I = 1/2MR^2 is rolling with a translational speed v along a horizontal surface without slipping. The work required to stop the disk is
A. 1/2 mv^2
B. 1/2mv^2 + 1/2Iw^2
C. 1/2Iw^2
D. 1/2mv^2 - 1/2Iw^2

We can use the kinematic equations to solve for the time it takes for the soccer ball to hit the ground.

Let's use the following variables:

h for the initial height of the soccer ball (12 m)

vi for the initial velocity of the soccer ball (4 m/s)

vf for the final velocity of the soccer ball (0 m/s)

d for the horizontal distance the soccer ball travels before hitting the ground (6.3 m)

t for the time it takes for the soccer ball to hit the ground (what we want to find)

Using the kinematic equation for vertical motion, we can find the time it takes for the soccer ball to reach the ground:

vf^2 = vi^2 + 2*a*h

0 = 4^2 + 2*(-9.8)*12

0 = 16 - 235.2

t_vertical = sqrt(235.2/16) = 3.05 s

So it takes 3.05 seconds for the soccer ball to hit the ground if we consider only the vertical motion.

Next, using the kinematic equation for horizontal motion, we can find the time it takes for the soccer ball to travel the horizontal distance of 6.3 m:

d = vi*t_horizontal

t_horizontal = d/vi = 6.3/4 = 1.575 s

So it takes 1.575 seconds for the soccer ball to travel the horizontal distance of 6.3 m.

Since we know the soccer ball takes the same amount of time to travel horizontally as it does to hit the ground, we can conclude that the time it takes for the soccer ball to hit the ground is 1.575 seconds.

Answer:

Without the table and diagram, it's difficult to provide a specific answer. However, in general, the gravitational attraction between two objects depends on their masses and the distance between them. The force of attraction is stronger when the masses are greater and when the objects are closer together.

Based on this understanding, we can evaluate the claims made by each student:

Student W claims that the probe is pulled harder by the planet with the greater mass when halfway between the planets. This claim is partially supported by the evidence, since the gravitational force is stronger when the masses are greater. However, it doesn't take into account the distance between the planets and the probe.

Student X claims that the probe is pulled harder by the planet nearest the Sun when halfway between the planets. This claim is not supported by the evidence, since the distance between the probe and each planet is not specified.

Student Y claims that the probe is pulled harder by the planet with the greater mass anywhere between the planets. This claim is partially supported by the evidence, since the gravitational force is stronger when the masses are greater. However, it doesn't take into account the distance between the planets and the probe.

Student Z claims that the probe is pulled harder by the planet nearest the Sun anywhere between the planets. This claim is not supported by the evidence, since the distance between the probe and each planet is not specified.

Overall, Student W and Student Y made claims that are partially supported by the evidence, but neither claim takes into account the distance between the planets and the probe. Therefore, it's difficult to determine which claim is best supported by the evidence without more information.

Explanation:

The force required to lift a load of 100 newtons using machine with mechanical advantage of 4 is 25 newtons.

The ratio of output force to the input force is called as mechanical advantage of a machine. In this case, mechanical advantage is given as 4.

As, Mechanical Advantage = Output Force / Input Force

4 = Output Force / Input Force

So, Output Force = Mechanical Advantage x Input Force

Output Force = 4 x Input Force

100 newtons = 4 x Input Force

Input Force = 100 newtons / 4

Input Force = 25 newtons

Therefore, the force required to lift a load of 100 newtons using a machine with a mechanical advantage of 4 is 25 newtons.

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If a 40 N block is resting on a rough horizontal table with a coefficient of static friction is 12 N.

Static friction is a force that resists the motion of two objects that are in contact with each other. It is caused by the forces of attraction between the two objects and is usually greater than the force of kinetic friction. The forces of static friction oppose the movement of the two objects and can be overcome by applying a force greater than the static friction.

The maximum force the block can withstand before it starts to move is 40 N multiplied by the coefficient of static friction.

