I don’t understand this problem. Please help!

paraffin wax–cs0.33wo3 [cesium tungsten bronze]

Its coating effectively reduce the solar heat gain and air conditioning energy utilization of building because of  high selective NIR

( NIR - near infrared )  absorbing ability.

the solar energy that absorbed by the window glass will overheat the glass due to photothermal conversion of paraffin wax.

to reduce this problem.

A new energy efficient composite window is designed by NIR shielding.

In the composite window the hexagonal phase cs0.33wo3 is prepared by a reaction of solid state then coated on commercial float glass.

cs0.33wo3 in the window reduces the heat gain.

This composite window is expected to better the  energy efficiency of buildings located in the high temp fluctuations.

The given question is incomplete The complete question is.

paraffin wax–cs0.33wo3 composite windows with excellent near- infrared shielding and thermal energy storage abilities

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the average acceleration of the bullet through the board   -55657×10⁵ m/s²

acceleration-  Rate of change of velocity with respect to time.

S = 0.10 mm = 10⁻⁵ m  ( distance)          [∵ 1mm = 10⁻³]

u =  480 m/s (initial velocity)

v = 345 m/s (final velocity)

As we know the 3rd equation of motion.  

v² = u² + 2aS

a = ? ( acceleration)

using these values in equation we get

(345)² = (480)² + 2×a× 10⁻⁵

a = (345)² -  (480)² / 2× 10⁻⁵

a =  -55657×10⁵ m/s²

The negative sign shows that the direction of acceleration is opposite of velocity thus bullet is slowing down.

the average acceleration of the bullet through the board  -55657×10⁵ m/s²

The given question is incomplete. The complete question is.

a bullet fired straight through a board 0.10 mm thick strikes the board with a speed of 480 m/sm/s, has constant acceleration through the board, and emerges with a speed of 345 m/sm/s.

What is the average acceleration of the bullet through the board/?

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In order to make his measurements for determining the Earth-Sun distance, Aristarchus waited for the Moon's phase to be exactly half full while the Sun was still visible in the sky. For this reason, he chose the time of a half (quarter) moon.

It was now possible for another Greek astronomer, Aristarchus, to attempt to determine the Earth's distance from the Sun after learning the distance to the Moon. Aristarchus discovered that the Moon, the Earth, and the Sun formed a right triangle when they were all equally illuminated. Now that he was aware of the distance between the Earth and the Moon, all he needed to know to calculate the Sun's distance was the current angle between the Moon and the Sun. It was a wonderful argument that was weakened by scant evidence. Aristarchus calculated this angle to be 87 degrees using only his eyes, which was not far off from the actual number of 89.83 degrees. But when there are significant distances involved, even slight inaccuracies might suddenly become significant. His outcome was more than a thousand times off.

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The average speed of driving the 10 miles would be lower than 35 mph.

The average speed of an object is the ratio of the total distance to the total time of motion of an object.

Mathematically, average speed of an object is given as;

v(average) = total distance / total time

The average speed of a car decreases with increase in the total time of motion.

Due to the many stop lights along the drive, the total of motion of the car will increase will the total distance traveled by the car (10 miles) will be constant.

Also, since the speed limit is 35 mph, the average speed of the car will lower than the 35 mph speed limit.

Thus, the average speed of driving the 10 miles would be lower than 35 mph.

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The difference in air pressure between the second floor and the top floor of a building is about equal to (1.2)(10)(100) = 1200 N/m2, where air density is equal to 1.2 kg/m3 and gravity acceleration is equal to 10 m/s2.

In physics, gravitational acceleration refers to the speed at which a body falls freely in a vacuum (and thus without experiencing drag). This is the constant acceleration brought on just by the gravitational pull. Gravimetry is the measurement and analysis of these rates. All bodies accelerate at the same rate in vacuum, independent of their masses or compositions.

The combined effects of gravity and the centrifugal force from Earth's rotation cause the Earth's gravity to be as great as it is at a given location on the surface. Depending on height, latitude, and longitude, the free fall acceleration varies at various locations on the surface of the Earth from 9.764 to 9.834 m/s2 (32.03 to 32.26 ft/s2). The exact definition of a conventional standard value is 9.80665 m/s2 (32.1740 ft/s2). Gravity anomalies are areas where this value differs significantly. Other effects like buoyancy or drag are not included in this.

