i just need help plzzzz

Answer:

tan 249 = 2.61

tan 249 = tan (249 - 180) = tan 69 = 2.61

Answer:

1)The ability to be maintained at a certain rate or amount is called sustainability.

3)Sustainability is measured by assessing performance of Social, Environmental, and Economic principles.

sorry but I don't know number 2.

I hope it will help you)):

Answer:

B. The force of gravity that acts on the kitten

Explanation:

Answer:

0 because she went to exact same place as before

Answer:

Explanation:

Total mechanical energy is

E = mgh + ½mv²

E = m(gh + ½v²)

E = 90(9.8(2.0) + ½4²)

E = 2,484 J answer b)

A person on a bike (m = 90 kg) is traveling 4 m/s at the top of a 2 m hill. the total energy of the biker would be 2484 Joules.

Mechanical energy is the combination of all the energy in motion represented by total kinetic energy and the total potential energy stored energy in the system which is represented by total potential energy.

As given in the problem a person on a bike (m = 90 kg) is traveling 4 m/s at the top of a 2 m hill.

The total kinetic energy of the biker

KE = 1/2 × m × v²

    = 0.5 × 90 × 4²

    = 720

Similarly, the total potential energy of the biker

PE = m × g × h

     =90 × 9.8 × 2

      = 1764 Joules

The total energy of the biker = 720 + 1764

                                                 = 2484 Joules

Thus, the total energy of the biker would be 2484 Joules .

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Answer:

c

Explanation:

Answer: Yes Because it matches with the mass and the amount of force Hope this helps :>

Explanation:

A matter can be separated into three states.

Answer:

Explanation:

The engine should create the same force

1) F = ma

  F = M(½a)

therefore

ma = ½Ma

 m = ½M

 M = 2m

 M = 2(0.8)

 M = 1.6 kg

2) Unbalanced forces

 a. Two people pulling on the same side of a wheelbarrow

 c. Two people of opposite sides of a big tire. One pushes the tire and one pulls it with equal force

3) b. The force of friction on the object is different if it is stationary or not

Weight=Applied force

[tex]\\ \sf\longmapsto F=mg[/tex]

[tex]\\ \sf\longmapsto F=20(10)[/tex]

[tex]\\ \sf\longmapsto F=200N[/tex]

Answer:

Weight=200

Explanation:

Given,

[tex]\sf\longmapsto \: mass = 20 \: kilograms[/tex]

We know that–

[tex]\sf\longmapsto \: acceleration \: \: because \: of \: gravity = 10m/s^2[/tex]

[tex]\sf\longmapsto \: Weight= \: is  \: F = m•g[/tex]

Let's start solving!

Weight = 20×10

Weight=200

Answer: I think it’s craters

Explanation:

Answer:

MOUNTAINS

CRATERS

PLATEAUS

Explanation:

The Moon has many familiar landforms like mountains, plains, and dark patches that look like seas. We now know that these areas are not seas filled with water. They are deep dry plains.

Answer:

a Penicillin is produced by fungal fermentation.

Explanation:

The industrial production of penicillin (PEN) occurs via fermentation using the filamentous fungus Penicillium chrysogenum

Penicillin G (benzylpenicillin) was first produced from a penicillium fungus that occurs in nature. The strain of fungus used today for the manufacture of penicillin G was created by genetic engineering to improve the yield in the manufacturing process.

Answer:

magnets are magnetic :)

Explanation:

Explanation:

[tex]V = IR \Rightarrow R = \dfrac{V}{I}[/tex]

Plugging in the numbers, we get

[tex]R=\dfrac{4.5\:\text{V}}{0.5\:\text{A}} = 9.0[/tex] ohms

Answer:

mercury

arsenic

ricin

ddt

Explanation:

pls mark me as brainliest

Among the materials listed, examples of persistent organic pollutants (POPs) are PCBs (Polychlorinated Biphenyls) DDT (Dichlorodiphenyltrichloroethane). The correct option is (2) and (3).

Persistent Organic Pollutants (POPs) are a class of chemicals that are long-lasting, bioaccumulative, and harmful to humans and wildlife. These pollutants are resistant to degradation and can persist in the environment for long periods of time, resulting in long-distance transport and bioaccumulation in the food chain.

PCBs (Polychlorinated Biphenyls): Once utilized in a variety of industrial applications such as electrical transformers and capacitors, PCBs are now prohibited in many countries due to their toxicity.

DDT (Dichlorodiphenyltrichloroethane): An pesticide that was widely used for agricultural and public health objectives in the past but is now restricted or banned due to its environmental and health effects.

Hence, the correct answer is PCBs and DDT. The correct option is (2) and (3).

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Answer:

yes

Explanation:

Explanation:

E = 9×10^9 × 0.0035 /(0.0075)²

= 9×10^9 × 3.5×10`³/(7.5×10`³)²

= 31.5×10^6 /(56.25 ×10^-6)

= 0.56 × 10^12

= 5.6 × 10^11 N/C (option C)

Answer:

1. it spins

2. falls in a curve

3. falls flat on the floor

Answer:

use a flight sim

Explanation: Solution

1.

Gravitational potential energy

U=mgh=500*9.8*50

U=245000 J

2.

Kinetic energy is present at bottom of the hill

K=(1/2)mV2=(1/2)*500*27.82

K=193210 J

3.

Work done by friction

W=193210-245000=-51790 J

The mechanical energy at the top and bottom of the hill is equal to 352800 J and 163840 J respectively.

Kinetic energy (KE) can be described as the energy possessed by a moving object due to its motion. Work by a body will be done to change the kinetic energy. The kinetic energy is represented as K.E = ½mv².

