I really need help I don't know how to solve this. : (
An object is traveling at a steady speed of 9 9/10 ​mi/h. How long will it take the object to travel ​2 1/10 mi? First round to the nearest integer to find the estimated answer. Then find the exact answer.

Step-by-step explanation:

39× 99

= -39×(100 - 1)

= (-39×100) - (-39 × 1)

= -3900 + 39

= -3861

Answer:

-3751

Step-by-step explanation:

you multiple times to the /number

Answer in the picture !!!

Answer:

Charge 26, 78, 130, 182, 234

Step-by-step explanation:

If Heads is (1,3,5,7,9) CHARGE and charge is (26,0,0,0,0) if 1 head=26 then you can just multiply or use repetitive addition if you were to multiply do 3x26=78, 5x26=130, 7x26=182, and 9x26=324. If you were to use repetitive addition do 26+26+26=78, 26+26+26+26+26=130, 26+26+26+26+26+26+26=182, and 26+26+26+26+26+26+26+26+26=234.

I hope it helps!

~XxBells is a cute girlxX~

Answer:

(0,5)

Step-by-step explanation:

Answer:

8

Step-by-step explanation:

The biggest common factor number is the GCF number. So the Greatest Common Factor 16, 24, 48 is 8.

please make my answer as brainelist

Answer:

Step-by-step explanation:

One square millimeter converted into square meter equals = 0.0000010 m2 , sq m

1 mm2 , sq mm = 0.0000010 m2 , sq m

Answer:

I think 50,682,000 square milliliters

Step-by-step explanation:

Answer:

3/1

Step-by-step explanation:

Beginning from 10, you count upward until you come across a point that's directly underneath a number to the x-axis.

In this case, you'd go upward 3 times, locating the y-axis at 30.

Then you would go either left or right and count how many times you do that.

In this case, you'd go right 1 time, locating the x-axis at 10.

Hence, the slope would be rise over run, or y over x.

In this case, the slope would be 30/10.

To simplify that, it would be 3 over 1.

To simplify it even more, it would just be 3.

Hope this helps.

If the function is translated 5 units down of the graph of f, the resulting function will be g(x) =. |x|-8

Translation is the technique that is used to change the position of a figure on an xy-plane.

For instance, if the function f(x) is translated k units down the graph, the resulting function will be g(x) = f(x) - k

Given the function f(x)=|x|-3, if the function is translated 5 units down of the graph of f, the resulting function will be;

g(x) = f(x) -  5

g(x) = |x|-3 - 5

g(x) =. |x|-8

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Answer:

Step-by-step explanation:

14+24i-26+3i+110+100i

A-98+137i

Answer: For each direct variation, find the constant of variation. Then find the value of $y$ when $x=-5 .$

$y=-\frac{2}{3}$ when $x=-\frac{1}{3}$

Step-by-step explanation:

The domain of the function f (x) = x2 + 6x + 5 over the function g(x) = x3 + x2 − 4x − 4 is {x ∈ ℝ| x ≠ −1, −2, 2}.

The main limiting issue with the domain this function is potentially picking an x-value that makes that denominator equal 0, because dividing by 0 is bad.

So, the domain will be all real numbers, except for those that make g(x)=0.

g(-1) = 0, g(-2)=0, and g(2) = 0, so -1, -2, and 2 must be excluded from the domain.

Your answer is {x ∈ ℝ| x ≠ −1, −2, 2}.

Therefore, we get that, the domain of the function f (x) = x2 + 6x + 5 over the function g(x) = x3 + x2 − 4x − 4 is {x ∈ ℝ| x ≠ −1, −2, 2}.

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Your question was incomplete. Please refer the content below:

Given f (x) = x2 + 6x + 5 and g(x) = x3 + x2 − 4x − 4, find the domain of f over g of x period

{x ∈ ℝ}

{x ∈ ℝ| x ≠ −5}

{x ∈ ℝ| x ≠ −1, −2, 2}

{x ∈ ℝ| x ≠ −2, 2}

Answer:

D

Step-by-step explanation:

a×10=0.07

a=0.07/10

=0.007

Answer:

D

Step-by-step explanation:

0.007 if you multiply this by 10 you move the decimal one place to the right, t hat would be 0.07

Therefore 1 9/10 bag of mulch is put on each vegetable bed.

Given a gardener spread 3 4/5 bags of mulch evenly over his 2 equal-sized vegetable beds.

We need to find how much he put on each vegetable bed as

Let the number of bags of mulch put on each vegetable bed be x

∴ 2 * x =  3 4/5

2 x = 19 / 5

x = 19 / 10

x = 1 9/10 bag

Therefore 1 9/10 bag of mulch is put on each vegetable bed.

