if a certain car, going with speed v1, rounds a level curve with a radius r1, it is just on the verge of skidding. if its speed is now doubled, the radius of the tightest curve on the same road that it can round without skidding is:

Answer:

It is a value that reading in the galvanometer must be multiplied with to get the ordinary unit

Explanation:

What is a galvanometer?

A galvanometer is an electromechanical instrument used for detecting and indicating an electric current.

A Number by which a certain function of the reading of a galvanometer must be multiplied to obtain the current value in ordinary units is a galvanometer constant

Answer:

112.5 J

Explanation:

I calculated it by K/G BY M/S TO POTENTIAL ENERGY.

Given values are:

The change in Potential energy is:

→ [tex]\Delta PE = mgh[/tex]

By substituting the values, we get

            [tex]= 1.0\times 9.8\times 15[/tex]

            [tex]= 147 \ J[/tex]

Thus the above response is correct.  

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Answer:

its it filled with energy

Answer:

The light slows down.

Explanation:

Answer:

c) Aeroplane

Explanation:

The aeroplane has the greatest mass than the other three objects, so it experiences the greatest gravitational force. Hence, the option (c) is the answer.

1) The longitudinal waves move in parallel direction to the source of vibration. The transverse waves move in perpendicular direction to the source of vibration . They are similar in the sense that energy is transferred in the form of waves.

2) Reflection occurs when waves bounce from a surface back toward the source. Refraction is when waves are deflected when the waves go through a substance.

3) The Law of Conservation of Energy

states that energy can neither be created

nor destroyed, it can only be transferred or

changed from one form to another.

Solution :

The expression for the intensity of light is given by :

[tex]$I=I_{max}\left(\frac{\sin \frac{\pi a \sin \theta}{\lambda}}{\frac{\pi a \sin \theta}{\lambda} }\right)^2$[/tex]

For a small angle, θ

sin θ = tan θ

        [tex]$=\frac{y}{L}$[/tex]

Therefore the above equation becomes,

[tex]$I=I_{max}\left(\frac{\sin \frac{\pi a y}{\lambda L}}{\frac{\pi a y}{\lambda L} }\right)^2 $[/tex]

The given data is

λ = 546.1 nm

L = distance between the slit and the screen = 140 cm

  = 1.40 m

a = width of the slit

  = [tex]$0.50 \times 10^{-3} \ m$[/tex]

Therefore,

[tex]$I=I_{max}\left(\frac{\sin \frac{\pi \times 0.50 \times 10^{-3} \times 4.10 \times 10^{-3}}{546.1 \times 10^{-9} \times 1.20}}{\frac{\pi \times 0.50 \times 10^{-3} \times 4.10 \times 10^{-3}}{546.1 \times 10^{-9} \times 1.20} }\right)^2 $[/tex]

  [tex]$=\left(\frac{0.170}{9.82}\right)^2$[/tex]

 [tex]$= 2.89 \times 10^{-4} \ I_{max}$[/tex]

Therefore the fractional intensity is   [tex]$\frac{I}{I_{max}}= 2.89 \times 10^{-4} $[/tex]

Answer:

L/E =de/dl so dl is 10m de=4m E=5N

Explanation:

L=(de x E)/dl = 2N

so when load is < effort it is speed multiplayer

Answer:

a = 0.16 [m/s²]

Explanation:

To solve this problem we must use the following equation of kinematics.

[tex]v_{f}=v_{o}+a*t\\[/tex]

where:

Vf = final velocity = 3.2 [m/s]

Vo = initial velocity = 1.1 [m/s]

t = time = 13 [s]

a = acceleration [m/s²]

Now replacing:

[tex]3.2=1.1+a*13\\2.1=13*a\\a=0.16[m/s^{2} ][/tex]

Answer:

0 m/s^2

Explanation:

If you're driving at constant speed in the same direction, your acceleration is always 0 m/s^2. acceleration is a vector, so any change in speed or direction would result in acceleration.

Answer:

The image formed by a convex mirror will always have its smaller than the size of the object no matter what the position of the object.

Explanation:

The image formed by a convex mirror will always have its smaller than the size of the object no matter what the position of the object.

