I AM GETTING TIMED! PLEASE HELP ME!!

I AM GETTING TIMED! PLEASE HELP ME!!

Answers

Answer 1

Explanation:

no.A (He) I think.............


Related Questions

0.12M NaOH solution to neutralize Oxalic acid solution. you will need the molecular weight of the Oxalic acid

Answers

Answer:

2 NaOH (aq) + H2C2O4(aq) Na2C2O4(aq) + 2H2O (l) Moles of NaOH used = Molarity x Volume (L) = 0.12 mole/L x 0.025

Explanation:

The decomposition of AB given here in this balanced equation 2AB (g)⟶ A2 (g) + B2 (g), has rate constants of 8.58 x 10-9 L/mol s at 325°C and 2.16 x 10-5 L/mol x at 407°C. Find the activation energy

Answers

Answer:

3.24 × 10^5 J/mol

Explanation:

The activation energy of this reaction can be calculated using the equation:

ln(k2/k1) = Ea/R x (1/T1 - 1/T2)

Where; Ea = the activation energy (J/mol)

R = the ideal gas constant = 8.3145 J/Kmol

T1 and T2 = absolute temperatures (K)

k1 and k2 = the reaction rate constants at respective temperature

First, we need to convert the temperatures in °C to K

T(K) = T(°C) + 273.15

T1 = 325°C + 273.15

T1 = 598.15K

T2 = 407°C + 273.15

T2 = 680.15K

Since, k1= 8.58 x 10-9 L/mol, k2= 2.16 x 10-5 L/mol, R= 8.3145 J/Kmol, we can now find Ea

ln(k2/k1) = Ea/R x (1/T1 - 1/T2)

ln(2.16 x 10-5/8.58 x 10-9) = Ea/8.3145 × (1/598.15 - 1/680.15)

ln(2517.4) = Ea/8.3145 × 2.01 × 10^-4

7.831 = Ea(2.417 × 10^-5)

Ea = 3.24 × 10^5 J/mol

The activation energy is 3.24 × 10^5 J/mol

Equation:

The activation energy of this reaction can be determined using the equation:

ln(k2/k1) = Ea/R x (1/T1 - 1/T2)

Here

Ea = the activation energy (J/mol)

R = the ideal gas constant = 8.3145 J/Kmol

T1 and T2 = absolute temperatures (K)

k1 and k2 = the reaction rate constants at  temperature

Now

First, we need to convert the temperatures in °C to K

So,

T(K) = T(°C) + 273.15

T1 = 325°C + 273.15

T1 = 598.15K

T2 = 407°C + 273.15

T2 = 680.15K

Since, k1= 8.58 x 10-9 L/mol, k2= 2.16 x 10-5 L/mol, R= 8.3145 J/Kmol, we can now determined Ea

So,

ln(k2/k1) = Ea/R x (1/T1 - 1/T2)

ln(2.16 x 10-5/8.58 x 10-9) = Ea/8.3145 × (1/598.15 - 1/680.15)

ln(2517.4) = Ea/8.3145 × 2.01 × 10^-4

7.831 = Ea(2.417 × 10^-5)

Ea = 3.24 × 10^5 J/mol

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In an experiment, two unknown compounds (one an alcohol and the other an amine) of equal molecular mass were heated. The result of the experiment shows that Compound A boiled at a lower temperature than Compound B.

Which of the following correctly explains the identity of Compound A and why this was the result? (4 points)

It is an amine; it contains nitrogen-hydrogen bonds that are less polar and oxygen-hydrogen bonds.
It is an alcohol; it contains nitrogen-hydrogen bonds that are less polar and oxygen-hydrogen bonds.
It is an alcohol; it contains oxygen-hydrogen bonds that are less polar and nitrogen-hydrogen bonds.
It is an amine; it contains oxygen-hydrogen bonds that are less polar and nitrogen-hydrogen bonds.

Answers

Answer:

It is an amine; it contains nitrogen-hydrogen bonds that are less polar and oxygen-hydrogen bonds.

