I really need this fast

Answer:

31

Explanation:

Answer:

D coarse texture

Explanation:

An igneous rock floats because air bubbles became trapped when molten material erupted from an underground volcano. This rock can be accurately described as extrusive and the correct option is option 2.

Igneous rocks (from the Latin word for fire) form when hot, molten rock crystallizes and solidifies. The melt originates deep within the Earth near active plate boundaries or hot spots, then rises toward the surface. Igneous rocks are divided into two groups, intrusive or extrusive, depending upon where the molten rock solidifies.

Igneous rocks can be easily identified with their texture, density, colour, and mineral composition. Its texture depends on the shape, size, time period to cool down and solidify, and the arrangement of crystals in the rock.

Therefore, an igneous rock floats because air bubbles became trapped when molten material erupted from an underground volcano. This rock can be accurately described as extrusive and the correct option is option 2.

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Answer:

1) 0.9972 g/cm³.

2) 77.62 g.

3) 25.01 cm³.

4) 7.11 cm³

5) 17.9 cm³.

6) 4.34 g/cm³

Explanation:

Hello.

In this case, for this gravimetry problem, we proceed as follows:

1) Since the temperature is 23.75 °C the density computed via lineal interpolation is:

[tex]\rho=1.004g/cm^3+23.75\°C*-0.000273\frac{g/cm^3}{\°C} =0.9972g/cm^3[/tex]

2) The mass of the solid is computed via the mass of the empty flask and the mass of the flask with the solid:

[tex]m_{solid}=135.95g-58.33g\\\\m_{solid}=77.62g[/tex]

3) In this case, since the volume of the flask equals the volume of the flask and the water because the volume of liquid water equals the volume of the container at which it is, we compute the volume of the flask considering both the mass and density of water:

[tex]m_{water}=83.27g-58.33g=24.94g\\\\V_{water}=\frac{24.94g}{0.9972g/cm^3}\\ \\V_{water}=25.01cm^3[/tex]

Thus, the volume of the flask is 25.0 cm³.

4) Here, we compute the volume of water when the water and the solid are inside the flask:

[tex]m_{water}=143.04g-135.95g=7.09g\\\\V_{water}=\frac{7.09g}{0.9972g/cm^3} =7.11cm^3[/tex]

Thus, the volume of the flask not occupied by the solid which corresponds to the water is 7.11 cm³.

5) Considering the previous volume of the flask, the volume of the solid is:

[tex]V_{solid}=25.01 cm^3-7.11cm^3\\\\V_{solid}=17.9cm^3[/tex]

6) Finally, the density of the solid is:

[tex]\rho _{solid}=\frac{77.62g}{17.9cm^3}\\ \\\rho _{solid}=4.34g/cm^3[/tex]

Regards.

Answer:

quantum mechanics

Explanation:

Answer:

I bealive the answer is D.

Answer:

The electron configuration of sulfur (S) normally is 1s2 2s2 2p6 3s2 3p4

S+ ion of sulfur would be 1s2 2s2 2p6 3s2 3p3

S- ion 1s2 2s2 2p6 3s2 3p5

Answer:

sorry im just doin it for the points but i rlly dont know

Explanation:

Answer:

2 NaOH (aq) + H2C2O4(aq) Na2C2O4(aq) + 2H2O (l) Moles of NaOH used = Molarity x Volume (L) = 0.12 mole/L x 0.025

Explanation:

sand

Explanation:

it is absorbing it

Answer:

Sand absorbers the water

Explanation:

On other days, however, when winds blow surface water toward land, the water can't just pile up on the beach, so water near the bottom has to compensate, moving offshore. ... One measures the speed and direction of flowing water by reflecting sound off particles carried by the currents.

Answer:

in Crystalline solids

Explanation:

Complete question is;

Consider this reaction: 2 HI(g) ⇄ H₂(g) + I₂(g)

At a certain temperature, this reaction follows first - order kinetics with a rate constant of 0.684 s^(-1). Suppose a vessel contains HI at a concentration of 0.32 M. Calculate the concentration of HI in the vessel 0.88 seconds later.

You may assume no other reaction is important.

Round your answer to 2 significant digits

Answer:

0.18 M

Explanation:

We are given;

Initial concentration of HI = 0.32 M

Time = 0.88 s

Rate is given as 0.684 s^(-1)

Now, we want to find the concentration of HI in the vessel 0.88 seconds later. It can be gotten from the formula;

ln (HI) = ln (HI)₀ - (kt)

Where;

(HI)₀ is the initial concentration

k is the reaction rate constant

t is time

Plugging in the relevant values, we have;

ln (HI) = In (0.32) - (0.684 × 0.88)

ln (HI) = -1.1394 - 0.6019

ln (HI) = -1.7413

(HI) = e^(-1.7413)

(HI) = 0.175 M ≈ 0.18 M

Answer:

v = 10 km/h

Explanation:

Step 1: Given data

Step 2: Calculate the speed in the Bike Trip

The speed (v) is equal to the distance traveled divided by the time elapsed. We will use the following mathematical expression.

v = d/t

v = 1 km/0.1 h

v = 10 km/h

The speed is 10 kilometers per hour.

