Answer:
C
Step-by-step explanation:
7-7 is wrong
A random sample of 10 employees of a company was selected to estimate the mean one-way commute time for all employees at the company. The mean and standard deviation of the sample were 38 minutes and 6 minutes, respectively. Assuming all conditions for inference are met, which of the following is the margin of error, in minutes, for a 95 percent confidence interval for the population mean one-way commute time? 1.812(610√) 1.812 times the fraction with numerator 6, and denominator the square root of 10 A 1.833(610√) 1.833 times the fraction with numerator 6, and denominator the square root of 10 B 1.96(610√) 1.96 times the fraction with numerator 6, and denominator the square root of 10 C 2.228(610√) 2.228 times the fraction with numerator 6, and denominator the square root of 10 D 2.262(610√)
Answer:
The margin of error is of [tex]2.262\frac{6}{\sqrt{10}} = 4.29[/tex]
Step-by-step explanation:
We have the standard deviation for the sample. So the T-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 10 - 1 = 9
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 9 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.95}{2} = 0.975[/tex]. So we have T = 2.262
The margin of error is:
[tex]M = T\frac{s}{\sqrt{n}} = 2.262\frac{6}{\sqrt{10}} = 4.29[/tex]
In which s is the standard deviation of the sample and n is the size of the sample.
The equation that represents the margin of error is: [tex]E = 2.262 \times \frac{6}{\sqrt {10}}[/tex]
The given parameters are:
Sample size = 10Mean = 38Standard deviation = 6Confidence Interval = 95%The margin of error is calculated using:
[tex]E = z_y \times \frac{\sigma}{\sqrt n}[/tex]
So, we have:
[tex]E = z_y \times \frac{6}{\sqrt {10}}[/tex]
The quantile at 95% confidence interval is 2.262
So, the equation becomes
[tex]E = 2.262 \times \frac{6}{\sqrt {10}}[/tex]
Hence, the equation that represents the margin of error is: [tex]E = 2.262 \times \frac{6}{\sqrt {10}}[/tex]
Read more about margin of error at:
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May someone please help me? The question is:
What type of triangle is DAE? Look at the image above.
Answer:
Right angle triangle
Step-by-step explanation:
What is an equation of the line that passes through the points (4, 3) and (-6, 3)?
Answer:
Step-by-step explanation:
(4,3)(-6,3)
3-3/-6-4
m=0
y=3
Answer:
y=3
Step-by-step explanation:
Something that I notice about this is that the 2 y coordinates are the same
This means that the line isn't increasing nor decreasing, it's constant
if we look at the y=mx+b
we have, so far,
y=0x+b
we just need be
we know that when x=4 y=3 so we have
3=(0)(4)+b
b=3
so the answer is just y=3
What is the percent of the shaded portion of the
figure??
60%
80%
20 %
.60%
HELP MEEE PLSSSSSSSS
I need help please and go look at my other answer i need that answer to that fast its 20 points and i will mark as brainlest
The answer is A because when you divide into 175 to find the amount discounted, then you subtract that to 175 and you get 145.25
The firm is requested to send 3 employees who have positive indications of asbestos on to a medical center for further testing. Suppose 40% of the employees have positive indications of asbestos in their lungs. a) Find the probability that exactly 10 employees will be tested in order to find 3 positives
Answer:
0.0645 = 6.45% probability that exactly 10 employees will be tested in order to find 3 positives
Step-by-step explanation:
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
And p is the probability of X happening.
40% of the employees have positive indications of asbestos in their lungs
This means that [tex]p = 0.4[/tex]
a) Find the probability that exactly 10 employees will be tested in order to find 3 positives
2 within the first 9([tex]P(X = 2)[/tex] when [tex]n = 9[/tex]), and the 10th, with 0.4 probability. So
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 2) = C_{9,2}.(0.4)^{2}.(0.6)^{7} = 0.1612[/tex]
0.4*0.1612 = 0.0645
0.0645 = 6.45% probability that exactly 10 employees will be tested in order to find 3 positives
The width of a rectangle is 23 yd. What is the perimeter of the rectangle if the length is 6 yd less than the width?
a. 40 yd
c. 391 yd
b. 104 yd
d. 80 yd
The measure of angle D is 55°, the measure of angle E is 85°, and
the measure of angle F is 10x. What is the value of x?