Potential energy (P.E) can be described as the energy that is stored by an object due to its position and is represented in the equation as P.E = mgh, where ‘m’ is the mass, ‘g’ is the acceleration due to gravity and ‘h’ is the height.

The mechanical energy = Kinetic energy + potential energy

Given, the mass of the car, m = 500 Kg

The height of the hill, h = 72 m

The velocity of the car, v = 25.6 m/s

At the top of the hill, the mechanical energy = potential energy

The potential energy at the top of the hill, = mgh

P. E. = 500 × 9.8 ×72

P.E. = 352800 J

At the bottom of the hill, the mechanical energy = kinetic energy

The kinetic energy of the car at the bottom of the hill,

K.E. =  ½ × 500 (25.6)²

K.E. = 163840 J

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Answer:

The question lacks a photo to fully answer correctly

If the fossil has its neck bent backwards towards its back, that is the common way to which dinosaurs died.

If the fossil is scattered a bit from its other linking fossil pieces, than it is most likely that the dinosaur was a meal to a predator.

Fossils that are in array but are divided clearly at a section suggests that land moved. Possibly earthquake or Pangea took place.

Answer:

Peripatus, which lived around 570 MYA, is in the top layer of rock. The trilobites that lived later, between 498 MYA and 445 MYA, appear in the bottom layer. Based on superposition, younger layers of rock are expected to be on top. The rock layers have been overturned, placing the younger layer on the bottom.

Explanation:

actually answer plauto

Answer:

B. Chemical energy

Explanation:

chemical energy is the energy stored in the bonds between atoms

Answer:

Thermogenesis:Your body's muscles, organs, and brain produce heat in a variety of ways

Explanation:

For example, muscles can produce heat by shivering. Hormonal thermogenesis: Your thyroid gland releases hormones to increase your metabolism. This increases the energy your body creates and the amount of heat it produces

El análisis de un grafico de velocidad versus tiempo permite encontrar los resultados para las preguntas son:

a) La velocidad es v= 0,6 m/s

b) La distancia recorrida  dₐ = 1,5 m

c) La distancia recorrida entre t= 5 y 10 s es  [tex]d_b[/tex] = 3,0 m

d) La aceleración   a = -0,4 m/s²

e) La distancia total recorrida  es [tex]d_{total}[/tex] = 5,3 m

f) La velocidad media es  [tex]v_{media}[/tex] = 0,44 m/s

La cinemática estudia el movimiento de los cuerpos, buscando relaciones entre la posición, la velocidad y la aceleración de los cuerpos.

La velocidad es definida como el cambio de la posición en función del tiempo y la aceleración es el cambio de la velocidad en el intervalo de tiempo.

           .[tex]v= \frac{\Delta x}{t} \\a = \frac{\Delta v}{t}[/tex]

Donde v y a son la velocidad y aceleración, respectivamente, t es el tiempo y Δx y Δv son la variación de la posición y la velocidad, respectivamente.  

En el adjunto muestran un grafico de la velocidad en función del tiempo, donde del área bajo la curva obtenemos la distancia recorrida y la pendiente corresponde a la aceleración del cuerpo.

Respondamos las preguntas:

a)  La velocidad de la bola a los 5 s.

Como es un grafico de velocidad versus tiempo, la velocidad puede ser leída directamente, en el grafico tenemos un valor de

          v= 0,6 m/s  

b) La distancia recorrida corresponde al área bajo la curva.

         [tex]d_a = \frac{v_f - v_o}{2} t \\d_a = \frac{0.6-0}{ 2}\ 5[/tex]  

         d = 1,5 m

c) La distancia en el intervalo de 5 a 10 s.

En este intervalo la velocidad es constante, el área es

        [tex]d_b = v \Delta t\\d_b = 0.6 \ 5\\[/tex]  

        d =  3 m

d) La aceleración en el intervalo  10 a 12 s.

La aceleracion es la pendiente del grafico

        a = [tex]\frac{\Delta v}{\Delta t}[/tex]  

        a = [tex]\frac{-0.2 - 0.6}{12-10}[/tex]

        a = -0,4 m/s²

El signo negativo indica que la aceleración se opone a la velocidad del cuerpo.

e) La distancia total recorrida  

       [tex]d_{total} = d_a + d_b + d_c[/tex]

      dₐ = 1,5 m

      [tex]d_b[/tex] = 3,0 m

Busquemos la distancia en el ultimo intervalo

         [tex]d_c = \frac{0.6 + 0.2}{2} ( 12-10)[/tex]

       [tex]d_c[/tex] = 0,8 m

Substituimos

     [tex]d_{total}[/tex] = 1,5 + 3,0 + 0,8

     [tex]d_{total}[/tex]  =  5,3 m

f) La rapidez  de la bola

La rapidez prmedio es la relación entre la distancia recorrida en el tiempo.

         [tex]v_{avg} = \frac{\Delta x}{\Delta t }[/tex]  

         [tex]v_{avg} = \frac{5.3}{12}[/tex]

         [tex]v_{avg}[/tex]  =0,44 m/s

En conclusión usando el análisis de un grafico de velocidad versus tiempo podemos encontrar los resultados para las preguntas son:

         a) La velocidad es v= 0,6 m/s

         b) La distancia recorrida  da = 1,5 m

         c) La distancia recorrida entre t= 5 y 10 s es  db = 3,0 m

         d) La aceleración   a = -0,4 m/s²

         e)  La distancia total recorrida  es [tex]d_{total}[/tex] = 5,3 m

          f) La velocidad media es  [tex]v_{avg}[/tex] = 0,44 m/s

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