I need to find the expense and percent of the budget monthly total and annual expenses please help

Answer:

$432.18

Step-by-step explanation:

First year

$1800

-  540

$1260

Second year

$1260

-   378

$882

Third year

$882

- 264.60

$617.40

Fourth year

$617.40

-185.22

$432.18

The fraction is half of the sweaters cost $ 50 or less.

After placing the given set of numbers in order, the median is the value that falls in the middle of the group.

From the given box plot,

The value of the median is $ 50

We can clearly see that the median is $ 50 this means, 50% of the clothes are below $ 50 and 50% of the clothes are above $ 50.

The percentage of $ 50 or less sweaters is now 50%.

So, Required fraction = 50 / 100

= 5 / 10

= 1 / 2

Therefore, the fraction is half of the sweaters cost $ 50 or less.

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Given question is incomplete, complete question is below

Bella works at a popular clothing store. last winter ,her manager asked her to track the sweater sales. this box plot show the results.

question: what fraction of the sweater cost $50 or less?

Answer: 452.39

Step-by-step explanation: R= 6, H = 12. Volume formula is V= pi*r^2*h/3. For you, the equation is V = pi*6^2*12/3. 6^2 = 36, and 12/3 = 4. V = pi*36*4. Solving, we get V = 452.39.

To understand how to approach problems involving similar triangles, parallel lines, and proportional parts.

When you have two similar triangles, their corresponding sides are proportional. This means that the ratio between the sides of one triangle is the same as the ratio between the sides of the other triangle.

If you have parallel lines cut by a transversal, corresponding angles will be congruent, which can help establish similarity between triangles.

For example, if you have two similar triangles ABC and DEF, where AB/DE = BC/EF = AC/DF, then you can use these ratios to solve for unknown side lengths or other values.

To answer questions 1-16, identify the given information and determine whether the triangles are similar. If they are, use the proportional relationships to solve for the unknowns.

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How do you solve these problems on Unit 6: similar triangles homework 5: parallel lines and proportional parts?

7. X-5/6 = 14/2x+3

16. X-7/35 = 4/x-3

Eric has completed 37.5% (or 0.375) of the project, while Victoria has completed 33.3% (or 0.333) of the project. Together, they have completed approximately 70.8% (or 0.708) of the project.

If Eric and Victoria are working on a project and Eric has completed 3/8 of the project, and Victoria has completed 1/3 of the project, then to find the total portion of the project completed, you can add their individual contributions: (3/8) + (1/3).

To add these fractions, you need a common denominator, which is 24 in this case. So, you can rewrite the fractions as (9/24) + (8/24). Adding them together gives you a total of 17/24 of the project completed by both Eric and Victoria, which is equal to 70.8% (or 0.708).

*complete question: Eric and victoria are working on a project. eric has completed 3/8 of the project and and victoria has completed 1/3 of the project. Calculate the total work they have completed together.

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A) The null hypothesis (H0) is that there has been no change in the prevalence of HIV since the last census. The alternative hypothesis (Ha) is that there has been a change in the prevalence of HIV since the last census

B) At a 95% confidence level, the critical value for a two-tailed test is ±1.96.

A) The null hypothesis (H0) is that there has been no change in the prevalence of HIV since the last census, i.e., the current prevalence of HIV is still 7.5%. The alternative hypothesis (Ha) is that there has been a change in the prevalence of HIV since the last census, i.e., the current prevalence of HIV is different from 7.5%.

B) To test the hypothesis, we can use a z-test for proportions. The test statistic can be calculated as:

z = (p - p0) / [tex]\sqrt{(p0(1-p0)/n)}[/tex]

where p is the sample proportion of HIV positive cases, p0 is the hypothesized proportion under the null hypothesis, and n is the sample size.

In this case, p = 468 / 4706 = 0.099, p0 = 0.075, and n = 4706. Plugging these values into the formula, we get:

z = (0.099 - 0.075) / [tex]\sqrt{0.075(1-0.075)/4706}[/tex] = 8.80

At a 95% confidence level, the critical value for a two-tailed test is ±1.96. Since the calculated z-value (8.80) is much larger than the critical value, we can reject the null hypothesis and conclude that there is strong evidence to suggest that the prevalence of HIV has changed since the last census. In other words, the prevalence of HIV is different from 7.5%.

