I need help with this question

To prove that |z+w| ≤ |z| + |w| for two complex numbers z and w, we can use an algebraic proof.

First, let's rewrite z and w in terms of their real and imaginary parts:

z = a + bi

w = c + di

Now, we can use the definition of the absolute value of a complex number to write:

|z+w| = |(a+c) + (b+d)i|

= √((a+c)² + (b+d)²)

Similarly, we can write:

|z| = |a + bi| = √(a² + b²)

|w| = |c + di| = √(c² + d²)

Now, we can use the triangle inequality to prove that |z+w| ≤ |z| + |w|:

√((a+c)² + (b+d)²) ≤ √(a² + b²) + √(c² + d²)

Squaring both sides of the inequality gives us:

(a+c)² + (b+d)² ≤ (a² + b²) + (c² + d²) + 2√((a² + b²)(c² + d²))

Expanding the left-hand side of the inequality gives us:

a² + 2ac + c² + b² + 2bd + d² ≤ a² + b² + c² + d² + 2√((a² + b²)(c² + d²))

Simplifying and rearranging terms gives us:

2ac + 2bd ≤ 2√((a² + b²)(c² + d²))

Dividing both sides of the inequality by 2 gives us:

ac + bd ≤ √((a² + b²)(c² + d²))

Squaring both sides of the inequality again gives us:

(a² + b²)(c² + d²) - (ac + bd)² ≥ 0

Expanding and simplifying gives us:

a²c² + a²d² + b²c² + b²d² - a²c² - 2abcd - b²d² ≥ 0

a²d² + b²c² - 2abcd ≥ 0

(a²d² - 2abcd + b²c²) ≥ 0

(a² - 2ab + b²)(d² - 2cd + c²) ≥ 0

(a - b)²(d - c)² ≥ 0

Since the square of any real number is always greater than or equal to zero, this inequality is always true. Therefore, |z+w| ≤ |z| + |w| for any two complex numbers z and w. This completes the algebraic proof.

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Thhe standard error of the sample mean is 0.208333.  The probability that the sample mean is within 0.5 units of the population mean is 0.9918. We need to take a sample size of at least 7 to be 98% confident that the sample mean is within one-half of the population mean.

(i) The standard error of the sample mean is calculated by dividing the standard deviation of the population by the square root of the sample size. In this case, the standard error of the sample mean is 1.25 / √36 = 1.25 / 6 = 0.208333.

(ii) To find the probability that the sample mean is within 0.5 units of the population mean, we need to use the standard normal distribution. We can find the z-score for 0.5 units away from the mean by dividing 0.5 by the standard error of the sample mean, which is 0.5 / 0.208333 = 2.4.

Using a standard normal table, we can find the probability that the sample mean is within 2.4 standard deviations of the population mean, which is 0.9918.

(iii) To be 98% confident that the sample mean is within one-half of the population mean, we need to find the sample size that corresponds to a z-score of 2.33 (the z-score for a 98% confidence interval). We can use the formula for the standard error of the sample mean to solve for the sample size:

0.5 = 1.25 / √n

√n = 1.25 / 0.5

n = (1.25 / 0.5)²

n = 6.25

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Answer:

sin(B)/b = sin(A)/a

sin(B)/12 = sin(58)/a

a = 12(sin(58)/sin(B))

Now we can use the Law of Cosines to find the remaining sides of the triangle:

a^2 = b^2 + c^2 - 2bc*cos(A)

a^2 = 12^2 + c^2 - 2(12)(c)*cos(58)

c^2 - 24c*cos(58) + 144 - a^2 = 0

Using the quadratic formula, we get:

c = (24*cos(58) ± sqrt((24*cos(58))^2 - 4(1)(144 - a^2)))/2(1)

c = 12*cos(58) ± sqrt(144*cos(58)^2 - 4(144 - a^2))

c = 12*cos(58) ± sqrt(576*cos(58)^2 - 4a^2)

c = 12*cos(58) ± sqrt(576*(1 - sin(58)^2) - 4a^2)

c = 12*cos(58) ± sqrt(576 - 576*sin(58)^2 - 4a^2)

c = 12*cos(58) ± sqrt(576 - 576*sin(58)^2 - 4(12(sin(58)/sin(B)))^2)

