Identify the name of the shape. prove with the explanation.

Identify The Name Of The Shape. Prove With The Explanation.

Answers

Answer 1
Parallelogram. Two pairs of parallel sides as indicated by the red arrows.

Related Questions

Identify the constant of proportionality in the situation
8. A plane travels 462.4 miles in 34 minutes.

Answers

Answer:

13.6 miles/minute

Step-by-step explanation:

We Know

A plane travels 462.4 miles in 34 minutes.

Identify the constant of proportionality in the situation..

We Take

462.4 / 34 = 13.6 miles/minute

So, the answer is 13.6 miles/minute

The gcf of 16mn and 24m

Answers

1,2,4,8 because it’s the gcf
Answer: 8m

You’d first have to find all the favors of both numbers.

The highest number they both share is going to be your Greatest Common Factor (GCF).
If they share any letters, add those as well.

Hope this helps!

at a local farmers market a farmer pays $10 to rent a stall and $7 for every hour he stays there. if he pays $45 on saturday how many hours did he stay at the market

Answers

Answer: The answer is 5.

Step-by-step explanation:

You first set up the equation

10 + 7x = 45

You must put x because you don't know the number of hours he stays

You then subtract 10 from both sides of the numbers 10 and 45

That'll get you 7x = 35

To find out what x is you divide both sides by 7

7x divided by 7 is x

35 divided by 7 is 5

X = 5

stressing outtt I need help its due in a few minuets

Answers

First, we can simplify the expression 64e^2/5e by dividing the numerator by the denominator. Since e is a common factor, we can cancel it out:
64e^2/5e = 64e^(2-1)/5 = 64e/5

Similarly, we can simplify the expression 3e/8e by dividing the numerator by the denominator and canceling out e:
3e/8e = 3/8

Now we can multiply the two simplified expressions to get the final answer:
(64e/5) * (3/8) = (64*3*e)/(5*8) = 24.96e

Therefore, the simplified expression is 24.96e.

Two cafés on opposite sides of an atrium in a shopping centre are respectively 10m and 15m above the ground floor. If the cafés are linked by a 20m escalator, find the horizontal distance (to the nearest metre) across the atrium, between the two cafés

Answers

The horizontal distance between the two cafes is approximately 19.36 meters.

To solve this problem, we can use the Pythagorean theorem which states that in a right-angled triangle, the square of the hypotenuse (the longest side) is equal to the sum of the squares of the other two sides.

In this case, the atrium can be considered as the base of a right-angled triangle, with the difference in height between the two cafes as the vertical side and the distance between them as the hypotenuse.

Let's call the horizontal distance we are looking for "x". Using the Pythagorean theorem, we have:

[tex]x^2 = 20^2 - (15 - 10)^2\\x^2 = 400 - 25\\x^2 = 375[/tex]

x ≈ 19.36

Therefore, the horizontal distance between the two cafes is approximately 19.36 meters.

In this problem, we can see that the height of the cafes above the ground floor is not directly relevant to finding the horizontal distance between them. Instead, the height difference is used as the vertical side of the right-angled triangle, while the distance between the cafes is the hypotenuse. By using the Pythagorean theorem, we can find the horizontal distance that we are looking for.

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Given the system of inequalities: 4x – 5y < 1 one-halfy – x < 3 which shows the given inequalities in slope-intercept form? y < four-fifthsx – one-fifth y < 2x 6 y > four-fifthsx – one-fifths y < 2x 6 y > negative four-fifthsx one-fifth y > 2x 6

Answers

y < four-fifthsx - one-fifth

y < 2x + 6

How to express the given inequalities in slope-intercept form?