Explanation:

The boiling point of a compound is a physical property. Such physical property are influenced by the intramolecular bonds between the molecules that makes a up compound.

Both Amine and Alcohols have the same type of intermolecular bonds between them. This bond type is called the hydrogen bonds.

A hydrogen bond is an electrostatic attraction between the hydrogen atom of one molecule and the electronegative atom of a neighboring molecule.

 Note: the strength of a hydrogen bond depends on the relative electronegativity of the atom directly joined to the hydrogen.

  The order of strength of the bond is;

             H.....F  > H.....O > H......N

In amines we have the H....N hydrogen bonds, for alcohol, it is the H....O hydrogen bonds.

So, the bonds in hydrogen bonds in the alcohol is stronger and it will impart a higher boiling point on the compound.

Answer: It is an amine; it contains nitrogen-hydrogen bonds that are less polar than oxygen-hydrogen bonds.

Explanation: I TOOK THE TEST AND GOT IT RIGHT

According to the principle of the conservation of mass the mass of the sodium sulfate was the following PLS HELP I NEED TO TURN THIS IN ASAP

Answers

Answer:

Explanation:

The Law of Conservation of Mass is defined and explained using examples of reacting mass calculations using the law are fully explained with worked out examples using the balanced symbol equation. The method involves reacting masses deduced from the balanced symbol equation.

PLEASE HELP ME !!!!!!!!!!!!!!
Name: Period; Date:

Problem:

Determine the amount of energy (heat) in Joules and Kcal required to raise the temperature 0f 98.5 grams water from 37.0 0C to 75.0 0C.
Restate the problem (in your own words & all relevant information included).
Model that best represents the problem. Draw and label.
Steps to solve the problem (include formula, known and unknown variables, etc)












Solution and final answer. (show cancellation of units).











Reflection: Must at least have 3 sentences.

Answers

Answer:

                                                               

Explanation:

                                                                           

What best explains whether bromine (Br) or neon (Ne) is more likely to form a covalent bond?

On left, a purple circle labeled Br surrounded by 4 concentric circles. The inner circle has 2 small green spheres. The second circle has 8 small green spheres. The third circle has 18 small green spheres. The fourth circle has 5 small green spheres. On right, a purple circle labeled Ne surrounded by 3 concentric circles. The inner circle has 2 small green spheres. The middle circle has 8 small green spheres. The outer circle has 8 small green spheres.
Bromine forms covalent bonds because it has seven valence electrons, but neon has eight valence electrons and already fulfills the octet rule.
Bromine forms covalent bonds because it has many electron shells, but neon has only two electron shells and is tightly bound to its electrons.
Neon forms covalent bonds because it can share its valence electrons, but bromine has seven valence electrons and can gain only one more electron.
Neon forms covalent bonds because it has only two electron shells, but bromine has many electron shells and will lose electrons in order to fulfill the octet rule.
Mark this and return

Answers

Answer:

Bromine forms covalent bonds because it has seven valence electrons, but neon has eight valence electrons and already fulfills the octet rule. Neutral atoms coming together to share electrons.

Hoped this helped

Answer:

the answer is A btw

Explanation:

What is thirty plus one equal

Answers

Answer:

31

Explanation:

The answer is 31
30+1=31

1. You return to the car from an all-day shopping spree at the mall.
Your favorite CD, which you left on the dashboard, is now stuck.what could be the experiment?

Answers

Answer:

it could be a bad experience

Explanation:

because the left the cd on the dashboard

A student buys a rope at the store. The label on the packaging says that the rope is 2.15 meters in length. The student measures the rope as 1.85m. What is the student’s percent error?

Answers

Answer:

30 center meters

Explanation:

2.15-1.85=0.30

If I was an astronaut the mass would be much larger than earth because, the more mass an object has, the more the object pulls towards it. Mass is the amount of matter that will be everywhere. mass of earth is so big, It creates a gravitational force that can pull objects toward its center. Please help!!!!! Right between "It." and mass I need a good transition word.

