Answer:
Number of dollar = 28.28 (Approx)
Step-by-step explanation:
Given:
176 dollar = 140 pound
1 pound = Rs.130
Find:
Number of dollars in Rs 2925
Computation:
1 pound = Rs.130
Number of pound = 2925 / 130
Number of pound = 22.5 pound
1 pound = 176 / 140
Number of dollar = [176 / 140]22.5
Number of dollar = 28.28 (Approx)
Given the g(x) function, what is the best estimate for the instantaneous rate of change at x=3? g(x) =x^2−2x+5
Answer:
4
Step-by-step explanation:
g(x) = x² − 2x + 5
g'(x) = 2x − 2
g'(3) = 4
show all work!!!!! brainleist will be given!
Answer:
+30
Step-by-step explanation:
1255- 1075 = 180
180 /6 = 30
A packet of candles and box of matches cost #420. The candles cost 20 times as much as the matches
Answer:
candles = $400
matches = $20
Step-by-step explanation:
Let cost of candles = $c
Let cost of matches = $m
c = 20 m (20 times m)
c + m = 420
20m + m = 420
21 m = 420
m = 20
c = 20 (20) = 400
Which is true about the polynomial 9x²y – 6x - 5y^2
Answer:
D
Step-by-step explanation:
It is a trinomial with a degree of 3.
This is the correct answer on the exam.
The radius of a nitrogen atom is 5.6 × 10-11 meters, and the radius of a beryllium atom is 1.12 × 10-10 meters. Which atom has a larger radius, and by how many times is it larger than the other?
Answer:
Beryllium, 2 times
Step-by-step explanation:
1.12×10⁻¹⁰ has a higher exponent than 5.6×10⁻¹¹.
-10 > -11
The ratio between them is:
(1.12×10⁻¹⁰) / (5.6×10⁻¹¹)
(1.12 / 5.6) (10⁻¹⁰ / 10⁻¹¹)
0.2 × 10¹
2
Score: 16.17/50
25/50 answered
Question 29
Juan invests $5,000 at 11% simple interest for 1 year. How much is in the account at the end of the 1 yea
period?
Answers
Submit Question
Answer:
There will be $4450 left at the end of the year.
Step-by-step explanation:
We first take 11% and multiply it by $5,000. We get 550. This means that the account will lose $550. Next, we take our original amount, $5,000, and subtract $550 from it. We will get $4450.
How to find the length of AB
Answers
A. 11.62
B. 27.22
C. 19.78
D. 22.02
Answer:
The answer is option C
Step-by-step explanation:
To find the length of AB we use sine
sin∅ = opposite / hypotenuse
From the question
The hypotenuse is AB
The opposite is AC
So we have
sin 54 = AC/AB
sin 54 = 16 / AB
AB = 16/sin 54
AB = 19.777
AB = 19.78Hope this helps you
Answer:
AB = 19.78
Step-by-step explanation:
From the diagram (Right-angle triangle):
AC = 16
AB = ?
Angle = 54°
Applying trig ratio:
Tan 54° = 16/BC
1.376381920 = 16/BC
Therefore;
BC = 16/1.376381920
BC = 11.62
To solve the length AB:
Cos 54° = BC/AB
0.587785252 = 11.62/AB
Solving AB gives:
AB = 11.62/0.587785252
AB = 19.78
A crew clears brush at a rate 2/3 acre in 2 days. How long will it take the same crew to clear the entire plot of 4 acres?
Answer:
It takes the crew 12 days to clear the bush.
Step-by-step explanation:
Given clears 2/3 acres / 2 days, or 1/3 acre per day
Time to clear 4 acres
= 4 / (1/3)
= 4 * (3/1)
= 12 days
This table shows values that represent an exponential function. What is the average rate of change for this function for the interval from x=3 to x=5?
Answer: The average rate of change for this function for the interval from x=3 to x=5 is 12.
Step-by-step explanation:
Complete question is provided in the attachment below.
