(i) The car starts from rest. From time = 0 to time = 15 s, the car has a constant acceleration to a speed of 28 m/s. From time = 15 s to time = 32 s, the car has a constant speed of 28 m/s. From time = 32 s, the car has a constant deceleration of 2.0 m/s² until it comes to rest. On Fig. 1.1, draw the graph, using the space below for any calculations.​

From the table, we can see that Charlene will have the most profit ($21) when she walks 3 dogs per month, charging $9 per walk.

Based on the provided data, we can create a demand schedule for the prices and the quantity demanded per month.

Let's first organize the data in a table:

Price ($) Quantity Demanded per Month

15 1

12 2

9 3

6 5

3 7

If you plotted these numbers on a graph, you would expect to see a downward-sloping curve, illustrating the inverse relationship between price and quantity demanded. As the price decreases, the quantity demanded per month increases.

Now let's consider Charlene's costs and profits from walking dogs. It costs her $2.00 for each bus ride to the dog owner's house.

To calculate her profit, we need to find her total revenue at each price point, then subtract her total costs.

Price ($) Quantity Demanded per Month Total Revenue ($) Total Costs ($) Profit ($)

15 1 15 2 13

12 2 24 4 20

9 3 27 6 21

6 5 30 10 20

3 7 21 14 7

From the table, we can see that Charlene will have the most profit ($21) when she walks 3 dogs per month, charging $9 per walk.

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No. The potential of a non-uniform charged sphere cannot be the same as that of a point charge.

The potential at any point in space is determined by the distribution of charge within the system, and a non-uniform charged sphere has a different charge distribution than a point charge.

A point charge has all of its charges concentrated at a single point, while a non-uniform charged sphere has charge distributed throughout its volume.

As a result, the electric field and potential will be different for these two systems, even if they have the same total charge. Therefore, the potential of a non-uniform charged sphere cannot be the same as that of a point charge.

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The thing that I expect will happen in th the below is each of the following.

With regards to Nursing Homes as the population ages, there will certainly be a greater demand for nursing homes during the next 50 years. The need for long-term care facilities is anticipated to increase as people live longer. More patients might need specialized care that can only be offered in a nursing home setting as medical technology advances. However, future changes to healthcare and governmental policy may also have an impact on the demand for nursing homes.

Baby High Chairs depending on demographic and lifestyle trends, demand for baby high chairs may rise or fall. Baby high chairs may become less popular if birth rates keep falling or if parents choose more adaptable seating solutions. However, if more parents opt to

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Ans. 0.75

To convert watts into kilowatts we must divide it by 1000

so dividing 750W by 1000

we get,

750/1000 = 0.75

hence 750W in kilowatts equals to 0.75

Answer:

Approximately [tex]63.2^{\circ}[/tex].

Explanation:

The refractive index [tex]n[/tex] gives the ratio between the speed of light in vacuum and the speed of light in the given material. A larger refractive index means slower speed of light in the medium. In this question, the speed of light is slower in polycarbonate than in quartz.

When light travels from a material of low light speed to a material of higher light speed, the angle of refraction [tex]\theta_{r}[/tex] will exceed the angle of incidence [tex]\theta_{i}[/tex] (both with respect to the normal.)

The critical angle at this interface is the [tex]\theta_{i}[/tex] for which [tex]\theta_{r} = 90^{\circ}[/tex]. Note that since [tex]\theta_{i}\![/tex] cannot exceed [tex]90^{\circ}[/tex], [tex]\theta_{i} < \theta{r}[/tex] and light must be entering a faster medium from a slower medium. In this question, light would be entering quartz ([tex]n = 1.41[/tex], faster) from polycarbonate ([tex]n = 1.58[/tex], slower.)

By Snell's Law:

[tex]n_{i}\, \sin(\theta_{i}) = n_{r}\, \sin(\theta_{r})[/tex],

Where:

Set [tex]n_{i} = 1.58[/tex] (polycarbonate), [tex]n_{r} = 1.41[/tex] (quartz), and [tex]\theta_{r} = 90^{\circ}[/tex]. Rearrange the equation and solve for [tex]\theta_{i}[/tex]:

[tex]\begin{aligned}\sin(\theta_{i}) &= \frac{n_{r}\, \sin(\theta_{r})}{n_{i}} \end{aligned}[/tex].

