Answer:
t = 10/9.81 = 1.02s
Explanation:
the ball will be up in the air for 1.02 seconds
Find the direction of vector A -> = ( 21m)x^ + ( -15m)y^ (in degrees)
Find the magnitude of vector A -> = (21m)x^ + (-15m)y^ (in meters)
Find the direction of vector B -> = (4.5m)x^ + (20m)y^ (in degrees)
Find the magnitude of vector B -> = (4.5m)x^ + (20m)y^ (in meters)
Find the direction of vector A-> + B -> (in degrees)
Find the magnitude of vector A-> + B -> (in meters)
Answer: ill do deeper reaseach because thats hard
Explanation:
The speed of sound is measured to be 340 m/s on a certain day.
What is this in Kilometers per hour?? s/km/h=
Please help and explain how to do these types of problems in very confused!!!
A pebble of mass 0.05kg is thrown vertically upwards. Give the direction and
magnitude of the net force on the pebble.
(a) During its upward motion.
(b) At the highest point where it is momentarily at rest.
In each case, 0.5N of force in a downward direction
No matter which way an object is moving, gravity's acceleration always works downward. In all three scenarios, the stone is just subject to the gravitational pull. According to Newton's second rule of motion, its magnitude is as follows:
Force=ma
Where, m is a mass of the pebble and a is acceleration due to gravity
F = Net force.
M = 0.05 kg of pebble mass
a=g=10m/s^2 F=0.05 × 10=0.5N
In all three scenarios, there is a downward-moving net force of 0.5N acting on the stone.
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At the mail racing championship in England, the winner moved at an average velocity of 2.4 mm/s [ford] for 140 s. Determine the winning snail's displacement during this time interval.
The displacement of the victorious snail will be 336.0mm .
The term displacement refers to a change in an object's position. It is a vector quantity and has a direction and magnitude .
We are given here,
Average velocity of snail = Δv = 2.4 mm/s
Time interval taken by snail = Δt = 140 s
The average velocity can be define as, the rate of change in displacement in the particular time interval of the object. The formula can be given as,
Δv = Δx / Δt
Where, Δv is the average velocity, Δx is the change in displacement, Δt is the time interval of an object. Unit can be written as meter/second.
Therefore, the displacement of snail during the race can be calculated by the relation i.e.
Δx = Δv × Δt
Thus , putting the values in above equation we get,
Δx = 2.4mm/s × 140s
Δx = 336.0 mm
Hence, the snail would move 336.0 mm in 140s.
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What distance has a car driven if it starts from rest and accelerates at a constant rate of 20 m/s/s for 7 seconds?
The distance traveled in meters is 290m. It can be solved using Newton's Laws of motion.
You can solve this problem by using the formula of
d = 1/2 a t^2
where d is the distance traveled in meters,
a = 20 m/s², and t =7 seconds
Plug-in the data to the formula and solve for the distance traveled after
7 s.
d = 1/2 a t^2
=1/2 × 20 × 7²
= 290m
Hence the dist travelled by the car is 290m
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Select the correct answer.
In the periodic table of elements, what do all of the elements in group 2 have in
common?
What is the direction of the velocity and
acceleration vectors of a baseball that is rising upward
towards its highest point above the ground?
Answer:
The direction of the velocity vector is upward and the direction of the acceleration vector is downward. A ball thrown straight upward moves initially with a decreasing upward velocity.
Explanation:
How much tension must a cable withstand if it is used to accelerate a 1000-kg car vertically upward at 0.60 m/s2 ?
Answer:
Approximately [tex]10410\; {\rm N}[/tex] (assuming that [tex]g = 9.81\; {\rm m \cdot s^{-2}}[/tex].)
Explanation:
There are two forces on this car:
Upward tension force from the cable, andDownward weight of the car (gravitational pull.)The net force on this car would be:
[tex](\text{net force}) = (\text{tension}) - (\text{weight})[/tex].
Rearrange to obtain:
[tex](\text{tension}) &= (\text{net force}) + (\text{weight})[/tex].
Let the mass of this car be [tex]m[/tex]. The weight of the car would be [tex]m\, g[/tex].
If the acceleration of the car is [tex]a[/tex], the net force on this car would be [tex]m\, a[/tex].
