if a star is 11 pc away from us, will its apparent visual magnitude be higher or lower than its absolute visual magnitude? what if the star is 5 pc away?

Answers

Answer 1

If a star is 11 pc away from us, its apparent visual magnitude will be lower than its absolute visual magnitude. The star's apparent magnitude would be only 0.38 magnitudes lower than its absolute magnitude.

This is because the apparent magnitude of a star is affected by its distance from us. As the distance increases, the star appears dimmer, and its apparent magnitude decreases.

The distance modulus formula gives us a way to calculate the difference between the apparent and absolute magnitudes of a star:

Distance modulus = 5 * log(distance in parsecs) - 5

For a star that is 11 pc away, the distance modulus is,

Distance modulus = 5 * log(11) - 5 = 1.38

This means that the star's apparent magnitude will be 1.38 magnitudes lower than its absolute magnitude.

If the same star were only 5 pc away from us, the distance modulus would be,

Distance modulus = 5 * log(5) - 5 = 0.38

In this case, the star's apparent magnitude would be only 0.38 magnitudes lower than its absolute magnitude. This means that the star would appear brighter and have a higher apparent magnitude when it is closer to us.

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Related Questions

A billiard ball of mass m = 0.150 kg hits the cushion of a billiard table at an angle of θ1 = 60.0 degrees at a speed of v1 = 2.50 m/s. It bounces off at an angle of θ2 = 47.0 degrees and a speed of v2 = 2.20 m/s.
a) What is the magnitude of the change in the momentum of the billiard ball?
b) In which direction does the change of momentum vector point? (Take the x-axis along the cushion and specify your answer in degrees.)

Answers

The magnitude of the change in the momentum of the billiard ball is 0.268 kg⋅m/s. The direction of the change of momentum vector points at 59.6 degrees, measured counterclockwise from the x-axis along the cushion.

This result can be found by using the equation for conservation of momentum, which states that both the magnitude and the direction of the momentum before and after the collision must be the same.

Since the mass and the speed of the ball changed, the direction of the vector must have changed as well. In this case, the vector changed direction from 60 degrees to 47 degrees, a difference of 13 degrees.

This means that the vector must have rotated counterclockwise by 13 degrees, or in other words, the change of momentum vector points at 59.6 degrees, measured counterclockwise from the x-axis along the cushion.

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a battery is rated at 12 v and 160 a-h. how much energy does the battery store? select one: a. 3.2 kj b. 1.9 kj c. 1.9 mj d. 6.0 kj e. 6.9 mj

Answers

The battery stores 6.9 MJ (megajoules) of energy. To calculate this, multiply the voltage of 12 V by the Amp-hour rating of 160 A-h. The result is 1920 watt-hours (12 V x 160 A-h = 1920 Wh). Since 1 Wh = 0.0036 MJ, the total energy stored is 1920 x 0.0036 MJ = 6.9 MJ. Answer is option e

The energy stored in a battery can be calculated by multiplying the battery's voltage (V) by its capacity in ampere-hours (Ah). In this case, the battery is rated at 12 V and 160 Ah, so the energy stored can be calculated as:

Energy (in Joules) = Voltage (in Volts) x Capacity (in Ampere-hours) x 3600 seconds

Where 3600 seconds is the number of seconds in an hour. Plugging in the given values, we get:

Energy = 12 V x 160 Ah x 3600 seconds

Energy = 6,912,000 Joules

To convert Joules to other units, we can use the following conversion factors:

1 Joule = 0.001 kilojoules (kJ)

1 Joule = 1 x 10^-6 megajoules (MJ)

Therefore, the energy stored in the battery is 6,912,000 Joules, which is equivalent to 6.9 MJ

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if you had a microscope which was capable of doing this, what would the frequency of electromagnetic radiation be, in hertz, that you would have to use?

Answers

Answer:

The electric power didn’t last very long. It lasted only as long as the chemical reaction in the battery.

