Answer:
52,000 kJ
Explanation:
The combustion reaction is the following:
2 C₂H₆(g) + 7 O₂(g) → 4CO₂(g) + 6H₂O(l) ΔHm= –3120 kJ
From the chemical reaction and the value of ΔH we can see that 2 moles of ethane gas (C₂H₆(g)) release 3120 kJ of heat energy. So, we have the conversion factor: 3120 kJ/2 moles C₂H₆.
To calculate how many kJ are released from the combustion of 1 kg of ethane, we have to first convert the mass to moles by using the molecular weight (MW) of ethane (C₂H₆):
MW(C₂H₆) = (12 g/mol x 2 C) + (1 g/mol x 6 H) = 30 g/mol
mass = 1 kg x 1000 g/1 kg = 1000 g
moles of C₂H₆= mass/MW = 1000 g/(30 g/mol) = 33.3 mol C₂H₆
Finally, we multiply the conversion factor by the number of moles of C₂H₆ in 1 kg:
heat energy released = 33.3 mol C₂H₆ x 3120 kJ/2 moles C₂H₆ = 52,000 kJ
Therefore, 51,000 kJ are released when 1 kg of ethane is burned.
What is the hydroxide [OH-] concentration of a solution that has a pOH of 4.90? 14 14 1.26 x10-5 1.26 x10, -5 9.1 9.1 7.94 x 104
Answer:
The hydroxide [OH-] concentration of the solution is 1.26*10⁻⁵ M.
Explanation:
The pOH (or potential OH) is a measure of the basicity or alkalinity of a solution.
POH indicates the concentration of hydroxyl ions [OH-] present in a solution and is defined as the negative logarithm of the activity of hydroxide ions (that is, the concentration of OH- ions):
pOH= -log [OH-]
A solution has a pOH of 4.90. Replacing in the definition of pOH:
4.90= -log [OH-]
Solving:
-4.90= log [OH-]
1.26*10⁻⁵ M= [OH-]
The hydroxide [OH-] concentration of the solution is 1.26*10⁻⁵ M.
What is the energy of each of the following photons in kilojoules per mole? Express the energy in kilojoules per mole to three significant digits.
Part A: ν=5.95×1019s−1
Part B: ν=20.00×103s−1
Part C: λ=2.57×102m
The energy of a photon can be calculated using the formula: E = hν = hc/λ, where E is the energy, h is Planck's constant (6.626 x 10^-34 Js), ν is the frequency, c is the speed of light (2.998 x 10^8 m/s), and λ is the wavelength which is 6.53 x 10^-38 kJ/mol
Part A: ν = 5.95 x 10^19 s^-1
E = hν = (6.626 x 10^-34 Js) x (5.95 x 10^19 s^-1) = 3.948 x 10^-14 J/photon
To convert to kilojoules per mole, we need to divide by Avogadro's number (6.022 x 10^23 photons/mol)E = (3.948 x 10^-14 J/photon) / (6.022 x 10^23 photons/mol) = 6.53 x 10^-38 kJ/mol
Part B: ν = 20.00 x 10^3 s^-1
E = hν = (6.626 x 10^-34 Js) x (20.00 x 10^3 s^-1) = 1.325 x 10^-31 J/photon
To convert to kilojoules per mole, we need to divide by Avogadro's number (6.022 x 10^23 photons/mol). E = (1.325 x 10^-31 J/photon) / (6.022 x 10^23 photons/mol) = 2.20 x 10^-55 kJ/mol. Part C: λ = 2.57 x 10^2 m. E = hc/λ = (6.626 x 10^-34 Js) x (2.998 x 10^8 m/s) / (2.57 x 10^2 m) = 3.948 x 10^-14 J/photon. To convert to kilojoules per mole, we need to divide by Avogadro's number (6.022 x 10^23 photons/mol) .E = (3.948 x 10^-14 J/photon) / (6.022 x 10^23 photons/mol) = 6.53 x 10^-38 kJ/mol. In all the parts, the energy is expressed in kilojoules per mole to three significant digits.
