How much force is required to accelerate an 8kg mass at 5m/s^2 if there is 14N of friction

Answer: I think it’s C but I’m not completely sure about it please correct me if I’m wrong

Answer: A The energy and intensity of X-rays can be controlled.|

Explanation:

Answer:

DC (direct current) is the unidirectional flow or movement of electric charge carriers (which are usually electrons). The intensity of the current can vary with time, but the general direction of movement stays the same at all times.

Direct current is produced by rectifiers, batteries, generators with commutators, and fuel cells. For example, the current flowing in appliances running on batteries or in a flashlight is a direct current.

Answer:

15000kgm/s

Explanation:

Given parameters:

Speed of the car  = 12m/s

Mass of car and passengers = 1250Kg

Unknown:

Momentum of the car  = ?

Solution:

Momentum is the quantity of motion a body posses;

  Momentum  = mass x velocity

Now insert the given parameters and solve;

  Momentum  = 12 x 1250  = 15000kgm/s

Answer:

2N

Explanation:

Given parameters:

Mass of the balloon = 1kg

Acceleration  = 2m/s²

Unknown:

Applied force = ?

Solution

According to Newton's second law of motion:

 Force   =  mass x acceleration

 Now insert the given parameters and solve;

   Force  = 1 x 2  = 2N

The ratio of the wavelength in air of the sound emitted by this vibrating string and the wavelength of the wave on the string is 2:1.

f = n/2L(√T/μ)

where;

μ = 0.0048 kg / 2 m = 0.0024 kg/m

f = 2/(2 x 2) (√48/0.0024)

f = (¹/₂)(√20,000)

f = (¹/₂)(141.42)

f = 70.71 Hz

v = √T/μ

v = (√48/0.0024)

v = 141.42 m/s

λ = v/f

λ = (141.42) / (70.71)

λ = 2 m

Speed of sound in air, v = 332 m/s

λ = v/f

λ = 332 / 70.71

λ = 4.7 m

Ratio of the wavelengths = 4.7 m / 2m = 2.3/1 ≈ 2 : 1

Thus, the ratio of the wavelength in air of the sound emitted by this vibrating string and the wavelength of the wave on the string is 2:1.

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Answer:

can you be more espisific

Explanation:

Answer:

a chemical change is a substance change in to a new substance

Explanation:

Answer:

Radiation

Explanation:

The form of heat that does not require matter or particles to happen is known as radiation.

the length of the cube's side in inches is 4.96 inches  

Density- It is a measurement of that how material is packed together tightly.

Its formula is ρ= m/v

where ρ is the density of material

m is the mass

v is the volume  

here we have to find the length of cube's side

a cube of silver has a mass = 21 kg. = 21×10³ [∵1kg = 1000g ]

density of silver = 10.49g/cm³

the length of the cube's side = ?

density is given by

ρ= m/v

to find the volume we rearrange the above equation

v=m/ρ

volume of a cube = (length)³ = l³

using values we get

l³ = 21×10³ /10.49 ≈ 2×10³ cm³

l =∛(2×10³)cm³

l = 1.26 ×10 = 12.6 cm

l = 4.96 inches                                       [∵ 1 cm = 0.394 inch ]

the length of the cube's side in inches is 4.96 inches  

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you may check it online

Answer:

it most likly right I'm not 100% sure

Answer:

a) 5.714 m/s²

b) 13.33 m/s²

Explanation:

, [tex]\text{The final velocity, }\text{\ensuremath{v_{f}}}\text{ of the car is }\text{\ensuremath{\dfrac{\Delta v}{\Delta t}=}}\dfrac{{180m}}{9.0s}=20\;m/s[/tex]

The car goes from an initial velocity of 0 m/s  to this final velocity in t=3.5s

Therefore the acceleration of the car is given by
[tex]\displaystyle a=\boldsymbol{\dfrac{{v}_{f}-{v}_{0}}{t}}[/tex]

where [tex]v_0[/tex] is the initial velocity

[tex]a=\dfrac{20-0}{3.5}=\dfrac{20}{3.5}=5.714\mathrm{m/s^{2}}\[/tex]

Part a
[tex]\text{Maximum\;Acceleration}}}=5.714 \;m/s^{2}[/tex]

Part b)

If the car accelerated from rest and reached final speed of 20 m/s in 1.5s instead of 3.5s then

[tex]a=\dfrac{\boldsymbol{20}}{\boldsymbol{1.5}}={\displaystyle \textbf{13.33}\;m/s^{2}}[/tex]

Answer:

The potential energy of the diver at the top is equal to the net work needed to be done to stop the diver.

PE = W

mg(h+d) = Fd

Explanation:

Answer:

18100 m/s.

Explanation:

conservation of momentum can be applied in solving this question, by using below expresion

mv = MV

where M = mass of recoil of canon =90.5kg

V =velocity of recoil of canon = 20.8 m/s.

m= mass of tennis ball=204g=104x 10⁻³kg

v = velocity of tennis ball

104 x 10⁻³ x v = 90.5 x 20.8

We can make V subject of formula

v = (90.5 x 20.8) / 104 x 10⁻³

v = 18100 m/s.