[tex]\begin{aligned}\theta_{i} &= \arcsin\left (\frac{n_{r}\, \sin(\theta_{r})}{n_{i}} \right) \\ &= \arcsin \left(\frac{1.41\, \sin(90^{\circ})}{1.58}\right) \\ &\approx 63.2^{\circ}\end{aligned}[/tex].

13. If the supply of gasoline rises, a substitute that may increase in demand could be electric or hybrid vehicles.

14. Here is how each of the following events may have affected the world price of oil using basic supply and demand analysis:

a. Tax credits offered for expenditures on home insulation would likely decrease the demand for oil as people would use less energy to heat their homes. This would lead to a decrease in the price of oil.

b. The completion of the Alaskan oil pipeline would increase the supply of oil, leading to a decrease in the price of oil.

c. The discovery of oil in Mexico and the North Sea would increase the supply of oil, leading to a decrease in the price of oil.

d. The popularity of Sport Utility Vehicles and minivans would increase the demand for oil as these vehicles typically consume more gasoline than smaller cars. This would lead to an increase in the price of oil.

e. The depletion of natural oil reserves would decrease the supply of oil, leading to an increase in the price of oil.

Answer:

Step 1: Given data

Acceleration due to gravity on the surface of the earth is g.

The radius of the earth is R and x is the height of the satellite above the earth's surface.

The mass of the satellite is m.

Step 2: Calculate the orbital speed of the satellite.

We know that,

mv2R+x=GMmR+x2

v=GMR+x

v=GMR2×R2R+x

Step 3: Final answer

v=gR2R+x

We can also write it as

v=gR2R+x12

Answer:

v = 15.939 km/h

Explanation:

distance (d) = 69.05 km

time (t) = 4.332 hours

Speed (v) = ?

v = d / t

v = 69.05 / 4.332

v = 15.939 km/h

The joint probability distribution of X and Y is 2/70 and 3/70.

The value of P[(X,Y)A], where A is the region that is given is 1/2.

Probability simply means the chance that a particular thing or event will happen. It is the occurence of likely events. It is simply the area of mathematics that deals with the numerical estimates of the chance that an event will occur or that a particular statement is true.

The value of P[(X,Y)A], where A is the region that is given is:

= 0 + 2/70 + 3/70 + 3/70 + 18/70 + 9/70

= 35 / 70

= 1/2.

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The time taken for the cordial to freeze is 267.2 s.

The amount of heat energy (Q) required to freeze the cordial can be calculated using the following formula:

Q = ml

where;

Q = 334 J/g x 200 g

Q = 66,800 J

The time taken for the cordial to freeze is calculated as;

t = Q/W

where;

t = (66,800 J) / (250 J/s)

t = 267.2 s

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Answer: true

Explanation: if the current element is above the current water level then it is true

Answer:

The velocity of the center of mass (Vcm) of a system of particles can be calculated using the formula:

Vcm = (m1v1 + m2v2 + m3v3 + ... + mnvn) / (m1 + m2 + m3 + ... + mn)

where m1, m2, m3, ... mn are the masses of the particles and v1, v2, v3, ... vn are their velocities.

In this problem, we have three particles with masses of 20g, 30g, and 50g and velocities of 2i, 10j, and 10k respectively. We can convert the masses to kg to make the calculations easier:

m1 = 20g = 0.02kg

m2 = 30g = 0.03kg

m3 = 50g = 0.05kg

Using the formula above, we can calculate the velocity of the center of mass:

Vcm = (m1v1 + m2v2 + m3v3) / (m1 + m2 + m3)

Vcm = (0.02kg * 2i + 0.03kg * 10j + 0.05kg * 10k) / (0.02kg + 0.03kg + 0.05kg)

Vcm = (0.04i + 0.3j + 0.5k) / 0.1kg

Vcm = 0.4i + 3j + 5k m/s

Therefore, the velocity of the center of mass of the three particles is 0.4i + 3j + 5k m/s.

mark me brilliant

Answer:60 seconds

Explanation: Since we have the boy's initial location si (0m), final location sf (600m) and his velocity v, we can have our position equation like so:

sf = si + vt
600 = 0 + 10t

Solve for t by dividing 600 by 10 and your time t = 60s

The electric current in the circuit below is 3 A And the right option is C. 3A.

