How many times will the while loop that follows be executed? var months = 5; var i = 1; while (i < months) { futureValue = futureValue * (1 + monthlyInterestRate); i = i+1; }

Answer:

Here is the C program :

#include<stdio.h>  // to use input output functions

   int main(){  //start of main() function body

   int n;  //to store the number of tests taken

   int test_scores[n], i;  //a variable length array test_score

   float sum=0,average;  //to store the sum and average of test scores

   int lowest;   //to store the lowest test score

   printf("Enter the number of tests taken :");//prompts user to enter number of test scores

   scanf("%d",&n); /  / reads the value of n from user

   printf("Enter test scores: ");  //prompts user to enter test scores

for(i=0; i<n; i++)  {  

 scanf("%d",&test_scores[i]);  //read the values of input test scores

 sum = sum + test_scores[i];   } //calculates the sum of the test scores by adding the values of test scores

        average=sum/n;  // compute the average by dividing sum of all test scores with the total number of test scores

               printf("Average is %.2f",average);  //displays the average

    printf("\nGrade is ");  // prints Grade is

    if (average >= 90) {  //if value of average is greater than or equal to 90

       printf("A");     }  //print the grade letter A

else if(average >= 80 && average < 90)  { //if value of average is greater than or equal to 80 and less than 90

 printf("B");  }   //print the grade letter B

else if(average>60 && average<80){ //if value of average is between 60 and 80

 printf("C");  }  //print the grade letter C

else if(average>40 && average<=60) {  //if value of average is greater than 40 and less than or equals to 60

 printf("D");  }  //print the grade letter D

else  {  //if the value of average is below 40

 printf("F");  }   //print the grade letter F

   lowest = test_scores[0];     //lowest points to the 1st element of test scores means the first input test score

   for (int j = 1; j < n;j++)     {  //loop iterates through the scores

       if (test_scores[j] < lowest)   {  // if the element at j-th index position of test_scores array is less than the element stored in the lowest variable

          lowest = test_scores[j];     }     } //then assign that element value of test_score to the lowest

     printf("\nLowest test score is:  %d.\n", lowest); } //displays the lowest test score

Explanation:

The program is well explained in the comments mentioned with each statement of the code.

The program prompts the user to enter the number of test scores as they are not already specified in the array because array test_scores is a variable length array which means its length is not fixed. The program then prompts the user to enter the test scores. The program then adds all the test scores and store the result in sum variable. Then it computes the average by dividing the value in sum variable to the number of test scores n. Then in order to determine the letter Grade the average value is used. The if else conditions are used to specify conditions in order to determine the Grade. Next the lowest score is determined by setting the value of lowest variable to the first element of the test_scores array. Then using for loop, the index variable j moves to each array element i.e. score and determines if the the value of element is less than that stored in the lowest variable. If the value positioned at j-th index of test_scores is less than that of lowest than this value is assigned to lowest. At last the lowest holds the minimum of the test scores.

Answer:

Decommission/Recycle

Explanation:

This specific scenario that is being described belongs to the final stage of the hardware lifecycle known as Decommission/Recycle. This is when the asset in question has completed its function for an extended period of time and is no longer functioning at maximum efficiency and/or newer hardware has hit the market. Once in this stage, the hardware in question is either repaired or scrapped for resources that can be used to create newer products.

Answer:

I am writing a C++ program:

#include <iostream>  //to use input output functions

#include<iomanip>  // to format the output

using namespace std;   // to identify objects like cin cout

void calculateCharge(double weight, double distance);   // function prototype

int main(){  //start of main() function body

  double w = 0.0, t = 0.0;  // w variable is for weight and t is for total

   unsigned int d = 0;   // d variable is to hold the value of distance

   calculateCharge(w, d); }  //calls calculateCharge method by passing weight and distance values to this method

void calculateCharge(double weight, double distance){  //method that takes weight and distance as parameters and compute the shipping charge

   double charge = 0.0;  //to store the value of shipping charges

   do {  // do while loop to handle multiple packages until a weight of 0 is entered

       cout << "Enter weight: " << endl;  //prompts user to enter weight

       cin >> weight;  //reads the input weight value

       if (weight == 0){  // if the value of weight is equal to 0

           break; }  // the loop breaks if value of weight is 0

       cout << "Enter distance: " << endl;  // if value of weight is not zero then the program precedes by prompting user to enter the value of distance