Explanation:

A 23.3 kg boy is moving along a circular path with the constant speed of 2.7 m/s. What is the magnitude of the centripetal force acting on the boy if the radius of the circle is 12.9 m. Note : Calculate the answer to 3 (three) significant figures by presenting it in normal ( decimal) form. Don't forget to include the unit.

Answers

The centripetal force for the given question would be 16.3 N.

Explanation:

The magnitude of the centripetal force acting on a 23.3 kg boy moving along a circular path with a constant speed of 2.7 m/s and the radius of the circle is 12.9 m is 16.3 N (newton).

What is centripetal force?

Centripetal force is the net force acting on an object moving in a circular path toward the center of the circle. It always points towards the center of the circle, hence the name "center-seeking force".

What is the formula for centripetal force?

The formula for centripetal force is Fc = (mv²)/r, where Fc is the centripetal force, m is mass, v is velocity or speed and r is the radius of the circular path.

In the given question: Mass, m = 23.3 kgVelocity, v = 2.7 m/s, Radius, r = 12.9. To calculate centripetal force,

F = (m x v^2)/r

Putting the given values in the above formula: F = (23.3 kg x (2.7 m/s)^2)/12.9 m= 16.3 N (newton)

Therefore, the magnitude of the centripetal force acting on the boy is 16.3 N (newton).

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A wheel is rotating about an axis that is in the z
-direction. The angular velocity ωz
is -6. 00 rad/s
at t
= 0, increases linearly with time, and is +4. 00 rad/s
at t
= 6. 00 s. We have taken counterclockwise rotation to be positive

Answers

The formula for angular velocity as a function of time when it rises linearly can be used to address this issue:

ωz(t) = ωz,0 + αz t

If t is time, z,0 is the angular acceleration at rest, and z is the starting angular velocity.

Applying the information provided, we have:

ωz,0 = -6.00 rad/s (initial angular velocity)

z (6.0 s) = +4.0 rad/s (final angular velocity)

t = 6.00 s (time elapsed) (time elapsed)

The angular acceleration z is what we're looking for.

Using the formula's supplied values as substitutes, we obtain:

-6.00 rad/s + z = +4.00 rad/s (6.00 s)

When we simplify and find z, we obtain:

Z = (5.00 rad/s - 6.0 rad/s)

/6.00 s = 1.67 rad/s^2

As a result, the wheel's angular acceleration is 1.67 rad/s2.

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how does the conservation of angular momentum explain the increased speed of a planet in its orbit at perihelion? quizley

Answers

The conservation of angular momentum explains that a planet moves faster at perihelion due to an increase in angular velocity, resulting in an increase in linear velocity.

The conservation of angular momentum can be found as:

The conservation of angular momentum is a fundamental principle in physics that states that the total amount of angular momentum in a system remains constant unless acted upon by an external force.According to the law of conservation of angular momentum, when a planet moves closer to the Sun at perihelion, the decrease in distance causes the angular momentum to remain constant. Therefore, the velocity of the planet must increase to compensate for the decrease in distance. At perihelion, which is the point in the planet's orbit where it is closest to the Sun, the planet is moving faster than at any other point in its orbit.This is because as the planet gets closer to the Sun, the gravitational force between the two objects gets stronger, causing the planet to speed up in order to maintain its angular momentum.The closer the planet is to the Sun, the faster it has to move to keep from falling into it due to the strong gravitational pull.Therefore, the conservation of angular momentum explains why a planet speeds up at perihelion because the planet has to maintain its angular momentum as it gets closer to the Sun.

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is it possible for the resultant of the electric and magnetic forces on a charge moving simultaneously through both fields to be zero?

Answers

Yes, it is possible for the resultant of the electric and magnetic forces on a charge moving simultaneously through both fields to be zero.

This is due to the fact that electric and magnetic forces are perpendicular to one another, meaning that they can be in opposition and cancel each other out.


To explain in more detail, electric fields exert a force on a charged particle that is proportional to its charge and the magnitude of the electric field. This force, Fe, is given by Fe = qE.

Meanwhile, magnetic fields exert a force on a moving charged particle that is proportional to its charge, the magnitude of the magnetic field, and its velocity. This force, Fm, is given by Fm = qv × B.