Electric current is the rate of flow of charge in a circuit.

To calculate the electric current in the circuit below, we use the formula:

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the right option is C. 3A

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The magnitude of acceleration at the given point is 8.04 m/s², and the direction of acceleration at the given point is 38.5° below the negative x-axis.

To find the magnitude of acceleration at the given point, we need to calculate the force acting on the block using the potential-energy function and then use Newton's second law, F=ma, to find the acceleration.

The force acting on the block can be found by taking the negative gradient of the potential-energy function;

F = -∇U = (-∂U/∂x)i + (-∂U/∂y)j

where i and j are unit vectors in the x and y directions, respectively.

Taking the partial derivatives of U(x,y) with respect to x and y, we get;

∂U/∂x = 11.0 J/m² × x

∂U/∂y = -11.1 J/m³ × y₂

Plugging in the values x=0.40 m and y=0.50 m, we get;

∂U/∂x = 1.76 J/m

∂U/∂y = -1.39 J/m

Therefore, the force acting on the block at (0.40 m, 0.50 m) is;

F = (-1.76 J/m)i + (-1.39 J/m)j

Using Newton's second law, F=ma, we can find the magnitude of acceleration:

a = F/m = ([tex]F_{x}[/tex][tex]F_{y}[/tex]/m₂ + [tex]F_{y}[/tex]₂/m₂)1/2

= [(1.76 J/m)2 + (-1.39 J/m)2]/0.0400 kg

= 8.04 m/s2

Therefore, the magnitude of acceleration at the given point is 8.04 m/s².

To find the direction of acceleration at the given point, we need to find the angle between the force vector and the positive x-axis.

The angle θ can be found using the formula;

θ = tan-1([tex]F_{y}[/tex] /[tex]F_{x}[/tex])

Plugging in the values of [tex]F_{x}[/tex] and [tex]F_{y}[/tex] at (0.40 m, 0.50 m), we get;

θ = tan-1(-1.39 J/m / 1.76 J/m)

= -38.5°

Since the force vector is in the third quadrant (i.e., both [tex]F_{x}[/tex] and [tex]F_{y}[/tex] are negative), the angle θ is negative. Therefore, the direction of acceleration at the given point is 38.5° below the negative x-axis.

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Answer:

a = 0.724 m/s2

Explanation:

Known:

m = 650 kg

F = 897 N

a = ?

Use this formula:

F = ma

a = F/m

a = 650/897

a = 0.724 m/s2

(a) F(x) = 0.503 x, where x is in meters and F is in newtons, is the formula given for the force. We can see that this equation's proportionality constant, C, must be expressed in newtons per meter. C is therefore measured in N/m in the SI.

(b) The work done by the force as the particle moves from x = 3.0 m to x = 1.5 m can be calculated using the formula for work, which is W = ∫ F(x) dx, where the integral is taken over the distance moved. Therefore, we have:

W = ∫ 0.503 x dx from x = 3.0 to x = 1.5

W = [0.503/2 x^2] from x = 3.0 to x = 1.5

W = [0.503/2 (1.5^2 - 3.0^2)]

W = -1.129 J

The work done by the force is -1.129 joules.

(c) At x = 3.0, the force is given to be in the opposite direction to the particle's velocity. Therefore, the force is opposing the motion of the particle. We can use the work–kinetic energy theorem to determine the change in kinetic energy of the particle between x = 3.0 and x = 1.5, and hence its speed at x = 1.5. The work–kinetic energy theorem states that the net work done on an object is equal to its change in kinetic energy. Therefore, we have:

W_net = ΔK

In this case, the only force acting on the particle is the given force, and we have already calculated the work done by this force as -1.129 J. Therefore, we have:

W_net = -1.129 J

ΔK = 1.129 J (since the work done is negative, indicating a decrease in kinetic energy)

We can use the formula for kinetic energy, K = (1/2)mv^2, to find the particle's speed at x = 1.5. Therefore, we have:

ΔK = (1/2)m(v^2 - v_0^2)

1.129 = (1/2)(1.5)(v^2 - 12^2)

v^2 = 12^2 - (2/1.5)(1.129)

v^2 = 56.49

v = 7.52 m/s

The particle's speed at x = 1.5 is 7.52 m/s.

