I got this information for a lab but I don't know how to do the hypothesis and the conclusion please can you guys help me with it quickly ​

Answer:

A

Explanation:

Answer:

when gravitational force suddenly disappears, then only centrifugal force will be acting and velocity is tangential to the orbit and hence, the satellite will fly off tangentially with same velocity v.

Answer:

25.88 N

Explanation:

Mass of the shopping cart,[tex]m=65 kg[/tex]

The coefficient of friction between the cart and the floor, [tex]\mu= 0.01[/tex]

Let, F be the required force to accelerate the cart at [tex]a=0.30 m/s^2[/tex].

Gravitational force, mg, acts downward which is being balanced by the normal reaction, N, on the cart by the floor.

As the motion of the cart in the vertical direction is zero. So, using the static equilibrium condition will be zero.

From free body diagram (FBD):

[tex]N-mg=0[/tex]

[tex]\Rightarrow N=mg.[/tex]

the net force action in this direction The frictional force, f, acts in the direction to opposes the motion of the cart as shown.

[tex]f=\muN=\mu mg[/tex]

Now, apply the dynamic equilibrium condition in the horizontal direction, i.e. net force acting on the body equals the rate of change of momentum of the body. From the FBD of the cart, we have

[tex]F-f-ma=0[/tex]

[tex]\Rightarrow F=f+ma[/tex]

[tex]\Rightarrow F=\mu mg+ma[/tex]

[tex]\Rightarrow F=m(\mu g +a)[/tex]

[tex]\Rightarrow F=65(0.01\times 9.81 + 0.3)[/tex]

[tex]\Rightarrow F=25.88 N.[/tex]

Hence, 25.88 N force required to accelerate the body with 0.03 [tex]m/s^2[/tex] .

Answer:

a)    V = - x ( σ / 2ε₀)

c)  parallel to the flat sheet of paper

Explanation:

a) For this exercise we use the relationship between the electric field and the electric potential

          V = - ∫ E . dx        (1)

for which we need the electric field of the sheet of paper, for this we use Gauss's law. Let us use as a Gaussian surface a cylinder with faces parallel to the sheet

       Ф = ∫ E . dA = [tex]q_{int}[/tex] /ε₀

the electric field lines are perpendicular to the sheet, therefore they are parallel to the normal of the area, which reduces the scalar product to the algebraic product

          E A = q_{int} /ε₀

area let's use the concept of density

        σ = q_{int}/ A

       q_{int} = σ A

          E = σ /ε₀

as the leaf emits bonnet towards both sides, for only one side the field must be

          E = σ / 2ε₀

         we substitute in equation 1 and integrate

      V = - σ x / 2ε₀  

       V = - x ( σ / 2ε₀)

if the area of ​​the sheeta is 100 cm² = 10⁻² m²

      V = - x  (10⁻²/(2 8.85 10⁻¹²) = - x  ( 5.6 10⁻¹⁰)

      x = 1 cm     V = -1   V

      x = 2cm     V = -2   V

This value is relative to the loaded sheet if we combine our reference system the values ​​are inverted

       V ’= V (inf) - V

       x = 1 V = 5

       x = 2 V = 4

       x = 3 V = 3

These surfaces are perpendicular to the electric field lines, so they are parallel to the sheet.

In the attachment we can see a schematic representation of the equipotential surfaces

b) From the equation we can see that the equipotential surfaces are parallel to the sheet and equally spaced

c) parallel to the flat sheet of paper

Answer:

Explanation:

To find the work done by an object given the distance covered by the object and it's force we use the formula

From the question

force = 5 N

distance = 2 m

We have

work done = 5 × 2

We have the final answer as

Hope this helps you

630 kilometers for the whole journey

Answer:

1 = 5.4 J

2 = 0.1979 C

3 = 5

Explanation:

Energy in a capacitor, E is

E = 1/2 * C * V²

E = 1/2 * 3000*10^-6 * 60²

E = 1/2 * 3000*10^-6 * 3600

E = 1/2 * 10.8

E = 5.4 J

E = Q²/2C = 6.53 J

E * 2C = Q²

Q² = 6.53 * 2 * 3000*10^-6

Q² = 13.06 * 3000*10^-6

Q² = 0.03918

Q = √0.03918

Q = 0.1979 C

The Capacitor, C is inversely proportional to the distance of separation, D. Thus, if D is increased by 5 to be 5D, then C would be C/5. And therefore, our energy stored in the capacitor is increased by a factor of 5.

Answer

No dan should reduce his discretionary apendings.

Explanation:

Explanation:

At a height of 93 m, the gravitational potential energy is given by :

P = mgh

Where, m is the mass of a penny

We can find its mass.

[tex]m=\dfrac{P}{gh}\\\\m=\dfrac{3}{9.8\times 93}\\\\m=0.00329\ kg[/tex]

We need to find how much potential energy will have transformed into kinetic energy at the half way point (46.5m). It can be calculated as :

[tex]E=mgh'\\\\E=0.00329\times 9.8\times 46.5\\\\E=1.499\ J[/tex]

Hence, a penny will have transferred 1.499 J of potential energy into kinetic energy.

Answer:

50 mph east

Explanation:

Answer:

Pls ezplain your question more

Explanation:

Answer:

orbit is the answer

Answer: Planets A and B have a rocky mantle and an iron core. They are at a distance of 1 AU or less from the Sun. This means they are relatively close to the Sun. There are the properties of inner (terrestrial) planets. So planet A and B are inner planets.