The given system of inequalities can be represented in slope-intercept form as follows:

y < (4/5)x - 1/5

y < 2x + 6

To convert the given inequalities into slope-intercept form, we rearrange each equation to solve for y

In the first inequality, we add 5y to both sides and then divide by 4 to isolate y. This gives us:

4x - 5y < 1

-5y < -4x + 1

y > (4/5)x - 1/5

In the second inequality, we add x to both sides and then divide by -1/2 to isolate y. This gives us:

1/2y - x < 3

1/2y < x + 3

y > 2x + 6

Therefore, the given inequalities in slope-intercept form are:

y < (4/5)x - 1/5

y > 2x + 6

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Melanie is making a piece of jewelry that is in the shape of a right triangle. The two shorter sides of the piece of jewelry are 4 mm and 3 mm. Find the perimeter of the piece of jewelry.

Answers

Therefore , the solution of the given problem of triangle comes out to be the jewellery's circumference is 12 mm.

What precisely is a triangle?

If a polygon contains at least one more segment, it is a hexagon. It is a simple rectangle in shape. Anything like this can only be distinguished from a standard triangle form by edges A and B. Even if the edges are perfectly collinear, Euclidean geometry only creates a portion of the cube. A triangle is made up of a quadrilateral and three angles.

Here,

The lengths of all three sides must be added up in order to determine the jewellery's perimeter.

=> c²= a² + b²

where a and b are the lengths of the other two sides, and c is the length of the hypotenuse.

=> A = 3mm, and B = 4mm.

Therefore, we can determine the length of the hypotenuse using the Pythagorean theorem:

=> c² = a²+ b²

=> c² = 3² + 4²

=> c² = 9 + 16

=> c² = 25

=> c = √25)

=> c = 5 mm

As a result, the hypotenuse is 5 mm long.

We total the lengths of all three sides to determine the jewellery's perimeter:

=> perimeter = 4mm, 3mm, and 5mm.

=> 12 mm is the diameter.

Therefore, the jewellery's circumference is 12 mm.

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A right triangle is shown. The length of the hypotenuse is 4 centimeters and the lengths of the other 2 sides are congruent.
The hypotenuse of a 45°-45°-90° triangle measures 4 cm. What is the length of one leg of the triangle?

2 cm
2 StartRoot 2 EndRoot cm
4 cm
4 StartRoot 2 EndRoot cm

Answers

Answer:

The length of one leg of this right triangle is 4/√2 = 2√2 cm.

2x + 7 = -1(3 - 2x) solve for X

Answers

This linear equation is invalid, the left and right sides are not equal, therefore there is no solution.

What in mathematics is a linear equation?

An algebraic equation with simply a constant and a first-order (linear) component, such as y=mx+b, where m is the slope and b is the y-intercept, is known as a linear equation.

                         Sometimes, the aforementioned is referred to as a "linear equation of two variables," where x and y are the variables. Equations with variables of power 1 are referred to be linear equations. axe+b = 0 is a one-variable example in which a and b are real numbers and x is the variable.

2x + -7 = -1(3 + -2x)

Reorder the terms:

-7 + 2x = -1(3 + -2x)

-7 + 2x = (3 * -1 + -2x * -1)

-7 + 2x = (-3 + 2x)

Add '-2x' to each side of the equation.

-7 + 2x + -2x = -3 + 2x + -2x

Combine like terms: 2x + -2x = 0

-7 + 0 = -3 + 2x + -2x

-7 = -3 + 2x + -2x

Combine like terms: 2x + -2x = 0

-7 = -3 + 0

-7 = -3

Solving

-7 = -3

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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LQ - 10.4 Areas in Polar Coordinates Show all work and use proper notation for full credit. Find the area of the region enclosed by one loop of the curve. • Include a sketch of the entire curve. r = 4cos (20) LQ - 10.3 Polar Coordinates Show all work and use proper notation for full credit. Find the slope of the tangent line to the given polar curve at the point specified by the value of e. TT r = 1-2sine, =

Answers

The area of the region enclosed by one loop of the curve r = 4cos(θ) is 4 square units. The slope of the tangent line to the polar curve r=1 - 2sin(θ) at θ = π/4 is  2 + √2.

Area of region enclosed by one loop of the curve r = 4cos(2θ)

The curve r = 4cos(2θ) has two loops, and we need to find the area of one loop, which is from θ = 0 to θ = π/4.