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On subtracting 12.82 from 43.3 we get 30.48 as answer.

How to subtract decimal numbers?

Write down decimal numbers such that the number from which you have to subtract is written first and number which you have to subtract from the fist number is written just below it such that the decimal is just lined below another decimal

For example if we have to subtract 4.2 from 12.8

we write it like   1 2 . 8

                         - 0 4 . 2

                        ______

                            0 8 . 6       and the starting from right start subtracting

Given 43.3-12.82

          4 3 . 3 0

     -    1 2 . 8 2

_______________

          3 0  . 4  8    

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Step-by-step explanation:

1. Cloud of Dust and gas

2. solar system formation

3. spinning disc

4. early solar system today

Step-by-step explanation:

you can ask questions for clarification

[tex]\begin{array}{ccll} \stackrel{hours}{t}&\stackrel{height}{h}\\ \cline{1-2} 3&20\\ 5&19 \end{array}[/tex]  with those values provided from the table, let's get its equation

[tex](\stackrel{x_1}{3}~,~\stackrel{y_1}{20})\qquad (\stackrel{x_2}{5}~,~\stackrel{y_2}{19}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{19}-\stackrel{y1}{20}}}{\underset{run} {\underset{x_2}{5}-\underset{x_1}{3}}} \implies \cfrac{19 -20}{5 -3} \implies -\cfrac{ 1 }{ 2 }[/tex]

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{20}=\stackrel{m}{-\cfrac{ 1 }{ 2 }}(x-\stackrel{x_1}{3}) \implies y-20=-\cfrac{ 1 }{ 2 }x+\cfrac{3}{2} \\\\\\ y=-\cfrac{ 1 }{ 2 }x+\cfrac{3}{2}+20\implies y=-\cfrac{ 1 }{ 2 }x+\cfrac{43}{2}\implies \LARGE \begin{array}{llll} h=-\cfrac{ 1 }{ 2 }t+\cfrac{43}{2} \end{array}[/tex]

how talll will the candle be after 8 hours?  namely when t = 8.

[tex]h=-\cfrac{ 1 }{ 2 }(8)+\cfrac{43}{2}\implies h=-4+\cfrac{43}{2}\implies h=\cfrac{35}{2}\implies \LARGE \begin{array}{llll} h=17\frac{1}{2} \end{array}[/tex]

The linear equation for the area is:

40 = 7*(x + 4)

The solution is x = 1.71 = x

Remember that for a rectangle of length L and width W, the area is:

A = L*W

In this case, we can see that:

W = 7

L = x + 4

A = 70

Replacing that, we can get the linear equation:

40 = 7*(x + 4)

Now we can solve this, we jus need to isolate x.

40/7 = x + 4

40/7 - 4 = x

5.71 - 4 = x

1.71 = x

The solution is x = 1.71 = x

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The given quadratic polynomial function f(x) = 2x² - 4x - 6 has the vertex at (1, -8). Thus, the correct option is option C.

A quadratic polynomial function is a function which may be written in the form of ax² + bx + c = 0 where a, b and c are coefficients and x is the variable of the function. The quadratic polynomial function forms a parabola when plotted on the graph.

To find the vertex to the quadratic polynomial function we determine the value of x coordinate by the formula (-b/2a) and substitute the value of x in the polynomial function to get the value of y coordinate.

f(x) = 2x² - 4x - 6.

x coordinate = (-b/2a)

x = (4/2×2)

x = 4/4

x = 1

Now, the value of y coordinate = 2(1)² - 4(1) - 6

y = -8.

Thus, the given quadratic polynomial function f(x) = 2x² - 4x - 6 has the vertex at (1, -8).

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The range of the population standard deviation with a 95% confidence level  = 0.33 ≤ σ ≤ 0.87.

A data distribution's spread is measured by standard deviation. It calculates the average separation between each data point. Whether we consider the data to be a population unto itself or a sample of a larger population affects the formula we use to calculate standard deviation.

Sample data, x: {6.5, 6.6, 6.7, 6.8, 7.1, 7.3, 7.4, 7.7, 7.7, 7.7}

Sample size n = 10

Applying chi-square statistics with df=n-1=9-1=8

now 95% confidence interval is given by:

= [tex]\sqrt{\frac{(n-1) S^2}{\chi_{8,0.025}^2}} < \sigma < \sqrt{\frac{(n-1) S^2}{\chi_{8,0.975}^2}}[/tex]

= [tex]\sqrt{\frac{(9-1) * 0.462^2}{17.53}} < \sigma < \sqrt{\frac{(9-1) * 0.462^2}{2.18}}[/tex]

=  0.107 ≤ σ² ≤ 0.757

= 0.33 ≤ σ ≤ 0.87

The range of the population standard deviation with a 95% confidence level  = 0.33 ≤ σ ≤ 0.87.