Answers

Answer:

In my opinion, I think that furthermore might be a good transition word.

hope this helps :)

Explanation:

I really need this fast

Answers

Answer:

b

I think it's me because a ball of golf into some races as it rolls up increases put

look at the picture ​

Answers

Answer:

C

Explanation:

If a substance is malleable, it can be hammered flat without breaking

Which method of heat transfer can take place without matter? (3 points)

a
Conduction

b
Convection

c
Insulation

d
Radiation

Answers

The answer is (D) radiation.

Answer:

I bealive the answer is D.

How do I do this question?The aluminum cup inside your calorimeter weighs 39.78 g. You add 50.01 g of ice cold water to the calorimeter. You measure the temperature of the calorimeter to be 0.5oC just before your next addition. You then add 50.72 g of hot water and a 49.98 g metal object, all having an initial temperature of 69.5oC. After the calorimeter reaches thermal equilibrium, the final temperature is measured to be 35.9oC.

What is the specific heat of the metal object, in units of J g-1 oC-1.

Assume that:

the calorimeter is completely insulated
the heat capacity of the empty calorimeter is the heat capacity of the aluminum cup: 0.903 J g-1 oC-1.
the density of water is: 1.00 g/mL.
the heat capacity of water is: 4.184 J g-1 oC-1.
Perform all calculations without rounding, but then provide your answer to the correct number of significant figures. Units can be entered as J/(gK)

Answers

Answer:

[tex]Cp_{metal}=0.922\frac{J}{g\°C}[/tex]

Explanation:

Hello.

In this problem we must realize that there is heat flow that moves from the hot metal object and the hot water to the cold water and the cold aluminum cup, which allows us to write:

[tex]Q_{cup}+Q_{cold,w}=-(Q_{metal}+Q_{hot,w})[/tex]

Which means that the heat lost be the hot metal object and the hot water is gained by both the cold water and the cold aluminum cup, which can be written in terms of mass, specific heats and change in temperature towards the equilibrium temperature (35.9 °C):

[tex]m_{cup}Cp_{cup}(T_{eq}-T_{cup})+m_{cold,w}Cp_{cold,w}(T_{eq}-T_{cold,w})=-(m_{metal}Cp_{metal}(T_{eq}-T_{metal})+m_{hot,w}Cp_{hot,w}(T_{eq}-T_{hot,w})[/tex]

We need to solve for the specific heat of the metal as shown below:

[tex]Cp_{metal}=\frac{m_{cup}Cp_{cup}(T_{eq}-T_{cup})+m_{cold,w}Cp_{cold,w}(T_{eq}-T_{cold,w})+m_{hot,w}Cp_{hot,w}(T_{eq}-T_{hot,w})}{-m_{metal}(T_{eq}-T_{metal})} \\\\Cp_{metal}=\frac{39.78g*0.903\frac{J}{g\°C}(35.9-0.5)\°C+50.01g*4.184\frac{J}{g\°C}(35.9-0.5)\°C +50.72g*4.184\frac{J}{g\°C}(35.9-69.5)\°C }{-49.98g(35.9-69.5)\°C } \\\\Cp_{metal}=\frac{1271.6J+7407.2J-7130.3J}{-1679.3g\°C} \\\\Cp_{metal}=0.922\frac{J}{g\°C}[/tex]Best regards.

which organelle helps to break down substances?

Answers

Answer:

Lysosomes

Explanation:

Potassium hydrogen phthalate is a solid, monoprotic acid frequently used in the laboratory to standardize strong base solutions. It has the unwieldy formula of KHC8H4O4. This is often written in shorthand notation as KHP. Of 5.06 grams of KHP are needed to exactly neutralize 35.3 mL of a barium hydroxide solution, what is the concentration of the base solution

Answers

Question: Potassium hydrogen phthalate is a solid, monoprotic acid frequently used in the laboratory to standardize strong base solutions. It has the unwieldy formula of KHC8H4O4. This is often written in shorthand notation as KHP. Of 5.06 grams of KHP are needed to exactly neutralize 35.3 mL of a barium hydroxide solution, what is the concentration of the base solution?