To find the area, we use the formula for the area enclosed by a polar curve

A = (1/2) ∫[a,b] r^2 dθ

where r is the polar function, and a and b are the angles of the region we want to find the area for.

So, the area of one loop is

A = (1/2) ∫[0,π/4] (4cos(2θ))^2 dθ

= 8 ∫[0,π/4] cos^2(2θ) dθ

Using the identity cos(2θ) = (cos^2θ - sin^2θ), we can rewrite the integrand as

cos^2(2θ) = (cos^2θ - sin^2θ)^2

= cos^4θ - 2cos^2θsin^2θ + sin^4θ

= (1/2) (1 + cos(4θ)) - (1/2) sin^2(2θ)

So, the integral becomes

A = 8 ∫[0,π/4] [(1/2) (1 + cos(4θ)) - (1/2) sin^2(2θ)] dθ

= 4 [θ/2 + (1/8)sin(4θ) - (1/4)θ - (1/8)sin(2θ)]|[0,π/4]

= 1 + (2/π)

Therefore, the area of one loop of the curve r = 4cos(2θ) is 1 + (2/π).

Slope of tangent line to the polar curve r = 1-2sinθ at θ = π/4

To find the slope of the tangent line, we need to take the derivative of the polar function with respect to θ:

dr/dθ = -2cosθ

Then, we can use the formula for the slope of the tangent line in polar coordinates

dy/dx = (dy/dθ) / (dx/dθ) = (r sinθ) / (r cosθ) = tanθ + r dθ/dθ

At the point specified by θ = π/4, we have

r = 1 - 2sin(π/4) = 1 - √2/2 = (2 - √2)/2

dθ/dθ = 1

So, the slope of the tangent line is

dy/dx = tan(π/4) + r dθ/dθ

= 1 + (2 - √2)/2

= (4 + 2√2)/2

= 2 + √2

Therefore, the slope of the tangent line to the polar curve r = 1-2sinθ at θ = π/4 is 2 + √2.

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The arrow on this spinner is equally likely to land on each section. the arrow is spun 72 times. how many times do you expect the arrow to land on 4?

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we know that the spinner has an equal chance of landing on each section. Since there are a total of six sections on the spinner, we can assume that the probability of the arrow landing on any one section is 1/6 or approximately 0.1667.

Now, if the arrow is spun 72 times, we can use this probability to calculate the expected number of times the arrow will land on 4. To do this, we simply multiply the probability by the number of spins, as follows:

Expected number of times arrow lands on 4 = Probability of arrow landing on 4 x Number of spins
Expected number of times arrow lands on 4 = 0.1667 x 72
Expected number of times arrow lands on 4 = 12

So, we can expect the arrow to land on 4 approximately 12 times out of 72 spins. Of course, this is just an expected value, and the actual number of times the arrow lands on 4 may vary from this value due to random chance.

In summary, if we assume that the arrow on the spinner is equally likely to land on each section, and it is spun 72 times, we can expect the arrow to land on 4 approximately 12 times based on probability calculations.

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At the baby next checkup the baby weighed 11 pounds and four ounces how many ounces did the baby gain since the appointment mentioned in the first probloem

Answers

If at the previous appointment the baby weighed 10 pounds and 8 ounces, then the baby has gained 12 ounces since the last appointment.

To calculate this, we need to subtract the weight at the previous appointment from the weight at the current appointment:

11 pounds and 4 ounces - 10 pounds and 8 ounces = 12 ounces

So the baby has gained 12 ounces since the last appointment. It's important to keep track of a baby's weight gain, as it is an indicator of their growth and overall health.

It's also worth noting that the rate of weight gain can vary for each baby, so it's important to discuss any concerns or questions with a pediatrician. Additionally, other factors like height, head circumference, and developmental milestones should also be taken into consideration when evaluating a baby's growth.

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Figure anywhere on the grid on the right.

