I need help ASAP!!

The length of a rectangle is 4 meters longer than its width.
The area of the rectangle is
117m^2.

What is the width of the rectangle?

HINT: you can use DESMOS for this kind of problem.

In order to decrease the margin of error, the best option in this instance is by decreasing the confidence level would make the interval to be narrower.

The correct option is D.

The margin of error, also known as the confidence interval, provides information on how closely your survey results will likely reflect the opinions of the general community.

The margin of error is a measure of the potential uncertainty in your survey results. It is more likely that the results will deviate from the "true figures" for the entire population the wider the margin of error.

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The angle subtended by the arc AB in the circle is 68.75 degrees.

We have,

We know that the circumference of a circle is given by 2πr,

where r is the radius of the circle.

The circumference of the circle with a radius of 6 cm is.

C = 2πr = 2π(6) = 12π cm

Since the arc AB of the circle is 9 cm, we can find the angle subtended by this arc using the formula:

angle = (arc length / circumference) x 360°

Plugging in the values we have:

angle = (9 / 12π) x 360°

angle = 68.75°

Therefore,

The angle subtended by the arc AB is 68.75 degrees.

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Answer:

f(x) = 0 at x = -2, 1, 3

A, B, and D are the correct choices.

The contrapositive statement is option D

If the hypothesis and conclusion of an earlier conditional statement are reversed, a contrapositive statement is produced.

Technically speaking, the contrapositive of a conditional statement that starts with "If p, then q" is "If not q, then not p." The initial assertion and its contrapositive, then, are both true because they are logically equivalent.

Thus the contrapositive statement as shown is the statement ~q ~p

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The expression a + b cannot be added/evaluated because 2.00x and 1.50y are not like terms

From the question, we have the following parameters that can be used in our computation:

a + b is equal to what ​

The above statement is an addition expression that adds the values of a and b

However, the terms of the expression are not like terms

i.e. a and b are not like terms

This means that the expression cannot be added/evaluated

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The solution of "quadratic-equation" , 3x² - 6x + 2 = 0 is (b) x = (3 ± √3)/3.

A "Quadratic-Equation" is defined as a second-degree polynomial equation of the form : ax² + bx + c = 0,

where x = variable, and "a", "b", and "c" are constants, with a ≠ 0.

We use the "quadratic-formula" to solve : which is ⇒ x = (-b ± √(b²-4ac))/(2a),

In the quadratic equation "3x² - 6x + 2 = 0", We get , a = 3, b = -6, and c = 2.

Substituting the values,

we get,

⇒ x = (-(-6) ± √((-6)²-4(3)(2)))/(2×3),

⇒ x = (6 ± √(36-24))/6,

⇒ x = (6 ± √12)/6,

⇒ x = (6 ± 2√3)/6,

⇒ x = (3 ± √3)/3,

So the two roots of the quadratic equation 3x² - 6x + 2 = 0 are : x = (3 + √3)/3 and x = (3 - √3)/3.

Therefore, the correct option is (b).

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The given question is incomplete, the complete question is

Find the solution of the given quadratic equation , 3x² - 6x + 2 = 0.

(a) x = 3 ± 23√3

(b) x = (3 ± √3)/3

(c) x = 6 ± 43√3

(d) x = 6 ± 23

Answer:

A and D are correct. This is a parallelogram, which is a quadrilateral. B is not correct because not all the sides are congruent. C is not correct. E and F are not correct because this parallelogram does not have any right angles.

The system of inequalities that represents the graph is

y ≥ x² - 2x + 4 and y < -x² + 4 is the

Option B is the correct answer.

We have,

The inequality y ≥ x² - 2x + 4 represents a parabola that opens upwards and has a vertex at (1,3) as shown below:

The inequality y < -x² + 4 represents an inverted parabola that opens downwards and has a vertex at (0,4) as shown below:

Therefore,

The system of inequalities that represents the graph is

y ≥ x² - 2x + 4 and y < -x² + 4 is the

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We can write the pull force of the magnet as [tex]2 \frac{1}{5} pounds[/tex].