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Answer:

.15(180) - .10(180) = .05(180) = 9

9 more people voted for split pea soup than for potato soup.

After 16 years, compounded yearly, Lizzie will have $5,995.68 for college in Option A and $5,789.95 in Option B, rounded to the nearest dollar.

For Option A, the interest rate is 3% compounded yearly. Using the formula for compound interest, we have:

FV = PV x (1 + r)ⁿ

where FV is the future value, PV is the present value, r is the annual interest rate as a decimal, and n is the number of years. Plugging in the values, we get:

FV = $3000 x (1 + 0.03)¹⁶ = $5,995.68

For Option B, the interest rate is 2% compounded quarterly. We need to convert the annual interest rate to a quarterly rate by dividing it by 4. Then we use the formula:

FV = PV x (1 + r/n)^(n x t)

where r/n is the quarterly interest rate, n is the number of compounding periods per year, and t is the total number of years. Plugging in the values, we get:

FV = $3000 x (1 + 0.02/4)^(4 x 16) = $5,789.95

Therefore, Lizzie will have $5,995.68 for college in Option A and $5,789.95 in Option B, rounded to the nearest dollar.

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To find the length of AC in triangle ABC, we will use the Angle Bisector Theorem and the given information:
In triangle ABC, the bisector of angle A divides BC into segments BD and DC, with lengths of 28 units and 24 units, respectively. Given that AB has a length of 31.5 units, we want to determine the possible length of AC.

Step 1: Apply the Angle Bisector Theorem, which states that the ratio of the lengths of the sides is equal to the ratio of the lengths of the segments created by the angle bisector. In this case, we have:

AB / AC = BD / DC

Step 2: Plug in the known values:

31.5 / AC = 28 / 24

Step 3: Simplify the ratio on the right side:

31.5 / AC = 7 / 6

Step 4: Cross-multiply to solve for AC:

6 * 31.5 = 7 * AC

Step 5: Calculate the result:

189 = 7 * AC

Step 6: Divide both sides by 7 to find AC:

AC = 189 / 7

Step 7: Calculate the value of AC:

AC = 27 units

So, the length of AC in triangle ABC could be 27 units.

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The evaluated inequality for the given question is x≥3, under the condition that  models the solution for 3x+4. 5≤5(x-2).

Then the given model for the solution for 3x+4. 5≤5(x-2), so we have to apply the principles of solving inequality

5 ≤ 5(x - 2)

5 ≤ 5x - 10

15 ≤ 5x

3 ≤ x

Then, the inequality that represents the given model is  x≥3.

Inequality refers to a relation that makes a non-equal comparison between two numbers or other mathematical expressions. It is used to compare the size or order of two values on the number line. There are different symbols to represent different kinds of inequalities.

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The integer that represents a credit of $30 if zero represents the original balance is +30.

A credit represents an increase in funds, while a debit represents a decrease. In this case, a credit of $30 means that $30 has been added to the account, increasing the balance. Since zero represents the original balance, adding $30 results in a positive balance of $30, which is represented by the integer +30.

Therefore, +30 represents a credit of $30 if the original balance is zero. The reasoning behind this is that a credit increases the balance, so a positive integer is used to indicate the amount by which the balance has increased. In this case, it is an increase of $30, hence +30.

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The maximum walking speed of a giraffe with a leg of 6 feet is approximately 1.41 times greater than that of a hippopotamus with a leg of 3 feet.

The equation given in the problem, S= square root of gL, represents the maximum walking speed S of an animal with a leg of length L. To find the ratio of the maximum walking speed of a giraffe with a leg of 6 feet to that of a hippopotamus with a leg of 3 feet, we can plug in the values of g and L for each animal and calculate the ratio.

For the giraffe: S = √(g6) = √(326) ≈ 9.8 ft/sec

For the hippopotamus: S = √(g3) = √(323) ≈ 5.7 ft/sec

So the ratio of the maximum walking speed of a giraffe with a leg of 6 feet to that of a hippopotamus with a leg of 3 feet is approximately 9.8/5.7 ≈ 1.72 or 1.41 to the nearest hundredth.