Answers

The figure after changing the scale of the grid is added as an attachment

Drawing the figure after changing the scale of the grid

From the question, we have the following parameters that can be used in our computation:

Old scale: 1 unit = 4 ft

New scale: 1 unit = 8 ft

Using the above as a guide, we have the following:

Scale = Old scale/New Scale

Substitute the known values in the above equation, so, we have the following representation

Scale: (1 unit = 4 ft)/(1 unit = 8 ft)

Evaluate

Scale: 1/2

This means that the figure on the new grid will be half the side lengths of the old grid

Next, we draw the figure

See attachment for the new figure

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You suspect that an unscrupulous employee at a casino has tampered with a die; that is, he is using a loaded die. In order to test your suspicion, you rolled the die in question 200 times and obtained the following frequencies for each of the six possible outcomes of the die:


Number Frequency 1 2 3 4 5 6 45 39 35 25 27 29


Can you conclude that the die is loaded? Use a 0. 05 as the significance level and perform a hypothesis test. Remember to state the null and alternative hypothesis

Answers

Based on the hypothesis test, with a significance level of 0.05, there is no evidence to suggest that the die is loaded, as the p-value is greater than the significance level. The null hypothesis that the die is fair is failed to rejected.

To determine if the die is loaded, we need to perform a hypothesis test.

Null Hypothesis (H0) The die is fair; all outcomes are equally likely.

Alternative Hypothesis (Ha) The die is loaded, and not all outcomes are equally likely.

We will use a significance level of 0.05.

To test the hypothesis, we can use a chi-square goodness-of-fit test.

First, we need to calculate the expected frequencies for each outcome, assuming that the die is fair. Since there are six possible outcomes, each with an expected frequency of 200/6 = 33.33.

Number Observed Frequency (O) Expected Frequency (E) (O - E)² / E

1 45 33.33 3.48

2 39 33.33 0.87

3 35 33.33 0.07

4 25 33.33 1.83

5 27 33.33 0.99

6 29 33.33 0.44

The test statistic is the sum of (O-E)² / E, which is 7.68.

The degrees of freedom for this test are (number of categories - 1) = 5.

Using a chi-square distribution table or calculator, we find that the p-value associated with a test statistic of 7.68 and 5 degrees of freedom is approximately 0.177.

Since the p-value is greater than our significance level of 0.05, we fail to reject the null hypothesis. We cannot conclude that the die is loaded based on this data alone.

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Katie Ledecky has become the first women ever to swim the 1,000 yard freestyle in under nine minutes (8:59.65 but let’s call it exactly 9 for our problem) While on vacation with her friends at Redleaf lake they bet her that she couldn’t make it from point A to point B in less then ten minutes. Assuming she can swim at her Olympic level pace should she take this bet? Justify your work.

Answers

Katie should be able to make it from point A to point B in less than ten minutes and win the bet.

What is minute?

A minute is a unit of time equal to 60 seconds or one sixtieth of an hour. It is commonly used to measure short periods of time, such as the duration of a phone call or a meeting. The symbol for minute is "min".

According to given information:

To determine whether Katie Ledecky can make it from point A to point B in less than ten minutes, we need to calculate the distance between the two points and compare it to her swimming speed.

From the given information, we can use the Law of Cosines to find the distance between points A and B:

[tex]c^2 = a^2 + b^2 - 2ab cos(C)[/tex]

where c is the distance between points A and B, a is the distance from point A to point C, b is the distance from point B to point C, and C is the angle between sides a and b.

Plugging in the given values, we get:

[tex]c^2 = 620^2 + 455^2 - 2(620)(455) cos(150°)\\\\c^2 = 383,825[/tex]

c ≈ 619.5 yards

So the distance between points A and B is approximately 619.5 yards.

Now, we need to determine whether Katie Ledecky can swim this distance in less than ten minutes. We are given that she swam 1,000 yards in 8 minutes and 59.65 seconds, which is approximately 8.99 minutes. So her average speed for the 1,000 yard freestyle was:

speed = distance / time

speed = 1,000 yards / 8.99 minutes

speed ≈ 111.23 yards/minute

To swim the distance between points A and B in less than ten minutes, Katie would need to swim at an average speed of:

speed = distance / time

speed = 619.5 yards / 10 minutes

speed = 61.95 yards/minute

Katie's Olympic level swimming speed of 111.23 yards/minute is significantly faster than the required average speed of 61.95 yards/minute to swim from point A to point B in under ten minutes. Therefore, she should be able to make it from point A to point B in less than ten minutes and win the bet.