The coefficient of static friction between the block and the table is determined by the materials of the block and the table and the surface roughness of the table.

If the coefficient of static friction is 0.3, then the maximum force the block can withstand before it starts to move is 40 N × 0.3 = 12 N.

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Answer:

Explanation:

Power=work done/time

work done=force* displacement

force=mass*acceleration due to gravity

Therefore, power= mass*acceleration due to gravity*displacement/time

20*9.8*1/1=196watts

Answer:White Candle

Explanation:because it reflects all colors of light.

Dividing this by 24.0 s gives a power output of 23,600 W.

Power is the ability to influence or control the behaviour of people, events, or things. It is the capacity to make decisions and take action in order to effect change. Power can be physical, economic, political, cultural, or social, and can be held by individuals, organizations, or governments. Power can be used positively to create positive change, or negatively to oppress or exploit. It can be used to create a sense of safety, stability, and justice, or to create uncertainty and chaos.

The power output of the crane is calculated by dividing the work done by the crane (the force multiplied by the distance moved) by the time taken to do the work. In this case, the work done is 13,700 N x 41.4 m = 570,380 Nm. Dividing this by 24.0 s gives a power output of 23,600 W.

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Answer:

1. To solve this problem using conservation of momentum, we can use the equation:

(m1 * v1) + (m2 * v2) = (m1 + m2) * vf

where m1 and v1 are the mass and velocity of the first object, m2 and v2 are the mass and velocity of the second object, and vf is the final velocity of the two objects after they stick together.

Plugging in the given values, we get:

(2 kg * 5 m/s) + (3 kg * 0 m/s) = (2 kg + 3 kg) * vf

Simplifying the equation, we get:

10 kg m/s = 5 kg * vf

vf = 2 m/s

Therefore, the final velocity of the two objects after the collision is 2 m/s.

2. Using the same equation as above and plugging in the given values, we get:

(1000 kg * 10 m/s) + (500 kg * 0 m/s) = (1000 kg + 500 kg) * vf

Simplifying the equation, we get:

10,000 kg m/s = 1500 kg * vf

vf = 6.67 m/s

Therefore, the final velocity of the two cars after the collision is 6.67 m/s.

3. Before the boy jumps off the bike, the total momentum of the system is:

(50 kg + 10 kg) * 5 m/s = 300 kg m/s

After the boy jumps off, the total momentum of the system is:

50 kg * v_bike

Using conservation of momentum, we can equate the two and solve for v_bike:

(50 kg + 10 kg) * 5 m/s = 50 kg * v_bike

Simplifying the equation, we get:

300 kg m/s = 50 kg * v_bike

v_bike = 6 m/s

Therefore, the velocity of the bike after the boy jumps off is 6 m/s.

4. Using the same equation as in problem 1 and plugging in the given values, we get:

(75 kg * 8 m/s) + (85 kg * -8 m/s) = (75 kg + 85 kg) * vf

Simplifying the equation, we get:

0 = 1600 kg * vf

vf = 0 m/s

Therefore, the final velocity of the two players after the collision is 0 m/s.

5. Using conservation of momentum and plugging in the given values, we can set up the equation:

(2 kg * 5 m/s) + (1 kg * 0 m/s) = (2 kg + 1 kg) * 2 m/s + (1 kg * vf)

Simplifying the equation, we get:

10 kg m/s = 5 kg * 2 m/s + vf

vf = 0 m/s

Therefore, the final velocity of the 1 kg ball after the collision is 0 m/s.

6. To solve this problem, we can use the conservation of momentum equation again:

(500 kg * 500 m/s) = (450 kg * vf_r) + (50 kg * 1000 m/s)

where vf_r is the final velocity of the rocket after releasing the satellite.

Simplifying the equation, we get:

250,000 kg m/s = 450 kg * vf_r

vf_r = 555.56 m/s

Therefore, the velocity of the rocket after releasing the satellite is 555.56 m/s.

