly 0.03042 carbon-14 is remaining.

Roughly 0.03 Carbon-14 is remaining. (When/If Multiple Choice)

Explanation:

Not a physics question, this is chemistry, but I'll answer.

First, divide 17,000/5700 to find the t, or time.

t = 2.98245614 or 2.98.

If it originally contained .24 grams, and a half life means x/2,

you would use the formula x/2^p, with p being the number of half lives

(these variables are made up, you can use any you would like)

In 17,000 years, the palm fossil experienced 2.98 half lives.

Thus meaning, using our equation, we would find (.24)/2^2.98

This equals 0.030418784 carbon-14 remaining to be exact.

(For Multiple Choice, it may be required to round to For Multiple Choice, it may be required to round to 3, so .24/2/2/2 or .24/2=.12 then .06 then it equals :  .03 Carbon-14)

Carbon -14 is used to date a palm fossil that originally contained 0.24 grams of carbon -14. The half life is 5700 years. If the fossil is found to be 17,100 years old then 0.0303 g of carbon -14 does it contain now.

What is radioactive decay ?

The process by which an unstable atomic nucleus loses energy through radiation is known as radioactive decay (also known as nuclear decay, radioactivity, radioactive disintegration, or nuclear disintegration). A radioactive substance is one that contains unstable nuclei. Alpha decay, beta decay (-decay), and gamma decay (-decay) are three of the most prevalent forms of decay, all of which entail the emission of one or more particles. The mechanism responsible for beta decay is the weak force, while the other two are regulated by electromagnetism and nuclear force. Electron capture is a fourth form of common decay in which an unstable nucleus grabs an inner electron from one of the electron shells.

According to decay formula,

N(t) = N₀ e^(-λt)

Given,

N₀ = 0.24g

t = 17100 years

λ = 0.693/T

Where T is half life.

λ = 0.693/5700 = 1.21 × 10⁻⁴

Putting all the values in the equation,

N(t) = 0.24g e^(-1.21 × 10⁻⁴ ×17,100)

N(t) = 0.0303 g

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The greatest variation in size, mass, and luminosity occurs in:.

Answers

The greatest variation in size, mass, and luminosity occurs in elliptical galaxies.

What is Variation?

This is defined as the difference from the norm which is exhibited by objects.

In the solar system, variation in features such as size, mass, and luminosity occurs mostly in elliptical galaxies due to presence of array of stars thereby making it the most appropriate choice.

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A force of 36N acts at an angle of 55 degrees to the vertical. The force moves its point of application by 64 cm in the direction of the force calculate work done by:


(A)the horizontal component of force


(B)the vertical component of the force


Answers

The work done by the horizontal component of force is 18.89 Joules while the vertical component of the force is 13.22 Joules.

WORK

The work done on an object, is the product of the force F and the distance S in the direction of the force. That is,

W = F x S

The S.I unit of work is Joule

Given that a force of 36N acts at an angle of 55 degrees to the vertical. The force moves its point of application by 64 cm in the direction of the force

To calculate work done by:

(A) the horizontal component of force;

Force F = 36Sin55 = 29.489N

W = 29.489 x 64/100

W = 18.87 J

(B) the vertical component of the force;

Force F = 36Cos55 = 20.649

W = 20.649 x 64/100

W = 20.649 x 0.64

W = 13.22 J

Therefore, the work done by the horizontal component of force is 18.89 Joules while the vertical component of the force is 13.22 Joules.

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Which statement about natural selection on early earth is correct?.

Answers

Answer:

wheres the statements

Explanation:

where its incomplete

Natural selection could act on a population of proto-cells on early Earth, selecting for those that were stable and had self-replicating, catalytic RNA that allowed them to grow and divide to produce similar daughter proto-cells. The correct option is option (B).

Natural selection could act on a population of proto-cells on early Earth. Proto-cells were early, simpler forms of cells that lacked DNA but had self-replicating, catalytic RNA. Through natural selection, those proto-cells that were more stable and had RNA molecules capable of self-replication and catalytic functions would have had a reproductive advantage.

These traits would allow them to grow, divide, and produce similar daughter proto-cells. Over time, this selection process could have led to the development of more complex and stable cellular structures, eventually leading to the emergence of cells that utilize DNA as their genetic material.

Therefore the correct option is option B.

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The complete question is:

Which statement about natural selection on early Earth is correct?