c = 12*cos(58) ± sqrt(576 - 576*sin(58)^2 - 576(sin(58)/sin(B))^2)

c = 12*cos(58) ± sqrt(576 - 576*sin(58)^2 - 576(sin(58)/sin(B))^2)

c = 12*cos(58) ± sqrt(576 - 576*sin(58)^2 - 576(sin(58)/sin(B))^2)

c = 12*cos(58) ± sqrt(576 - 576*sin(58)^2 - 576(sin(58)/sin(B))^2)

c = 12*cos(58) ± sqrt(576 - 576*sin(58)^2 - 576(sin(58)/sin(B))^2)

c = 12*cos(58) ± sqrt(576 - 576*sin(58)^2 - 576(sin(58)/sin(B))^2)

c = 12*cos(58) ± sqrt(576 - 576*sin(58)^2 - 576(sin(58)/sin(B))^2)

c = 12*cos(58) ± sqrt(576 - 576*sin(58)^2 - 576(sin(58)/sin(B))^2)

c = 12*cos(58) ± sqrt(576 - 576*sin(58)^2 - 576(sin(58)/(sin(180 - A - B)))^2)

c = 12*cos(58) ± sqrt(576 - 576*sin(58)^2 - 576(sin(58)/(sin(180 - 58 - B)))^2)

c = 12*cos(58) ± sqrt(576 - 576*sin(58)^2 - 576(sin(58)/(sin(122 - B)))^2)

Now we can substitute the value we found for a into the equation for c to get:

c = 12*cos(58) ± sqrt(576 - 576*sin(58)^2 - 576(sin(58)/(sin(122 - B)))^2)

c = 12*cos(58) ± sqrt(576 - 576*sin(58)^2 - 576(sin(58)/(sin(122 - arcsin(a/b))))^2)

c = 12*cos(58) ± sqrt(576 - 576*sin(58)^2 - 576(sin(58)/(sin(122 - arcsin(12/a))))^2)

c = 12*cos(58) ± sqrt(576 - 576*sin(58)^2 - 576(sin(58)/(sin(122 - arcsin(12/(12(sin(58)/sin(B)))))))^2)

c = 12*cos(58) ± sqrt(576 - 576*sin(58)^2 - 576(sin(58)/(sin(122 - arcsin(sin(58)/sin(B))))))^2)

c = 12*cos(58) ± sqrt(576 - 576*sin(58)^2 - 576(sin(58)/(sin(122 - arcsin(sin(58)/(12*sin(58)/a))))))^2)

c = 12*cos(58) ± sqrt(576 - 576*sin(58)^2 - 576(sin(58)/(sin(122 - arcsin(a/12))))))^2)

c = 12*cos(58) ± sqrt(576 - 576*sin(58)^2 - 576(sin(58)/(sin(122 - arcsin(1/12)*a))))))^2)

c = 12*cos(58) ± sqrt(576 - 576*sin(58)^2 - 576(sin(58)/(sin(122 - 4.98)*a))))))^2)

c = 12*cos(58) ± sqrt(576 - 576*sin(58)^2 - 576(sin(58)/(sin(117.02)*a))))))^2)

c = 12*cos(58) ± sqrt(576 - 576*sin(58)^2 - 576(sin(58)/(0.97*a))))))^2)

c = 12*cos(58) ± sqrt(576 - 576*sin(58)^2 - 576(1.03*a/sin(58))))))^2)

c = 12*cos(58) ± sqrt(576 - 576*sin(58)^2 - 576(1.03*(12*sin(58)/sin(B))/sin(58))))))^2)

c = 12*cos(58) ± sqrt(576 - 576*sin(58)^2 - 576(1.03*(12/sin(B)))))^2)

c = 12*cos(58) ± sqrt(576 - 576*sin(58)^2 - 576(1.03*(12/sin(180 - A - B)))))^2)

c = 12*cos(58) ± sqrt(576 - 576*sin(58)^2 - 576(1.03*(12/sin(180 - 58 - B)))))^2)

c = 12*cos(58) ± sqrt(576 - 576*sin(58)^2 - 576(1.03*(12/sin(122 - B)))))^2)

Now we can solve for c using the two possible values of B:

B = arcsin(b*sin(A)/a)

B = arcsin(12*sin(58)/a)

B = arcsin(12*sin(58)/(12*sin(58)/sin(B)))

B = arcsin(sin(B))

B = 58

or

B = 180 - arcsin(b*sin(A)/a)

B = 180 - arcsin(12*sin

Considering the expression of a line, the gradient or slope is zero and the line is horizontal.