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Coca-Cola is making a version of Coke that uses sucrose (C12H22O11) instead of high fructose corn syrup. If there are 39.24 grams of sucrose in a 12.0 fluid oz. can of this Coke, what is the molarity of sucrose in the Coke
Coca-Cola is making a version of Coke that uses sucrose (C12H22O11) instead of high fructose corn syrup. The molarity of sucrose in the Coke is 0.32 mol/L.
Coca-Cola is making a version of Coke that uses sucrose (C12H22O11) instead of high fructose corn syrup. If there are 39.24 grams of sucrose in a 12.0 fluid oz. can of this Coke, what is the molarity of sucrose in the Coke.
To find the molarity of sucrose in the Coke, we first need to find the number of moles of sucrose present in the can. We can use the mass of sucrose (39.24 g) and the molar mass of sucrose (342.3 g/mol) to find the number of moles of sucrose:
= (39.24 g) / (342.3 g/mol)
= 0.114 mol
Next, we need to find the volume of the can in liters. We can convert the volume in fluid oz. to liters using the conversion factor 1 fluid oz.
= 0.0295735 L:
= (12.0 fluid oz.) x (0.0295735 L/fluid oz.)
= 0.354882 L
Finally, we can use the formula for molarity (moles of solute / liters of solution) to find the molarity of sucrose in the Coke:
= molarity
= (0.114 mol) / (0.354882 L)
= 0.32 mol/L
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Help please help me
Answer:
Strong acids are defined by their pKa. The acid must be stronger in aqueous solution than a hydronium ion, so its pKa must be lower than that of a hydronium ion. Therefore, strong acids have a pKa of <-174. Strong acids can be organic or inorganic.
Explanation:
Bond Strength
Strong acids have mostly ions in solution, therefore the bonds holding H and A together must be weak. Strong acids easily break apart into ions. Weak acids exist mostly as molecules with only a few ions in solution, therefore the bonds holding H and A together must be strong.
i think it will help you
At 125 C the pressure of a sample of oxygen (O2) is 2.25 atm. What will the
pressure be at 25°C in closed (constant volume) container?
Answer:
1.68 atm
Explanation:
Applying
P/T = P'/T'................... Equation 1
Where P = Initial pressure, T = Initial Temperature, P' = Final pressure, T' = Final Temperature.
Make P' The subject of the equation
P' = PT'/T.............. Equation 2
From the question,
Given: P = 2.25 atm, T = 125°C = (125+273) K = 398 K, T' = 25°C = (25+273) K = 298 K.
Substitute these values into equation 2
P' = (2.25×298)/398
P' = 1.68 atm
Shown below is the phase diagram for a typical liquid mixture of two components, A and B. a What is the significance of the horizontal line between points X and Y? O The length of the line XY corresponds to the difference in boiling point of components A and B. O A boiling liquid with composition X will produce vapor with composition Y. O The point X gives the vapor composition of the less volatile component and Y gives the vapor composition of the more volatile component. The line gives the difference. O A boiling liquid with composition Y will produce a vapor with composition X. b Using the phase diagram, determine the molar composition of the vapor in equilibrium with a boiling liquid that has a composition of 40% A and 60.% B. Percentage vapor composition A= 10 % Percentage vapor composition B 90 % What is the boiling point of this liquid? Boiling point 100 °C
The line between points X and Y represents the difference in boiling points of components A and B. A boiling liquid with a composition of 40% A and 60% B will produce a vapor with a composition of 10% A and 90% B, and have a boiling point of 100°C.
The significance of the horizontal line between points X and Y on the phase diagram is that it represents the difference in boiling points of components A and B. This line indicates the point at which the vapor and liquid phases are in equilibrium. On the diagram, point X gives the vapor composition of the less volatile component, while point Y gives the vapor composition of the more volatile component.
By looking at the phase diagram, we can determine the molar composition of the vapor in equilibrium with a boiling liquid that has a composition of 40% A and 60% B. The vapor composition of the less volatile component (X) is 10%, while the vapor composition of the more volatile component (Y) is 90%. The boiling point of this liquid is 100°C.
