If 21.6 g of NO and 13.8 g of O₂ are used to form NO₂, how many moles of excess reactant will be left over? 2 NO (g) + O₂ (g) → 2 NO₂ (g)

Answers

Answer 1

Answer: 0.071 moles of excess reactant [tex](O_2)[/tex] will be left over.

Explanation:

To calculate the moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}[/tex]

a) moles of [tex]NO[/tex]

[tex]\text{Number of moles}=\frac{21.6g}{30.01g/mol}=0.720moles[/tex]

b) moles of [tex]O_2[/tex]

[tex]\text{Number of moles}=\frac{13.8g}{32g/mol}=0.431moles[/tex]

[tex]2NO(g)+O_2(g)\rightarrow 2NO_2(g)[/tex]

According to stoichiometry :

2 moles of [tex]NO[/tex] require 1 mole of [tex]O_2[/tex]

Thus 0.720 moles of  [tex]NO[/tex] require=[tex]\frac{1}{2}\times 0.720=0.360moles[/tex] of [tex]O_2[/tex]

Thus [tex]NO[/tex] is the limiting reagent as it limits the formation of product and [tex]O_2[/tex] is the excess regaent.

moles of [tex]O_2[/tex] left = (0.431-0.360) = 0.071 moles


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Answer:

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Answer:

Solution A : calcium hydroxide

Solid B : calcium oxide

Gas C : Hydrogen gas

Explanation:

i) When metals react with water they form hydroxides thus calcium hydroxide

ii) When metals eact with oxygen they form oxides.

iii) Wehn metals react with hydrochloric acid they form a salt and a gas hydrogen.

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Answer:

A. 4 cm, 40 mm

B. 5.5 cm, 50 mm

C. 8.8cm, 80 mm

D. 8.2 cm, 82 mm

E. 9.5cm, 95 mm

Explanation:

NB: 1 cm = 10 mm

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Answers

Answer:

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Explanation: I took the test and i got 100%

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There are 6 atoms of oxygen per molecule of C₆H₁₂O₆. Considering that there are 6 molecules, the total number of atoms of oxygen are:

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There are 36 oxygen atoms in the representation "6 C₆H₁₂O₆".

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Answer:

The opposite of an endothermic process is an exothermic process, one that releases or "gives out" energy, usually in the form of heat and sometimes as electrical energy.

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Hope this helps you. Have a nice day. Please mark as brainliest. It helps a lot. ^_^

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Explanation:

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Answers

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I guess

Answer:

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