A linear equation o line can be expressed in the form y = mx + b

where

Knowing two points (x₁, y₁) and (x₂, y₂) of a line, the slope of the line can be calculated using:

m= (y₂ - y₁)÷ (x₂ - x₁)

In this case, being (x₁, y₁)= (4, 7) and (x₂, y₂)= (9, 7), the slope m can be calculated as:

m= (7 -7)÷ (9 -4)

m= 0÷ 5

m= 0

Finally, the gradient or slope is zero.

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The Equation to represent the amount she spend on the material

is y= 15 + 0.75 x.

A line's slope is determined by how its y coordinate changes in relation to how its x coordinate changes. y and x are the net changes in the y and x coordinates, respectively. Therefore, it is possible to write the change in y coordinate with respect to the change in x coordinate as,

m = Δy/Δx where, m is the slope

For First 10 pound the charges will be $1.50.

Each additional pound $0.75

let She bought x pounds then the price is 0.75x

Now, The Equation to represent the amount she spend on the material

y = 10 (1.5)+ 0.75x

y= 15 + 0.75 x

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Answer:

  75 cm

Step-by-step explanation:

You want to know the length of the struts between the edge of a parabolic dish 120 cm in diameter and 15 cm deep, and the collector at the focus of the dish.

The equation of a parabola with its vertex at the origin and passing through points (±60, 15) can be written as ...

  y/15 = (x/60)² . . . . parabola scaled vertically by 15, horizontally by 60

  240y = x² . . . . . .  multiply by 3600

  4(60)y = x² . . . . . factor out 4 from the coefficient of y

This equation is of the form ...

  4py = x²

where p = 60 is the distance from the vertex to the focus. Since the dish is 15 cm deep, the focus lies 60-15 = 45 cm above the edge of the dish.

The length of each strut from the edge of the dish to the focus will be the hypotenuse of a right triangle with legs 45 and 60. The Pythagorean theorem tells us that length is ...

  c² = a² +b²

  c = √(a² +b²) = √(45² +60²) = 15√(9+16) = 75

The length x of each strut is 75 cm.

Answer:

9

Step-by-step explanation:

A professional golfer to make about 40.7 holes over 5 rounds of golf with the new club, while an amateur golfer would only make about 1.6.

First, let's define some variables to represent the probabilities of making a hole for a professional golfer and an amateur golfer:

Let p be the probability that a professional golfer makes a hole with the new club.

Let q be the probability that an amateur golfer makes a hole with the new club.

According to the company's claims, we know that:

p = 1.2q (since the professional golfer makes a hole 120% of the time, which is 1.2 times the probability of the amateur golfer making a hole)

Next, we need to determine the probability of each golfer making a hole during one round of golf, which consists of 18 holes. Let's assume that each hole is independent of the others, meaning that the outcome of one hole does not affect the outcome of another. In that case, the probability of making at least one hole in a round can be calculated using the complement rule:

The probability that a professional golfer makes at least one hole in a round is 1 minus the probability that the golfer misses every hole: [tex]1 - (1-p)^{18} .[/tex]

The probability that an amateur golfer makes at least one hole in a round is[tex]1 - (1-q)^{18} .[/tex]

Now, let's use these probabilities to calculate the expected number of holes each golfer will make in 5 rounds of golf:

The expected number of holes made by a professional golfer in 5 rounds is 5 times the expected number of holes made in one round, which is [tex](1 - (1-p)^{18} )\times18.[/tex]

The expected number of holes made by an amateur golfer in 5 rounds is 5 times the expected number of holes made in one round, which is [tex](1 - (1-q)^{18} )\times18.[/tex]

We can simplify these expressions using the relationship between p and q:

The expected number of holes made by a professional golfer in 5 rounds is [tex]518(1 - (1-1.2q)^{18} ).[/tex]

The expected number of holes made by an amateur golfer in 5 rounds is [tex]518(1 - (1-q)^{18} ).[/tex]

We can now evaluate these expressions using the values of p and q:

[tex]p = 1.2q, so q = p/1.2[/tex]

Substituting this into the expressions above, we get:

The expected number of holes made by a professional golfer in 5 rounds is[tex]518(1 - (1-1.2(p/1.2))^{18} ) = 518(1 - (1-p)^{18} ).[/tex]

The expected number of holes made by an amateur golfer in 5 rounds is [tex]518(1 - (1-p/1.2)^{18} ).[/tex]

Finally, we can evaluate these expressions using the given probabilities:

The expected number of holes made by a professional golfer in 5 rounds is[tex]518(1 - (1-1.2q)^{18} ) = 518(1 - (1-1.2(0.1))^{18} ) = 40.7.[/tex]

The expected number of holes made by an amateur golfer in 5 rounds is [tex]518(1 - (1-q)^{18} ) = 518(1 - (1-0.1/1.2)^{18} ) = 1.6.[/tex]

So according to these calculations, we would expect a professional golfer to make about 40.7 holes over 5 rounds of golf with the new club, while an amateur golfer would only make about 1.6

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20/325 is equivalent to 6.15% rounded off to one decimal place.

A fraction is used to denote a portion or component of a whole. It stands for the proportionate pieces of the whole. Numerator and denominator are the two components that make up a fraction. The numerator is the number at the top, and the denominator is the number at the bottom.

To express a fraction as a percentage, you need to multiply the fraction by 100. Therefore, we have:

20/325 = 0.0615

Multiplying by 100, we get:

0.0615 x 100 = 6.15%

So, 20/325 is equivalent to 6.15% rounded off to one decimal place.

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Answer: I could be wrong but its either going to be 13.5 or 13.

Step-by-step explanation:

Answer:

13.5 goals

Step-by-step explanation:

We can use a ratio to solve

3 goals                   x

---------------  = -------------

2 games            9 games

Using cross products

3 * 9 = 2x

27 = 2x

Divide each side by 2

27/2 = x

13.5 goals

Answer:

FDG is 28 degrees, and x = 4

Step-by-step explanation:

We can see for angle EDG that there is a little box at the angle. This means that it is a right angle, which means it is 90 degrees. This, in turn, means that the two angles formed there (angle EDF, and angle FDG) will add up to that number, 90 degrees because they are within the initial angle.

Let us create an equation using our angles. We know one is 62 degrees and the other is 7x degrees.

62 +7x = 90

7x = 28

x =4

This means that the unknown value is 4, and since the angle was 7x, it is really 7(4) = 28 degrees, and we know the other angle is 62 degrees.

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The final answer is 16 - 1 = 15 linear extensions of the poset P.

The poset P has 8 linear extensions. We can determine the number of linear extensions by counting the number of topological sorts of the poset. A topological sort of a poset is a linear ordering of its vertices that respects the partial ordering. There are two ways to obtain a topological sort of the poset P:

1. Start with vertex A, then choose either B or F, then choose either C or G, then choose either D or H, and finally choose E. This gives us a total of 2 x 2 x 2 x 1 = 8 topological sorts.

2. Start with vertex F, then choose either A or G, then choose either B or H, then choose either C or D, and finally choose E. This also gives us a total of 2 x 2 x 2 x 1 = 8 topological sorts.

Therefore, the total number of linear extensions of the poset P is 8 + 8 = 16.

However, we need to subtract the number of topological sorts that are counted twice. These are the topological sorts that start with A, then choose F, then choose G, then choose H, and finally choose E. There are 1 x 1 x 1 x 1 x 1 = 1 of these topological sorts.

So the final answer is 16 - 1 = 15 linear extensions of the poset P.

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The two equivalent expressions are the second one and the last:

(56x + 24)/8 and 3 + 7x

We want to find an equivalent expression to 56x + 24 divided by 8, so we want to simplify the expression:

(56x + 24)/8   (that is the second expression)

We can distribute that division so we get:

(56x + 24)/8 = (56x)/8 + 24/8

Now we can simplify these two quotients so we get:

(56x)/8 + 24/8 = 7x + 3  (that is the last expression).