Also notice that convex mirror always makes virtual images.

Another feature of the convex mirror is that an upright image is always formed by the convex mirror.

An important mirror formula to remember which is applicable for both convex and mirrors

Here:

'u' is an object which gets placed in front of a spherical mirror of focal

length 'f' and image 'u' is formed by the mirror.

Answer:

right side up

Explanation:

Answer:

Given = 55kg, 4.5 m

Unknown = Work done

Formula = (mg) × d

Solution = 2425.5 J

Answer = 2425.5 J

Explanation:

Formula we use,

→ W = (mg) × d

Then the value of work done is,

→ (55 × 9.8) × 4.5

→ 539 × 4.5

→ 2425.5 J

Hence, the work done is 2425.5 J.

heat and thermal energy can be differentiated as is that thermal energy is not actually transferred. It is not moving, but remains part of the system's internal energy. Heat, on the other hand, is a passing energy. H. Energy transferred from a hotter system.

In summary, thermal energy is the energy hipster. As such, it cannot be converted into other types of energy. Only the difference in thermal energy can be converted/used to do work. Such processes are never 100% efficient. Every energy form that cannot be recovered.

Thermal energy transfer occurs in three ways: convection, conduction and radiation. When heat energy is transferred between adjacent molecules that are in contact with each other, it is called conduction

Thermal energy and temperature are closely related. However, temperature is the average kinetic energy of matter particles and thermal energy is the total kinetic energy of matter particles.

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Answer:

resultant increases by factor of 1.12

Explanation:

EDITED :

Assume force = 1  for simplicity and one vector is on the x axis

at 55 degrees

   horizontal components = 1 + cos 55 = 1.574

   vertical component = sin 55 = .8192

         resultant = 1.77

at 15 degrees

    horizontal components = 1 + cos 15 = 1.966

    vertical component  = sin 15 = .2588

         resultant = 1.98

resultant increases by  1.98 / 1.77 = 1.12 original

Answer:

Explanation:

The velocity of sound wave is expressed using the formula;

[tex]v = f \lambda[/tex] where

f is the frequency

[tex]\lambda\\[/tex] is the wavelength

Given

f = 1300Hz

v = 38m/s

Required

wavelength [tex]\lambda\\[/tex]

From the formula;

[tex]\lambda\\[/tex] = v/f

[tex]\lambda\\[/tex] = 38/1300

[tex]\lambda\\[/tex] = 0.0292m

Hence the required value of the wavelength is 0.0292m

The wavelength of a stationary listener is 0.029 m.

The given parameters;

The wavelength of a stationary listener is calculated as follows;

[tex]v = f\lambda[/tex]

where;

λ is the wavelength of the sound wave

The value of the wavelength is determined as;

[tex]\lambda = \frac{v}{f} \\\\\lambda = \frac{38}{1300} \\\\\lambda = 0.029 \ m[/tex]

Thus, the wavelength of a stationary listener is 0.029 m.

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Answer:

The inertia of an object does not change as the objects velocity changes because the inertia will remain the same as long as the mass is the same.

:

Ranking Earthquake Intensity

Magnitude Average number per year Modified Mercalli Intensity

2.0 – 2.9 >1 million I

3.0 – 3.9 about 100,000 II – III

4.0 – 4.9 about 10,000 IV – V

5.0 – 5.9 about 1,000 VI – VII

Explanation:

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Explanation:

Because it is the easiest branch of science to understand

The average velocity during the time interval is (V)=4m/s.

Velocity is a expression of the displacement that an object or particle undergoes with respect to time. Velocity is a vector quantity. The average velocity means total distance divided by total time.

To calculate the average velocity we are using the formula,

Vₙ = (v₁+v₂)/2

Here we are known,

v₁= The position of a particle moving along the x-axis with the average velocity during the time interval from t = 1.0 s

v₂= The position of a particle moving along the same x-axis with the average velocity during the time interval from t = 4.0 s

We have to calculate, the average velocity during the time interval= Vₙ

To calculate the velocities we are using the formula,

v = dx/dt

Here, x=11+14t-2t²

v=dx/dt=14-4t

At, t=1.0s, v₁=14-4*1=10m/s

At, t=4.0s, v₂= 14-4*4=-2m/s

Now, the average velocity is,

Vₙ =(v₁+v₂)/2

Or, Vₙ =(10-2)/2

Or, Vₙ =4m/s

Thus from the above calculation we can conclude that, the average velocity during the time interval from t = 1.0 s to t=4.0 s is (V)=4m/s.

