A and B being Hermitian operators means that they are equal to their own conjugate transpose.
What is a Hermitian operator?
A Hermitian operator is an operator that is equal to its own complex conjugate. This means that if an operator A is Hermitian, then A=A*. This property is important in quantum mechanics, since it guarantees that the eigenvalues of the operator are real.
AB ≠ BA
(AB + BA) = (A + B)*(A + B) = A*A + A*B + B*A + B*B
(AB + BA) is Hermitian since the conjugate transpose of a sum is the sum of the conjugate transposes.
i(AB-BA) = i(A - B)*(A - B) = -iA*A + iA*B -iB*A + iB*B
i(AB-BA) is Hermitian since the conjugate transpose of a sum is the sum of the conjugate transposes.
The expectation value of A2 is always real and non-negative since A2 is Hermitian and thus equal to its own conjugate transpose, which implies its eigenvalues are real.
If A2 = 2, then A can have eigenvalues of ±√2.
Hence, eigenvalues of A is ±√2.
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You rub a piece of wool upon your skin and your skin becomes negatively charged because it gained _____.
When you touch a piece of wool against your skin, your skin acquires a negative charge because of the conservation of charge, which caused it to gain a positive charge.
Charge is a material's property that can be transferred into another person's body. The transfer of the charge results in the generation of electricity. The following are some examples of charge's various properties: 1 Electric charge addition 2 Electric charge conservation 3 Electric charge quantization. Equations in chemistry are denoted by the capital letter Q to denote charge, with the elementary charge of an electron (e) serving as a standard unit. The coulomb is the SI-derived unit of charge (C). In electrical engineering, the ampere-hour (Ah) unit of charge is frequently used.Dipole Definition in Chemistry and Physics. by this primary information we can consider that when you rub a piece of wool upon your skin and your skin becomes negatively charged because it gained a positive charge as the result of conservation of charge.
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Position Collisions
Scenario 1: Fatima and Alberta are playing catch. Fatima is standing at
the door, while Alberta is standing 8m away to the right. Fatima throws a
paper ball to the right with a speed of 2.4m/s. Alberta realizes that she is
to far away and runs to the left at 0.6m/s. When and where will Alberta meet
the paper ball?
Answer:
t = (x_ball + 8 ) / 0.6
Explanation:
To solve this problem, we can use the equations of motion for the paper ball and Alberta, and then set them equal to each other to find the time and position where they will meet.
The equation of motion for the paper ball is:
x = x0 + v0t + (1/2)at^2
where x is the position of the paper ball, x0 is the initial position (the door), v0 is the initial velocity (2.4 m/s to the right), t is the time, and a is the acceleration (which is 0 for a thrown ball).
The equation of motion for Alberta is:
x = x0 + v0t + (1/2)at^2
where x is the position of Alberta, x0 is the initial position (8 m to the right), v0 is the initial velocity (-0.6 m/s to the left), t is the time, and a is the acceleration (which is 0 for a person running).
If we set these two equations equal to each other, we get:
x_ball = x_alberta
x0 + v0t + (1/2)at^2 = x0 + v0t + (1/2)at^2
This simplifies to:
x_ball = x_alberta
Then we know that both x_ball and x_Alberta are the same point in space (where Alberta met the paper ball)
Now to find time, we need to use one of the original equation for time t. Using equation of motion for Alberta,
x_Alberta = x0 + v0t
So, t = (x_Alberta - x0) / v0
t = (x_ball - 8 ) / (-0.6) = (x_ball + 8 ) / 0.6
The negative sign of velocity of Alberta tells that she is running towards left whereas ball is thrown towards right.
So we can find time and position where Alberta will meet the paper ball by plugging in the specific distance (x_ball) and known values for x0, v0 and acceleration.
Which of the following objects is not a close approximation of a thermal emitter?
A) hot, thin gas
B) a star
C) a filament in a light bulb
D) you
E) a planet
A thermal emitter cannot be accurately approximated by hot, thin gas.
Devices known as thermal emitters radiate heat from a heated component. Some of them can be used as broadband infrared light sources for applications in spectroscopy, for instance, when the very low brightness is acceptable. Some of them are special types of incandescent lamps, sometimes in a very compact form. Their emission may be fairly continuous, but not always with high calibration accuracy. Unique designs, such as the globar and the Nernst lamp. These sources occasionally have an infrared filter installed that only allows the transmission of infrared light in a specific spectral range.