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At one sewage treatment plant, bacteria cultures produce 1000 L of methane gas per day at 1.0 atm pressure. What volume tank (V2) would be needed to store one day's amount of gas at a pressure of 5.0 atm?
At a pressure of 5.0 atm, IS 200 L of gas would need to be stored in the volume tank (V2).
How to find the volume?The mass of a body can be calculated from its volume using density, and vice versa. The mass is equal to the volume multiplied by the density (M = Vd), whereas the volume is equal to the mass divided by the density (V = M/d). Use a laboratory scale to weigh the masses, or use the density formula D = m/V to convert the solvent volume to mass. Find your ultimate volume by multiplying the solute and solvent masses.Volume, which is measured in cubic units, is the area in three dimensions that matter occupies or that is encircled by a surface. Cubic metres (m3), a derived measure, are used as the SI unit of volume.To learn more about volume, refer to:
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how many grams of KNO3 that should be placed in the airbag to fully react with the Na.
10 Na + 2KNO: > 1K20 + 5Naz0 + 1 N2 (g)
NaN3→ Na + 32N2 1 mole of sodium azide gives 32 moles of N2
How much nitrogen is in an airbag?
37 gallons
The amount of nitrogen gas produced by a handful (130 grammes) of sodium azide is 67 litres, which is sufficient to inflate a typical air bag. An air bag can be inflated in as little as 0.03 SECOND. There is another chemistry at play.
Even though we don't typically link chemistry with cars, a lot of chemistry happens in a functioning car, such as the chemical processes that take place in the battery to produce electricity and the burning of gasoline to power the engine. Another reaction includes the air bag, which is one that most drivers would much rather not experience firsthand.
Instead of using compressed gas, air bags are inflated using the byproducts of a chemical reaction. Sodium azide, often known as NaN3, is the principal chemical involved in the air bag reaction
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which of the following compounds contains the Iron (III) ion?
A) FeN
B)FeS
C)FeCl2
D)FeS
Answer:
(A)
Explanation:
All the Fe ions in the other choices have +2 valences. Since the N ion has a -3 valence, the compound FeN can only be formed if Fe has a +3 valence.
Learning Task 3: Why can a car run faster on a smooth
rood than on a rough roade (5points).
Answer:
it is easy to push a car on smooth road than on a rough road because friction is less in smooth road than on rough roads.
Answer:
Why can a car run faster on a smooth
rood than on a rough road it is because friction is less in smooth roads than in rough road....
Explanation:
hope it helps..stay safe!
How does the urinary system maintain homeostasis?
Answer:
here is ur ans Lilly
Explanation:
In addition to maintaining fluid homeostasis in the body, the urinary system controls red blood cell production by secreting the hormone erythropoietin. The urinary system also plays a role in maintaining normal blood pressure by secreting the enzyme renin.hope it's helpful for you mark brainlest where you from , age
What is the relative rate of diffusion of CH4 and NO2?
The ratio of effusion rates of Sulphur dioxide and methane is 0.5
To calculate the rate of diffusion of gas, we use Graham's Law.
This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:
Rate of Diffusion ∝ 1 ÷ √molar mass of the gas
We are given:
Molar mass of Sulphur dioxide = 64.066 g/mol
Molar mass of methane = 16.04 g/mol
By taking their ratio, we get:
Rate of SO₂ ÷ Rate of CH₄ = √MCH₄ ÷ √MSO₂
Rate of SO₂ ÷ Rate of CH₄ = √16.04 ÷ √64.066
Rate of SO₂ ÷ Rate of CH₄ = 0.5
Hence, the ratio of rate of effusion of Sulphur dioxide and methane will be 0.5
What reagent causes the observed visual change in a positive Lucas test?
The observed visual change from a clear and colourless characteristic to a turbid, cloudy, and hazy characteristic, in a positive Lucas test, is caused by the Lucas reagent.
The Lucas Test is used to detect the presence of a primary alcohol.
