I need helppppp plus!!!!

Answer:

...

Step-by-step explanation:

Hey there! I'm happy to help!

Here is our equation

3x - 4 (2x - 5) = 15

First, we will sue the distributive property to remove the parentheses. The term outside the parentheses is -4, so that is what we multiply the insides by.

3x-8x+20=15

We combine our like terms (our x-values).

-5x+20=15

We subtract 20 from both sides.

-5x=-5

We divide both sides by -5.

x=1

Have a wonderful day and keep on learning! :D

Answer: x = 1

Step-by-step explanation:

Given

3x - 4 (2x - 5) = 15

Expand parentheses and apply the distributive property

3x - 4 · 2x - 4 · (-5) = 15

3x - 8x + 20 = 15

Combine like terms

(3x - 8x) + 20 = 15

-5x + 20 = 15

Subtract 20 on both sides

-5x + 20 - 20 = 15 - 20

-5x = -5

Divide -5 on both sides

-5x / -5 = -5 / -5

[tex]\boxed{x=1}[/tex]

Hope this helps!! :)

Please let me know if you have any questions

Answer:

a. 33 sq.m

b.33x sq.m

Step-by-step explanation:

In a) formula of area of rectangle is:

Area= length * width

where 3m is width and 11m is length

Now area = 3 *11

area= 33 sq.m

In b) formula is same as above

area= 3x * 11

area= 33x sq.m

Answer:

y = 4x

k = 4

Step-by-step explanation:

Answer:

This is an incomplete question.

Step-by-step explanation:

Can you please repeat the question properly.

Answer:

[tex]227 \frac{1}{16} [/tex]

Step-by-step explanation:

[tex]15 \frac{3}{4} \times (7 \frac{3}{4} + 6 \frac{2}{3} ) [/tex]

[tex] = \frac{63}{4} \times ( \frac{31}{4} + \frac{20}{3} )[/tex]

[tex] = \frac{63}{4} \times ( \frac{93}{12} + \frac{80}{12} )[/tex]

[tex] = \frac{63}{4} \times \frac{173}{12} [/tex]

[tex] = 227\frac{1}{16} [/tex]

Answer:

it is a cubic bi-nominal

Step-by-step explanation:

Answer:

Step-by-step explanation:

before it is factored, it is a binomial. I think that is the way I would answer the question. If you take out an x, you get one monomial and something that does not factor giving rational results for the numerical coefficients.

x (2x^2 - 9) This can't be factored giving rational coefficients.

Answer:

-9

math websites helpp:)

Answer:

[tex]6 \times {10}^{3} = 6000[/tex]

Step-by-step explanation:

[tex](1.5 \times {10}^{ - 6} ) \times (4 \times {10}^{9} )[/tex]

[tex] = (1.5 \times 4) \times ( {10}^{ - 6} \times {10}^{9} )[/tex]

[tex] = 6 \times ( {10}^{ - 6} \times {10}^{9}) [/tex]

[tex] = 6 \times {10}^{ - 6 + 9} [/tex]

[tex] = 6 \times {10}^{3} [/tex]

[tex] = 6000[/tex]

Answer:

{all multiples of three} , {all multiples of four}

Step-by-step explanation:

hope it helps u

pls mark me as branliest

Answer:

option d!!!!!!

12, and 18

Answer:

No

Step-by-step explanation:

Any point that aligns on the line of y = 2 is a solution. But (8, -2) falls below that line since the point's y-coordinate is equal to -2, not 2. Hope this helps!

Patterns are set of rules that guide the creation of a dataset. The observation from the first three designs are as follows:

The pattern

The first three design show that, as the design number increases (i.e. 1, 2, 3), the number of tiles used also increases (i.e. 7, 12, 19)

The expressions for the number of tiles

The design number and the number of tiles is represented as follows

[tex]1 \to 7[/tex]

[tex]2 \to 12[/tex]

[tex]3 \to 19[/tex]

From the designs, we observe that some tiles are at the middle, while other tiles are at the sides.

Design 1 has 1 tile at the center and 6 tiles at either sides.