7. Using the same conservation of momentum equation and plugging in the given values, we get:

(5 kg * 10 m/s) + (2 kg * 0 m/s) = (5 kg + 2 kg) * vf

Simplifying the equation, we get:

50 kg m/s = 7 kg * vf

vf = 7.14 m/s

Therefore, the final velocity of the 5 kg mass after the collision is 7.14 m/s.

8. Using the same conservation of momentum equation and plugging in the given values, we get:

(1 kg * 2 m/s) + (2 kg * 0 m/s) = (1 kg + 2 kg) * 1 m/s + (2 kg * vf)

Simplifying the equation, we get:

2 kg m/s = 3 kg + (2 kg * vf)

vf = -0.5 m/s

Therefore, the final velocity of the 2 kg mass after the collision is -0.5 m/s. This negative velocity indicates that the mass is moving in the opposite direction to the initial direction.

According to the solving the final velocity of the two objects after they stick together is 1.67 m/s.

The velocity of a body determines whether it is moving away from the ground or towards an object. Speed is often a scalar quantity. Velocity is a vector quantity in its most basic form. It gauges the rate of change in a distance. It relates to how quickly displacement is altering.

the objects stick together after the collision, we can use conservation of momentum to solve for the final velocity of the combined mass:

m1 * v1 + m2 * v2 = (m1 + m2) * vf

where m1 and v1 are the mass and velocity of the first object, m2 and v2 are the mass and velocity of the second object, and vf is the final velocity of the combined mass.

Substituting the given values:

(2 kg) * (5 m/s) + (3 kg) * (0 m/s) = (2 kg + 3 kg) * vf

Simplifying and solving for vf:

vf = 1.67 m/s

the final velocity of the two objects after they stick together is 1.67 m/s.

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Answer:

The frequency of a mass vibrating on a string describes the number of complete cycles of vibration that occur per unit of time, usually measured in hertz (Hz).

Explanation:

Electromagnetic induction is the process of generating an electric current by moving a conductor through a magnetic field.

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Answer:

b

Explanation:

あなたは本当に知りたいですか？私はあなたが答えを理解する方法ではなく、答えのためにここにいるという意味ですので、答えを書き留めて正しいことができますので、あなたの幸せを願っています

To answer the question we have, 1.93401 J of energy is lost when the puck travels over the uneven surface.

Energy is referred to by scientists as the capacity for work. People have figured out how to transform energy from one kind to the other before employing it to accomplish tasks, making western civilisation possible.

Hockey weighs 0.171 kg.

Starting speed: 5.65 m/s

Ultimately, the speed was 3.05 m/s.

We must determine how much kinetic energy was lost on the tough patch.

[tex]E_{d}=\frac{1}{2} v^2_{2} -v^2_1[/tex]

Where, m = mass

v₁ = Initial velocity

v₂ = Final velocity

Put the value into the formula

[tex]E_{d}=\frac{1}{2}[/tex] × 0.171 × [tex](3.05^2 - 5.65^2)[/tex]

=  1.93401 J energy is dissipated as the puck slides over the rough patch.

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Answer:

Explanation:

We can solve this problem using trigonometry. Let's draw a diagram:

          |\

          | \

          |  \   <- Sun rays

          |   \

          |    \

          |     \

          |      \

          ---------

           Pool

The angle between the sun rays and the horizontal line is 90 - 25 = 65 degrees. Let's call the depth of the pool "d". We want to find the value of "d" that makes the bottom of the pool completely shaded.

We can see that the triangle formed by the sun rays, the top edge of the pool, and the bottom edge of the shaded area is a right triangle. The angle between the sun rays and the top edge of the pool is also 65 degrees, because the top edge is parallel to the ground.

Using trigonometry, we can write:

tan(65 degrees) = d / 4.9 m

Solving for "d", we get:

d = 4.9 m * tan(65 degrees)

Using a calculator, we find:

d ≈ 13.7 m

Therefore, the pool is approximately 13.7 meters deep.