When the test is positive, the mixture of the primary alcohol with the Lucas reagent changes from a clear and colourless characteristic to a turbid, cloudy, and hazy characteristic. This visual change is due to the reaction of the primary alcohol with the Lucas reagent which is a mixture of concentrated hydrochloric acid and zinc chloride.
The Lucas Test is used to detect the presence of a primary alcohol, and when a positive result is obtained, the reaction of the primary alcohol with the Lucas reagent, a mixture of hydrochloric acid and zinc chloride, causes the visual change from a clear and colourless characteristic to a turbid, cloudy, and hazy one.
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la actual definición de un elemento es
Answer:
La definición de un elemento es una parte o aspecto de algo abstracto, especialmente uno que es esencial o característico.
1. isostasy subduction 2. deepest ocean depths fjord 3. drowned glaciated valley plate tectonics 4. theory of crustal structure trench 5. oceanic plate going down buoyancy
The isostasy is relates to the buoyancy , the deepest oceans depths relates to the trench, the theory of the crustal structure relates to the plate tectonics.
The match the following for the given options are given below as follows :
1 ) isostasy buoyancy
2) deepest ocean depths trench
3) drowned glaciated valley fjord
4) theory of crustal structure tectonic plates
5) oceanic plate going down subduction
The above are the correct order for the given following relations. these given options are related to the earth movement. like isostasy is the rising or the settling of the part of the earth's lithosphere.
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What are the possible stress or disturbances for chemical reactions
How many bonds could each of the following chelating ligands form with a metal ion?
a. acetylacetone(acacH)
b. dirthylenetriamine
c. Salen
d. porphine
a. Acetylacetone(acacH) can form up to 4 bonds with a metal ion.
b. Dirthylenetriamine can form up to 4 bonds with a metal ion.
c. Salen can form up to 6 bonds with a metal ion.
d. Porphine can form up to 8 bonds with a metal ion.
A 16. 81 gram sample of an organic compound containing C, H and O is analyzed by combustion analysis and 21. 33 grams of CO2 and 5. 822 grams of H2O are produced. In a separate experiment, the molar mass is found to be 104. 1 g/mol. Determine the empirical formula and the molecular formula of the organic compound
A 16. 81 gram sample of an organic compound containing C, H and O is analyzed by combustion analysis and 21. 33 grams of CO₂ and 5. 822 grams of H₂O are produced. In a separate experiment, the molar mass is found to be 104. 1 g/mol. The empirical formula is CH₃ and molecular formula is C₇H₇O₂₁
The empirical formula can be calculate as follows:
The reaction can be write
CxHyOz → CO₂ + H₂O
As a result, we may state that there are two O-atoms for every one C-atom (12g) in CO2 (32g).
This indicates that the ratio is 12g C/32g O.
The molar mass of CO₂ is 44 g/mole.
(12/44) x 33 = 9 g
There are 9 grams of carbon in every 33 grams of CO₂
The same can be done for water:
In H₂O, each element is represented by two H atoms and one O atom. 2 g H and 16 g O.
[2 g H / 18 g H2O] are present in 5. 822 g of water
(2/18)x 5.822= 0.6468 g
The initial sample had 14.16 g of sample, 9 g of C, and 0.6468 g of H, which resulted in 34.3532g of oxygen.
Determine the amount of moles.
C: 9.0 g / 12.0 g/mol = 0.75 mol
H: 0.6468 g / 1.0 g/mol = 0.6468 mol
O: 34.3532g / 16.0 g/mol = 2.14 mol
Then we divide by the smallest number
C: 0.75 mol / 0.6468 mol = 1
H: 0.6468 mol / 0.6468 mol= 1
O: 2.14 mol/ 0.6468 mol = 3
so the empirical formula will be CH₃
Determine the molecular formula
mass molecular formula / mass of empirical formula = n
We have to multiply the empirical formula by n to get the molecular formula.
104.1 /15 = 7= n
This means the molecular formula = C₇H₇O₂₁
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15.0 L of an ideal gas at 298 K and 3.36 bar are heated to 350 K with a new pressure of 4.90 atm. What is the new volume in litres
The new volume in litres is 13.29 L.