Since these forces are perpendicular to each other if the electric force is equal in magnitude to the magnetic force but opposite in direction, they can cancel each other out. This will result in a net force of zero on the particle.

Therefore, it is true that it is possible for the resultant of the electric and magnetic forces on a charge moving simultaneously through both fields to be zero.

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which way of varying the normal force to measure the coefficient of friction do you think is better? why?

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There are two ways of varying the normal force to measure the coefficient of friction; namely, varying the weight of the object and tilting the surface.

What is the coefficient of friction?

It is a term that refers to the force that opposes the motion of one surface on another when the two surfaces come into contact. Friction can be useful when we want to prevent the sliding of an object, but it can also be a disadvantage when we want the object to move.

In general, tilting the surface is a better way of varying the normal force to measure the coefficient of friction than varying the weight of the object. This is because the weight of the object can vary the force of gravity acting on the object, making it more challenging to calculate the coefficient of friction on the object.

On the other hand, by tilting the surface, we can achieve a more uniform change in normal force, making it easier to calculate the coefficient of friction. Additionally, by tilting the surface, we can eliminate any other factors that may affect the motion of the object, such as air resistance, making the coefficient of friction more accurate.

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Which event is an example of vaporization?
A. The outside of a glass of ice water becomes moist. B. Perspiration dries on a person's skin. C. A cloud forms in the sky
D. Frost forms on a blade of grass

Answers

Perspiration dries on a person's skin. The correct answer is option B.

Vaporization is the process by which a liquid changes into a gas or vapor, and perspiration is a liquid that is secreted by sweat glands in the skin. When perspiration dries on a person's skin, it is evaporating and changing into a gas due to the heat energy from the person's body. This is an example of the physical change of state from a liquid to a gas through vaporization. The other options do not involve a change of state from a liquid to a gas, and instead involve other processes such as condensation. Hence option B  is the correct answer .

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a marine biologist is preparing a deep-sea submersible for a dive. the sub stores breathing air under high pressure in a spherical air tank that measures 78.0 cm wide. the biologist estimates she will need 3700. l of air for the dive. calculate the pressure to which this volume of air must be compressed in order to fit into the air tank. write your answer in atmospheres. be sure your answer has the correct number of significant digits.

Answers

The pressure to which this volume of air must be compressed in order to fit into the air tank is 0.13 atm.

What is the ideal gas law?

The ideal gas law is pV = nRT. Where p is the pressure, V is the volume, n is the number of moles, R is the universal gas constant, and T is the temperature.

The air tank is a sphere, so the volume is given by V = 4/3πr², where r is the radius. Given that the tank measures 78.0 cm wide,

the radius is r = 78.0/2

                       = 39.0 cm

                       = 0.39 m.

Hence, V = 4/3π(0.39)³

                = 0.019 m³

The biologist needs 3700 L of air, which is equivalent to 3.7 m³. Therefore, the number of moles of gas is

n = PV/RT,

where P is the pressure, R is the gas constant (8.31 J/mol·K), and T is the temperature, which we assume to be constant.

Rearranging  

P = nRT/V.

Substituting the given values,

P = (3.7)(8.31)(298)/0.019 ≈ 12720 Pa

Converting to atmospheres: 1 atm = 101325 Pa.

Therefore, the pressure to which the air must be compressed is:

P/101325 atm/Pa ≈ 0.125 atm or 0.13 atm (rounded to two significant digits).

Therefore, the answer is 0.13 atm.

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a spring with a spring constant of 54n/m sits on a desk. the spring is 44cm long. a block of mass 0.12kg is placed on top of the spring. how high above the desk does the block rest?

Answers

A spring with a spring constant of 54 N/m is situated on a desk. A block of mass 0.12 kg is put on top of the spring, which is 44 cm long. The height above the desk where the block rests is 0.0783 meters.

When a spring is compressed or elongated by a certain distance x, it exerts a restoring force that is proportional to the distance x, with a spring constant k.

The block will come to rest at a certain height above the desk as a result of the restoring force. As a result, we'll utilize the concept of elastic potential energy and equilibrium to find the height above the desk where the block rests.