The solutions for questions A and B are

Generally, Tension is a physical force that pulls on an object, often tending to stretch it. It is typically measured in units of force per area, such as newtons per square meter (N/m2). Tension is an important concept in mechanics, physics, engineering, and other fields.

(a) T_1=m_1(g-a)

T_1=4.81 (9.8-3.94)

T_1=28.1866N

(b) In freefall

a=g

T_1=m_1(g-g)

T_1=0 N

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Answer:

20.5 m/s

Explanation:

While the three stable isotopes of Argon share the same number of protons and electrons, they differ in their atomic masses due to varying numbers of neutrons.

This means they have identical electron configurations and chemical properties. Additionally, they all have the same number of electrons, 18, which determines their chemical behavior and bonding capabilities.

However, the isotopes differ in their neutron numbers, which gives rise to their atomic masses. Argon-36 has 18 protons and 18 neutrons, Argon-38 has 18 protons and 20 neutrons, and Argon-40 has 18 protons and 22 neutrons.

This variation in neutron count leads to differences in atomic mass. Consequently, the isotopes exhibit different atomic weights, with Argon-36 having a mass of approximately 36 atomic mass units (amu), Argon-38 around 38 amu, and Argon-40 approximately 40 amu.The differing atomic masses affect the isotopes' physical properties.

For instance, the isotopes may have different boiling points, melting points, or densities due to variations in the average mass of their atoms. These subtle differences are relevant in scientific research, especially in fields like geochronology and radiometric dating, where the abundance ratios of these isotopes are utilized to determine the age of rocks and minerals.

In summary,  These differences give rise to variations in their atomic weights and physical properties.

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The kinship chart of family is given in the image attached. The kinship chart of the Kardashian-Jenner family with "Kris Jenner" as "ego":

In this kinship chart, Kris Jenner is the "ego" or the main person we are focusing on. Her children are Kourtney Kardashian (daughter) and Robert Kardashian (son). Kourtney has three children: Mason, Penelope, and Reign. Robert has four children: North, Saint, Chicago, and Psalm.

Therefore, Each arrow represents a biological relationship, and each symbol represents a gender and a generational difference. "F" stands for female, "M" stands for male, and "-" stands for unknown gender.

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We can see here that the trend of the data shows in each trial, the number of bread and cheese used drastically reduced or are used up after each reaction.

The data represents  the Law of Conservation of Mass by showing that if you add two elements you will have one product.

The Law of Conservation of Mass is a fundamental principle in chemistry, which states that the total mass of the reactants in a chemical reaction is equal to the total mass of the products.

In other words, the total mass of matter in a closed system remains constant during a chemical reaction, and no matter is created or destroyed.

The part that completes the question is seen below:

9. Conduct the SAME trials as you did above, but this time count the number of ingredients you started with and what you ended up with. You are NOT counting sandwiches, but all the individual ingredients.

Trial Number                                  1          2         3       4        5    

#of Bread Before Reaction           5         6         3      5         6

#of Cheese Before Reaction        3         4         4      2         5

#of Bread After Reaction              1          0         1       1          0

#of Cheese After Reaction           1          1          3      0         2

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The average speed of the skier is 53.3 m/min.

option C.

Average speed is a measure of how fast an object or a person travel over a certain distance in a specific amount of time.

It is calculated by dividing the total distance traveled by the time it took to travel that distance.

The formula for average speed is:

Average Speed = Total Distance Traveled / Time Taken

The average speed of the skier is calculated as follows;

Average speed = ( 160 m ) / 3 mins

Average speed = 53.3 m/min

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Answer:

To calculate the resistance of the microwave, we can use Ohm's Law, which states that:

resistance = voltage / current

Substituting the given values into this equation, we get:

resistance = 5V / 0.3A

resistance = 16.67 ohms

Therefore, the resistance of the microwave with 5V and a current of 300mA is 16.67 ohms.

yes they would balance because they have the same weight

Explanation:

hope this helps (:

Since the two children have the same weight, they have to sit at equal distances from the pivot of the seesaw.  Then they will balance.