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Part A: In the given scenario, the expression (32 + 2x) represents the rental price charged by the equipment rental business after x price increases of $2 each. The initial rental price is $32, and for every $2 increase in rental price, the rental price is raised by 2 units. The expression (24 – x) represents the number of rentals the equipment rental business can expect to make after x price increases. As the rental price increases, the number of customers is expected to decrease by one rental for every $2 increase in rental price.

Part B: To find the revenue after 3 rental price increases, we need to calculate f(3), where f(x) = (32 + 2x)(24 – x).

Substituting x = 3, we get:

f(3) = (32 + 2(3))(24 – 3) = (32 + 6)(21) = 38 × 21 = $798

Therefore, the revenue after 3 rental price increases is $798.

Part C: To find the rental price that would give the maximum revenue for the company, we need to find the value of x that maximizes the function f(x) = (32 + 2x)(24 – x). We can do this by finding the critical points of the function, which occur when the derivative of the function is equal to zero:

f'(x) = (32 + 2x)(-1) + (24 - x)(2) = -32 + 16x + 48 - 2x = 14x + 16

Setting f'(x) = 0 and solving for x, we get:

14x + 16 = 0

[tex]x = \frac{-16}{14} = \frac{-8}{7}[/tex]

However, [tex]x = \frac{-8}{7}[/tex] is not a valid solution since it represents a negative number of rental price increases, which is not possible in this scenario. Therefore, we need to test the endpoints of the interval [0, 6], since x represents the number of rental price increases and cannot exceed 6 (which would result in a rental price of $44, the maximum price in this scenario).

f(0) = (32 + 2(0))(24 - 0) = 32 × 24 = $768

f(6) = (32 + 2(6))(24 - 6) = 44 × 18 = $792

Comparing the values of f(0), f(3), and f(6), we see that f(6) gives the maximum revenue of $792. Therefore, the rental price that would give the maximum revenue for the company is $44, which is the rental price after 6 price increases of $2 each.

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Answer:

Step-by-step explanation:

a and b are sometimes true.

This is when line z intersects x and y at right angles.

Answer:

10

Step-by-step explanation:

40 = 10 × 4

70 = 10 × 7

GCF of 40 and 70 = 10

The slope of the line that is represented by the given data in the question is 3/4.

To find the slope of a line, we need to use the formula:

slope = (change in y) / (change in x)

We can choose any two points on the line and use their coordinates to calculate the change in y and the change in x. Let's choose the points (-9, 4) and (7, 16) from the given data.

Change in y = 16 - 4 = 12

Change in x = 7 - (-9) = 16

Plugging these values into the slope formula, we get:

slope = 12 / 16 = 3 / 4

We can also interpret this slope as the rate of change of y with respect to x. For every increase of 1 in x, y increases by 3/4. Similarly, for every decrease of 1 in x, y decreases by 3/4.

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Answer:

x = 58°

Step-by-step explanation:

Label the point where the diagonals cross as T

Diagonals always meet at right angles

m∠SRT = 32

Sum of interior angles of ΔSRT = 180

x = 180 - 90 - 32 = 58

Unfortunately, this integral doesn't have a simple closed-form solution. However, you can use numerical methods or software like Wolfram Alpha or a graphing calculator to approximate the value of the integral.

We have:

y = t and ds = sqrt(9t^4 + 1) dt

So, the line integral becomes:

∫C y^3 ds = ∫0^5 (t^3)(sqrt(9t^4 + 1)) dt

Using the substitution u = 9t^4 + 1, we get du/dt = 36t^3, which means dt = du/36t^3. Also, when t = 0, u = 1 and when t = 5, u = 1126.

Substituting these values and simplifying, we get:

∫C y^3 ds = (1/36) ∫1^1126 (u-1/4)(1/2) du
= (1/72) [(u-1)^2 u^(1/2)]_1^1126
= (1/72) [(1125)^2 (1126^(1/2)) - (1)^2 (1^(1/2))]

= 3555.89 (approx)

Therefore, the line integral is approximately equal to 3555.89.
To evaluate the line integral along the curve C with the given parameterization x = t^3 and y = t for 0 ≤ t ≤ 5, we need to find the integral of y^3ds. First, we need to find the derivative of the parameterization with respect to t:

dx/dt = 3t^2
dy/dt = 1

Now, we can find the differential arc length ds, which is given by the formula:

ds = √((dx/dt)^2 + (dy/dt)^2) dt

ds = √((3t^2)^2 + (1)^2) dt
ds = √(9t^4 + 1) dt

Next, substitute the parameterization of y in terms of t (y = t) into the integral:

∫(y^3 ds) = ∫(t^3 √(9t^4 + 1)) dt, with limits 0 to 5.