Thus:
[tex]\begin{aligned}(\text{tension}) &= (\text{net force}) + (\text{weight}) \\ &= m\, a + m\, g \\ &= (m)\, (a + g) \\ &= (1000\; {\rm kg}) \, (0.60\; {\rm m \cdot s^{-2}} + 9.81\; {\rm m\cdot s^{-2}}) \\ &\approx 10410\; {\rm N}\end{aligned}[/tex].
I throw a ball straight up, It takes 4 secs to reach the highest point. How high did the ball travel?
The height reached by the ball is 78.4 m.
What is Height?Height can be defined as the vertical distance between two points.
To calculate the height reached by the ball, we use the formula below.
Formula:
H = ut+gt²/2............ Equation 1Where:
H = Height reached by the ballt = Time taken to reach the heightu = Initial velocityg = acceleration due to gravityFrom the question,
Given:
t = 4 sg = 9.8 m/s²u = 0 m/sSubstitute these values into equation 1
H = (0×4)+(9.8×4²)/2H = 9.8×8H = 78.4 mHence, the height reached by the ball is 78.4 m.
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what is the general formula for measuring [tex] \vec{B} [/tex] , i.e. , magnetic field intensity ?
tysm ;-;
Explanation:
[tex]{ \rm{ \vec{B}} = \frac{ \mu_{0}N}{l} } \\ [/tex]
N is number of turns
l is conductor length
mu_0 is permeability
[tex]{ \boxed{ \tt{ \mu_{0} = 4\pi \times {10}^{ - 7} }}}[/tex]
#include <stdio.h>
int main()
{
const int LENGTH = 10;
const int WIDTH = 5;
const char NEWLINE = '\n';
int area;
area = LENGTH * WIDTH;
printf("value of area : %d", area);
printf("%c", NEWLINE);
return 0;
}
A coin is dropped from a height of {x} meters. Neglecting air resistance, how much
time (in seconds) was the coin in the air?
Please help
The time of motion of the coin is determined as t = √(0.204x).
What is time of motion of a projectile?
The time of motion of an object or a projectile is the time taken for the objects to travel from its initial position to the final position.
The time taken for the coin to fall from the given height "x" is calculated as follows;
h = vt + ¹/₂gt²
where;
h is the height from which the coin is dropped = xv is the initial vertical velocity of the coin = 0t is the time of motion of the coin g is acceleration due to gravity = 9.8 m/s²x = 0 + ¹/₂gt²
2x = gt²
t² = 2x/g
t = √(2x/g)
t = √(2x/9.8)
t = √(0.204x)
Thus, the time of motion of the coin is determined as t = √(0.204x)
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A bicycle with 26-inch diameter wheels is traveling at 20 mi/h. Find the angular speed of the wheels in rad/min.
______radians per minute.
How many revolutions per minute do the wheels make?
___revolutions per minute
A bicycle with 26-inch diameter wheels is traveling at 20 mi/h. Find the angular speed of the wheels in rad/min.
______radians per minute
___revolutions per minuteω = 1320 rad/min, Revolution per minutes = 210.084
Diameter = 24 in
Radius r = 24/2 in = 12 in = 12 × 2.54 cm = 30.48 cm = 0.3048 m
Linear Speed v= 15 mi/hr = 15 * 1609.34 / 3600 m/s = 6.7056 m/s
Angular Speed ω = v / r = (6.7056 m/s) / (0.3048 m) = 21.999945
ω = 22 rad/s = 22× 60 rad/min = 1320 rad/min
∴ 1 revolution = 2π rad
⇒1 rad = 1 / 2π rev
so 1320 rad/min = 1320 / 2π rev/min = 210.0845 rev/min
Revolution per minutes = 210.0845
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A 0.15 kg arrow is shot at +44 m/s. It hits an apple (m = 0.49 kg), and goes through the apple, leaving with a velocity of +28 m/s.
What is the velocity of the apple after the arrow leaves it?
A football player has a mass of 100 kg and can accelerate at 4 m/s². How much
force does this football player apply?
Answer: F=400 N
Explanation:
F=ma ==> F=force, m=mass, a=acceleration
F=100*4
F=400 N
What is the most common number of neutrons in an atom of argon?