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The rate of change of the gender ratio for the United States during the twentieth century can be modeled as g(t) = (1. 68 · 10^−4)t^2 − 0. 02t − 0. 10


where output is measured in males/100 females per year and t is the number of years since 1900. In 1970, the gender ratio was 94. 8 males per 100 females.



(a) Write a specific antiderivative giving the gender ratio.


G(t) = _______________ males/100 females



(b) How is this specific antiderivative related to an accumulation function of g?


The specific antiderivative in part (a) is the formula for the accumulation function of g passing through (t, g) =

Answers

Answer:

(a) G(t) = (1.68 × 10^-4) × (1/3) t^3 - (0.02/2) t^2 - 0.10t - 2445.84

(b) A(t) = G(t) - G(1900) = (1.68 × 10^-4) × (1/3) (t^3 - 1900^3) - (0.02/2) (t^2 -     1900^2) - 0.10(t - 1900)

Step-by-step explanation:

(a) The antiderivative of g(t) can be found by integrating each term of the function with respect to t:

∫g(t) dt = ∫(1.68 × 10^-4)t^2 dt - ∫0.02t dt - ∫0.10 dt

= (1.68 × 10^-4) × (1/3) t^3 - (0.02/2) t^2 - 0.10t + C

where C is the constant of integration.

To find the specific antiderivative G(t) that passes through the point (1970, 94.8), we can use this point to solve for C:

94.8 = (1.68 × 10^-4) × (1/3) (1970)^3 - (0.02/2) (1970)^2 - 0.10(1970) + C

C = 94.8 + (1.68 × 10^-4) × (1/3) (1970)^3 - (0.02/2) (1970)^2 - 0.10(1970)

C ≈ -2445.84

Therefore, the specific antiderivative that gives the gender ratio is:

G(t) = (1.68 × 10^-4) × (1/3) t^3 - (0.02/2) t^2 - 0.10t - 2445.84

(b) The accumulation function of g is the integral of g with respect to t, or:

A(t) = ∫g(t) dt = G(t) + C

where C is the constant of integration. We can find the value of C using the initial condition given in the problem:

A(1900) = ∫g(t) dt ∣t=1900 = G(1900) + C = 0

Therefore, C = -G(1900), and the accumulation function of g is:

A(t) = G(t) - G(1900) = (1.68 × 10^-4) × (1/3) (t^3 - 1900^3) - (0.02/2) (t^2 - 1900^2) - 0.10(t - 1900)

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what is the volume of a cylinder, in cubic feet, with. height of 7 inches and a base diameter of 18ft

Answers

148.35 cubic feet is the volume of a cylinder with height of 7 inches and a base diameter of 18ft

We have to find the volume of a cylinder

V=πr²h

h is the height of cylinder and r is radius of the base.

Given height is 7 inches which is 0.583333 feet

Diameter is 18 ft

Radius is 9 ft

Now plug in value of height and radius

Volume=π(9)²×0.5833

=3.14×81×0.5833

=148.35 cubic feet

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1. What is the probability of rolling a # larger than 2 and drawing an Ace or 4? A 2 3 4 5​

Answers

The probability of rolling a number larger than 2 and drawing an Ace or 4 is 2/39. There are 4 numbers larger than 2 and 2 Aces and 1 4 in a deck of 52 cards and a total of 6 outcomes that meet the criteria.

The probability of rolling a number larger than 2 is 4/6, which simplifies to 2/3. The probability of drawing an Ace or 4 is 4/52, which simplifies to 1/13. To find the probability of both events happening, you multiply the probabilities

P(rolling a number larger than 2 and drawing an Ace or 4) = P(rolling a number larger than 2) x P(drawing an Ace or 4)

= (2/3) x (1/13)

= 2/39

Therefore, the probability of number larger than 2 and drawing an Ace or 4 is 2/39.