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Jocelyn stood in the middle of a trampoline causing the springs around the edge to stretch. Her identical twin, Jennifer, who has the same mass, joined her in the center of the trampoline Which statement best describes the effect this had on the springs? A The springs maintained the same amount of displacement B The springs stretched to double the original displacement, C The spring displacement reduced to half of the original displacement
B. The springs stretched to double the original displacement, is the the statement that best describe the effect this had on the springs.
What is displacement?The displacement is the shortest distance in geometry and mechanics between the initial and final positions of a point P. From the starting position to the ending position of the point trajectory, it measures the length and direction of the net motion, or total motion, in a straight line. A displacement can be discovered by using the translation that joins the starting point and ending point.
Another way to define a displacement as a relative position is the relationship between a point's final position, or xf, and its starting position, or xi (resulting from motion). The corresponding displacement vector can be defined by the difference between the starting and final positions:
[tex]$ s=x_{\textrm {f}}-x_{\textrm {i}}=\Delta {x}}$[/tex]
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what is the upward acceleratiob of a helicopter with a mass of 5250 kg if a force of 11000 N acts upon it
Answer:
[tex]2.09 m/s^{2}[/tex]
Explanation:
The upward acceleration of an object can be calculated using the formula:
[tex]a = F / m[/tex]
where:
a is the acceleration of the object (in meters per second squared)
F is the force acting on the object (in newtons)
m is the mass of the object (in kilograms)
So in this case, we have:
[tex]a = 11000 N / 5250 kg = 2.09 m/s^2[/tex]
This is the upward acceleration of the helicopter when a force of 11000 N is acting on it.
A weight of 10 N hangs motionless from a spring. The spring is stretched 0.286 m from its original length. What is the force constant for the spring?
a-2.8 N/m
b-22 N/m
c-35 N/m
d-43 N/m
Answer:
C. -35N/m
Explanation:
Using Hooke's Law, we know that the elastic constant of a spring can be found with this formula:
[tex]F=-kx[/tex]
where:
[tex]F[/tex] is the force ( in Newtons)
[tex]k[/tex] is the constant ( in Newtons per meter)
[tex]x[/tex] is the extension ( in meters)
thus, by rearranging the formula we can get:
[tex]k=-\frac{F}{x}[/tex]
[tex]k = -\frac{10}{0.286}[/tex]
[tex]k=-34.96503N/m[/tex]
Rounding off the answer, we get -35N/m
Does a ball rolling on an inclined plane have the same acceleration on the way up as it does on the way down?
Answer:
The answer is below
Explanation:
The acceleration of a ball rolling down an inclined plane would be greater than that of the acceleration of a ball rolling up if acted upon by a force of equal magnitude. For a ball rolling down an inclined plane, the acceleration due to gravity (gsinθ) acts in the direction of motion of the ball thereby leading to an increase in the acceleration of the ball; while for a balling rolling upwards, the acceleration due to gravity acts in the direction opposite to the motion of the ball thereby leading to a decrease in the acceleration of the ball.
When you wear a backpack, your center of gravity shifts in which direction? A. up. B. back. C. forward. D. up and back
When we wear the backpack, the center of gravity will go to the back and up direction.
A location established in relation to an object or set of objects is the center of mass. It represents the system's average location as weighted by each component's mass. The center of gravity for straightforward stiff objects with homogeneous density is found at the centroid.
Because the center of mass of any body is situated where the majority of the body mass is concentrated, when we wear a backpack, the center of mass shifts toward the up and back.
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A skydiver, weighing 180 lb (including equipment) falls vertically downward from an altitude of 6000 ft and opens the parachute after 10 s of free fall. Assume that the force of air resistance, which is directed opposite to the velocity, is of magnitude 0. 75|v| when the parachute is closed and is of magnitude 12|v| when the parachute is open, where the velocity v is measured in ft/s. (A computer algebra system is recommended. Use g = 32 ft/s^2 for the acceleration due to gravity. Round your answers to two decimal places. ) (a) Find the speed of the skydiver when the parachute opens. Ft/s (b) Find the distance fallen before the parachute opens. Ft (c) What is the limiting velocity v_L after the parachute opens? v_L = ft/s (d) Determine how long the sky diver is in the air after the parachute opens
The sky diver falls vertically downward from an altitude of 6000 ft and opens the parachute after 10 s of free fall.