(d) kinetic energy theorem states that the net work done on an object is equal to its change in kinetic energy. In this case, the net work done by the given force Is -1.129 J, the initial kinetic energy of the particle (since we are told its speed at x = 3.0).

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Answer:

Explanation:

Increased heart rate

OA: A. A claim, assumption, or method that is commonly thought to be based on science but is not scientific.

Science is a systematic enterprise that builds and organizes knowledge in the form of testable explanations and predictions about the universe.

A claim, assumption, or method that is commonly thought to be based on science but is not scientific is called pseudoscience. Pseudoscience is often presented as being scientific, but it does not meet the criteria of science. For example, pseudoscience may be based on speculation or personal opinion, rather than on evidence. It may also be based on experiments that are not properly controlled or that are not reproducible.

Pseudoscience can be harmful because it can lead people to make decisions that are not based on evidence. For example, people who believe in pseudoscience may be more likely to avoid proven medical treatments or to use unproven treatments that could actually be harmful.

It is important to be able to identify pseudoscience so that you can make informed decisions about your health and your life. If you are unsure whether something is pseudoscience, you can ask a scientist or do some research to find out more.

The length one vectors i, j, and k, which stand for conventional measure vectors in three different dimensions, contribute along the positive x, y, and z axes, respectively.

Unit vectors i and j, which run along the x-axis and y-axis, respectively, define the Cartesian coordinate system. The radial unit vector r, which indicates the direction away from the origin, and the unit vector t, which is orthogonal (perpendicular) to the radial direction, together create the polar coordinate system.

The size of the discrepancy is three if the product of two vectors with units is a unit vector. steps to determine the size of Consider a and b, two unit vectors whose total is a unit vector c.

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Answer:

To meet the requirements of running for at least 30 minutes and developing a steady power of 500W, the flywheel engine needs to have sufficient energy storage capacity and be capable of delivering a steady power output.

Assuming that the flywheel engine is 100% efficient (i.e., no energy losses due to friction, air resistance, or other factors), the energy storage capacity required can be calculated as follows:

Energy storage capacity = Power x Time

= 500W x 30min

= 15,000 watt-minutes or 250 watt-hours

This means that the flywheel engine needs to be capable of storing at least 250 watt-hours of mechanical energy.

Answer:

W = 6000 Joule

Explanation:

Work is defined as force times distance

W = F * d

We know that F = 15N, we just need the distance (d)

Imagine you have a square lawn with length of 10 m and width of 20m. So, we want to know the the distance you have to travel to cover every square meter of the lawn.

The width of the mower is only 50 cm = 0.5 m.

This means that you have to go back and forth 40 times to cover 20m (lawn width), with a distance of 10 m (lawn length). So,

d = 10 (meter) * 40 (times) = 400 meter

Therefore:

W = (15) * (400) = 6000 J

No, two observers standing on opposite sides of the truck would not hear the same pitch at the same time.

This is due to the fact that the sound waves produced by the truck's horn would move at a specific pace that would be constant for both viewers. The distance between the horn and each viewer, however, fluctuates as the truck passes the two people, resulting in a variation in the amount of time it takes for the sound waves to reach each person.

The Doppler effect, which comes from this change in time, changes how the sound waves are perceived in terms of pitch. To be more precise, the observer in front of the truck would hear a higher pitch (shorter wavelength) and the observer behind the truck would hear a lower pitch (longer wavelength).

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Explanation:

The parallel resistors ( 10 and 40 Ω) have an equivalent resistance of

( 40 * 10 ) / ( 40 + 10 )  = 8 Ω

Then you can add all of the series resistances to find the total resistance

15 + 25 + 8 Ω = 48 Ω

Remember V = IR ....then   V/R = I

      Current =    V/ R = 55 v / 48 Ω = 1.15 A

The work done by the muscle in stretching the Achilles tendon is 20.04 joules.