Answer:

A substance's specific heat tells you how much heat is required to ... the temperature of 1.0 g of that substance by 1∘C . ... ΔT - the change in temperature, defined s final ...

Answer:

Fe₂O₃ + 3Zn → 2Fe + 3ZnO

Explanation:

Step 1: RxN

Fe₂O₃ + Zn → Fe + ZnO

Step 2: Balance RxN

We need 2 Fe's on both sides.

We also need 3 O's on both sides.

Fe₂O₃ + 3Zn → 2Fe + 3ZnO

Answer:

The options are not given, here are the options.

metal

a. Metal

b. a metalloid

c. a non-metal

d. a gas

The correct option is C.

Non metal

Explanation:

Henry should classify it as non metals because non metals are substances or elements that are poor conductors of heat and electricity they break easily I .e meaning they lack the ducibility of metals, meaning they cannot be stretched, they are brittle, they are not shiny and does not reflect light, they have high electronegativities that is they have atoms that can hold electrons to what they have.

Answer:

C

Explanation:

Because it’s doesn’t reflect light and metals and metalloids do

Answer:

[tex]2877kJ/mol[/tex]

Explanation:

Hello.

In this case, since the bond energy per C-H bond is 411 kJ/mol and we of course avoid the C-C bond since we are asked to compute the energy to break 7 C-H bonds, the 411 kJ/mol are multiplied by 7 as shown below:

[tex]7*411kJ/mol\\\\=2877kJ/mol[/tex]

Thus, we obtain the required bond dissociation energy. Note that propane CH₃-CH₂-CH₃ has seven C-H bonds; 3 from the first CH₃, two from the CH₂ and 3 from the last CH₃.

Best regards.

Bond dissociation energy is defined as the energy required to dissociate or break a bond to form two or more molecular fragments.

In the given molecule of propane, the energy required to break the seven C-H bonds is 2877 kJ/mol.

The bond dissociation energy for the highly stable bond will be very high. In the given bonds of carbon and hydrogen, we know that:

Each C-H bond has an energy of 411 kJ/mol.

To calculate the bond dissociation energy of 7 C-H bonds, we have:

1 C-H bonds = 411 kJ/mol

7 C-H bonds = 411 x 7

7 C-H bonds = 2877 kJ/mol

Therefore, the bond dissociation energy required to break the seven C-H bonds is 2877 kJ/mol.

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Answer:

water,salt are the house hold items

Answer:

Explanation:

The density of a substance can be found by using the formula

[tex]density = \frac{mass}{volume} \\[/tex]

From the question

mass = 22 g

volume = 2 cm³

We have

[tex]density = \frac{22}{2} \\ [/tex]

We have the final answer as

Hope this helps you

Answer:

A) During this procedure ( hypoventilation ) The CO2 in the arterial blood vessels and the lungs increases and this drives the PH level in the system lower, and the equilibrium will shift to the right. this is because the Blood-PH level is controlled by CO2 - bicarbonate buffer system

B) The blood PH may rise to 7.60 during Hyperventilation because the removal of CO2 from the lungs causes the increase in  [tex]H^+[/tex] which is directly proportional to the increase in Blood PH levels

C) Hyper ventilation before a dash would be useful because it will remove excessive Hydrogen ions and and raise the Blood PH levels in preparedness of the production of acids like Lactic acid

Explanation:

A) During this procedure ( hypoventilation ) The CO2 in the arterial blood vessels and the lungs increases and this drives the PH level in the system lower, and the equilibrium will shift to the right. this is because the Blood-PH level is controlled by CO2 - bicarbonate buffer system

[tex]CO_{2} +H_{2} O[/tex] ⇄ [tex]H^+ + HCO^-_{3}[/tex]

B) The blood PH may rise to 7.60 during Hyperventilation because the removal of CO2 from the lungs causes the increase in  [tex]H^+[/tex] which is directly proportional to the increase in Blood PH levels

C) Hyper ventilation before a dash would be useful because it will remove excessive Hydrogen ions and and raise the Blood PH levels in preparedness of the production of acids like Lactic acid

Answer:

decanting

stirring

solvent

Explanation:

Gravity filtration consists of a pump and a filter (to be placed outside the basin, above the water level). The pump is placed in the water. Connected by a hose to the filter, water is sucked up to the device.

In the gravity-type configuration, water is sucked into the filter, which causes an imbalance between the levels of the basin and the filter: this imbalance causes the movement of water - with the dirt - from the basin to the filter via the main drain and the skimmer.

The fill in the blanks with decanting, stirring, and solvent

It comprises of a pump & a filter.The pump should be placed in the water.  In the gravity-type configuration, water could be into the filter, which resulted an imbalance between the levels of the basin and the filter: this imbalance causes the movement of water.

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Given parameters:

Volume of CuSO₄ = 250mL

Concentration of CuSO₄ = 2.01M

Unknown:

Mass of CuSO₄.5H₂O = ?