Explanation and answer:

2KHP + Ba(OH)2 ---> 2H2O + Ba(KP)2

you need 2 moles of KHP to neutralise 1 mole of Ba(OH)2

moles KHO = mass / molar mass  

= 2.43 g / 204.22 g/mol  

= 0.0118989 mol

moles Ba(OH)2 = 1/2 x moles KHP

= 0.005949 mol

Molarity Ba(OH)2 = moles / Litres

= 0.005949 mol / 0.0213 L

= 0.279 M (3 sig figs)

Write a nuclear reaction for the fission of Uranium-235 by bombardment with a neutron.

Answers

Answer:

jumm453685ruuhkcswch


What is the correct electron configuration of a sulfur ion?

Answers

Answer:

The electron configuration of sulfur (S) normally is 1s2 2s2 2p6 3s2 3p4

S+ ion of sulfur would be 1s2 2s2 2p6 3s2 3p3

S- ion 1s2 2s2 2p6 3s2 3p5

Figure 5 below shows four abiotic factors of an ecosystem. Choose the
statement that identifies a major characteristic of abiotic factors in
ecosystems.


A. They are all living.
B. There are equal amounts in every ecosystem.
C. They are not alive, never have been alive, and never will be alive.
D. They are impossible to measure.

Answers

C. They are not alive, never have been alive, and will never be alive.

What is the volume of “a pencil has a density of .875 g/ml . It has a mass of 3.5 grams

Answers

Answer:

The answer is 4 mL

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

[tex]volume = \frac{mass}{density} \\[/tex]

From the question

mass of pencil = 3.5 g

density = 0.875 g/mL

So we have

[tex]volume = \frac{3.5}{0.875} \\ [/tex]

We have the final answer as

4 mL

Hope this helps you

A homerun in a baseball game was measured at 450 feet. How many meters is this equal to?

Answers

Answer:

137.16

Explanation:

PLEASE PLEASE HELP
3. SEP Analyze Data Suppose you did not want to calculate the precise atomic
mass for one of the elements, such as nitrogen or oxygen. How could you
approximate the value of the atomic mass?

Answers

add it up maybe?

Explanation:

The atomic mass of any element can be easily determined with the help of the number of protons and neutrons. You are simply required to add the number of neutrons and protons in order to estimate the atomic mass of any element.

What is Atomic mass?

The Atomic mass of an element may be defined as the average mass of the atoms of an element that are significantly measured in the atomic mass unit (amu).

Another method through which you can approximate the value of the atomic mass of any element is that you are simply required to double the value of the atomic number that is known for each specific element.

For example, The atomic number of oxygen is 8, while its atomic mass is 8 × 2 = 16. Similarly, the atomic number of nitrogen is 7, while its atomic mass is 7 × 2 = 14.

Therefore, it is well described above.

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Determine the mass of CuSO4 • 5H20 that must be used to prepare 250mL of 2.01 M CuSO4(aq).

Answer in units of g.

Answers

Given parameters:

Volume of CuSO₄ = 250mL

Concentration of CuSO₄ = 2.01M

Unknown:

Mass of CuSO₄.5H₂O = ?

To solve this problem, we must write the chemical relationship between both species.;

             CuSO₄.5H₂O  →   CuSO₄ + 5H₂O

Now that we know the expression, it is possible to solve for the unknown mass.