What is Acceleration?
Acceleration is the rate of change of velocity over time. It is basically a vector quantity, meaning it has both magnitude and direction. Acceleration is caused by a force and is measured in meters per second squared (m/s2).
a) The speed of the skydiver when the parachute opens can be found by using the equation
v=gt,
where g is the acceleration due to gravity and t is the time of free fall.
We can substitute the given values into the equation to find the speed.
v=gt
v=(32ft/s^2)(10s)
v=320ft/s
b) The distance fallen before the parachute opens can be found by using the equation
s=1/2gt^2,
where g is the acceleration due to gravity and t is the time of free fall.
We can substitute the given values into the equation to find the distance.
s=1/2gt^2
s=(1/2)(32ft/s^2)(10s)^2
s=16000ft.
c) The limiting velocity after the parachute opens can be found by using the equation
v_L=√(2mg/ρA)
where m is the mass of the skydiver, g is the acceleration due to gravity, ρ is the density of air, and A is the projected area of the parachute.
We can substitute the given values into the equation to find the limiting velocity.
v_L=√(2(180lb)(32ft/s^2)/(1.225kg/m^3)(6m^2))
v_L=30.68ft/s.
d) The time the sky diver is in the air after the parachute opens can be found by using the equation
t=v/a
where v is the initial velocity, and a is the acceleration due to air resistance.
We can substitute the given values into the equation to find the time.
t=v/a
t=(320ft/s)/(12ft/s^2)
t=26.67s.
So, the sky diver is in the air for 26.67s after the parachute opens.
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A 2.00-kilogram object weighs 19.6 newtons on Earth. If the acceleration due to gravity on Mars is 3.7 1 m/s^2, what is the object's mass on Mars
The 2.00-kilogram object weighs 19.6 newtons on Earth, its weight on the Mars is 2.00 kg.
The mass is known as the amount of matter which is contained in a body. It is a property which is consistent in a body regardless of the body's current location, gravitational pull and various other factors which exist.
Mass and weight are two separate quantities. Weight is computed as a product of mass and acceleration. Mass has a property to remain constant and it means that whether the object is on any planet, irrespective of that, it will be constant. The mass remains the same that is 2.00 kg.
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What s an asteroid?
1. A rocky orbiting object.
2. A type of moon.
3. A dying star.
4. A very small, around planet.
Answer:
A. rocky orbiting object
Answer:
A rocky orbiting object.
i hope it's helpful
A car goes into a skid and comes to a gradual stop, accelerating at a constant rate to do so. At the midpoint of the skid, how much of its kinetic energy has the car lost (as a percentage, give % as the units)?
The percentage of the lost kinetic energy of the car, at the midpoint of the skid, is 50%.
In physics, work is the measurement of the energy used to move objects. When you are walking, you're using energy to move your body so the work done would be greater than zero.
According to work-energy theorem, work is equal to force times displacement (W = F · x).
A type of energy is kinetic energy, which is the energy of a moving object. If an object is at rest, its kinetic energy is zero. Kinetic energy is equal to one half of a mass times velocity squared (KE = 0.5 · m · v²).
When a car goes into a skid and comes to a gradual stop, at the midpoint of the skid the car has spend 50% its kinetic energy. This is simply because the velocity of the car at the midpoint of the skid is half the velocity of the car when the car starts going into a skid, assuming constant acceleration.
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if the crumple zone exerts +200,000 N of force on the wall, how much force will the wall exert on the crumple zone?
Answer: -200,000N
(To be more specific, 200,000N in the opposite direction)
Explanation:
By Newton's 3rd law (Action reaction pair)
The crumple zone exerts a force on the wall, the wall will exert an equal but opposite force on the wall.
Same magnitude -> 200,000N
Opposite direction-> Include a negative sign as force is a vector which depends on both magnitude and direction.
An object is swung in a circle with the radius of 5 m. If the object makes one rotation in 2.2 sec, what is the velocity of the object?
Answer:
14.28 m/s
Explanation:
We use this equation to find ciruclar velocity: v = 2πr/T
Find your given:
r = 5 m
T = 2.2 s
Plug in your given into the equation:
v = 2π(5 m)/2.2 s
v = 14.28 m/s
Identity the following on the wave shown below:
Amplitude:
V, Wavelength
I neeed help pleaseeeee asap
Explanation:
Your wavelength is 0.4
Yout Amplitude is 1
A man is pushing a baby stroller. Compared to the magnitude of the force exerted on the stroller by the man, the magnitude of the force exerted on the man by the stroller is A larger. B zero. C smaller, but greater than zero. D the same
A man is pushing a baby stroller. Compared to the magnitude of the force exerted on the stroller by the man, the magnitude of the force exerted on the man by the stroller is the same.
