How much force is needed to accelerate an object with a mass of 90 kg at a rate of 1.2 ms

Answers

Answer 1
Force = mass x acceleration = 90 x 1.2 = 108 Newtons

Related Questions

I just had to shove an eos in my mouth because I keep shouting random things.....

Answers

Answer:

oooop tehehehehehee

ahahhhahaaahahjabasa

Answer:

uhm- heh, wut lol ️️

What is the meaning of agility

Answers

Answer:

Agility or nimbleness is an ability to change the body's position efficiently, and requires the integration of isolated movement skills using a combination of balance, coordination, speed, reflexes, strength and endurance.

Explanation:

Hope this helps I don't know if this is what you were looking for?

Ability to move quickly and easily

Iu Metallic bonding is similar to iconic bonding because

Answers

Answer:

In an ionic bond the valence electrons are transferred from the metal

Explanation:

A length of 20-gauge copper wire (of diameter 0.8118 mm) is formed into a circular loop with a radius of 25.0 cm. A magnetic field perpendicular to the plane of the loop increases from zero to 10.0 mT in 0.34 s. Find the average electrical power dissipated in the process

Answers

Answer:

The average electrical power dissipated in the process is 0.653 mW

Explanation:

Given;

gauge of copper wire, 20 gauge

resistivity from chart, [tex]\rho = 1.68 *10^{-8} \ ohm.m[/tex]

radius of the circular loop, r = 25 cm

magnetic field strength, B = 10 .0 mT

time, t = 0.34 s

Length of the wire, L = 2πr = 2 x π x 0.25 = 1.571 m

Area of the wire, A = πR² ⇒ R = D/2 = 0.8118 mm/ 2 = 0.4059 mm

= π(0.4059 x 10⁻³)² = 0.5177 x 10⁻⁶ m²

The resistance of the wire is given by;

[tex]R = \frac{\rho L}{A}\\\\ R = \frac{1.68*10^{-8}*1.571}{(0.5177*10^{-6})}\\\\ R = 5.098 *10^{-2} \ ohms[/tex]

Now, determine the electric potential;

[tex]E = N\frac{d\phi}{dt}\\\\ E = N(\frac{BA}{dt})\\\\ E = 1(\frac{(10*10^{-3})(\pi*0.25^2)}{0.34} )\\\\E = 0.00577 \ V[/tex]

The average power is given by;

P = V²/R

P = (0.00577²) / (5.098 x 10⁻²)

P = 6.53 x 10⁻⁴ W

P = 0.653 mW

Therefore, the average electrical power dissipated in the process is 0.653 mW

who is the first person to reach in space​

Answers

Answer:

cosmonaut Yuri Gagarin

Explanation:

On that day in 1961, Russian cosmonaut Yuri Gagarin (left, on the way to the launch pad) became the first human in space, making a 108-minute orbital flight in his Vostok 1 spacecraft.

i hoped this helped plz list me as a brainliest

What characterizes moral development in middle and late childhood? Give an Example?

Answers

Answer: what characterizes moral development in mid to late childhood is

People at this level of moral development base their decisions on what their parents and/or law enforcement says is right. Stage 3 is about social conformity. ... Stage 4 is all about law and order for all. For example, someone may think, 'If I steal, I will break the law and breaking the law is wrong.Feb 17, 2016

Explanation:


Starting from rest, a car travels 18 meters as it accelerates uniformly for 3.0 seconds. What is the magnitude of
the car's acceleration?

Answers

Answer:

[tex]a=4\frac{m}{s^2}[/tex]

Explanation:

Hello.

In this case, for this uniformly accelerated motion in which the car starts from rest at 0 m/s and travels 18 m in 3.0 s, we can compute the acceleration by using the following equation:

[tex]x_f=x_0+v_0t+\frac{1}{2}at^2[/tex]

Whereas the final distance is 18 m, the initial distance is 0 m, the initial velocity is 0 m/s and the time is 3.0 s, that is why the acceleration turns out:

[tex]a=\frac{2(x_f-v_ot)}{t^2} =\frac{2(18m-0m/s*3.0s)}{(3.0s)^2}\\ \\a=4\frac{m}{s^2}[/tex]

Best regards.