Formula: The average rate of change for this function y=f(x) for the interval from x= a to x= b :
[tex]Rate =\dfrac{f(b)-f(a)}{b-a}[/tex]
Let y= f(x) for the given table:
At x= 3 , f(3)=8 and f(5)=32
Then, the average rate of change for this function for the interval from x=3 to x=5:
[tex]Rate=\dfrac{f(5)-f(3)}{5-3}\\\\=\dfrac{32-8}{2}\\\\=\dfrac{24}{2}=12[/tex]
Hence, the average rate of change for this function for the interval from x=3 to x=5 is 12. (Option A is correct.)
A car travels 133 mi averaging a certain speed. If the car had gone 30 mph faster, the trip would have taken 1 hr less. Find the car's average speed.
Answer:
49.923 mph
Step-by-step explanation:
we know that the car traveled 133 miles in h hours at an average speed of x mph.
That is, xh = 133.
We can also write this in terms of hours driven: h = 133/x.
If x was 30 mph faster, then h would be one hour less.
That is, (x + 30)(h - 1) = 133, or h - 1 = 133/(x + 30).
We can rewrite the latter equation as h = 133/(x + 30) + 1
We can then make a system of equations using the formulas in terms of h to find x:
h = 133/x = 133/(x + 30) + 1
133/x = 133/(x + 30) + (x + 30)/(x + 30)
133/x = (133 + x + 30)/(x + 30)
133 = x*(133 + x + 30)/(x + 30)
133*(x + 30) = x*(133 + x + 30)
133x + 3990 = 133x + x^2 + 30x
3990 = x^2 + 30x
x^2 + 30x - 3990 = 0
Using the quadratic formula:
x = [-b ± √(b^2 - 4ac)]/2a
= [-30 ± √(30^2 - 4*1*(-3990))]/2(1)
= [-30 ± √(900 + 15,960)]/2
= [-30 ± √(16,860)]/2
= [-30 ± 129.846]/2
= 99.846/2 ----------- x is miles per hour, and a negative value of x is neglected, so we'll use the positive value only)
= 49.923
Check if the answer is correct:
h = 133/49.923 = 2.664, so the car took 2.664 hours to drive 133 miles at an average speed of 49.923 mph.
If the car went 30 mph faster on average, then h = 133/(49.923 + 30) = 133/79.923 = 1.664, and 2.664 - 1 = 1.664.
Thus, we have confirmed that a car driving 133 miles at about 49.923 mph would have arrive precisely one hour earlier by going 30 mph faster
plzzzz solve the second one
Answer:
x=10/3
Step-by-step explanation:
isolate the variable
Answer:
1. x = 4
2. x = 10/3
Step-by-step explanation:
1. 3x - 5 = 3 + x
3x - x = 3 + 5
2x = 8
x = 4
2. x/2 + 5/9 = 2x/3
(x/2 + 5/9) * 18 = (2x/3) * 18
9x + 10 = 12x
10 = 12x - 9x
10 = 3x
x = 10/3
A motorcycle stunt rider jumped across the Snake River. The path of his motorcycle was given
approximately by the function H(1) 0.0004.x2 + 2.582 + 700, where H is measured in
feet above the river and is the horizontal distance from his launch ramp.
How high above the river was the launch ramp?
What was the rider's maximum height above the river, and how far was the ramp when he reached maximum height?
Correct question:
A motorcycle stunt rider jumped across the Snake River. The path of his motorcycle was given
approximately by the function H(t) = - 0.0004.x2 + 2.582 + 700, where H is measured in
feet above the river and is the horizontal distance from his launch ramp.
How high above the river was the launch ramp?
What was the rider's maximum height above the river, and how far was the ramp when he reached maximum height?
Answer:
A) 700 feet ; 4866.7025 feet above the river
3227.5 Feets from the ramp
Step-by-step explanation:
Given the Height function:
H(t) = 0.0004x^2 + 2.582x + 700
H = height in feet above the river
x = horizontal distance from launch ramp.
How high above the river was the launch ramp?
H(t) = - 0.0004x^2 + 2.582x + 700
To find height of launch ramp above the river, we set the horizontal distance to 0, because at this point, the motorcycle stunt rider is on the launch ramp and thus the value of H when x = 0 should give the height of the launch ramp above the river.