Explanation:

Planet C is composed if the gases hydrogen and helium. It has a high mass and is much farther from 1 AU from the sun. These properties are consistent with the outer planets. So, planet C is an outer (gas giant) planet.

Answer:

Planets A and B have a rocky mantle and an iron core. They are at a distance of 1 AU or less from the Sun. This means they are relatively close to the Sun. There are the properties of inner (terrestrial) planets. So planet A and B are inner planets.

Explanation:

Answer:

Usbe

Explanation:

Answer:

65 miles per hour.

Explanation:

Answer:

Average speed of entire trip is : 3.67 m/s

Explanation:

Speed is calculated as the distance covered divided by time

Average speed will be the :speed before stop add to speed after stopping then divide by 2

Speed before stop = 200/ 60 = 3.33 m/s

Speed after stop = 400/100= 4m/s

Average speed = (3.33+4)/2 = 7.33/2 = 3.67 m/s

Answer:

28 m/s

Explanation:

v(final)^2=v(initial)^2+2a(delta y)

=sqrt(2*-9.8 m/s^2*-40)

28 m/s

The speed of the camera with which it hits the water is 27.93 meters per second.

The speed of an object is the rate of change of position of an object in any of the directions. Speed can be measured as the ratio of distance covered by the object to the total time taken in which the distance was covered by the object. Speed is a scalar quantity because it has only magnitude and no direction.

v = gt

where, v is the velocity,

g is the acceleration due to gravity,

and t is the time taken by the object

v = (9.8 m/s²) (2.85s)

v = 27.93 m/s

Therefore, the speed of the camera as it hits the water is 27.93 meters per second.

Learn more about Speed here:
https://brainly.com/question/28224010

#SPJ2

Answer:

c-) both objects will reach the bottom at the same instant.

(b) decrease.

Explanation:

Although the feather is lighter than the coin, the tube where the experiment is performed is evacuated. Therefore there is no air that prevents the feather from falling freely with the same acceleration and speed as the coin.

In fact in the equations of kinematics proposed by Newton, the mass of the bodies is not taken into account, as we can see in the following equation:

[tex]v_{f}= v_{i} +g*t[/tex]

where:

Vf = final velocity [m/s]

Vi = initial velocity [m/s]

g = gravity acceleration [m/s^2]

t = time [s]

Therefore the answer is C.

Gravitational pull is a function of height, as the height of the body increases, the force of gravity decreases.

Answer:

36m/s

Explanation:

v=u+at

v=21+(2.2×6.9)

v=21+15.18

v=36.18

v=36m/s

Answer:

one right angel = 90 degrees

and two acute angels?

Explanation:

Answer:

The distance will be x = 1320 [m]

Explanation:

To solve this problem we must use the expression of physics that relates space to time, which is defined as speed.

v = Speed = 11 [m/s]

t = time = 120 [s]

x = distance [m]

v = x/t

x = v*t

x = 11*120

x = 1320 [m]

Answer:

a) F = 9.69 N

b) F = 10.88 N

c) F = 8.51 N

Explanation:

a) The kinetic frictional force when the elevator is stationary is the following:

[tex] F_{k} = \mu_{k}N = \mu(mg) [/tex]    

Where:

F(k) is the kinetic frictional force

N is the normal force = mg

m: is the mass = 2.60 kg

g: is the gravity = 9.81 m/s²

μ(k) is the coefficient of kinetic friction = 0.380

[tex] F_{k} = \mu(mg) = 0.380*2.60 kg*9.81 m/s^{2} = 9.69 N [/tex]    

b) When the elevator is accelerating upward with acceleration "a" equal to 1.20 m/s²

[tex] F_{k} = \mu_{k}N = \mu[m(g + a)] [/tex]    

The normal is equal to mg plus ma because the elevator is accelerating upward

[tex] F_{k} = \mu m(g + a) = 0.380*2.60 kg(9.81 m/s^{2} + 1.20 m/s^{2}) = 10.88 N [/tex]    

c) When the elevator is accelerating downward with a =1.20 m/s² we can find the kinetic frictional force similar to the previous case:

[tex] F_{k} = \mu m(g - a) = 0.380*2.60 kg(9.81 m/s^{2} - 1.20 m/s^{2}) = 8.51 N [/tex]    

I hope it helps you!

Answer:

Explanation:

speed (velocity) = distance / time

                          = 0.2 km (1000 m/km)

                                     95 secs.

                          = 2.10 meters per second

Answer:

Explanation:

Cardinality of a set is the number of elements in that set. Given the set.

F= {mango, apple, banana, orange)​, we are to determine the cardinality of the set i.e the amount of fruit present in the set. Cardinality of the set F is represented as n(F).

Since there are 4 different fruit in the given set F, hence the cardinality of the set F is n(F) = 4

Answer:

At 40 deg  Vy = V sin 40

at 70 deg Vy = V sin 70

So the ball launched at 70 deg has the greatest vertical velocity and will remain in the air the longest:

Since t = Vy / g    time for to reach zero vertical velocity and also the time for the ball to reach velocity Vy on the downward path

Mathis kicked a ball on a level surface at 30∘ and 60∘ with the same total speed as shown below.

Which launch angle results in the greater maximum height for the ball?

Answer: CORRECT (SELECTED)

60

Answer:

Single Replacement

Explanation:

Answer:

Force=Mass*acceleration

on earth, acceleration=9.81 m/s^2

900 N=Mass*9.81 m/s^2

Mass=91.74 Kg

F=Mass*acceleration(Jupiter)

F=91.74Kg*25.9m/s

F=2376.066 N on Jupiter

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