So, we have:

[tex]1 \to 1 + 6[/tex]

[tex]2 \to 4 + 8[/tex]

[tex]3 \to 9 + 10[/tex]

Expand

[tex]1 \to 1^2 + 6 \to 1^2 + 2 \times 3 \to 1^2 + 2 \times (1 + 2)[/tex]

[tex]2 \to 2^2 + 8 \to 2^2 + 2 \times 4 \to 2^2 + 2 \times (2 + 2)[/tex]

[tex]3 \to 3^2 + 10 \to 3^2 + 2 \times 5 \to 3^2 + 2 \times (3 + 2)[/tex]

Notice the pattern,

The number of tiles in design n will be:

[tex]Tiles = n^2 + 2 \times (n + 2)[/tex]

Open bracket

[tex]Tiles = n^2 + 2n + 4[/tex]

Hence, the expressions for number of tiles in design n are:

[tex]n^2 + 2(n + 2)[/tex] and [tex]n^2 + 2n + 4[/tex]

Technology to prove that both expressions are equivalent

To prove that [tex]n^2 + 2(n + 2)[/tex] and [tex]n^2 + 2n + 4[/tex] are equivalent using technology, the graphs of [tex]n^2 + 2(n + 2)[/tex] and [tex]n^2 + 2n + 4[/tex] can be plotted and then compared

The table and graph for the first 6 designs

The table entry for the first 6 designs is calculated as follows:

[tex]n = 1\ \ \ \ \ Tiles = 1^2 + 2 \times 1 + 4 = 7[/tex]        

[tex]n = 2\ \ \ \ \ Tiles = 2^2 + 2 \times 2 + 4 = 12[/tex]        

[tex]n = 3\ \ \ \ \ Tiles = 3^2 + 2 \times 3 + 4 = 19[/tex]        

[tex]n = 4\ \ \ \ \ Tiles = 4^2 + 2 \times 4 + 4 = 28[/tex]        

[tex]n = 5\ \ \ \ \ Tiles = 5^2 + 2 \times 5 + 4 = 39[/tex]        

[tex]n = 6\ \ \ \ \ Tiles = 6^2 + 2 \times 6 + 4 = 52[/tex]        

So, we have:

[tex]\begin{array}{cc}Design & {Tiles} & {1} & {7} & {2} & {12} & 3 & {19} & {4} & {28} & {5} & {39}& {6} & {52} \ \end{array}[/tex]

See attachment for the graph of the above table

All the points on the curve make sense in this scenario because all values are positive.

The pattern type

We have:

[tex]Tiles = n^2 + 2n + 4[/tex]

When an equation has a degree of 2, the equation is quadratic.

Hence, the pattern is quadratic.

The largest design that an empty sign of 10ft by 12ft can contain.

From the first three designs:

The number of tiles on a complete row and column are always the same.

Design 1 has 3 tiles in its complete row and column

Design 2 has 4 tiles in its complete row and column

Design 3 has 5 tiles in its complete row and column

The relationship between the design number (d) and the number of complete tiles (t) is:

[tex]d = t - 2[/tex]

For the 10ft by 12ft empty sign

[tex]t = 10[/tex] because [tex]10 < 12[/tex]

So, we have:

[tex]d = t - 2[/tex]

[tex]d = 10 - 2[/tex]

[tex]d = 8[/tex]

Hence, the largest design number is design 8

Read more about patterns at:

https://brainly.com/question/13382968

Answer:

PQ measures 36 units.

Step-by-step explanation:

Line RS bisects segment PQ at R. By the definition of a bisector:

[tex]\displaystyle PR = RQ[/tex]

Hence:

We are given that RQ = x + 9 and RP = 2x, and we want to determine PQ.

Solve for x. Substitute:

[tex]\displaystyle (2x) = (x+9)[/tex]

Hence:

[tex]\displaystyle x = 9[/tex]

PQ is given by:

[tex]\displaystyle PQ = PR + RQ[/tex]

Since PR = RQ:

[tex]\displaystyle PQ =2PR[/tex]

Substitute and evaluate:

[tex]\displaystyle \begin{aligned} PQ &= 2PR \\ &= 2(2x) \\ &= 4x \\ &= 4(9) \\ &= 36 \end{aligned}[/tex]

Hence, PQ measures 36 units.

Answer:

125

Step-by-step explanation:

5³= 5 × 5 × 5 = 125

Answer:

125 is your answer.

Step-by-step explanation:

b = 5

=5 X 5 X 5

=125

Answer:

600

almost got confused with hundredth lol decimals

Answer:

600

Step-by-step explanation:

=======================================================

Explanation:

We start with set M = {m,a,t,h,s}

Then we cross off any letter we find in set N

So we'll cross off the 'm' and 'a' since they are both in N. We're kicking these letters out of the set.

We go from {m,a,t,h,s} to {t,h,s}

We leave t,h and s alone as those letters aren't in set N. So we don't kick them out.