1. Conjecture: In triangle ABC and A'B'C', all corresponding segments are parallel if the scale factor is greater than or equal to 1.

Let ABC and A'B'C' be two triangles with corresponding sides AB and A'B', BC and B'C', and AC and A'C'. Assume that the scale factor between the two triangles is greater than or equal to 1.

To prove that all corresponding segments are parallel, we need to show that the slopes of these segments are equal.

Consider segment AB and A'B'. Let (x₁, y₁) and (x₂, y₂) be the coordinates of points A and B, and (x₁', y₁') and (x₂', y₂') be the coordinates of points A' and B', respectively. Then, the slope of segment AB is (y₂ - y₁)/(x₂ - x₁), and the slope of segment A'B' is (y₂' - y₁')/(x₂' - x₁').

Since the scale factor is greater than or equal to 1, we have |AB| <= |A'B'|, |BC| <= |B'C'|, and |AC| <= |A'C'|.

Without loss of generality, assume that |AB| <= |A'B'|. Then, we have:

|x₂ - x₁| <= |x₂' - x₁'|, and |y₂ - y₁| <= |y₂' - y₁'|.

Thus, we can conclude that (y₂ - y₁)/(x₂ - x₁) = (y₂' - y₁')/(x₂' - x₁'), which implies that segment AB is parallel to segment A'B'.

Similarly, we can prove that segment BC is parallel to segment B'C' and segment AC is parallel to segment A'C'.

Therefore, we have shown that all corresponding segments are parallel when the scale factor is greater than or equal to 1.

3. If the scale factor is less than one, the proof would need to be modified. In this case, we would have |AB| >= |A'B'|, |BC| >= |B'C'|, and |AC| >= |A'C'|. As a result, we would need to adjust the inequality signs in the proof accordingly. Specifically, we would need to reverse the signs of the inequalities involving the absolute values of the differences between the x and y coordinates of the points in each pair of corresponding segments.

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The interia is varied and it depends on the mass, itt will be sameshape and size so it will be light closer.

What is volume ?

Space is occupied by every three-dimensional object. Its volume serves as a gauge for this area. The area contained by an object's limits in three-dimensional space is referred to as its volume. Another name for it is an object's capacity.

What is element ?

The atoms make the element. The atoms are created up of the element; it is a pure substance it can't be able to split up. The element is created up of a single kind of atom. Atoms are the main thing for the creation of elements. Elements are classified according to their performance and physical properties. Elements are placed based on the performance in the Mendeleev periodic table.

Therefore, The interia is varied and it depends on the mass, itt will be sameshape and size so it will be light closer.

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(a)The rifle exerts a force of 628 N on the bullet while it is in the barrel.

(b) (i)  There is no friction between the bullet and the barrel, there is no force of friction to consider.

    (ii) Just after it has left the barrel, the only force acting on the bullet would be the force of gravity pulling it downward.

(c) The rifle gives the bullet an acceleration of about 24885 g's.

(d) the bullet is in the barrel for 0.030 s.

What is Force?

Force is a physical quantity that describes the interaction between two objects, causing a change in motion. Specifically, it is an influence that can cause an object to accelerate, change direction, or deform. Force is defined as the product of mass and acceleration, according to Newton's second law of motion. Mathematically, force can be represented by the equation:

                              F = m*a

(a) To determine the force that the rifle exerts on the bullet while it is in the barrel, we need to use the equation for the work done by a constant force:

                                   W = Fd

where W is the work done, F is the force, and d is the distance over which the force is applied. We can rearrange this equation to solve for the force:

F = W/d

We know that the work done on the bullet is equal to the change in kinetic energy:

W = ΔK = (1/2)mv^2

where m is the mass of the bullet and v is its velocity. Plugging in the given values, we get:

W = (1/2)(0.00420 kg)(370 m/s)^2 = 283 J

The distance over which the force is applied is given as 45.0 cm = 0.45 m. So the force exerted by the rifle on the bullet is:

F = W/d = 283 J / 0.45 m = 628 N

Therefore, the rifle exerts a force of 628 N on the bullet while it is in the barrel.