To calculate the work done by the muscle in stretching the Achilles tendon, we can use the formula:

Work = Force × Distance

We know that the force exerted on the tendon by the muscle increased from 3230 N to 4787 N, causing the tendon to stretch by 0.500 cm.

converting the distance from centimeters to meters:

Distance = 0.500 cm = 0.005 m

Now we can calculate the work done by the muscle:

Work = Force × Distance

Work = (4787 N + 3230 N)/2 × 0.005 m

Work = 4008.5 N × 0.005 m

Work = 20.04 J

Therefore, the work done by the muscle in stretching the Achilles tendon is 20.04 joules.

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Answer:

Sound and power are related through intensity, which is the amount of power per unit area. The intensity of a sound wave is proportional to the square of its amplitude, which is a measure of how far the wave oscillates from its equilibrium position.

To solve this problem, you can use the formula for sound intensity:

I = P/A

where I is the intensity of the sound wave in watts per square meter (W/m^2), P is the power of the sound wave in watts (W), and A is the area of the eardrum in square meters (m^2).

You are given that the softest sound a human ear can hear is 0 dB, which corresponds to an intensity of 10^-12 W/m^2. You are also given that sounds above 130 dB cause pain. To find the maximum power the ear can receive before the listener feels pain, you can rearrange the formula for intensity to solve for power:

P = AI

where A is the area of the eardrum in square meters.

Substituting the given values, you get:

P = (51 x 10^-6 m^2)(10^-12 W/m^2 x 10^(130/10))

Simplifying this expression, you get:

P = 1.8 x 10^-3 W

Therefore, the most power the ear can receive before the listener feels pain is 1.8 x 10^-3 watts.

The air becomes humid during warm front passes and a cold front means a transition where warm air is being replaced by the cold air.What do you mean by weather?

The weather means the atmosphere at a particular place and time with respect to temperature, pressure, cloudiness, wind, etc.

A warm front means when the air is very warm and humid as compared to before.

A cold front is when the air is very colder and drier than the air above it. More than 15 degrees temperature can drop down when a cold front passes.

A cold front will probably bring winds, thunderstorms, and rain.Therefore, the cold front moves faster than the warm front.Learn more about the Weather here:

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The number of electrons represent a Change of -70 μC is 4.3 × 10¹⁴.

Electric charge is the physical property of matter that experiences force when it is placed in electric field. F = qE where q is amount of charge, E = electric field and F = is force experienced by the charge. there are two types of charges, positive charge and negative charge which are generally carried by proton and electron resp. like charges repel each other and unlike charges attract each other. the flow charges is called as current. Elementary charge is amount of charge a electron is having, whose value is 1.602 x 10⁻¹⁹ C

The value of elementary charge that is charge on 1 electron is 1.6× 10⁻¹⁹ C

-70 μC = N × 1.6× 10⁻¹⁹ C

N = -70 μC / 1.6× 10⁻¹⁹ C

N = -70 μC / 1.6× 10⁻¹⁹ C

N = 4.3 × 10¹⁴ electrons

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Four point masses 2kg, 4kg, 6kg and 8kg are placed at the corners of Square ABCD of 2cm long respectively. the Position of center of mass of the system from the corner A. is (1 , 1.4 ) cm.

Considering A as it origin

center of mass along X axis

[tex]X = \frac{M_{a}r_{a} + M_{b}r_{b} + M_{c}r_{c} + M_{d}r_{d} }{M_{a} + M_{b} + M_{c}+ M_{d}}[/tex]

X = 2×0+4×2+6×2+8×0 ÷ (2+4+6+8)

X = 20 ÷ 20 = 1 cm

[tex]Y = \frac{M_{a}r_{a} + M_{b}r_{b} + M_{c}r_{c} + M_{d}r_{d} }{M_{a} + M_{b} + M_{c}+ M_{d}}[/tex]

Y = 2×0+4×0+6×2+8×2 ÷ (2+4+6+8)

Y = 28 ÷ 20 = 1.4 =cm

The position of the center of the mass from the corner A which is the origin is (1 , 1.4 ) cm.

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Answer:

the learning which is gained through observation and experimentation