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The electric field outside the cylinder a distance r from the axis. E=6k/λr [k= 1/4πε1]

The electric force per unit charge is referred to as the electric field. It is assumed that the field's direction corresponds to the force it would apply to a positive test charge. From a positive point charge, the electric field radiates outward, and from a negative point charge, it radiates in.

From the point charge, the electric field radiates outward in all directions. Spherical equipotential surfaces are represented by the circles. The vector sum of the individual fields can be used to calculate the electric field from any number of point charges.

E outside of the cylinder is given by:

E(2rL) = L+2rL

q out =3λL

E=0 2rL /3rL

E=6k/λr [k= 1/4πε1]

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The number of turns required on the secondary winding is 1,600 turns.

The number of turns needed in the secondary winding is calculated as follows;

Ns/Np = Es/Ep

where;

Ns/80 = 2200/110

Ns = 80( 2200/110)

Ns = 1,600 turns

Thus, the number of turns required on the secondary winding is 1,600 turns.

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The resultant  superposition of waves is -1.647cm

We are given that

y₁ = 3.0 cos (4.0x - 1.6t)

y₂ = 4.0 sin (5.0x -2.0t)

where x and y are in centimeters and seconds respectively

It is given that resultant wave is y1+y2

at x=1, t=1

y= y1+y2

 = 3.0 cos (4.0x - 1.6t) + 4.0 sin (5.0x - 2.0t)

  = 3.0 cos ( 4 x 1 -1.6 x1) + 4.0 sin(5 x 1 - 2.0 x 1)

  = 3 cos (2.4rad) + 4 sin(3rad)

   = -2.212 + 0.5645

 =  -1.647cm

Hence the superposition of waves is -1.647cm

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The mass of the air in the cylinder will be 0.811 Kg.

The ideal gas law also referred to as the generic gas equation, is the equation of state for a hypothetical perfect gas. It is a good approximation of the behavior of several gases under diverse conditions, despite significant limitations.

Given that a vertical cylinder with a heavy piston contains air at 300 K . The initial pressure is 2.00 ×10⁵Pa, and the initial volume is 0.350m³. Take the molar mass of air as 28.9 g/mol.

The mass of the air in the cylinder will be calculated as below:-

P₁V₁ = nRT₁

n = ( P₁V₁  / RT₁ )

( m / M ) =  ( P₁V₁  / RT₁ )

m = ( P₁V₁ M / RT₁ )

m = ( P₁V₁ M / RT₁ ) = ( 2 x 10⁵ x 0.35 x 0.0289 ) / ( 8.314 x 300 )

m = 0.811 Kg

Therefore, the mass of the air in the cylinder will be 0.811 Kg.

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Photon move at the speed of light which is option (b)

As electrons and protons are particles of the atoms and posses mass so they do not move at the speed of light even in vaccum.

Photon is a light energy so it moves with the speed of light .

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Answer:

A?

Explanation:

i don't know correct me if i'm wrong

Answer:

Third answer choice

Explanation:

Dot in the middle and Fn and Fg

Hope this helps! :)

A family ice show is held at an enclosed arena. The skaters perform to music with level 80.0 db. This level is too loud for your baby, who yells at 75.0 db. 155 db. is the combined sound level.

In physical science, the force or motion of brilliant energy is the power moved per unit region, where the region is estimated on the plane opposite to the heading of spread of the energy. Light force assumes an essential part. With expanded light the fish' s vision improves, and they will turn out to be more careful about hunters.

The formula for intensity is given by, I = P A. Where I am the intensity, P is the power and A is the area of cross section.

The sun' s point decides how much light entering the water. As would be normal, the most elevated measure of sun-based force happens on the globe right where the sun is above and as the point of the sun brings down, the sun-oriented power declines.