(b) (i) The free-body diagram of the bullet while it is in the barrel would show two forces acting on it: the force of the rifle pushing it forward, and the force of gravity pulling it downward. Since there is no friction between the bullet and the barrel, there is no force of friction to consider.

(ii) Just after it has left the barrel, the only force acting on the bullet would be the force of gravity pulling it downward.

(c) We can calculate the acceleration of the bullet using the formula:

a = Δv/t

where Δv is the change in velocity and t is the time for which the acceleration occurs. We know that the initial velocity of the bullet is 370 m/s and that it starts from rest, so the change in velocity is:

Δv = 370 m/s

The distance over which the acceleration occurs is given as 45.0 cm = 0.45 m. Using the formula for distance traveled with constant acceleration, we can find the time for which the acceleration occurs:

d = (1/2)at^2

0.45 m = (1/2)a(t^2)

Solving for t, we get:

t = sqrt(0.9/a)

Plugging this into the equation for acceleration, we get:

a = Δv/t = 370 m/s / sqrt(0.9/a)

Solving for a, we get:

a = 2.44 x 10^5 m/s^2

To express this acceleration in units of g's, we can divide by the acceleration due to gravity:

a/g = 2.44 x 10^5 m/s^2 / 9.81 m/s^2 = 24885

Therefore, the rifle gives the bullet an acceleration of about 24885 g's.

(d) Using the same formula as before for distance traveled with constant acceleration, we can solve for the time the bullet is in the barrel:

d = (1/2)at^2

0.45 m = (1/2)(2.44 x 10^5 m/s^2)t^2

Solving for t, we get:

t = [tex]\sqrt{(0.00092)}[/tex]s = 0.030 s

Therefore, the bullet is in the barrel for 0.030 s.

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The bullet is in the barrel for 7.05 x 10^-5 seconds. Acceleration can also be caused by changes in direction, such as when an object moves in a circular path.

What is Acceleration?

Acceleration is a fundamental concept in physics and plays an important role in understanding the motion of objects. It is used to describe the behavior of objects in a wide range of applications, from simple everyday situations such as cars accelerating and braking, to more complex phenomena such as the acceleration of particles in particle accelerators or the acceleration of celestial bodies in space.

(a) To find the force exerted by the rifle on the bullet, we can use the kinematic equation:

v^2 = u^2 + 2as

where v is the final velocity (muzzle velocity), u is the initial velocity (0 m/s), a is the acceleration, and s is the distance traveled (45.0 cm = 0.45 m).

Rearranging this equation to solve for acceleration:

a = (v^2 - u^2) / 2s

Plugging in the given values:

a = (1200 m/s)^2 / (2 x 0.45 m) = 3.20 x 10^6 m/s^2

The force exerted by the rifle on the bullet can be found using Newton's second law:

F = ma

where F is the force, m is the mass of the bullet (4.20 g = 0.00420 kg), and a is the acceleration we just calculated:

F = 0.00420 kg x 3.20 x 10^6 m/s^2 = 13,440 N

Therefore, the rifle exerts a force of 13,440 N on the bullet while it is in the barrel.

(b)

(i) Free-body diagram of the bullet while it is in the barrel:

The only force acting on the bullet while it is in the barrel is the force exerted by the rifle, which is directed to the right.

  |

  |

-->|  F

  |

  |

Once the bullet has left the barrel, it is subject to air resistance, which we will assume acts in the opposite direction to the velocity of the bullet. The force of gravity on the bullet is negligible for this problem.

  |

  |

<--|  F_air

  |

  |

(c) The acceleration given to the bullet can be expressed in terms of g's by dividing by the acceleration due to gravity, g:

a_g = a / g = (3.20 x 10^6 m/s^2) / 9.81 m/s^2 = 326,000 g's

Therefore, the rifle gives the bullet an acceleration of 326,000 g's.