1. A UEFA BAll is vertically Thrown up with an 'ni-
tial velocity of 25mls. Calculate;
i maximum height
Answer:
maximum height,h=31.25m
Explanation:
when an object is thrown vertically upward, v=0.
using the formula, v²= u²+2gh.
since the object is thrown upwards, g= -10m/s
v²=u²-2gh
0²=25²- 2×10×h
0=625-20h
20h = 625
h=31.25m
A dog running in an open field has components of velocity vx = 2.8 m/s and vy = -1.8 m/s at time t1 = 12.0 s. For the time interval from t1 = 12.0 s to t2 = 25.0 s, the average acceleration of the dog has magnitude 0.45 m/s2 and direction 36.0 ∘ measured from the +x-axis toward the +y-axis.
The x and y component of the dog's velocity at t₂ = 25.0 s is 7.53 m/s and 2.933 m/s respectively.
The magnitude of the dog's velocity is 8.076 m/s.
The velocity components of a dog running in an open field are:
[tex]v_{x}=2.8 {~}m/s\\v_{y}=-1.8{~}m/s[/tex] at t₁ = 12 sec.
The average acceleration of the dog in the time interval t₁ = 12 sec to t₂ = 25 sec is 0.45 m/s² and the direction 36°.
(A) The x component of the dog velocity at t₂ = 25 sec will be:
Vₓ = vₓ + aₓ(cos(36)) × (t)
Vₓ = 2.8 + ( 0.45) × (0.89) × ( 25 - 12 )
Vₓ = 2.8 + 4.7327
Vₓ = 7.53 m/s
(B) The y component of the dog's velocity at t₂ = 25 sec will be:
[tex]V_y=v_y+a_y(cos(\theta))t\\V_y=-1.8+(0.45)(cos(36))(25-12)\\V_y=-1.8+4.7327\\V_y=2.933{~}m/s[/tex]
(C) Therefore, the magnitude of the dog's velocity is:
[tex]V=\sqrt{(v_x)^{2}+(v_y)^{2}}\\V=\sqrt{(7.53)^{2}+(2.93)^{2}}\\ V=\sqrt{56.7+8.58}\\ V=\sqrt{65.28}\\ V=8.0796{~}m/s[/tex]
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The complete question is mentioned below:
A dog running in an open field has components of velocity vₓ = 2.8 m/s and [tex]v_y = -1.8{~} m/s[/tex] at time t₁ = 12.0 s. For the time interval from t₁ = 12.0 s to t₂ = 25.0 s, the average acceleration of the dog has a magnitude of 0.45 m/s² and a direction of 36.0° measured from the +x-axis toward the +y-axis.
(A) At time t₂ = 25.0 s, what is the x-component of the dog's velocity?
(B) At time t₂ = 25.0 s, what is the y-component of the dog's velocity?
(C) What is the magnitude of the dog's velocity?
i have no question d d d d
Answer:
okay
Explanation:
why don't you have any question in this app?
Imagine that a car is traveling from your left to your right at a constant velocity. Which two actions could the driver take that may be represented as (a) a velocity vector and an acceleration vector both pointing to the right and then (b) changing so the velocity vector points to the right and the acceleration vector points to the left?
Question 13 options:
(a) Push down on the brakes and then (b) push down on the accelerator.
(a) Push down on the brakes and then (b) push down on the brakes a second time.
(a) Push down on the accelerator and then (b) push down again on the accelerator a second time.
(a) Push down on the accelerator and then (b) push down on the brakes.
The two actions that the driver could take would be to (a) Push down on the accelerator and then (b) push down on the brakes, therefore the correct answer is option D.
What is Velocity?The total displacement covered by any object per unit of time is known as velocity.
When the driver pushes down on the accelerator the velocity and the acceleration would be in the same direction.
When he pushes down on the brakes the acceleration vector would point in the opposite that of velocity, therefore the correct answer is option D.
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What is electronegativity and how does it relate to the bonding of atoms? Define the terms valence electron, covalent bond, ionic bond, and metallic bond in your answer.
The tendency of an atom to attract electrons (or electron density) to itself is measured by its electronegativity. It determines the distribution of the shared electrons between the two atoms in a bond. The stronger an atom's electronegativity, the more strongly it would attract electrons to its bonds.