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The position of a particle moving along the x-axis is given by x = (11 + 14t – 2.0t²), where t is in seconds and x is in meters. What is the average velocity during the time interval from t = 1.0 s to t = 4.0 s

Answer:

a spring scale

Explanation:

i think it is correct

The statements that are true are

A satellite is a moon, planet of machine that orbits a planet or a star.

From the diagram, we see that X is a planet, Y is a planet and also a moon to X and z is amoon to Y and Z

Since X does not orbit Y but Y orbits X.

So, the statement is false.

Since Y does not orbit Z but Z orbits Y.

So, the statement is false.

Since X does not orbit Y but Y orbits X, and Z orbits Y.

Since only Z orbits Y, then the statement is false.

Since Z orbits Y and Y orbits X and invariably, Z also orbits X. So, Y and Z orbit X.

So, the statement is true

Since Y orbits X but Z orbits Y, Y is a satellite for X but not Z, since Z orbits Y and is a satellite for Y.

Since Y is only a satellite for X and not Z,

So, the statement is false.

Since Y orbits X, so Y is a satellite for X.

So, the statement is true.

Since Z orbits Y, so Z is a satellite for Y.

So, the statement is true

So, the statements that are true are

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Answer:

1.791 MN

Explanation:

Thrust of the rocket can be found using the relation

T = v.dm/dt, where

T = thrust off the rocket

v = speed of the rocket, 9 km/s = 9000 m/s

dm/dt = rate at which fuel burns, 199 kg/s

Substituting the values into the formula, we have

T = 9000 * 199

T = 1791000 N

T = 1.791*10^6 N

Since 1 MN = 10^6, thus

T = 1.791 MN

The thrust of the rocket in units of MN is 1.71 Meganewton.

Given the following data:

Conversion:

Relative speed = 9 km/s to m/s = 9000 m/s

To determine the thrust of the rocket in units of MN:

Mathematically, the thrust of an object is given by this formula:

[tex]Thrust = V\frac{dm}{dt}[/tex]

Substituting the given parameters into the formula, we have;

[tex]Thrust = 9000 \times 199[/tex]

Thrust = 1,791,000 Newton

In units of MN:

1 MN = [tex]1 \times 10^6\;N[/tex]

Thrust = 1.71 MN

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Answer:

a) [tex]F_{x} = 58.2 N[/tex]

[tex] F_{y} = 48.9 N [/tex]

b) a = 1.5 m/s²

Explanation:

a) The horizontal and vertical components of Emily's force can be found knowing the angle and the exerted force.

Since the handle is inclined at 40.0° below the horizontal we have:

[tex] F_{x} = |F|*cos(\theta) = 76.0 N*cos(40) = 58.2 N [/tex]

[tex] F_{y} = |F|*sin(\theta) = 76.0 N*sin(40) = 48.9 N [/tex]

b) The acceleration of the car can be calculated as follows:

[tex] F_{x} = ma [/tex]        

We used the horizontal component of the force because the cart is moving in that direction.

[tex] a = \frac{F_{x}}{m} = \frac{58.2 N}{38.8 kg} = 1.5 m/s^{2} [/tex]

Hence, the acceleration of the car is 1.5 m/s².    

I hope it helps you!

Answer:

hiiiiiiiiiiiii baby.........

Answer:

3.33s

Explanation:

Given parameters:

Acceleration  = 15m/s²

Initial velocity  = 0m/s

Final velocity  = 50m/s

Unknown:

Time taken for the acceleration  = ?

Solution:

To solve this problem, we must understand that acceleration is the rate of change of velocity with time.