A mixed number refers to number that contains both an integer (whole number) and a proper fraction (a fraction whose numerator is less than its denominator).

To represent the pull force as a mixed number, we must to convert the decimal 0.2 to a fraction. Since 0.2 is equal to 1/5, we can write it as 2 and 1/5 pounds/ Therefore, the mixed number representation of the magnet's pull force of 2.2 pounds is 2 1/5 pounds.

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Hello!

To find the equation of the line that passes through the points (0,-8) and (4,-3), we can use the slope-intercept form of the equation:

y = mx + b

where m is the slope of the line and b is the y-intercept.

First, find the slope (m) of the line using the formula:

m = (y2 - y1)/(x2 - x1)

where (x1, y1) = (0,-8) and (x2, y2) = (4,-3).

m = (-3 - (-8))/(4 - 0) = 5/4

Now that we have the slope (m), we can use the point-slope form of the equation to find the equation of the line:

y - y1 = m(x - x1)

where (x1, y1) = (0,-8) and m = 5/4.

y - (-8) = (5/4)(x - 0)

Simplify the equation to get the slope-intercept form:

y + 8 = (5/4)x

y = (5/4)x - 8

Therefore, the equation of the line that passes through the points (0,-8) and (4,-3) is y = (5/4)x - 8.

The Volume of the box is 12 cubic unit.

We have,

Height = 1 unit

Width = 2 unit

Length = 6 unit

So, Volume of box

= l w h

= 1 x 2 x 6

= 12 cubic unit

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In the rhombus PQRS, if angle ∠ SPQ = 120° then ∠SPO is 30°

∠POS is 90° and ∠PSO is 60 degrees, ∠PO is 90° and ∠SO  is 150°

PQRS is a rhombus.

∠ SPQ = 120° and SP = 8.

We have to find angles,∠SPO = (180° - ∠SPQ) / 2

= (180° - 120°) / 2

= 30°

∠POS = 90°

Now we have to find angle PSO

∠PSO+∠SPO+∠POS =180

30+90+∠PSO=180

120+∠PSO=180

∠PSO=180-120

∠PSO=60 degrees

∠PO = 360° / 4 = 90°

∠SO = 180° - ∠POS = 180° - 30°

= 150°

The area we find by using formula diagonal 1 × diagonal 2/2

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Answer:

Step-by-step explanation:

Answer:

[tex]\Huge \boxed{\bf{x = 33}}[/tex]

Step-by-step explanation:

To solve for x in the equation [tex]3x - 3 = 4(x - 9)[/tex], we will follow these steps:

1. Distribute the 4 on the right-hand side of the equation:

2. To isolate x, subtract 3x from both sides:

3. Lastly, add 36 to both sides of the equation to solve for x:

So, the solution to the equation [tex]3x - 3 = 4(x-9)[/tex] is [tex]x = 33[/tex].

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________________________________________________________

The tank holds approximately 994,040 liters.

The volume of a right circular cylinder is given by the formula:

V = πr^2h

Where

The cylinder's diameter is specified as 13 m, hence the radius may be computed using the formula: r = d/2 = 13/2 = 6.5 m

The cylinder is described as having a 6 m length.

These values are substituted into the volume calculation to produce the following result:

V = π(6.5)^2(6)

V ≈ 994.04 cubic meters

Since 1 cubic meter equals 1000 liters, we can convert the volume to liters by multiplying by 1000.

V = 994.04 cubic meters x 1000 liters/cubic meter

V = 994,040 liters

Therefore, the tank holds approximately 994,040 liters.

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Answer:

A.