Hence, the speed of the ball is 18100 m/s.

In alpha decay, the nucleus loses two protons, in beta decay, the nucleus either loses or gains a proton whereas in gamma decay, no change in proton number occurs only energy is released.

Alpha decay is a type of radioactive decay in which the nucleus of an atom emits an alpha particle which leads to transforming into a new atomic nucleus by losing two protons. During beta decay, the proton in the nucleus is transformed into a neutron and and neutron is transformed into proton while on the other hand, gamma decay is a type of decay in which nucleus changes from a higher energy state to a lower energy state due to the release of electromagnetic radiation.

So we can conclude that In alpha decay, the nucleus loses two protons, in beta decay, the nucleus either loses or gains a proton whereas in gamma decay, no change in proton number occurs only energy is released.

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Because a is not a function of t .

So d/dt of a is zero.

The electric field each creates at the centre of the other is 1.7×10^4N/C.

Consider two balloons of diameter 0.200m each with a mass 1.00g hanging apart with 0.0500m separation on the ends of string making angles of 10.0° with the vertical

E = ke q /r^2

= [(8.99×10^9N⋅m^2C^2)(1.2×10^−7C)] / (0.25m)^2

= 1.7×10^4N/C

Gauss Law states that the total electric flux out of a closed surface is equal to the charge enclosed divided by the permittivity. The electric flux in an area is defined as the electric field multiplied by the area of the surface projected in a plane and perpendicular to the electric field.

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Answer:

O electric potential

Explanation:

Answer:

[tex]electric \: potential[/tex]

Explanation:

[tex]hope \: helps \\ and \: brainliest \: if \: helped[/tex]

Answer:

Seems like you desperately need answers

The potential energy change is 1.47 KJ or 1470 J. The weight of the person is given 60 kg. Thus vertical height of the person is 2.5 m.

Potential energy is a form of energy, generated by virtue of the position of an object in the gravitational field. Potential energy depends on the mass, acceleration and height from the ground at which the object is placed/

Thus, P = Mgh. Where m is mass, h is height and g be the acceleration due to gravity, which is equal to 9.8 m/s². It is given that the mass of the person is 60 kg.

The potential energy in the gravitational field is 1.47 KJ or 1470 J, now the height h of the person can be calculated as follows:

h = p/mg.

  = 1470 J/ (60 Kg × 9.8 m/s²)

  = 2.5 m

Therefore, the vertical height of the hanging person is 2.5 m.

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Answ. B and C

Explanation:

The two statements which correctly describes transmutation include the following:

This is the process of conversion of a chemical element into another with the atomic nuclei being changed.

Transmutation has true statements which are mentioned above thereby making option B and C the most appropriate choice.

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Answer:

best answer would be a

Explanation:

d is just a law

c is just the start of a paragraph

and b would be a revision or addtion to the already amendments

Answer:

The answer is "[tex]16 \ \frac{m}{s}[/tex]"

Explanation:

[tex]Pressure \ (P) = 3.00 \times 10^{5}\ Pa\\\\Velocity\ V_1 = 1.00 \ \frac{m}{s}[/tex]

Using the formula for equating the continuity equation:

[tex]\to V_1 \times A_1 = V_2 \times A_2\\\\\to A_2 = \frac{A_1}{16} \\\\\therefore \\\\\to V_2 = V_1 \times \frac{A_1}{A_2} \\\\\to V_2 = 1 \times 16 = 16 \ \frac{m}{s}[/tex]

The speed of the flow in the narrow section is [tex]16m/s[/tex].

To find the speed of the flow in the narrow section, We use equation of continuity.

                     [tex]V_{1}*A_{1}=V_{2}*A_{2}[/tex]

Given that , initial speed [tex]V_{1}=1m/s[/tex]

Let us consider that, initial cross-section area is[tex]A_{1}=A[/tex].

When the pipe narrows to one-fourth its original diameter.

Then,   Area   [tex]A_{2}=\frac{A}{4^{2} }=\frac{A}{16}[/tex]

Substituting values in above equation.

         [tex]1*A=V_{2}*\frac{A}{16}\\\\V_{2}=16m/s[/tex]

Hence, the speed of the flow in the narrow section is [tex]16m/s[/tex].

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Answer:

El trabajo de frontera ejercido por el gas es 10,297.875 joules.

Explanation:

Supongamos que el gas se comporta idealmente y que el proceso es isotérmico y adiabático. El trabajo efectuado por el gas en el proceso equivale al área bajo la curva de la gráfica PV. Puesto que es una línea recta y que tanto la presión como el volumen son variables positivas, tenemos que esa área es la suma del rectángulo inferior (límite inferior de la presión) y el triángulo superior (entre los límites inferior y superior de la presión). Es decir:

[tex]W = P_{min}\cdot (V_{2}-V_{1})+\frac{1}{2}\cdot (P_{max}-P_{min})\cdot (V_{2}-V_{1})[/tex] (1)

Donde:

[tex]W[/tex] - Trabajo de frontera ejercido por el gas, medida en joules.