Given the distance travelled and the time taken, the magnitude of  the car's acceleration is 4m/s²

Given the data in the question;

Since the car starts from rest,

Initial velocity; [tex]u = 0m/s[/tex]Distance travelled; [tex]s = 18m[/tex]time taken; [tex]t = 3.0s[/tex]

Acceleration; [tex]a = \ ?[/tex]

To determine the magnitude of  the car's acceleration

We use the Second Equation of Motion:

[tex]s = ut + \frac{1}{2}at^2[/tex]

Where s is the speed, u is the initial velocity, a is the acceleration and t is the time.

We substitute our values into the equation and solve for "a"

[tex]18m = (0m/s\ * 3.0s) + (\frac{1}{2}\ *\ a\ *\ (3.0s)^2) \\\\18m = 4.5s^2 \ *\ a\\\\a = \frac{18m}{4.5s^2} \\\\a = 4 m/s^2[/tex]

Therefore, the magnitude of  the car's acceleration is 4m/s²

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A car is pushed and travels 12 m. The same car is then pushed and it travels 15m. What could of
happened? Select 2 answers.
The force was increased
The mass was decreased
The force was decreased
The mass was increased

Answers

Explanation:

The force was increased

Consider a capacitor made of two rectangular metal plates of length and width , with a very small gap between the plates. There is a charge on one plate and a charge on the other. Assume that the electric field is nearly uniform throughout the gap region and negligibly small outside. Calculate the attractive force that one plate exerts on the other. Remember that one of the plates doesn't exert a net force on itself. (Enter the magnitude. Use any variable or symbol stated above along with the following as necessary: r0.)
F = θ/2∑0_w

Answers

Answer:

F= σ² L² /2ε₀

F = (L² ε₀/4π)   ΔV² / r⁴

Explanation:

a)  For this exercise we can use Coulomb's law

          F = - k Q² / r²

where the negative sign indicates that the force is attractive and the value of the charge is equal to the two plates

Capacitance is defined by

         C = Q / ΔV

        Q = C ΔV

also the capacitance for a parallel plate capacitor is related to its shape

         C = ε₀ A / r

we substitute

         Q = ε₀ A ΔV / r

we substitute in the force equation

            F = k (ε₀ A ΔV / r)² / r²

           k = 1 / 4πε₀

           F = ε₀ /4π  L² ΔV² / r⁴4

           F = L² ΔV² ε₀/ (4π r⁴)

           F = (L² ε₀/4π)   ΔV² / r⁴

b) Another way to solve the exercise is to use the relationship between the force and the electric field

          F = q E

where we can calculate the field created by a plane using Gaussian law, where we use a cylinder with a base parallel to the plate as the Gaussian surface

           Ф = ∫E .dA = [tex]q_{int}[/tex] / ε₀

the plate have two side

           2E A = q_{int} / ε₀

              E = σ / 2ε₀

               σ = q_{int} / A

               

substituting in force

          F = q σ / 2ε₀

the charge total on the other plate is

       q = σ A

       q = σ  L²

      F= σ² L² /2ε₀

Which statements are true for two oppositely charged, isolated parallel plates: C=capacitance, U=stored energy (Q and -Q = charge on the plates). Note: Isolated plates can not lose their charge.

1. Inserting a dielectric decreases U.

2. When the distance is doubled, C increases.

3. Increasing the distance increases the Electric field.

4. Inserting a dielectric increases Q.

5. Inserting a dielectric increases C.

6. When the distance is halved, Q stays the same.

7. When the distance is doubled, U increases.

Answers

Answer:

Explanation:

1) True. The stored energy (U) is proportional to the electric field strength (E). The electric field strength decreases when a dielectric is introduced hence inserting a dielectric decreases U.

2) False. From the formula [tex]C=\frac{Q}{V}=\frac{Q}{Vd}[/tex], capacitance is inversely proportional to distance hence if the distance is doubled, capacitance decreases.

3) False. As the distance between the electric field and the object increases, its electric field decreases.

4) False. If a dielectric is inserted, the plates are further separated. Q stays the same.

5) True. The electric field strength decreases when a dielectric is introduced and  capacitance is inversely proportional to electric field hence Inserting a dielectric increases C

6) True. If a dielectric is inserted, the plates are further separated. Q stays the same.

7) True. When the distance is doubled, U increases


Q.9) Consider a plot of the displacement (x) as a function of the applied force (F) for an ideal elastic spring as
shown, see figure. The slope of the curve would be
A) the acceleration due to gravity.
B) the reciprocal of the acceleration of gravity.
C) the mass of the object attached to the spring.
D) the reciprocal of the spring's constant.