At x = 0
Height (H) =
- 0.0004(0)^2 + 2.582(0)+ 700
0 + 0 + 700 = 700 Feets
B) Maximum height abive the river and how far the rider is from the ramp when maximum height is reached :
Taking the derivative of H with respect to x
dH'/dx = 2*-(0.0004)x^(2-1) + 2.582x^(1-1) + 0
dH'/dx = 2*-(0.0004)x^(1) + 2.582x^(0) + 0
dH'/dx = - 0.0008x + 2.582
Set dH'/dx = 0 and find x:
0 = - 0.0008x + 2.582
-2.582 = - 0.0008x
x = 2.582 / 0.0008
x = 3227.5 feets
To get vertical position at x = 0
Height (H) =
- 0.0004(3227.5)^2 + 2.582(3227.5)+ 700
- 4166.7025 + 8333.405 + 700
= 4866.7025 feet
4866.7025 feet above the river
3227.5 Feets from the ramp
Using quadratic function concepts, it is found that:
The launch ramp was 700 feet above the river.The maximum height is of 4866.7 feet.The ramp was 3227.5 feet along when he reached maximum height.The height after x seconds is given by the following equation:
[tex]H(x) = -0.0004x^2 + 2.582x + 700[/tex]
Which is a quadratic equation with coefficients [tex]a = -0.0004, b = 2.582, c = 700[/tex]
The height of the ramp is the initial height, which is:
[tex]H(0) = -0.0004(0)^2 + 2.582(0) + 700 = 700[/tex]
Thus, the launch ramp was 700 feet above the river.
The maximum height is the h-value of the vertex, given by:
[tex]h_{MAX} = -\frac{\Delta}{4a} = -\frac{b^2 - 4ac}{4a}[/tex]
Then, substituting the coefficients:
[tex]h_{MAX} = -\frac{(2.582)^2 - 4(-0.0004)(700)}{4(-0.0004)} = 4866.7[/tex]
The maximum height is of 4866.7 feet.
The horizontal distance is the x-value of the vertex, given by:
[tex]x_V = -\frac{b}{2a} = -\frac{2.582}{2(-0.0004)} = 3227.5[/tex]
The ramp was 3227.5 feet along when he reached maximum height.
A similar problem is given at https://brainly.com/question/24705734
Find the most general antiderivative of the function.
(x) = 3/5 - 8/x, x > 0
Answer:
[tex]F = \frac{3}{5} x - 8\cdot \ln |x| + C[/tex]
Step-by-step explanation:
Let be [tex]f(x) = \frac{3}{5}-\frac{8}{x}[/tex] and [tex]F[/tex] is the antiderivative of [tex]f(x)[/tex] such that:
1) [tex]F = \int {\left(\frac{3}{5}-\frac{8}{x} \right)} \, dx[/tex] Given.
2) [tex]F = \frac{3}{5} \int \, dx -8\int {\frac{dx}{x} }[/tex] ([tex]\int {[f(x)+g(x)]} \, dx = \int {f(x)} \, dx + \int {g(x)} \, dx[/tex])
3) [tex]F = \frac{3}{5} x - 8\cdot \ln |x| + C[/tex], where [tex]C[/tex] is the integration constant. ([tex]\int {k} \, dx = k\cdot x[/tex]; [tex]\int {\frac{dx}{x} } = \ln|x|[/tex], [tex]\int {k\cdot f(x)} \, dx = k\int {f(x)} \, dx[/tex]) Result.
Please answer this correctly without making mistakes
Answer: 4.3 mi
Step-by-step explanation:
From Oxford, getting to Kingswood takes 7.5mi, and getting to Norwood takes 11.8mi. Thus, simply do 11.8-7.5 to get 4.3mi.
Hope it helps <3
Helpppp asapppppp....
Answer:
C.
Step-by-step explanation:
So, here's what you need to remember:
If we have a function f(x) and a factor k:
k(f(x)) will be a vertical stretch if k is greater than 1, and a vertical compression if k is greater than zero but less than 1.
f(kx) will be a horizontal compression if k is greater than 1, and a horizontal stretch if k is greater than zero but less than 1.