(d) The time the bullet is in the barrel can be found using the kinematic equation:

s = ut + (1/2)at^2

where s is the distance traveled (0.45 m), u is the initial velocity (0 m/s), a is the acceleration we calculated earlier (3.20 x 10^6 m/s^2), and t is the time the bullet is in the barrel (which we want to find).

Rearranging and solving for t:

t = sqrt(2s/a) = sqrt(2 x 0.45 m / 3.20 x 10^6 m/s^2) = 7.05 x 10^-5 s

Therefore, the bullet is in the barrel for 7.05 x 10^-5 seconds.

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(a) Frequency of the tuning fork is 686 Hz.

(b) Minimum value to hear a resonance is 0.25 m.

(c) The next level above 0.625 to hear a resonance is 0.875 m.

Resonance frequency is defined as the natural frequency at which the medium vibrates with maximum amplitude.

Here,

(a) Velocity of sound, v = 343 m/s

    Distance, L₁ = 0.375 m

                L₂ = 0.625 m

     From the equation,

    ΔL = 1/2 λ

    λ = 2ΔL = 2(0.625 - 0.375)

    λ = 0.5 m

  Therefore,

  frequency, f = v/λ

  f = 343/0.5

  f = 686 Hz

(b) Minimum value to hear a resonance = λ/2 = 0.25 m

(c) Next level above 0.625 to hear resonance,

L₃ = 0.625 + λ/2 = 0.625 +(0.5/2)

L₃ = 0.875 m

Hence,

(a) Frequency of the tuning fork is 686 Hz.

(b) Minimum value to hear a resonance is 0.25 m.

(c) The next level above 0.625 to hear a resonance is 0.875 m.

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Answer:

In water, the particles are much closer together, and they can quickly transmit vibration energy from one particle to the next. This means that the sound wave travels over four times faster than it would in air, but it takes a lot of energy to start the vibration.

Explanation:

Answer:

slower as it is more dense in water

Explanation:

Answer:

To calculate the work being done, we need to use the formula:

work = force x distance x cos(theta)

where force is in newtons, distance is in meters, and theta is the angle between the direction of the force and the direction of the movement.

In this case, the force is the weight of the leaf blower, which is 1600 N, the distance is 6 meters, and the angle between the force and the movement is 0 degrees (since Kyle is lifting the leaf blower straight up). So we have:

work = 1600 N x 6 m x cos(0°)

work = 9600 J

Therefore, the joules of work being put out by Kyle are 9600 J.

Explanation:

Newton’s second law says that when an unbalanced force is applied to a mass, it causes it to accelerate.

What is Newton's law?

Newton's laws are a set of three fundamental principles that describe the behavior of objects in motion, developed by the physicist Sir Isaac Newton in the late 17th century. The laws are as follows:

The first law, also known as the law of inertia, states that an object at rest will remain at rest, and an object in motion will remain in motion with a constant velocity, unless acted upon by an external force.

The second law, also known as the law of acceleration, states that the acceleration of an object is directly proportional to the net force applied to it, and inversely proportional to its mass. This can be expressed mathematically as F = ma, where F is the net force applied, m is the mass of the object, and a is the resulting acceleration.

The third law, also known as the law of action-reaction, states that for every action, there is an equal and opposite reaction. This means that when one object exerts a force on another object, the second object exerts an equal and opposite force back on the first object.

Together, these laws provide a framework for understanding the behavior of objects in motion, and have been applied in countless areas of science and engineering.

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Answer:

Look down below

Explanation:

300Hz is the 5th harmonic in a 60 Hz system, or the 6th harmonic in a 50 Hz system.