Answer: {t,h,s}  choice A

Answer:

0.2272727

Step-by-step explanation:

The total number of marbles to begin with is 4 + 2 + 6 = 12

He draws 1 marble, which makes the total 11

He draws another marble, which makes the new total 10

6/12 * 5 / 11 = 30 / 132 = 1/2 * 5 / 11 = 5/22

I take it that the approximate probability is a decimal.

30/132 = 0.22727 ...

5/22 = 0.2272727 ....

The answers to the two fractions are the same and approximately the right answer of 5/22

Answer:

m = 3/2

Step-by-step explanation:

-3(2m+1)+7=-5

Distribute

-6m -3 +7 = -5

Combine like terms

-6m +4 = -5

Subtract 4 from each side

-6m+4-4 = -5-4

-6m =-9

Divide each side by -6

-6m/-6 = -9/-6

m = 3/2

Answer:

the answer is [tex]\frac{1}{41} (23x-2ln(5sinx+4cosx))[/tex]

Step-by-step explanation:

[tex]\int {\frac{3sinx+2cosx}{5sinx+4cosx} } \, dx[/tex]

here,

a=3, b=2, c=5, d=4

[tex]M=\frac{ac+bd}{c^2+d^2 }=\frac{3*5+2*4}{5^2+4^2}=\frac{23}{41}[/tex]

[tex]N=\frac{bc-ad}{c^2+d^2 }=\frac{2*5-3*4}{5^2+4^2}=\frac{-2}{41}[/tex]

[tex]\int {\frac{3sinx+2cosx}{5sinx+4cosx} } \, dx=\int{\frac{\frac{23}{41}(5sinx+4cosx)-\frac{2}{41}(5cosx-4sinx) }{5sinx+4cosx} }\,dx[/tex]

[tex]=\frac{23}{41}\int\, dx -\frac{2}{41} \int{\frac{5cosx-4sinx}{5sinx+4cosx} }\, dx[/tex]

[tex]=\frac{1}{41} (23x-2ln(5sinx+4cosx))[/tex]

pls mark it as the brainliest

X=10

Y=14

Step-by-step explanation:

Solve simultaneously using substitution method as shown in the image

Answer:

C: 1/4x + 4 = 3

Step-by-step explanation:

1/4x + 4 = 3

1/4x = 3 - 4

x = - 4

Thus, option c gives out the solution x = - 4.

Answer:

3

Step-by-step explanation:

12 times 3 = 36

36 times 6 = 216

12(x times 6)

(12)6x

72x

216 = 72x

216/72 = 3

Answer:

The number 3 makes this statement true.

[tex]x=3[/tex]

Step-by-step explanation:

Given the equation:

[tex](12*3)*6=12*(x*6)[/tex]

Using the order of operations, we can evaluate the terms in the parentheses through the process of multiplication:

[tex]36*6=12*6x[/tex]

Multiply the terms on both sides of the equation:

[tex]216=72x[/tex]

Finally, divide both sides of the equation by the coefficient of [tex]x[/tex], which is [tex]72[/tex]:

[tex]3=x[/tex]

[tex]x=3[/tex]

-

Let's check our work by substituting the solved [tex]x[/tex] value for

[tex](12*3)*6=12*(3*6)[/tex]

[tex]36*6=12*18[/tex]

[tex]216=216[/tex]

Since both sides of the equation are equal to each other, our solution is correct!

Answer:

5/7 i believe thats the answer to your question

Answer:

x=(-5)/2

Step-by-step explanation:

-8×(-2)=-2x+11

16-11=(-2x)

x=(-5)/2

Answer:

8 more hours

Step-by-step explanation:

13 hrs + 6 hrs = 19

27hrs total - 19hrs

27-19+=8 more hours. TADA!!!!

Answer:

8

Step-by-step explanation:

total hours you can work 3 week : 27 hours

total hour you can work in first and second week: 13+6= 19 hours

=>the third week will take: 27 - 19=8 hours

Answer:

Option I

Step-by-step explanation:

Let

[tex]f(x)=x^2+3x-28[/tex]

We know by subsitution,

[tex]f(-9)=(-9)^2+3(-9)-28=26>0[/tex]

[tex]f(0)=0^2+3(0)-28=-28<0[/tex]

[tex]f(5)=5^2+3(5)-28=12>0[/tex]

Since a quadratic equation only have 1 turning point, we know for some values a in (-9, 5) such that f(a)<0. And the option of the range of a must lie with in (-9, 5).

Therefore, only Option I is correct.