We are multiplying 0.5 to the function. In other words: 0.5f(x).
This is outside the function, so it's vertical.
0.5 is less than 1, so this would be a vertical compression
You have a spool of ribbon that is 279 inches long. How many 4 1/2-inch pieces can
you cut? Write your answer as a mixed number
Answer:
62
Step-by-step explanation:
Turn 4 and 1/2 into a decimal.
4.5
Divide 279 by 4.5
279/4.5=62
You can cut 62 4 and 1/2 inch pieces.
PLZ help me !!!!!! QUICKLY
What is the solution to the inequality −1/6e ≥ 2 ?
Answer:
e < -12Step-by-step explanation:
In algebra, we always need to follow a set of steps that involve undoing the operations that led to the equation to reveal the value of x.
Step 1: Divide by -1/6e < -12
(Since we divided by a negative number, we must reverse the inequality sign.)
Step 2: Check(-1/6)(-12) > 2
2 > 2 ✅
Now we check a number less than -12, such as -14.
(-1/6)(-14) > 2
2 1/3 > 2 ✅
The correct answer is: e < -12I'm always happy to help :)Consider the Equation y > 3x + 1 (a) Find an ordered pair that satifies the equation (b) Is the equation a Releation? explain (c) Is the equation a Function? explain
Answer:
(a) (1,5)
(b) Every subset of a cartesian product is a relation, therefore this is a relation.
(c) The relation IS NOT a function.
Step-by-step explanation:
(a)
(1,5)
Notice that 3(1) +1 = 4 < 5 therefore (1,5) is an order pair that satisfies the equation.
(b)
Every subset of a cartesian product is a relation, therefore this is a relation.
(b)
A relation is a function of the following condition holds
if (a,b) and (c,b) belong to the relation then (a=c)
In this case, (1,5), (0,5) belong to the relation but 0 is different than 5, therefore the relation IS NOT a function.
heLpPppPPpppPPpppppPPpppPPpppPPpppPPPpppPPPpppPPPPppppp
Answer:
Triangle D is your answer.
Answer:
Hey there!
Triangle C is unique, as one side and two angles determine a unique triangle.
Hope this helps :)
Find the dimensions of a rectangle with area 512 m2 whose perimeter is as small as possible. (If both values are the same number, enter it into both blanks.)
Answer:
√512 by √512Step-by-step explanation:
Length the length and breadth of the rectangle be x and y.
Area of the rectangle A = Length * breadth
Perimeter P = 2(Length + Breadth)
A = xy and P = 2(x+y)
If the area of the rectangle is 512m², then 512 = xy
x = 512/y
Substituting x = 512/y into the formula for calculating the perimeter;
P = 2(512/y + y)
P = 1024/y + 2y
To get the value of y, we will set dP/dy to zero and solve.
dP/dy = -1024y⁻² + 2
-1024y⁻² + 2 = 0
-1024y⁻² = -2
512y⁻² = 1
y⁻² = 1/512
1/y² = 1/512
y² = 512
y = √512 m
On testing for minimum, we must know that the perimeter is at the minimum when y = √512
From xy = 512
x(√512) = 512
x = 512/√512
On rationalizing, x = 512/√512 * √512 /√512
x = 512√512 /512
x = √512 m
Hence, the dimensions of a rectangle is √512 m by √512 m
What is the best way to remember the 6 trigonometric ratios?
Answer:
SOHCAHTOA
Step-by-step explanation:
Usually, in American schools, the term "SOHCAHTOA" is used to remember them. "SOH" is sine opposite hypotenuse, "CAH" is cosine adjacent hypotenuse, and "TOA" is tangent opposite adjacent. There is also Csc which is hypotenuse/opposite, Sec which is hypotenuse/adjacent, and Cot is adjacent/opposite.
Answer: SOHCAHTOA
Step-by-step explanation:
The pneumonic I learned is SOH-CAH-TOA. it says that Sin = opposite/hypotenuse. Cos = adjacent/hypotenuse. Tan = opposite/adjacent.