[tex]x = 4[/tex]
55+85=140
180-140=40
10x=40
divide by ten on each side
x=4
1. write an equvialent expression: -1/2 (-2x + 4y)
2. Factor to write an equivalent expression: 26a - 10.
Answer:
1) x-2y 2) 2(13a-5)
Step-by-step explanation:
1) -1/2(-2x+4y)=2/2x-4/2y=x-2y
2) 26a-10=2(13a-5)
Use the grouping method to factor 2x3 + 6x2 - 7x- 21.
O A. (x - 3)(x + 7)
O B. (x+3)(2x2 - 7)
C. 2x(x + 3)(x - 7)
O D. (x - 3)(2x2 + 7)
Answer:
B. (x+3)(2x2−7)
Step-by-step explanation:
2x3 + 6x2 - 7x- 21
(2x3+6x2)(-7x-21)
2x2(x+3)-7(x+3)
(x+3)(2x2-7)
In a survey of 2,500 people who owned a certain type of car, 750 said they would buy that type of car again. What percent of the people surveyed were satisfied with the car?
Answer:
30%
Step-by-step explanation:
Simply divide your final value (750) by your initial value (2500).
HELPPPP!!! PLEASEEEE I’M FAILING ALGEBRA AND I NEED HELP WITH THIS QUESTION
a/b The decay can be modeled by this equation, (1 - r), the r being the rate of decay. So it would be 1-0.115. (0.115 is your answer for a) You have to convert the percent into a decimal by moving the deicmal place two places to the left. 0.885 is your answer for b.
c. For function notation, that just means write an equation. So you want your decay times your inital. V(t)=15000(0.885)^x. We get the V(t) from the directions that they want us to put it in; it's basically y.
d. Since it's two years, plug in 2 for x. This shows the decay after two years
V(t)=15000(0.885)^2
e. As with d, plug in 10 for x. V(t)=15000(0.885)^t
1/5 = something/10 = something/100 = something percentage %
Answer:
20%
Step-by-step explanation:
The computation is shown below:
Let something be x
[tex]\frac{1}{5} = \frac{x}{10} = \frac{x}{100} = x\%[/tex]
[tex]0.2 = \frac{x}{10} = \frac{x}{100} = x\%[/tex]
So if we see that 0.2 would be equivalent to the [tex]\frac{x}{10}[/tex] and then [tex]\frac{x}{100}[/tex] after than x percentage
Therefore according to this the x percentage is 20%
Hence, the x percentage is 20%
PLEASE ANSWER I NEED HELP PLEASE PLEASEEEE
Graph the number pairs, and then complete the inequality.
3 ____-3
Answer:
3>-3
Step-by-step explanation:
make an open dot on 3 and make a line going towards the left.
The parallelogram shown below has an area of 60 units^2
Answer:
b = 5.5
Step-by-step explanation:
In a paralelogram
A = bh
Just plug in the numbers
they said A = 60
and the number 11 is the height
60 = 11b
Divide
b = 60/11
b = 5.454545454
A two pound bag of
apples costs $5.00. How
much would it cost to
purchase 10 pounds of
apples?
Answer:
$25.00
Step-by-step explanation:
find the perimeter n area pls !
