how many moles are in 3.4 x 10^23 molecules of carbon dioxide CO2

1.)

density is found by [tex]\rho=\frac{m}{V}[/tex]

[tex]\rho=\frac{3.1}{0.35}\\\\ \rho=8.857 g/cm^3[/tex]

2.)

Volume is [tex]lwh[/tex]

7*10*5

V=350[tex]cm^3[/tex]

3.)

using the density formula

[tex]\rho=\frac{m}{V}[/tex]

[tex]\rho=\frac{4.3}{3}[/tex]

[tex]\rho=1.43g/ml[/tex]

4.)

rearrange the density formula for V

[tex]V=\frac{m}{\rho}[/tex]

[tex]V=\frac{58.5}{9.9}\\\\ V=5.909cm^3[/tex]

5.)

rearrange the density formula for [tex]m[/tex]

[tex]m=\rho V\\\\m=(6.7)(5)\\\\m=33.5g[/tex]

(19) The potential energy of the piano is 14700 J.

(20) The height of the cannon ball is 35.71 m.

This can be defined as the energy of a body due to its position in the gravitational field.

(19) To calculate the potential energy of the piano, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values intyo equation 1

(20) To calculate the heigth of the cannon ball we use the formula below.

From the question,

Given:

Substitute these values into equation 2

Hence, (19) The potential energy of the piano is 14700 J and (20) The height of the cannon ball is 35.71 m

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The wrong Juan did in this investigation is he multiplied by 4 and did not count it for 60 seconds to calculate the heart rate per minute.

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Answer:

c

Explanation:

There are four boxes so each are 25%.

Red = 25%

Red and White = 50%

White = 25%

Answer:

3.5x1024 3.5 x 10 24 carbon dioxide molecules weighs 256 g.

Answer:

ionic bonding occurs when unstable atoms donates one or more valence electrons to a unstable atom

Explanation:

Answer:

Yeast is used for the leavening of bread. Yeast uses the sugars and oxygen in dough to produce more yeast cells and carbon dioxide gas. The carbon dioxide makes the dough rise which gives the bread a light and spongy texture. Yeast also works on the gluten network.

Explanation:

Answer:

B) Lose electrons to form positive ions

Explanation:

If the light completely falls on the two beakers, the degree of hotness increases with respect to time, while if the light is transmitted, the water would gradually cool down.

The effect of transmitted light on temperature is understood by the fact that the intensity of transmitted light became maximum during the process of cooling. While it gets the opposite when the water warms significantly.

According to the context of this question, if all the light reaching the two beakers had been transmitted, the degree of hotness of the water gradually declines. Due to this, the water in the two beakers cool down.

Therefore, the water cools slowly if all the light reaching the two beakers had been transmitted.

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Answer:

1. Objective

2. Objective

3. Opinion

4. Objective

5. Opinion

6. Opinion

7. Opinion (I think.)

8. Opinion (I think.)

Explanation:

fraction of the volume of the atom that is taken up by the nucleus is 1.07x10⁻¹³Å³

Sphere volume is calculated by formula =

V=4/3(πr³) , V is volume , r is radius
Radius = diameter/2

Radius of atom = 2/2=1

Radius of nucleus = (9.50x10⁻⁵)/2 = 4.75x10⁻⁵

now we may calculate the volume for the atom and the nucleus

atom volume = (4/3) × 3.14 × (1 )³ = 4.186 ų

nucleus volume = (4/3) × 3.14 × (4.75× 10⁻⁵)³ = 4.48 × 10⁻¹³Å³

now the fraction of volume of the atom that is taken up by the nucleus:

fraction = nucleus volume / atom volume 

fraction =4.48 × 10⁻¹³/4.186 = 1.07x10⁻¹³Å³

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Answer:

Kr

Explanation:

Just took the test

Answer:

Answer: The mass of product left in the test tube will be less than the initial measured mass of the reactants.

Explanation: This is because one of the products of the reaction is a gas (hydrogen) and it escapes as the reaction happens in an open system.

This is the reaction,

Mg(s) + 2HCl(aq) --------> MgCl2(aq) + H2(g)

So, evidently, only MgCl2 is left in the reaction test tube together with unreacted reactants.

But, the hydrogen gas that escapes accounts for the lesser mass at the end of the reaction.