Hope it helps <3
What is the slope of the line shown below (3,9) (1,1)
Answer:
slope m = 4Step-by-step explanation:
The formula of a slope:
[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]
We have the points
[tex](3;\ 9)\to x_1=3;\ y_1=9\\(1;\ 1)\to x_2=1;\ y_2=1[/tex]
Substitute:
[tex]m=\dfrac{1-9}{1-3}=\dfrac{-8}{-2}=4[/tex]
Answer:
m=4
Step-by-step explanation:
Slope can be found using the following formula:
[tex]m=\frac{y_{2} -y_{1} }{x_{2} -x_{1} }[/tex]
where [tex](x_{1},y_{1})[/tex] and [tex](x_{2},y_{2})[/tex] are points on the line.
We are given the points (3,9) and (1,1). Therefore,
[tex]x_{1}=3\\y_{1}=9 \\x_{2}=1\\y_{2}=1[/tex]
Substitute each value into the formula.
[tex]m=\frac{1-9}{1-3}[/tex]
Subtract in the numerator first.
[tex]m=\frac{-8}{1-3}[/tex]
Subtract in the denominator.
[tex]m=\frac{-8}{-2}[/tex]
Divide.
[tex]m=4[/tex]
The slope of the line is 4.
6.3.67 x 10-3 is equivalent to:
A. 0.03267
B. 3.35.7
C. 0.003267
D. 3267
simplify the following expressions showing the steps:
(9+9.4i)+(-8.6-4i)
(9.4i)(-4i)
Answer:
a) 17.6 + 5.4i
b) 37.6
Step-by-step explanation:
a) (9 + 9.4i) + (8.6 - 4i)
Collect like terms:
9 + 8.6 + 9.4i - 4i
= 17.6 + 5.4i
b) (9.4i)(-4i)
Expand the brackets:
9.4 * -4 * i * i
[tex]i = \sqrt{-1}[/tex]
Therefore, i * i = -1
=> (9.4i)(-4i) = -37.6 * -1
= 37.6
540 beads are shared in the ratio 4:5. The larger share of beads is
Answer:
300
Step-by-step explanation:
A(dd): 4+5= 9
D(ivide): 540/9 = 60
T(imes): 4 x 60= 240 beads
5 x 60= 300 beads
I hope this helped :)
Number of larger share of beads is 300 seeds
Given that;
Number of total beads = 540
Beads ratio = 4:5
Find:
Number of larger share of beads
Computation:
Number of larger share of beads = 5[540 / (4+5)]
Number of larger share of beads = 5[540 / 9]
Number of larger share of beads = 5[60]
Number of larger share of beads = 300 seeds
Learn more:
https://brainly.com/question/13419413?referrer=searchResults
The amount of precipitation (in inches) in June of a recent year was measured in some randomly selected Michigan and Ohio cities (see below).
Assume that the mean amount of June precipitation in Michigan and Ohio cities are both approximately normally distributed.
Construct a 98% confidence interval for the difference of the mean amount of June precipitation in Michigan cities minus mean amount of June precipitation in Ohio cities.
Michigan Ohio
Lansing :3.46 Akron:3.15
BigRapids :3.27 Dayton:4.17
Monroe:3.62 Fremont:4.06
Marquette:2.68 Toledo:3.86
Alpena:2.68 Cincinnate:4.17
Answer:
The 98% confidence interval for the difference of the mean amount of June precipitation in Michigan cities and Ohio cities is (-1.77, 0.29).
Step-by-step explanation:
The (1 - α)% confidence interval for the difference between two population mean is:
[tex]CI=(\bar x_{1}-\bar x_{2})\pm t_{\alpha/2, (n-1)}\cdot\sqrt{\frac{s_{1}^{2}}{n_{1}}+\frac{s_{2}^{2}}{n_{2}}}[/tex]
Compute the value of sample means and sample standard deviations from the provided data.