From Newton's third law of motion, the force exerted on the stroller by the man is same as the force exerted on the man by the stroller but is in the opposite direction.
Thus, the magnitude of the force exerted on the stroller by the man and the magnitude of the force exerted on the man by the stroller is same but in opposite direction.
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Match Column A with Column B. Write the letter of your answer on the space provided.
Column A
1. boiling point
2. oven toasters
3. "C
4. "moving"
5. grease
6. thermometer
7. Energy at rest
8. Radiant energy
9. calories
10. coal
Column b
a. lubricants
b. Celsius
c. temperature
d. potential energy
e. 100 °C
f. electricity
g. kinetic fricion
h. heat
i. spontaneous combustion
j. light energy
k. energy
I meant to put chemistry not physics lol
Answer:
1. e
2. f
3. b
4. g
5. a
6. c
7. d
8. j
9. k
10. i
The points of Column A with Column B related to unit measurement, temperature and energy are matched with their appropriate option.
[tex]1-2-3-4-5-6-7-8-9-10\\ e-f-b-g-a-c-d-j-k-l[/tex]
What is energy?Energy is the capacity of a object to do a work. More the energy object posses, more the work it can do.
The main categories of energy
1. Kinetic—The energy of moving objects.2. Potential—The energy stored in objects.Let's match the point of Column A with Column B.
1. Boiling point of water is at 100 degree Celsius.2. Oven toasters is the electric device which runs on the electricity.3. "C" is symbol which represent the Celsius to show the temperature of a body on the Celsius scale.4. Kinetic friction is the force which is enforce between the moving surface. 5. Grease is used as the lubricants. This is a semi-solid lubricants used in moving or rotating system to avoid friction.6. Thermometer is device which is used to measure the temperature of the body.7. Energy at rest is called the potential energy. Potential energy is the stored energy of the body which it posses due its position.8. Radiant energy is the type of electromagnetic energy which is the form of light energy.9. Calories is the unit of measurement which is used to measure the energy of a body. 10. The burning of coal provides spontaneous combustion.Thus, the points of Column A with Column B related to unit measurement, temperature and energy are matched with their appropriate option.
[tex]1-2-3-4-5-6-7-8-9-10\\ e-f-b-g-a-c-d-j-k-l[/tex]
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The Cessna Cardinal, a single-engine light plane, has a wing with an area of 16. 2 m^2, and an aspect ratio of 7. 31. Assume the span efficiency factor is 0. 62. A. If the airplane is flying at standard sea-level conditions with velocity of 251 km/h, what is the induced drag when the total weight is 9800N b. Calculate the induced drag when the
The Cessna Cardinal, a single-engine light plane, has a wing area of 16.2 m² and an aspect ratio of 7.31 with span efficiency factor of 0.62 then the induced drag when the total weight is 9800 N is 18.8 N.
Given that,
Wing area (A) = 16.2m²
Aspect ratio (r) = 7.31
Efficiency factor (e) = 0.62
Weight of plane (W) = 9800 N
Velocity of airplane (v) = 251 km/h = 251× 5/18 = 69.72 m/s
We know,
Dynamic pressure (p) = 1/2ρv²
where ρ is density of plane = 1.225
p = 1/2 × 1.225 × 69.72 × 69.72 = 2977.29 pa
Lift coefficient Cl = W/p × A = W/(1/2ρv²) A
where, A is the area of wing
Cl = 9800/2977.29 × 16.2 = 0.203
Induced drag coefficient (Cd) = Cl²/πer² = (0.203 × 0.203)/(π × 0.62 × 7.31 × 7.31) = 0.041/(104.08) = 0.39×10⁻³
Induced drag (d) = p × A × Cd = 2977.29 × 16.2 × 0.39 × 10⁻³ = 18.8 N.
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A 15,000 kg rocket traveling at +230 m/s turns on its engines. Over a 6. 0 s period it burns 1,000 kg of fuel. An observer on the ground measures the velocity of the expelled gases to be −1,200 m/s
First, we need to calculate force of the rocket.