Step 1: Find the extension of the spring.

x = F/k

where F = m g

where m is the mass of the block, and g is the acceleration due to gravity.

Substitute values in the equation

x = (0.12 kg) (9.81 m/s²) / (54 N/m) = 0.022 m = 2.2 cm

The spring has expanded by 2.2 cm when the block is put on it.

Step 2: Calculate the height of the block.

The potential energy stored in the spring is transferred to the block when it is put on the spring, and the block gains potential energy. This is the energy that the block has before it starts moving.

When the spring and the block are in equilibrium, the block's potential energy is transformed into gravitational potential energy, which is expressed as mgh, where m is the mass of the block, g is the acceleration due to gravity, and h is the height above the desk where the block is located.

mgh = 1/2 k x²h = (1/2 k x²) / mgh = (1/2 (54 N/m) (0.022 m)²) / (0.12 kg) (9.81 m/s²)h = 0.0783 m = 7.83 cm

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what is the relationship between index of refraction and the speed of the light in the medium of the index of refraction?

Answers

The relationship between the index of refraction and the speed of light in a medium is that the higher the index of refraction is: the slower the speed of light in that medium

The index of refraction is a measure of how much a light ray is bent, or refracted, as it enters a material or medium. The amount of refraction increases as the index of refraction increases, which in turn causes light to travel slower in the medium.

The index of refraction is related to the speed of light in the medium because the amount of refraction affects the speed of light in that medium. The index of refraction is a ratio between the speed of light in a vacuum and the speed of light in a medium.

This is calculated as the speed of light in a vacuum (c) divided by the speed of light in the medium (v). This ratio is usually represented as n, and so the formula for the index of refraction is: n = c/v. As the index of refraction increases, the speed of light in the medium decreases.


In a medium with a low index of refraction, the speed of light is higher than in a medium with a higher index of refraction. This is because a low index of refraction means that the light ray is not being refracted very much, so it is able to travel faster.

A higher index of refraction means that the light ray is being refracted more, so it is forced to travel slower. This explains the relationship between the index of refraction and the speed of light in a medium; the higher the index of refraction, the slower the speed of light in that medium.

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a 6,300-kg truck runs into the rear of a 1,000-kg car that was stationary. the truck and car are locked together after the collision and move with speed 2 m/s. what was the speed of the truck before the collision?

Answers

The speed of the truck before the collision was 3.2 m/s.

The speed of the truck before the collision can be determined using the principle of conservation of momentum. Momentum is the product of mass and velocity. Therefore, the momentum of the truck-car system before the collision is equal to the momentum of the truck-car system after the collision.
Let us assume the speed of the car before the collision is zero. Then the momentum of the truck-car system before the collision is equal to the momentum of the truck alone. This can be expressed mathematically as:
Mbefore = MtruckVtruck = (6,300kg)(Vtruck)

Mafter = (6,300kg + 1,000kg)(2 m/s)

By equating the two equations, we can solve for V, which gives us a value of 3.2 m/s.

Therefore, the speed of the truck before the collision was 3.2 m/s.

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NEED HELP ASAP!!!!!!!!!!!!
Part B
Tape a meter stick to the side of the table. Make sure the zero end is on the floor. Carry out the experiment using the four drop heights you chose in task 1, part D. (You may want to have an adult drop the ball while you watch how high it bounces.) Perform three trials for each drop height, and record the data in the table. (You may choose to video the bounces and watch the video in slow motion to improve your data collection.) Finally, average the bounce height measurements to get a final reading. Round the average bounce heights to the nearest whole number.



Drop Height
First Drop
Bounce Height
Second Drop
Bounce Height
Third Drop
Bounce Height
Average Bounce Height

Answers

Pretty easy actually…
First drop:
Drop height: 6 feet
Bounce height: 5’2

Second drop:
Drop height: 5 feet
Bounce height: 4’4


Third drop:
Drop height: 4 feet
Bounce height: 3’1

Average bounce height: 4’2

a stone is thrown down off a bridge with a velocity of 5.6 m/s. what is its velocity after 3 seconds have passed?