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I understand that the question you are looking for is:

The values listed below are waiting times (in minutes) of customers at the Jefferson Valley Bank, where customers enter a single waiting line that feeds three teller windows. Find the sample variance s2 then construct a 95% confidence interval for the population standard deviation σ. Round sample variance to three decimal places. Assume that the population has a normal distribution. Critical values should have three decimal places and confidence interval limits should have two decimal places.

6.5, 6.6, 6.7, 6.8, 7.1, 7.3, 7.4, 7.7, 7.7, 7.7

Answer:

a. 7.78%

b.

c. lower

Step-by-step explanation:

5x+30=45

tkae the 30 to the other side and it becomes

5x=45-30

that gives you 15. then you want to divide 5 by 15

and then that gives you 3

x=3

Hope this helps you!

Kendra's samples are precise but not accurate.

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The sequence is in geometric series. Common ration= - 1/2, missing number i.e., the 5th term = 4

An arithmetic series is one where each term is equal to the one before it plus some number. Whereas a geometric series is one where each term equals the one before it multiplied by a certain value.

Here the sequence is Geometric series as from the sequence we are getting the common ratio.

Common ratio = [tex]\frac{-32}{64}[/tex] = [tex]\frac{16}{-32}[/tex] = -[tex]\frac{1}{2}[/tex]

Now we have to find the 5th term of the sequence.

We know the formula to find the nth term of the geometric series which is:

[tex]a_{n}[/tex] = a [tex]r^{n-1}[/tex]

[tex]a_{5}[/tex] = 64 [tex](\frac{-1}{2} )^{4}[/tex]

[tex]a_{5}[/tex] = 64/16

   = 4

Therefore the missing number is 4.

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Answer:

she has 130 crayons 100 crayons divided by 2 = 50 crayons each divide 30 by 2 =15

then she has the four crayons left divide those by 2

Answer: 13 cm 34 mm

Step-by-step explanation:

(80 cm 4 mm) * 1 layer/6 layers=

(80 cm 4 mm) * 1/6=

(80 cm 4 mm)/6=

(80 cm+4 mm) * 1/6=

80 cm/6 + 4 mm/6=

80/6 cm + 4/6 mm=

(78+2)/6 cm + 2/3 mm=

78/6 cm + 2/6 cm + 2/3 mm=

13 cm + 2/6 * 1000 mm + 2/3 mm=

13 cm + 1/3 * 1000 mm + 2/3 mm=

13 cm + 1000/3 mm + 2/3 mm=

13 cm+1002/3 mm=13 cm 34 mm

Answer: x∈(-∞,-2√6-2)U(2√6-2,+∞)

Step-by-step explanation:

[tex]\displaystyle\\y=\frac{1}{4} (x+2)^2-6\\y > 0\\Hence,\\\frac{1}{4}(x+2)^2-6 > 0 \\\\\frac{1}{4}(x+2)^2-6+6 > 0+6\\\\\frac{1}{4}(x+2)^2 > 6\\[/tex]

Multiply both parts of the equation by 4:

[tex](x+2)^2 > 24[/tex]

Extract the square root of both parts of the inequality:

[tex]|x+2| > \sqrt{24} \\|x+2| > \sqrt{4*6} \\|x+2| > 2\sqrt{6}[/tex]

Expand the modulus - we get a set of inequalities:

[tex]\displaystyle\\\left [{{x+2 > 2\sqrt{6}\ \ \ \ (1) } \atop {-(x+2) > 2\sqrt{6} \ \ \ (2)}} \right.\\[/tex]

Multiply both parts of inequality (2) by -1 and reverse the sign of the inequality:

[tex]\displaystyle\\\left [ {{x+2-2 > 2\sqrt{6}-2 } \atop {x+2 < -2\sqrt{6} }} \right. \ \ \ \ \ \left [ {{x > 2\sqrt{6}-2 } \atop {x+2-2 < -2\sqrt{6} -2}} \right. \ \ \ \ \ \left [ {{x > 2\sqrt{6}-2 } \atop {x < -2\sqrt{6}-2 }} \right.[/tex]

Thus,

[tex]x\in(-\infty,-2\sqrt{6}-2)U(2\sqrt{6} -2,+\infty)[/tex]