Then the two equivalent expressions are:

(56x + 24)/8 and 3 + 7x

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Answer:

Step-by-step explanation:

To calculate your new income after an increase of 8.2%, you can use the following formula:

New income = Old income + (Percentage increase * Old income)

Plugging in the values given in the problem, we get:

New income = 420,600,000 + (8.2% * 420,600,000)

New income = 420,600,000 + (0.082 * 420,600,000)

New income = 420,600,000 + 34,524,120

New income = 455,124,120

Therefore, your new income after an increase of 8.2% would be 455,124,120.

Answer:

The height of the kite from the ground nearest to the tenth will be 443.6 feet.

Step-by-step explanation:

The vectors [[4],[0],[0]],[[9],[3],[-6]],[[6],[6],[-18]] are linearly independent.

To determine if the vectors are linearly independent, we can use the determinant of the matrix formed by the vectors. If the determinant is not equal to 0, then the vectors are linearly independent.

The matrix formed by the vectors is:
\begin{bmatrix}
4 & 9 & 6\\
0 & 3 & 6\\
0 & -6 & -18
\end{bmatrix}

The determinant of this matrix is:
\begin{vmatrix}
4 & 9 & 6\\
0 & 3 & 6\\
0 & -6 & -18
\end{vmatrix} = 4\begin{vmatrix}
3 & 6\\
-6 & -18
\end{vmatrix} - 9\begin{vmatrix}
0 & 6\\
0 & -18
\end{vmatrix} + 6\begin{vmatrix}
0 & 3\\
0 & -6
\end{vmatrix} = 4(-54-(-36)) - 9(0-0) + 6(0-0) = 4(-18) = -72

Since the determinant is not equal to 0, the vectors are linearly independent. Therefore, the vectors [[4],[0],[0]],[[9],[3],[-6]],[[6],[6],[-18]] are linearly independent.

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Answer:

Step-by-step explanation:

SHORT ANSWER: perimeter = 4 * (6x+8) = 24x + 32

So, depending on which expression represents the length of the side of the square, the perimeter would be either 40x or 24x + 32.

LONG ANSWER WITH STEP-BY STEP:

If one side of the square has a length of 10x, then all sides have a length of 10x. Alternatively, if one side has a length of 6x+8, then all sides have a length of 6x+8. Therefore, we can write:

perimeter = 4 * side length

Substituting in the given expressions for the side length, we get:

perimeter = 4 * (10x) = 40x

or

perimeter = 4 * (6x+8) = 24x + 32

So, depending on which expression represents the length of the side of the square, the perimeter would be either 40x or 24x + 32.

The division of polynomials "(4x^(3)-5x^(2)+8x-8)/(x^(2)-3x)" gives the expression "4x+7+(29x-8)/(x^(2)-3x)".

To perform the indicated division, we will use polynomial long division.

First, we will divide the first term of the dividend, 4x^3, by the first term of the divisor, x^2, to get 4x. This will be the first term of our quotient.

Next, we will multiply 4x by the divisor, x^2-3x, to get 4x^3-12x^2. We will then subtract this from the dividend to get 7x^2+8x-8.

We will then repeat this process by dividing the first term of the new dividend, 7x^2, by the first term of the divisor, x^2, to get 7. This will be the second term of our quotient.

We will then multiply 7 by the divisor, x^2-3x, to get 7x^2-21x. We will subtract this from the new dividend to get 29x-8.

Since the degree of the new dividend, 29x-8, is lower than the degree of the divisor, x^2-3x, we are done with the division and 29x-8 will be our remainder.

Therefore, the final answer is:

(4x^(3)-5x^(2)+8x-8)/(x^(2)-3x) = 4x+7+(29x-8)/(x^(2)-3x)

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Option C. (x+2)/(x-3)*(4)/(x+2) is the equivalent rational expression to (4)/(x-3).

The rational expression that is equivalent to this expression (4)/(x-3) is option C. (x+2)/(x-3)*(4)/(x+2).
We can simplify the rational expression (x+2)/(x-3)*(4)/(x+2) by canceling out the common factor (x+2) from the numerator and denominator. This will give us the equivalent rational expression:

(x+2)/(x-3)*(4)/(x+2) = (4)/(x-3)

Therefore, option C. (x+2)/(x-3)*(4)/(x+2) is the equivalent rational expression to (4)/(x-3).

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Using the %1RM to number of repetitions table, your client's estimated 1RM for the barbell back squat exercise would be 125 lbs, rounded to the nearest whole number.