Now, evaluate the integral:

∫(t^3 √(9t^4 + 1)) dt from 0 to 5.

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By the end of 12 months, Claire will need 1,596,018 pens to house all the rabbits.

The number of adult rabbits in each month is the sum of the adult rabbits from the previous month and the number of baby rabbits that have grown to adulthood.

The number of baby rabbits in each month is the product of the number of adult rabbits in the previous month and the number of kits each pair of rabbits produces (6 in this case).

The total number of rabbits is simply the sum of the number of adult rabbits and the number of baby rabbits. Finally, the minimum pen size needed is found by divide the total number of rabbits by 2 (since each rabbit needs 2 square feet of space).

Month 1

Beginning of month: 2 rabbits (1 male, 1 female)

End of month: 8 rabbits (3 males, 5 females)

Number of pens needed: 16 square feet / 2 square feet per pen = 8 pens

Month 2

Beginning of month: 8 rabbits (3 males, 5 females)

End of month: 26 rabbits (11 males, 15 females)

Number of pens needed: 52 square feet / 2 square feet per pen = 26 pens

Month 3

Beginning of month: 26 rabbits (11 males, 15 females)

End of month: 80 rabbits (35 males, 45 females)

Number of pens needed: 160 square feet / 2 square feet per pen = 80 pens

Month 4

Beginning of month: 80 rabbits (35 males, 45 females)

End of month: 242 rabbits (105 males, 137 females)

Number of pens needed: 484 square feet / 2 square feet per pen = 242 pens

Month 5

Beginning of month: 242 rabbits (105 males, 137 females)

End of month: 728 rabbits (315 males, 413 females)

Number of pens needed: 1456 square feet / 2 square feet per pen = 728 pens

Month 6

Beginning of month: 728 rabbits (315 males, 413 females)

End of month: 2186 rabbits (945 males, 1241 females)

Number of pens needed: 4372 square feet / 2 square feet per pen = 2186 pens

Now, to continue for the next 6 months

Month 7

Beginning of month: 2186 rabbits (945 males, 1241 females)

End of month: 6568 rabbits (2835 males, 3733 females)

Number of pens needed: 13136 square feet / 2 square feet per pen = 6568 pens

Month 8

Beginning of month: 6568 rabbits (2835 males, 3733 females)

End of month: 19702 rabbits (8499 males, 11203 females)

Number of pens needed: 39404 square feet / 2 square feet per pen = 19702 pens

Month 9

Beginning of month: 19702 rabbits (8499 males, 11203 females)

End of month: 59110 rabbits (25499 males, 33611 females)

Number of pens needed: 118220 square feet / 2 square feet per pen = 59110 pens

Month 10

Beginning of month: 59110 rabbits (25499 males, 33611 females)

End of month: 177334 rabbits (76535 males, 100799 females)

Number of pens needed: 354668 square feet / 2 square feet per pen = 177334 pens

Month 11

Beginning of month: 177334 rabbits (76535 males, 100799 females)

End of month: 532006 rabbits (229799 males, 302207 females)

Number of pens needed: 1064012 square feet / 2 square feet per pen = 532006 pens

Month 12

Beginning of month: 532006 rabbits (229799 males, 302207 females)

End of month: 1596018 rabbits (689397 males, 906621 females)

Number of pens needed: 3192036 square feet / 2 square feet per pen = 1596018 pens

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The approximate distance between Padma and the bear is 21.2 ft, which corresponds to option A.

The approximate distance between Padma and the bear, we can use trigonometry. Since James and Padma are on opposite sides of the 100-ft-wide canyon,

we can form two right triangles with the bear's position as one of the vertices.

Step 1: Determine the horizontal distance from James to the bear.

Since the angle of depression from James to the bear is 45 degrees, the horizontal distance (x) and vertical distance (y) are equal due to the properties of a 45-45-90 right triangle. Therefore, x = y. Since the canyon is 100 ft wide, x + y = 100 ft. We can solve for x:

x + x = 100

2x = 100

x = 50 ft

Step 2: Determine the vertical distance from James to the bear.
Since x = y in the 45-45-90 right triangle, the vertical distance from James to the bear is also 50 ft.