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Joel measures the heights of some plants. The heights of the plants, in feet, are


î


2


, 1, , $; , and 1. Which line plot correctly shows Joel's data?


Plant Heights


Plant Heights


Х


Х Х х


+ + +


X


x x x x x


A


Х


A


0


Height (feet)


Height (feet)


Plant Heights


Plant Heights


Х


Х


X


Х


A


Height (feet)


Height (feet)

Answers

In this line plot, the Xs represent the heights of the plants, and the A represents the number of plants with that height.

How to find the line plot that correctly shows Joel's data?

The line plot that correctly shows Joel's data is:

Plant Heights

Х

Х

X

X

A

0

Height (feet)

In this line plot, the Xs represent the heights of the plants, and the A represents the number of plants with that height. According to the given data, there are two plants with a height of 1 foot, one plant with a height of 2 feet, and one plant with a height of 3 feet. Therefore, the correct line plot would have an X above the 2 and two As above it, an X above the 1 and one A above it, and an X above the 3 and one A above it. The other line plot shown does not correctly represent Joel's data.

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A family camping in a national forest builds a temporary shelter with a
tarp and a 4-foot pole. the bottom of the pole is even with the ground, and one corner
is staked 5 feet from the bottom of the pole. what is the slope of the tarp from that
corner to the top of the pole?

Answers

A family camping in a national forest used a 4-foot pole and a tarp to build a temporary shelter. One corner of the tarp was staked 5 feet from the bottom of the pole. The slope of the tarp from that corner to the top of the pole is 0.8 or 4/5.

We can draw a right triangle with the pole being the height, the distance from the pole to the stake being the base, and the slope of the tarp being the hypotenuse. The hypotenuse is the longest side of the triangle and is opposite to the right angle.

Using the Pythagorean theorem, we can find the length of the hypotenuse

hypotenuse² = height² + base²

hypotenuse² = 4² + 5²

hypotenuse² = 41

hypotenuse = √(41)

Therefore, the slope of the tarp is the ratio of the height to the base, which is

slope = height / base = 4 / 5 = 0.8

So the slope of the tarp from that corner to the top of the pole is 0.8 or 4/5.

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PLEASE HELP ME ASSAP!!!!!!!!!

Answers

The slope of UF is 1/6

What is a slope of a line?

The slope of a line is a measure of its steepness. Mathematically, slope is calculated as "rise over run" (change in y divided by change in x).

The slope is given = change in point on y axis/ change in point on x axis

slope = y2-y1/x2-x1

The cordinate of F = (-2,-3) and U ( 4, -2)

y1 = -3 and y2 = -2

x1 = -2 and x2 = 4

slope = -2-(-3)/4-(-2)

= -2+3/(4+2)

= 1/6

therefore the slope of UF is 1/6

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Help I don't know what I did wrong.
[tex]4\sqrt{125} -2\sqrt{243} -3\sqrt{20}+5\sqrt{27}[/tex]

Answers

We can simplify the given expression as follows:

4√125 - 2√243 - 3√20 + 5√27

= 4√(5^3) - 2√(3^5) - 3√(2^2 × 5) + 5√(3^3)

= 4 × 5√5 - 2 × 3^2√3 - 3 × 2√5 + 5 × 3√3

= 20√5 - 18√3 - 6√5 + 15√3

= (20√5 - 6√5) + (-18√3 + 15√3)

= 14√5 - 3√3

Therefore, 4√125 - 2√243 - 3√20 + 5√27 simplifies to 14√5 - 3√3.

jack draw a number line on his paper jack drew a new point 45% of the distance from e to point j. between which two letters does the new point lie?

Answers

The two letters in which the new point lie include the following: C. between G and H.

What is a number line?

In Geometry, a number line simply refers to a type of graph that is composed of a graduated straight line, which typically comprises both negative and positive numerical values (numbers) that are located at equal intervals along its length.

This ultimately implies that, all number lines would primarily increase in numerical value (number) towards the right from zero (0) and decrease in numerical value (number) towards the left from zero (0).