The mass in the test tube at the end of the reaction +

the mass of Hydrogen gas that escapes = the mass of reactants before the reaction; consolidating the law of conservation of mass.

Answer: Referring to a solution that does not completely disassociate, the conductivity would be low.

Explanation: Ions that are completely disassociated conduct better than ions that still are connected by bonds.

The kind of conductivity that would you expect insoluble compounds have is very poor or low. Due to this, these compounds do not dissociate to any appreciable extent.

Conductivity is measured through the utilization of salinity measurement. This measurement most frequently determines the parts per thousand or grams per liter.

A Siemen is also referred to as its smaller equivalents, the milli-Siemen, and the micro-Siemen, which are each one-millionth of a Siemen, is a unit used to determine the conductivity of any given solution.

Some solutions like NaCl, HCl, NaOH, etc have high electrical conductivity because they readily dissociate into their ions. While insoluble compounds do not have this capability to dissociation, so they generally have low or poor electrical conductivity.

Therefore, insoluble compounds generally have low or poor electrical conductivity.

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Law of Conservation of mass: Mass cannot be created nor destroyed. Reference: Antoine Lavoisier – By carefully weighing the reactants & products of chemical reactions. The laws of chemical combination describe the basic principles obeyed by interacting atoms and molecules, interactions that can include many different combinations that happen in many different ways. This amazing diversity of interactions allows for an astounding variety of chemical reactions and compounds. The most fundamental concept in chemistry is the law of conservation of mass, which states that there is no detectable change in the quantity of matter during an ordinary chemical reaction. Modern chemistry is based on several fundamental laws, including:

No, neon normally does not form any compounds because neon has eight electrons in its outermost shell and is unreactive.

Neon belongs to the Group 18 of the periodic table.

The other elements(Helium, argon, krypton, radon, xenon) along with neon present in group 18 are known as noble gases.

All the elements of this group are unreactive and gases.

All these gases except Helium have 8 electrons in their outermost level, which is a stable electronic configuration.

As they have a stable electronic configuration, they don’t have any tendency to accept electrons from other elements or donate their electrons, which makes them unreactive.

Thus, neon normally does not form any compounds because neon has eight electrons in its outermost shell and is unreactive.

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True.

However, overpopulation also increases if there is a shortage in the population of consumers. As a result population of producers increase.

Answer:

True (statement is correct)

Explanation:

Yeah, overpopulation occurs when the number of organisms of a species exceeds the ecosystem's carrying capacity. Hence, the given statement is correct (true).

The boiling point (in C) of a 0.743 m  aqueous solution of KCI : 100.7608°C

Solutions from volatile substances have a higher boiling point and lower freezing points than the solvent  

ΔTb = Tb solution - Tb solvent  

ΔTb = boiling point elevation  

[tex]\large {\boxed {\boxed {\bold {\Delta Tb \: = \: Kb.m}}}[/tex]

For electrolyte solutions there is a van't Hoff factor = i  

i = 1 + (n-1) α  

n = number of ions from the electrolyte  

α = degree of ionization, strong electrolyte α = 1, for non electrolytes i = 1  

KCl⇒K⁺+Cl⁻⇒ electrolyte  solution(2 ions K⁺ and Cl⁻),  strong electrolyte α = 1

ΔTb=Kb.m.i

i = 1 + (n-1) α  

i=1+(2-1).1=2

Kb for water (solvent) : 0.512 °C kg/mol

molal KCl = 0.743 m

The boiling point of solution :

[tex]\tt Tb-100=0.512\times 0.743\times 2\\\\Tb-100=0.7608\\\\Tb=100.7608^OC[/tex]

The correct answer is 100.761.

Answer:

85g

Explanation:

To convert the moles of a substance to grams we need to know the molar mass of the substance. We, as first, must obtain the molar mass of (NH₄)₂S as follows:

There are 2 atoms of N, 8 of H and 1 of S:

N = 2*14g/mol = 28g/mol

H = 8*1g/mol = 8g/mol

S = 1*32g/mol = 32g/mol

Molar mass: 68g/mol

That means 1 mole of (NH₄)₂S has a mass of 68g.