First find the number of moles of CuSO₄;

         Number of moles  = Concentration x Volume

Take 250mL to L so as to ensure uniformity of units;

           Volume  = 250 x 10⁻³L

  Input the parameters and solve for number of moles;

        Number of moles  = 250 x 10⁻³  x  2.01 = 0.5mol

From the equation;

             1 mole of CuSO₄ is produced from 1 mole of CuSO₄.5H₂O  

So  0.5 moles of CuSO₄ will be produced from 0.5 moles of CuSO₄.5H₂O

Now let us find the molar mass of CuSO₄.5H₂O = 63.6 + 32 + 4(16) + 5(2x1 + 16)  = 249.6g/mole

Mass of CuSO₄.5H₂O = number of moles x molar mass

                                      = 0.5 x 249.6

                                     = 124.8g

The mass of CuSO₄.5H₂O is 124.8g

how do i get the bond dissociation energy to break 7 C-H bond(s) in 1 mole of propane (CH₃CH₂CH₃) molecules is

Answers

Answer:

[tex]2877kJ/mol[/tex]

Explanation:

Hello.

In this case, since the bond energy per C-H bond is 411 kJ/mol and we of course avoid the C-C bond since we are asked to compute the energy to break 7 C-H bonds, the 411 kJ/mol are multiplied by 7 as shown below:

[tex]7*411kJ/mol\\\\=2877kJ/mol[/tex]

Thus, we obtain the required bond dissociation energy. Note that propane CH₃-CH₂-CH₃ has seven C-H bonds; 3 from the first CH₃, two from the CH₂ and 3 from the last CH₃.

Best regards.

Bond dissociation energy is defined as the energy required to dissociate or break a bond to form two or more molecular fragments.

In the given molecule of propane, the energy required to break the seven C-H bonds is 2877 kJ/mol.

The bond dissociation energy for the highly stable bond will be very high. In the given bonds of carbon and hydrogen, we know that:

Each C-H bond has an energy of 411 kJ/mol.

To calculate the bond dissociation energy of 7 C-H bonds, we have:

1 C-H bonds = 411 kJ/mol

7 C-H bonds = 411 x 7

7 C-H bonds = 2877 kJ/mol

Therefore, the bond dissociation energy required to break the seven C-H bonds is 2877 kJ/mol.

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What voltage is required to move 2 amps through 20 ohms?

Answers

Answer:

v=ir

v=2×20

=40V is the answer

Answer:

a

Explanation:

the answer is a

the substance most likely to be a gas at room temperature is

Answers

Answer:

The water

Explanation:

How many grams of H2 are needed to react with 47 grams of N2 to produce 200 grams of NH3?

Answers

I think it’s law conservation of mass.

So 200g(NH3)-47g(N2)=153g(H2)

H2+N2—->NH3

The term mole concept is used here to determine the mass of hydrogen. The mass of hydrogen required to produce 200 g of ammonia is 35.28 g.

What is a mole?

One mole of a substance is defined as that quantity of it which contains as many entities as there are atoms exactly in 12 g of carbon - 12. The formula used to calculate the number of moles is:

Number of moles = Given mass / Molar mass

The balanced equation is:

N₂ + 3H₂ → 2NH₃

3 moles of H₂ gives 2 moles of NH₃

The molecular mass of NH₃ is 17 g/mol

n = 200 / 17 = 11.76 mol

1 mole comes from 1.5 moles of H₂

So 11.76 mol comes 1.5 × 11.76 moles H₂ = 17.64 moles of H₂

Mass of H₂ =  17.64 × 2 = 35.28 g

Thus the mass of H₂ needed is 35.28 g.

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Pls answer! 30 points and brainliest for the correct answer!

Answers

Answer: 313.4 I think

Explanation:

sorry if i got it wrong i tried my best

Answer:

it equals up 30 to 35 for me

Explanation:

sorry if its wrong

is the scientific method cyclic or linear?

Answers

Answer:

Instead of being a linear process, the scientific method is a complex cycle that involves many people and does not follow set steps, but is more free form in nature. Ideas generate new ideas and lead to new hypotheses, and deeper understanding.

Answer:

The answer is

Cyclic...

: )

Write the Lewis structure for sis2

Answers

Answer:

N2H4 is straightforward with no double or triple bonds. In the N2H4 Lewis structure the two Nitrogen (N) atoms go in the center (Hydrogen always goes on the outside). Hydrogen (H) only needs two valence electrons to have a full outer shell. In the Lewis structure for N2H4 there are a total of 14 valence electrons.

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