Answer:
6yx
Step-by-step explanation:
solve for X
(4x+7)
(2x+5)
Answer:
x= 28
Step-by-step explanation:
combine the equations and set equal to 180, since a striaght line is 180 degrees. When combined you get, 6x + 12=180. Subtract, 180-12=168, then divide by 6 to get 28
Refer to the Exhibit Teacher's Salary. Find the probability that a randomly selected teacher receives a salary of $45,000 or more. (Do not round your answer)
Answer:
[tex]P(x \ge 45000) = 0.77935[/tex]
Step-by-step explanation:
Given [Missing from the question]
Exhibit Teacher's Salary:
[tex]\bar x=50000[/tex]
[tex]s = 6500[/tex]
Required
Calculate [tex]P(x\ge 45000)[/tex]
First, we calculate the z score
[tex]z = \frac{x - \bar x}{s}[/tex]
[tex]z = \frac{45000 - 50000}{6500}[/tex]
[tex]z = \frac{-5000}{6500}[/tex]
[tex]z = -0.77[/tex]
[tex]P(x \ge 45000) = P(z \ge -0.77)[/tex]
[tex]P(x \ge 45000) = 1 - P(z \le -0.77)[/tex]
From the table:
[tex]P(z \le -0.77) = 0.22065[/tex]
So, we have:
[tex]P(x \ge 45000) = 1 - 0.22065[/tex]
[tex]P(x \ge 45000) = 0.77935[/tex]
Suppose that 30% of the applicants for a certain industrial job possess advanced training in computer programming. Applicants are interviewed sequentially and are selected at random from the pool.
(a) Find the probability that the first applicant with advanced training in programming is found on the fifth interview.
(b) What is the expected number of applicants who need to be interviewed in order to find the first one with advanced training?
(c) Let Y denote the number of the trial on which the first applicant with computer training was found. If each interview costs $30, find the expected value and variance of the total cost incurred interviewing candidates until an applicant with advanced computer training is found.
Answer:
Step-by-step explanation:
From the given information:
Assume X represents the no. interviewed until 1 has advanced training.
X obeys a Geometric distribution with parameter 0.3.
X [tex]\sim[/tex] Geom (0.30)
For geometric distribution, the probability density is:
[tex]P(X =x) = p(1-p) ^{x-1} \ \ \ where; x =1,2,3...[/tex]
TO calculate the required probability;
[tex]P(X =5) =0.30 (1-0.30)^{5-1}[/tex]
[tex]P(X =5) =0.30 (0.70)^{4}[/tex]
[tex]P(X=5) = 0.30 \times 0.2401[/tex]
[tex]\mathbf{P(X=5) = 0.07203}[/tex]
(b)
The expected no. of applicants that need to be interviewed are:
[tex]E(X)=\dfrac{1}{p}[/tex]
[tex]E(X)=\dfrac{1}{0.30}[/tex]
E(X) = 3.33
(c)
The mean and the variance can be computed as:
[tex]E(Y) = \dfrac{1}{p}[/tex]
[tex]E(Y) = \dfrac{1}{0.30}[/tex]
E(Y) = 3.33
[tex]V(Y)=\dfrac{1-p}{p^2}[/tex]
[tex]V(Y)=\dfrac{1-0.3}{0.3^2}[/tex]
[tex]V(Y)=\dfrac{0.7}{0.3^2}[/tex]
[tex]V(Y)=7.778[/tex]
Suppose C represents the no. of the total cost and given that each interview costs $30.
Then C = 30Y
Recall that; C is constant for a random variable X
∴
E(C) = E(30Y)
E(C) = 30E(Y)
E(C) = 30*3.33
E(C) =99.9
E(C) [tex]\simeq[/tex] 100
V(C) = V(30Y)
V(C) = 900 V(Y)
V(C) = 900*7.778
V(C) = 7000.2
V(C) [tex]\simeq[/tex] 7000
Express g(x) = x4 + 2x3 − x2 + 4x + 12 as the product of linear and irreducible quadratic terms.
convert 50 watts to kilowatts
Answer:
0.05 kilowatts
Answer:
0. 05
Step-by-step explanation:
Please help!!!!
I do not know how to resolve this.
Answer:
5/9
Step-by-step explanation:
x is divided by -2 less than 5
Answer:
X/-2>5
Step-by-step explanation:
This is an Inequality
Solve the System of Equations below using Substitution or Elimination
-4x – 4y = 0
4x + 4y = 0
Answer:
(0,0) or Infinitely many solutions.