A single electron, or one of two or more, in an atom's outer shell is known a valence electron and is responsible for the chemical characteristics of the atom.When two or more nonmetal atoms bond together via sharing valence electrons, a covalent molecule is formed i.e. Covalent bonds are formed when two nonmetal atoms share valence electrons. When two atoms start sharing electrons, covalent bonds are formed. The positively charged atomic nuclei of the atoms attract the electrons to it.The complete transfer of valence pair of electrons) between atoms is referred to as an ionic bond. It is a kind of chemical bond that produces two ions with opposite charges. In ionic bonding, the nonmetal takes the lost electrons to form a negatively charged anion while the metal loses them to become a positively charged cations.In a metallic bond, which is a specific type of chemical bond formed between positively charged atoms, a lattice of cations shares the free electrons. Ionic and covalent bonds, On the other side, develop between two distinct atoms. The main kind of chemical bond that develops between metal atoms is known as metallic bonding.To know more about electronegativity
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Stone Bonner throws a football pass horizontally to his teammate. How could he
increase the range the ball covers during the throw?
There is nothing he could do to increase the range because gravity is constant.
He could throw the ball from a lower height.
He could choose a a football with less mass.
He could throw the ball with a greater horizontal velocity
He can increase the range of the ball covers during the throw by throwing the ball with a greater horizontal velocity
Assuming a projectile is launched from the ground level, the range is defined as the distance between the launch point and the point where the projectile hits the ground.
Range = [tex]u^{2}[/tex] sin (2 (theta )) / g
u = initial horizontal velocity
g= acceleration due to gravity
theta = angle of velocity vector with the ground
since , initial horizontal velocity is directly proportional to the range
hence , if we increase horizontal velocity range of the projectile will also increase .
hence , correct option is d) He could throw the ball with a greater horizontal velocity
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A person kicks a soccer ball off of a 20 meter hill and it lands 17 meters away. What
would be the final horizontal velocity of the soccer ball?
the final horizontal velocity of the soccer ball is 16.53 (m/s)
Typically, horizontal velocity is defined as horizontal displacement divided by time, expressed in units like meters per second or miles per hour. Simply put, displacement is the separation of a thing from its origin. V stands for the needed soccer ball's initial horizontal velocity (in m/s). T stands for the soccer ball's time of flight, expressed in seconds. The kinematic relations that result from the data given are as follows:
22 = 0 + (1/2) *g*T^2 [g = acceleration due to gravity]
or T^2 = 44/g
or T = √(44/g)
35 = V*T
or V = 35/T
or V = 35*√(g/44)
or V = 35*√ (9.81/44) (Assumed) g = 9.81 m/s2
V = 16.53 (m/s)
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John Deere, a U.S. company, sells a tractor to a farmer in Canada what Gdp category is it in?
John Deere, a U.S. company, sells a tractor to a farmer in Canada. It is a GDP category is net exports.
Who is a farmer?Farmers are the person who usually cultivates and grows crops. They often also have cattle farming also. These farmers earn money by selling the crops in the market.
As a person is exporting goods and services to the US market, then we can say that the person is an exporter of court. There is GDP which is gross domestic product the US company that sells the status to Canada will be termed as the net exporter and represented over in that category.
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4. A wave is described by the following equation: = 10i(40 − 2).
a) Identify the wavenumber and angular frequency and calculate the frequency, period, wavelength, and the speed of the wave. b) Draw the wave for t = 0.
The calculated answer is 320 cm/s.
The wave diagram is attached below.
The quantity of waves that pass a set location in a predetermined period of time is known as frequency. Therefore, if a wave passes through in half a second, the frequency is 2 per second. The frequency is 100 times per hour if it takes 1/100 of an hour. Even though the concept of frequency as it is commonly understood is based on events per second, other units of time, like minutes or hours, may also be employed.
For a wave with the equation y=Acos(kx)t,
k= 2 = 40cm² =0.157rad/cm,
v=28=50.3rad/s,
T= 1/ = 1/8Hz
=0.125s.