       cin >> distance;  //reads the input distance value

       cout << fixed << setprecision(2) << endl;  //set the precision to 2 means the sets the number of digits of an output to 2 decimal places

       if(weight <= 2)  //if the value of weight is less than or equals to 2

charge = (distance/500) * 3.10;  //compute the charge by this formula

else if(weight > 2 && weight <= 6)  //if weight is over 2 kg but not more than 6 kg

charge = (distance/500) * 4.20;  //charge is computed by multiplying value of distance to that of weight and if distance is greater than 500 then it is divided by 500 first

else if(weight > 6 && weight <= 10)  // if weight is over 6 kg but not more than 10 kg

charge = (distance/500) * 5.30;  //compute shipping charges by this formula

else  //if weight is over 10 kg

charge = (distance/500) * 6.40;   // compute shipping charge by multiplying value of distance to that of 6.40 weight value and if distance is greater than 500 then distance is divided by 500 first

cout << "Shipping charges: $" << charge << "\n";   //display the computed shipping charge

   } while (weight != 0);  //the loop continues to execute until weight 0 is entered

}              

Explanation:

The program is explained in the comments mentioned above. The program has a main() function that declares variable for weight, distance and total and then calls calculateCharge() method passing weight and dsitance in order to compute and return the shipping charge.

In calculateCharge() the user is prompted to enter the values for weight and distance. Then the based on the value of weight , the shipping charge is computed. Shipping charge is computed by multiplying the weight with distance. The distance is assumed to be 500 but if the distance entered by user exceeds 500 then the distance value is divided by 500 and then multiplied by the specified weight (according to if or else if conditions) in order to compute shipping charge. The program has a do while loop that keeps taking input from user until the user enters 0 as the value of weight.

The screenshot of the program and its output is attached.

Answer:

age = int(input("Enter your age: "))

charge = 0

if age > 55:

   charge = 10

if 21 <= age <= 54:

   charge = 15

if 13 <= age <= 20:

   charge = 10

if 3 <= age <= 12:

   charge = 5

if 0 <= age < 3:

   charge = 0

print(charge)

Explanation:

*It is in Python.

Ask the user for the age

Check the each given range and set the charge accordingly using if statements

Print the charge

Answer:

x1 = 39

x2 = 400

x3 = 92

x4 = 62

x5 = 0

Explanation:

This statement calls the f() function passing 2 to the function. The f(x) function takes a number x as parameter and returns the following:

g(x) + math.sqrt(h(x))

This again calls function g() and h()  

The above statement calls g() passing x i.e. 2 to the function g(x) and calls function h() passing x i.e. 2 to h() and the result is computed by adding the value returned by g() to the square root of the value returned by the h() method.

The g(x) function takes a number x as parameter and returns the following:

return 4*h(x)

The above statement calls function h() by passing value 2 to h() and the result is computed by multiplying 4 with the value returned by h().

The h(x) function takes a number x as parameter and returns the following:

return x*x + k(x)-1

The above statement calls function k() by passing value 2 to k() and the result is computed by subtracting 1 from the value returned by k() and adding the result of x*x (2*2) to this.

The k(x) function takes a number x as parameter and returns the following:

return 2 * (x + 1)

As the value of x=2 So

2*(2+1) = 2*(3) = 6

So the value returned by k(x) is 6

Now lets go back to the function h(x)

return x*x + k(x)-1

x = 2

k(x) = 6

So

x*x + k(x)-1 = 2*2 + (6-1) = 4 + 5 = 9

Now lets go back to the function g(x)

return 4*h(x)

As x = 2

h(x) = 9

So

4*h(x)  = 4*9 = 36

Now lets go back to function f(x)

return g(x) + math.sqrt(h(x))

As x=2

g(x) = 36

h(x) = 9

g(x) + math.sqrt(h(x))  = 36 + math.sqrt(9)

                                  = 36 + 3 = 39

Hence

The above statement means that first the function g() calls function h() and function h() is passed a value i.e 2.