Step 3: Determine the horizontal distance from Padma to the bear.
We can now use Padma's angle of depression, 65 degrees, to find the horizontal distance (p) from Padma to the bear. Using the tangent function:

tan(65) = vertical distance / horizontal distance

tan(65) = 50 ft / p

Solving for p:

p = 50 ft / tan(65) ≈ 21.2 ft

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The discount Joe received is $256 and Joe paid only $1024 for the computer after availing the 20% discount.

Joe purchased a computer that was priced at $1280. However, he was able to avail a discount of 20% off the regular price. To find out the discount that Joe received, we can use a simple formula.

Discount = Regular Price x Discount Rate

In this case, the regular price is $1280 and the discount rate is 20%. Therefore, the discount Joe received is:

Discount = $1280 x 0.20
Discount = $256

So, Joe received a discount of $256 on his purchase of the computer. This means that he paid only $1024 for the computer after availing the 20% discount. It's always important to calculate discounts before making any purchase to ensure you're getting the best deal possible.

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The correct answer is option (a), increase the height of the carton to 7 inches.

How can the volume of a handmade carton be increased by 42 cubic inches?

To increase the volume of the carton by 42 cubic inches, we need to increase either the length, width, or height of the carton or a combination of these dimensions.

Let's first calculate the current volume of the carton:

Volume = length x width x height

Volume = 7 x 6 x 6

Volume = 252 cubic inches

Now, we need to find a new dimension that will increase the volume by 42 cubic inches.

a) If we increase the height to 7 inches, the new volume will be:

New Volume = 7 x 6 x 7

New Volume = 294 cubic inches

The volume has increased by 42 cubic inches, so option (a) is the correct answer.

b) If we increase the height to 8 inches, the new volume will be:

New Volume = 7 x 6 x 8

New Volume = 336 cubic inches

The volume has increased by 84 cubic inches, which is more than required.

c) If we increase the width of the base to 8 inches, the new volume will be:

New Volume = 7 x 8 x 6

New Volume = 336 cubic inches

The volume has increased by 84 cubic inches, which is more than required.

d) If we increase the width of the base to 9 inches, the new volume will be:

New Volume = 7 x 9 x 6

New Volume = 378 cubic inches

The volume has increased by 126 cubic inches, which is more than required.

Therefore, the correct answer is option (a), increase the height of the carton to 7 inches.

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The length of the shadow cast by the 5 foot 6 inch student is approximately 1.83 feet.

To solve this problem, we'll set up a proportion using the principles of similar triangles. The two triangles in this case are the building and its shadow, and the student and their shadow.

Convert the height of the student to feet. 5 feet 6 inches is equal to 5.5 feet.

Set up the proportion. Let x represent the length of the shadow cast by the student. We have the following proportion:

(height of building) / (length of building's shadow) = (height of student) / (length of student's shadow)
60 / 20 = 5.5 / x

Cross-multiply and solve for x:

60 * x = 20 * 5.5
60x = 110
x = 110 / 60
x = 1.83 (rounded to two decimal places)

The length of the shadow cast by the 5 foot 6 inch student is approximately 1.83 feet.

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The corresponding values for the triangle in the larger circle are;

1. Perimeter of Δ BSH = 71.4 cm

2. The measure of ∠SBH = 102°.

3.  The area of Δ BSH = 41.54 cm²

4. The length of the circumference of circle B = 52.275 cm

1. The ratio of the perimeters of similar triangles is equal to the ratio of their corresponding sides. Since OB/OA = 4.25, we have:

Perimeter(Δ BSH) = Perimeter(Δ ARG) × 4.25

Perimeter(Δ BSH) = 16.8 cm × 4.25 = 71.4 cm

2. Since the triangles are similar, their corresponding angles are congruent. Therefore, ∠SBH = ∠RAG = 102°.

3. The ratio of the areas of similar triangles is equal to the square of the ratio of their corresponding sides. Since OB/OA = 4.25, we have:

Area(Δ BSH) = Area(Δ ARG) × (4.25)²

Area(Δ BSH) = 2.3 cm² × (4.25)² = 2.3 cm² × 18.0625 = 41.54 cm²

4. The ratio of the circumferences of similar circles is equal to the ratio of their radii or diameters. Since OB/OA = 4.25, we have:

Circumference(circle B) = Circumference(circle A) × 4.25

Circumference(circle B) = 12.3 cm × 4.25 = 52.275 cm

The above answers are in response to the following questions below;

Dante created the following measurements and calculations:

He then made the following measurements and calculations:

He calculated the ratio OB = 4.25.