Given,
Temperature 1 (T₁) = 298 K
Volume 1 (V₁) = 15 L
Temperature 2 (T₂) = 383 K
Pressure 1 (P₁) = 3.36 atm
Pressure 2 (P₂) = 4. atm
By Ideal Gas Equation,
P₁V₁/T₁ = P₂V₂/T₂
⇒ (3.36*15)/298 = (4.90*V₂)/383
⇒50.4/298 = 4.90V₂/383
⇒ (50.4*383) / (298*4.90) = V₂
⇒ 19303.2/1460.2 = V₂
⇒13.29 L = V₂
New Volume will be 13.29 L.
Ideal gas law is a precise approximation of the behavioral of several gases under various situations in thermodynamics. The Ideal Gas Equation is a mathematical formula that combines empirical laws such as Charle's law, Boyle's law, Gay-law, Lussac's and Avogadro's law.
The equation characterizing the states of hypothetical gases stated mathematically by combinations of empirical or physical constants is known as the Ideal Gas Equation. It's also known as the universal gas equation. It is defined as follows:
"The ideal gas law seems to be the equation of state for a fictitious perfect gas. It is a decent approximation of the behavioral of various gases under numerous situations, while it has significant limitations".
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spectroscopy
There is something strange about Star 3’s spectrum.
Explain what this is called and what it means about this star.
Which example is the site of reduction when the dry cell is operating
Answer:
A battery contains electrochemical cells that can store chemical energy to be converted to electrical energy. A dry-cell battery stores energy in an immobilized electrolyte paste, which minimizes the need for water. Common examples of dry-cell batteries include zinc-carbon batteries and alkaline batteries.
Explanation: i hope this helps sorry if it didnt
Answer:
Your answer would Graphite Rod I got this correct on my quiz
that is of course if you had the multiple choice answer like how I did on my quiz.
Sorry if its late, Hope this helps!
What are memory B cells and memory T cell
Answer: Memory B and memory T cells are types of lymphocytes.
Explanation:
Memory B cells forms the part of adaptive immune system. These cells develop inside the germinal centers of the secondary lymphoid organs. These cells circulate in the blood. These are produced by the bone marrow and can be found in tonsil and spleen. Memory B cells are responsible for recognizing previous infections with a foreign antigen and prepare antibody against the new infection. Memory T cells recognize the antigen lived in the body for longer and produce quick response against it on second exposure. These are one of the types of T lymphocytes.
A bank robber i driving north on Catchem Lane at 90 mph to avoid be arreted. Peed
velocity
acceleration
The robber is driving at a constant velocity of 90 mph and is not accelerating/decelerating, which means their acceleration is 0 mph/sec.
What is velocity?A vector quantity that has magnitude and direction is velocity. In time, it is the rate at which the displacement changes. You can calculate speed using the formula speed = distance/time. This is a way of measuring how fast something is moving in a particular direction. Acceleration, or the rate at which an object's velocity changes, is closely related to velocity. As a vector quantity, velocity has both direction and magnitude. To maintain constant velocity, the object must be moving in the same direction at a constant velocity.
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The complete question is as follows:
A bank robber is driving north on Catchem Lane at 90 mph to avoid be arrested. Calculate:
Speed
Velocity
Acceleration
Explain why estuaries, salt marshes, and mangrove forests have more variation in salinity than other marine habitats like the ocean and sea floor.
completely saturated with salt to freshwater. ... Salt marshes, estuaries, and mangrove forests are each unique ecosystems in ... These areas often serve as nursing grounds where young marine life is ... Several reptiles reside in the salt marsh habitat,
2. How many grams would be in a 2.75 mole sample of carbon (C)?
a. 0.2299
b. 4.379
c. 33.0 g
d. 1.66x10279
Answer:
b is your answer
Explanation:
A flask contains a mixture of N2 and O2 at STP. If the partial pressure of N2 is 40 kPa, what's the mole fraction o
A flask contains a mixture of N₂ and O₂ at STP. If the partial pressure of N₂ is 40 kPa, the partial pressure of O₂ is 61.325 kPa.