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The kinetic energy of the muon is 4.08 MeV

Given that:

A pion (mπ = 273 me)

muon (mµ= 207me)

Neutrino (mv=0)

(Let’s assume that c =1, and that me= 0.511MeV)

Since the pion is at rest conversation of momentum dictates that the momenta of the muon and the neutrino be equal in magnitude,

P_μ=P_v      (1)

Since the pion is at rest its energy equals its mass, E_π=m_π. Since the neutrino is massless its energy equals its momentum E_v=P_v . By conservation of energy,

E_π=E_μ+E_v, so

E_μ=m_π-P_v     (2)

Substituting the right sides of (1) and (2) into the left side of the fundamental kinematic equation for the muon E_μ^2-P_μ^2=m_μ^2 yields

〖(m_π-P_v)〗^2-P_μ^2=m_μ^2

Solving for P_v gives (the magnitudes of) the momenta of the decay particles and the kinetic energy (equal to the total energy) of the massless neutrino,

P_v (〖=P〗_u=E_v )=((m_π^2-m_μ^2))/(2m_π )

P_v=(〖273〗^2-〖207〗^2)/(2× 273)=29.65 MeV  

The kinetic energy of the muon equals its total energy minus its mass which, using (2), is

〖(m〗_π-P_v)-m_μ=4.08 MeV

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B = μ₀i/2πr

i = 2πrB/μ₀

∵ 16.50 nano Tesla = 1.65×10⁻⁸ Tesla

∵8.10Km = 8100 m

i = 2(3.14)(8100)(1.65×10⁻⁸)/4×3.14×10⁻⁷

i = 668.25 A

So the current carried up or down the funnel of the tornado is 668.25 A.

A tornado is a fast spinning column of air that occasionally strikes the base of a cumulonimbus cloud as well as the Earth's surface.

A tornado is a narrow, violently rotating column of air that extends from the ground to a thunderstorm.

Tornadoes are difficult to notice since wind is invisible unless they build a condensation funnel of water droplets, dust, and debris.

Some tornadoes increase and become powerful or destructive. Strong tornadoes can last for twenty minutes or more and have winds of up to 200 miles per hour, whereas severe tornadoes can persist for more than an hour and have winds of 200 to 300 miles per hour!

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The speed of sound used in water is 5408 Hz.

(d) The frequency that submarine B is able to detect is   [tex]fo = fs (V -V_O/ v +V_s).[/tex]

                  [tex]=53.273[/tex] × [tex]10 3hz) (1533 m/s + 11 m/s / (45 m/s - 1533 m/s))[/tex]

Frequency [tex]= 5408 HZ[/tex]

Hence, the speed of sound used in water is [tex]5408Hz[/tex].

Submarine, any naval vessel capable of propulsion both below and above the surface of the ocean. Submarines are very distinct from surface ships in terms of appearance and design, making this a unique capacity among warships.

When Germany used them to attack surface merchant ships during World War I (1914–18), submarines initially played a significant role in naval warfare. Torpedo's, a type of self-propelled underwater missile used by submarines, were used as their main armament in such attacks. In World War II (1939–1955), submarines participated in similar operations on a bigger scale, in both the Atlantic (by Germany) and Pacific (by the United States).

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If the particle's speed is doubled. The momentum's value is then increased by twice.

In Newton's equations of motion, an object's linear momentum, translational momentum, or simply momentum is the product of its speed and mass. Given that it has a dual magnitude and its direction, it is a vector quantity. kg-m/s is the SI unit for momentum.

Let m be the item's mass and v be its speed. Then the momentum is given as,

P = mv   kg-m / s

A particle is traveling less quickly than c / 2. if the particle's speed is twice.

P = m(2v)

P = 2mv

If the particle's speed is twice. The momentum's value is then increased by a factor of two.

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The wavelength of a 2.4 ghz sine wave is 0.5 inches.

In physical science, the frequency is the spatial time of an occasional wave the distance over which the wave's shape rehashes. Albeit X-beams have numerous advantageous applications, utilizing them requires alert since openness can cause visual deficiency, malignant growth and different wounds. Frequency and recurrence are conversely related so that more drawn out waves have lower frequencies, and more limited waves have higher frequencies. Frequency addresses the distance between two successive recurrence wave tops and is normally used to portray the electromagnetic range.