                                      OA

He measured the perimeter of Δ ARG, and found it to be 16.8 cm.

He measured ∠RAG = 102°.

He calculated the area of Δ ARG, and found it to be 2.3 cm2.

He calculated the circumference of circle A, and found it to be approximately 12.3 cm.

He would now like to calculate corresponding values for the triangle in the larger circle, and he needs your help.

Calculate the following, using your knowledge that all circles are similar, along with the data already collected by Noah..

5. Find the perimeter of Δ BSH.

6. Find the measure of ∠SBH.

7. Find the area of Δ BSH.

8. Find the length of the circumference of circle B.

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Using Newton's method, the root of the equation cos(x) = x correct to six decimal places is approximately 0.739085.

To solve the equation cos(x) = x, we can use Newton's method, which involves repeatedly applying an iterative formula to approximate the root of the equation. We first rewrite the equation in the form f(x) = cos(x) - x = 0 and find its derivative f'(x) = -sin(x) - 1.

The iterative formula for Newton's method is given by xn+1 = xn - f(xn)/f'(xn). Applying this formula, we get xn+1 = xn + cos(xn) - xn sin(xn) + 1.

To start the iteration, we need to guess a suitable value for x1. From the graph of y = cos(x) and y = x, we can see that they intersect at a point whose x-coordinate is slightly less than 1. Therefore, we take x1 = 1 as a convenient first approximation.

Using a calculator in radian mode, we can apply the iterative formula to obtain the following approximations:

x2 ≈ 0.75036387

x3 ≈ 0.73911289

x4 ≈ 0.73908513

x5 ≈ 0.73908513

Since x4 and x5 agree to six decimal places, we can conclude that the root of the equation cos(x) = x correct to six decimal places is approximately 0.739085.

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The probability that the next customer will pay with cash is 0.639 or approximately 63.9%.

To find the probability that the next customer will pay with cash, we need to know the total number of customers, including those who paid with cash, debit card, and credit card.

Total number of customers = number of customers who paid with cash + number of customers who used debit card + number of customers who used credit card

Total number of customers = 71 + 4 + 36

Total number of customers = 111

Therefore, there were 111 customers in total.

The probability that the next customer will pay with cash is the number of customers who paid with cash divided by the total number of customers.

Probability of paying with cash = number of customers who paid with cash / total number of customers

Probability of paying with cash = 71 / 111

Probability of paying with cash = 0.639 (rounded to three decimal places)

Therefore, the probability that the next customer will pay with cash is 0.639 or approximately 63.9%.

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The point N(-5,-3) lies inside the circle centered at C(0,0) with radius √38.

Since the point M(0, √38) lies on the circle with center C(0,0), we can find the radius of the circle by finding the distance between M and C:

r = √[tex]((0 - 0)^2[/tex] + (√[tex]38 - 0)^2)[/tex] = √38

Now that we know the radius of the circle is √38, we can determine where the point N(-5,-3) lies relative to the circle. We can find the distance between N and the center of the circle:

d = √[tex]((-5 - 0)^2[/tex] + [tex](-3 - 0)^2)[/tex] = √34

Since the distance between N and the center of the circle is less than the radius of the circle, the point N is inside the circle. Therefore, N lies inside the circle centered at C(0,0) with radius √38.

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The population in this study is the jars of marinara sauce produced at the Barilla plant in Ames, IA.

The population in this study refers to all jars of marinara sauce produced at the Barilla plant in Ames, IA in the last week. It represents the entire set of jars that the quality assurance engineer could potentially sample from.

The population mean is stated as 26.2 ounces, indicating the average amount of sauce per jar for the entire population. The population standard deviation is given as 0.04 ounces, representing the variability in the amount of sauce across all jars produced.

The quality assurance engineer randomly selected a sample of 34 jars from this population and found the mean amount of sauce per jar to be 26.197 ounces.

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