A. Natural selection could only act on populations of living organisms that had DNA as their genetic material.

B. Natural selection could act on a population of proto-cells on early Earth, selecting for those that were stable and had self-replicating, catalytic RNA that allowed them to grow and divide to produce similar daughter proto-cells.

C. Natural selection acted on populations of proto-cells on early Earth in order to make them more like modern living cells that have DNA as their genetic material.

Cells are of various shapes and sizes.The biggest single cell known is the
A. Amoeba
B. Bacteria
C. Egg of an ostrich
D. Human Ovum​

Answers

Answer:

Explanation:

egg of an ostrich is the biggest

help me PLEASE, it's physical science D:

Answers

Answer:

90

Explanation:

The bottom number on the element is the number of protons and the top number is the total of the protons + neutrons

what is the most effective way to convert atms to pascals

Answers

Answer:

1 Atm (atmospheric pressure) is equal to 101325 pascal (Pa). To convert atm to pascal, multiply the atm value by 101325. atm to pascal formula. Pa = atm * 101325.

Explanation:

Which of these
is a term for the
process of
wearing rock
down by
friction?
A. rusting
B. dissolving
C. abrasion
D. exfoliation

Answers

Answer: C.

Explanation:  Abrasion is where two things rub together causing friction, which in turn wears the rock down.


______is the change from a liquid to a gas at a temperature below boiling point​

Answers

Evaporation is this process
The process is called Evaporation

A 42.0-cm-diameter wheel, consisting of a rim and six spokes, is constructed from a thin, rigid plastic material having a linear mass density of 25.0 g/cm. this wheel is released from rest at the top of a hill 69.0 m high.

Answers

For a 42.0-cm-diameter wheel, consisting of a rim and six spokes,the angular speed is mathematically given as

w=118.6 rad/s

What is the angular speed?

Generally, the equation for the  Conservation of energy  is mathematically given as

K1+U1=K2+U2

Therefore

Mgh+0=0+(1/2)MV2+(1/2)Iω2

Where

M=m+6m

M=2rλ(π+3)

Therefore

[tex]2r \lambda (\pi+3)gh=0.52r \lambda (\pi+3)(rw)2+(1/2)[(2 \pi \lambda r)r2+6( \lambda r)r2/3]w2[/tex]

[tex]w=\sqrt{[(\pi+3)*9.8*53/(0.42/2)2*(\pi+2)[/tex]

w=118.6 rad/s

In conclusion, The angular speed is

w=118.6 rad/s

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If a fossil contains 60% of its original carbon, how old is the fossil

Answers

if im not mistaken its 5600years old

The wavelength of a sound wave in this room is 4. 13 m and the frequency is 75 Hz. What is the speed of the wave in the room?

if you double the frequency of the sound wave but keep the wavelength the same, determine the new speed of the wave.​

Answers

Let's see

#1

[tex]\\ \rm\Rrightarrow v=f\lambda[/tex]

f is frequencylambda is wavelength

[tex]\\ \rm\Rrightarrow v=75(4.13)[/tex]

[tex]\\ \rm\Rrightarrow v=309.75ms^{-1}[/tex]

#2

New frequency:-

2(75)=150

[tex]\\ \rm\Rrightarrow v=150(4.13)[/tex]

[tex]\\ \rm\Rrightarrow v=619.5ms^{-1}[/tex]

A force of 4,500 N acts on a car. The
acceleration of the car is 3 m/s/s. What
is the mass of the car? Show your work
below.

Answers

Answer:

1500 kg is mass of car

Explanation:

F = ma

F/a = m

4500n / 3 m/s^2 = 1500 kg

Which statement describes a chemical property related to the particles that make up a material

Answers

Answer:

Salt crystals are hard and brittle because they are made up of atoms that combine by ionic bonding.

Explanation:

When isaac newton theorized that gravity caused objects to fall to the ground, he had also discovered the force that causes:.

Answers

Answer:

He did not find out any other force

Explanation:

Maybe the answer is that newton found out that the same force causes the earth rotating around the sun.

which of the following is an example of wernickes aphasia?

Answers

An example of wernickes aphasia is someone making a speech which does not make sense.

It majorly caused by loss of flow of blood to the brain. Other causes include

Head injuryBrain inflammationBrain infectionStroke. e.t.c

What is wernickes aphasia?

Wernickes aphasia can simply be defined as a language disorder that makes it very difficult for an individual to understand words and communicate with other people.

So therefore; an exam of wernickes aphasia is someone making a speech which does not make sense.