Step-by-step explanation:

Peter should choose to base his report card percentage on the median if he wants to have the highest percentage possible. To calculate the median, Peter would first order the scores from lowest to highest: 44%, 64%, 71%, 75%, 84%, 90%, 98%. Then, he would select the middle score as the median, which is 75%. If Peter drops his lowest score (44%), his percentage based on the median would be 80% ((64%+71%+75%+84%+90%+98%)/6). If he were to choose the mean, his percentage would also be 80%. However, since the median is not affected by extreme values like the 44% score, it is a more reliable measure of central tendency in this case.

I did this on homework b4 and got It right so this Is 100 percent right.

Answer:

Peter should choose the median after dropping one test score so he can have the highest percentage possible.

If we calculate the mean of all seven test scores, we get:

(84+71+64+90+75+44+98)/7 = 73.14%

If we calculate the median of all seven test scores, we get:

Arrange the scores in ascending order:

44, 64, 71, 75, 84, 90, 98

The median is 75.

If we drop the lowest score (44) and calculate the mean of the remaining six test scores, we get:

(84+71+64+90+75+98)/6 = 80.5%

If we drop the lowest score (44) and calculate the median of the remaining six test scores, we get:

Arrange the scores in ascending order:

64, 71, 75, 84, 90, 98

The median is 79.5%.

Therefore, Peter should choose the median after dropping one test score to have the highest possible percentage.

Answer:

The answer to your problem is, A. 5/2 and 25/4 

Step-by-step explanation:

In the problem the two similar figures, with side lengths 30 yds and 12 yds.

In order to solve the problem we need to find the ratio of the perimeters and the ratio of the areas of the larger figure to the smaller figure.

Using this information we know the the ratio of the perimeter of similar figure is equal to the scale factor and the ratio of the areas equal to the square of the scale factor.

the scale factor = 30/12 = 5/2

the ratio of the perimeter = 5/2

the ratio of the areas = (5/2)² = 25/4

Thus the answer to your problem is, A. 5/2 and 25/4 

Answer: 4.375 Cups and 35 Ounces.

Step-by-step explanation:

The amount of fluid ounces in 1 cup is 8, meanwhile the amount of fluid ounces in an ounce is 1.

Hope that helps

The blanks will be -

(a) Capital Gain = $4000

(b) Percent of Capital Gain = 14.8%

(c) Purchase price per share = $5

(d) Percent of capital gain = 140%

(e) The selling price per share = $35.65

(f) Capital Gain = $3022.5

(g) Purchase price per share = $29

(h) Percent of capital loss = 20.7%

(i) Purchase price per share $54 and selling price per share $62.

The number of shares is 500.

So, Capital Gain = (500*62 - 500*54) = $4000

Percent of Capital Gain = (4000/(500*54))*100% = 14.8% (rounding to nearest tenth)

(ii) Number of shares = 100 and selling price of per share = $12 and capital gross = $700.

Purchase price per share = (12*100 - 700)/100 = 500/100 = $5

So the percent of capital gain = (700/(5*100))*100% = 140%

(iii) Number of shares = 650 and purchasing price per share = $31 and percent of capital gain = 15%

The selling price per share = 31*(100+15)/100 = $35.65

Capital Gain = (31*650)*15% = $3022.5

(iv) Number of shares = 1300 and selling price of per share = $23 and capital loss = - $7800

Purchasing price per share = $ (23*1300+7800)/1300 = $29

Percent of capital loss = (7800/(29*1300))*100% = 20.7% (rounding to nearest tenth)

Hence, (a) $4000; (b) 14.8% (gain); (c) $5; (d) 140% (gain); (e) $35.65; (f) $3022.5; (g) $29; (h) 20.7% (loss).

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$138.38  you pay per month if you choose to not pay in full

If you pay in full, you get a 10% discount on the six-month policy, which means you would pay:

1,025 - 0.1(1,025) = 922.50

If you choose to not pay in full, you would not get the 10% discount for paying in full.

We get the 10% discount for being a good driver, which would be applied to each monthly payment.

This means that each monthly payment would be:

(1 - 0.1)(922.50) / 6 = 138.38

we get a monthly payment of $138.38.