As x=2

The function k() returns:

2 * (x + 1)   = 2 * (2 + 1) = 6

The function h() returns:

x*x + k(x)-1 = 2*2 + (6-1) = 4 + 5 = 9

Now The function g() returns:

4 * h(x)  = 4 * h(9)

This method again calls h() and function h() calls k(). The function k() returns:

2 * (x + 1)   = 2 * (9 + 1) = 20

Now The function h() returns:

x*x + k(x)-1 = 9*9 + (20-1) = 81 + 19 = 100

h(9) = 100

Now The function g() returns:

4 * h(x)  = 4 * h(9) = 4 * 100 = 400

Hence

g() returns:

return 4 h(x)

h() returns:

return x*x + k(x)-1

k(2) returns:

return 2 (x + 1)

          = 2 ( 3 ) = 6

Now going back to h(2)

x * x + k(x)-1  = 2*2 + 6 - 1 = 9

Now going back to g(2)

4 h(x)  = 4 * 9 = 36

So k(g(2) + h(2)) becomes:

   k(9 + 36 )

    k(45)

Now going to k():

return 2 (x + 1)

2 (x + 1)   = 2(45 + 1)

             = 2(46)

             = 92

So k(g(2) + h(2)) = 92

Hence

Compute f(0)

f() returns:

return g(0) + math.sqrt(h(0))

f() calls g() and h()

g() returns:

return 4 * h(0)

g() calls h()

h() returns

return 0*0 + k(0)-1

h() calls k()

k() returns:

return 2 * (0 + 1)

2 * (0 + 1)  = 2

Going back to caller function h()

Compute h(0)

0*0 + k(0)-1  = 2 - 1 = 1

Going back to caller function g()

Compute g(0)

4 * h(0)  = 4 * 1 = 4

Going back to caller function f()

compute f(0)

g(0) + math.sqrt(h(0))  = 4 + 1 = 5

f(0) = 5

Compute f(1)

f() returns:

return g(1) + math.sqrt(h(1))

f() calls g() and h()

g() returns:

return 4 * h(1)

g() calls h()

h() returns

return 1*1 + k(1)-1

h() calls k()

k() returns:

return 2 * (1 + 1)

2 * (1 + 1)  = 4

Going back to caller function h()

Compute h(0)

1*1 + k(1)-1  = 1 + 4 - 1 = 4

Going back to caller function g()

Compute g(1)

4 * h(1)  = 4 * 4 = 16

Going back to caller function f()

compute f(1)

g(1) + math.sqrt(h(1))  = 16 + 2 = 18

f(1) = 18

Compute f(2)

f() returns:

return g(2) + math.sqrt(h(2))

f() calls g() and h()

g() returns:

return 4 * h(2)

g() calls h()

h() returns

return 1*1 + k(2)-1

h() calls k()

k() returns:

return 2 * (2+1)

2 * (3)  = 6

Going back to caller function h()

Compute h(2)

2*2 + k(2)-1  = 4 + 6 - 1 = 9

Going back to caller function g()

Compute g(2)

4 * h(2)  = 4 * 9 = 36

Going back to caller function f()

compute f(2)

g(2) + math.sqrt(h(2))  = 36 +3 = 39

f(1) = 13.7

Now

x4 = f(0) + f(l) + f(2)

    = 5 + 18 + 39

    = 62

Hence  

Compute f(-1)

f() returns:

return g(-1) + math.sqrt(h(-1))

f() calls g() and h()

g() returns:

return 4 * h(-1)

g() calls h()

h() returns

return 1*1 + k(-1)-1

h() calls k()

k() returns:

return 2 * (-1+1)

2 * (0)  = 0

Going back to caller function h()

Compute h(-1)

-1*-1 + k(-1)-1  = 1 + 0 - 1 = 0

Going back to caller function g()

Compute g(-1)

4 * h(-1)  = 4 * 0 = 0

Going back to caller function f()

compute f(-1)

g(-1) + math.sqrt(h(-1))  = 0

f(-1) = 0

Compute g(-1)

g() returns:

return 4 * h(-1)

g() calls h()

h() returns

return 1*1 + k(-1)-1

h() calls k()

k() returns:

return 2 * (-1+1)

2 * (0)  = 0

Going back to caller function h()

Compute h(-1)

-1*-1 + k(-1)-1  = 1 + 0 - 1 = 0

Going back to caller function g()

Compute g(-1)

4 * h(-1)  = 4 * 0 = 0

g(-1) = 0

Compute h(-1)

h() returns

return 1*1 + k(-1)-1

h() calls k()

k() returns:

return 2 * (-1+1)

2 * (0)  = 0

Going back to caller function h()

Compute h(-1)