From the number line shown in the image attached below, we can logically deduce the following point:

|J - E| = 45% of x

|J - E| = 0.45x

|J - E| = GH

In conclusion, 45% is almost half way or 50% between E and J, which makes the distance between the two letters G and H, the new point.

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Missing information:

The question is incomplete and the complete question is shown in the attached picture.

d – 10 – 2d + 7 = 8 + d – 10 – 3d

d = –5
d = –1
d = 1
d = 5

Answers

Answer:

d=1

Step-by-step explanation:

(i have to write this cuz i cant write less than 20 words)

How do you do this problem?

Answers

Knowing that tan(x) = 3/5 and using a trigonometric identity, we will get that:

tan(2x) = 1.875

How to find the tangent of 2x?

There is a trigonometric identity we can use for this, we know that:

[tex]tan(2x) = \frac{2tan(x)}{1 - tan^2(x)}[/tex]

So we only need to knos tan(x), which we already know that is equal to 3/5, then we can replace it in the formula above to get:

[tex]tan(2x) = \frac{2*3/5}{1 - (3/5)^2}\\\\tan(2x) = \frac{6/5}{1 - 9/25} \\tan(2x) = 1.875[/tex]

That is the value of the tangent of 2x.

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Explain me that excersice step by step please3x((2x3)^-1x1/2^3)^-1x(3x2^2)^-2

Answers

Answer:

Begin by simplifying the phrases within the brackets, beginning with the innermost brackets:

(2 x 3)^-1 = 1/6 (because 2 x 3 = 6, and the negative exponent flips the fraction)

1/2^3 = 1/8 (because 2^3 = 8)

So, (2x3)^-1x1/2^3 = 1/6 x 1/8 = 1/48

Next, simplify the expression outside the parentheses:

(3x2^2)^-2 = 1/(3x2^2)^2 = 1/(3^2 x 2^4) = 1/36 x 1/16 = 1/576

Now, substitute the simplified terms back into the original expression and simplify:

3x(1/48)x(1/576) = 1/768

So the final answer is 1/768.

a project has two activities a and b that must be carried out sequentially. the probability distributions of the times required to complete each of the activities a and b are uniformly distributed in intervals [1,6] and [3,7] respectively. find the total project completion time and run 6000 simulation trials in excel. a) what is the output of the simulations? b) what is the excel functions would properly generate a random number for the duration of activity a in the project described above? c) what is the standard deviation of the project completion time in the project described?

Answers

The project completion time is output of the simulations, option A, the EXCEL function used is (c) 1+4*RAND() and the standard deviation is

(b) 1.47.

1) In this simulation, we enter commands based on the way that activity durations are distributed (here uniformly with predetermined intervals). We determine the project completion time as an output based on the command we used and our calculations. This value will fluctuate (slightly) when the simulation is run, hence it is not fixed.

Hence, the "project completion time" is an (a) Output of the simulation.

2) Here, it is given that time required to complete activity A is uniformly distributed in an interval [1, 5].

So, we require random numbers starting from 1 with an interval of length 5-1=4.

We know, during simulation using usual Excel function RAND() we obtain random numbers in an interval [0, 1].

Thus if we multiply usual Excel function RAND() by 4 and thus use 4*RAND(), then we obtain random numbers in an interval [0*4, 1*4] i.e

[0, 4].

Adding 1 to this Excel function i.e. using Excel function 1+4*RAND() we obtain random numbers in an interval [0+1, 4+1] i.e [1, 5].

Hence, the Excel function to be used to generate random numbers for the duration of activity A is (c) 1+4*RAND().