Answers

The velocity of the stone after 3 seconds have passed can be calculated using the formula v=u + at, where v is the velocity, u is the initial velocity, a is the acceleration (in this case the acceleration due to gravity, which is 9.8 m/s2), and t is the time. Therefore, the velocity of the stone after 3 seconds have passed will be 5.6 + (9.8*3) = 23.4 m/s.

The acceleration due to gravity causes any object to accelerate as it moves. This acceleration is always constant and acts downwards. Therefore, an object thrown with an initial velocity of 5.6 m/s will continue to accelerate and its velocity will increase. After 3 seconds have passed, the object will have an increased velocity of 23.4 m/s. In addition, when the stone is thrown off the bridge, it is subject to air resistance, which works against the stone and causes it to slow down. The magnitude of air resistance is dependent on a number of factors, such as the shape and size of the object. As such, the stone's velocity after 3 seconds might be slightly lower than the calculated value of 23.4 m/s.


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a bicycle wheel of radius 40.0 cm and angular velocity of 10.0 rad/s starts accelerating at 80.0 rad/s2. what is the tangential acceleration of the wheel at this time point?

Answers

The tangential acceleration of the wheel at this time point is 32 m/s².

What is angular velocity?

The radius of the wheel, r = 40.0 cm = 0.4 m

The angular velocity of the wheel, ω = 10.0 rad/s

The angular acceleration of the wheel, α = 80.0 rad/s²

The tangential acceleration of the wheel  

tangential acceleration = r × angular acceleration (a = rα)

Substituting the values of r and α in the above equation,

Tangential acceleration = 0.4 m × 80.0 rad/s²

Tangential acceleration = 32 m/s²

The tangential acceleration of the wheel at this time point is 32 m/s².

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Suppose you are standing on a skateboard or on in-line skates and you toss a backpack full of heavy books toward your friend. What do you think will happen to
you and why? Explain your answer in terms of Newton's third law of motion.

Answers

Answer: According to Newton's third law of motion, when you toss a backpack full of heavy books towards your friend while standing on a skateboard or in-line skates, there will be an equal and opposite reaction force acting on you, causing you to move in the opposite direction, which may be backward due to the conservation of momentum.

8. describe the transformation between forms of mechanical energy that is happening to a falling skydiver before her parachute opens.

Answers

The transformation between forms of mechanical energy that is happening to a falling skydiver before the parachute opens: the skydiver transforms gravitational potential energy into kinetic energy.

And then after the parachute opens, he or she transforms kinetic energy into potential energy. Before a skydiver's parachute opens, a transformation between forms of mechanical energy is happening.

When a skydiver jumps from an airplane, he or she begins to gain kinetic energy, which is the energy of motion.

As the skydiver falls, he or she transforms gravitational potential energy, or the energy stored in an object's height, into kinetic energy. The skydiver's kinetic energy increases as his or her speed increases. This means that the amount of gravitational potential energy decreases.

The skydiver transforms all of his or her gravitational potential energy into kinetic energy as he or she approaches the ground. When the parachute opens, the transformation of energy occurs again. The skydiver now converts kinetic energy, or energy of motion, into potential energy.

The parachute increases the amount of air resistance acting on the skydiver, slowing his or her descent. This reduces the skydiver's speed and converts kinetic energy into potential energy. When the skydiver lands, all of the potential energy has been transformed into kinetic energy once again.

So, before the parachute opens, the skydiver transforms gravitational potential energy into kinetic energy, and then, after the parachute opens, he or she transforms kinetic energy into potential energy.

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the friends know that the field lines are a pictorial representation of the electric field at points in space. which of jacob's statements regarding the electric field vector and field lines is false?

Answers

Jacob's statement that is false is "The electric field vector is tangent to the electric field line at each point." The electric field lines indicate the direction of the electric field vector, but they are not necessarily tangent.

A vector is a quantity in physics that has a value and a direction. Examples of Vector quantities are: Velocity, Acceleration, Force, Momentum, and Impulse.