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The minimum value of the objective function is 47, which occurs at the point (3,2), and the maximum value is 117, which occurs at the point (0,9).

To solve this linear programming problem, we need to first graph the feasible region defined by the given constraints:

The first constraint, x ≥ 0, represents the non-negative values of x along the x-axis.

The second constraint, 4x + 8y ≥ 32, can be rewritten as y ≥ -(1/2)x + 4, which is a line with a y-intercept of 4 and a slope of -(1/2). The feasible region is above this line.

The third constraint, 10x - y ≤ 30, can be rewritten as y ≥ 10x - 30, which is a line with a y-intercept of -30 and a slope of 10. The feasible region is above this line as well.

The fourth constraint, x + 6y ≤ 54, can be rewritten as y ≤ -(1/6)x + 9, which is a line with a y-intercept of 9 and a slope of -(1/6). The feasible region is below this line.

The feasible region is therefore the polygon bounded by the lines y = -(1/2)x + 4, y = 10x - 30, y = -(1/6)x + 9, and x = 0. To find the minimum and maximum values of the objective function f(x,y) = 11x + 13y, we need to evaluate this function at each corner of the feasible region and compare the results.

The corners of the feasible region are (0,4), (3,2), (5,4), and (0,9). Evaluating the objective function at these corners, we get:

f(0,4) = 52

f(3,2) = 47

f(5,4) = 89

f(0,9) = 117

Therefore, the minimum value of the objective function is 47, which occurs at the point (3,2), and the maximum value is 117, which occurs at the point (0,9).

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The triangles are not congruent.

Given that, two triangles, EFG and HIJ are similar,

So,

Since, the triangles are similar, but according to the definition of similarity, two objects that are similar are not necessarily congruent,

so the Δ EFG is not congruent to Δ HIJ.

Cos 30° = HI / HJ

√3/2 = 3/HI

HI = 3.5

Therefore, the scale factor Δ EFG to Δ HIJ = EF / HI = 10/3.5 = 2/0.7

The ratio of perimeter of similar objects are same as the scale factor,

so, the ratio of their perimeters = 2/0.7

The ratio of the areas of the similar objects are the ratios of the squares of the scale factor.

So, the ratio of their areas = 4/0.49

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Answer:

Step-by-step explanation:

You want to identify the given shapes as a regular or irregular polygon, or neither.

A regular polygon is one that has all sides congruent, and all interior angles congruent. Polygon E is marked as having congruent sides and congruent angles.

Polygon E is a regular polygon.

A polygon is a closed figure formed by line segments connected end-to-end. A simple polygon is one that has no intersecting line segments. A convex polygon is one that has all interior angles measuring 180° or less.

Any simple polygon that is not a regular polygon is an irregular polygon.

Polygons A, B, D are irregular polygons.

A circle is not a polygon. Figure C is neither a regular polygon nor an irregular polygon.

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The vertices after transformation are N′(1, 2), M′(−2, 1), O′(−1, 3).

We have,

N(−5, 2), M(−2, 1), O(−3 , 3).

We know the rule to reflect over a vertical line x =a is

(x, y) --> (-x-2a, y)

So, for x=2 the rule will be

(x, y) --> (-x-4, y)

Now, the vertices after transformation are

M(-2, 1) -> M'(-2, 1)

N(-5, 2) -> N'(1, 2)

O(-3, 3) -> O'(-1, 3)

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Answer:

To translate triangle ABC 3 units up, we need to add 3 to the y-coordinate of each vertex:

A' = (-3, 3 + 3) = (-3, 6)

B' = (0, 7 + 3) = (0, 10)

C' = (-3, 0 + 3) = (-3, 3)

Therefore, the coordinates of the vertices for the image triangle A'B'C' are A'(-3, 6), B'(0, 10), and C'(-3, 3).

So the correct answer is: A′(−3, 6), B′(0, 10), C′(−3, 3).

Answer:

the third one: m<a = m<d