Step-by-step explanation:
-−4x−4y=0
−4x−4y+4y=0+4y(Add 4y to both sides)
−4x=4y
−4x/-4= 4y/-4
(Divide both sides by -4)
x=−y
4x+4y=0
4(−y)+4y=0
0=0
these are fractions. Help plz will give brainly
Step-by-step explanation:
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1.32 Factory defective rate. A factory quality control manager decides to investigate the percentage of defective items produced each day. Within a given work week (Monday through Friday) the percentage of defective items produced was 2%, 1.4%, 4%, 3%, 2.2%. (a) Calculate the mean for these data. (b) Calculate the standard deviation for these data, showing each step in detail.
Answer:
a) the mean percentage of defective item produced is 2.52 %
b) the standard deviation of percentage of defective item produced is 1.01%
Step-by-step explanation:
Given that;
the percentage of defective items produced was 2%, 1.4%, 4%, 3%, 2.2%.
sample size n = 5
a) Calculate the mean for these data
mean percentage of defective item produced will be;
[tex]x^{bar}[/tex] = ∑x / n
[tex]x^{bar}[/tex] = ∑x / n = ( 2% + 1.4% + 4% + 3% + 2.2% ) / 5
[tex]x^{bar}[/tex] = 12.6 / 5
[tex]x^{bar}[/tex] = 2.52 %
Therefore, the mean percentage of defective item produced is 2.52 %
b) Calculate the standard deviation for these data
Formula for standard deviation is;
S = √( (∑(x-[tex]x^{bar}[/tex] )²) / (n-1) )
so we make a table;
x ( x - [tex]x^{bar}[/tex] )% ( x - [tex]x^{bar}[/tex] )²%
2% -0.52 0.2704
1.4% -1.12 1.2544
4% 1.48 2.1904
3% 0.48 0.2304
2.2%. -0.32 0.1024
summation 4.048
so (∑(x-[tex]x^{bar}[/tex] )² = 4.048%
so we substitute the value into our equation;
S = √( (∑(x-[tex]x^{bar}[/tex] )²) / (n-1) )
S = √( (4.048%) / (5-1) )
S = √( 4.048% / 4 )
S = √( 1.0121
S = 1.00598 % ≈ 1.01%
Therefore, the standard deviation of percentage of defective item produced is 1.01%
a Basketball ticket costs $45 but they are having a promotional game night and all tickets are 25% off what is the new price of the ticket
Answer:
Should be $11.25
Step-by-step explanation:
Since 25% is 1/4 you can just divide 45 by 4.
45/4 = 11.25
Answer: 33.75. 25% of 45 is 11.25. So 45-11.25=33.75
Step-by-step explanation:
answer:
P- 56
P+ 56
p
56- P
Answer:
p-56
Step-by-step explanation:
Since Pablo has 56 less peppermints
you would take Ryan's amount (P) and subtract 56 to get Pablo's amount
2/9 of the students in a school are in sixth grade.
a. How many sixth graders are there if the school has
90 students?
b. How many sixth graders are there if the school has
27 students?
c. if the school has x students write an expression for the number of students of sixth graders in terms of x
d. how many students are in the school of 42 of them are in 6th grade
Answer:
a) 20 sixth graders.
b) 6 sixth graders.
c) 2/9x sixth graders.
d) 189 students in the school.
Step-by-step explanation:
a) 2/9 of 90 = 2/9 * 90 = 20 students.
b) 2/9 of 27 = 2/9 * 27 = 6 students.
c) 2/9 of x = 2/9x
d) 42 = 2/9x so solve the equation: x = 189 students.
If we have 90 students in the school then we will have 20 sixth grade students.
a. From the details of the question, we have 2/9 of the students in the school in sixth grade. Hence;
Number of students in sixth grade = 2/9 × 90 = 20 sixth grade students
b. If the school has 27 students, number of sixth graders = 2/9 × 27 = 6 sixth grade students
c. If we have x students in the school, the number of sixth graders = 2/9 × x = 2/9x students
d. If we have 42 students in sixth grade, the number of students in the school is;
2/9 × x = 42
x = 9/2 × 42 = 189 students
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