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The statements about the skateboarder's energy is true option C which is  if friction is present, mechanical energy will be conserved. the pe is the greatest at the bottom of the ramp.

Energy is the ability to perform a task or do work. Energy can be potential or kinetic energy. Potential energy is the energy posses by a body in a state of rest while kinetic energy is the energy in motion.

As the skateboarder travels  the ramp, potential energy turn to kinetic energy and if  friction is present some of the energy in the system is converted to heat energy.

Therefore, The statements about the skateboarder's energy is true option C which is  if friction is present, mechanical energy will be conserved. the pe is the greatest at the bottom of the ramp.

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The given equations of motion are rearranged for the said variables.

In the given equations of motion, the variables used represents:

[tex]v_{f}[/tex] = Final velocity

[tex]v_{i}[/tex] = Initial velocity

Δx = Displacement

a = Acceleration

t = Time

The given equations that are rearranged for said variables are as follows.

Therefore, the given equations of motion are rearranged above for the said variables.

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The direction of electric field at any point of z axis is always positive because of the symmetry property.

ELECTRIC FIELD - It is a force that fills the space around  every charge in space.

It is a physical quantity. It represents the vector field that is generated by a charge in the area around that charge. It is defined as the electric force per unit test charge that placed at distance from the charged that generate the electric field.

the electric field is outward from the positive charge and inward  negative point charge.

The direction of electric field at any point of z axis is always positive because of the symmetry property.

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The Position-Time graph for the given Velocity-Time graph is drawn in the image attached.

From the Velocity-Time graph we can take the information needed.

[tex]t_{1}[/tex] = 1 s

[tex]t_{2}[/tex] = 2 s

[tex]t_{3}[/tex] = 3 s

[tex]t_{4}[/tex] = 4 s

[tex]t_{5}[/tex] = 5 s

[tex]v_{1}[/tex] = 10 m / s

[tex]v_{2}[/tex] = 20 m / s

[tex]v_{3}[/tex] = 30 m / s

[tex]v_{4}[/tex] = 40 m / s

[tex]v_{5}[/tex] = 50 m / s

v = d / t

d = v * t

[tex]d_{1}[/tex] = 10 * 1 = 10 m

[tex]d_{2}[/tex] = 20 * 2 = 40 m

[tex]d_{3}[/tex] = 30 * 3 = 90 m

[tex]d_{4}[/tex] = 40 * 4 = 160 m

[tex]d_{5}[/tex] = 50 * 5 = 250 m

Therefore, the Position-Time graph is drawn in the image attached.

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The displacement of the dealer's homing pigeon in the car is 12.81 miles.

The displacement of an object is the change in position of an object.

Displacement is a vector quantity because it can be described by both magnitude and direction.

The displacement of the dealer's homing pigeon in the car is calculated as follows;

initial position = 10 miles east

final position = 8 miles south

displacement = √(10² + 8²)

displacement = 12.81 miles

Thus, the displacement of the dealer's homing pigeon in the car is 12.81 miles.

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The height at which the seagull was flying is 82.45 m.

The height of motion or maximum height in projectile motion occurs when the object reaches a vertical velocity of zero magnitudes.

The height at which the seagull was flying is calculated as follows;

v² = u² - 2gh

where;

0 = u² - 2gh

2gh = u²

h =  u²/2g

h = (40.2²) / (2 x 9.8)

h = 82.45 m

Thus, the height at which the seagull was flying is 82.45 m.

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The velocity of the car will be 36.8 m/s when it has traveled a distance of 70 cm.

The velocity at any moment in time during a particle's motion is given by instantaneous velocity, a continuous function of time. By calculating the derivative of the position function, which gives us the functional form of instantaneous velocity v, we may determine the instantaneous velocity at a certain time (t).

Velocity is a vector quantity.

SI unit is m/s.

According to the question, the Given values are :

Distance =40 cm

=0.4 meter

Velocity, v =2105.3 cm/s

=21.053 m/s

21.053=0.4/t

⇒t=0.4/21.053

t=0.019 seconds

Now, the distance is 70 cm

=0.70 meters

v=0.7/0.019

v=36.8 m/sec

Hence, the velocity will be 36.8 m/sec when it has traveled a distance of 70 cm.