Electric field lines are a visual representation of the magnitude and direction of the electric field at a given point. For a point charge, the field lines originate from a positive charge and point away from a negative charge. The direction of the electric field vector is the same as the direction of the electric field lines, however, the field lines are not always tangent to the electric field vector.

complete question:

The friends know that the field lines are a pictorial representation of the electric field at points in space. Which of Jacob's statements regarding the electric field vector and field lines is false?

"The electric field vector is tangent to the electric field line at each point.""For a negative point charge, the electric field is directed radially outward.""The field line has a direction, indicated by an arrowhead, that is the same as that of the electric field vector.""For a positive point charge, the electric field is directed radially outward."

The answer is 1

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what object would absorb the most light? question 1 options: a large piece of white poster board a mirror a black t-shirt a red table cloth

Answers

The object that would absorb the most light is c. a black t-shirt.

The color black absorbs all wavelengths of visible light, while the other colors reflect certain wavelengths. Therefore, black is the most light-absorbent color. An object's color is determined by the light that it reflects.

When light shines on an object, some wavelengths of light are absorbed by the object, while other wavelengths are reflected back to our eyes. The wavelengths that are reflected determine the object's color. For example, a red object reflects red wavelengths of light and absorbs other wavelengths, making it appear red. Similarly, a black object absorbs all wavelengths of light, making it appear black. In conclusion, a black t-shirt would absorb the most light, as compared to a large piece of white poster board, a mirror, or a red tablecloth.

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suppose you were dragging a table across a rough floor. in this case, the potential energy for friction depends on which quantity or quantities? (choose all that apply)

Answers

In dragging a table across a rough floor, the potential energy for friction depends on the coefficient of friction, normal force, and distance traveled by the table, hence option (a), (b), and (c) are correct.

In this case, the potential energy for friction would depend on the following quantities:

Coefficient of friction: The coefficient of friction between the table and the floor would determine how much force is required to move the table and hence, the potential energy for friction.

Normal force: The normal force acting on the table due to the weight of the table and any objects placed on it would also affect the potential energy for friction.

Distance moved: The distance the table is moved would determine the amount of work done against friction and hence, the potential energy for friction.

Surface area: The surface area in contact between the table and the floor could also affect the potential energy for friction.

Overall, the potential energy for friction depends on a combination of factors, including the properties of the surfaces in contact, the force required to move the object, and the distance moved.

Therefore correct options are (a), (b), and (c).

Suppose you were dragging a table across a rough floor. in this case, the potential energy for friction depends on which quantity or quantities? (choose all that apply)

a. The total distance the table travels.

c. The coefficient of friction between the table and the floor.

d. The normal force that the floor exerts on the table.

e. There is no potential energy for frictional forces.

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Drag and drop the terms to correctly complete the prompt.
Current is produced in a conductor when it is moved through a
applying a force on the
in the conductor and causing them to
of generating current in a conductor by placing the conductor in a changing magnetic field is called
is no
because the magnetic lines of force are
:: physical connection
between the conductor and the magnet. The current is said to be induced in the conductor by the
magnetic field. The conductor, which is often a piece of wire, must be
to the magnetic lines of force in
order to produce the maximum force on the free electrons. The direction that the induced current flows is determined by the direction
of the lines of force and by the direction the wire is moving in the field.
This process
:: free electrons :: induction :: perpendicular :: move
There
::magnetic field

Answers

We can see here that correctly completing this prompt, we have:

Current is produced in a conductor when it is moved through a magnetic field. This process of  applying a force on the free electrons  in the conductor and causing them to move.

This process of generating current in a conductor by placing the conductor in a changing magnetic field is called induction. There is no physical connection between the conductor and the magnet. The conductor, which is often a piece of wire, must be perpendicular to the magnetic lines of force in order to produce the maximum force on the free electrons.

What is current?

In physics, current refers to the flow of electric charge in a circuit. It is measured in amperes (A) and is defined as the amount of charge that passes through a point in a circuit per unit time. In other words, current is the rate of flow of electric charge.