[tex]V_{1}[/tex], [tex]V_{2}[/tex] - Volúmenes del gas antes y después de la expansión, medidas en metros cúbicos.

[tex]P_{min}[/tex] - Límite inferior de la presión del gas, medida en pascales.

[tex]P_{max}[/tex] - Límite superior de la presión del gas, medida en pascales.

Si sabemos que [tex]V_{1} = 0.06\,m^{3}[/tex], [tex]V_{2} = 0.13\,m^{3}[/tex], [tex]P_{min} = 125,432\,Pa[/tex] y [tex]P_{max} = 168,793\,Pa[/tex], entonces el trabajo de frontera ejercido por el gas es:

[tex]W = (125,432\,Pa)\cdot (0.13\,m^{3}-0.06\,m^{3})+\frac{1}{2}\cdot (168,793\,m-125,432\,m) \cdot (0.13\,m^{3}-0.06\,m^{3})[/tex]

[tex]W = 10,297.875\,J[/tex]

El trabajo de frontera ejercido por el gas es 10,297.875 joules.

Answer:

125m

Explanation:

25m/s x 5 = 125

The vector magnetic force on the particle is [tex]3.47 \times 10^{-2}{~}\hat{j}{~} N[/tex].

A stream of charged particles, such as electrons or ions, traveling through an electrical conductor or a vacuum is known as an electric current.

One long wire carries a current I = 30.0 A to the left along the x-axis. I' = 50.0 A of current is being carried by a second lengthy wire to the right along the line (y = 0.280 m, z = 0).

Now,

The charge of a particle is -2.00μC which is moving with a velocity of v = [tex]150\hat{i} {~}Mm/s[/tex].

At y = 0.1 m the total magnetic field will be:

B = [ μ₀ (I') / 2πr ] + [μ₀ (I) / 2πr]

[tex]B = [\frac{\mu_{0} }{2 \pi}] \times( \frac{50}{0.28-0.1} (-\hat{k})] + \frac{30}{0.1}(-\hat{k})[/tex]

B = 1.16 × 10⁻⁴ T

Then the force on the particle is:

F =q(v × B)

[tex]F = (-2 \times 10^{-6} ) ( 150 \times 10^{6})\hat{i} \times (1.16 \times 10^{-4})(-\hat{k})[/tex]

F = 3.47 × 10⁻² N

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weightlessness is the complete or near complete absense of the sensation of weight.

when in freefall,the only force acting upon your body is the force of gravity a noun contact force.since the gravity cannot be felt without any other opposing forces,you would have no sensation of it.you would feel weightless when in a state of freefall.

The free body that shows the ball falling at terminal velocity is B. A free body diagram with 2 forces: the first pointing downward labeled F Subscript g Baseline 20 N and the second pointing upward labeled F Subscript air Baseline 20 N.

It should be noted that at terminal velocity, the ball will stop accelerating and the net force on the ball will be zero.

In this case, for the net force to be zero, equal, their resultant force is zero. That is F₁ + F₂ = 0 ⇒ F₁ = -F₂

Since F₁ = 20 N, then F₂ = -F₁ = -20 N

Therefore, if F₁ points upwards since it is positive, then F₂ points downwards since it is negative.

Therefore, the correct option is B.

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A ball is falling at terminal velocity. Terminal velocity occurs when the ball is in equilibrium and the forces are balanced. Which free body diagram shows the ball falling at terminal velocity? A free body diagram with one force pointing downward labeled F Subscript g Baseline 20 N. A free body diagram with 2 forces: the first pointing downward labeled F Subscript g Baseline 20 N and the second pointing upward labeled F Subscript air Baseline 20 N. A free body diagram with 2 forces. The first pointing downward labeled F Subscript g Baseline 20 N and the second pointing upward labeled F Subscript air Baseline 5 N. A free body diagram with 2 forces: the first pointing downward labeled F Subscript g Baseline 20 N and the second pointing upward labeled F Subscript air Baseline 30 N.

Answer:

D. 100% Chance of having a child with dimple

The potential difference that stopped electron is 1.422v

potential difference in between two points is the amount of work done is moving a unit charge from one point to another point.

The mass of the electron,

m = 9.109*10⁻³¹

Va (initial speed) = 500,000 m/s

Vb (final speed) = 0 m/s

Electron has been stopped because the electrons move from higher potential to lower potential.

by the work energy theorem

W = ½ mv² (1 equation)

The Potential difference is

W = eV

V = W/e

put the value of W form equation 1.

[tex]V = \frac{\frac{1}{2} (V_{b} ^{2} - V_{a} ^{2} )}{e}[/tex]

e = 9.109*10⁻³¹

V = 1/2 [(500000m/s²) - 0m/s² ] / 9.109*10⁻³¹

V  = 1.422v

The potential difference that stopped electron is 1.422v

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Answer:

There are two types of bone marrow – red bone marrow (myeloid tissue) and yellow bone marrow (fatty tissue).  Red bone marrow is involved in production of blood cells, while yellow marrow is important for fat storage. As you age, yellow bone marrow replaces red bone marrow.

Explanation:

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