To solve this problem, we must write the chemical relationship between both species.;

             CuSO₄.5H₂O  →   CuSO₄ + 5H₂O

Now that we know the expression, it is possible to solve for the unknown mass.

First find the number of moles of CuSO₄;

         Number of moles  = Concentration x Volume

Take 250mL to L so as to ensure uniformity of units;

           Volume  = 250 x 10⁻³L

  Input the parameters and solve for number of moles;

        Number of moles  = 250 x 10⁻³  x  2.01 = 0.5mol

From the equation;

             1 mole of CuSO₄ is produced from 1 mole of CuSO₄.5H₂O  

So  0.5 moles of CuSO₄ will be produced from 0.5 moles of CuSO₄.5H₂O

Now let us find the molar mass of CuSO₄.5H₂O = 63.6 + 32 + 4(16) + 5(2x1 + 16)  = 249.6g/mole

Mass of CuSO₄.5H₂O = number of moles x molar mass

                                      = 0.5 x 249.6

                                     = 124.8g

The mass of CuSO₄.5H₂O is 124.8g

ammonium, sulfate, phosphate, nitrate

Answer:

It is an amine; it contains nitrogen-hydrogen bonds that are less polar and oxygen-hydrogen bonds.

Explanation:

The boiling point of a compound is a physical property. Such physical property are influenced by the intramolecular bonds between the molecules that makes a up compound.

Both Amine and Alcohols have the same type of intermolecular bonds between them. This bond type is called the hydrogen bonds.

A hydrogen bond is an electrostatic attraction between the hydrogen atom of one molecule and the electronegative atom of a neighboring molecule.

 Note: the strength of a hydrogen bond depends on the relative electronegativity of the atom directly joined to the hydrogen.

  The order of strength of the bond is;

             H.....F  > H.....O > H......N

In amines we have the H....N hydrogen bonds, for alcohol, it is the H....O hydrogen bonds.

So, the bonds in hydrogen bonds in the alcohol is stronger and it will impart a higher boiling point on the compound.

Answer: It is an amine; it contains nitrogen-hydrogen bonds that are less polar than oxygen-hydrogen bonds.

Explanation: I TOOK THE TEST AND GOT IT RIGHT

Question: Potassium hydrogen phthalate is a solid, monoprotic acid frequently used in the laboratory to standardize strong base solutions. It has the unwieldy formula of KHC8H4O4. This is often written in shorthand notation as KHP. Of 5.06 grams of KHP are needed to exactly neutralize 35.3 mL of a barium hydroxide solution, what is the concentration of the base solution?

Explanation and answer:

2KHP + Ba(OH)2 ---> 2H2O + Ba(KP)2

you need 2 moles of KHP to neutralise 1 mole of Ba(OH)2

moles KHO = mass / molar mass  

= 2.43 g / 204.22 g/mol  

= 0.0118989 mol

moles Ba(OH)2 = 1/2 x moles KHP

= 0.005949 mol

Molarity Ba(OH)2 = moles / Litres

= 0.005949 mol / 0.0213 L

= 0.279 M (3 sig figs)

Answer:

Explanation:

The Law of Conservation of Mass is defined and explained using examples of reacting mass calculations using the law are fully explained with worked out examples using the balanced symbol equation. The method involves reacting masses deduced from the balanced symbol equation.

Answer:

5.80 mol He 6.02210^23 atoms He/ 1 mol He. This cancels out moles, leaving 3.49*10^24 atoms He. Mass is used as a method of counting atoms.

The number of atoms in 5.80 moles of He is equal to 3.49 × 10²⁴ atoms.

Avogadro’s number is used to represent the number of entities in one mole of any substance. Generally, these entities are ions, molecules, atoms, electrons, or protons, depending upon the type of reaction or reactant and product.

The value of Avogadro’s constant is found approximately 6.022 × 10²³ mol⁻¹. This number was named after the scientist Amedeo Avogadro after his death.

Given, the number of moles of helium = 5.80

The number of atoms in one mole of He = 6.022 × 10²³

The number of atoms on 5.80 moles of He = 5.80 × 6.022 × 10²³

Total number of atoms =  3.49 × 10²⁴

Therefore, the number of atoms in 5.80 moles of Helium is 3.49 × 10²⁴ He atoms.

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Answer:

E2

Explanation:

We can generally regard the bromocyclohexane as having a secondary carbon atom to Which the bromine atom is attached.

Tert-butoxide in tert-butanol favours the formation of an alkene (elimination) leading to the predominance of the less substituted alkene.

Generally, bulky bases such as tert-butoxide favours elimination by E2 mechanism over substitution.

The mechanism of Reaction A is E2 and also mechanism over substitution.

We can generally regard the Bromo cyclohexane as maintaining a secondary carbon atom to Which the bromine atom is connected.

Tert-butoxide in tert-butanol prefers the formation of an alkene (elimination) leading to the predominance of the undersized substituted alkene. Therefore, Commonly, bulky bases such as tert-butoxide favors elimination by the E2 mechanism over substitution.

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