Mathematically;

           a  = [tex]\frac{v - u}{t}[/tex]  

a is the acceleration

v is the final velocity

u is the initial velocity

t is the time taken

     So;

          15  = [tex]\frac{50 - 0}{t}[/tex]  

           15t  = 50

              t  = 3.33s

Answer:

25 N

If you’re doing ck-12

The object may be swung with maximum velocity of 7.07 m/s without breaking the string.

The centripetal force definition states that: The force applied to an item in curved motion that is pointed toward the axis of rotation or the centre of curvature is known as a centripetal force.

Newtons are used to measure centripetal force.

Given that:

mass of the object = 0.500 kg.

The length of the string = 1.00 m.

If the maximum speed of the object be v,

maximum centripetal force be = 0.5v²/1.0 N = v²/2 N.

As the maximum force the string can withstand without breaking is 25.0 N,

25.0 = v²/2

⇒ v = 5√2 m/s = 7.07 m/s.

Hence,   the object may be swung with maximum velocity of 7.07 m/s without breaking the string.

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Answer:

[tex]t = 0.55[/tex]

Explanation:

Given

[tex]Height, s = 1.5m[/tex]

[tex]Velocity, v = 70m/s[/tex]

Required

Determine the time to hit the ground

Using free fall formula:

[tex]S = \frac{1}{2}gt^2[/tex]

Take g as 9.8 and substitute value for S

[tex]1.5 = \frac{1}{2} * 9.8 * t^2[/tex]

[tex]1.5 = 4.9 * t^2[/tex]

Make t^2 the subject

[tex]t^2 = \frac{1.5}{4.9}[/tex]

[tex]t^2 = 0.30612244898[/tex]

Solve for t

[tex]t = \sqrt{0.30612244898[/tex]

[tex]t = 0.55[/tex] -- approximated

Answer:

Humans can detect sounds in a frequency range from about 20 Hz.

Answer:

Work done = 1/2 × Ne

Explanation:

Given that if  a force of N stretches a spring m beyond its natural​ length, how much work does it take to stretch the spring m beyond its natural​ length

Using Hook's law

Force = N

Let the extension = e

Work done in stretching spring m beyond its natural length will be

Workdone = 1/2 × Ne

Or

From Hook law,

N = Ke

Work done = 1/2 × Ke^2

velocity of the train is same so acceleration of the train is zero.

Acceleration of an object is known as change in velocity of the object. For a given interval of time.

Distance travelled by the train in first second is, d₁ = 6m

Distance travelled by the train in the 2nd second is, d₂ = 6m

Distance traveled by the train in 3rd second, d₃ = 6m

Formula for the velocity of the train.

v= d/t

where v is velocity

d is distance travelled

t is time taken

For first second velocity is

v₁ = d₁/t₁

v1 = 6/1s = 6m/s

for 2nd second velocity is

v₂= d₂/t₂

v₂ = 6/1 = 6m/s

for 3rd second velocity is

v₃ = d₃/t₃

v₃ = 6/1 = 6m/s

here we saw that the speed of train remains constant for each interval of time. So change of velocity is zero.

velocity of the train is same so acceleration of the train is zero.

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Answer:

The heat absorbed in each cycle is 9,234.286 J

Explanation:

Given;

power output, P = 5 kW = 5,000 W

efficiency of the engine, e = 30 % = 0.3

thermal heat expelled, [tex]Q_c[/tex] = 6464 J

let the heat absorbed = [tex]Q_h[/tex]

The efficiency of the engine is given as;

[tex]e = \frac{W}{Q_h} = \frac{Q_h-Q_c}{Q_h} = \frac{Q_h}{Q_h} - \frac{Q_c}{Q_h} = 1-\frac{Q_c}{Q_h}\\\\e = 1-\frac{Q_c}{Q_h}\\\\0.3 = 1-\frac{Q_c}{Q_h}\\\\\frac{Q_c}{Q_h} = 1-0.3\\\\\frac{Q_c}{Q_h} = 0.7\\\\Q_h = \frac{Q_c}{0.7} \\\\Q_h = \frac{6464}{0.7} = 9,234.286 \ J.[/tex]

Therefore, the heat absorbed in each cycle is 9,234.286 J.