[tex]\bar x_{1}=3.142\\\\\bar x_{2}=3.882\\\\s_{1}=0.4396\\\\s_{2}=0.4283\\n_{1}=n_{2}=5[/tex]
The critical value of t for 98% confidence level and (n - 1) = 4 degrees of freedom is:
[tex]t_{\alpha/2, (n-1)}=t_{0.02/2, 4}=3.747[/tex]
Compute the 98% confidence interval for the difference of the mean amount of June precipitation in Michigan cities and Ohio cities as follows:
[tex]CI=(\bar x_{1}-\bar x_{2})\pm t_{\alpha/2, (n-1)}\cdot\sqrt{\frac{s_{1}^{2}}{n_{1}}+\frac{s_{2}^{2}}{n_{2}}}[/tex]
[tex]=(3.142-3.882)\pm3.747\cdot\sqrt{\frac{0.4396^{2}}{5}+\frac{0.4283^{2}}{5}}\\\\=-0.74\pm 1.0285\\\\=(-1.7685, 0.2885)\\\\\approx (-1.77, 0.29)[/tex]
Thus, the 98% confidence interval for the difference of the mean amount of June precipitation in Michigan cities and Ohio cities is (-1.77, 0.29).
A trip 50 miles out of town takes 45 minutes. If the same person
drives another 120 miles at the same rate how many hours will it
take?
Hey there! I'm happy to help!
We see that it takes 45 minutes for a person to drive 50 miles. We can write this as a fraction that is 45/50, which simplifies to 9/10, meaning it would take this person 9 minutes to travel 10 miles.
So, how long would it take to travel 120? Well, we know that if we take 10 miles and multiply it by 12 we will have 120 miles. If we take the time it takes to drive those ten miles (9 minutes) and multiply it by 12, we will figure out how long it takes to drive 120 miles!
9×12=108
However, we want this to be written in hours. We know that there are 60 minutes in an hour, and if we subtract 60 from 108 we have 48. This gives us 1 hour and 48 minutes.
Therefore, it will take 1 hour and 48 minutes for this person to travel 120 miles at the same rate.
Have a wonderful day! :D
EMILIEJI
Find the slope of the line through (3, 7) and (-1, 4)
a) 2
11
Ob) 4
Od
2
O d) 3
Answer:
slope of the line through (3, 7) and (-1, 4) is
[tex]m = \frac{4 - 7}{ - 1 - 3} \\ \\ = \frac{ - 3}{ - 4} \\ \\ = \frac{3}{4} [/tex]
Hope this helps you
Answer:
3/4
Step-by-step explanation:
Using the slope formula
m = (y2-y1)/(x2-x1)
= (4-7)/(-1-3)
= -3/-4
= 3/4
Gravel is being dumped from a conveyor belt at a rate of 35 ft3/min, and its coarseness is such that it forms a pile in the shape of a cone whose base diameter and height are always equal. How fast is the height of the pile increasing when the pile is 12 ft high? (Round your answer to two decimal places.)
Answer:
0.31 ft/s
Step-by-step explanation:
The volume of a cone is given by the formula:
V = πr²h/3
From the question, we are given the diameter and the height to be equal, thus;
r = h/2
Putting h/2 for r into the volume equation, we have;
V = (π(h/2)²h)/3
V = πh³/12
Using implicit derivatives,we have;
dV/dt = (πh²/4)(dh/dt)
From the question, we want to find out how fast is the height of the pile increasing. This is dh/dt.
We have;
dV/dt = 35 ft³/min and h = 12ft
Plugging in the relevant values, we have;
35 = (π×12²/4)(dh/dt)
dh/dt = (35 × 4)/(144 × π)
dh/dt = 0.3095 ft/s ≈ 0.31 ft/s
Evaluate each expression for the given values of the variables: a+b+c , if a=5; b=–1; c=–8
Answer:
The answer is
- 4Step-by-step explanation:
a + b + c
a = 5 b = - 1 c = - 8
Substitute the values of a , b , c into the above expression
That's
5 + ( - 1) + ( - 8)
5 - 1 - 8
Subtract the numbers
4 - 8
We have the final answer as
- 4Hope this helps you
Answer:
-4
Step-by-step explanation:
5 + - 1 - 8= -4