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By using uniform motion, the average force is 3106.89 N.

We need to know about the uniform motion to solve this problem. The uniform motion is an object's motion under acceleration. It should follow the rule

vt = vo + a . t

vt² = vo² + 2a . s

s = vo . t + 1/2 . a . t²

where vt is final velocity, vo is initial velocity, a is acceleration, t is time and s is displacement.

From the question above, we know that

vo = 0 m/s

vt = 10.6 m/s

m = 0.85 kg

t = 2.9 ms = 2.9 x 10¯³ second

Find the acceleration by using the first equation

vt = vo + a . t

10.6 = 0 + a. 2.9 x 10¯³

a = 3655.17 m/s²

Find the average force

F = m . a

F = 0.85 . 3655.17

F = 3106.89 N

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You should connect two 10 Ohms resistors in parallel and then connect it in series with a 3 Ohms resistors.

In order to achieve the desired resistance under the given circumstances, we would connect two 10 Ohms resistors in parallel and then connect it in series with a 3 Ohms resistors.

Mathematically, the total equivalence resistance of two resistors that are connected in parallel is given by:

1/Rt = 1/R₁ + 1/R₂

1/Rt = 1/10 + 1/10

1/Rt = 2/10

1/Rt = 1/5

Rt = 5 Ohms.

Next, we would connect this 5 Ohms resistor in series with the 3 Ohms resistor:

R₃ = 3 + Rt

R₃ = 3 + 5

R₃ = 8 Ohms.

In conclusion, you can create an equivalent resistance of 8 ohms from only 10 ohms resistors and 3 ohm resistors by connecting two 10 Ohms resistors in parallel and then connect it in series with a 3 Ohms resistors.

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The Kinetic energy of the pupil with mass of 55kg swinging back on a chair and falling off at a speed of 0.6 m/s is "9.9 J".

Kinetic energy is defined as the energy possessed by a body due to the virtue of velocity.

the S.I. unit of Kinetic energy is joule .

Kinetic energy is conserved.

velocity is defined as the displacement per unit time.

S.I unit of velocity is m/s.

given:

Mass (m) = 55 kg

velocity (v) = 0.6 m/s

Kinetic energy(K)=1/2×mv²

Kinetic energy (K)=1/2×55×0.36

Kinetic energy (K)= 9.9 joule

therefore,

The Kinetic energy of the pupil with mass of 55kg swinging back on a chair and falling off at a speed of 0.6 m/s is "9.9 J".

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The total energy output in 1010 years is therefore equal to (22M + 33S) 1010 kWh.

Energy output in 1010 years will be equal to (22M + 33S) 1010 kWh.

22 windmills make up the model home. M kWh of energy are produced by one wind turbine year. 22 windmills generate 22 M kWh of energy each year. 33 solar panels make up the model home. S kWh of energy is produced by one solar panel annually. Energy produced by 33 solar panels annually equals 33 S kWh.

Now, the total amount of energy produced by 22 windmills and 33 solar panels in a year is equal to (22 M + 33 S) kWh.

One of the most crucial steps you can take to lessen your influence on the environment is to use renewable energy. More than all of our driving and flying put together, electricity production is our main source of greenhouse gases. Clean energy also lessens damaging smog, toxic buildup in our air and water, and the effects of coal mining and gas extraction. It will take time to replace our fossil fuel infrastructure, and clean energy demand from consumers and companies, as well as strong, continuous support from state and federal mandates to create renewable energy generation.

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The electric flux is zero through four cube surfaces.

Assuming the charged filament is quite long, and you are not near the edges, the two opposing sides that the filament travels through have no flux. If the charge filament is long, which you may assume is indefinitely long, then there is the equal amount of charge on the left and right of where you are, therefore the electric field has no preference for left or right.

This implies that the electric field can only travel in or out of the filament. No field lines run through the two faces of the cube that the filament goes through if the electric field is not moving left or right. There are electric field lines on the four sides of the filament.

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