What is Velocity?
Velocity is a vector quantity that describes the rate and direction of a body's motion. It is represented by an arrow pointing in the direction of motion and having a length equal to the rate of motion. Velocity is a fundamental concept in classical mechanics and is defined as the rate of change of position with respect to time.
Calculate the force of the rocket:
F = ma = (15,000 kg)(230 m/s) = 3,450,000 kg m/s2
Calculate the force of the exhaust gases:
F = ma = (1,000 kg)(-1,200 m/s) = -1,200,000 kg m/s2
Calculate the net force on the rocket:
Net Force = F_rocket + F_exhaust = 3,450,000 kg m/s2 + (-1,200,000 kg m/s2) = 2,250,000 kg m/s2
Calculate the acceleration of the rocket:
a = F/m = (2,250,000 kg m/s2)/(15,000 kg) = 150 m/s2
Calculate the change in velocity of the rocket:
Δv = a × t = (150 m/s2)(6.0 s) = 900 m/s.
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PLEASE HELP ILL GUVE BRAINLIEST
energy is converted from kinetic energy to potential energy when you..
a. ski down a hill
b. climb a mountain
c. run around a level track
d. two of the above
Answer:
b. climb a mountain
Which of the following will produce a magnetic field?
a. moving particles
b. moving charged particles
c. changes at rest
d. none of the above
Answer:
b.
Explanation:
Answer:
b
Explanation:
when moving charged bodies move there is changing magnetic flux linking in the particles and thus magnetic field is created between them
A spring gains 2.34 joules of elastic potential energy as it is compressed 0.250 meter from its equilibrium position. What is the spring constant of this spring
According to the given information the spring constant is 74.9 J N/m
What are Joules Joules?joule, unit of work or energy in the International System of Units (SI); it is equal to the work done by a force of one newton acting through one metre. Named in honour of the English physicist James Prescott Joule, it equals 107 ergs, or approximately 0.7377 foot-pounds.
What does Joules sell?Established in the British countryside by Tom Joule in 1989, Joules is a true premium lifestyle brand with an authentic heritage. Now a truly multi-channel business, Joules designs and sells clothing, footwear, accessories, homeware, gifting and lifestyle product collections for all the family.
= PEs = 16kx² 234)
= 1/2k(25mm)² K
= 74.9 J N/m
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How does energy affect the appearance of light?
Answer:
The bigger the energy source the more light it makes
Answer:
Energy effects light by heat, and radiation. and the depth of it and how big and other things, radiation can change the appearance slightly and heat also.
for example energy can make light, the light bulb in my opinion is electricity turned off and on Etc.
Energy can be made by light also, and other things that are completely complicated. Just look into generators and how they do that and etc.
hello please help i’ll give brainliest
Answer:
D, the lithosphere. (CRUST AND UPPER MANTLE)
Explanation:
A tectonic plate (also called lithospheric plate) is a massive, irregularly shaped slab of solid rock, generally composed of both continental and oceanic lithosphere. Plate size can vary greatly, from a few hundred to thousands of kilometers across; the Pacific and Antarctic Plates are among the largest. Plate thickness also varies greatly, ranging from less than 15 km for young oceanic lithosphere to about 200 km or more for ancient continental lithosphere (for example, the interior parts of North and South America).
Information found on:
https://pubs.usgs.gov/gip/dynamic/tectonic.html#:~:text=A%20tectonic%20plate%20(also%20called,both%20continental%20and%20oceanic%20lithosphere.&text=Continental%20crust%20is%20composed%20of,such%20as%20quartz%20and%20feldspar.
How long does it take a plane, traveling at a constant speed of 130 m/s, to fly once around a circle whose radius is 2650 m
51.6 seconds long does it take a plane, traveling at a constant speed of 130 m/s, to fly once around a circle whose radius is 2650 m.
The time it takes for an object to travel once around a circle of radius r at a constant speed v can be found using the equation:
T = 2 x π x r ÷ v
where T is the time in seconds, pi is approximately 3.14, r is the radius of the circle in meters, and v is the speed of the object in meters per second.
Given a constant speed of 130 m/s and a radius of 2650 m, the time it would take for a plane to fly once around the circle would be:
T = 2 x π x 2650 m / 130 m/s
T = 51.6 sec
So, it would take approximately 51.6 seconds for a plane traveling at a constant speed of 130 m/s to fly once around a circle whose radius is 2650 m.