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The uncertainty principle applies not only to momentum and position, but also to energy and time.
a. True
b. False

Answers

Answer:

(a)    that is a true statement

A red, 400Kg bumper car is moving to the right at 2m/s. The red bumper car collides head on with a blue bumper car with a combined driver/car mass of 600kg and a velocity of 1m/s. The collision was elastic. If the blue car bounced backwards at a velocity of 0.25m/s, what was the final velocity of the red car?

Answers

Based on the principle of the conservation of linear mometum, the recoil velocity of the bliue car is 3.1 m/s.

Principle of conservation of linear momentum

The principle of conservation of linear momentum states that; the total mometum before collsion is equal to the total momentum after collision.

Now;

m1u1 + m2u2 = m2v2 + m2v2

(400Kg * 2m/s) + (600kg *  1m/s) = (600kg * 0.25m/s) + (400Kg * v)

800 + 600 = 150 + 400v

800 + 600 - 150 =  400v

v = 800 + 600 - 150/400

v = 3.1 m/s

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If a spring has a spring constant of 0. 5 N/m and it is stretched 0. 5 m, what is the force

of the spring?

Answers

Answer:

0.25N

Explanation:

k=0.5N/m

e=0.5m

f=?

were k=spring constant

e=extension

F=force

According to hooks law,

f=ke

f=0.5x0.5 =0.25 N

please help me I’ll make u brainliest please


A 1 liter jar contains 0.5 moles of gas at a pressure of 2 atm. What is the temperature of the gas?


What is the volume of a
container of 4 moles of gas at 200 K with a pressure of 3 atm?


Your scientist friend is trying to figure out how many molecules of gas are in a container. They know that the container has a volume of 5 liters, and they measured the pressure and temperature to be 3.5 atm and 275 K. From this information, what do you tell them the mole measurement should be?


Answers

Answer:

See below  ( Ideal gas law)

Explanation:

A)   PV = n RT       P = 2 * 760 = 1520 mm  

    1520 ( 1)  =  .5 (8.314)(T)       T is in Kelvin

     T = 365.64 K

B) PV = nRT

   3 ( 760) V = 4 ( 8.314)(200)

           V = 2.92 Liters

C) PV = nRT

    3.5 (760) (5) = n (8.314)(275)    n = 5.8 moles

Particle A and particle B, each of mass M, move along the x-axis exerting a force on each other. The potential energy of the system of two particles assosicated with the force is given by the equation U=G/r 2, where r is the distance between the two particles and G is a positive constant

Answers

Speed of particle B is 2v₀/3 m/s to the left. Particle A and particle B will always have equal speed since they experience equal forces.

Conservation of energy

The speed and direction of the particle B is determined by applying the principle of conservation of energy as follows;

K.E₁ + P.E₁ = K.E₂ + P.E₂

[tex]\frac{1}{2} Mv^2_A + \frac{G}{r^2} = \frac{1}{2} Mv^2_B + \frac{G}{r^2} \\\\ \frac{1}{2} Mv^2_A = \frac{1}{2} Mv^2_B\\\\v^2_A = v^2_B\\\\v_A = v_B[/tex]

[tex]v_B = \frac{2v_0}{3} \ m/s \ to \ the \ left[/tex]

At any given position, the speed of particle A and particle B will be equal, since they experience equal force and they have equal masses.

The complete question is below:

Particle A and particle B, each of mass M, move along the x-axis exerting a force on each other. The potential energy of the system of two particles assosicated with the force is given by the equation U=G/r 2, where r is the distance between the two particles and G is a positive constant. At time t=T1 particle A is observed to be traveling with speed 2vo/3 to the left. The speed and direction of motion of particle B is ?

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Answer:

Explanation:

the linear momentum is conserved MiVi=MaVa+MbVb

MV0=2V0M/3+MVb

Vb=V0/3

Please Help! 20 BRAIN POINTS
An astronaut (m = 95 kg) and her tool box (m = 21 kg) is drifting through deep space at a speed of 0.4 m/s [FWD]. In order to change the direction of travel, the astronaut throws her tool box forward. What is the minimum speed of the thrown tool box necessary, so that the astronaut changes direction?

Answers

Answer:

The Speed of the throw that is required to create enough impulse, to change the direction of the momentum is: -1.81m/s

Explanation:

m1=95kg

m2=21kg

V1=.4m/s

V2=?