-1*-1 + k(-1)-1  = 1 + 0 - 1 = 0

h(-1) = 0

Compute k(-1)

k() returns:

return 2 (x + 1)

k(-1) = 2 ( -1 + 1 ) = 2 ( 0 ) = 0

k(-1) = 0

x5 = f(-1) + g(-1) + h(-1) + k(-1)

    = 0  + 0 + 0 + 0

    = 0

Hence

Answer and Explanation:

public class petData

{

private int ageYears;

private String fullName;

private int IdNumber;

public void setName (String givenName)

{

fullName = givenName;

return;

}

public void setAge (int numYears)

{

ageYears = numYears;

return;

}

public void setID (int numID)

{

IdNumber = numID;

return;

}

public void printAll ()

{

System.out.print ("Name: " + fullName);

System.out.print (", Age: " + ageYears);

return;

}

}

From the above, we have defined a class petData, with methods setName, setAge, printAll. These methods all make use of the string variable fullName and integer variable ageYears. From the above, setName method sets fullName variable to name given to its string parameter givenName while setAge method does the same with the ageYears variable in initializing it. This is also done by the ID method. These variables are then used by printAll method in printing out the Name and age of the object which would be created with the petData class

E. g: petData dog= new petData();

Answer:

psychographics

Explanation:

The study of people according to their attitudes, aspirations and other psychological criteria

Answer:

well you could use variables in C and display them

Explanation:

Answer:

c. Create a lookup relationship between the Candidate and Interview objects.

d. Create a trigger on the Interview object that updates a field on the Candidate object.

Explanation:

Objects relationships is considered a form of field type that joins two or more objects together such that, after understanding objects and fields, it creates some form of bonding known as object relationships. This helps define security on interview records that is independent from the security on candidate records.

For an example, in a standard object like Account, where a sales representative opens an account, and has had interviews or chats with a few people at that account’s company, and as well made contacts with the likes of executives or IT managers and still stored those contacts’ information in salesforce.

Hence, what would a developer do to accomplish this task is to:

1. Create a lookup relationship between the Candidate and Interview objects.

2. Create a trigger on the Interview object that updates a field on the Candidate object.

Answer:

Hello your question lacks the required options here are the options

answer : source IP and destination port

Explanation:

The information that is used in an attempt to identify the local destination address is the source IP and destination port

source IP is simply the internet protocol address of a device from which an IP packet is sent to another device while destination port are the ports found in a destination device that receives IP packets from source ports  they are found in many internet applications  

Answer:

Following are the answer to this question:

Explanation:

There will be several ways to provide it, although it is simpler to let another front side Will work out a three-way handshake or transfer packages to there with a Server chosen. Its application responds TCP packets with both the destination node of the front end.

The very first packet was sent to a computer as an option. Mention, even so, that perhaps the end of the queue end remains in the loop in this scenario. Rather than obtaining this information from the front end like in the primary healthcare services, you have the advantage of this capability: its selected server helps to generate TCP state.

Answer:

Program fidelity

Explanation:

Answer:

The answer is "0.77"

Explanation:

The fixed-length segment value = 1  

The propagation time of one end to another end is = 3  

The Transfer power to move the consumer from the obtained segment = 2  

The second last sender assigns a loan = 7 segments  

The overall transmission time = 3+2+3   =  8  

The maximum throughput value is:

[tex]\to \frac{7}{(1 + 8)}\\\\ \to \frac{7}{9}\\\\\to 0.77[/tex]

Answer:

Artificial Neural

Explanation:

An artificial neural is the piece of a computing system designed to simulate the way the human brain analyzes and processes information. It is the foundation of artificial intelligence.

Answer:

scope

Explanation:

An Open Authorization refers to a method  that helps to share data using third party services without giving your credentials and there is a mechanism in an Open Authorization that allows to limit the access that the third party app has to an account that is called scope. Because of that, the answer is that an Open Authorization (OAuth) access token would have a scope that tells what the third party app has access to because it is what limits the access the app has to an account and it shows the access given in a consent screen.