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Lithium is the lightest of metals and the least dense of all nongaseous elements. A pure lithium sample with a volume of 13.0cm^3 has a mass of 6.94g. What is the density of lithium?
Answer:
D(ensity) = M / V = 6.94 g / 13 cm^3 = .534 g / cm^3
Compare to H20 at 1 gm / cm^3
What is the intensity of 60 dB sound?
The intensity of 60 dB sound is 10⁻⁶ W/m².
A common conversation between two persons seated at a distance of around one meter (3 14 feet) is as loud as 60 dB. It is equivalent to the typical noise level in a restaurant or office.
The decibel scale is a logarithmic one rather than a linear one. Accordingly, 10 dB denotes a sound that is 10 times louder than 0 dB, which represents no sound at all. Now, a sound at 20 decibels is 100 times louder than one at 0 decibels. And so on until a sound that is 100 decibels is 1 billion times louder than total silence (0 decibels).
A sound at 60 dB is therefore 100 times louder than a sound at 40 decibels and 1000 times louder than a sound at 30 decibels, while being 10 times louder than a sound at 50 decibels.
The formula for sound volume is L = log(I/I₀), or (I/I₀) = 10^L.
Given that L = 60dB = 6bel and that we know that I₀ = 10⁻¹² W/m²,
I/I₀ = 10⁶.
or I = 10⁻¹² × 10⁶ = 10⁻⁶ W/m²
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An object of mass 3 kg is accelerated at 4 m/s2. What force is acting on the object?
Answer:
12 N
Explanation:
Given,
Mass ( m ) = 3 kg
Acceleration ( a ) = 4 m/s^2
To find : Force ( F ) = ?
Formula : -
F = ma
F
= 3 x 4
= 12 N
Therefore, the force acting on the object is 12 N.
Answer: 12 N
Explanation:
Assume this piston has a maximum pressure rating of 2.5 pounds-force per square inch [psi]. The force applied to the cylindrical piston is 100 newtons [N]. What is the diameter of the piston, in units of inches [in]
Explanation:
Always write what you know first about the problem
The surface of the piston that has the force applied is a circle
The area of a circle is pi x r^2
Pressure is Force / Area
Write this out
P = F / (pi x r^2)
solve for r
sqrt( F / (P x Pi)) = r
But dont forget that d = 2 x r
The diameter of the piston is equal to 3.38 inches.
What is pressure?The pressure can be defined as the force that is applied per unit area. Force will be applied perpendicular to the surface per unit area. pressure can be measured in the unit of pascal. A Pascal can be defined as the pressure exerted by one force Newton on one square area.
The mathematical expression to calculate pressure is:
Pressure = Force/area
Given, the maximum pressure of the piston, P = 2.5 psi
We know that 1 psi = 703.07 Kg/m²
P = 2.5 × 703.07 = 1757.67 Kg/m²
The force applied, F = 100N = 100/ 9.8 Kg = 10.20 Kg
The area of the piston, A = F/P
A = 10.20/1757.67
A = 0.00580 m²
Area of the piston, A = πr²
0.0058 = 3.14 × r²
r = 0.04297 m
Diameter, d = 2r = 0.0859 m
We know that one meter = 39.37 inch
The diameter of the piston, d = 0.0859 × 39.37 = 3.384 inch
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If two boxes, one with a mass of 4 kg and one with a mass of 10 kg are sitting on a shelf. Explain the differences in their amount of potential energy.
Answer:
The box with a mass of 10 kilograms would have a greater amount of potential energy than the box with a mass of 4 kilograms.
Explanation:
Potential energy can be defined as an energy possessed by an object or body due to its position.
Mathematically, potential energy is given by the formula;
[tex] P.E = mgh[/tex]
Where,
P.E represents potential energy measured in Joules.
m represents the mass of an object.
g represents acceleration due to gravity measured in meters per seconds square.
h represents the height measured in meters.
Let's assume the height is 5 meters.
Acceleration due to gravity, g = 10 m/s²
For box with mass of 10 kg
[tex] P.E = 10*10*5[/tex]
P.E = 500 Joules.
For box with mass of 4 kg;
[tex] P.E = 4*10*5[/tex]
P.E = 200 Joules.
Hence, the box with a mass of 10 kilograms would have a greater amount of potential energy than the box with a mass of 4 kilograms.