STP is the abbreviation which is used for a Standard Temperature and Pressure. The standard temperature is 273 K as well as the standard pressure is 1 atm pressure.
1 atm = 101.325 kPa
According to Dalton's law, state's that the sum of the individual pressures exerted by the gases in a mixture is the total pressure.
[tex]P_{total}[/tex]= [tex]P_{A}[/tex] + [tex]P_{B}[/tex]
Therefore, [tex]P_{total}[/tex]= [tex]p_{n2}[/tex] + [tex]P_{O2}[/tex]
[tex]P_{N2}[/tex] = 40kPa
[tex]P_{total}[/tex] = 101.325kPa
101.325kPa = 40kpa + [tex]P_{O2}[/tex]
[tex]P_{O2}[/tex] = 61.325kpa
--The given question is incorrect, the correct question is
--"A flask contains a mixture of N₂ and O₂ at STP. If the partial pressure exerted by the N₂ is 40.0 kPa, the partial pressure of O₂ is?"--
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Use information from the reaction to design an experiment that could be used to remove the tarnish (Ag2S) from a silver fork
Line a basin with foil, add a teaspoon of bicarbonate of soda and a sprinkle of salt, and then pour in hot water. The tarnished silver object may then be immersed in water, ensuring sure it comes into touch with the aluminum foil, as well as the silver sulphide tarnish will quickly dissipate.
Tarnish is caused by a chemical interaction between silver and sulfur-containing compounds in the air. Silver sulphide is formed when silver combines with sulphur. Silver sulphide is a dark substance. A thin layer of silver sulphide grows on the surface of silver, darkening it.
Experimental design is a technique that enables scientists and engineers to efficiently assess the effect of multiple inputs, or factors, on measures of performance, or responses. A bone density research, for example, contains three experimental groups: a control group, the stretching exercise group, as well as a jumping exercise group. In a between-subjects experiment, investigators allocate each participant to one of three groups at random. While silver is the most commonly linked with tarnishing, it may occur on almost every metal, including aluminum, copper, and brass.
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can someone label these?
1. Label
A. sediment
B. weathering & erosion
C. sedimentary rock
D. Igneous rock
E. Melting
2. label
A. Sediment
B.weathering & erosion
C. Sedimentary rock
D. Igneous rock
E. Melting
3. Label
A. Sediment
B.weathering & erosion
C. Sedimentary rock
D. Igneous rock
E. Melting
4. Label
A. Weathering & erosion
B. Sedimentary rock
C. Igneous rock
D.Melting
E. Heat &pressure
5. Label
A. Weathering & erosion
B. Sedimentary rock
C. Igneous rock
D.Melting
E. Heat &pressure
6. Label
A. Weathering & erosion
B. Sedimentary rock
C. Igneous rock
D.Melting
E. Heat &pressure
Counting Atoms in Chemical Equations Nitrogen gas reacts with hydrogen to produce ammonia. Use the chemical equation to complete the statements. N2 + 3H2 → 2NH3
Answer:
There are 2 nitrogen atoms on the product side.
There are 6 hydrogen atoms on the reactant side.
Explanation:
Answer:
There are 2 nitrogen atoms on the product side.
There are 6 hydrogen atoms on the reactant side.
Explanation:
As seen in the picture below,
changing the subscripts of chemicals can mathematically balance the equation. why is it unacceptablle
To balance a chemical equation, you can only adjust the coefficients; you cannot change the subscripts. The ratios of the atoms in the molecule and the resulting chemical characteristics are altered by changing subscripts.
What occurs if the subscript in a chemical equation is changed?Changing the coefficients solely affects the quantity of molecules in that specific chemical. However, modifying the subscripts will change the substance itself, rendering your chemical equation incorrect.
What distinguishes altering a subscript from altering a coefficient in a chemical formula?You can determine the substance from the subscript. You can find out how much of each element is present in the molecule. The substance itself would change if it were altered. In contrast, simply altering the coefficient results in a change in the number of molecules.
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