V'=<0 or -.01 at lowest.

for the Impulse formula, I found: m1 x V1 + m2 x V2 = <0

so,

(95) x (.4) + (21) x (V2)=<0

38kgm/s+(21kg x V2)=<0 or -0.01m/s

I found that V2 was equivalent to -1.81, and when you plugin the value, you get the equation

(95) x (.4) + (21) x (-1.81) = -0.01m/s

What is the origin of all stars? supernova dwarfs protostars nebulae

Answers

Answer:

Nebulae

Explanation:

Hope this helps!

Answer:

D nebulae

Explanation:

A ball of play-doh with a mass of 1 kg is thrown at 5 m/s against a wall. The wall causes the play-doh to smash and come to a stop in 0.13 s. What force does the wall apply to the play-doh to make it stop?"

Provide the magnitude of the force applied by the wall (number only).

Answers

The magnitude of the force applied by the wall on the ball while smashed is 38.462 newtons.

How to determine the required impact force to stop a ball of Play-Doh(TM)

After a quick reading of the statement we conclude that the impact theorem shall be useful to determine the dynamic force required to stop the ball when smashed. The impulse theorem results from the combination of the Newton's laws of motion, principle of energy conservation and work-energy theorem:

[tex]m \cdot v_{o} = F\cdot \Delta t[/tex]     (1)

Where:

m - Mass of the ball, in kilograms.[tex]v_{o}[/tex] - Initial speed of the ball, in meters per second.Δt - Impact time, in seconds. F - Impact force, in newtons.

If we know that m = 1 kg, [tex]v_{o} = 5\,\frac{m}{s}[/tex] and Δt = 0.13 s, then the impact force is:

F = (1 kg) · (5 m/s)/(0.13 s)

F = 38.462 N

The magnitude of the force applied by the wall on the ball while smashed is 38.462 newtons. [tex]\blacksquare[/tex]

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Three liquids are at temperatures of 2°C, 21°C, and 34°C, respectively. Equal masses of the first two liquids are mixed, and the equilibrium temperature is 5 C. Equal masses of the second and third are then mixed, and the equilibrium temperature is 30.1°C.
Find the equilibrium temperature when equal masses of the first and
third are mixed.
Answer In units of 'C.

Answers

Answer:

m - mass of each liquids (all masses are equal )

C_1C 1 - specific heat of the first third C_2C 2 - specific heat of the second  liquid

C_3C 3- specific heat of the third liquid

Temperature of liquids: T_1=7 ◦C,T_2=20◦C, T_3=34◦CT

1 =7◦C,T 2 =20◦C,T 3=34◦C

Temperature of 1+2 liquids mix: T_{12}=11^oCT

12 =11 oC

Temperature of 2+3 liquids mix: T_{23}=22.6^oCT

23=22.6 oC

Temperature of 1+3 liquids mix: T_{13} - ?T 13 −?

When the first two are mixed:

m C₁ (T₁ − T_{12}) + m C₂ (T₂ − T_{12}) = 0 \\ C₁ (7− 11) + C₂ (20 − 11) = 0\\ 4C_1=9C_2\\ C_1=2.25C_2mC₁(T₁−T 12)+mC₂(T₂−T 12 )=0C₁(7−11)+C₂(20−11)=04C \1=9C 2C 1 =2.25C 2

​When the second and therd are mixed:

m C_2 (T_2 − T_{23}) + m C_3 (T_3 − T_{23}) = 0 \\ C_2 (20−22.6) + C₂ (34 −22.6) = 0\\ 2.6C_2=11.4C_3\\ C_2=4.38C_3mC 2 (T 2 −T 23 )+mC 3 (T 3 −T 23 )=0C 2(20−22.6)+C₂(34−22.6)=02.6C 2 =11.4C 3C2 =4.38C 3

​When the first and therd are mixed:

m C_1 (T_1 − T_{13}) + m C_3 (T_3 − T_{13}) = 0 \\ C_1 (7−T_{13}) + C_3 (34 −T_{13}) = 0\\ C_1=2.25C_2=2.25(4.38C_3)=9.86C_3\\ 9.86C_3 (7−T_{13})=-C_3(34 −T_{13})\\ 9.86 (7−T_{13})=-(34 −T_{13})\\ T_{13}=9.5^oCmC 1(T1 −T13)+mC 3(T3−T13 )=0C1 (7−T13 )+C 3(34−T 13 )=0C1 =2.25C2=2.25(4.38C3 )=9.86C39.86C3 (7−T13 )=−C3(34−T13 )9.86(7−T13)=−(34−T13 )T13 =9.5 oCT_{13}=9.5^oCT 13 =9.5 o C:

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