Answer:

Modify your program by replacing

for x in country:

       country_gold.append(gold[x])

       country_gold.append("Did not get gold")

with

for x in country:

       try:

               country_gold.append(gold[x])

       except:

               country_gold.append("Did not get gold")

Explanation:

The addition of try/except clause in the program is to let the program manage error;

In this case, the program checks for a country in the list country; This is implemented using the following line

for x in country:

If the country exists, the statement in the try block is executed

try:

 country_gold.append(gold[x])  ->This appends the country name to the country_gold list

Otherwise, the statement in the except clause is executed

except:

 country_gold.append("Did not get gold")  -> This appends "Did not get gold" to the country_gold list

To confirm what you've done, you may add the following line of code at the end of the program: print(country_gold)

Answer:

SQRRR or SQ3R is a reading comprehension method named for its five steps: survey, question, read, recite, and review. The method was introduced by Francis P. Robinson, an American education philosopher in his 1946 book Effective Study. The method offers a more efficient and active approach to reading textbook material

Answer:

A, B, C, D and E

Explanation:

Transmission Control protocol (TCP) is a protocol that describes how connections are made and maintained between devices in a network which will help applications in these devices communicate and transmit data.

The following are some of the features of TCP:

i. It supports full duplex communication: In other words, TCP allows for concurrent transmission of data in both directions.

ii. it has a graceful connection shutdown: TCP allows for graceful termination and closing of connection. This means that when there is no more data to be sent by any of the communicating devices, rather than just close connection from its end, it first informs the other device about its completion and asks if it's safe to close the connection. From there, if the other device then says it doesn't have any data to send either, they then reach a consensus to close the connection at their respective ends.

iii. Its connections are logical: TCP makes use of the reliability and flow control mechanisms which require that it initialize and maintain some status information for each stream of data. This status information containing sockets, sequence numbers and window sizes is called a logical connection.

iv. Data is sent as discrete messages: Like other discrete messages, the IP treats the data in TCP as discrete messages by placing them into the IP datagram and transmitting to the target host.

v. It is an end-to-end protocol: TCP governs the way data is transmitted between two devices at their respective ends to ensure reliable delivery. In other words, it is responsible for the transmission of data from a source to one or more destinations. It sits on the operating system of the source and also on the operating system(s) of the destination(s).

Answer:

(A) Injection

Explanation:

SQL injection is one of the most common web attacks used by attackers to steal data or compromise a web application (especially the database) by inserting or "injecting" SQL queries or commands through the input data from the web application.

In web applications, form inputs are used to make requests to the database either for validation or submission of data by executing queries in the database. If these queries are interfered with by passing query like commands into the form input fields rather than some regular alphanumeric characters, then we have an SQL injection.

When this happens;

i. the attackers can modify an SQL query to return additional results from the database

ii. the attackers can change a query to interfere with the application's regular logic flow.

iii. the attackers can extract sensitive information about the database such as its version and structure.

Answer:

int ComputeFibonacci(int N) {

   if(N == 0)

       return 0;

   else if (N == 1)

       return 1;

   else

       return ComputeFibonacci(N-1) + ComputeFibonacci(N-2);

}

Explanation:

Inside the function ComputeFibonacci that takes one parameter, N, check the base cases first. If N is eqaul to 0, return 0. If N is eqaul to 1, return 1. Otherwise, call the ComputeFibonacci function with parameter N-1 and N-2 and sum these and return the result.

For example,

If N = 4 as in the main part:

ComputeFibonacci(4) → ComputeFibonacci(3) + ComputeFibonacci(2) = 2 + 1 = 3

ComputeFibonacci(3) → ComputeFibonacci(2) + ComputeFibonacci(1) = 1 + 1 = 2

ComputeFibonacci(2) → ComputeFibonacci(1) + ComputeFibonacci(0) = 1 + 0  = 1

*Note that you need to insert values from the bottom. Insert the values for ComputeFibonacci(1) and  ComputeFibonacci(0) to find ComputeFibonacci(2) and repeat the process.

Answer:

In C++ it can be written as:

if(cost>=50&&cost<=75)

   { cout<<"The cost is in the desired range";}

In Python:

if(cost <= 75 and cost>= 50):

   print("The cost is in the desired range")

Explanation:

cost>50&&cost<75 covers the requirement that cost should be between 50 and 75 dollars

But the whole statement cost>=50&&cost<=75 covers the requirement that cost should be between 50 and 75 dollars and message should also be displayed if the cost is exactly 50 dollars or exactly 75 dollars. For example if the value of cost=50 then this message The cost is in the desired range is displayed.

In the above program && in C++, and in Python is used which is a logical operator which means that both the conditions cost <= 75 and cost>= 50 should be true for the if condition to evaluate to true. For example if cost=35 then this message is not printed because both the conditions are false i.e. 35 is neither less than or equal to 75 nor greater than or equal to 50.