Answers

Answer:

Option (D).

Explanation:

For an ideal spring, the force is given in terms of displacement as follows :

F=-kx

[tex]x=\dfrac{-F}{k}\\\\\text{or}\\\\x=\dfrac{-1}{k}F[/tex]...(1)

Where,

x is displacement in spring i.e. compression or stretching

k is spring constant of the spring

-ve sign shows that the force exerted by the spring is in opposite direction of the spring's displacement.

The equation of a line is : y=mx+c, m is slope

From equation (1)

Slope = 1/k

or

Slope = reciprocal of the spring's constant.

It would mean that the slope of the curve represents the reciprocal of the spring's constant.

Using the spring constant and displacement relation, the slope of the curve would be the reciprocal of the spring's constant.

Using the Force constant relation :

F = ke

F = Force ; k = spring constant ; e = extension

F = kx

Making the x the subject of the formula :

x = F/k

The slope, which is the spring constant can be expressed as ;

x = 1/k × F

Hence, the slope is the reciprocal of the spring constant.

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What are two differences between the dwarf planets and our traditional 8 planets?
Enter Answer Here

Answers

The criteria for a dwarf planet are:
1) orbits the sun
2) has enough mass to assume a nearly round shape
3) has not cleared the neighborhood around its orbit
4) is not a satellite or moon
What is the main difference between a dwarf planet and a planet?
Planets have

I’m probably wrong but I tried

How do warm ocean currents affect the weather?
A. They make the equator warmer.
B. They make the tropical regions warmer.
C. They reduce precipitation in coastal areas.
D. They result in warmer air temperatures near the current.
If you get it right you get 100 points and a brainliest

Answers

Answer:

the answer is D I believe

Answer:

Answer: D

They result in warmer air temperatures near the current.

Explanation:

i took a test with the same question and got it right

11)A 1100 kg car travels on a straight highway with a speed of 30 m/s. The driver sees a red light ahead and applies her
brakes, which exert a constant braking force of 4000N. In how many seconds will the car stop?

Answers

Answer:

Time taken = 8.25 second

Explanation:

Given:

Force = 4000 N

Force = ma

4,000 = (1100)(a)

Acceleration = 3.6363 m/s²

v = u + at

0 = 30 + (3.6363)t

Time taken = 8.25 second

The time taken by the car to stop is 8.26 s.

Given data:

The mass of car is, m = 1100 kg.

The speed of car is, u = 30 m/s.

The magnitude of braking force is, F = 4000 N.

We need to first obtain the acceleration of car to get that, apply the Newton's second law as,

F = - ma    (Negative sign shows that the force will resist the motion)

4000 = -(1100) a

[tex]a =-\dfrac{4000}{1100}\\\\a =-3.63 \;\rm m/s^{2}[/tex]

Now, apply the first kinematic equation of motion to obtain the time taken by the car to stop as,

v = u + at

Here, v is the final speed and v = 0, since car will stop finally.

So,

[tex]0=30+(-3.63)t\\\\t = \dfrac{30}{3.63}\\\\t=8.26 \;\rm s[/tex]

Thus , we can conclude that the time taken by the car to stop is 8.26 s.

Learn more about the Newton's second law of motion here:

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what is not a property that can be used to identify a mineral?​

Answers

Answer:

Color.

Explanation:

Hello.

In this case, among the properties minerals have, we list: color , streak which is the color as a powder , hardness , cleavage or fracture , crystalline structure , diaphaneity or degree of transparency, tenacity which is the capacity of its molecules to be held together,  magnetism which is the capacity to attract or repel other magnetic materials , luster which explains if its surface reflects light , odor , taste  and specific gravity which is a relationship between its density and the density of water.

In such a way, since the most of them are known as measurements, we can distinguish among minerals by contrasting those data, nevertheless, color is not a suitable property to identify a material since there could exist minerals with similar colors.

Best regards.

What is the speed of an object that travels 12 meters in 3
seconds?

Answers

Answer:

4 meters per second

Explanation:

12 divided by 3 = 4

4 meters per second

A car moving with a constant acceleration covers the distance between two points 80 m apart in 8.0 s. Its velocity as it passes the second point is 15 m/s. What was the velocity at the first point? Show work for brainliest!!