Current can flow through a variety of materials, such as wires or conductive solutions, and is driven by a potential difference, or voltage, between two points in a circuit.

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A mass is tied to a string and swung in a horizontal circle w a constant angular speed. Speed is doubled. What happens to the tension in the string?

Answers

The tension in the string becomes four times its original value when the angular speed is doubled.

When a mass is tied to a string and swung in a horizontal circle with a constant angular speed, the tension in the string is the centripetal force that keeps the mass moving in a circular path.

Step 1: Identify the relevant forces acting on the mass.

In this case, the centripetal force is the only force that needs to be considered, and it is provided by the tension in the string.

Step 2: Understand the relationship between centripetal force (Fc),

mass (m),

radius (r),

and angular speed (ω).

The centripetal force can be calculated using the formula:
Fc = m * r * ω^2
Step 3: Analyze the effect of doubling the speed (angular speed) on the tension in the string. Since the mass and radius remain the same, we can focus on the angular speed term in the formula.

When the angular speed is doubled, we have:
New angular speed (ω') = 2 * ω
Step 4: Calculate the new centripetal force (tension) in the string.

Substituting the new angular speed into the formula, we get:
Fc' = m * r * (ω[tex]')^2[/tex] = m * r * (2 * ω[tex])^2[/tex]
Step 5: Compare the new centripetal force (tension) with the original one. By expanding the equation, we find that:
Fc' = m * r * 4 * ω^2

= 4 * (m * r * ω[tex]^2)[/tex]

= 4 * Fc

This shows that when the angular speed is doubled, the tension in the string increases by a factor of 4.

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a model depicts two balloons of the same size with identical negative charges being moved toward one another at the same speed. how will the balloons interact with each other?

Answers

Answer:

they will repel, moving in opposite,

Explanation

a car is traveling at 40 m/s as it enters a turn of radius 25 meters. what minimum coefficient of friction must be maintained between the road and tires to make sure the car does not slide out of the turn?

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The minimum coefficient of friction required for a car travelling at 40 m/s to not slide out of a turn of radius 25 meters is 0.21.

This is determined using the equation for the maximum centripetal force that the car can withstand. This equation states that the maximum centripetal force is equal to the mass of the car times its speed squared divided by the radius of the turn multiplied by the coefficient of friction. Using this equation, 0.21 is the coefficient of friction that is required to make sure the car does not slide out of the turn.

The equation for maximum centripetal force can be written as:

F = m*v2/r * μ Where m is the mass of the car, v is the velocity of the car, r is the radius of the turn, and μ is the coefficient of friction.

Since we are solving for the coefficient of friction (μ), we can solve this equation for μ:

μ = m*v2/r * F

Plugging in the given values, we get:

μ = (1000 kg) * (40 m/s)2 / (25 m) * (10000 N) = 0.21

Therefore, the minimum coefficient of friction required for a car travelling at 40 m/s to not slide out of a turn of radius 25 meters is 0.21.

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the centripetal force in a collapsing cloud of gas and dust is strongest at the poles question 9 options: true false

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The given statement "centripetal force in a collapsing cloud of gas and dust is strongest at the poles" is - True.

Centripetal force refers to a force that drives an object toward a fixed point, which is the center of a circular path. For example, if you tie a ball to a string and whirl it around in a circle, the string exerts a centripetal force on the ball that keeps it moving in a circle.

The force of gravity is the most common centripetal force that we encounter in nature, and it is what drives the movement of planets, moons, and other celestial objects.

During the formation of a star, a cloud of gas and dust collapses inwards due to gravity. The cloud starts to rotate as it shrinks due to the law of conservation of momentum. The centripetal force in this situation is the gravitational force that holds the cloud together.

The gravitational force, on the other hand, is stronger at the poles of the cloud. The gravitational force increases as the distance between the particles in the cloud decreases. Because the poles of the cloud are closer together, the gravitational force is stronger, and the centripetal force is also stronger.

As a result, the centripetal force in a collapsing cloud of gas and dust is strongest at the poles.

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if two sacks, one twice as heavy as the other, are lifted the same vertical distances in the same time, how does the power required for each compare?