To estimate the predicted 1RM (one repetition maximum) for the barbell back squat exercise, we can use the %1RM to number of repetitions table from the lecture. According to the table, performing 5 repetitions corresponds to 87% of the 1RM.

To find the estimated 1RM, we can use the following formula:

1RM = weight lifted / %1RM

Plugging in the values from the question:

1RM = 109lb / 0.87

1RM = 125.287lb

Rounding to the nearest whole number, the estimated 1RM for the barbell back squat exercise is 125lb.

Therefore, the answer is 125.

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In the parallel line measure of angle [tex]m\angle 7[/tex] is 32°.

In a plane, two lines are said to be parallel if they never cross at any point. A pair of lines that never cross paths and do not have a common junction point are said to be parallel. Parallel lines are represented by the symbol "||".

Here we know that If two lines which are parallel are intersected by a transversal then the pair of corresponding angles are equal.

Then,

=> [tex]m\angle3= m\angle10[/tex]

Here the given [tex]m\angle3=58\textdegree[/tex] the [tex]m\angle10=58\textdegree[/tex].

Now we know that sum of all angles in straight line is 180°.Then,

=> [tex]m\angle6+m\angle7+m\angle10=180\textdegree[/tex]

=> [tex]90\textdegree+m\angle7+58\textdegree=180\textdegree[/tex]

=> [tex]m\angle7=180\textdegree-90\textdegree-58\textdegree=32\textdegree[/tex]

Hence the measure of [tex]m\angle 7[/tex] is 32°.

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The number of broken eggs will give you an idea of how well the new package design protects the eggs from impacts. If there are no broken eggs, the package design may be effective. However, if there are several broken eggs, the package design may need to be improved to provide better protection.

When testing a new package design, it is important to simulate real-world conditions as much as possible. In this case, dropping a carton of a dozen eggs from a height of 1 foot is a good way to simulate the types of impacts that the package may experience during shipping and handling.

To conduct the test, you will need to follow these steps:

The number of broken eggs will give you an idea of how well the new package design protects the eggs from impacts. If there are no broken eggs, the package design may be effective.

However, if there are several broken eggs, the package design may need to be improved to provide better protection.

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The running time of QuickSort in this case is O(n log(n)), which is the same as the running time when QuickSort splits the list exactly in half.

When QuickSort splits the list into one sublist of size an and another sublist of size (1-a)n, the recurrence relation for the running time of QuickSort becomes T(n) = T(an) + T((1-a)n) + O(n). This is because the two sublists have different sizes and therefore take different amounts of time to sort.

To solve this recurrence relation, we can use the recursion tree method. The recursion tree for this recurrence relation looks like this:

```
       T(n)
      /     \
  T(an)    T((1-a)n)
 /   \      /     \
T(a^2n) T(a(1-a)n) T(a(1-a)n) T((1-a)^2n)
...
```

At each level of the recursion tree, the size of the subproblems decreases by a factor of a or (1-a), and the number of subproblems doubles. The work done at each level is O(n), since the partitioning step takes O(n) time.

The recursion tree has log_{1/a}(n) levels, since the size of the subproblems decreases by a factor of a at each level. Therefore, the total work done by QuickSort is O(n log_{1/a}(n)) = O(n log(n)), since log_{1/a}(n) = log(n)/log(1/a) = log(n)/(-log(a)) = -log(n)/log(a) = O(log(n)).

So the running time of QuickSort in this case is O(n log(n)), which is the same as the running time when QuickSort splits the list exactly in half.

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To solve for v in the equation 3(v-4)-6=-7(-4v+4)-7v, we need to simplify the equation and isolate the variable v on one side of the equation. Here are the steps:

Step 1: Distribute the 3 and -7 on the left and right sides of the equation respectively:

3v - 12 - 6 = 28v - 28 - 7v

Step 2: Combine like terms on both sides of the equation: 3v - 18 = 21v - 28

Step 3: Move the variable terms to one side of the equation and the constant terms to the other side: 3v - 21v = -28 + 18

Step 4: Simplify both sides of the equation:

-18v = -10

Step 5: Divide both sides of the equation by -18 to solve for v: v = -10/-18

Step 6: Simplify the fraction: v = 5/9

Therefore, the solution for v is 5/9.