1.25moles have a mass of:

1.25moles * (68g/mol) =

The balanced equation :

8Al + 3Fe₃O₄→ 4Al₂O₃ + 9Fe

You just have to look for which element is in bold because the question is not clear

Equalization of chemical reaction equations can be done using variables. Steps in equalizing the reaction equation:

1. gives a coefficient on substances involved in the equation of reaction such as a, b, or c etc.

2. make an equation based on the similarity of the number of atoms where the number of atoms = coefficient × index between reactant and product

3. Select the coefficient of the substance with the most complex chemical formula equal to 1

Reaction

Al + Fe₃O₄→ Al₂O₃ + Fe

give a coefficient

aAl + Fe₃O₄→ bAl₂O₃ + cFe

O, left=4, right=3b⇒3b=4⇒b=4/3

Al, left=a, right=2b⇒a=2b⇒a=2.4/3⇒a=8/3

Fe, left=3, right=c⇒c=3

The equation becomes :

8/3Al + Fe₃O₄→ 4/3Al₂O₃ + 3Fe x3

8Al + 3Fe₃O₄→ 4Al₂O₃ + 9Fe

Answer:

D. lysosome

Explanation:

hope it helps :D

sorry if its wrong :/

answer: it should be false

Answer:

Explanation:

yes leon is correct because matter is anything that takes space and also has mass in it.

thks.

Answer:

Transition metals can have multiple oxidation states because of their electrons. The transition metals have several electrons with similar energies, so one or all of them can be removed, depending the circumstances. When they attach to other atoms, some of their electrons change energy levels.

Explanation:

Answer:

They move in fixed orbits around the nucleus.

Explanation:

In the Bohr model, it shows the electrons moving in fixed paths around the nucleus, making it easier to see and count them.

Answer:

Pretty sure the electrons orbit.

Explanation:

Bases are substances that can release hydroxide ions or take up hydrogen ions into the water.

Bases are those substances that have a pH above 7. They are bitter. When bases are added to water, they release hydroxide ions. And takes up hydrogen ions. Bases that fall at the pH of 8 are considered weak bases whereas those bases that fall at the pH of 14 are considered strong bases. A few examples of bases are sodium hydroxide, calcium hydroxide, potassium hydroxide, etc.

[tex]NaOH + H _{2}O→ Na ^{ + } + OH ^{ - } [/tex]

Substances that fall within the pH of 7 are considered neutral substances.

Acids are substances that have a pH below 7. They are sour. When acids are added to water they release hydrogen ions. Acids that fall at the pH of 6 are considered weak acids whereas those bases that fall at the pH of 1 are considered strong acids. A few examples of acids are acetic acid, hydrochloric acid, sulphuric acid, nitric acid, etc.

[tex]CH _{3}COOH + H _{2} O→COO ^{ - } + H ^{ + } [/tex]

Therefore, the substances that release hydroxide ions or take up hydrogen ions into the water are known as bases.

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Answer: 32.06 atomic mass units

Explanation:

Answer:

c

Explanation:

Answer: Yes we can extract all the lithium from the amount of compound we have.

Explanation:

To calculate the moles :

[tex]moles=\frac{\text {given mass}}{\text {Molar mass}}[/tex]

[tex]\text{Moles of} Li=\frac{150g}{7g/mol}=21.4moles[/tex]

[tex]\text{Moles of} Li_2O=\frac{675g}{30g/mol}=22.5moles[/tex]

[tex]2Li_2O\rightarrow 4Li+O_2[/tex]

According to stoichiometry :

2 moles of [tex]Li_2O[/tex] produce 4 moles of [tex]Li[/tex]

Thus 22.5 moles of [tex]Li_2O[/tex] will produce=[tex]\frac{4}{2}\times 22.5=45moles[/tex]  of Li

As 21.4 moles is a lesser quantity than 45 moles, thus it can be produced

Yes, you can extract all the lithium you need from the compound

We'll begin by calculating the mass of lithium, Li in 1 mole of Li₂O. This can be obtained as described below:

1 mole of Li₂O = (2×7) + 16

1 mole of Li₂O = 14 + 16 = 30 g

SUMMARY

30 g of Li₂O contains 14 g of Li.

30 g of Li₂O contains 14 g of Li.

Therefore,

675 g of Li₂O Will contain = (675 × 14)/30 = 315 g of Li.

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