Answers

Answer:

Explanation:

3.6

An object is dropped from rest and falls freely 20 meters to Earth. When is the speed of the object 9.8 meters per second?

Answers

Answer:

at the end of its first second of fall

Explanation:

Can I have brainliest

PLZ HELP!!!
Which of the following is a vector quantity?

Answers

Answer:

B 30 M down

Explanation:

In physics we have two types of quantities:

- Scalar quantity: it is a quantity which only has a magnitude (e.g: mass and time are scalar quantities, since they only have a magnitude)

- Vector quantity: it is a quantity which has both a magnitude and a direction (e.g: velocity is a vector quantity, since it has a magnitude (the speed) and a direction)

In this problem, we have:

A. 100 ounces of water  --> scalar (this is a volume, which has only a magnitude)

B. 30 m down  --> vector (this is a displacement, which has both a magnitude (30 m) and a direction (down)

C. 88 mi/s  --> scalar (this is a speed, which has only a magnitude)

D. 45 gallons in a bucket --> scalar (this is a volume, which has only a magnitude)

So, the correct option is B.

credit to skyluke89

The correct answer is B

Apollo 14 astronaut Alan B. Shepard Jr. used an improvised six-iron to strike two golf balls while on the Fra Mauro region of the moon’s surface, making what some consider the longest golf drive in history. Assume one of the golf balls was struck with initial velocity v0 = 31.75 m/s at an angle θ = 26° above the horizontal. The gravitational acceleration on the moon’s surface is approximately 1/6 that on the earth’s surface. Use a Cartesian coordinate system with the origin at the ball's initial position.
Randomized Variables
vo 32.75 m/s
theta 32 degrees
What horizontal distance, R in meters, did this golf ball travel before returning to the lunar surface?

Answers

Complete Question

Apollo 14 astronaut Alan B. Shepard Jr. used an improvised six-iron to strike two golf balls while on the Fra Mauro region of the moon’s surface, making what some consider the longest golf drive in history. Assume one of the golf balls was struck with initial velocity v0 = 32.75 m/s at an angle θ = 32° above the horizontal. The gravitational acceleration on the moon’s surface is approximately 1/6 that on the earth’s surface. Use a Cartesian coordinate system with the origin at the ball's initial position.

Randomized Variables

vo 32.75 m/s

theta 32 degrees

What horizontal distance, R in meters, did this golf ball travel before returning to the lunar surface?

Answer:

The  horizontal distance is  [tex]R =  590.2 \ m [/tex]  

Explanation:

From the question we are told that

 The initial  velocity is  [tex]v_o =  32.75 \  m/s[/tex]

  The angle is  [tex]\theta =  26^o[/tex]

  The gravitational acceleration of the moon is [tex]g_m  =  \frac{1}{6}  *  9.8   = 1.633 m/s^2[/tex]

 Generally the distance traveled is mathematically represented as

    [tex]R =  \frac{v_o^2 sin 2(\theta)}{g_m}[/tex]

=> [tex]R =  \frac{32.75^2 sin 2(32)}{1.633}[/tex]

=> [tex]R =  590.2 \ m [/tex]  

             

what is the right way to sleep

Answers

Answer:

by lying down on a nice and soft quilted matress

On a nice soft bed after a nice hot shower

How to drawing the resultant vector of two vectors being added:

Answers

Answer:

Explanation:

you connect vector b with vector a making it head to tail

A man driving a car traveling at 20 m/sec slams on the brakes and decelerates at 3.25
m/s^2. How far does the car travel before it stops?

Answers

Recall that

[tex]{v_f}^2-{v_i}^2=2a\Delta x[/tex]

where [tex]v_i[/tex] and [tex]v_f[/tex] are initial and final velocities, respectively; [tex]a[/tex] is acceleration; and [tex]\Delta x[/tex] is the net displacement, or distance if the object is moving in a single direction.

The car has initial speed 20 m/s and acceleration -3.25 m/s². It comes to a stop, so it has 0 final speed. Then

0² - (20 m/s)² = 2 (-3.25 m/s²) ∆x

x = (20 m/s)² / (7.5 m/s²) ≈ 53.3 m

astronaut A can cover 10 meters per minute walking with the heavy shovel. What does
this sentence describe?
a) None of these things
b) Both speed and velocity
C) The velocity of the astronaut
d) The speed of the astronaut

Answers

Answer:

d) The speed of the astronaut

Explanation:

The sentence describes the speed of the astronaut. This speed value is 10meters per minute.

