How many numbers x between 1 and 100 (inclusive) have the property that x2+x3 is a perfect square?
(Please help. I'm suffering)

Answers

Answer 1
Answer:  9

=========================================================

Explanation:

Factor the given expression

x^2+x^3

x^2*1+x^2*x

x^2(1+x)

x^2(x+1)

We end up with something where the factor x^2 is a perfect square regardless of whatever we replace x with from the set {1,2,3,...,99,100}.

In short, we don't need to worry about the x^2 portion.

--------------------

The only thing of importance is the x+1 factor.

The x+1 must be a perfect square so that the original expression is as well.

Let's say M is some perfect square between 1 and 100. That means M belongs to the set of values

{1, 4, 9, 16, 25, 36, 49, 64, 81, 100}

If we want M+1 to be a perfect square, then we'll need to subtract 1 from each item in that set above to counteract the "plus 1" in "M+1".

Subtract 1 from each item to end up with this modified set

{0, 3, 8, 15, 24, 35, 48, 63, 80, 99}

--------------------

Every item mentioned in that second set will make x^2+x^3 to be a perfect square.

For example, let's pick x = 15

x^2(x+1) = 15^2*(15+1)  

x^2(x+1) = 15^2*16

x^2(x+1) = 15^2*4^2

x^2(x+1) = (15*4)^2

x^2(x+1) = 60^2

This confirms that x^2+x^3 is a perfect square for x = 15. I'll let you check the other values.

There are 10 values in the set {1^2,2^2,...,9^2,10^2} = {1,2,...,81,100}. There are also 10 values in the set {0,3,8, ..., 80, 99} we got earlier. The cardinality hasn't changed. However, we'll kick out 0 because it's not between 1 and 100. So we end up with 9 as our final answer.

--------------------

To summarize, there are 9 values of x that make x^2+x^3 a perfect square, where x is some whole number between 1 and 100 inclusive.

Answer 2
The both the question and first answer is crazy confusing so I am simply gonna pray u succeed ma boi

Related Questions

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Answer:

X = 2

5y + (what is that number???) can not see it

Someone put the same question earlier and I answered, I will answer again

So to find x ,
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1
What is the solution to the equation
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?
O X=-3
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Answers

Solution:

[tex] \frac{1}{x} = \frac{x + 3}{ {2x}^{2} } \\ = > \frac{2 {x}^{2} }{x} = x + 3 \\ = > 2x = x + 3 \\ = > 2x - x = 3 \\ = > x = 3[/tex]

Answer:

The answer is option d. X = 3

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Answers

Answer:

10r=-50

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.........

r would equal -50/10 and you would get -5

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Answers

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so 2.75 x 0.10x0

= 2.75

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Answers

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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

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Answers

Answer:

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Answer:6

Step-by-step explanation:


yea

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The number line compares the numbers –6, 3, and 5.

1. Write an inequality that compares –6 and 3. Justify your inequality using the number line.

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Answers

#1

-6-3-5

Hence inequality will be

[tex]\\ \sf\longmapsto -6\leqslant 5[/tex]

#2.

3<5

But we need inequality

[tex]\\ \sf\longmapsto 3\leqslant 5[/tex]

#3

The inequality given by

[tex]\\ \sf\longmapsto -6\leqslant 3\leqslant 5[/tex]

Answer:

1. Inequality

[tex] \hookrightarrow \: { \rm{ - 6 < 0 < 3}}[/tex]

2. Inequality

[tex] \hookrightarrow \: { \rm{3 < 0 < 5}}[/tex]

3. Inequality

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Answers

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Answer:

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Answers

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Answers

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Answer:

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Answers

Answer:

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Answers

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Can someone tell me
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Answers

Answer:

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Step-by-step explanation:

seeing as how the sum of all angles in a triangle is 180 degrees, we can get an equation:

28+39+x=180

simplify to get:

67+x=180

subtract 67 from both sides to get your answer:

113=x

Answer:

[tex]x=113[/tex]

[tex]y=67[/tex]

[tex]z=49[/tex]

Step-by-step explanation:

To find x:

We can use the angle sum property of a triangle which states that, The sum of all internal angles of a triangle is always equal to 180°.

Therefore, [tex]28+39+x=180[/tex]

[tex]67+x=180[/tex]

[tex]x=180-67[/tex]

[tex]x=113[/tex]

Now that we know the value of [tex]x[/tex] we can use it to find the value of [tex]y[/tex].

We can see that angle [tex]x[/tex] and [tex]y[/tex] are supplementary which means:

[tex]x+y=180[/tex]

[tex]113+y=180[/tex]

[tex]y=180-113[/tex]

[tex]y=67[/tex]

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[tex]64+y+z=180[/tex]

[tex]64+67+z=180[/tex]

[tex]131+z=180[/tex]

[tex]z=180-131[/tex]

[tex]z=49[/tex]

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I am assuming you mean

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