Answer:

Here is the next_number method:

def next_number(self): #method to return next number in the sequence

    temporary = self.back1 + self.back2 # adds previous number to next number and stores the result in a temporary variable

    self.back2 = self.back1 #Updates back2 with the former value of back1,

    self.back1 = temporary #update back1 with the new next item in the sequence.

    return temporary #

Explanation:

I will explain the working of the above method.

back1 = 1

back2 = 0

At first call to next_number()  method:

temporary = back1 + back2

                 = 1 + 0

temporary = 1

self.back2 = self.back1

self.back2 = 1

self.back1 = temporary

self.back1 = 1

return temporary

This return statement returns the value stored in temporary variable i.e. 1

Output: 1

back1 = 1

back2 = 1

At second call to next_number()  method:

temporary = back1 + back2

                 = 1 + 1

temporary = 2

self.back2 = self.back1

self.back2 = 1

self.back1 = temporary

self.back1 = 2

return temporary

This return statement returns the value stored in temporary variable i.e. 2

output: 2

back1 = 2

back2 = 1

At second call to next_number()  method:

temporary = back1 + back2

                 = 2 + 1

temporary = 3

self.back2 = self.back1

self.back2 = 2

self.back1 = temporary

self.back1 = 3

return temporary

This return statement returns the value stored in temporary variable i.e. 3

Output: 3

back1 = 3

back2 = 2

At second call to next_number()  method:

temporary = back1 + back2

                 = 3 + 2

temporary = 5

self.back2 = self.back1

self.back2 = 3

self.back1 = temporary

self.back1 = 5

return temporary

This return statement returns the value stored in temporary variable i.e. 5

Output: 5

back1 = 5

back2 = 3

At second call to next_number()  method:

temporary = back1 + back2

                 = 5 + 3

temporary = 8

self.back2 = self.back1

self.back2 = 5

self.back1 = temporary

self.back1 = 8

return temporary

This return statement returns the value stored in temporary variable i.e. 8

Output: 8

Calling next_number 5 times would print 1, 2, 3, 5, and 8.

The complete program along with its output is attached.

Answer:

I am writing a Python program:

def string_finder(target,search): #function that takes two parameters i.e. target string and a search string

   position=(target.find(search))# returns lowest index of search if it is found in target string

   if position==0: # if value of position is 0 means lowers index

       return "Beginning" #the search string in the beginning of target string

   elif position== len(target) - len(search): #if position is equal to the difference between lengths of the target and search strings

       return "End" # returns end

   elif position > 0 and position < len(target) -1: #if value of position is greater than 0 and it is less than length of target -1

       return "Middle" #returns middle        

   else: #if none of above conditions is true return not found

       return "not found"

#you can add an elif condition instead of else for not found condition as:

#elif position==-1    

#returns "not found"

#tests the data for the following cases      

print(string_finder("Georgia Tech", "Georgia"))

print(string_finder("Georgia Tech", "gia"))

print(string_finder("Georgia Tech", "Tech"))

print(string_finder("Georgia Tech", "Idaho"))

Explanation:

The program can also be written in by using string methods.

def string_finder(target,search):  #method definition that takes target string and string to be searched

       if target.startswith(search):  #startswith() method scans the target string and checks if the (substring) search is present at the start of target string

           return "Beginning"  #if above condition it true return Beginning

       elif target.endswith(search):  #endswith() method scans the target string and checks if the (substring) search is present at the end of target string

           return "End" #if above elif condition it true return End

       elif target.find(search) != -1:  #find method returns -1 if the search string is not in target string so if find method does not return -1 then it means that the search string is within the target string and two above conditions evaluated to false so search string must be in the middle of target string

           return "Middle"  #if above elif condition it true return End

       else:  #if none of the above conditions is true then returns Not Found

           return "Not Found"

Answer:

Total amount of O₂ occupy volume = 76.50 L

2 .30 gm O₂ occupy volume = 7.48 L

Explanation:

We konw that,

Molar mass of O₂ = 31.9988 gm / mol

1 mole of O₂ = 31.9988 gm

Sample of oxygen = 0.600 mole

Computation:

0.600 mole = 31.9988 × 0.600

0.600 mole = 19.199 gm

Total amount of O₂ = 4.30 + 19.199

Total amount of O₂ = 23.499 gm

Total amount of O₂ occupy volume = 14 × 23.499/4.30

Total amount of O₂ occupy volume = 76.50 L

Total gm of O₂ = 4.30 - 2.00= 4.30 gm

2 .30 gm O₂ occupy volume = 14 × 2.30/4.30

2 .30 gm O₂ occupy volume = 7.48 L

Answer:

The program written in python is as follows

def countchr(phrase, char):

     count = 0

     for i in range(len(phrase)):

           if phrase[i] == char:

                 count = count + 1

     return count

phrase = input("Enter a Phrase: ")

char = input("Enter a character: ")

print("Occurence: ",countchr(phrase,char))

Explanation:

To answer this question, I made use of function

This line defines function countchr

def countchr(phrase, char):

This line initializes count to 0

     count = 0

This line iterates through each character of input phrase

     for i in range(len(phrase)):

This line checks if current character equals input character

           if phrase[i] == char:

The count variable is incremented, if the above condition is true

                 count = count + 1

The total number of occurrence is returned using this line

     return count

The main method starts here; This line prompts user for phrase

phrase = input("Enter a Phrase: ")

This line prompts user for a character

char = input("Enter a character: ")

This line prints the number of occurrence of the input charcater in the input phrase

print("Occurence: ",countchr(phrase,char))

Answer:

The programming language is not stated;

I'll answer this question using python programming language

The program starts here (Lines written in bold are comments and are used for explanatory purpose)

#This line imports the random module into the program

import random

#This line prompts the user to enter the filename

filename = input("Enter file name: ")

#This line prompts the user to enter the number of random numbers to generate

num = int(input("Number of random  numbers: "))

#This line adjusts the filename to a .txt file

filename = filename+".txt"

#This line checks if the filename exists; if yes, it creates and open a new file and if otherwise, it uses the existing filr

f = open(filename,'a+')

#This line iterates through the number of random to generate

for i in range(1,num+1):

     #This line generates random number within the range of 1 to 1000

     n = random.randint(1,1000)

     #This line prints the generated random number to file

     print(n, file = f)

#This line closes the created file

f.close()

Answer:

Following are the code to this question:

/*using the select statement, that selects column name from the table blog.posts */  

SELECT blog.posts.user_id, blog.posts.body, users.name/*column name user_id, body, name*/  

FROM blog.posts/* use table name blog.posts*/

RIGHT OUTER JOIN users ON blog.posts.user_id = users.id;/*use right join that connect table through user_id*/

Explanation:

In the structured query language, RIGHT JOIN  is used to recovers from both the right side of the table both numbers, although the left table has no sets. It also ensures that even if the 0 (null) documents are linked inside this left table, its entry will always return the outcome row, but still, the number of columns from its left table will be NULL.

In the above-given right join code, the select statements used that selects the column names "user_id, body, and the name" from the table "blog. posts" and use the right join syntax to connect the table through the id.    

Answer:

val = int(input("Enter a positive odd value "))

flag = True # let the number entered is alreay prime

if(val > 2 and val%2 == 1):  # prime numbers start from 2

   half = int(val/2);

   for div in range(2,half):  # dividing the number from 2 to half of its number

       if(val % div == 0): # if completely divisible

           print("Not prime")

           flag = False   # Changing the status of prime number as false

           break

   if(flag == True):

       print(val, "is a prime number")

else:

   print("Invalid input, Please Enter a valid positive odd number")

Explanation:

Steps:

1. Let us take input from the user using input() method.

2.  Initially, let the number is prime.

3. If the number is negative or even, the go to else part and ask the user for a valid input and terminate the program by giving a message to user.

(We actually check for values greater than 2 because 1 is not considered as  a prime number)

4. If the number is positive and odd, then we keep on dividing the number from 2 to half of its number.

(We actually check for values greater than 2 because 1 is not considered as  a prime number)

5. If the number is divisible, we change the status to False and break the loop.

6. If the flag is still True, we print that it is a Prime number else we print that it is not a prime number.

Please refer to the comments section as well and the attached image for proper indentation of the program.

Answer:

The technician will want to add ACL for ports 20 and 21

Explanation:

The FTP protocol by default will attempt to use 21 for TCP access and 20 for data access.  By enabling an Access Control List (ACL) on ports 20 and 21, the technician can prevent FTP traffic from leaving the network on the default ports.

Cheers.