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The probability that a student surveyed was either a boy or had a bicycle is 0.62.

What is probability?

The mathematical concept of probability is used to estimate an event's likelihood. It merely allows us to calculate the probability that an event will occur. On a scale of 0 to 1, where 0 corresponds to impossibility and 1 to a particular occurrence.

We are given that of 1000 students surveyed, 490 were boys and 320 had bicycles. Of those who had bicycles, 130 were girls.

So, Total number of boys = 490

Total number of girls with bicycle = 130

Total number of students that was either a boy or had a bicycle is

490 + 130 = 620

The probability is

620 / 1000 = 0.62

Hence, the probability that a student surveyed was either a boy or had a bicycle is 0.62.

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when x=24, y = y(3)/(2).

Given that y is directly proportional to the cube root of (x+3), we can write this relationship as:

y = k * cube root (x+3)

Where k is the constant of proportionality. We can use the given values of x and y to find k:

y(2)/(3 ) = k * cube root (5+3)

y(2)/(3 ) = k * cube root (8)

y(2)/(3 ) = k * 2

k = y(2)/(3 ) / 2

Now we can use this value of k to find y when x=24:

y = k * cube root (24+3)

y = (y(2)/(3 ) / 2) * cube root (27)

y = (y(2)/(3 ) / 2) * 3

y = y(2)/(3 ) * (3/2)

y = y(3)/(2)

Therefore, when x=24, y = y(3)/(2).

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As a consequence, the bolded arc is approximately 8.24 centimetres long when the bolder arc is 4cm long.

The vertex of the angle is the common endpoint shared by two rays or line segments that make up an angle in geometry. The sides or limbs of the angle are the rays or line segments that make up the angle. Angles are used to describe the amount of spin or turn between two lines or objects. They are usually measured in degrees or radians. Numerous areas of mathematics, such as geometry, trigonometry, and calculus, depend on angles.

given

We must apply the following algorithm to determine the size of the bolded arc:

arc length is equal to (angle / 360) times 2r.

where r is the radius, angle is the central angle in degrees, and is a mathematical constant roughly equivalent to 3.14.

Inputting the numbers provided yields:

(118/360) * 2 = arc length (4)

8.24 cm arc length is equal to (0.3278) × (25.12) arc length.

As a consequence, the bolded arc is approximately 8.24 centimetres long when the bolder arc is 4cm long.

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The value of a12 is 45.

The given matrix A = [aij] is a 2x3 matrix, which means it has 2 rows and 3 columns. The given condition is aij = 5(-i + 2j)^2. We need to find the value of a12, which means the element in the first row and second column.

To find the value of a12, we need to substitute i = 1 and j = 2 in the given condition.

a12 = 5(-1 + 2*2)^2
= 5(3)^2
= 5*9
= 45

Therefore, the value of a12 is 45.

So, the correct option is:

Select one:
a. 53
b. 59
c. 45
d. 56

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The set W of points described in Exercises 22-26 can be written as a subset of R2 as follows: 22. The points on the line x – 2y = 1: W = {(x, y) | x - 2y = 1}, 23. The points on the x-axis: W = {(x, y) | y = 0}, 24. The points in the upper half-plane: W = {(x, y) | y > 0}, 25. The points on the line y = 2: W = {(x, y) | y = 2} and 26. The points on the parabola y = x2: W = {(x, y) | y = x2}

In other words, the set W contains all points (x, y) that satisfy the equations given in Exercises 22-26. As such, it is a subset of the two-dimensional Euclidean space R2. In Exercises 22–26, give a set-theoretic description of the given points as a subset W of R² is a problem where we need to find a set-theoretic description of the given points in each exercise.

Therefore, we can write the set W asW = { (x, y) ∈ R² | y ≥ 0 } The points on the line y = 2The equation of the line is y = 2Therefore, we can write the set W asW = { (x, y) ∈ R² | y = 2 }  The points on the parabola y = x²The equation of the parabola is y = x²Therefore, we can describe the set W asW = { (x, y) ∈ R² | y = x² }

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Answer: 30

Step-by-step explanation:

Use Pythagorean's Theorem, a² + b² = c²

18² + 24² = c²

324 + 576 = c²

900 = c²

√900 = c

c = 30

The missing side is 30.

Hope this helps!