Now let us understand why;

Speed is the distance divided by time. It is a scalar quantity without regard for direction but it has magnitude. The value 10meters per minute clearly shows this instance. We do not know the direction the astronaut is moving towards. Velocity, like speed is the displacement of a body with time. It is a vector quantity and it shows the direction of motion. For example, 10m/s due west is a velocity value because we know the direction.

Therefore, since there is no directional sense, the value indicates speed.

The given sentence describes the speed of the astronaut. Hence, option (d) is correct.

Given data:

The distance covered by the astronaut A is, d = 10 m.

the time interval is, t = 1 min = 60 s.

Clearly,  the given sentence describes the speed of the astronaut. This speed value is 10 meters per minute.  This is because of following reason:

Speed is the distance divided by time. It is a scalar quantity without regard for direction but it has magnitude. The value 10meters per minute clearly shows this instance. We do not know the direction the astronaut is moving towards. Velocity, like speed is the displacement of a body with time. It is a vector quantity and it shows the direction of motion. For example, 10m/s due west is a velocity value because we know the direction.

Thus, we can conclude that the given sentence describes the speed of the astronaut. Hence, option (d) is correct.

Learn more about the speed here:

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Your classmate’s mass is 63 kg and the table weighs 500 N. Calculate the normal force on the table by the floor. Show your work!

Answers

Answer:

[tex]F_N=1234.8N[/tex]

Explanation:

Hello.

In this case, since the normal force is opposite to the total present weight, we can compute it by considering the mass of the classmate with the gravity to compute its weight, and the weight of the table:

[tex]F_N=63kg*9.8m/s^2+500N\\\\F_N=617.4N+500N\\\\F_N=1234.8N[/tex]

Best regards.

What would the kinetic energy and potential energy be with the snowboarder, before during and after a jump?

Answers

Answer: Before the jump, the snowboarder would carry potential energy.

During the jump he will carry kinetic energy.

And after the jump, assuming hes at a full stop, he will carry potential energy once again.

Answer:

Before the jump, the snowboarder would carry potential energy.During the jump he will carry kinetic energy.And after the jump, assuming hes at a full stop, he will carry potential energy once again.                             Explanation:

A projectile is fired with a horizontal velocity of 20 mfs and a vertical velocity of 45
6. What is the magnitude of its original velocity vector?
7. How long will the projectile be in the air?
8. What is its range?

Answers

Answer:

6. 49.2 m/s

7. 9.18 s

8. 184 m

Explanation:

6. Use Pythagorean theorem.

v₀² = v₀ₓ² + v₀ᵧ²

v₀² = (20 m/s)² + (45 m/s)²

v₀ = 49.2 m/s

7. Given:

Δy = 0 m

v₀ᵧ = 45 m/s

aᵧ = -9.8 m/s²

Find: t

Δy = v₀ᵧ t + ½ aᵧt²

(0 m) = (45 m/s) t + ½ (-9.8 m/s²) t²

0 = 45t − 4.9t²

0 = t (45 − 4.9t)

t = 9.18 s

8. Given:

v₀ₓ = 20 m/s

aₓ = 0 m/s²

t = 9.18 s

Find: Δx

Δx = v₀ₓ t + ½ aₓt²

Δx = (20 m/s) (9.18 s) + ½ (0 m/s²) (9.18 s)²

Δx = 184 m

A race car driver travel 350 ft/s (250mph) for 20 seconds. How far did she travel?

Answers

7000 feet((((((((((((((((((((
7000 I think I’m not sure

How does the eccentricity of a typical cometary orbit compare to that of a typical planet

Answers

Answer:

Explanation:

Comets are balls of ice and dust in orbit around the Sun. The orbits of comets are different from those of planets - they are elliptical. A comet's orbit takes it very close to the Sun and then far away again.

If you throw an object straight up into the air with an initial velocity of 42m/s. What is it’s velocity at the peak of its flight?
A. 42m/s
B. -42m/s
C. 9.8m/s
D. -9.8m/s
E. 0m/s
F. 0m/s2
G. None of these

Answers

0 m/s. It’s trivial
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