Wave speed = k = 0.157*50.3
= 320 cm/s
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Interpreting Graphics
6. Figure 1.9 shows position-time graphs of the straight-line movement of
two brown bears in a wildlife preserve. Which bear has the greater aver-
age velocity over the entire period? Which bear has the greater velocity
at t = 8.0 min? Is the velocity of bear A always positive? Is the velocity of
bear B ever negative?
Answer:
Time difference = T1-T2 = D1/V1-D2/V2 = D ( 1/V1-1/V2)
Time difference = 5.5 min = 5.5*60=330 sec, V1 = .09 m/s, V2= 1.9 m/s
330 = D (1/.9 – 1/1.9)
330= D(1.11-.5263)
330=D(.585)
D= 330/.585 = 564.3 m
Explanation:
Two batteries of 7 V and 13 V with the internal resistances 1 ohm and 2 ohm respectively are connected in parallel with a resistance of 12 22. Find the current through each branch of the circuit and the potential difference across 12 ohm resistance.
the current through each branch of the circuit and the potential difference across 12-ohm resistance is 0.711A
The flow of charge is the current. A component is used to measure current. Potential difference is measured between two points on either side of a component because it represents the energy transferred between two points in a circuit.
-12(I1+I2) -1I1+7=0
12(I1+I2) +1I1=7
For the loop
-12(I1+I2) -2I=13
From 1&2
2I -I1=13-7=6
I1=2I2-6
The crucial distinction between current and voltage. Current in the circuit flows due to voltage, which is the potential difference between two locations in an electric field. The term "current" refers to the rate at which electrons are moving.
I2=85/38=2.237A
I1=2I 2-6
I1=2 x 85/38-6=-1.526A
I=I1+I2=-1.526+2.237=0.711A
Potential difference across 12-ohm resistance
V=0.711 x 12=8.53 v
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A car travels 1,139 meters South, and 37 seconds what is the average velocity in meters per second to the South?
Answer:
see below
Explanation:
1 139 m / 37 s = 30.784 m/s South
WILL GIVE BRAINLIEST!!!!
How many revolutions around the Sun does Uranus complete by the time Jupiter finishes its orbit?
Answer:
0
Explanation:
it takes 84 years for Uranus to orbit the Sun. It only takes 12 years for Jupiter to orbit the Sun. So technically by the time that Jupiter finishes it's one, Uranus will not be able to even finish half of its orbit.
HELP ASAP!!!!!!
If a car goes along a straight road heading east and speeds up from 45 ft/s to 60 ft/s in 5 s, calculate the acceleration.
fus 2
a=
Note: If the speed were given in miles per hour, and the time were given in minutes, you could change the minutes to a
fraction of an hour and do the problem. The answer would be in miles/h².
Answer:
3ft/s²
Explanation:
[tex]a = \frac{60 - 45}{5} = 3ft \div {s}^{2} [/tex]
An 80.8 kg man is standing on a frictionless ice surface when he throws a 2.3 kg book at 11.8 m/s. With what velocity does the man
move across the ice?
VM= ? m/s in the opposite direction as the book
The amount of velocity does the man who standing on a frictionless ice surface move across the ice(V)= 1 m/s in the opposite direction as the book.
What is Velocity?Velocity of a particle is its speed and the direction in which it is moving.
It can also be described as the instantaneous rate of change of the particle's distance traveled.
How can we calculate the values of the velocity does the man move across the ice?To calculate the velocity we would be using the formula,
M₁U₁ + M₂U₂ = M₁V₁+ M₂V₂
Here we are given that,
Apply the law of linear momentum
Before the throw:
M₁=Man initial mass= 80kg,
U₁=Man's initial velocity = 0,
M₂=Book initial mass = 4kg,
U₂=Book's initial velocity = 0.
After the throw:
M₁=Man final mass = 80kg,
V₁=Man's final velocity = V.
M₂=Book final mass = 4kg,
V₂=Book final velocity = 20.
Now we put the values in the formula, we get,
M₁U₁ + M₂U₂ = M₁V₁+ M₂V₂
Or, (80x0) + (4x0) = (80V) + (4x20)
Or, 0=80V + 80
Or, 80V = -80
Or, V = -80/80
Or, V= -1m/s.
From the above calculation we can conclude that,
The amount of velocity does the man move across the ice(V)= 1 m/s in the opposite direction as the book
[Note: The (-)Ve sign shows that the opposite direction]
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