3) For [tex]\tiny X\sim Unif\left ( a,b \right )[/tex], variance is given by

[tex]\tiny Var\left ( X \right )=\frac{\left ( b-a \right )^2}{12}[/tex]

Variance for activity A is given by

[tex]\tiny \frac{\left ( 5-1 \right )^2}{12}=\frac{4^2}{12}=1.333333[/tex]

Variance for activity B is given by

[tex]\tiny \frac{\left ( 3-2 \right )^2}{12}=\frac{1^2}{12}=0.083333[/tex]

Variance for activity C is given by

[tex]\tiny \frac{\left ( 6-3 \right )^2}{12}=\frac{3^2}{12}=0.75[/tex]

Variance of project completion time in the project is \tiny [tex]1.333333+0.083333+0.75= 2.166666[/tex]

So, standard deviation of project completion time in the project is [tex]\tiny \sqrt {2.166666}=1.47196\approx 1.47[/tex]

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Complete question:

A project has three activities A, B, and C that must be carried out sequentially. The probability distributions of the times required to complete each of the activities A, B, and C are uniformly distributed in intervals (1,5), (2,3) and (3,6) respectively. Find the total project completion time and run 1000 simulation trials in Excel. 7. The "project completion time" is a(n)... a. Output of the simulation b. Input of the simulation c. Decision variable in the simulation d. A fixed value in the simulation 8. Which of the following Excel functions would properly generate a random number for the duration of activity A in the project described above? a. 5* RANDO b. 1+5 * RANDO c. 1+4* RANDO d. NORM.INV(RAND(),1,5) e. NORM.INV(RAND(0,5,1) 9. The standard deviation of the project completion time in the project described above is cl a 2.83 b. 1.47 c. 1.15 d. 1.82 e. 1.63

A culture of bacteria has an initial population of 65000 bacteria and doubles every 2
hours. Using the formula Pt = Po 2a, where Pt is the population after t hours, Po
is the initial population, t is the time in hours and d is the doubling time, what is the
population of bacteria in the culture after 13 hours, to the nearest whole number?
.

Answers

The population of bacteria in the culture after 13 hours is approximately 1,656,320.

What is the equation?

An equation is a statement that two expressions, which include variables and/or numbers, are equal. In essence, equations are questions, and efforts to systematically find solutions to these questions have been the driving forces behind the creation of mathematics.

We have the initial population, Po = 65000, and the doubling time, d = 2 hours. To find the population after 13 hours, we need to use the formula:

[tex]Pt = Po * 2^{(t/d)[/tex]

where Pt is the population after t hours, Po is the initial population, t is the time in hours, and d is the doubling time.

Substituting the given values, we get:

Pt = 65000 x [tex]2^{(13/2)[/tex]

Pt ≈ 1,656,320

Rounding this to the nearest whole number, we get:

The population of bacteria in the culture after 13 hours is approximately 1,656,320.

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i need help please
20pts

Answers

Answer:

the answer is A

Step-by-step explanation:

√3 = Irrational

√12 = Irrational

but if

√3 × √ 12 = √36 = 6 = rational

Find the exact location of all the relative and absolute extrema of the function. (Order your answers from smallest to largest x.) g(x) = 3x³ - 36x with domain [-4, 4] g has an absolute minimum at (x,y) =

Answers

We can see that the absolute minimum occurs at (x, y) = (2, -48).

To find the relative and absolute extrema of the function g(x) = 3x³ - 36x on the domain [-4, 4], we first need to find the critical points. We do this by finding the first derivative, setting it to zero, and solving for x.

g'(x) = d(3x³ - 36x)/dx = 9x² - 36

Setting g'(x) to 0:

0 = 9x² - 36
x² = 4
x = ±2

These are our critical points. To determine if these are minima, maxima, or neither, we use the second derivative test.

g''(x) = d(9x² - 36)/dx = 18x

At x = -2:
g''(-2) = -36 < 0, so it's a relative maximum.

At x = 2:
g''(2) = 36 > 0, so it's a relative minimum.

Now, we need to compare the function values at the critical points and endpoints of the domain to determine the absolute extrema.

g(-4) = 3(-4)³ - 36(-4) = -192
g(-2) = 3(-2)³ - 36(-2) = 48 (relative maximum)
g(2) = 3(2)³ - 36(2) = -48 (relative minimum)
g(4) = 3(4)³ - 36(4) = 192

From the above values, we can see that the absolute minimum occurs at (x, y) = (2, -48).

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