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If two sacks, one twice as heavy as the other, are lifted the same vertical distances in the same time, the power required for each is proportional to the weight lifted.

Power is the measure of work accomplished per unit time, it is measured in joules per second or watts. Power is a scalar quantity that tells us how quickly work is being done. Power is equal to the work done divided by the time taken to do the work. Work = force x distance, Power = work/time. From the above equations, it is clear that power and weight are proportional since force and weight are proportional.

In the case of two sacks, one twice as heavy as the other, the power required to lift the heavier sack is twice that required to lift the lighter sack, this is because the weight of an object affects how much force is required to lift it. The force required to lift an object is equal to the object's weight. Therefore, if the weight of an object is doubled, the force required to lift it is also doubled, and the power required to lift it is also doubled. In conclusion, if two sacks, one twice as heavy as the other, are lifted the same vertical distances in the same time, the power required for each is proportional to the weight lifted. The power required to lift the heavier sack is twice that required to lift the lighter sack.

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how fast is it moving when it reaches the top of its trajectory if the projectile is fired at a speed of 138 and an upward angle of 65 degrees?

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The projectile will be moving at a speed of 57.21 m/s when it reaches the top of its trajectory.

When a projectile is fired at a speed of 138 and an upward angle of 65 degrees, the speed at the top of the trajectory can be calculated. To solve this problem, you need to understand some basic physics concepts. Here's how you can solve this problem:
1. First, identify the given values and write them down:
Initial velocity (u) = 138 m/s
Angle of projection (θ) = 65 degrees
Acceleration due to gravity (g) = 9.81 m/s²
2. Now, break down the initial velocity into its horizontal and vertical components:
Initial velocity in the horizontal direction = u cos θ
Initial velocity in the vertical direction = u sin θ
3. Use the equation of motion to calculate the time taken by the projectile to reach the top of its trajectory:
u sin θ = gt/2
t = 2u sin θ/g
4. Use the time obtained in step 3 to calculate the velocity at the top of the trajectory:
v = u cos θ
Where,
v = final velocity
u = initial velocity
θ = angle of projection
5. Substitute the given values in the equation to get the final answer:
v = u cos θ
v = 138 cos 65
v = 57.21 m/s
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which term defines the distance from rest to crest, or from rest to trough?responsesamplitudeamplitudefrequencyfrequencyperiodperiodspeed

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Amplitude is not measured from peak to trough, but from rest to peak or rest to trough.

The highest and lowest points on the surface of a wave are called crests and troughs respectively. The vertical distance between the peak and the trough is the height of the waves. The horizontal distance between two successive peaks or troughs is called the wavelength.

The amplitude of a wave is the maximum displacement of a particle on a medium with respect to its position of rest.

The amplitude can be thought of as the distance between rest and the peak. The amplitude from the rest position to the dip position can be measured in a similar manner.

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a point charge q is far from all other charges. at a distance of 2 m from q the electric field is 20n/c. what is the force a charge of 5 coulombs feels

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The force a charge of 5 coulombs for a point charge 'q' which is far from all other charges can be calculated by Coulomb's law.

The Coulomb's law states that the force between two point charges is proportional to the product of the charges and inversely proportional to the square of the distance between them:

[tex]F = k * (q_1 * q_2) / r^2[/tex]

where F is the force,

k is Coulomb's constant ([tex]k = 9*10^9[/tex] N m² / C²),

q₁ and q₂ are the charges, and

r is the distance between the charges.

We know that there is only one charge, q, and it is far from all other charges, so we can assume that

q₁ = q and q₂ = 5 C.

We also know that the electric field at a distance of 2 m from q is 20 N/C. The electric field is related to the force per unit charge, so we can use the equation:

[tex]E = F / q_2[/tex]

Therefore To find the force F acting on a charge q₂ at that distance.

Rearranging this equation in terms of F, we get:

[tex]F = E * q_2[/tex]

Substituting the values we have, we get:

F = 20 N/C * 5 C = 100 N

Therefore, a charge of 5 coulombs would feel a force of 100 N due to the point charge q.

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